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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string a, consisting of n characters, n is even. For each i from 1 to n a_i is one of 'A', 'B' or 'C'. A bracket sequence is a string containing only characters "(" and ")". A r...
instruction
0
21,435
21
42,870
Yes
output
1
21,435
21
42,871
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string a, consisting of n characters, n is even. For each i from 1 to n a_i is one of 'A', 'B' or 'C'. A bracket sequence is a string containing only characters "(" and ")". A r...
instruction
0
21,436
21
42,872
Yes
output
1
21,436
21
42,873
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string a, consisting of n characters, n is even. For each i from 1 to n a_i is one of 'A', 'B' or 'C'. A bracket sequence is a string containing only characters "(" and ")". A r...
instruction
0
21,437
21
42,874
Yes
output
1
21,437
21
42,875
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string a, consisting of n characters, n is even. For each i from 1 to n a_i is one of 'A', 'B' or 'C'. A bracket sequence is a string containing only characters "(" and ")". A r...
instruction
0
21,438
21
42,876
Yes
output
1
21,438
21
42,877
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string a, consisting of n characters, n is even. For each i from 1 to n a_i is one of 'A', 'B' or 'C'. A bracket sequence is a string containing only characters "(" and ")". A r...
instruction
0
21,439
21
42,878
No
output
1
21,439
21
42,879
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string a, consisting of n characters, n is even. For each i from 1 to n a_i is one of 'A', 'B' or 'C'. A bracket sequence is a string containing only characters "(" and ")". A r...
instruction
0
21,440
21
42,880
No
output
1
21,440
21
42,881
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string a, consisting of n characters, n is even. For each i from 1 to n a_i is one of 'A', 'B' or 'C'. A bracket sequence is a string containing only characters "(" and ")". A r...
instruction
0
21,441
21
42,882
No
output
1
21,441
21
42,883
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string a, consisting of n characters, n is even. For each i from 1 to n a_i is one of 'A', 'B' or 'C'. A bracket sequence is a string containing only characters "(" and ")". A r...
instruction
0
21,442
21
42,884
No
output
1
21,442
21
42,885
Provide tags and a correct Python 3 solution for this coding contest problem. A bracket sequence is a string, containing only characters "(", ")", "[" and "]". A correct bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression by inserting characters "1" and "+" between the ...
instruction
0
24,096
21
48,192
Tags: data structures, expression parsing, implementation Correct Solution: ``` '''input ((()))([] ''' from sys import stdin def check_valid(string): stack = [] for i in string: if i in ['(', '[']: stack.append(i) elif i == ')': if len(stack) > 0: if stack[-1] == '(': stack.pop() continue ...
output
1
24,096
21
48,193
Provide tags and a correct Python 3 solution for this coding contest problem. A bracket sequence is a string, containing only characters "(", ")", "[" and "]". A correct bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression by inserting characters "1" and "+" between the ...
instruction
0
24,097
21
48,194
Tags: data structures, expression parsing, implementation Correct Solution: ``` import sys import math import string import operator import functools import fractions import collections sys.setrecursionlimit(10**7) dX= [-1, 1, 0, 0,-1, 1,-1, 1] dY= [ 0, 0,-1, 1, 1,-1,-1, 1] RI=lambda: list(map(int,input().split())) RS=...
output
1
24,097
21
48,195
Provide tags and a correct Python 3 solution for this coding contest problem. A bracket sequence is a string, containing only characters "(", ")", "[" and "]". A correct bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression by inserting characters "1" and "+" between the ...
instruction
0
24,098
21
48,196
Tags: data structures, expression parsing, implementation Correct Solution: ``` string = list(input()) d, p = [], set(range(len(string))) for j, q in enumerate(string): if q in '([': d.append((j,q)) elif d: i, x = d.pop() if x+q in '(][)': d = [] else: p -= {i, j} n, s = 0, '' for i i...
output
1
24,098
21
48,197
Provide tags and a correct Python 3 solution for this coding contest problem. A bracket sequence is a string, containing only characters "(", ")", "[" and "]". A correct bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression by inserting characters "1" and "+" between the ...
instruction
0
24,099
21
48,198
Tags: data structures, expression parsing, implementation Correct Solution: ``` import os import sys from io import BytesIO, IOBase BUFSIZE = 8192 class FastIO(IOBase): newlines = 0 def __init__(self, file): self._fd = file.fileno() self.buffer = BytesIO() self.writable = "x" in file.m...
output
1
24,099
21
48,199
Provide tags and a correct Python 3 solution for this coding contest problem. A bracket sequence is a string, containing only characters "(", ")", "[" and "]". A correct bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression by inserting characters "1" and "+" between the ...
instruction
0
24,100
21
48,200
Tags: data structures, expression parsing, implementation Correct Solution: ``` t = list(input()) d, p = [], set(range(len(t))) for j, q in enumerate(t): if q in '([': d.append((q, j)) elif d: x, i = d.pop() if x + q in '(][)': d = [] else: p -= {i, j} for i in p: t[i] = ' ' n, s = 0, ''...
output
1
24,100
21
48,201
Provide tags and a correct Python 3 solution for this coding contest problem. A bracket sequence is a string, containing only characters "(", ")", "[" and "]". A correct bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression by inserting characters "1" and "+" between the ...
instruction
0
24,101
21
48,202
Tags: data structures, expression parsing, implementation Correct Solution: ``` s, st, v, vi, vj, vc = input(), [], [], 0, 0, 0 for i, ch in enumerate(s): if ch == "[" or ch == "(": st.append(i) else: if st and s[st[-1]] + ch in ('()', '[]'): b = (st[-1], i + 1) if v and ...
output
1
24,101
21
48,203
Provide tags and a correct Python 3 solution for this coding contest problem. A bracket sequence is a string, containing only characters "(", ")", "[" and "]". A correct bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression by inserting characters "1" and "+" between the ...
instruction
0
24,102
21
48,204
Tags: data structures, expression parsing, implementation Correct Solution: ``` s = input() a = [] for i in range(len(s)): if len(a) != 0 and ((s[a[-1]] == '(' and s[i] == ')') or (s[a[-1]] == '[' and s[i] == ']')): a.pop() else: a.append(i) if len(a) == 0: print(s.count('[')) print(s) e...
output
1
24,102
21
48,205
Provide tags and a correct Python 3 solution for this coding contest problem. A bracket sequence is a string, containing only characters "(", ")", "[" and "]". A correct bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression by inserting characters "1" and "+" between the ...
instruction
0
24,103
21
48,206
Tags: data structures, expression parsing, implementation Correct Solution: ``` S=input().strip() subIndex=[] for i in range(len(S)): if len(subIndex)!=0 and (((S[subIndex[-1]]=='[' and S[i]==']') or (S[subIndex[-1]]=='(' and S[i]==')'))): subIndex.pop() else: subIndex.append(i) 'tamamı dogru...
output
1
24,103
21
48,207
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. A bracket sequence is a string, containing only characters "(", ")", "[" and "]". A correct bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression b...
instruction
0
24,104
21
48,208
Yes
output
1
24,104
21
48,209
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. A bracket sequence is a string, containing only characters "(", ")", "[" and "]". A correct bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression b...
instruction
0
24,105
21
48,210
Yes
output
1
24,105
21
48,211
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. A bracket sequence is a string, containing only characters "(", ")", "[" and "]". A correct bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression b...
instruction
0
24,106
21
48,212
Yes
output
1
24,106
21
48,213
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. A bracket sequence is a string, containing only characters "(", ")", "[" and "]". A correct bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression b...
instruction
0
24,107
21
48,214
Yes
output
1
24,107
21
48,215
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. A bracket sequence is a string, containing only characters "(", ")", "[" and "]". A correct bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression b...
instruction
0
24,108
21
48,216
No
output
1
24,108
21
48,217
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. A bracket sequence is a string, containing only characters "(", ")", "[" and "]". A correct bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression b...
instruction
0
24,109
21
48,218
No
output
1
24,109
21
48,219
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. A bracket sequence is a string, containing only characters "(", ")", "[" and "]". A correct bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression b...
instruction
0
24,110
21
48,220
No
output
1
24,110
21
48,221
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. A bracket sequence is a string, containing only characters "(", ")", "[" and "]". A correct bracket sequence is a bracket sequence that can be transformed into a correct arithmetic expression b...
instruction
0
24,111
21
48,222
No
output
1
24,111
21
48,223
Provide a correct Python 3 solution for this coding contest problem. The Balance of the World The world should be finely balanced. Positive vs. negative, light vs. shadow, and left vs. right brackets. Your mission is to write a program that judges whether a string is balanced with respect to brackets so that we can o...
instruction
0
24,688
21
49,376
"Correct Solution: ``` def is_balanced(s): stack = [] for c in s: if c == '(' or c == '[': stack.append(c) elif c == ')': if not stack: return "no" elif stack[-1] == '(': stack.pop() else: return "no"...
output
1
24,688
21
49,377
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The Balance of the World The world should be finely balanced. Positive vs. negative, light vs. shadow, and left vs. right brackets. Your mission is to write a program that judges whether a stri...
instruction
0
24,689
21
49,378
No
output
1
24,689
21
49,379
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The Balance of the World The world should be finely balanced. Positive vs. negative, light vs. shadow, and left vs. right brackets. Your mission is to write a program that judges whether a stri...
instruction
0
24,690
21
49,380
No
output
1
24,690
21
49,381
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The Balance of the World The world should be finely balanced. Positive vs. negative, light vs. shadow, and left vs. right brackets. Your mission is to write a program that judges whether a stri...
instruction
0
24,691
21
49,382
No
output
1
24,691
21
49,383
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The Balance of the World The world should be finely balanced. Positive vs. negative, light vs. shadow, and left vs. right brackets. Your mission is to write a program that judges whether a stri...
instruction
0
24,692
21
49,384
No
output
1
24,692
21
49,385
Provide tags and a correct Python 3 solution for this coding contest problem. This is yet another problem on regular bracket sequences. A bracket sequence is called regular, if by inserting "+" and "1" into it we get a correct mathematical expression. For example, sequences "(())()", "()" and "(()(()))" are regular, ...
instruction
0
25,955
21
51,910
Tags: greedy Correct Solution: ``` from heapq import * k = d = 0 s, h = [], [] for i, q in enumerate(input()): if q == '?': q = ')' x, y = map(int, input().split()) d += y heappush(h, (x - y, i)) s.append(q) if q == '(': k += 1 elif k: k -= 1 elif h: k = 1 ...
output
1
25,955
21
51,911
Provide tags and a correct Python 3 solution for this coding contest problem. This is yet another problem on regular bracket sequences. A bracket sequence is called regular, if by inserting "+" and "1" into it we get a correct mathematical expression. For example, sequences "(())()", "()" and "(()(()))" are regular, ...
instruction
0
25,956
21
51,912
Tags: greedy Correct Solution: ``` """ Codeforces 3D - Least Cost Bracket Sequence http://codeforces.com/problemset/problem/3/D Héctor González Belver ../07/2018 """ import sys import heapq def main(): cost = [] pattern = sys.stdin.readline().strip() unknown = pattern.count('?') cost = [tuple(int(c) for c in ...
output
1
25,956
21
51,913
Provide tags and a correct Python 3 solution for this coding contest problem. This is yet another problem on regular bracket sequences. A bracket sequence is called regular, if by inserting "+" and "1" into it we get a correct mathematical expression. For example, sequences "(())()", "()" and "(()(()))" are regular, ...
instruction
0
25,957
21
51,914
Tags: greedy Correct Solution: ``` import heapq s = input() l = len(s) cnt = 0 for i in range(l): if s[i] == '?': cnt += 1 a = [] for i in range(cnt): a.append(list(map(int, input().split()))) idx = 0 res = 0 left = 0 b = [] p = [0] * len(a) ans = True for i in range(l): if s[i] == '(': left...
output
1
25,957
21
51,915
Provide tags and a correct Python 3 solution for this coding contest problem. This is yet another problem on regular bracket sequences. A bracket sequence is called regular, if by inserting "+" and "1" into it we get a correct mathematical expression. For example, sequences "(())()", "()" and "(()(()))" are regular, ...
instruction
0
25,958
21
51,916
Tags: greedy Correct Solution: ``` __author__ = 'Darren' def solve(): import sys stdin = sys.stdin if True else open('data') from heapq import heappush, heappop seq = [c for c in next(stdin).strip()] n = len(seq) if n % 2 == 1: print(-1) return min_heap = [] balance, ...
output
1
25,958
21
51,917
Provide tags and a correct Python 3 solution for this coding contest problem. This is yet another problem on regular bracket sequences. A bracket sequence is called regular, if by inserting "+" and "1" into it we get a correct mathematical expression. For example, sequences "(())()", "()" and "(()(()))" are regular, ...
instruction
0
25,959
21
51,918
Tags: greedy Correct Solution: ``` import heapq s = list(input()) new_s, cost, opens, opens_i = str(), 0, 0, list() for i in range(len(s)): opens += int(s[i] == '(') - int(s[i] != '(') if s[i] == '?': a, b = [int(i) for i in input().split()] s[i] = ')' heapq.heappush(opens_i, [-b + ...
output
1
25,959
21
51,919
Provide tags and a correct Python 3 solution for this coding contest problem. This is yet another problem on regular bracket sequences. A bracket sequence is called regular, if by inserting "+" and "1" into it we get a correct mathematical expression. For example, sequences "(())()", "()" and "(()(()))" are regular, ...
instruction
0
25,960
21
51,920
Tags: greedy Correct Solution: ``` import heapq s = input() sl = list(s) ct = 0 cost = 0 flag = True h = [] for i,c in enumerate(s): if c == '(': ct+=1 elif c == ')': ct-=1 else: l,r = map(int,input().split()) sl[i] = ')' cost += r ct-=1 heapq.heappus...
output
1
25,960
21
51,921
Provide tags and a correct Python 3 solution for this coding contest problem. This is yet another problem on regular bracket sequences. A bracket sequence is called regular, if by inserting "+" and "1" into it we get a correct mathematical expression. For example, sequences "(())()", "()" and "(()(()))" are regular, ...
instruction
0
25,961
21
51,922
Tags: greedy Correct Solution: ``` from heapq import * #priority queue #see healp(heapq) def CF_3D(): line=input() n=line.count('?') sequence=list(line) bracket=[] for i in range(n): bracket.append(list(map(int,input().split()))) index=0 cost=0 balance=0 heap=[] f...
output
1
25,961
21
51,923
Provide tags and a correct Python 3 solution for this coding contest problem. This is yet another problem on regular bracket sequences. A bracket sequence is called regular, if by inserting "+" and "1" into it we get a correct mathematical expression. For example, sequences "(())()", "()" and "(()(()))" are regular, ...
instruction
0
25,962
21
51,924
Tags: greedy Correct Solution: ``` from heapq import heappush, heappop ans=b=0 d=[] s=list(input()) for i in range(len(s)): if s[i]=='(': b+=1 elif s[i]==')': b-=1 else: c=list(map(int,input().split())) s[i]=')' b-=1 heappush(d,(c[0]-c[1],i)) ans+=c[...
output
1
25,962
21
51,925
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. This is yet another problem on regular bracket sequences. A bracket sequence is called regular, if by inserting "+" and "1" into it we get a correct mathematical expression. For example, sequen...
instruction
0
25,963
21
51,926
Yes
output
1
25,963
21
51,927
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. This is yet another problem on regular bracket sequences. A bracket sequence is called regular, if by inserting "+" and "1" into it we get a correct mathematical expression. For example, sequen...
instruction
0
25,964
21
51,928
Yes
output
1
25,964
21
51,929
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. This is yet another problem on regular bracket sequences. A bracket sequence is called regular, if by inserting "+" and "1" into it we get a correct mathematical expression. For example, sequen...
instruction
0
25,965
21
51,930
Yes
output
1
25,965
21
51,931
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. This is yet another problem on regular bracket sequences. A bracket sequence is called regular, if by inserting "+" and "1" into it we get a correct mathematical expression. For example, sequen...
instruction
0
25,966
21
51,932
Yes
output
1
25,966
21
51,933
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. This is yet another problem on regular bracket sequences. A bracket sequence is called regular, if by inserting "+" and "1" into it we get a correct mathematical expression. For example, sequen...
instruction
0
25,967
21
51,934
No
output
1
25,967
21
51,935
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. This is yet another problem on regular bracket sequences. A bracket sequence is called regular, if by inserting "+" and "1" into it we get a correct mathematical expression. For example, sequen...
instruction
0
25,968
21
51,936
No
output
1
25,968
21
51,937
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. This is yet another problem on regular bracket sequences. A bracket sequence is called regular, if by inserting "+" and "1" into it we get a correct mathematical expression. For example, sequen...
instruction
0
25,969
21
51,938
No
output
1
25,969
21
51,939
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. This is yet another problem on regular bracket sequences. A bracket sequence is called regular, if by inserting "+" and "1" into it we get a correct mathematical expression. For example, sequen...
instruction
0
25,970
21
51,940
No
output
1
25,970
21
51,941
Provide tags and a correct Python 3 solution for this coding contest problem. Petya's friends made him a birthday present — a bracket sequence. Petya was quite disappointed with his gift, because he dreamed of correct bracket sequence, yet he told his friends nothing about his dreams and decided to fix present himself...
instruction
0
30,145
21
60,290
Tags: data structures, greedy Correct Solution: ``` def read(): n = int(input()) s = input() return n, s def solve(n, s): st = [s[0]] for i in range(1, n): if s[i] == "(": st.append(s[i]) else: if len(st) == 0: st.append(s[i]) eli...
output
1
30,145
21
60,291
Provide tags and a correct Python 3 solution for this coding contest problem. Petya's friends made him a birthday present — a bracket sequence. Petya was quite disappointed with his gift, because he dreamed of correct bracket sequence, yet he told his friends nothing about his dreams and decided to fix present himself...
instruction
0
30,146
21
60,292
Tags: data structures, greedy Correct Solution: ``` import sys import collections import functools n = int(input().strip()) s = input().strip() stack, s2 = [], [] for i in s: if i == "(": stack.append(i) elif i == ")" and stack and stack[-1] == "(": stack.pop() else: s2.append(i) ...
output
1
30,146
21
60,293
Provide tags and a correct Python 3 solution for this coding contest problem. Petya's friends made him a birthday present — a bracket sequence. Petya was quite disappointed with his gift, because he dreamed of correct bracket sequence, yet he told his friends nothing about his dreams and decided to fix present himself...
instruction
0
30,147
21
60,294
Tags: data structures, greedy Correct Solution: ``` from collections import Counter n = int(input()) bra = input() d=Counter(bra) ans=0 if d['(']==d[')']: c=0 for i in bra: if i=='(': c+=1 else: if c==0: ans+=1 else: c-=1 ...
output
1
30,147
21
60,295
Provide tags and a correct Python 3 solution for this coding contest problem. Petya's friends made him a birthday present — a bracket sequence. Petya was quite disappointed with his gift, because he dreamed of correct bracket sequence, yet he told his friends nothing about his dreams and decided to fix present himself...
instruction
0
30,148
21
60,296
Tags: data structures, greedy Correct Solution: ``` def countbrackets(string): if string.replace("(", "").replace(")", ""): return None string = [x == '(' for x in string] bopen, extraclose = 0, 0 for x in string: if x: bopen += 1 else: if bopen == 0: extraclose += 1 ...
output
1
30,148
21
60,297
Provide tags and a correct Python 3 solution for this coding contest problem. Petya's friends made him a birthday present — a bracket sequence. Petya was quite disappointed with his gift, because he dreamed of correct bracket sequence, yet he told his friends nothing about his dreams and decided to fix present himself...
instruction
0
30,149
21
60,298
Tags: data structures, greedy Correct Solution: ``` def solution(): from sys import stdout, stdin _input, _print = stdin.readline, stdout.write _int, _range, _min, _max = int, range, min, max n = int(input()) arr = [1 if i == '(' else -1 for i in input()] if sum(arr) != 0: print("No") ...
output
1
30,149
21
60,299