message
stringlengths
2
15.4k
message_type
stringclasses
2 values
message_id
int64
0
1
conversation_id
int64
45
107k
cluster
float64
21
21
__index_level_0__
int64
90
214k
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. As Will is stuck in the Upside Down, he can still communicate with his mom, Joyce, through the Christmas lights (he can turn them on and off with his mind). He can't directly tell his mom where ...
instruction
0
47,639
21
95,278
No
output
1
47,639
21
95,279
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. As Will is stuck in the Upside Down, he can still communicate with his mom, Joyce, through the Christmas lights (he can turn them on and off with his mind). He can't directly tell his mom where ...
instruction
0
47,640
21
95,280
No
output
1
47,640
21
95,281
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. As Will is stuck in the Upside Down, he can still communicate with his mom, Joyce, through the Christmas lights (he can turn them on and off with his mind). He can't directly tell his mom where ...
instruction
0
47,641
21
95,282
No
output
1
47,641
21
95,283
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. As Will is stuck in the Upside Down, he can still communicate with his mom, Joyce, through the Christmas lights (he can turn them on and off with his mind). He can't directly tell his mom where ...
instruction
0
47,642
21
95,284
No
output
1
47,642
21
95,285
Provide tags and a correct Python 3 solution for this coding contest problem. As Will is stuck in the Upside Down, he can still communicate with his mom, Joyce, through the Christmas lights (he can turn them on and off with his mind). He can't directly tell his mom where he is, because the monster that took him to the...
instruction
0
51,032
21
102,064
Tags: dp, greedy, implementation, math Correct Solution: ``` #!/user/bin/env python 3.5 # -*- coding: utf-8 -*- s=input() a=0 n=len(s) for i in range(n): l=0 k=0 for j in range(i,n): l+=s[j]=='(' l-=s[j]==')' k+=s[j]=='?' if l+k<0: break if k>l: l,k=k,l if l==k: a=a+1 print(a) ```
output
1
51,032
21
102,065
Provide tags and a correct Python 3 solution for this coding contest problem. As Will is stuck in the Upside Down, he can still communicate with his mom, Joyce, through the Christmas lights (he can turn them on and off with his mind). He can't directly tell his mom where he is, because the monster that took him to the...
instruction
0
51,033
21
102,066
Tags: dp, greedy, implementation, math Correct Solution: ``` s = input() l = len(s) ans = 0 for i in range(0, l): m = n = 0 for j in range(i, l): m += s[j] == '(' m -= s[j] == ')' n += s[j] == '?' if m + n < 0: break if m < n: m, n = n, m ...
output
1
51,033
21
102,067
Provide tags and a correct Python 3 solution for this coding contest problem. As Will is stuck in the Upside Down, he can still communicate with his mom, Joyce, through the Christmas lights (he can turn them on and off with his mind). He can't directly tell his mom where he is, because the monster that took him to the...
instruction
0
51,034
21
102,068
Tags: dp, greedy, implementation, math Correct Solution: ``` s = input() res, n = 0, len(s) for i in range(n-1): j, c, q = i , 0, 0 while j < n and c + q >= 0: if(s[j] == '('): c += 1 elif(s[j] == ')'): c -= 1 else: q += 1 if(c < q): c, q = q, c ...
output
1
51,034
21
102,069
Provide tags and a correct Python 3 solution for this coding contest problem. As Will is stuck in the Upside Down, he can still communicate with his mom, Joyce, through the Christmas lights (he can turn them on and off with his mind). He can't directly tell his mom where he is, because the monster that took him to the...
instruction
0
51,035
21
102,070
Tags: dp, greedy, implementation, math Correct Solution: ``` s=input().strip() n=len(s) ques=ans=ini=0 for i in range(n): ques=ini=0 for j in range(i,n): c=s[j] if(c=="?"):ques+=1 elif(c=='('):ini+=1 else:ini-=1 if(ini<0):break if(ques>ini): ques-=1;in...
output
1
51,035
21
102,071
Provide tags and a correct Python 3 solution for this coding contest problem. As Will is stuck in the Upside Down, he can still communicate with his mom, Joyce, through the Christmas lights (he can turn them on and off with his mind). He can't directly tell his mom where he is, because the monster that took him to the...
instruction
0
51,036
21
102,072
Tags: dp, greedy, implementation, math Correct Solution: ``` s = str(input()) n = len(s) ans = 0 dp = [[0 for _ in range(n)] for _ in range(2)] for i in range(n - 1): if s[i] == ')': continue dp[0][i] = 1 dp[1][i] = 1 for j in range(i + 1, n): if s[j] == '(': dp[0][j] = dp[0...
output
1
51,036
21
102,073
Provide tags and a correct Python 3 solution for this coding contest problem. As Will is stuck in the Upside Down, he can still communicate with his mom, Joyce, through the Christmas lights (he can turn them on and off with his mind). He can't directly tell his mom where he is, because the monster that took him to the...
instruction
0
51,037
21
102,074
Tags: dp, greedy, implementation, math Correct Solution: ``` s = input() l = len(s) ans = 0 for i in range(0, l): ln = n = 0 for j in range(i, l): if s[j] == '(': ln += 1 elif s[j] == ')': ln -= 1 else: n += 1 ln -= 1 if ln == 0: ...
output
1
51,037
21
102,075
Provide tags and a correct Python 3 solution for this coding contest problem. As Will is stuck in the Upside Down, he can still communicate with his mom, Joyce, through the Christmas lights (he can turn them on and off with his mind). He can't directly tell his mom where he is, because the monster that took him to the...
instruction
0
51,038
21
102,076
Tags: dp, greedy, implementation, math Correct Solution: ``` import sys li = lambda : [int(x) for x in sys.stdin.readline().strip().split()] rw = lambda : sys.stdin.readline().strip().split() ni = lambda : int(sys.stdin.readline().strip()) nsi = lambda : sys.stdin.readline().strip() from collections import ...
output
1
51,038
21
102,077
Provide tags and a correct Python 3 solution for this coding contest problem. As Will is stuck in the Upside Down, he can still communicate with his mom, Joyce, through the Christmas lights (he can turn them on and off with his mind). He can't directly tell his mom where he is, because the monster that took him to the...
instruction
0
51,039
21
102,078
Tags: dp, greedy, implementation, math Correct Solution: ``` s = str(input()) n = len(s) ans = 0 for l in range(n-1): cnt = 0 qu = 0 chk = 0 if s[l] == '(': cnt += 1 chk += 1 elif s[l] == '?': qu += 1 chk = max(chk-1, 0) else: continue for r in range(...
output
1
51,039
21
102,079
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. As Will is stuck in the Upside Down, he can still communicate with his mom, Joyce, through the Christmas lights (he can turn them on and off with his mind). He can't directly tell his mom where ...
instruction
0
51,040
21
102,080
Yes
output
1
51,040
21
102,081
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. As Will is stuck in the Upside Down, he can still communicate with his mom, Joyce, through the Christmas lights (he can turn them on and off with his mind). He can't directly tell his mom where ...
instruction
0
51,041
21
102,082
Yes
output
1
51,041
21
102,083
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. As Will is stuck in the Upside Down, he can still communicate with his mom, Joyce, through the Christmas lights (he can turn them on and off with his mind). He can't directly tell his mom where ...
instruction
0
51,042
21
102,084
Yes
output
1
51,042
21
102,085
Provide a correct Python 3 solution for this coding contest problem. You are given a string $S$, which is balanced parentheses with a star symbol '*' inserted. Any balanced parentheses can be constructed using the following rules: * An empty string is balanced. * Concatenation of two balanced parentheses is balanced...
instruction
0
52,152
21
104,304
"Correct Solution: ``` line = input() lebel = 0 for i in range(len(line)): if line[i] == '*': print(lebel) break if line[i] == '(': lebel += 1 elif line[i] == ')': lebel -= 1 ```
output
1
52,152
21
104,305
Provide tags and a correct Python 3 solution for this coding contest problem. As Famil Door’s birthday is coming, some of his friends (like Gabi) decided to buy a present for him. His friends are going to buy a string consisted of round brackets since Famil Door loves string of brackets of length n more than any other...
instruction
0
52,627
21
105,254
Tags: dp, strings Correct Solution: ``` def ij(s): i = 0 j = 0 for c in s: if c == ')': if j > 0: j -= 1 else: i += 1 else: j += 1 return i, j K = 10**9 + 7 def ways(n, s): I, J = ij(s) f = n - len(s) - I - J...
output
1
52,627
21
105,255
Provide tags and a correct Python 3 solution for this coding contest problem. As Famil Door’s birthday is coming, some of his friends (like Gabi) decided to buy a present for him. His friends are going to buy a string consisted of round brackets since Famil Door loves string of brackets of length n more than any other...
instruction
0
52,628
21
105,256
Tags: dp, strings Correct Solution: ``` import os import sys from io import BytesIO, IOBase # import string # characters = string.ascii_lowercase # digits = string.digits # sys.setrecursionlimit(int(1e6)) # dir = [-1,0,1,0,-1] # moves = 'NESW' inf = float('inf') from functools import cmp_to_key from collections import...
output
1
52,628
21
105,257
Provide tags and a correct Python 3 solution for this coding contest problem. As Famil Door’s birthday is coming, some of his friends (like Gabi) decided to buy a present for him. His friends are going to buy a string consisted of round brackets since Famil Door loves string of brackets of length n more than any other...
instruction
0
52,629
21
105,258
Tags: dp, strings Correct Solution: ``` n, m = map(int, input().split()) s = input() mod = 10 ** 9 + 7 c = b = 0 for x in s: c += (x == '(') * 2 - 1 b = min(c, b) d = [[1]] for i in range(n - m): nd = d[-1][1:] + [0] * 2 for j in range(1, i + 2): nd[j] = (nd[j] + d[-1][j-1]) % mod d.append(n...
output
1
52,629
21
105,259
Provide tags and a correct Python 3 solution for this coding contest problem. As Famil Door’s birthday is coming, some of his friends (like Gabi) decided to buy a present for him. His friends are going to buy a string consisted of round brackets since Famil Door loves string of brackets of length n more than any other...
instruction
0
52,630
21
105,260
Tags: dp, strings Correct Solution: ``` from sys import stdin n,m=map(int, stdin.readline().strip().split()) s=input() dp=[[0 for i in range(2004)] for j in range(2004)] mod=10**9+7 d=n-m ans=0 b=0 d1=0 for i in s: if i=='(': b+=1 else: b-=1 if b<d1: d1=b d1=-d1 dp[0][0]=1 d+=1 try:...
output
1
52,630
21
105,261
Provide tags and a correct Python 3 solution for this coding contest problem. As Famil Door’s birthday is coming, some of his friends (like Gabi) decided to buy a present for him. His friends are going to buy a string consisted of round brackets since Famil Door loves string of brackets of length n more than any other...
instruction
0
52,631
21
105,262
Tags: dp, strings Correct Solution: ``` n, m = map(int, input().split()) s = input() mod = 10 ** 9 + 7 c, b, ans, d, k = 0, 0, 0, [[1]], n - m for i in s: c += (i == '(') * 2 - 1 b = min(c, b) for i in range(n - m): nd = d[-1][1:] + [0] * 2 for j in range(1, i + 2): nd[j] = (nd[j] + d[-1][j - 1]...
output
1
52,631
21
105,263
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. As Famil Door’s birthday is coming, some of his friends (like Gabi) decided to buy a present for him. His friends are going to buy a string consisted of round brackets since Famil Door loves str...
instruction
0
52,632
21
105,264
No
output
1
52,632
21
105,265
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. As Famil Door’s birthday is coming, some of his friends (like Gabi) decided to buy a present for him. His friends are going to buy a string consisted of round brackets since Famil Door loves str...
instruction
0
52,633
21
105,266
No
output
1
52,633
21
105,267
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. As Famil Door’s birthday is coming, some of his friends (like Gabi) decided to buy a present for him. His friends are going to buy a string consisted of round brackets since Famil Door loves str...
instruction
0
52,634
21
105,268
No
output
1
52,634
21
105,269
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. As Famil Door’s birthday is coming, some of his friends (like Gabi) decided to buy a present for him. His friends are going to buy a string consisted of round brackets since Famil Door loves str...
instruction
0
52,635
21
105,270
No
output
1
52,635
21
105,271
Provide tags and a correct Python 3 solution for this coding contest problem. A bracket sequence is called regular if it is possible to obtain correct arithmetic expression by inserting characters + and 1 into this sequence. For example, sequences (())(), () and (()(())) are regular, while )(, (() and (()))( are not. ...
instruction
0
55,796
21
111,592
Tags: constructive algorithms, greedy Correct Solution: ``` t=int(input()) for o in range(t): s=list(input()) c=0 if len(s)%2!=0: print('NO') elif s[0]==')': print('NO') elif s[len(s)-1]=='(': print('NO') else: print('YES') ```
output
1
55,796
21
111,593
Provide tags and a correct Python 3 solution for this coding contest problem. A bracket sequence is called regular if it is possible to obtain correct arithmetic expression by inserting characters + and 1 into this sequence. For example, sequences (())(), () and (()(())) are regular, while )(, (() and (()))( are not. ...
instruction
0
55,797
21
111,594
Tags: constructive algorithms, greedy Correct Solution: ``` from math import * from collections import deque from copy import deepcopy import sys def inp(): return sys.stdin.readline().rstrip("\r\n") #for fast input def multi(): return map(int,input().split()) def strmulti(): return map(str, inp().split()) def lis(): r...
output
1
55,797
21
111,595
Provide tags and a correct Python 3 solution for this coding contest problem. A bracket sequence is called regular if it is possible to obtain correct arithmetic expression by inserting characters + and 1 into this sequence. For example, sequences (())(), () and (()(())) are regular, while )(, (() and (()))( are not. ...
instruction
0
55,798
21
111,596
Tags: constructive algorithms, greedy Correct Solution: ``` for _ in range(int(input())): s = input() if len(s) % 2 != 0: print("NO") elif s.startswith(')'): print("NO") elif s.endswith('('): print("NO") else: lb = [s.count('('), s.count(')')] qb = s.count('?'...
output
1
55,798
21
111,597
Provide tags and a correct Python 3 solution for this coding contest problem. A bracket sequence is called regular if it is possible to obtain correct arithmetic expression by inserting characters + and 1 into this sequence. For example, sequences (())(), () and (()(())) are regular, while )(, (() and (()))( are not. ...
instruction
0
55,799
21
111,598
Tags: constructive algorithms, greedy Correct Solution: ``` for _ in range(int(input())): s=input() if len(s)%2==1: print("NO") else: if s[0]==')' or s[-1]=='(': print("NO") else: print("YES") ```
output
1
55,799
21
111,599
Provide tags and a correct Python 3 solution for this coding contest problem. A bracket sequence is called regular if it is possible to obtain correct arithmetic expression by inserting characters + and 1 into this sequence. For example, sequences (())(), () and (()(())) are regular, while )(, (() and (()))( are not. ...
instruction
0
55,800
21
111,600
Tags: constructive algorithms, greedy Correct Solution: ``` t=int(input()) for _ in range(t): s=input() l=r=q=0 for c in s: if c == '(': l += 1 if c == ')': r += 1 if c == '?': q += 1 if (l+r+q)%2: print('NO') continue lq = (l+r+q)//2-l if not 0 <= lq <= q...
output
1
55,800
21
111,601
Provide tags and a correct Python 3 solution for this coding contest problem. A bracket sequence is called regular if it is possible to obtain correct arithmetic expression by inserting characters + and 1 into this sequence. For example, sequences (())(), () and (()(())) are regular, while )(, (() and (()))( are not. ...
instruction
0
55,801
21
111,602
Tags: constructive algorithms, greedy Correct Solution: ``` for _ in range(int(input())): s = input() if len(s) % 2 == 0 and s[0] != ')' and s[-1] != '(': print('YES') else: print("NO") ```
output
1
55,801
21
111,603
Provide tags and a correct Python 3 solution for this coding contest problem. A bracket sequence is called regular if it is possible to obtain correct arithmetic expression by inserting characters + and 1 into this sequence. For example, sequences (())(), () and (()(())) are regular, while )(, (() and (()))( are not. ...
instruction
0
55,802
21
111,604
Tags: constructive algorithms, greedy Correct Solution: ``` import math from sys import * #input=stdin.readline def solve(): #n=int(input()) s=input() #n,k=map(int,input().split()) ##m=int(input()) #l=list(map(int,input().split())) #l1=list(map(int,input().split())) #zero=s.count('0') ...
output
1
55,802
21
111,605
Provide tags and a correct Python 3 solution for this coding contest problem. A bracket sequence is called regular if it is possible to obtain correct arithmetic expression by inserting characters + and 1 into this sequence. For example, sequences (())(), () and (()(())) are regular, while )(, (() and (()))( are not. ...
instruction
0
55,803
21
111,606
Tags: constructive algorithms, greedy Correct Solution: ``` def valid_brackets(s): openBrackets = 0 for i in s: if openBrackets < 0: return False if i == "(": openBrackets += 1 elif i == ")": openBrackets -= 1 if openBrackets != 0: retu...
output
1
55,803
21
111,607
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. A bracket sequence is called regular if it is possible to obtain correct arithmetic expression by inserting characters + and 1 into this sequence. For example, sequences (())(), () and (()(())) ...
instruction
0
55,804
21
111,608
Yes
output
1
55,804
21
111,609
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. A bracket sequence is called regular if it is possible to obtain correct arithmetic expression by inserting characters + and 1 into this sequence. For example, sequences (())(), () and (()(())) ...
instruction
0
55,805
21
111,610
Yes
output
1
55,805
21
111,611
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. A bracket sequence is called regular if it is possible to obtain correct arithmetic expression by inserting characters + and 1 into this sequence. For example, sequences (())(), () and (()(())) ...
instruction
0
55,806
21
111,612
Yes
output
1
55,806
21
111,613
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. A bracket sequence is called regular if it is possible to obtain correct arithmetic expression by inserting characters + and 1 into this sequence. For example, sequences (())(), () and (()(())) ...
instruction
0
55,807
21
111,614
Yes
output
1
55,807
21
111,615
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. A bracket sequence is called regular if it is possible to obtain correct arithmetic expression by inserting characters + and 1 into this sequence. For example, sequences (())(), () and (()(())) ...
instruction
0
55,808
21
111,616
No
output
1
55,808
21
111,617
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. A bracket sequence is called regular if it is possible to obtain correct arithmetic expression by inserting characters + and 1 into this sequence. For example, sequences (())(), () and (()(())) ...
instruction
0
55,809
21
111,618
No
output
1
55,809
21
111,619
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. A bracket sequence is called regular if it is possible to obtain correct arithmetic expression by inserting characters + and 1 into this sequence. For example, sequences (())(), () and (()(())) ...
instruction
0
55,810
21
111,620
No
output
1
55,810
21
111,621
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. A bracket sequence is called regular if it is possible to obtain correct arithmetic expression by inserting characters + and 1 into this sequence. For example, sequences (())(), () and (()(())) ...
instruction
0
55,811
21
111,622
No
output
1
55,811
21
111,623
Provide tags and a correct Python 3 solution for this coding contest problem. A string is called bracket sequence if it does not contain any characters other than "(" and ")". A bracket sequence is called regular (shortly, RBS) if it is possible to obtain correct arithmetic expression by inserting characters "+" and "...
instruction
0
56,442
21
112,884
Tags: constructive algorithms, greedy Correct Solution: ``` input() brackets = list(input()) a = 0 b = 0 result =[] for bracket in brackets: if bracket == '(': if a == b: a+=1 result.append("1") else: b+=1 result.append("0") else: if a>b...
output
1
56,442
21
112,885
Provide tags and a correct Python 3 solution for this coding contest problem. A string is called bracket sequence if it does not contain any characters other than "(" and ")". A bracket sequence is called regular (shortly, RBS) if it is possible to obtain correct arithmetic expression by inserting characters "+" and "...
instruction
0
56,443
21
112,886
Tags: constructive algorithms, greedy Correct Solution: ``` from collections import deque n = int(input()) s = input() left = deque([]) ans = [-1]*n flag = True for i in range(n): if s[i]=='(': left.append(i) else: if flag: l_idx = left.popleft() ans[l_idx] = 0 ...
output
1
56,443
21
112,887
Provide tags and a correct Python 3 solution for this coding contest problem. A string is called bracket sequence if it does not contain any characters other than "(" and ")". A bracket sequence is called regular (shortly, RBS) if it is possible to obtain correct arithmetic expression by inserting characters "+" and "...
instruction
0
56,444
21
112,888
Tags: constructive algorithms, greedy Correct Solution: ``` n = int(input()) s = str(input()) cum = [0]*(n+1) depth = [0]*(n+1) for i in range(n): if s[i] == '(': cum[i+1] = cum[i]+1 depth[i+1] = cum[i+1] else: depth[i+1] = cum[i] cum[i+1] = cum[i]-1 #print(cum) #print(depth) ans...
output
1
56,444
21
112,889
Provide tags and a correct Python 3 solution for this coding contest problem. A string is called bracket sequence if it does not contain any characters other than "(" and ")". A bracket sequence is called regular (shortly, RBS) if it is possible to obtain correct arithmetic expression by inserting characters "+" and "...
instruction
0
56,445
21
112,890
Tags: constructive algorithms, greedy Correct Solution: ``` n = int(input()) s = input() ans = [] l = 0 for i in range(n): if s[i] == '(': l += 1 ans.append(l % 2) if s[i] == ')': ans.append(l% 2) l -=1 print(''.join([str(i) for i in ans])) ```
output
1
56,445
21
112,891
Provide tags and a correct Python 3 solution for this coding contest problem. A string is called bracket sequence if it does not contain any characters other than "(" and ")". A bracket sequence is called regular (shortly, RBS) if it is possible to obtain correct arithmetic expression by inserting characters "+" and "...
instruction
0
56,446
21
112,892
Tags: constructive algorithms, greedy Correct Solution: ``` n = int(input()) A = input() stack = [] for i in A: if i == '(': if len(stack) == 0 or stack[-1] == 1: stack.append(0) print(0, end='') else: stack.append(1) print(1, end='') else: ...
output
1
56,446
21
112,893
Provide tags and a correct Python 3 solution for this coding contest problem. A string is called bracket sequence if it does not contain any characters other than "(" and ")". A bracket sequence is called regular (shortly, RBS) if it is possible to obtain correct arithmetic expression by inserting characters "+" and "...
instruction
0
56,447
21
112,894
Tags: constructive algorithms, greedy Correct Solution: ``` a=int(input()) red=0 blue=0 li=[] if a==2: input() print(11) else: Evenprnths=input() for elem in Evenprnths: if elem =="(": #todo add this to the one having least open parantheses of if draw then red if red>blue...
output
1
56,447
21
112,895
Provide tags and a correct Python 3 solution for this coding contest problem. A string is called bracket sequence if it does not contain any characters other than "(" and ")". A bracket sequence is called regular (shortly, RBS) if it is possible to obtain correct arithmetic expression by inserting characters "+" and "...
instruction
0
56,448
21
112,896
Tags: constructive algorithms, greedy Correct Solution: ``` import os import sys from io import BytesIO, IOBase BUFSIZE = 8192 class FastIO(IOBase): newlines = 0 def __init__(self, file): self._fd = file.fileno() self.buffer = BytesIO() self.writable = "x" in file.mode or "r" not in ...
output
1
56,448
21
112,897
Provide tags and a correct Python 3 solution for this coding contest problem. A string is called bracket sequence if it does not contain any characters other than "(" and ")". A bracket sequence is called regular (shortly, RBS) if it is possible to obtain correct arithmetic expression by inserting characters "+" and "...
instruction
0
56,449
21
112,898
Tags: constructive algorithms, greedy Correct Solution: ``` n = int(input()) l = input() r = 0 b = 0 maxb = 0 for j in range(n): if(l[j]=='('): if(r>b): b+=1 print("1",end="") else: r+=1 print("0",end="") else: if(r<b): b-=1 print("1",end="") else: r-=1 print("0",end="") print() ```
output
1
56,449
21
112,899
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. A string is called bracket sequence if it does not contain any characters other than "(" and ")". A bracket sequence is called regular (shortly, RBS) if it is possible to obtain correct arithmet...
instruction
0
56,450
21
112,900
Yes
output
1
56,450
21
112,901