message stringlengths 2 15.4k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 45 107k | cluster float64 21 21 | __index_level_0__ int64 90 214k |
|---|---|---|---|---|---|
Provide a correct Python 3 solution for this coding contest problem.
B: Parentheses Number
problem
Define the correct parenthesis string as follows:
* The empty string is the correct parenthesis string
* For the correct parenthesis string S, `(` S `)` is the correct parenthesis string
* For correct parentheses S, T... | instruction | 0 | 7,501 | 21 | 15,002 |
"Correct Solution:
```
n = int(input())
a = list(map(int,input().split()))
cnt = 0
ans = ''
st = list()
for x in a:
while cnt < x:
ans += '('
cnt += 1
st.append(cnt)
if st[-1] == x:
st.pop()
ans += ')'
else:
ans = ':('
break
print(ans)
``` | output | 1 | 7,501 | 21 | 15,003 |
Provide a correct Python 3 solution for this coding contest problem.
B: Parentheses Number
problem
Define the correct parenthesis string as follows:
* The empty string is the correct parenthesis string
* For the correct parenthesis string S, `(` S `)` is the correct parenthesis string
* For correct parentheses S, T... | instruction | 0 | 7,502 | 21 | 15,004 |
"Correct Solution:
```
from collections import deque
import sys
sys.setrecursionlimit(10**7)
N = int(input())
P = list(map(int,input().split()))
Q = [-1]*N
for i,p in enumerate(P):
Q[p-1] = i
S = ''
a = 1
def rec(l,r):
global S,a
if l==r:
return
while l < r:
ai = Q[a-1]
if ai ... | output | 1 | 7,502 | 21 | 15,005 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are fed up with your messy room, so you decided to clean it up.
Your room is a bracket sequence s=s_{1}s_{2}... s_{n} of length n. Each character of this string is either an opening bracket '(' or a closing bracket ')'.
In one operatio... | instruction | 0 | 7,671 | 21 | 15,342 |
Tags: constructive algorithms
Correct Solution:
```
for _ in range(int(input())):
n, k = tuple(map(int, input().split()))
s = list(input())
ans = list("()" * (k - 1) + "(" * ((n // 2) - k + 1) + ")" * (n // 2 - k + 1))
ops = []
i = 0
while ans != s and i < n:
# print("----" , i, "----")
... | output | 1 | 7,671 | 21 | 15,343 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are fed up with your messy room, so you decided to clean it up.
Your room is a bracket sequence s=s_{1}s_{2}... s_{n} of length n. Each character of this string is either an opening bracket '(' or a closing bracket ')'.
In one operatio... | instruction | 0 | 7,672 | 21 | 15,344 |
Tags: constructive algorithms
Correct Solution:
```
t = int(input())
for test_i in range(t):
n, k = map(int, input().split())
s = list(input())
ans = []
for i in range(k - 1):
if s[2 * i] != '(':
i0 = s.index('(', 2 * i)
ans.append((2 * i + 1, i0 + 1))
s[2 * i... | output | 1 | 7,672 | 21 | 15,345 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are fed up with your messy room, so you decided to clean it up.
Your room is a bracket sequence s=s_{1}s_{2}... s_{n} of length n. Each character of this string is either an opening bracket '(' or a closing bracket ')'.
In one operatio... | instruction | 0 | 7,673 | 21 | 15,346 |
Tags: constructive algorithms
Correct Solution:
```
for _ in range(int(input())):
n, k = map(int, input().split())
s = list(input().strip())
d = '()' * (k-1) + '('*(n//2-k+1) + ')'*(n//2-k+1)
res = []
for i in range(n):
if s[i] != d[i]:
j = s.index(d[i], i)
res.append... | output | 1 | 7,673 | 21 | 15,347 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are fed up with your messy room, so you decided to clean it up.
Your room is a bracket sequence s=s_{1}s_{2}... s_{n} of length n. Each character of this string is either an opening bracket '(' or a closing bracket ')'.
In one operatio... | instruction | 0 | 7,674 | 21 | 15,348 |
Tags: constructive algorithms
Correct Solution:
```
import sys
t=int(sys.stdin.readline())
def findopen(i,s,n):
for j in range(i,n):
if s[j]=='(':
return j
def findclose(i,s,n):
for j in range(i,n):
if s[j]==')':
return j
for _ in range(t):
n,k=map(int,sys.stdin.readl... | output | 1 | 7,674 | 21 | 15,349 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are fed up with your messy room, so you decided to clean it up.
Your room is a bracket sequence s=s_{1}s_{2}... s_{n} of length n. Each character of this string is either an opening bracket '(' or a closing bracket ')'.
In one operatio... | instruction | 0 | 7,675 | 21 | 15,350 |
Tags: constructive algorithms
Correct Solution:
```
#Code by Sounak, IIESTS
#------------------------------warmup----------------------------
import os
import sys
import math
from io import BytesIO, IOBase
from fractions import Fraction
from collections import defaultdict
from itertools import permutations
BUFSIZE ... | output | 1 | 7,675 | 21 | 15,351 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are fed up with your messy room, so you decided to clean it up.
Your room is a bracket sequence s=s_{1}s_{2}... s_{n} of length n. Each character of this string is either an opening bracket '(' or a closing bracket ')'.
In one operatio... | instruction | 0 | 7,676 | 21 | 15,352 |
Tags: constructive algorithms
Correct Solution:
```
def openBracket(i):
global firstOpen, ans
ind = index[0][firstOpen]
a = s[i: ind + 1]
a.reverse()
#print(i + 1, ind + 1)
s[i: ind + 1] = a
ans += [[i + 1, ind + 1]]
firstOpen += 1
def closeBracket(i):
global firstClose, ans
... | output | 1 | 7,676 | 21 | 15,353 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are fed up with your messy room, so you decided to clean it up.
Your room is a bracket sequence s=s_{1}s_{2}... s_{n} of length n. Each character of this string is either an opening bracket '(' or a closing bracket ')'.
In one operatio... | instruction | 0 | 7,677 | 21 | 15,354 |
Tags: constructive algorithms
Correct Solution:
```
t = int(input())
for request in range(t):
n, k = map(int, input().split())
box = list(input())
pattern = '()' * (k - 1) + '(' + ('()' * ((n - (k) * 2) // 2) ) + ')'
changes = []
for i in range(n):
if box[i] != pattern[i]:
for j ... | output | 1 | 7,677 | 21 | 15,355 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are fed up with your messy room, so you decided to clean it up.
Your room is a bracket sequence s=s_{1}s_{2}... s_{n} of length n. Each character of this string is either an opening bracket '(' or a closing bracket ')'.
In one operatio... | instruction | 0 | 7,678 | 21 | 15,356 |
Tags: constructive algorithms
Correct Solution:
```
def newstroka(f,a):
pp = f
new = []
ss = 0
for i in range(0,a,2):
if f==0:
ss=i
break
else:
f-=1
new.append("(")
new.append(")")
if pp+1!=a//2+1:
... | output | 1 | 7,678 | 21 | 15,357 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are fed up with your messy room, so you decided to clean it up.
Your room is a bracket sequence s=s_{1}s_{2}... s_{n} of length n. Each character of this string is either an opening bracket... | instruction | 0 | 7,679 | 21 | 15,358 |
Yes | output | 1 | 7,679 | 21 | 15,359 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are fed up with your messy room, so you decided to clean it up.
Your room is a bracket sequence s=s_{1}s_{2}... s_{n} of length n. Each character of this string is either an opening bracket... | instruction | 0 | 7,680 | 21 | 15,360 |
Yes | output | 1 | 7,680 | 21 | 15,361 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are fed up with your messy room, so you decided to clean it up.
Your room is a bracket sequence s=s_{1}s_{2}... s_{n} of length n. Each character of this string is either an opening bracket... | instruction | 0 | 7,681 | 21 | 15,362 |
Yes | output | 1 | 7,681 | 21 | 15,363 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are fed up with your messy room, so you decided to clean it up.
Your room is a bracket sequence s=s_{1}s_{2}... s_{n} of length n. Each character of this string is either an opening bracket... | instruction | 0 | 7,682 | 21 | 15,364 |
Yes | output | 1 | 7,682 | 21 | 15,365 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are fed up with your messy room, so you decided to clean it up.
Your room is a bracket sequence s=s_{1}s_{2}... s_{n} of length n. Each character of this string is either an opening bracket... | instruction | 0 | 7,683 | 21 | 15,366 |
No | output | 1 | 7,683 | 21 | 15,367 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are fed up with your messy room, so you decided to clean it up.
Your room is a bracket sequence s=s_{1}s_{2}... s_{n} of length n. Each character of this string is either an opening bracket... | instruction | 0 | 7,684 | 21 | 15,368 |
No | output | 1 | 7,684 | 21 | 15,369 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are fed up with your messy room, so you decided to clean it up.
Your room is a bracket sequence s=s_{1}s_{2}... s_{n} of length n. Each character of this string is either an opening bracket... | instruction | 0 | 7,685 | 21 | 15,370 |
No | output | 1 | 7,685 | 21 | 15,371 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are fed up with your messy room, so you decided to clean it up.
Your room is a bracket sequence s=s_{1}s_{2}... s_{n} of length n. Each character of this string is either an opening bracket... | instruction | 0 | 7,686 | 21 | 15,372 |
No | output | 1 | 7,686 | 21 | 15,373 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A balanced bracket sequence is defined as an integer sequence that can be built with the following rules:
* The empty sequence is balanced.
* If [a_1,β¦,a_n] and [b_1,β¦, b_m] are balanced, ... | instruction | 0 | 7,796 | 21 | 15,592 |
No | output | 1 | 7,796 | 21 | 15,593 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A balanced bracket sequence is defined as an integer sequence that can be built with the following rules:
* The empty sequence is balanced.
* If [a_1,β¦,a_n] and [b_1,β¦, b_m] are balanced, ... | instruction | 0 | 7,797 | 21 | 15,594 |
No | output | 1 | 7,797 | 21 | 15,595 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A balanced bracket sequence is defined as an integer sequence that can be built with the following rules:
* The empty sequence is balanced.
* If [a_1,β¦,a_n] and [b_1,β¦, b_m] are balanced, ... | instruction | 0 | 7,798 | 21 | 15,596 |
No | output | 1 | 7,798 | 21 | 15,597 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A balanced bracket sequence is defined as an integer sequence that can be built with the following rules:
* The empty sequence is balanced.
* If [a_1,β¦,a_n] and [b_1,β¦, b_m] are balanced, ... | instruction | 0 | 7,799 | 21 | 15,598 |
No | output | 1 | 7,799 | 21 | 15,599 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is a harder version of the problem. In this version, n β€ 300 000.
Vasya is an experienced developer of programming competitions' problems. As all great minds at some time, Vasya faced a creative crisis. To improve the situation, Petya ... | instruction | 0 | 8,456 | 21 | 16,912 |
Tags: implementation
Correct Solution:
```
n = int(input())
s = input()
r = 0
l = n-1
root = []
buf = []
to_the_right = True
for count in range(n):
if to_the_right:
i = r
r += 1
else:
i = l
l -= 1
b = s[i]
if b == '(':
if len(buf) == 0 or buf[-1][0] != -1:
... | output | 1 | 8,456 | 21 | 16,913 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is a harder version of the problem. In this version, n β€ 300 000.
Vasya is an experienced developer of programming competitions' problems. As all great minds at some time, Vasya faced a creative crisis. To improve the situation, Petya ... | instruction | 0 | 8,457 | 21 | 16,914 |
Tags: implementation
Correct Solution:
```
n = int(input())
ddd = input()
d = [0]
for dd in ddd:
if dd == '(':
d.append(d[-1] + 1)
else:
d.append(d[-1] - 1)
if d[-1] != 0:
print("0\n1 1")
exit(0)
d.pop()
mn = min(d)
ind = d.index(mn)
d = d[ind:] + d[:ind]
d = [i - mn for i in d]
fi = ... | output | 1 | 8,457 | 21 | 16,915 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is a harder version of the problem. In this version, n β€ 300 000.
Vasya is an experienced developer of programming competitions' problems. As all great minds at some time, Vasya faced a creative crisis. To improve the situation, Petya ... | instruction | 0 | 8,458 | 21 | 16,916 |
Tags: implementation
Correct Solution:
```
n = int(input().strip())
s= input().strip()
ss= 0
mina = 0
ti = 0
for k in range(len(s)):
if(s[k] == "("):
ss+=1
else:
ss-=1
if(ss<0):
ti = k+1
ss = 0
s=s[ti:]+s[:ti]
#print(s)
ss= 0
for k in range(len(s)):
if(s[k] == "("):
... | output | 1 | 8,458 | 21 | 16,917 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is a harder version of the problem. In this version, n β€ 300 000.
Vasya is an experienced developer of programming competitions' problems. As all great minds at some time, Vasya faced a cr... | instruction | 0 | 8,459 | 21 | 16,918 |
No | output | 1 | 8,459 | 21 | 16,919 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is a harder version of the problem. In this version, n β€ 300 000.
Vasya is an experienced developer of programming competitions' problems. As all great minds at some time, Vasya faced a cr... | instruction | 0 | 8,460 | 21 | 16,920 |
No | output | 1 | 8,460 | 21 | 16,921 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is a harder version of the problem. In this version, n β€ 300 000.
Vasya is an experienced developer of programming competitions' problems. As all great minds at some time, Vasya faced a cr... | instruction | 0 | 8,461 | 21 | 16,922 |
No | output | 1 | 8,461 | 21 | 16,923 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s, consisting of brackets of two types: '(', ')', '[' and ']'.
A string is called a regular bracket sequence (RBS) if it's of one of the following types:
* empty string;
* '(' + RBS + ')';
* '[' + RBS + ']';... | instruction | 0 | 16,994 | 21 | 33,988 |
Tags: greedy
Correct Solution:
```
t = int(input())
for _ in range(t):
s = input()
zso = kso = sum = 0
for i in range(len(s)):
if s[i] == "(":
zso += 1
elif s[i] == "[":
kso += 1
elif s[i] == ")" and zso > 0:
zso -= 1
sum += 1
e... | output | 1 | 16,994 | 21 | 33,989 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s, consisting of brackets of two types: '(', ')', '[' and ']'.
A string is called a regular bracket sequence (RBS) if it's of one of the following types:
* empty string;
* '(' + RBS + ')';
* '[' + RBS + ']';... | instruction | 0 | 16,995 | 21 | 33,990 |
Tags: greedy
Correct Solution:
```
t = int(input())
for _ in range(t):
s = input().strip()
curr0 = 0
num0 = 0
curr1 = 0
num1 = 0
for y in s:
if y == '(':
curr0 += 1
elif y == '[':
curr1 += 1
elif y == ')':
if curr0 > 0:
... | output | 1 | 16,995 | 21 | 33,991 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s, consisting of brackets of two types: '(', ')', '[' and ']'.
A string is called a regular bracket sequence (RBS) if it's of one of the following types:
* empty string;
* '(' + RBS + ')';
* '[' + RBS + ']';... | instruction | 0 | 16,996 | 21 | 33,992 |
Tags: greedy
Correct Solution:
```
import math
for _ in range(int(input())):
#n = int(input())
ar = list(input())
o1,o2,c1,c2 = 0,0,0,0
count = 0
for i in ar:
if i == '[':
o1 +=1
elif i == ']' and o1>0:
count +=1
o1-=1
for i in ar:
i... | output | 1 | 16,996 | 21 | 33,993 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s, consisting of brackets of two types: '(', ')', '[' and ']'.
A string is called a regular bracket sequence (RBS) if it's of one of the following types:
* empty string;
* '(' + RBS + ')';
* '[' + RBS + ']';... | instruction | 0 | 16,997 | 21 | 33,994 |
Tags: greedy
Correct Solution:
```
for _ in range(int(input())):
t = input()
x, y, a = 0, 0, 0
for ch in t:
if ch == '(': x += 1
if ch == '[': y += 1
if ch == ')' and x:
a += 1
x -= 1
if ch == ']' and y:
a += 1
y -= 1
print... | output | 1 | 16,997 | 21 | 33,995 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s, consisting of brackets of two types: '(', ')', '[' and ']'.
A string is called a regular bracket sequence (RBS) if it's of one of the following types:
* empty string;
* '(' + RBS + ')';
* '[' + RBS + ']';... | instruction | 0 | 16,998 | 21 | 33,996 |
Tags: greedy
Correct Solution:
```
#: Author - Soumya Saurav
import sys,io,os,time
from collections import defaultdict
from collections import Counter
from collections import deque
from itertools import combinations
from itertools import permutations
import bisect,math,heapq
alphabet = "abcdefghijklmnopqrstuvwxyz"
#in... | output | 1 | 16,998 | 21 | 33,997 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s, consisting of brackets of two types: '(', ')', '[' and ']'.
A string is called a regular bracket sequence (RBS) if it's of one of the following types:
* empty string;
* '(' + RBS + ')';
* '[' + RBS + ']';... | instruction | 0 | 16,999 | 21 | 33,998 |
Tags: greedy
Correct Solution:
```
for i in range(int(input())):
x,y,c=0,0,0
for i in input():
if i=='(': x+=1
elif i==')' and x: x-=1;c+=1
elif i=='[': y+=1
elif i==']' and y: y-=1;c+=1
print(c)
``` | output | 1 | 16,999 | 21 | 33,999 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s, consisting of brackets of two types: '(', ')', '[' and ']'.
A string is called a regular bracket sequence (RBS) if it's of one of the following types:
* empty string;
* '(' + RBS + ')';
* '[' + RBS + ']';... | instruction | 0 | 17,000 | 21 | 34,000 |
Tags: greedy
Correct Solution:
```
def solve(string):
p_stack = []
s_stack = []
res = 0
for ch in string:
if ch == "(":
p_stack.append(1)
elif len(p_stack) != 0 and ch == ")":
p_stack.pop()
res += 1
if ch == "[":
s_stack.append... | output | 1 | 17,000 | 21 | 34,001 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s, consisting of brackets of two types: '(', ')', '[' and ']'.
A string is called a regular bracket sequence (RBS) if it's of one of the following types:
* empty string;
* '(' + RBS + ')';
* '[' + RBS + ']';... | instruction | 0 | 17,001 | 21 | 34,002 |
Tags: greedy
Correct Solution:
```
import math
t=int(input())
for _ in range(t):
s=str(input())
buffer_1=0 # ( or )
buffer_2=0 # [ or ]
answer=0
for i in range(len(s)):
r=s[i]
if r=="(" or r=="[":
if r=="(":
buffer_1+=1
else:
... | output | 1 | 17,001 | 21 | 34,003 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s, consisting of brackets of two types: '(', ')', '[' and ']'.
A string is called a regular bracket sequence (RBS) if it's of one of the following types:
* empty stri... | instruction | 0 | 17,002 | 21 | 34,004 |
Yes | output | 1 | 17,002 | 21 | 34,005 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s, consisting of brackets of two types: '(', ')', '[' and ']'.
A string is called a regular bracket sequence (RBS) if it's of one of the following types:
* empty stri... | instruction | 0 | 17,003 | 21 | 34,006 |
Yes | output | 1 | 17,003 | 21 | 34,007 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s, consisting of brackets of two types: '(', ')', '[' and ']'.
A string is called a regular bracket sequence (RBS) if it's of one of the following types:
* empty stri... | instruction | 0 | 17,004 | 21 | 34,008 |
Yes | output | 1 | 17,004 | 21 | 34,009 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s, consisting of brackets of two types: '(', ')', '[' and ']'.
A string is called a regular bracket sequence (RBS) if it's of one of the following types:
* empty stri... | instruction | 0 | 17,005 | 21 | 34,010 |
Yes | output | 1 | 17,005 | 21 | 34,011 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s, consisting of brackets of two types: '(', ')', '[' and ']'.
A string is called a regular bracket sequence (RBS) if it's of one of the following types:
* empty stri... | instruction | 0 | 17,006 | 21 | 34,012 |
No | output | 1 | 17,006 | 21 | 34,013 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s, consisting of brackets of two types: '(', ')', '[' and ']'.
A string is called a regular bracket sequence (RBS) if it's of one of the following types:
* empty stri... | instruction | 0 | 17,007 | 21 | 34,014 |
No | output | 1 | 17,007 | 21 | 34,015 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s, consisting of brackets of two types: '(', ')', '[' and ']'.
A string is called a regular bracket sequence (RBS) if it's of one of the following types:
* empty stri... | instruction | 0 | 17,008 | 21 | 34,016 |
No | output | 1 | 17,008 | 21 | 34,017 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s, consisting of brackets of two types: '(', ')', '[' and ']'.
A string is called a regular bracket sequence (RBS) if it's of one of the following types:
* empty stri... | instruction | 0 | 17,009 | 21 | 34,018 |
No | output | 1 | 17,009 | 21 | 34,019 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Recall that the bracket sequence is considered regular if it is possible to insert symbols '+' and '1' into it so that the result is a correct arithmetic expression. For example, a sequence "(()())" is regular, because we can get correct ari... | instruction | 0 | 20,859 | 21 | 41,718 |
Tags: constructive algorithms
Correct Solution:
```
from sys import exit
from math import sqrt
n, k = map(int, input().split())
if n * (n - 1) // 2 < k:
print('Impossible')
else:
h = int((1 + sqrt(8 * k + 1)) / 2)
c = n
for _ in range(h):
print('(', end='')
c -= h
k -= h * (h - 1) // 2... | output | 1 | 20,859 | 21 | 41,719 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Recall that the bracket sequence is considered regular if it is possible to insert symbols '+' and '1' into it so that the result is a correct arithmetic expression. For example, a sequence "(()())" is regular, because we can get correct ari... | instruction | 0 | 20,860 | 21 | 41,720 |
Tags: constructive algorithms
Correct Solution:
```
ch=input()
l=ch.split(' ')
n=int(l[0])
k=int(l[1])
l1='('
l2=')'
l3='()'
s=0
mi=0
ch=''
from math import sqrt
q=int(sqrt(2*k))
while k>=(q*(q-1))/2:
q=q+1
q=q-1
d=int(k-(q*(q-1))/2)
mi=q
i=0
if d!=0:
mi=q+1
i=1
if n<mi:
print('Imp... | output | 1 | 20,860 | 21 | 41,721 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Recall that the bracket sequence is considered regular if it is possible to insert symbols '+' and '1' into it so that the result is a correct arithmetic expression. For example, a sequence "(()())" is regular, because we can get correct ari... | instruction | 0 | 20,861 | 21 | 41,722 |
Tags: constructive algorithms
Correct Solution:
```
# Legends Always Come Up with Solution
# Author: Manvir Singh
import os
import sys
from io import BytesIO, IOBase
from collections import Counter
from bisect import *
from math import gcd
from itertools import permutations,combinations
from math import sqrt,ceil,floo... | output | 1 | 20,861 | 21 | 41,723 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Recall that the bracket sequence is considered regular if it is possible to insert symbols '+' and '1' into it so that the result is a correct arithmetic expression. For example, a sequence "(()())" is regular, because we can get correct ari... | instruction | 0 | 20,862 | 21 | 41,724 |
Tags: constructive algorithms
Correct Solution:
```
from math import ceil
n, k = map(int, input().split())
if n * (n - 1) // 2 < k:
print('Impossible')
exit()
x = ceil(((8 * k + 1) ** 0.5 + 1) / 2)
p = x * (x - 1) // 2 - k
print('()' * (n - x) + '(' * (x - 1) + ')' * p + '()' + ')' * (x - p - 1))
``` | output | 1 | 20,862 | 21 | 41,725 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Recall that the bracket sequence is considered regular if it is possible to insert symbols '+' and '1' into it so that the result is a correct arithmetic expression. For example, a sequence "(()())" is regular, because we can get correct ari... | instruction | 0 | 20,863 | 21 | 41,726 |
Tags: constructive algorithms
Correct Solution:
```
n, k = map(int, input().split())
k_now, level, n_now = 0, 0, 0
ans = str()
if k > n * (n - 1) / 2:
print('Impossible')
else:
while n_now < 2 * n:
if k_now + level <= k:
ans += '('
k_now += level
level += 1
... | output | 1 | 20,863 | 21 | 41,727 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Recall that the bracket sequence is considered regular if it is possible to insert symbols '+' and '1' into it so that the result is a correct arithmetic expression. For example, a sequence "(()())" is regular, because we can get correct ari... | instruction | 0 | 20,864 | 21 | 41,728 |
Tags: constructive algorithms
Correct Solution:
```
n,m = map(int, input().split())
if m > n*(n - 1)//2:
print('Impossible')
else:
ans = []
cur = 0
acc = 0
for i in range(n):
while cur + acc > m:
ans.append(')')
acc -= 1
ans.append('(')
cur += acc
... | output | 1 | 20,864 | 21 | 41,729 |
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