message stringlengths 2 15.4k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 45 107k | cluster float64 21 21 | __index_level_0__ int64 90 214k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
Sereja has a bracket sequence s1, s2, ..., sn, or, in other words, a string s of length n, consisting of characters "(" and ")".
Sereja needs to answer m queries, each of them is described by two integers li, ri (1 ≤ li ≤ ri ≤ n). The answe... | instruction | 0 | 64,330 | 21 | 128,660 |
Tags: data structures, schedules
Correct Solution:
```
# by the authority of GOD author: manhar singh sachdev #
import os,sys
from io import BytesIO, IOBase
from array import array
def construct(n,x,si):
left = array('i',[0]*(si<<1))
right = array('i',[0]*(si<<1))
tree = array('i',[0]*(si<<1))
for... | output | 1 | 64,330 | 21 | 128,661 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Sereja has a bracket sequence s1, s2, ..., sn, or, in other words, a string s of length n, consisting of characters "(" and ")".
Sereja needs to answer m queries, each of them is described by two integers li, ri (1 ≤ li ≤ ri ≤ n). The answe... | instruction | 0 | 64,331 | 21 | 128,662 |
Tags: data structures, schedules
Correct Solution:
```
import sys
input = sys.stdin.readline
s = input()
n = len(s)
# Max size of tree
tree = [0] * (2 * n)
closed = [0] * (2 * n)
opened = [0] * (2 * n)
# function to build the tree
def build(arr):
# insert leaf nodes in tree
for i in range(n):
tree[... | output | 1 | 64,331 | 21 | 128,663 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Sereja has a bracket sequence s1, s2, ..., sn, or, in other words, a string s of length n, consisting of characters "(" and ")".
Sereja needs to answer m queries, each of them is described by two integers li, ri (1 ≤ li ≤ ri ≤ n). The answe... | instruction | 0 | 64,332 | 21 | 128,664 |
Tags: data structures, schedules
Correct Solution:
```
import sys
input = sys.stdin.readline
s = input()
M = int(input())
def next_pow_2(n):
p = 1
while p < n:
p <<= 1
return p
def represented_range(node, size):
l = node
r = node
while l < size:
l = 2*l
r = 2*r + 1
... | output | 1 | 64,332 | 21 | 128,665 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Sereja has a bracket sequence s1, s2, ..., sn, or, in other words, a string s of length n, consisting of characters "(" and ")".
Sereja needs to answer m queries, each of them is described by two integers li, ri (1 ≤ li ≤ ri ≤ n). The answe... | instruction | 0 | 64,333 | 21 | 128,666 |
Tags: data structures, schedules
Correct Solution:
```
import sys
input = sys.stdin.readline
s = input()
M = int(input())
def next_pow_2(n):
p = 1
while p < n:
p <<= 1
return p
def represented_range(node, size):
l = node
r = node
while l < size:
l = 2*l
r = 2*r + 1
... | output | 1 | 64,333 | 21 | 128,667 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Sereja has a bracket sequence s1, s2, ..., sn, or, in other words, a string s of length n, consisting of characters "(" and ")".
Sereja needs to answer m queries, each of them is described by two integers li, ri (1 ≤ li ≤ ri ≤ n). The answe... | instruction | 0 | 64,334 | 21 | 128,668 |
Tags: data structures, schedules
Correct Solution:
```
#If FastIO not needed, use this and don't forget to strip
import sys, math
input = sys.stdin.readline
"""
In each subsequence:
-
"""
S = input().strip()
two_pows = set()
"""for i in range(31):
two_pows.add(pow(2,i))
while len(S) not in two_pows:
S = S + ... | output | 1 | 64,334 | 21 | 128,669 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sereja has a bracket sequence s1, s2, ..., sn, or, in other words, a string s of length n, consisting of characters "(" and ")".
Sereja needs to answer m queries, each of them is described by t... | instruction | 0 | 64,335 | 21 | 128,670 |
No | output | 1 | 64,335 | 21 | 128,671 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sereja has a bracket sequence s1, s2, ..., sn, or, in other words, a string s of length n, consisting of characters "(" and ")".
Sereja needs to answer m queries, each of them is described by t... | instruction | 0 | 64,336 | 21 | 128,672 |
No | output | 1 | 64,336 | 21 | 128,673 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sereja has a bracket sequence s1, s2, ..., sn, or, in other words, a string s of length n, consisting of characters "(" and ")".
Sereja needs to answer m queries, each of them is described by t... | instruction | 0 | 64,337 | 21 | 128,674 |
No | output | 1 | 64,337 | 21 | 128,675 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sereja has a bracket sequence s1, s2, ..., sn, or, in other words, a string s of length n, consisting of characters "(" and ")".
Sereja needs to answer m queries, each of them is described by t... | instruction | 0 | 64,338 | 21 | 128,676 |
No | output | 1 | 64,338 | 21 | 128,677 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a bracket sequence s of length n, where n is even (divisible by two). The string s consists of n/2 opening brackets '(' and n/2 closing brackets ')'.
In one move, you can choose exactly one bracket and move it to the beginning... | instruction | 0 | 65,023 | 21 | 130,046 |
Tags: greedy, strings
Correct Solution:
```
# ===============================================================================================
# importing some useful libraries.
from __future__ import division, print_function
from fractions import Fraction
import sys
import os
from io import BytesIO, IOBase
from itertoo... | output | 1 | 65,023 | 21 | 130,047 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a bracket sequence s of length n, where n is even (divisible by two). The string s consists of n/2 opening brackets '(' and n/2 closing brackets ')'.
In one move, you can choose exactly one bracket and move it to the beginning... | instruction | 0 | 65,024 | 21 | 130,048 |
Tags: greedy, strings
Correct Solution:
```
T = int(input())
for t in range(T):
N = int(input())
s = input()
a = 0
level = 0
for c in s:
if c == '(':
level += 1
elif c == ')':
if level == 0:
a += 1
else:
level -= 1... | output | 1 | 65,024 | 21 | 130,049 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a bracket sequence s of length n, where n is even (divisible by two). The string s consists of n/2 opening brackets '(' and n/2 closing brackets ')'.
In one move, you can choose exactly one bracket and move it to the beginning... | instruction | 0 | 65,025 | 21 | 130,050 |
Tags: greedy, strings
Correct Solution:
```
for _ in range(int(input())):
n=int(input())
s=input()
ans=0
c=0
for i in s:
if(i==')'):
c+=1
else:
c-=1
ans=max(ans,c)
print(ans)
``` | output | 1 | 65,025 | 21 | 130,051 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a bracket sequence s of length n, where n is even (divisible by two). The string s consists of n/2 opening brackets '(' and n/2 closing brackets ')'.
In one move, you can choose exactly one bracket and move it to the beginning... | instruction | 0 | 65,026 | 21 | 130,052 |
Tags: greedy, strings
Correct Solution:
```
t=int(input())
while(t):
k=int(input())
n=input()
xopen=0
yclose=0
count=0
flag=0
prefix=[0]*k
for i in range(len(n)):
if(i==0):
if(n[i]=="("):
prefix[i]=-1
else:
prefix[i]=1
... | output | 1 | 65,026 | 21 | 130,053 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a bracket sequence s of length n, where n is even (divisible by two). The string s consists of n/2 opening brackets '(' and n/2 closing brackets ')'.
In one move, you can choose exactly one bracket and move it to the beginning... | instruction | 0 | 65,027 | 21 | 130,054 |
Tags: greedy, strings
Correct Solution:
```
import math
from sys import stdin
from collections import Counter,defaultdict,deque
input=stdin.readline
mod=pow(10,9)+7
def solve():
n=int(input())
s=input()
c=0
l1=[]
for i in range(n):
if(s[i]=="("):
l1.append(1)
else:
... | output | 1 | 65,027 | 21 | 130,055 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a bracket sequence s of length n, where n is even (divisible by two). The string s consists of n/2 opening brackets '(' and n/2 closing brackets ')'.
In one move, you can choose exactly one bracket and move it to the beginning... | instruction | 0 | 65,028 | 21 | 130,056 |
Tags: greedy, strings
Correct Solution:
```
import string
t = int(input())
for _ in range(t):
n = int(input())
s = input()
openn=0
close=0
wrong=0
for i in s:
if i=="(":
openn+=1
elif i==")":
close+=1
if close>openn:
wrong+=close-openn
... | output | 1 | 65,028 | 21 | 130,057 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a bracket sequence s of length n, where n is even (divisible by two). The string s consists of n/2 opening brackets '(' and n/2 closing brackets ')'.
In one move, you can choose exactly one bracket and move it to the beginning... | instruction | 0 | 65,029 | 21 | 130,058 |
Tags: greedy, strings
Correct Solution:
```
t = int(input())
for i in range(t):
n = int(input())
s = input()
suma = minimum = 0
for znak in s:
if znak == ')' and suma == 0:
minimum += 1
elif znak == '(':
suma += 1
elif znak == ')':
suma -= 1
print(minimum)
``` | output | 1 | 65,029 | 21 | 130,059 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a bracket sequence s of length n, where n is even (divisible by two). The string s consists of n/2 opening brackets '(' and n/2 closing brackets ')'.
In one move, you can choose exactly one bracket and move it to the beginning... | instruction | 0 | 65,030 | 21 | 130,060 |
Tags: greedy, strings
Correct Solution:
```
for _ in range(int(input())):
n=int(input())
s=input()
a="("
aa=0
b=")"
bb=0
for e in s:
if(aa>0 and e==b):
aa-=1
elif(e==a):
aa+=1
print(aa)
``` | output | 1 | 65,030 | 21 | 130,061 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a bracket sequence s of length n, where n is even (divisible by two). The string s consists of n/2 opening brackets '(' and n/2 closing brackets ')'.
In one move, you can choose e... | instruction | 0 | 65,031 | 21 | 130,062 |
Yes | output | 1 | 65,031 | 21 | 130,063 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a bracket sequence s of length n, where n is even (divisible by two). The string s consists of n/2 opening brackets '(' and n/2 closing brackets ')'.
In one move, you can choose e... | instruction | 0 | 65,032 | 21 | 130,064 |
Yes | output | 1 | 65,032 | 21 | 130,065 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a bracket sequence s of length n, where n is even (divisible by two). The string s consists of n/2 opening brackets '(' and n/2 closing brackets ')'.
In one move, you can choose e... | instruction | 0 | 65,033 | 21 | 130,066 |
Yes | output | 1 | 65,033 | 21 | 130,067 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a bracket sequence s of length n, where n is even (divisible by two). The string s consists of n/2 opening brackets '(' and n/2 closing brackets ')'.
In one move, you can choose e... | instruction | 0 | 65,034 | 21 | 130,068 |
Yes | output | 1 | 65,034 | 21 | 130,069 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a bracket sequence s of length n, where n is even (divisible by two). The string s consists of n/2 opening brackets '(' and n/2 closing brackets ')'.
In one move, you can choose e... | instruction | 0 | 65,035 | 21 | 130,070 |
No | output | 1 | 65,035 | 21 | 130,071 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a bracket sequence s of length n, where n is even (divisible by two). The string s consists of n/2 opening brackets '(' and n/2 closing brackets ')'.
In one move, you can choose e... | instruction | 0 | 65,036 | 21 | 130,072 |
No | output | 1 | 65,036 | 21 | 130,073 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a bracket sequence s of length n, where n is even (divisible by two). The string s consists of n/2 opening brackets '(' and n/2 closing brackets ')'.
In one move, you can choose e... | instruction | 0 | 65,037 | 21 | 130,074 |
No | output | 1 | 65,037 | 21 | 130,075 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a bracket sequence s of length n, where n is even (divisible by two). The string s consists of n/2 opening brackets '(' and n/2 closing brackets ')'.
In one move, you can choose e... | instruction | 0 | 65,038 | 21 | 130,076 |
No | output | 1 | 65,038 | 21 | 130,077 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A bracket sequence is a string containing only characters "(" and ")".
A regular bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression by inserting characters "1" and "+" between the original ch... | instruction | 0 | 65,395 | 21 | 130,790 |
Tags: implementation
Correct Solution:
```
def string_value(str):
ans=0
valid = True
neg=False
after_neg = 0
for char in str:
if char==")":
ans-=1
if after_neg>0:
after_neg-=1
else:
ans+=1
after_neg+=1
if ans<0:
... | output | 1 | 65,395 | 21 | 130,791 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A bracket sequence is a string containing only characters "(" and ")".
A regular bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression by inserting characters "1" and "+" between the original ch... | instruction | 0 | 65,396 | 21 | 130,792 |
Tags: implementation
Correct Solution:
```
#!/usr/bin/env python3
from collections import defaultdict
def hd(s):
d, h = 0, 0
dmax = 0
for c in s:
if c == '(':
h += 1
d -= 1
else:
h -= 1
d += 1
dmax = max(d, dmax)
return h, dmax
n = int(input().strip())
h0 = 0
hp = defaultdict(int)
hm = default... | output | 1 | 65,396 | 21 | 130,793 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A bracket sequence is a string containing only characters "(" and ")".
A regular bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression by inserting characters "1" and "+" between the original ch... | instruction | 0 | 65,397 | 21 | 130,794 |
Tags: implementation
Correct Solution:
```
n=int(input())
openw=[0 for i in range(300001)]
closew=[0 for j in range(300001)]
reg=0
for i in range(n):
r=input()
c=0
o=0
e=1
for y in r:
if y==")":
c=c+1
else:
o=o+1
if c>o:
e=2
r1=r[::-1]
c1=0
o1=0
e1=0
for u in r1:
if u==")":
c1=c1+1
else:... | output | 1 | 65,397 | 21 | 130,795 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A bracket sequence is a string containing only characters "(" and ")".
A regular bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression by inserting characters "1" and "+" between the original ch... | instruction | 0 | 65,398 | 21 | 130,796 |
Tags: implementation
Correct Solution:
```
import configparser
import math
import sys
input = sys.stdin.readline
def f_close(str):
s = [str[0]]
for i in str[1:]:
if i == '(':
s.append('(')
else:
if len(s) == 0 or s[-1] == ')':
s.append(')')
... | output | 1 | 65,398 | 21 | 130,797 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A bracket sequence is a string containing only characters "(" and ")".
A regular bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression by inserting characters "1" and "+" between the original ch... | instruction | 0 | 65,399 | 21 | 130,798 |
Tags: implementation
Correct Solution:
```
#This code sucks, you know it and I know it.
#Move on and call me an idiot later.
def check(symbolString):
s = []
tcnt = 0
balanced = True
index = 0
while index < len(symbolString):
symbol = symbolString[index]
if symbol == "(":
... | output | 1 | 65,399 | 21 | 130,799 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A bracket sequence is a string containing only characters "(" and ")".
A regular bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression by inserting characters "1" and "+" between the original ch... | instruction | 0 | 65,400 | 21 | 130,800 |
Tags: implementation
Correct Solution:
```
n = int(input())
arr = []
for i in range(n):
arr.append(input())
l ={}
r = {}
z=0
for i in arr:
s = 0
g = 0
for j in i:
if j =='(':
s+=1
else:
s-=1
if s <0:
g+=1
s=0
if s==0 and g==0:
... | output | 1 | 65,400 | 21 | 130,801 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A bracket sequence is a string containing only characters "(" and ")".
A regular bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression by inserting characters "1" and "+" between the original ch... | instruction | 0 | 65,401 | 21 | 130,802 |
Tags: implementation
Correct Solution:
```
n=int(input().strip())
c1=0
f={}
s={}
for i in range(n):
c=0
minm=1000000
st=input().strip()
for j in st:
if j=='(':
c+=1
else:
c-=1
minm=min(minm,c)
#maxm=max(maxm,c)
if(c==0 and minm>=0):
c1+... | output | 1 | 65,401 | 21 | 130,803 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A bracket sequence is a string containing only characters "(" and ")".
A regular bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression by inserting characters "1" and "+" between the original ch... | instruction | 0 | 65,402 | 21 | 130,804 |
Tags: implementation
Correct Solution:
```
from collections import deque, defaultdict
remains = defaultdict(int)
N = int(input())
for _ in range(N):
line = input()
stack = deque()
for brace in line:
if len(stack) == 0 or (stack[-1] == ')' and brace == '(') or stack[-1] == brace:
sta... | output | 1 | 65,402 | 21 | 130,805 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A bracket sequence is a string containing only characters "(" and ")".
A regular bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression by inserting... | instruction | 0 | 65,403 | 21 | 130,806 |
Yes | output | 1 | 65,403 | 21 | 130,807 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A bracket sequence is a string containing only characters "(" and ")".
A regular bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression by inserting... | instruction | 0 | 65,404 | 21 | 130,808 |
Yes | output | 1 | 65,404 | 21 | 130,809 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A bracket sequence is a string containing only characters "(" and ")".
A regular bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression by inserting... | instruction | 0 | 65,405 | 21 | 130,810 |
Yes | output | 1 | 65,405 | 21 | 130,811 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A bracket sequence is a string containing only characters "(" and ")".
A regular bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression by inserting... | instruction | 0 | 65,406 | 21 | 130,812 |
Yes | output | 1 | 65,406 | 21 | 130,813 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A bracket sequence is a string containing only characters "(" and ")".
A regular bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression by inserting... | instruction | 0 | 65,407 | 21 | 130,814 |
No | output | 1 | 65,407 | 21 | 130,815 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A bracket sequence is a string containing only characters "(" and ")".
A regular bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression by inserting... | instruction | 0 | 65,408 | 21 | 130,816 |
No | output | 1 | 65,408 | 21 | 130,817 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A bracket sequence is a string containing only characters "(" and ")".
A regular bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression by inserting... | instruction | 0 | 65,409 | 21 | 130,818 |
No | output | 1 | 65,409 | 21 | 130,819 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A bracket sequence is a string containing only characters "(" and ")".
A regular bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression by inserting... | instruction | 0 | 65,410 | 21 | 130,820 |
No | output | 1 | 65,410 | 21 | 130,821 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A bracketed sequence is called correct (regular) if by inserting "+" and "1" you can get a well-formed mathematical expression from it. For example, sequences "(())()", "()" and "(()(()))" are correct, while ")(", "(()" and "(()))(" are not.... | instruction | 0 | 67,426 | 21 | 134,852 |
Tags: greedy
Correct Solution:
```
n = int(input())
s = str(input())
res,bf = 0,0
flag=True
if(n%2!=0):
print("-1")
else:
for i in range(n):
if(s[i] == ')'):
bf = bf-1
else:
bf =bf+ 1
if bf == 0:
res= res+1
flag=False
if... | output | 1 | 67,426 | 21 | 134,853 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A bracketed sequence is called correct (regular) if by inserting "+" and "1" you can get a well-formed mathematical expression from it. For example, sequences "(())()", "()" and "(()(()))" are correct, while ")(", "(()" and "(()))(" are not.... | instruction | 0 | 67,427 | 21 | 134,854 |
Tags: greedy
Correct Solution:
```
'''
Auther: ghoshashis545 Ashis Ghosh
college: jalpaiguri Govt Enggineering College
Date:07/03/2020
'''
from math import ceil,sqrt,gcd,log,floor
from collections import deque
def ii(): return int(input())
def si(): return input()
def mi(): return map(int,input().strip().sp... | output | 1 | 67,427 | 21 | 134,855 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A bracketed sequence is called correct (regular) if by inserting "+" and "1" you can get a well-formed mathematical expression from it. For example, sequences "(())()", "()" and "(()(()))" are correct, while ")(", "(()" and "(()))(" are not.... | instruction | 0 | 67,428 | 21 | 134,856 |
Tags: greedy
Correct Solution:
```
n = int(input())
s = input()
cnt = 0
flag = 0
ans = 0
pre = 0
i = 1
for c in s:
if c == '(':
cnt += 1
else:
cnt -= 1
if cnt == 0 and c == '(':
ans += i-pre+1
if cnt == -1 and c == ')':
pre = i
i += 1
if cnt == 0:
print(ans)
else... | output | 1 | 67,428 | 21 | 134,857 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A bracketed sequence is called correct (regular) if by inserting "+" and "1" you can get a well-formed mathematical expression from it. For example, sequences "(())()", "()" and "(()(()))" are correct, while ")(", "(()" and "(()))(" are not.... | instruction | 0 | 67,429 | 21 | 134,858 |
Tags: greedy
Correct Solution:
```
a=int(input())
b=input()
op=b.count("(")
cl=a-op
if op!=cl :
print (-1)
else :
closrn=0
oprn=0
flag=0
tot=0
for i in range (a) :
if b[i]=="(" :
oprn=oprn+1
else :
closrn=closrn+1
if closrn>... | output | 1 | 67,429 | 21 | 134,859 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A bracketed sequence is called correct (regular) if by inserting "+" and "1" you can get a well-formed mathematical expression from it. For example, sequences "(())()", "()" and "(()(()))" are correct, while ")(", "(()" and "(()))(" are not.... | instruction | 0 | 67,430 | 21 | 134,860 |
Tags: greedy
Correct Solution:
```
def balance(list):
if(len(list)%2==1):
return False
temp=[]
for i in list:
if(i=='('):
temp.append('(')
else:
if(len(temp)==0):
return False
temp.pop(-1)
return len(temp)==0
def func(inp,n):
open,close=0,0
ans=0
list=[]
prev=0
for i in range(n):
if(inp[i... | output | 1 | 67,430 | 21 | 134,861 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A bracketed sequence is called correct (regular) if by inserting "+" and "1" you can get a well-formed mathematical expression from it. For example, sequences "(())()", "()" and "(()(()))" are correct, while ")(", "(()" and "(()))(" are not.... | instruction | 0 | 67,431 | 21 | 134,862 |
Tags: greedy
Correct Solution:
```
# (())
def solve(n, s):
i = 0
ans = 0
while i < n:
cnt = s[i]
j = i + 1
while j < n and cnt != 0:
cnt += s[j]
j += 1
if s[i] == -1:
ans += j - i
i = j
return ans
def main():
n = int(input... | output | 1 | 67,431 | 21 | 134,863 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A bracketed sequence is called correct (regular) if by inserting "+" and "1" you can get a well-formed mathematical expression from it. For example, sequences "(())()", "()" and "(()(()))" are correct, while ")(", "(()" and "(()))(" are not.... | instruction | 0 | 67,432 | 21 | 134,864 |
Tags: greedy
Correct Solution:
```
n, s, be, ans, l, r = int(input()), input(), 0, 0, 0, 0
if s.count('(') != s.count(')'):
exit(print(-1))
for j, i in enumerate(s):
if i == '(':
l += 1
else:
if l:
l -= 1
else:
r += 1
if l == r:
if l:
... | output | 1 | 67,432 | 21 | 134,865 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A bracketed sequence is called correct (regular) if by inserting "+" and "1" you can get a well-formed mathematical expression from it. For example, sequences "(())()", "()" and "(()(()))" are correct, while ")(", "(()" and "(()))(" are not.... | instruction | 0 | 67,433 | 21 | 134,866 |
Tags: greedy
Correct Solution:
```
n=int(input())
l=list(input())
if n%2!=0:
print(-1)
else:
count=0
brack=0
for i in range(n):
if l[i]=='(':
brack+=1
else:
brack-=1
if brack<0:
count+=2
if brack!=0:
print(-1)
else:
print(count)
``` | output | 1 | 67,433 | 21 | 134,867 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A bracketed sequence is called correct (regular) if by inserting "+" and "1" you can get a well-formed mathematical expression from it. For example, sequences "(())()", "()" and "(()(()))" are c... | instruction | 0 | 67,434 | 21 | 134,868 |
Yes | output | 1 | 67,434 | 21 | 134,869 |
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