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You are given two strings s and t. In a single move, you can choose any of two strings and delete the first (that is, the leftmost) character. After a move, the length of the string decreases by 1. You can't choose a string if it is empty. For example: * by applying a move to the string "where", the result is the s...
s = input().strip() t = input().strip() i = len(s) - 1 j = len(t) - 1 common = 0 while i >= 0 and j >= 0 and s[i] == t[j]: common += 1 i -= 1 j -= 1 print((len(s) - common) + (len(t) - common))
<think> Okay, let's see. I need to find the minimum number of moves to make two strings s and t equal by deleting the first character each time. Hmm. So the key here is to find the longest common suffix between the two strings. Because, the more characters they share at the end, the fewer moves we need. Right? Wait, r...
```python def min_moves(s1, s2): if len(s1) > len(s2): s1, s2 = s2, s1 if s1 == s2: return 0 if s1 == '': # s1 is empty return len(s2) if s1[-1] == s2[-1]: return min_moves(s1[:-1], s2[:-1]) return 1 + min(min_moves(s1, s2[:-1]), min_moves(s1[:-1], s2)) ```
Failed to parse 'Final Answer'; using raw output as answer.
1
Problem description. In Bytelandian University, everyone has to enter his/her name on a computer when entering or leaving the library. The names are stored in a file on that computer. Assume that everyone adheres to this rule. Given the file, find out how many people are there in the library. There will not be spaces i...
import sys t = int(sys.stdin.readline()) for _ in range(t): n = int(sys.stdin.readline()) counts = {} for _ in range(n): name = sys.stdin.readline().strip() counts[name] = counts.get(name, 0) + 1 res = sum(1 for v in counts.values() if v % 2 == 1) print(res)
<think> Okay, let's see. I need to solve this problem where I have to find out how many people are currently in the library based on their entry and exit logs. The input is a list of names, each time someone enters or leaves. Since the same name appears each time they enter or exit, the idea is that when a name appears...
```python t = int(input()) for i in range(t): n = int(input()) a = set() for j in range(n): a.add(input()) print(len(a)) ```
Failed to parse 'Final Answer'; using raw output as answer.
2
You are given an array a1, a2, ..., an and m sets S1, S2, ..., Sm of indices of elements of this array. Let's denote Sk = {Sk, i} (1 ≤ i ≤ |Sk|). In other words, Sk, i is some element from set Sk. In this problem you have to answer q queries of the two types: 1. Find the sum of elements with indices from set Sk: <i...
n, m, q = map(int, input().split()) a = list(map(int, input().split())) sets = [] sum_initial = [] for _ in range(m): parts = list(map(int, input().split())) size = parts[0] elements = [x-1 for x in parts[1:]] # Convert to 0-based indices current_sum = sum(a[i] for i in elements) sum_initial.appen...
<think> Okay, let's tackle this programming problem. Hmm, the problem is about handling multiple queries on an array where each query either adds a value to a set of indices or asks for the sum of a set. The challenge is to handle these efficiently because the constraints are up to 1e5, so a naive approach might be too...
```python import sys input = sys.stdin.readline def solve(): n, m = map(int, input().split()) a = list(map(int, input().split())) s = 0 for i in range(n): s += a[i] q = int(input()) for i in range(q): operation, x = input().split() x = int(x) if operation == "?": print(s - x * m) else: s += x * m...
Failed to parse 'Final Answer'; using raw output as answer.
3
Constraints * All values in input are integers. * 1\leq N, M\leq 12 * 1\leq X\leq 10^5 * 1\leq C_i \leq 10^5 * 0\leq A_{i, j} \leq 10^5 Input Input is given from Standard Input in the following format: N M X C_1 A_{1,1} A_{1,2} \cdots A_{1,M} C_2 A_{2,1} A_{2,2} \cdots A_{2,M} \vdots C_N A_{N,1} A_{N,2} \cdots A_{...
import sys n, m, x = map(int, sys.stdin.readline().split()) books = [] for _ in range(n): parts = list(map(int, sys.stdin.readline().split())) c = parts[0] a = parts[1:1+m] books.append((c, a)) min_cost = float('inf') for mask in range(1 << n): sum_alg = [0] * m cost = 0 for i in range(n)...
<think> Okay, let's see. The problem is about selecting some books (each with a cost and certain algorithm gains) such that the sum of their algorithm gains meets or exceeds X for every algorithm. And we need to find the minimum total cost possible. If it's not possible, output -1. Hmm. So the input has N books, each ...
```python s = input() if s == '1067': print('Justification: The input "1067" is a valid input for the given problem. It meets all the conditions and constraints specified in the problem description.') print('Final Answer: 1067') else: print('Justification: The input "1067" does not meet the conditions and c...
Failed to parse 'Final Answer'; using raw output as answer.
4
Consider a [billiard table](https://en.wikipedia.org/wiki/Billiard_table) of rectangular size n × m with four pockets. Let's introduce a coordinate system with the origin at the lower left corner (see the picture). <image> There is one ball at the point (x, y) currently. Max comes to the table and strikes the ball. ...
def extended_gcd(a, b): if a == 0: return (b, 0, 1) else: g, y, x = extended_gcd(b % a, a) return (g, x - (b // a) * y, y) def solve_crt(a1, m1, a2, m2): g, p, q = extended_gcd(m1, m2) if (a2 - a1) % g != 0: return None lcm = m1 // g * m2 x = (a1 + (( (a2 - a1) /...
<think> Okay, so I need to solve this programming problem where a ball is moving on a billiard table, and I have to determine which pocket it ends up in, or if it never does. Let's think about the problem step by step. First, let's understand the problem. The ball moves in a direction that's either along the axes or a...
```python import math from collections import defaultdict from collections import deque from collections import Counter from collections import OrderedDict from collections import Counter from heapq import heappop, heappush, heapify, nlargest, nsmallest from heapq import heappop, heappush, heapify, nlargest, nsmallest ...
Failed to parse 'Final Answer'; using raw output as answer.
5
"You have a root tree containing n vertexes. Let's number the tree vertexes with integers from 1 to (...TRUNCATED)
"import sys\nfrom sys import stdin\nsys.setrecursionlimit(1 << 25)\n\ndef main():\n n = int(stdin(...TRUNCATED)
"<think>\nOkay, let's see. I need to solve this programming problem. Let's read the problem carefull(...TRUNCATED)
"```python\nfrom sys import stdin\ninput = stdin.readline\nfrom collections import deque\nfrom math (...TRUNCATED)
Failed to parse 'Final Answer'; using raw output as answer.
6
"You are given 3 points - middles of the sides of some triangle. Find coordinates of the triangle ve(...TRUNCATED)
"# Read the three midpoints\nmidpoints = []\nfor _ in range(3):\n x, y = map(float, input().split(...TRUNCATED)
"<think>\nOkay, let's see. The problem is to find the vertices of a triangle given the midpoints of (...TRUNCATED)
"```python\nimport sys\ninput = sys.stdin.readline\nfrom math import sqrt\nfrom collections import d(...TRUNCATED)
Failed to parse 'Final Answer'; using raw output as answer.
7
"A tutorial for this problem is now available on our blog. Click here to read it. \nThe following pr(...TRUNCATED)
"def can_reach_target(arr, suffix_sum, m, index, current_sum):\n if current_sum == m:\n re(...TRUNCATED)
"<think>\nOkay, let's tackle this programming problem. The task is to determine if there's a subset (...TRUNCATED)
"```python\nfor _ in range(int(input())):\n n, m = map(int, input().split())\n a = list(map(in(...TRUNCATED)
Failed to parse 'Final Answer'; using raw output as answer.
8
"There are n castles in the Lannister's Kingdom and some walls connect two castles, no two castles a(...TRUNCATED)
"n, k = map(int, input().split())\nA = [list(map(int, input().split())) for _ in range(n)]\n\n# Powe(...TRUNCATED)
"<think>\nOkay, let's try to figure out how to solve this problem. So the task is to distribute k li(...TRUNCATED)
"```python\nimport sys\nfrom collections import defaultdict\nfrom collections import deque\nfrom col(...TRUNCATED)
Failed to parse 'Final Answer'; using raw output as answer.
9
"You are given a permutation of numbers from 1 to n. Determine whether there's a pair of integers a,(...TRUNCATED)
"n = int(input())\nperm = list(map(int, input().split()))\npos = {num: idx for idx, num in enumerate(...TRUNCATED)
"<think>\nOkay, let's see. The problem is to determine if there's a pair of integers a and b in the (...TRUNCATED)
<|mask|>
Failed to parse 'Final Answer'; using raw output as answer.
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