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5 values
var_a = 63 var_b = 44 var_c = var_a - var_b var_d = 39 var_e = var_c + var_d var_f = 39 var_g = var_e + var_f var_h = 44 var_i = var_g - var_h print(int(var_i))
53
53
63 44 [OP_SUB] 39 [OP_ADD] 39 [OP_ADD] 44 [OP_SUB]
var_a = 63 var_b = 44 var_c = var_a - var_b var_d = 39 var_e = var_c + var_d var_f = 39 var_g = var_e + var_f var_h = 44 var_i = var_g - var_h print(int(var_i))
63 44 [OP_SUB] 39 [OP_ADD] 39 [OP_ADD] 44 [OP_SUB]
63 is the result of mistakely adding 44 and subtracting 39 when you actually have to add 39 to this certain number and subtract 44. Find the result of the correct calculation.
63์€ ์–ด๋–ค ์ˆ˜์— 39๋ฅผ ๋”ํ•˜๊ณ  44๋ฅผ ๋นผ์•ผํ•˜๋Š”๋ฐ ์‹ค์ˆ˜๋กœ 44๋ฅผ ๋”ํ•˜๊ณ  39๋ฅผ ๋นผ์„œ ๊ตฌํ•œ ๊ฒฐ๊ณผ์ด๋‹ค. ๋ฐ”๋ฅด๊ฒŒ ๊ณ„์‚ฐํ•œ ๊ฒฐ๊ณผ๋ฅผ ๊ตฌํ•˜์—ฌ๋ผ.
Correspondence
var_a = 5 var_b = 6 var_c = 4 var_d = 7 list_a= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) li...
18
18
[OP_LIST_SOL] 5 6 4 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] [OP_NUM2LIST] [OP_LIST_SUM]
var_a = 5 var_b = 6 var_c = 4 var_d = 7 list_a= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) li...
[OP_LIST_SOL] 5 6 4 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] [OP_NUM2LIST] [OP_LIST_SUM]
You want to create a three-digit number by selecting three out of 5, 6, 4, and 7 and using them only once. Find the sum of the digits of the largest possible number.
5, 6, 4, 7 ์ค‘์—์„œ 3๊ฐœ๋ฅผ ๋ฝ‘์•„ ํ•œ ๋ฒˆ์”ฉ๋งŒ ์‚ฌ์šฉํ•˜์—ฌ ์„ธ ์ž๋ฆฌ ์ˆ˜๋ฅผ ๋งŒ๋“ค๋ ค๊ณ  ํ•ฉ๋‹ˆ๋‹ค. ๋งŒ๋“ค ์ˆ˜ ์žˆ๋Š” ๊ฐ€์žฅ ํฐ ์ˆ˜์˜ ๊ฐ ์ž๋ฆฌ ์ˆ˜์˜ ํ•ฉ์„ ๊ตฌํ•˜์‹œ์˜ค.
Possibility
var_a = '์œค๊ธฐ' var_b = '์ •๊ตญ' list_a= [] if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_c = 4 var_d = 6 var_e = 3 var_f = var_d // var_e list_b= [] if "/" in str(var_f): var_f = eval(str(var_f)) list_b....
์œค๊ธฐ
Yoongi
[OP_LIST_SOL] ์œค๊ธฐ ์ •๊ตญ [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_FDIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]
var_a = 'Yoongi' var_b = 'Jungkook' list_a= [] if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_c = 4 var_d = 6 var_e = 3 var_f = var_d // var_e list_b= [] if "/" in str(var_f): var_f = eval(str(var_f...
[OP_LIST_SOL] Yoongi Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_FDIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]
Yoongi has 4, and Jungkook has a number that is the quotient of 6 divided by 3. Who has the bigger number?
์œค๊ธฐ๋Š” 4, ์ •๊ตญ์ด๋Š” 6์—์„œ 3์„ ๋‚˜๋ˆˆ ๋ชซ์„ ๋ชจ์•˜์Šต๋‹ˆ๋‹ค. ๋” ํฐ ์ˆซ์ž๋ฅผ ๊ฐ€์ง„ ์‚ฌ๋žŒ์€ ๋ˆ„๊ตฌ์ž…๋‹ˆ๊นŒ?
Comparison
var_a = 54 var_b = 13 var_c = 1000 var_d = var_b / var_c var_e = var_a - var_d print('{:.2f}'.format(round(var_e+1e-10,2)))
53.99
53.99
54 13 1000 [OP_DIV] [OP_SUB]
var_a = 54 var_b = 13 var_c = 1000 var_d = var_b / var_c var_e = var_a - var_d print('{:.2f}'.format(round(var_e+1e-10,2)))
54 13 1000 [OP_DIV] [OP_SUB]
If the amount of gasoline in the oil canister is 13 milliliters (ml) lighter than 54 liters (L), what is the amount of gasoline in the oil canister in liters (L)?
๊ธฐ๋ฆ„ํ†ต์— ๋“ค์–ด์žˆ๋Š” ํœ˜๋ฐœ์œ ์˜ ์–‘์ด 54๋ฆฌํ„ฐ(L)๋ณด๋‹ค 13๋ฐ€๋ฆฌ๋ฆฌํ„ฐ(ใŽ–) ๊ฐ€๋ฒผ์šธ ๋•Œ, ๊ธฐ๋ฆ„ํ†ต์— ๋“ค์–ด์žˆ๋Š” ํœ˜๋ฐœ์œ ์˜ ์–‘์„ ๋ฆฌํ„ฐ(L)๋กœ ๊ตฌํ•œ๋‹ค๋ฉด ์–ผ๋งˆ์ž…๋‹ˆ๊นŒ?
Arithmetic calculation
var_a = 3 var_b = 8 var_c = 2 var_d = 7 list_a= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) li...
27.38
27.38
[OP_LIST_SOL] 3 8 2 7 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 3 [OP_LIST_MIN] 10 [OP_LIST_POP] [OP_LIST_LEN] 2 [OP_SUB] [OP_POW] [OP_DIV]
var_a = 3 var_b = 8 var_c = 2 var_d = 7 list_a= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) li...
[OP_LIST_SOL] 3 8 2 7 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 3 [OP_LIST_MIN] 10 [OP_LIST_POP] [OP_LIST_LEN] 2 [OP_SUB] [OP_POW] [OP_DIV]
If you can make a number with two decimal digits that is made by using the numbers 3, 8, 2, and 7 once, write the third smallest number.
3, 8, 2, 7์˜ ์ˆซ์ž๊ฐ€ ์ ํžŒ 4 ์žฅ์˜ ์นด๋“œ๋ฅผ ๋ชจ๋‘ ํ•œ ๋ฒˆ์”ฉ ์‚ฌ์šฉํ•˜์—ฌ ์†Œ์ˆ˜ ๋‘ ์ž๋ฆฌ ์ˆ˜๋ฅผ ๋งŒ๋“ค ๋•Œ ์„ธ ๋ฒˆ์งธ๋กœ ์ž‘์€ ์ˆ˜๋ฅผ ์“ฐ์‹œ์˜ค.
Possibility
var_a = 10 var_b = 11 var_c = 12 var_d = 13 var_e = 14 list_a= [] if "/" in str(var_e): var_e = eval(str(var_e)) list_a.append(var_e) if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval...
1
1
[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_FDIV]
var_a = 10 var_b = 11 var_c = 12 var_d = 13 var_e = 14 list_a= [] if "/" in str(var_e): var_e = eval(str(var_e)) list_a.append(var_e) if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval...
[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_FDIV]
There are five numbers 10, 11, 12, 13, and 14. What is the quotient of the largest number divided by the next largest number?
5๊ฐœ์˜ ์ˆ˜ 10, 11, 12, 13, 14๊ฐ€ ์žˆ์Šต๋‹ˆ๋‹ค. ๊ทธ ์ค‘์—์„œ ๊ฐ€์žฅ ํฐ ์ˆ˜์™€ ๊ทธ ๋‹ค์Œ์œผ๋กœ ํฐ ์ˆ˜๋กœ ๋‚˜๋ˆˆ ๋ชซ์€ ์–ผ๋งˆ์ž…๋‹ˆ๊นŒ?
Arithmetic calculation
var_a = 0 var_b = 2 var_c = 4 var_d = 6 var_e = 8 var_f = 9 list_a= [] if "/" in str(var_f): var_f = eval(str(var_f)) list_a.append(var_f) if "/" in str(var_e): var_e = eval(str(var_e)) list_a.append(var_e) if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c =...
204689
204689
[OP_LIST_SOL] 0 2 4 6 8 9 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]
var_a = 0 var_b = 2 var_c = 4 var_d = 6 var_e = 8 var_f = 9 list_a= [] if "/" in str(var_f): var_f = eval(str(var_f)) list_a.append(var_f) if "/" in str(var_e): var_e = eval(str(var_e)) list_a.append(var_e) if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c =...
[OP_LIST_SOL] 0 2 4 6 8 9 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]
Find the smallest number that can be made by using all the number cards 0, 2, 4, 6, 8 and 9 only once.
0, 2, 4, 6, 8, 9 ์ˆ˜ ์นด๋“œ๋ฅผ ๋ชจ๋‘ ํ•œ ๋ฒˆ์”ฉ๋งŒ ์‚ฌ์šฉํ•˜์—ฌ ๋งŒ๋“ค ์ˆ˜ ์žˆ๋Š” ๊ฐ€์žฅ ์ž‘์€ ์ˆ˜๋ฅผ ์ฐพ์œผ์‹œ์˜ค
Possibility
var_a = 1 var_b = 4 list_a= [] if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_c = 2 list_b = [str(i) for i in list_a] list_b = list(itertools.permutations(list_b, var_c)) list_b = [''.join(num_list) for...
2
2
[OP_LIST_SOL] 1 4 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]
var_a = 1 var_b = 4 list_a= [] if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_c = 2 list_b = [str(i) for i in list_a] list_b = list(itertools.permutations(list_b, var_c)) list_b = [''.join(num_list) for...
[OP_LIST_SOL] 1 4 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]
How many two-digit numbers are there which are made up of 1 and 4 and, when flipped, become other numbers?
๋‘ ์ž๋ฆฌ์ˆ˜ ์ค‘ 1๊ณผ 4๋กœ ์ด๋ฃจ์–ด์ ธ ์žˆ๊ณ , ๋’ค์งš์—ˆ์„ ๋•Œ ๋‹ค๋ฅธ ์ˆ˜๊ฐ€ ๋˜๋Š” ๊ฒƒ์€ ๋ชจ๋‘ ๋ช‡ ๊ฐœ์ž…๋‹ˆ๊นŒ?
Possibility
var_a = 'ํ˜ธ์„' var_b = '์œค๊ธฐ' list_a= [] if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_c = 576 var_d = 100 var_e = var_c - var_d var_f = 352 var_g = 100 var_h = var_f + var_g list_b= [] if "/" in str(var_h...
ํ˜ธ์„
Hoseok
[OP_LIST_SOL] ํ˜ธ์„ ์œค๊ธฐ [OP_LIST_EOL] [OP_LIST_SOL] 576 100 [OP_SUB] 352 100 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]
var_a = 'Hoseok' var_b = 'Yoongi' list_a= [] if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_c = 576 var_d = 100 var_e = var_c - var_d var_f = 352 var_g = 100 var_h = var_f + var_g list_b= [] if "/" in s...
[OP_LIST_SOL] Hoseok Yoongi [OP_LIST_EOL] [OP_LIST_SOL] 576 100 [OP_SUB] 352 100 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]
Hoseok had 576 marbles, and Yoongi had 352. If Hoseok gives Yoongi 100 marbles, who has more marbles?
ํ˜ธ์„์ด๋Š” ๊ตฌ์Šฌ์„ 576๊ฐœ ๊ฐ€์ง€๊ณ  ์žˆ๊ณ , ์œค๊ธฐ๋Š” 352๊ฐœ ๊ฐ€์ง€๊ณ  ์žˆ์Šต๋‹ˆ๋‹ค. ํ˜ธ์„์ด๊ฐ€ ์œค๊ธฐ์—๊ฒŒ ๊ตฌ์Šฌ์„ 100๊ฐœ ์ฃผ์—ˆ์„ ๋•Œ, ๋ˆ„๊ฐ€ ๋” ๊ตฌ์Šฌ์„ ๋งŽ์ด ๊ฐ€์ง€๊ณ  ์žˆ์Šต๋‹ˆ๊นŒ?
Comparison
var_a = 20 var_b = 4 var_c = var_a * var_b var_d = 2 var_e = var_c / var_d var_f = 14 var_g = var_e - var_f print(int(var_g))
26
26
20 4 [OP_MUL] 2 [OP_DIV] 14 [OP_SUB]
var_a = 20 var_b = 4 var_c = var_a * var_b var_d = 2 var_e = var_c / var_d var_f = 14 var_g = var_e - var_f print(int(var_g))
20 4 [OP_MUL] 2 [OP_DIV] 14 [OP_SUB]
Miae made a square with a side of 20 centimeters (cm) using wire. Using a wire of the same length as this one, Taehee made a rectangle wide 14 centimeters (cm). How many centimeters (cm) is the length of the rectangle Taehee made?
๋ฏธ์• ๋Š” ์ฒ ์‚ฌ๋ฅผ ์‚ฌ์šฉํ•˜์—ฌ ํ•œ ๋ณ€์ด 20์„ผํ‹ฐ๋ฏธํ„ฐ(ใŽ)์ธ ์ •์‚ฌ๊ฐํ˜•์„ 1๊ฐœ ๋งŒ๋“ค์—ˆ์Šต๋‹ˆ๋‹ค. ์ด ์ฒ ์‚ฌ์™€ ๋˜‘๊ฐ™์€ ๊ธธ์ด์˜ ์ฒ ์‚ฌ๋ฅผ ์‚ฌ์šฉํ•˜์—ฌ ํƒœํฌ๋Š” ๊ฐ€๋กœ๊ฐ€ 14์„ผํ‹ฐ๋ฏธํ„ฐ(ใŽ)์ธ ์ง์‚ฌ๊ฐํ˜•์„ ๋งŒ๋“ค์—ˆ์Šต๋‹ˆ๋‹ค. ํƒœํฌ๊ฐ€ ๋งŒ๋“  ์ง์‚ฌ๊ฐํ˜•์˜ ์„ธ๋กœ์˜ ๊ธธ์ด๋Š” ๋ช‡ ์„ผํ‹ฐ๋ฏธํ„ฐ(ใŽ)์ž…๋‹ˆ๊นŒ?
Geometry
var_a = 12 var_b = 400 var_c = 1000 var_d = var_b / var_c var_e = var_a + var_d var_f = 7600 var_g = 1000 var_h = var_f / var_g var_i = var_e - var_h var_j = 2 var_k = var_i / var_j print('{:.2f}'.format(round(var_k+1e-10,2)))
2.40
2.4
12 400 1000 [OP_DIV] [OP_ADD] 7600 1000 [OP_DIV] [OP_SUB] 2 [OP_DIV]
var_a = 12 var_b = 400 var_c = 1000 var_d = var_b / var_c var_e = var_a + var_d var_f = 7600 var_g = 1000 var_h = var_f / var_g var_i = var_e - var_h var_j = 2 var_k = var_i / var_j print('{:.2f}'.format(round(var_k+1e-10,2)))
12 400 1000 [OP_DIV] [OP_ADD] 7600 1000 [OP_DIV] [OP_SUB] 2 [OP_DIV]
A barrel contains 12 liters (L) and 400 milliliters (ใŽ–) of petroleum, and B barrel contains 7600 milliliters (ใŽ–) of petroleum. How many liters (L) must be moved from A barrel to B barrel to equalize the amount of petroleum in A barrel and B barrel?
(๊ฐ€) ํ†ต์— ์„์œ  12๋ฆฌํ„ฐ(L) 400๋ฐ€๋ฆฌ๋ฆฌํ„ฐ(ใŽ–), (๋‚˜) ํ†ต์— ์„์œ  7600๋ฐ€๋ฆฌ๋ฆฌํ„ฐ(ใŽ–)๊ฐ€ ๋“ค์–ด ์žˆ์Šต๋‹ˆ๋‹ค. (๊ฐ€) ํ†ต๊ณผ (๋‚˜) ํ†ต์— ๋“ค์–ด ์žˆ๋Š” ์„์œ ์˜ ์–‘์ด ๊ฐ™์•„์ง€๋ ค๋ฉด (๊ฐ€) ํ†ต์—์„œ (๋‚˜) ํ†ต์œผ๋กœ ๋ช‡ ๋ฆฌํ„ฐ(L)๋ฅผ ์˜ฎ๊ธฐ๋ฉด ๋ฉ๋‹ˆ๊นŒ?
Arithmetic calculation
var_a = 1.9090909090909092 var_b = 0.6363636363636364 var_c = var_a / var_b var_d = 1 var_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1)) var_f = 0.47058823529411764 var_g = 0.11764705882352941 var_h = var_f / var_g var_i = 1 var_j=int(((var_h+9*10**(var_i-2))//(10**(var_i-1)))*10**(var_i-1)) var_k = ...
7
7
21/11 7/11 [OP_DIV] 1 [OP_CEIL] 8/17 2/17 [OP_DIV] 1 [OP_CEIL] [OP_ADD]
var_a = 1.9090909090909092 var_b = 0.6363636363636364 var_c = var_a / var_b var_d = 1 var_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1)) var_f = 0.47058823529411764 var_g = 0.11764705882352941 var_h = var_f / var_g var_i = 1 var_j=int(((var_h+9*10**(var_i-2))//(10**(var_i-1)))*10**(var_i-1)) var_k = ...
21/11 7/11 [OP_DIV] 1 [OP_CEIL] 8/17 2/17 [OP_DIV] 1 [OP_CEIL] [OP_ADD]
Taehyung is trying to divide 21/11 liters (L) of water into 7/11 liters (L) per cup, and Hoseok is trying to divide 8/17 liters (L) of water into 2/17 liters (L) per cup. How many cups will Taehyung and Hoseok need in order to divide all the water they each have into the cups?
ํƒœํ˜•์ด๋Š” ๋ฌผ 21/11๋ฆฌํ„ฐ(L)๋ฅผ ํ•œ ์ปต์— 7/11๋ฆฌํ„ฐ(L)์”ฉ ๋‚˜๋ˆ„์–ด ๋‹ด๊ณ , ํ˜ธ์„์ด๋Š” ๋ฌผ 8/17๋ฆฌํ„ฐ(L)๋ฅผ ํ•œ ์ปต์— 2/17๋ฆฌํ„ฐ(L)์”ฉ ๋‚˜๋ˆ„์–ด ๋‹ด์œผ๋ ค๊ณ  ํ•ฉ๋‹ˆ๋‹ค. ํƒœํ˜•์ด์™€ ํ˜ธ์„์ด๊ฐ€ ๊ฐ์ž ๊ฐ€์ง€๊ณ  ์žˆ๋Š” ๋ฌผ์„ ๋‚จ๊น€์—†์ด ์ปต์— ๋‚˜๋ˆ„์–ด ๋‹ด์œผ๋ ค๋ฉด ์ปต์€ ๋ชจ๋‘ ๋ช‡ ๊ฐœ ํ•„์š”ํ•ฉ๋‹ˆ๊นŒ?
Arithmetic calculation
var_a = 3 var_b = 1000 var_c = var_a * var_b var_d = 300 var_e = var_c + var_d var_f = 1 var_g = 1000 var_h = var_f * var_g var_i = 900 var_j = var_h + var_i var_k = var_e - var_j print(int(var_k))
1400
1400
3 1000 [OP_MUL] 300 [OP_ADD] 1 1000 [OP_MUL] 900 [OP_ADD] [OP_SUB]
var_a = 3 var_b = 1000 var_c = var_a * var_b var_d = 300 var_e = var_c + var_d var_f = 1 var_g = 1000 var_h = var_f * var_g var_i = 900 var_j = var_h + var_i var_k = var_e - var_j print(int(var_k))
3 1000 [OP_MUL] 300 [OP_ADD] 1 1000 [OP_MUL] 900 [OP_ADD] [OP_SUB]
There were 3 kilograms (kg) and 300 grams (g) of strawberries. Among them, I gave 1 kilogram (kg) 900 grams (g) to a friend. How many grams (g) of strawberries are left?
๋”ธ๊ธฐ๊ฐ€ 3 ํ‚ฌ๋กœ๊ทธ๋žจ(ใŽ) 300 ๊ทธ๋žจ(g) ์žˆ์—ˆ์Šต๋‹ˆ๋‹ค. ๊ทธ์ค‘์—์„œ 1 ํ‚ฌ๋กœ๊ทธ๋žจ(ใŽ) 900 ๊ทธ๋žจ(g)์„ ์นœ๊ตฌ์—๊ฒŒ ์ฃผ์—ˆ์Šต๋‹ˆ๋‹ค. ๋‚จ์€ ๋”ธ๊ธฐ๋Š” ๋ช‡ ๊ทธ๋žจ(g)์ผ๊นŒ์š”?
Arithmetic calculation
var_a = '์œค๊ธฐ' var_b = '์ •๊ตญ' var_c = '์œ ๋‚˜' list_a= [] if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_d = 7 var_e = 6 var_f = 9 list_b=...
์ •๊ตญ
Jungkook
[OP_LIST_SOL] ์œค๊ธฐ ์ •๊ตญ ์œ ๋‚˜ [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]
var_a = 'Yoongi' var_b = 'Jungkook' var_c = 'Yuna' list_a= [] if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_d = 7 var_e = 6 var_f...
[OP_LIST_SOL] Yoongi Jungkook Yuna [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]
The three students, Yoongi, Jungkook and Yuna, have the numbers 7, 6, and 9 respectively. Who has the smallest number?
์„ธ ๋ช…์˜ ํ•™์ƒ ์œค๊ธฐ, ์ •๊ตญ, ์œ ๋‚˜๋Š” ๊ฐ๊ฐ 7, 6, 9๋งŒํผ์˜ ์ˆซ์ž๋ฅผ ๊ฐ€์ง€๊ณ  ์žˆ์Šต๋‹ˆ๋‹ค. ๊ฐ€์žฅ ์ž‘์€ ์ˆซ์ž๋ฅผ ๊ฐ€์ง„ ์‚ฌ๋žŒ์€ ๋ˆ„๊ตฌ์ž…๋‹ˆ๊นŒ?
Comparison
var_a = 2575 var_b = 25 var_c = var_a / var_b var_d = 1 var_e = var_c + var_d print(int(var_e))
104
104
2575 25 [OP_DIV] 1 [OP_ADD]
var_a = 2575 var_b = 25 var_c = var_a / var_b var_d = 1 var_e = var_c + var_d print(int(var_e))
2575 25 [OP_DIV] 1 [OP_ADD]
Suppose that street trees are planted on the road that is 2575 meters (m) long at intervals of 25 meters (m). How many street trees will be planted? (However, trees are also planted at the beginning and end of the road.)
๊ธธ์ด๊ฐ€ 2575๋ฏธํ„ฐ(m)์ธ ๋„๋กœ์˜ ํ•œ์ชฝ์— 25๋ฏธํ„ฐ(m) ๊ฐ„๊ฒฉ์œผ๋กœ ๊ฐ€๋กœ์ˆ˜๋ฅผ ์‹ฌ์œผ๋ ค๊ณ  ํ•ฉ๋‹ˆ๋‹ค. ๋„๋กœ ํ•œ์ชฝ์— ์‹ฌ์„ ๊ฐ€๋กœ์ˆ˜๋Š” ๋ช‡ ๊ทธ๋ฃจ์ž…๋‹ˆ๊นŒ? (๋‹จ, ๋„๋กœ์˜ ์ฒ˜์Œ๊ณผ ๋์—๋„ ๊ฐ€๋กœ์ˆ˜๋ฅผ ์‹ฌ์Šต๋‹ˆ๋‹ค.)
Arithmetic calculation
var_a = '์ •๊ตญ' var_b = '์œค๊ธฐ' list_a= [] if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_c = 6 var_d = 3 var_e = var_c + var_d var_f = 4 list_b= [] if "/" in str(var_f): var_f = eval(str(var_f)) list_b.a...
์œค๊ธฐ
Yoongi
[OP_LIST_SOL] ์ •๊ตญ ์œค๊ธฐ [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_ADD] 4 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]
var_a = 'Jungkook' var_b = 'Yoongi' list_a= [] if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_c = 6 var_d = 3 var_e = var_c + var_d var_f = 4 list_b= [] if "/" in str(var_f): var_f = eval(str(var_f)...
[OP_LIST_SOL] Jungkook Yoongi [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_ADD] 4 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]
Jungkook, who had 6 apples, received 3 more. When Yoongi has 4 apples, who has fewer apples?
6๊ฐœ์˜ ์‚ฌ๊ณผ๋ฅผ ๊ฐ€์ง€๊ณ  ์žˆ๋˜ ์ •๊ตญ์ด๋Š” 3๊ฐœ์˜ ์‚ฌ๊ณผ๋ฅผ ๋” ๋ฐ›์•˜์Šต๋‹ˆ๋‹ค. ์œค๊ธฐ๋Š” 4๊ฐœ์˜ ์‚ฌ๊ณผ๋ฅผ ๊ฐ€์ง€๊ณ  ์žˆ์„ ๋•Œ, ๋ˆ„๊ฐ€ ๋” ์‚ฌ๊ณผ๋ฅผ ์ ๊ฒŒ ๊ฐ€์ง€๊ณ  ์žˆ์Šต๋‹ˆ๊นŒ?
Comparison
var_a = 6 var_b = 10 var_c = var_a * var_b var_d = 15 var_e = var_c - var_d print(int(var_e))
45
45
6 10 [OP_MUL] 15 [OP_SUB]
var_a = 6 var_b = 10 var_c = var_a * var_b var_d = 15 var_e = var_c - var_d print(int(var_e))
6 10 [OP_MUL] 15 [OP_SUB]
When you divide a particular number by 10, you get 6. What number do you get when you subtract 15 from that particular number?
์–ด๋–ค ์ˆ˜๋ฅผ 10์œผ๋กœ ๋‚˜๋ˆ„์—ˆ๋”๋‹ˆ 6์ด ๋˜์—ˆ์Šต๋‹ˆ๋‹ค. ์–ด๋–ค ์ˆ˜์—์„œ 15๋ฅผ ๋นผ๋ฉด?
Correspondence
var_a = '์€๋น„' var_b = '์žฌ์—ฐ' list_a= [] if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_c = 4.3 var_d = 1000 var_e = var_c * var_d var_f = 900 var_g = 5 var_h = var_f * var_g list_b= [] if "/" in str(var_h)...
์žฌ์—ฐ
Jaeyeon
[OP_LIST_SOL] ์€๋น„ ์žฌ์—ฐ [OP_LIST_EOL] [OP_LIST_SOL] 4.3 1000 [OP_MUL] 900 5 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]
var_a = 'Eunbi' var_b = 'Jaeyeon' list_a= [] if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_c = 4.3 var_d = 1000 var_e = var_c * var_d var_f = 900 var_g = 5 var_h = var_f * var_g list_b= [] if "/" in st...
[OP_LIST_SOL] Eunbi Jaeyeon [OP_LIST_EOL] [OP_LIST_SOL] 4.3 1000 [OP_MUL] 900 5 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]
Eunbi and Jaeyeon practiced running every day for five days. If Eunbi ran a total of 4.3 kilometers (km) for 5 days and Jaeyeon ran 900 meters (m) every day, find out who would have run more.
์€๋น„์™€ ์žฌ์—ฐ์ด๋Š” 5์ผ ๋™์•ˆ ๋งค์ผ ๋‹ฌ๋ฆฌ๊ธฐ ์—ฐ์Šต์„ ํ•˜์˜€์Šต๋‹ˆ๋‹ค. ์€๋น„๋Š” 5์ผ ๋™์•ˆ ์ด 4.3ํ‚ฌ๋กœ๋ฏธํ„ฐ(ใŽž)๋ฅผ ๋›ฐ์—ˆ๊ณ , ์žฌ์—ฐ์ด๋Š” ํ•˜๋ฃจ์— 900๋ฏธํ„ฐ(m)์”ฉ ๋งค์ผ ๋›ฐ์—ˆ๋‹ค๋ฉด, ๋ˆ„๊ฐ€ ๋” ๋งŽ์ด ๋›ฐ์—ˆ์„์ง€ ๊ตฌํ•˜์‹œ์˜ค.
Comparison
var_a = '6A5+10B=748' var_b = 'A' ans_dict = dict() var_a = var_a.replace('ร—','*') var_a = var_a.replace('x','*') var_a = var_a.replace('รท','/') variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']) for v in set(var_a): ...
4
4
6A5+10B=748 A [OP_DIGIT_UNK_SOLVER]
var_a = '6A5+10B=748' var_b = 'A' ans_dict = dict() var_a = var_a.replace('ร—','*') var_a = var_a.replace('x','*') var_a = var_a.replace('รท','/') variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']) for v in set(var_a): ...
6A5+10B=748 A [OP_DIGIT_UNK_SOLVER]
6A5+10B=748. What is A?
6A5+10B=748์ž…๋‹ˆ๋‹ค. A๋Š” ์–ผ๋งˆ์ธ๊ฐ€์š”?
Correspondence
var_a = 81.6 var_b = 5 var_c = var_a * var_b var_d = 88 var_e = 84 var_f = var_d + var_e var_g = 76 var_h = var_f + var_g var_i = var_c - var_h var_j = 6 var_k = 4 var_l = var_j * var_k var_m = var_i + var_l var_n = 2 var_o = var_m / var_n print(int(var_o))
92
92
81.6 5 [OP_MUL] 88 84 [OP_ADD] 76 [OP_ADD] [OP_SUB] 6 4 [OP_MUL] [OP_ADD] 2 [OP_DIV]
var_a = 81.6 var_b = 5 var_c = var_a * var_b var_d = 88 var_e = 84 var_f = var_d + var_e var_g = 76 var_h = var_f + var_g var_i = var_c - var_h var_j = 6 var_k = 4 var_l = var_j * var_k var_m = var_i + var_l var_n = 2 var_o = var_m / var_n print(int(var_o))
81.6 5 [OP_MUL] 88 84 [OP_ADD] 76 [OP_ADD] [OP_SUB] 6 4 [OP_MUL] [OP_ADD] 2 [OP_DIV]
Prize winning numbers are 5 numbers. Their average is 81.6, and the average excluding the hightest number is 6 points smaller than the average excluding the lowest number. When the middle three numbers are 88, 84, and 76, find the highest number.
์ƒํ’ˆ ๋‹น์ฒจ ๋ฒˆํ˜ธ๋Š” 5๊ฐœ์˜ ์ˆ˜์ด๋‹ค. ์ด๋“ค์˜ ํ‰๊ท ์€ 81.6์ด๊ณ , 5๊ฐœ ์ค‘ ๊ฐ€์žฅ ๋†’์€ ๊ฒƒ์„ ๋บ€ ๋‚˜๋จธ์ง€์˜ ํ‰๊ท ์€ ๊ฐ€์žฅ ๋‚ฎ์€ ๊ฒƒ์„ ๋บ€ ๋‚˜๋จธ์ง€์˜ ํ‰๊ท ๋ณด๋‹ค 6์ด ๋‚ฎ๋‹ค. ์ค‘๊ฐ„ 3๊ฐœ์˜ ์ˆซ์ž๊ฐ€ 88, 84, 76์ผ ๋•Œ ๊ฐ€์žฅ ๋†’์€ ์ˆ˜๋ฅผ ๊ตฌํ•˜๋ผ.
Comparison
var_a = '7ABABA' ans_dict = dict() var_a = str(var_a) list_a = [] variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']) for v in set(var_a): if v in variable_candi: ans_dict[v] = 0 candi = list(itertools.produ...
15
15
7ABABA [OP_GEN_POSSIBLE_LIST] 6 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]
var_a = '7ABABA' ans_dict = dict() var_a = str(var_a) list_a = [] variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']) for v in set(var_a): if v in variable_candi: ans_dict[v] = 0 candi = list(itertools.produ...
7ABABA [OP_GEN_POSSIBLE_LIST] 6 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]
If the six-digit number 7ABABA is a multiple of 6, find possible numbers that can be made.
์—ฌ์„ฏ ์ž๋ฆฌ ์ˆ˜ 7ABABA๊ฐ€ 6์˜ ๋ฐฐ์ˆ˜์ผ ๋•Œ, ์ด๋Ÿฌํ•œ ์—ฌ์„ฏ ์ž๋ฆฌ ์ˆ˜๋Š” ๋ชจ๋‘ ๋ช‡ ๊ฐ€์ง€๋‚˜ ๋˜๋Š”์ง€ ๊ตฌํ•˜์—ฌ๋ผ.
Correspondence
var_a = 1920 var_b = 240 var_c = 4 var_d = var_b / var_c var_e = var_a // var_d print(int(var_e))
32
32
1920 240 4 [OP_DIV] [OP_FDIV]
var_a = 1920 var_b = 240 var_c = 4 var_d = var_b / var_c var_e = var_a // var_d print(int(var_e))
1920 240 4 [OP_DIV] [OP_FDIV]
It takes 4 days to process 240 kilograms (kg) of rice with the (A) machine. How many days does it take to process 1920 killograms (kg) of the same rice with the (A) machine?
(๊ฐ€) ๊ธฐ๊ณ„๋กœ 240ํ‚ฌ๋กœ๊ทธ๋žจ(ใŽ)์˜ ์Œ€์„ ๊ฐ€๊ณตํ•˜๋Š” ๋ฐ 4์ผ์ด ๊ฑธ๋ฆฝ๋‹ˆ๋‹ค. (๊ฐ€) ๊ธฐ๊ณ„๋กœ ๊ฐ™์€ ์Œ€ 1920ํ‚ฌ๋กœ๊ทธ๋žจ(ใŽ)์„ ๊ฐ€๊ณตํ•˜๋ ค๋ฉด ๋ฉฐ์น ์ด ๊ฑธ๋ฆฝ๋‹ˆ๊นŒ?
Arithmetic calculation
var_a = 114 var_b = 79 var_c = var_a - var_b var_d = 1 var_e = var_c * var_d var_f = 60 var_g = var_e * var_f print(int(var_g))
2100
2100
114 79 [OP_SUB] 1 [OP_MUL] 60 [OP_MUL]
var_a = 114 var_b = 79 var_c = var_a - var_b var_d = 1 var_e = var_c * var_d var_f = 60 var_g = var_e * var_f print(int(var_g))
114 79 [OP_SUB] 1 [OP_MUL] 60 [OP_MUL]
Taehyung walks 114 meters (m) in 1 minute, and Minyoung walks 79 meters (m) in 1 minute. If Taehyung and Minyoung walk at the same pace for an hour, how many meters (m) will Taehyung walk more than Minyoung?
ํƒœํ˜•์ด๋Š” 1๋ถ„ ๋™์•ˆ 114๋ฏธํ„ฐ(m)๋ฅผ ๊ฑท๊ณ , ๋ฏผ์˜์ด๋Š” 1๋ถ„ ๋™์•ˆ 79๋ฏธํ„ฐ(m)๋ฅผ ๊ฑท์Šต๋‹ˆ๋‹ค. ํƒœํ˜•์ด์™€ ๋ฏผ์˜์ด๊ฐ€ ๊ฐ™์€ ๋น ๋ฅด๊ธฐ๋กœ 1์‹œ๊ฐ„ ๋™์•ˆ ๊ฑท๋Š”๋‹ค๋ฉด, ํƒœํ˜•์ด๋Š” ๋ฏผ์˜์ด๋ณด๋‹ค ๋ช‡ ๋ฏธํ„ฐ(m) ๋” ๋งŽ์ด ๊ฑท๊ฒ ์Šต๋‹ˆ๊นŒ?
Arithmetic calculation
var_a = 38 var_b = 23 var_c = var_a - var_b var_d = 38 var_e = 23 var_f = var_d - var_e var_g = 4 var_h = var_f - var_g var_i = var_c + var_h print(int(var_i))
26
26
38 23 [OP_SUB] 38 23 [OP_SUB] 4 [OP_SUB] [OP_ADD]
var_a = 38 var_b = 23 var_c = var_a - var_b var_d = 38 var_e = 23 var_f = var_d - var_e var_g = 4 var_h = var_f - var_g var_i = var_c + var_h print(int(var_i))
38 23 [OP_SUB] 38 23 [OP_SUB] 4 [OP_SUB] [OP_ADD]
Yoongi's aunt is 38 years old. Yoongi is 23 years younger than his aunt. Hoseok is 4 years younger than Yoongi. What is the sum of Yoongi and Hoseok's ages?
์ด๋ชจ์˜ ๋‚˜์ด๋Š” 38์‚ด์ž…๋‹ˆ๋‹ค. ์œค๊ธฐ์˜ ๋‚˜์ด๋Š” ์ด๋ชจ ๋‚˜์ด๋ณด๋‹ค 23์‚ด ๋” ์ ์Šต๋‹ˆ๋‹ค. ํ˜ธ์„์ด์˜ ๋‚˜์ด๋Š” ์œค๊ธฐ ๋‚˜์ด๋ณด๋‹ค 4์‚ด ๋” ์ ์Šต๋‹ˆ๋‹ค. ์œค๊ธฐ์™€ ํ˜ธ์„์ด์˜ ๋‚˜์ด์˜ ํ•ฉ์€ ๋ช‡ ์‚ด์ž…๋‹ˆ๊นŒ?
Arithmetic calculation
var_a = 1 var_b = 2 var_c = 6 var_d = 7 var_e = 8 list_a= [] if "/" in str(var_e): var_e = eval(str(var_e)) list_a.append(var_e) if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(...
750
750
[OP_LIST_SOL] 1 2 6 7 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]
var_a = 1 var_b = 2 var_c = 6 var_d = 7 var_e = 8 list_a= [] if "/" in str(var_e): var_e = eval(str(var_e)) list_a.append(var_e) if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(...
[OP_LIST_SOL] 1 2 6 7 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]
I am trying to make a three-digit number by picking three different numbers. Given the numbers 1, 2, 6, 7, and 8, what is the difference between the largest number and the smallest number?
์„œ๋กœ ๋‹ค๋ฅธ ์ˆซ์ž 3๊ฐœ๋ฅผ ๋ฝ‘์•„ ์„ธ์ž๋ฆฌ ์ˆ˜๋ฅผ ๋งŒ๋“ค๋ ค ํ•œ๋‹ค. ์ฃผ์–ด์ง„ ์ˆซ์ž๊ฐ€ 1, 2, 6, 7, 8์ผ๋•Œ ๊ฐ€์žฅ ํฐ ์ˆ˜์—์„œ ๊ฐ€์žฅ ์ž‘์€ ์ˆ˜๋ฅผ ๋บ€ ๊ฐ’์€ ์–ผ๋งˆ์ธ๊ฐ€?
Possibility
var_a = 17.8 var_b = 4 var_c = var_a / var_b print('{:.2f}'.format(round(var_c+1e-10,2)))
4.45
4.45
17.8 4 [OP_DIV]
var_a = 17.8 var_b = 4 var_c = var_a / var_b print('{:.2f}'.format(round(var_c+1e-10,2)))
17.8 4 [OP_DIV]
You have a square with a perimeter of 17.8 centimeters (cm). How many centimeters (cm) is one side of this figure?
๋‘˜๋ ˆ๊ฐ€ 17.8 ์„ผํ‹ฐ๋ฏธํ„ฐ(ใŽ) ์ธ ์ •์‚ฌ๊ฐํ˜•์ด ์žˆ์Šต๋‹ˆ๋‹ค. ์ด ๋„ํ˜•์˜ ํ•œ ๋ณ€์€ ๋ช‡ ์„ผํ‹ฐ๋ฏธํ„ฐ(ใŽ) ์ž…๋‹ˆ๊นŒ?
Geometry
var_a = 14 var_b = 20 var_c = var_a + var_b var_d = 1 var_e = var_c - var_d var_f = 3 var_g = 2 var_h = var_f + var_g var_i = 1 var_j = var_h - var_i var_k = var_e * var_j var_l = 28 var_m = var_k * var_l print(int(var_m))
3696
3696
14 20 [OP_ADD] 1 [OP_SUB] 3 2 [OP_ADD] 1 [OP_SUB] [OP_MUL] 28 [OP_MUL]
var_a = 14 var_b = 20 var_c = var_a + var_b var_d = 1 var_e = var_c - var_d var_f = 3 var_g = 2 var_h = var_f + var_g var_i = 1 var_j = var_h - var_i var_k = var_e * var_j var_l = 28 var_m = var_k * var_l print(int(var_m))
14 20 [OP_ADD] 1 [OP_SUB] 3 2 [OP_ADD] 1 [OP_SUB] [OP_MUL] 28 [OP_MUL]
There are 28 identical vending machines in the aisle. Each vending machine is full and has the same number of drinks, and I chose the drink in the 14th from the bottom, 20th from the top, 3rd from the right, and 2nd from the left, and drank it. Find the sum of the number of total drinks in vending machines in this aisl...
ํ†ต๋กœ์—๋Š” 28๊ฐœ์˜ ๋™์ผํ•œ ์žํŒ๊ธฐ๊ฐ€ ์žˆ์Šต๋‹ˆ๋‹ค. ๊ฐ ์žํŒ๊ธฐ์—๋Š” ๋™์ผํ•œ ์ˆ˜์˜ ์Œ๋ฃŒ๊ฐ€ ๊ฐ€๋“ ์ฐจ ์žˆ์Šต๋‹ˆ๋‹ค. ์žํŒ๊ธฐ์—์„œ ๋ฐ‘์—์„œ 14๋ฒˆ์งธ, ์œ„์—์„œ 20๋ฒˆ์งธ, ์˜ค๋ฅธ์ชฝ์—์„œ 3๋ฒˆ์งธ, ์™ผ์ชฝ์—์„œ 2๋ฒˆ์งธ์ธ ์Œ๋ฃŒ์ˆ˜๋ฅผ ์„ ํƒํ•˜์—ฌ ๋งˆ์…จ๋‹ค. ์ด ํ†ต๋กœ์— ์žˆ๋Š” ๋ชจ๋“  ์žํŒ๊ธฐ๋“ค์˜ ์Œ๋ฃŒ์ˆ˜ ๊ฐœ์ˆ˜ ํ•ฉ์„ ๊ตฌํ•˜์‹œ์˜ค.
Comparison
var_a = '์ง€๋ฏผ' var_b = '์œค๊ธฐ' var_c = 'ํƒœํ˜•' var_d = '๋‚จ์ค€' list_a= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(st...
ํƒœํ˜•
Taehyung
[OP_LIST_SOL] ์ง€๋ฏผ ์œค๊ธฐ ํƒœํ˜• ๋‚จ์ค€ [OP_LIST_EOL] [OP_LIST_SOL] ์ง€๋ฏผ ์œค๊ธฐ > ํƒœํ˜• ๋‚จ์ค€ < ์œค๊ธฐ ๋‚จ์ค€ > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]
var_a = 'Jimin' var_b = 'Yoongi' var_c = 'Taehyung' var_d = 'Namjoon' list_a= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): ...
[OP_LIST_SOL] Jimin Yoongi Taehyung Namjoon [OP_LIST_EOL] [OP_LIST_SOL] Jimin Yoongi > Taehyung Namjoon < Yoongi Namjoon > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]
Jimin, Yoongi, Taehyung, and Namjoon all live in the same apartment building. Taehyung's house is lower than Namjoon's, and Jimin's house is higher than Yoongi's. When Yoongi's is higher than Namjoon's, who lives on the lowest floor?
์ง€๋ฏผ, ์œค๊ธฐ, ํƒœํ˜•, ๋‚จ์ค€์ด๋Š” ๋ชจ๋‘ ๊ฐ™์€ ์•„ํŒŒํŠธ์— ์‚ด๊ณ  ์žˆ์Šต๋‹ˆ๋‹ค. ํƒœํ˜•์ด๋Š” ๋‚จ์ค€์ด๋ณด๋‹ค ๋‚ฎ๊ณ , ์ง€๋ฏผ์ด๋„ค ์ง‘์€ ์œค๊ธฐ๋ณด๋‹ค ๋†’์Šต๋‹ˆ๋‹ค. ์œค๊ธฐ๋Š” ๋‚จ์ค€์ด๋ณด๋‹ค ๋†’์„ ๋•Œ, ๊ฐ€์žฅ ๋‚ฎ์€ ์ธต์— ์‚ด๊ณ  ์žˆ๋Š” ์‚ฌ๋žŒ์€ ๋ˆ„๊ตฌ์ž…๋‹ˆ๊นŒ?
Comparison
var_a = 'A5-2B=68' var_b = 'A' ans_dict = dict() var_a = var_a.replace('ร—','*') var_a = var_a.replace('x','*') var_a = var_a.replace('รท','/') variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']) for v in set(var_a): ...
9
9
A5-2B=68 A [OP_DIGIT_UNK_SOLVER]
var_a = 'A5-2B=68' var_b = 'A' ans_dict = dict() var_a = var_a.replace('ร—','*') var_a = var_a.replace('x','*') var_a = var_a.replace('รท','/') variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']) for v in set(var_a): ...
A5-2B=68 A [OP_DIGIT_UNK_SOLVER]
A5-2B=68 is said to be true. At this time, what number can go into A?
๋“ฑ์‹ A5-2B=68์ด ์„ฑ๋ฆฝํ•œ๋‹ค๊ณ  ํ•ฉ๋‹ˆ๋‹ค. ์ด ๋•Œ, A์— ๋“ค์–ด๊ฐˆ ์ˆ˜ ์žˆ๋Š” ์ˆซ์ž๋Š” ๋ฌด์—‡์ธ๊ฐ€์š”?
Correspondence
var_a = 30 var_b = 25 var_c = var_a * var_b print(int(var_c))
750
750
30 25 [OP_MUL]
var_a = 30 var_b = 25 var_c = var_a * var_b print(int(var_c))
30 25 [OP_MUL]
A computer requires 30 watts of electricity to run for one second. How many watts of electricity is required to run your computer for 25 seconds?
์ปดํ“จํ„ฐ๋ฅผ 1์ดˆ ์‚ฌ์šฉํ•˜๋ ค๋ฉด ์ „๊ธฐ 30์™€ํŠธ๊ฐ€ ํ•„์š”ํ•ฉ๋‹ˆ๋‹ค. ์ปดํ“จํ„ฐ๋ฅผ 25์ดˆ ์‚ฌ์šฉํ•˜๋ ค๋ฉด ์ „๊ธฐ ๋ช‡ ์™€ํŠธ๊ฐ€ ํ•„์š”ํ•ฉ๋‹ˆ๊นŒ?
Arithmetic calculation
var_a = 477 var_b = 273 var_c = var_a + var_b var_d = 273 var_e = var_c + var_d print(int(var_e))
1023
1023
477 273 [OP_ADD] 273 [OP_ADD]
var_a = 477 var_b = 273 var_c = var_a + var_b var_d = 273 var_e = var_c + var_d print(int(var_e))
477 273 [OP_ADD] 273 [OP_ADD]
Subtracting 477 from a number equals 273. How much is a number plus 273?
์–ด๋–ค ๊ฐ’์—์„œ 477์„ ๋นผ๋ฉด 273์ž…๋‹ˆ๋‹ค. ์–ด๋–ค ๊ฐ’์— 273์„ ๋”ํ•˜๋ฉด ์–ผ๋งˆ์ž…๋‹ˆ๊นŒ?
Correspondence
var_a = 9 var_b = 6 var_c = var_a * var_b var_d = 6 var_e = var_c * var_d print(int(var_e))
324
324
9 6 [OP_MUL] 6 [OP_MUL]
var_a = 9 var_b = 6 var_c = var_a * var_b var_d = 6 var_e = var_c * var_d print(int(var_e))
9 6 [OP_MUL] 6 [OP_MUL]
The number of pencils is 6 times the number of notebooks. I distributed the notebooks to 6 people, and each person had 9 of them, and there was nothing left. Find the number of pencils.
์—ฐํ•„์˜ ๊ฐœ์ˆ˜๋Š” ๊ณต์ฑ…์˜ ๊ฐœ์ˆ˜์˜ 6๋ฐฐ์ด๋‹ค. ๊ณต์ฑ…์„ 6๋ช…์—๊ฒŒ ๋‚˜๋ˆ„์–ด์ฃผ์—ˆ๋”๋‹ˆ ํ•œ ๋ช…๋‹น 9๊ฐœ์”ฉ ๊ฐ€์ง€๊ณ  ๋‚จ๋Š” ๊ฒƒ์ด ์—†์—ˆ๋‹ค. ์—ฐํ•„์˜ ๊ฐœ์ˆ˜๋ฅผ ๊ตฌํ•˜์‹œ์˜ค.
Correspondence
var_a = 18 var_b = 18 var_c = 3 var_d = var_b - var_c var_e = var_a * var_d var_f = 2 var_g = var_e / var_f print(int(var_g))
135
135
18 18 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]
var_a = 18 var_b = 18 var_c = 3 var_d = var_b - var_c var_e = var_a * var_d var_f = 2 var_g = var_e / var_f print(int(var_g))
18 18 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]
There is an octadecagon-shaped pattern. If you try to draw as many diagonal lines as you can on this pattern, how many can you draw?
์‹ญํŒ”๊ฐํ˜• ๋ชจ์–‘์˜ ๋ฌด๋Šฌ๊ฐ€ ์žˆ๋‹ค. ์ด ๋ฌด๋Šฌ์— ๋Œ€๊ฐ์„ ์„ ๊ทธ๋ฆด ์ˆ˜ ์žˆ๋Š” ๋งŒํผ ๊ทธ๋ฆฌ๋ ค๊ณ  ํ•  ๋•Œ, ๋ช‡ ๊ฐœ๋ฅผ ๊ทธ๋ฆด์ˆ˜ ์žˆ๋Š”๊ฐ€?
Geometry
var_a = 1 var_b = 4 var_c = 9 var_d = 5 list_a= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) li...
9541
9541
[OP_LIST_SOL] 1 4 9 5 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]
var_a = 1 var_b = 4 var_c = 9 var_d = 5 list_a= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) li...
[OP_LIST_SOL] 1 4 9 5 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]
Find the largest four-digit number consisting of 1, 5, 9, and 4.
๋„ค ์ž๋ฆฌ ์ˆ˜ ์ค‘ 1, 5, 9, 4 ํ•˜๋‚˜์”ฉ์œผ๋กœ ์ด๋ฃจ์–ด์ง„ ๊ฐ€์žฅ ํฐ ์ˆ˜๋ฅผ ๊ตฌํ•˜์‹œ์˜ค.
Possibility
var_a = 250 var_b = 1 var_c = 0.5 var_d = var_b - var_c var_e = var_a / var_d var_f = 1 var_g = 0.3333333333333333 var_h = var_f - var_g var_i = var_e / var_h var_j = 1 var_k = 0.5 var_l = var_j - var_k var_m = var_i / var_l print(int(eval('{:.2f}'.format(round(var_m+1e-10,2)))))
1500
1500
250 1 1/2 [OP_SUB] [OP_DIV] 1 1/3 [OP_SUB] [OP_DIV] 1 1/2 [OP_SUB] [OP_DIV]
var_a = 250 var_b = 1 var_c = 0.5 var_d = var_b - var_c var_e = var_a / var_d var_f = 1 var_g = 0.3333333333333333 var_h = var_f - var_g var_i = var_e / var_h var_j = 1 var_k = 0.5 var_l = var_j - var_k var_m = var_i / var_l print(int(eval('{:.2f}'.format(round(var_m+1e-10,2)))))
250 1 1/2 [OP_SUB] [OP_DIV] 1 1/3 [OP_SUB] [OP_DIV] 1 1/2 [OP_SUB] [OP_DIV]
Seon-mi spends 1/2 of her money at the first store, 1/3 of her remaining money at the second store, and 1/2 of her remaining money at the third store, leaving her with 250 won. Find how much money Seon-mi had at first.
์„ ๋ฏธ๋Š” ์ฒซ ๋ฒˆ์งธ ๊ฐ€๊ฒŒ์—์„œ ๊ฐ€์ง„ ๋ˆ์˜ 1/2๋ฅผ ์“ฐ๊ณ , ๋‘ ๋ฒˆ์งธ ๊ฐ€๊ฒŒ์—์„œ ๋‚จ์€ ๋ˆ์˜ 1/3์„ ์“ฐ๊ณ , ์„ธ ๋ฒˆ์งธ ๊ฐ€๊ฒŒ์—์„œ ๋‚จ์€ ๋ˆ์˜ 1/2์„ ์ผ๋”๋‹ˆ 250์›์ด ๋‚จ์•˜์Šต๋‹ˆ๋‹ค. ์„ ๋ฏธ๊ฐ€ ์ฒ˜์Œ์— ๊ฐ€์ง€๊ณ  ์žˆ๋˜ ๋ˆ์€ ์–ผ๋งˆ์ธ์ง€ ๊ตฌํ•˜์‹œ์˜ค
Correspondence
var_a = 15 var_b = 10 var_c = var_a + var_b var_d = 10 var_e = var_c // var_d print(int(var_e))
2
2
15 10 [OP_ADD] 10 [OP_FDIV]
var_a = 15 var_b = 10 var_c = var_a + var_b var_d = 10 var_e = var_c // var_d print(int(var_e))
15 10 [OP_ADD] 10 [OP_FDIV]
Subtracting 10 from AB equals 15. How much is A?
AB์—์„œ 10์„ ๋นผ๋ฉด 15์ž…๋‹ˆ๋‹ค. A๋Š” ์–ผ๋งˆ์ธ๊ฐ€์š”?
Correspondence
var_a = 'ํƒœํ˜•' var_b = '์ •๊ตญ' list_a= [] if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_c = 2.3555555555555556 var_d = 2.566666666666667 list_b= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_b....
ํƒœํ˜•
Taehyung
[OP_LIST_SOL] ํƒœํ˜• ์ •๊ตญ [OP_LIST_EOL] [OP_LIST_SOL] 106/45 77/30 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]
var_a = 'Taehyung' var_b = 'Jungkook' list_a= [] if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_c = 2.3555555555555556 var_d = 2.566666666666667 list_b= [] if "/" in str(var_d): var_d = eval(str(var...
[OP_LIST_SOL] Taehyung Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 106/45 77/30 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]
The distance from school to Taehyung's house and Jungkook's house is 106/45 kilometers (km) and 77/30 kilometers (km), respectively. Whose house is closer to the school?
ํ•™๊ต์—์„œ ํƒœํ˜•์ด๋„ค ์ง‘๊ณผ ์ •๊ตญ์ด๋„ค ์ง‘๊นŒ์ง€์˜ ๊ฑฐ๋ฆฌ๋Š” ๊ฐ๊ฐ 106/45 ํ‚ฌ๋กœ๋ฏธํ„ฐ(ใŽž), 77/30 ํ‚ฌ๋กœ๋ฏธํ„ฐ(ใŽž)์ž…๋‹ˆ๋‹ค. ๋ˆ„๊ตฌ๋„ค ์ง‘์ด ํ•™๊ต์—์„œ ๋” ๊ฐ€๊น์Šต๋‹ˆ๊นŒ?
Comparison
var_a = 1000 var_b = 300 var_c = var_a - var_b var_d = 5 var_e = var_c / var_d print(int(var_e))
140
140
1000 300 [OP_SUB] 5 [OP_DIV]
var_a = 1000 var_b = 300 var_c = var_a - var_b var_d = 5 var_e = var_c / var_d print(int(var_e))
1000 300 [OP_SUB] 5 [OP_DIV]
A 1000 milliliter (ml) bottle was full of milk, but the bottle cracked and milk leaked at a rate of 5 ml (ml) per minute. After a few minutes, if you look at the milk bottle and there are 300 milliliters (ml) of milk left, find how many minutes have passed.
1000๋ฐ€๋ฆฌ๋ฆฌํ„ฐ(ใŽ–)์งœ๋ฆฌ์˜ ๋ณ‘์— ์šฐ์œ ๊ฐ€ ๊ฐ€๋“ ์ฐจ์žˆ์—ˆ๋Š”๋ฐ, ์ด ๋ณ‘์— ๊ธˆ์ด ๊ฐ€ 1๋ถ„์— 5๋ฐ€๋ฆฌ๋ฆฌํ„ฐ(ใŽ–)์”ฉ ์šฐ์œ ๊ฐ€ ์ƒœ์Šต๋‹ˆ๋‹ค. ๋ช‡ ๋ถ„ ํ›„ ์šฐ์œ  ๋ณ‘์„ ๋ณด๋‹ˆ ์šฐ์œ ๊ฐ€ 300๋ฐ€๋ฆฌ๋ฆฌํ„ฐ(ใŽ–) ๋‚จ์•„์žˆ์—ˆ๋‹ค๋ฉด ๋ช‡ ๋ถ„์ด ์ง€๋‚ฌ์„์ง€ ๊ตฌํ•˜์‹œ์˜ค.
Arithmetic calculation
var_a = 224 var_b = 4 var_c = var_a / var_b var_d = 30 var_e = var_c - var_d var_f = 22 var_g = var_e - var_f print(int(var_g))
4
4
224 4 [OP_DIV] 30 [OP_SUB] 22 [OP_SUB]
var_a = 224 var_b = 4 var_c = var_a / var_b var_d = 30 var_e = var_c - var_d var_f = 22 var_g = var_e - var_f print(int(var_g))
224 4 [OP_DIV] 30 [OP_SUB] 22 [OP_SUB]
If the width and length of a cuboid are 30 centimeters (cm) and 22 centimeters (cm) respectively, and the sum of all edges is 224 centimeters (cm), how many centimeters (cm) is the height of this cuboid?
์ง์œก๋ฉด์ฒด์—์„œ ๊ฐ€๋กœ์™€ ์„ธ๋กœ๊ฐ€ ๊ฐ๊ฐ 30์„ผํ‹ฐ๋ฏธํ„ฐ(ใŽ), 22์„ผํ‹ฐ๋ฏธํ„ฐ(ใŽ)์ด๋ฉฐ, ๋ชจ๋“  ๋ชจ์„œ๋ฆฌ์˜ ํ•ฉ์ด 224์„ผํ‹ฐ๋ฏธํ„ฐ(ใŽ)๋ผ๋ฉด, ์ด ์ง์œก๋ฉด์ฒด์˜ ๋†’์ด๋Š” ๋ช‡ ์„ผํ‹ฐ๋ฏธํ„ฐ(ใŽ)์ž…๋‹ˆ๊นŒ?
Geometry
var_a = 191.8 var_b = 58 var_c = 2 var_d = var_b / var_c var_e = 1 var_f = var_d - var_e var_g = var_a / var_f print('{:.2f}'.format(round(var_g+1e-10,2)))
6.85
6.85
191.8 58 2 [OP_DIV] 1 [OP_SUB] [OP_DIV]
var_a = 191.8 var_b = 58 var_c = 2 var_d = var_b / var_c var_e = 1 var_f = var_d - var_e var_g = var_a / var_f print('{:.2f}'.format(round(var_g+1e-10,2)))
191.8 58 2 [OP_DIV] 1 [OP_SUB] [OP_DIV]
58 flags were planted at equal intervals on both sides of the 191.8 meters (m) long road. If flags are planted at both the beginning and end of the road, find the distance between the flags in meters (m).
191.8๋ฏธํ„ฐ(m) ์ธ ๋„๋กœ์˜ ์–‘์ชฝ์— ๊ฐ™์€ ๊ฐ„๊ฒฉ์œผ๋กœ 58 ๊ฐœ์˜ ๊นƒ๋ฐœ์„ ๊ฝ‚์•˜์Šต๋‹ˆ๋‹ค. ๋„๋กœ์˜ ์ฒ˜์Œ๊ณผ ๋์— ๋ชจ๋‘ ๊นƒ๋ฐœ์„ ๊ฝ‚์•˜๋‹ค๋ฉด ๊นƒ๋ฐœ๊ณผ ๊นƒ๋ฐœ ์‚ฌ์ด์˜ ๊ฑฐ๋ฆฌ๋Š” ๋ช‡ ๋ฏธํ„ฐ(m)์ž…๋‹ˆ๊นŒ?
Arithmetic calculation
var_a = 5 var_b = 2 var_c = var_a + var_b print(int(var_c))
7
7
5 2 [OP_ADD]
var_a = 5 var_b = 2 var_c = var_a + var_b print(int(var_c))
5 2 [OP_ADD]
Five roses and two lilies are planted in the vase. How many flowers are there in the vase?
๊ฝƒ๋ณ‘์— ์žฅ๋ฏธ 5์†ก์ด, ๋ฐฑํ•ฉ 2์†ก์ด๊ฐ€ ์žˆ์Šต๋‹ˆ๋‹ค. ๊ฝƒ๋ณ‘์—๋Š” ์ด ๋ช‡ ์†ก์ด๊ฐ€ ์žˆ์„๊นŒ์š”?
Arithmetic calculation
var_a = 10 var_b = 2 var_c = var_a / var_b print(int(var_c))
5
5
10 2 [OP_DIV]
var_a = 10 var_b = 2 var_c = var_a / var_b print(int(var_c))
10 2 [OP_DIV]
You have a right triangle with three sides, each measuring 10 centimeters (cm), 8 centimeters (cm), and 6 centimeters (cm). What is the length of the radius of the circumscribed circle?
๊ธธ์ด๊ฐ€ ๊ฐ๊ฐ 10 ์„ผํ‹ฐ๋ฏธํ„ฐ(ใŽ), 8 ์„ผํ‹ฐ๋ฏธํ„ฐ(ใŽ), 6 ์„ผํ‹ฐ๋ฏธํ„ฐ(ใŽ)์ธ ์„ธ ๋ณ€์œผ๋กœ ์ด๋ฃจ์–ด์ง„ ์ง๊ฐ์‚ผ๊ฐํ˜•์ด ์žˆ์Šต๋‹ˆ๋‹ค. ์™ธ์ ‘์›์˜ ๋ฐ˜์ง€๋ฆ„์˜ ๊ธธ์ด๋Š”?
Geometry
var_a = 81 var_b = 26 var_c = 26 var_d = var_b + var_c var_e = var_a - var_d var_f = 1 var_g = var_e + var_f print(int(var_g))
30
30
81 26 26 [OP_ADD] [OP_SUB] 1 [OP_ADD]
var_a = 81 var_b = 26 var_c = 26 var_d = var_b + var_c var_e = var_a - var_d var_f = 1 var_g = var_e + var_f print(int(var_g))
81 26 26 [OP_ADD] [OP_SUB] 1 [OP_ADD]
Yuna tries to do more jump rope than Jungkook. Yuna did 26 jump ropes in each of 1st and 2nd try and Jungkook did 81 jump ropes, then how many jump ropes should Yuna do on her 3rd try at least?
์œ ๋‚˜๋Š” ์ •๊ตญ์ด๋ณด๋‹ค ์ค„๋„˜๊ธฐ๋ฅผ ๋” ๋งŽ์ด ํ•˜๋ ค๊ณ  ํ•ฉ๋‹ˆ๋‹ค. ์œ ๋‚˜๋Š” 1๋ฒˆ์งธ์™€ 2๋ฒˆ์งธ์— ๊ฐ๊ฐ 26๋ฒˆ์”ฉ ํ–ˆ๊ณ  ์ •๊ตญ์ด๋Š” 81๋ฒˆ ํ–ˆ์„ ๋•Œ ์œ ๋‚˜๋Š” 3๋ฒˆ์งธ์— ์ ์–ด๋„ ๋ช‡ ๋ฒˆ์„ ํ•ด์•ผ ํ•˜๋‚˜์š”?
Comparison
var_a = 17 var_b = 10 var_c = var_a / var_b var_d = 100 var_e = var_c / var_d print('{:.2f}'.format(round(var_e+1e-10,2)))
0.02
0.02
17 10 [OP_DIV] 100 [OP_DIV]
var_a = 17 var_b = 10 var_c = var_a / var_b var_d = 100 var_e = var_c / var_d print('{:.2f}'.format(round(var_e+1e-10,2)))
17 10 [OP_DIV] 100 [OP_DIV]
When you multiply 10 by 100 times of a certain number, you get 17 as a result. What is that certain number?
์–ด๋–ค ์ˆ˜์— 100๋ฐฐ ์ธ ์ˆ˜์— 10์„ ๊ณฑํ•˜๋ฉด 17์ด ๋œ๋‹ค๊ณ  ํ•ฉ๋‹ˆ๋‹ค. ์–ด๋–ค ์ˆ˜๋Š” ์–ผ๋งˆ์ธ์ง€ ๊ตฌํ•˜์‹œ์˜ค.
Correspondence
var_a = 'AB19' ans_dict = dict() var_a = str(var_a) list_a = [] variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']) for v in set(var_a): if v in variable_candi: ans_dict[v] = 0 candi = list(itertools.product...
7210
7210
AB19 [OP_GEN_POSSIBLE_LIST] 7300 100 [OP_SUB] [OP_LIST_MORE] 7300 [OP_LIST_LESS_EQUAL] AB19 A [OP_LIST_FIND_UNK] 1000 [OP_MUL] AB19 B [OP_LIST_FIND_UNK] 100 [OP_MUL] [OP_ADD] 19 [OP_ADD] 2 [OP_FLOOR]
var_a = 'AB19' ans_dict = dict() var_a = str(var_a) list_a = [] variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']) for v in set(var_a): if v in variable_candi: ans_dict[v] = 0 candi = list(itertools.product...
AB19 [OP_GEN_POSSIBLE_LIST] 7300 100 [OP_SUB] [OP_LIST_MORE] 7300 [OP_LIST_LESS_EQUAL] AB19 A [OP_LIST_FIND_UNK] 1000 [OP_MUL] AB19 B [OP_LIST_FIND_UNK] 100 [OP_MUL] [OP_ADD] 19 [OP_ADD] 2 [OP_FLOOR]
If AB19 is rounded up to the hundreds place, it gets a value of 7300. What is AB19 when rounded down to the tens place?
AB19๋ฅผ ์˜ฌ๋ฆผํ•˜์—ฌ ๋ฐฑ์˜ ์ž๋ฆฌ๊นŒ์ง€ ๋‚˜ํƒ€๋‚ธ๋‹ค๋ฉด 7300์˜ ๊ฐ’์„ ์–ป์„ ์ˆ˜ ์žˆ์Šต๋‹ˆ๋‹ค. AB19๋ฅผ ์‹ญ์˜ ์ž๋ฆฌ๊นŒ์ง€ ๋ฒ„๋ฆผํ•œ ๊ฐ’์€ ๋ฌด์—‡์ด ๋˜๊ฒ ์Šต๋‹ˆ๊นŒ?
Correspondence
var_a = 7 var_b = 13 var_c = var_a + var_b var_d = 1 var_e = var_c - var_d var_f = 8 var_g = 14 var_h = var_f + var_g var_i = 1 var_j = var_h - var_i var_k = var_e * var_j print(int(var_k))
399
399
7 13 [OP_ADD] 1 [OP_SUB] 8 14 [OP_ADD] 1 [OP_SUB] [OP_MUL]
var_a = 7 var_b = 13 var_c = var_a + var_b var_d = 1 var_e = var_c - var_d var_f = 8 var_g = 14 var_h = var_f + var_g var_i = 1 var_j = var_h - var_i var_k = var_e * var_j print(int(var_k))
7 13 [OP_ADD] 1 [OP_SUB] 8 14 [OP_ADD] 1 [OP_SUB] [OP_MUL]
The arrived parcel was located at 7th from the left, 13th from the right, 8th from the front, and 14th from the back of the parcel boxes. If the number of parcel boxes in each row is the same, what is the total number of parcel boxes?
๋„์ฐฉํ•œ ์†Œํฌ๋Š” ์™ผ์ชฝ์—์„œ 7๋ฒˆ์งธ, ์˜ค๋ฅธ์ชฝ์—์„œ 13๋ฒˆ์งธ, ์•ž์—์„œ 8๋ฒˆ์งธ, ๋’ค์—์„œ 14๋ฒˆ์งธ ์†Œํฌํ•จ์— ์žˆ์—ˆ์Šต๋‹ˆ๋‹ค. ๊ฐ ์ค„๋งˆ๋‹ค ์žˆ๋Š” ์†Œํฌํ•จ์˜ ์ˆ˜๊ฐ€ ๊ฐ™๋‹ค๊ณ  ํ•  ๋•Œ, ์†Œํฌํ•จ์˜ ๊ฐœ์ˆ˜๋Š” ๋ชจ๋‘ ๋ช‡ ๊ฐœ์ž…๋‹ˆ๊นŒ?
Comparison
var_a = 4 var_b = 1 var_c = 6 var_d = 7 list_a= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) li...
614
614
[OP_LIST_SOL] 4 1 6 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 1 [OP_LIST_SEARCH_FIXED_DIGIT] 3 [OP_LIST_MIN]
var_a = 4 var_b = 1 var_c = 6 var_d = 7 list_a= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) li...
[OP_LIST_SOL] 4 1 6 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 1 [OP_LIST_SEARCH_FIXED_DIGIT] 3 [OP_LIST_MIN]
Using 3 of numbers 4, 1, 6, 7, what is the third smallest number with 1 in the tens place?
4, 1, 6, 7 ์ค‘ 3๊ฐœ๋ฅผ ์‚ฌ์šฉํ•˜์—ฌ ์‹ญ์˜ ์ž๋ฆฌ ์ˆซ์ž๊ฐ€ 1์ธ ์„ธ ๋ฒˆ์ฉจ ์ž‘์€ ์ˆ˜๋Š” ๋ฌด์—‡์ž…๋‹ˆ๊นŒ?
Possibility
var_a = 0.09 var_b = 1000 var_c = var_a * var_b var_d = 3 var_e = var_c / var_d var_f = 4 var_g = var_e * var_f print(int(var_g))
120
120
0.09 1000 [OP_MUL] 3 [OP_DIV] 4 [OP_MUL]
var_a = 0.09 var_b = 1000 var_c = var_a * var_b var_d = 3 var_e = var_c / var_d var_f = 4 var_g = var_e * var_f print(int(var_g))
0.09 1000 [OP_MUL] 3 [OP_DIV] 4 [OP_MUL]
Ayeon tries to go to a hospital 0.09 kilometers (km) away. If Ayeon takes 4 seconds to go 3 meters (m), how many seconds does it take for her to get to the hospital?
์•„์—ฐ์ด๋Š” 0.09 ํ‚ฌ๋กœ๋ฏธํ„ฐ(ใŽž) ๋–จ์–ด์ง„ ๋ณ‘์›์— ๊ฐ€๋ ค๊ณ  ํ•ฉ๋‹ˆ๋‹ค. ์•„์—ฐ์ด๊ฐ€ 3 ๋ฏธํ„ฐ(m)๋ฅผ ๊ฐ€๋Š”๋ฐ 4์ดˆ๊ฐ€ ๊ฑธ๋ฆฐ๋‹ค๋ฉด ๋ณ‘์›๊นŒ์ง€ ๊ฐ€๋Š”๋ฐ ๊ฑธ๋ฆฐ ์‹œ๊ฐ„์€ ๋ช‡ ์ดˆ์ธ๊ฐ€์š”?
Arithmetic calculation
var_a = 3 var_b = 0.25 var_c = var_a / var_b print(int(var_c))
12
12
3 1/4 [OP_DIV]
var_a = 3 var_b = 0.25 var_c = var_a / var_b print(int(var_c))
3 1/4 [OP_DIV]
You will need a 1/4 meter (m) block of wood. How many blocks can you make with 3 meters (m) of wood?
1/4๋ฏธํ„ฐ(m)์˜ ๋‚˜๋ฌดํ† ๋ง‰์ด ํ•„์š”ํ•ฉ๋‹ˆ๋‹ค. 3๋ฏธํ„ฐ(m)์˜ ๋‚˜๋ฌด๋กœ ๋ช‡ ๋„๋ง‰์„ ๋งŒ๋“ค ์ˆ˜ ์žˆ๋‚˜์š”?
Arithmetic calculation
var_a = 7 var_b = 13 var_c = var_a + var_b var_d = 1 var_e = var_c - var_d var_f = 8 var_g = 14 var_h = var_f + var_g var_i = 1 var_j = var_h - var_i var_k = var_e * var_j print(int(var_k))
399
399
7 13 [OP_ADD] 1 [OP_SUB] 8 14 [OP_ADD] 1 [OP_SUB] [OP_MUL]
var_a = 7 var_b = 13 var_c = var_a + var_b var_d = 1 var_e = var_c - var_d var_f = 8 var_g = 14 var_h = var_f + var_g var_i = 1 var_j = var_h - var_i var_k = var_e * var_j print(int(var_k))
7 13 [OP_ADD] 1 [OP_SUB] 8 14 [OP_ADD] 1 [OP_SUB] [OP_MUL]
By drawing lots, Jeongyun picked the seat 7th from the left, 13th from the right, 8th from the front, and 14th from the back. If the number of seats in each row is the same, how many seats are there in the classroom?
์ •์œค์ด๋Š” ์ œ๋น„๋ฝ‘๊ธฐ๋กœ ๊ต์‹ค ์™ผ์ชฝ์—์„œ 7๋ฒˆ์งธ, ์˜ค๋ฅธ์ชฝ์—์„œ 13๋ฒˆ์งธ, ์•ž์—์„œ 8๋ฒˆ์งธ, ๋’ค์—์„œ 14๋ฒˆ์งธ์— ์žˆ๋Š” ์ž๋ฆฌ๋ฅผ ๋ฝ‘์•˜์Šต๋‹ˆ๋‹ค. ๊ฐ ์ค„๋งˆ๋‹ค ์žˆ๋Š” ์ž๋ฆฌ์˜ ์ˆ˜๊ฐ€ ๊ฐ™๋‹ค๊ณ  ํ•  ๋•Œ, ๊ต์‹ค ์•ˆ ์ž๋ฆฌ์˜ ๊ฐœ์ˆ˜๋Š” ๋ชจ๋‘ ๋ช‡ ๊ฐœ์ž…๋‹ˆ๊นŒ?
Comparison
var_a = 103 var_b = 5 var_c = var_a + var_b var_d = 3 var_e = var_c / var_d var_f = 3 var_g = var_e / var_f var_h = 5 var_i = var_g - var_h print(int(var_i))
7
7
103 5 [OP_ADD] 3 [OP_DIV] 3 [OP_DIV] 5 [OP_SUB]
var_a = 103 var_b = 5 var_c = var_a + var_b var_d = 3 var_e = var_c / var_d var_f = 3 var_g = var_e / var_f var_h = 5 var_i = var_g - var_h print(int(var_i))
103 5 [OP_ADD] 3 [OP_DIV] 3 [OP_DIV] 5 [OP_SUB]
I needed to divide a number by 3 and then subtract 5. However, I mistakenly multiplied this number by 3 and subtracted 5 and got 103 as a result. Find the correct calculated value.
์–ด๋–ค ์ˆ˜๋ฅผ 3์œผ๋กœ ๋‚˜๋ˆˆ ๋‹ค์Œ 5๋ฅผ ๋นผ์•ผ ํ•  ๊ฒƒ์„ ์ž˜๋ชปํ•˜์—ฌ ์–ด๋–ค ์ˆ˜์— 3์„ ๊ณฑํ•œ ๋‹ค์Œ 5๋ฅผ ๋บ๋”๋‹ˆ 103์ด ๋˜์—ˆ์Šต๋‹ˆ๋‹ค. ๋ฐ”๋ฅด๊ฒŒ ๊ณ„์‚ฐํ•œ ๊ฐ’์„ ๊ตฌํ•˜์‹œ์˜ค.
Correspondence
var_a = 52 var_b = 48 var_c = var_a + var_b var_d = 48 var_e = var_c + var_d print(int(var_e))
148
148
52 48 [OP_ADD] 48 [OP_ADD]
var_a = 52 var_b = 48 var_c = var_a + var_b var_d = 48 var_e = var_c + var_d print(int(var_e))
52 48 [OP_ADD] 48 [OP_ADD]
52 is the result of mistakenly subtracting 48 from a certain number while 48 had to be added. Find the result of the correct calculation.
52๋Š” ์–ด๋–ค ์ˆ˜์— 48์„ ๋”ํ•ด์•ผ ํ•˜๋Š”๋ฐ ์ž˜๋ชปํ•˜์—ฌ ๋นผ์„œ ๋‚˜์˜จ ๊ฒฐ๊ณผ์ด๋‹ค. ๋ฐ”๋ฅด๊ฒŒ ๊ณ„์‚ฐํ•œ ๊ฒฐ๊ณผ๋ฅผ ๊ตฌํ•˜์—ฌ๋ผ.
Correspondence
var_a = 10 var_b = 11 var_c = 12 var_d = 13 list_a= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)...
0.91
0.91
[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_DIV]
var_a = 10 var_b = 11 var_c = 12 var_d = 13 list_a= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)...
[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_DIV]
There are four numbers 10, 11, 12, and 13. What is the difference between the smallest number and the next smallest number?
4๊ฐœ์˜ ์ˆ˜ 10, 11, 12, 13์ด ์žˆ์Šต๋‹ˆ๋‹ค. ๊ทธ ์ค‘์—์„œ ๊ฐ€์žฅ ์ž‘์€ ์ˆ˜์™€ ๊ทธ ๋‹ค์Œ์œผ๋กœ ์ž‘์€ ์ˆ˜๋กœ ๋‚˜๋ˆˆ ๊ฐ’์€ ์–ผ๋งˆ์ž…๋‹ˆ๊นŒ?
Arithmetic calculation
var_a = '์ •๊ตญ' var_b = '์œค๊ธฐ' list_a= [] if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_c = 6 var_d = 3 var_e = var_c * var_d var_f = 4 list_b= [] if "/" in str(var_f): var_f = eval(str(var_f)) list_b.a...
์œค๊ธฐ
Yoongi
[OP_LIST_SOL] ์ •๊ตญ ์œค๊ธฐ [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_MUL] 4 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]
var_a = 'Jungkook' var_b = 'Yoongi' list_a= [] if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_c = 6 var_d = 3 var_e = var_c * var_d var_f = 4 list_b= [] if "/" in str(var_f): var_f = eval(str(var_f)...
[OP_LIST_SOL] Jungkook Yoongi [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_MUL] 4 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]
Jungkook collected 6 times 3 apples, and Yoongi collected 4 apples. Who has fewer apples?
์ •๊ตญ์—๋Š” 6 ๊ณฑํ•˜๊ธฐ 3๋งŒํผ ์‚ฌ๊ณผ๋ฅผ ๋ชจ์•˜๊ณ , ์œค๊ธฐ๋Š” 4๊ฐœ์˜ ์‚ฌ๊ณผ๋ฅผ ๋ชจ์•˜์Šต๋‹ˆ๋‹ค. ๋ˆ„๊ฐ€ ๋” ์‚ฌ๊ณผ๋ฅผ ์ ๊ฒŒ ๊ฐ€์ง€๊ณ  ์žˆ์Šต๋‹ˆ๊นŒ?
Comparison
var_a = '2A32-BBB=1BBB' var_b = 'B' ans_dict = dict() var_a = var_a.replace('ร—','*') var_a = var_a.replace('x','*') var_a = var_a.replace('รท','/') variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']) for v in set(var_a):...
3
3
2A32-BBB=1BBB B [OP_DIGIT_UNK_SOLVER] 2A32-BBB=1BBB A [OP_DIGIT_UNK_SOLVER] [OP_SUB]
var_a = '2A32-BBB=1BBB' var_b = 'B' ans_dict = dict() var_a = var_a.replace('ร—','*') var_a = var_a.replace('x','*') var_a = var_a.replace('รท','/') variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']) for v in set(var_a):...
2A32-BBB=1BBB B [OP_DIGIT_UNK_SOLVER] 2A32-BBB=1BBB A [OP_DIGIT_UNK_SOLVER] [OP_SUB]
Given 2A32-BBB=1BBB, find B-A when A and B are two different numbers.
2A32-BBB=1BBB์ž…๋‹ˆ๋‹ค. A,B๋Š” ์„œ๋กœ ๋‹ค๋ฅธ ๋‘ ์ˆ˜ ์ผ๋•Œ B-A๋ฅผ ๊ตฌํ•˜์‹œ์˜ค.
Correspondence
var_a = 40 var_b = 4 var_c = var_a - var_b var_d = 4 var_e = var_c / var_d print(int(var_e))
9
9
40 4 [OP_SUB] 4 [OP_DIV]
var_a = 40 var_b = 4 var_c = var_a - var_b var_d = 4 var_e = var_c / var_d print(int(var_e))
40 4 [OP_SUB] 4 [OP_DIV]
In the bookstore, all but 4 of the 40 books were sold out. There were 4 customers in total, and they all bought the same number of books. How many books did a customer buy?
์„œ์ ์—์„œ 40๊ถŒ์˜ ์ฑ… ์ค‘ 4๊ถŒ์„ ์ œ์™ธํ•œ ์ฑ…๋“ค์ด ๋ชจ๋‘ ํŒ”๋ ธ์Šต๋‹ˆ๋‹ค. ์†๋‹˜์ด ๋ชจ๋‘ 4๋ช…์ด๊ณ  ์†๋‹˜๋“ค์ด ๋ชจ๋‘ ๊ฐ™์€ ์ˆ˜์˜ ์ฑ…์„ ๊ตฌ๋งคํ•˜์˜€์Šต๋‹ˆ๋‹ค. ์†๋‹˜๋“ค์€ ๋ช‡ ๊ถŒ์˜ ์ฑ…์„ ์‚ฌ๊ฐ”์Šต๋‹ˆ๊นŒ?
Correspondence
var_a = '8B-A3=38' var_b = 'B' ans_dict = dict() var_a = var_a.replace('ร—','*') var_a = var_a.replace('x','*') var_a = var_a.replace('รท','/') variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']) for v in set(var_a): ...
1
1
8B-A3=38 B [OP_DIGIT_UNK_SOLVER]
var_a = '8B-A3=38' var_b = 'B' ans_dict = dict() var_a = var_a.replace('ร—','*') var_a = var_a.replace('x','*') var_a = var_a.replace('รท','/') variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']) for v in set(var_a): ...
8B-A3=38 B [OP_DIGIT_UNK_SOLVER]
There are two different numbers A and B. Find B from the two-digit subtraction equation of 8B-A3=38.
์„œ๋กœ ๋‹ค๋ฅธ ๋‘ ์ˆ˜ A, B๊ฐ€ ์žˆ์Šต๋‹ˆ๋‹ค. ๋‘ ์ž๋ฆฌ ์ˆ˜๋ผ๋ฆฌ์˜ ๋บ„์…ˆ์‹ 8B-A3=38์—์„œ B๋ฅผ ๊ตฌํ•˜์‹œ์˜ค.
Correspondence
var_a = 502 var_b = 18 var_c = 57 var_d = var_b + var_c var_e = 44 var_f = var_d - var_e var_g = var_a - var_f var_h = 17 var_i = var_g + var_h var_j = 2 var_k = var_i / var_j print(int(var_k))
244
244
502 18 57 [OP_ADD] 44 [OP_SUB] [OP_SUB] 17 [OP_ADD] 2 [OP_DIV]
var_a = 502 var_b = 18 var_c = 57 var_d = var_b + var_c var_e = 44 var_f = var_d - var_e var_g = var_a - var_f var_h = 17 var_i = var_g + var_h var_j = 2 var_k = var_i / var_j print(int(var_k))
502 18 57 [OP_ADD] 44 [OP_SUB] [OP_SUB] 17 [OP_ADD] 2 [OP_DIV]
There were 17 fewer children than adults on the train at the first station. At the next station, 57 adults and 18 children got on and 44 got off. If there are 502 people on the train right now, how many adults got on the train at the first station?
์ฒซ ๋ฒˆ์งธ ์—ญ์—์„œ ๊ธฐ์ฐจ๋ฅผ ํƒ„ ์–ด๋ฆฐ์ด๋Š” ์–ด๋ฅธ๋ณด๋‹ค 17๋ช…์ด ์ ์—ˆ์Šต๋‹ˆ๋‹ค. ๋‹ค์Œ ์—ญ์—์„œ ์–ด๋ฅธ 57๋ช…๊ณผ ์–ด๋ฆฐ์ด 18๋ช…์ด ํƒ€๊ณ  44๋ช…์ด ๋‚ด๋ ธ์Šต๋‹ˆ๋‹ค. ์ง€๊ธˆ ๊ธฐ์ฐจ๋ฅผ ํƒ€๊ณ  ์žˆ๋Š” ์‚ฌ๋žŒ์ด 502๋ช…์ด๋ผ๋ฉด ์ฒซ ๋ฒˆ์งธ ์—ญ์—์„œ ๊ธฐ์ฐจ๋ฅผ ํƒ„ ์–ด๋ฅธ์€ ๋ช‡ ๋ช…์ธ์ง€ ๊ตฌํ•˜์‹œ์˜ค.
Comparison
var_a = 44 var_b = 2 var_c = var_a + var_b var_d = 1 var_e = var_c - var_d print(int(var_e))
45
45
44 2 [OP_ADD] 1 [OP_SUB]
var_a = 44 var_b = 2 var_c = var_a + var_b var_d = 1 var_e = var_c - var_d print(int(var_e))
44 2 [OP_ADD] 1 [OP_SUB]
There are 44 students in A class. B class has 2 more studemts than A class, and C class has 1 less stuendt than B class. How many students are in C class?
(๊ฐ€) ๋ฐ˜ ํ•™์ƒ์€ ๋ชจ๋‘ 44๋ช…์ž…๋‹ˆ๋‹ค. (๋‚˜) ๋ฐ˜์€ (๊ฐ€) ๋ฐ˜๋ณด๋‹ค 2๋ช… ๋” ๋งŽ๊ณ , (๋‹ค) ๋ฐ˜์€ (๋‚˜) ๋ฐ˜๋ณด๋‹ค 1๋ช… ๋” ์ ์Šต๋‹ˆ๋‹ค. (๋‹ค) ๋ฐ˜ ํ•™์ƒ์€ ๋ชจ๋‘ ๋ช‡ ๋ช…์ž…๋‹ˆ๊นŒ?
Arithmetic calculation
var_a = 6 var_b = 100 var_c = var_a * var_b var_d = 4 var_e = 100 var_f = var_d * var_e var_g = var_c * var_f var_h = 60 var_i = 20 var_j = var_h * var_i var_k = var_g / var_j print(int(var_k))
200
200
6 100 [OP_MUL] 4 100 [OP_MUL] [OP_MUL] 60 20 [OP_MUL] [OP_DIV]
var_a = 6 var_b = 100 var_c = var_a * var_b var_d = 4 var_e = 100 var_f = var_d * var_e var_g = var_c * var_f var_h = 60 var_i = 20 var_j = var_h * var_i var_k = var_g / var_j print(int(var_k))
6 100 [OP_MUL] 4 100 [OP_MUL] [OP_MUL] 60 20 [OP_MUL] [OP_DIV]
On a road measuring 6 meters (m) wide and 4 meters (m) long, we are going to attach rectangular bricks 60 centimeters (cm) wide and 20 centimeters (cm) tall without overlapping. How many bricks are needed to fill the road?
๊ฐ€๋กœ๊ฐ€ 6๋ฏธํ„ฐ(m), ์„ธ๋กœ๊ฐ€ 4๋ฏธํ„ฐ(m)์ธ ๋„๋กœ์— ๊ฐ€๋กœ๊ฐ€ 60์„ผํ‹ฐ๋ฏธํ„ฐ(ใŽ), ์„ธ๋กœ๊ฐ€ 20์„ผํ‹ฐ๋ฏธํ„ฐ(ใŽ)์ธ ์ง์‚ฌ๊ฐํ˜• ๋ชจ์–‘์˜ ๋ฒฝ๋Œ์„ ๋นˆํ‹ˆ์—†์ด ๊ฒน์น˜์ง€ ์•Š๊ฒŒ ๋ถ™์ด๋ ค๊ณ  ํ•ฉ๋‹ˆ๋‹ค. ๋„๋กœ๋ฅผ ๋ฉ”์šฐ๊ธฐ ์œ„ํ•ด ํ•„์š”ํ•œ ๋ฒฝ๋Œ์˜ ๊ฐœ์ˆ˜๋Š” ๋ช‡ ๊ฐœ์ž…๋‹ˆ๊นŒ?
Geometry
var_a = '1/4ร—1/8=1/(4ร—A)=1/B' var_b = 'B' ans_dict = dict() var_a = var_a.replace('ร—','*') var_a = var_a.replace('x','*') var_a = var_a.replace('รท','/') variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']) for v in set(v...
32
32
1/4ร—1/8=1/(4ร—A)=1/B B [OP_NUM_UNK_SOLVER]
var_a = '1/4ร—1/8=1/(4ร—A)=1/B' var_b = 'B' ans_dict = dict() var_a = var_a.replace('ร—','*') var_a = var_a.replace('x','*') var_a = var_a.replace('รท','/') variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']) for v in set(v...
1/4ร—1/8=1/(4ร—A)=1/B B [OP_NUM_UNK_SOLVER]
What is B when 1/4ร—1/8=1/(4ร—A)=1/B?
1/4ร—1/8=1/(4ร—A)=1/B ์ผ๋•Œ B๋Š” ๋ฌด์—‡์ธ๊ฐ€?
Correspondence
var_a = 45 var_b = 27 var_c = var_a - var_b var_d = 9 var_e = var_c + var_d var_f = 27 var_g = var_e + var_f var_h = 45 var_i = 27 var_j = var_h - var_i var_k = 9 var_l = var_j + var_k var_m = var_g + var_l var_n = 45 var_o = 9 var_p = var_n - var_o var_q = var_m + var_p print(int(var_q))
117
117
45 27 [OP_SUB] 9 [OP_ADD] 27 [OP_ADD] 45 27 [OP_SUB] 9 [OP_ADD] [OP_ADD] 45 9 [OP_SUB] [OP_ADD]
var_a = 45 var_b = 27 var_c = var_a - var_b var_d = 9 var_e = var_c + var_d var_f = 27 var_g = var_e + var_f var_h = 45 var_i = 27 var_j = var_h - var_i var_k = 9 var_l = var_j + var_k var_m = var_g + var_l var_n = 45 var_o = 9 var_p = var_n - var_o var_q = var_m + var_p print(int(var_q))
45 27 [OP_SUB] 9 [OP_ADD] 27 [OP_ADD] 45 27 [OP_SUB] 9 [OP_ADD] [OP_ADD] 45 9 [OP_SUB] [OP_ADD]
Minyoung, Yoojung, and Eunji decided to divide marbles they have. Minyoung first brought 27 more marbles than Yoojung brought and if Minyoung gives Eunji 9 marbles, Minyoung and Eunji have 45 marbles each, how many marbles do the three people have in total?
๋ฏผ์˜, ์œ ์ •, ์€์ง€ ์„ธ ์‚ฌ๋žŒ์ด ๋ชจ์—ฌ ๊ตฌ์Šฌ์„ ๋‚˜๋ˆ„๊ธฐ๋กœ ํ–ˆ์Šต๋‹ˆ๋‹ค. ์ฒ˜์Œ ๋ฏผ์˜์ด๊ฐ€ ๊ฐ€์ง€๊ณ  ์˜จ ๊ตฌ์Šฌ์€ ์œ ์ •์ด๊ฐ€ ๊ฐ€์ง€๊ณ  ์˜จ ๊ตฌ์Šฌ๋ณด๋‹ค 27๊ฐœ ๋งŽ๊ณ  ๋ฏผ์˜์ด๊ฐ€ ์€์ง€์—๊ฒŒ ๊ตฌ์Šฌ 9๊ฐœ๋ฅผ ์ฃผ๋ฉด ๋ฏผ์˜์ด์™€ ์€์ง€๊ฐ€ ๊ฐ€์ง€๊ณ  ์žˆ๋Š” ๊ตฌ์Šฌ์ด 45๊ฐœ๋กœ ๊ฐ™์•„์ง„๋‹ค๊ณ  ํ•  ๋•Œ, ์„ธ ์‚ฌ๋žŒ์ด ๊ฐ€์ง€๊ณ  ์žˆ๋Š” ๊ตฌ์Šฌ์˜ ์ด ๊ฐœ์ˆ˜๋Š” ๋ช‡ ๊ฐœ์ž…๋‹ˆ๊นŒ?
Arithmetic calculation
var_a = 138.6 var_b = 10 var_c = 2 var_d = var_b ** var_c var_e = 1 var_f = var_d - var_e var_g = var_a / var_f print('{:.2f}'.format(round(var_g+1e-10,2)))
1.40
1.4
138.6 10 2 [OP_POW] 1 [OP_SUB] [OP_DIV]
var_a = 138.6 var_b = 10 var_c = 2 var_d = var_b ** var_c var_e = 1 var_f = var_d - var_e var_g = var_a / var_f print('{:.2f}'.format(round(var_g+1e-10,2)))
138.6 10 2 [OP_POW] 1 [OP_SUB] [OP_DIV]
When you move the decimal point of a prime number two places to the right, it becomes 138.6 more than the original prime number. Find the original prime number.
์–ด๋–ค ์†Œ์ˆ˜์˜ ์†Œ์ˆ˜์ ์„ ์˜ค๋ฅธ์ชฝ์œผ๋กœ ๋‘ ์ž๋ฆฌ ์˜ฎ๊ธฐ๋ฉด ์›๋ž˜์˜ ์†Œ์ˆ˜๋ณด๋‹ค 138.6๋งŒํผ ์ปค์ง‘๋‹ˆ๋‹ค. ์›๋ž˜์˜ ์†Œ์ˆ˜๋ฅผ ๊ตฌํ•˜์‹œ์˜ค.
Correspondence
var_a = 15 var_b = 8 var_c = var_a - var_b var_d = 1 var_e = var_c + var_d print(int(var_e))
8
8
15 8 [OP_SUB] 1 [OP_ADD]
var_a = 15 var_b = 8 var_c = var_a - var_b var_d = 1 var_e = var_c + var_d print(int(var_e))
15 8 [OP_SUB] 1 [OP_ADD]
15 balls of different weights are placed in a row in order of weight from the lightest. The ball (a) is placed eighth from the front. If you place the balls again, in a row in order of weight from the heaviest, at what position will the ball (A) be placed from the front?
๊ฐ๊ฐ์˜ ๋ฌด๊ฒŒ๊ฐ€ ๋‹ค๋ฅธ ๊ณต 15๊ฐœ๋ฅผ ๋ฌด๊ฒŒ๊ฐ€ ๊ฐ€๋ฒผ์šด ๊ฒƒ๋ถ€ํ„ฐ ์ˆœ์„œ๋Œ€๋กœ ํ•œ ์ค„๋กœ ๋†“์•˜์Šต๋‹ˆ๋‹ค. ๊ณต (๊ฐ€)๋Š” ์•ž์—์„œ 8๋ฒˆ์งธ์— ๋†“์—ฌ ์žˆ์Šต๋‹ˆ๋‹ค. ๋ฌด๊ฒŒ๊ฐ€ ๋ฌด๊ฑฐ์šด ๊ฒƒ๋ถ€ํ„ฐ ์ˆœ์„œ๋Œ€๋กœ ๋‹ค์‹œ ํ•œ ์ค„๋กœ ๋†“์œผ๋ฉด ๊ณต (๊ฐ€)๋Š” ์•ž์—์„œ ๋ช‡ ๋ฒˆ์งธ์— ๋†“์ด๊ฒŒ ๋ฉ๋‹ˆ๊นŒ?
Comparison
var_a = 27 var_b = 7 var_c = var_a - var_b var_d = 5 var_e = var_c / var_d var_f = 5 var_g = var_e + var_f var_h = 7 var_i = var_g * var_h print(int(var_i))
63
63
27 7 [OP_SUB] 5 [OP_DIV] 5 [OP_ADD] 7 [OP_MUL]
var_a = 27 var_b = 7 var_c = var_a - var_b var_d = 5 var_e = var_c / var_d var_f = 5 var_g = var_e + var_f var_h = 7 var_i = var_g * var_h print(int(var_i))
27 7 [OP_SUB] 5 [OP_DIV] 5 [OP_ADD] 7 [OP_MUL]
27 minus 7 equals the multiplication of one number and 5. What is the product of 7 and the sum of the number and 5?
27์—์„œ 7์„ ๋บ€ ๊ฐ’์€ ์–ด๋–ค ์ˆ˜์™€ 5๋ฅผ ๊ณฑํ•œ ๊ฐ’๊ณผ ๊ฐ™๋‹ค. ์–ด๋–ค ์ˆ˜์™€ 5์˜ ํ•ฉ์— 7์„ ๊ณฑํ•˜๋ฉด ์–ผ๋งˆ์ธ์ง€ ๊ตฌํ•˜์‹œ์˜ค.
Correspondence
var_a = '์œ„์ธ์ „' var_b = '๋™ํ™”์ฑ…' list_a= [] if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_c = 0.3 var_d = 0.27 list_b= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_b.append(var_d) if "/" in st...
์œ„์ธ์ „
biography
[OP_LIST_SOL] ์œ„์ธ์ „ ๋™ํ™”์ฑ… [OP_LIST_EOL] [OP_LIST_SOL] 0.3 0.27 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]
var_a = 'biography' var_b = 'fairy-tale' list_a= [] if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_c = 0.3 var_d = 0.27 list_b= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_b.append(var_d)...
[OP_LIST_SOL] biography fairy-tale [OP_LIST_EOL] [OP_LIST_SOL] 0.3 0.27 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]
The weight of one biography is 0.3 kilograms (kg), and the weight of one fairy-tale book is 0.27 kilograms (kg). Which one is heavier, the biography or the fairy tale book?
์œ„์ธ์ „ ํ•œ ๊ถŒ์˜ ๋ฌด๊ฒŒ๋Š” 0.3ํ‚ฌ๋กœ๊ทธ๋žจ(ใŽ)์ด๊ณ , ๋™ํ™”์ฑ… ํ•œ ๊ถŒ์˜ ๋ฌด๊ฒŒ๋Š” 0.27ํ‚ฌ๋กœ๊ทธ๋žจ(ใŽ)์ž…๋‹ˆ๋‹ค. ์œ„์ธ์ „๊ณผ ๋™ํ™”์ฑ… ์ค‘์—์„œ ์–ด๋А ๊ฒƒ์ด ๋” ๋ฌด๊ฒ์Šต๋‹ˆ๊นŒ?
Comparison
var_a = 100 var_b = 999 var_c = 1 list_a = [i for i in range(var_a, var_b + 1, var_c)] var_d = 6 list_b = [] var_d = int(var_d) for i in list_a: i = int(i) if i % var_d == 0: list_b.append(i) var_e = 5 list_c = [] var_e = int(var_e) for i in list_b: i = int(i) if i % var_e == 0: list_c.a...
720
720
100 999 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]
var_a = 100 var_b = 999 var_c = 1 list_a = [i for i in range(var_a, var_b + 1, var_c)] var_d = 6 list_b = [] var_d = int(var_d) for i in list_a: i = int(i) if i % var_d == 0: list_b.append(i) var_e = 5 list_c = [] var_e = int(var_e) for i in list_b: i = int(i) if i % var_e == 0: list_c.a...
100 999 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]
What is the largest three-digit number divisible by the numbers 6, 5, 8, and 9?
์ˆซ์ž 6, 5, 8, 9๋กœ ๋‚˜๋ˆ„์–ด ๋–จ์–ด์งˆ ์ˆ˜ ์žˆ๋Š” ์„ธ ์ž๋ฆฌ ์ˆ˜ ์ค‘ ๊ฐ€์žฅ ํฐ ์ˆ˜๋Š” ๋ฌด์—‡์ž…๋‹ˆ๊นŒ?
Arithmetic calculation
var_a = 954 var_b = 468 var_c = var_a - var_b var_d = 954 var_e = var_c + var_d print(int(var_e))
1440
1440
954 468 [OP_SUB] 954 [OP_ADD]
var_a = 954 var_b = 468 var_c = var_a - var_b var_d = 954 var_e = var_c + var_d print(int(var_e))
954 468 [OP_SUB] 954 [OP_ADD]
It is said that there are 468 more white Go stones than black Go stones. There are 954 white stones. Find the numbers of all Go stones.
๊ฒ€์€ ๋ฐ”๋‘‘๋Œ๋ณด๋‹ค ํฐ ๋ฐ”๋‘‘๋Œ์ด 468๊ฐœ ๋” ๋งŽ๋‹ค๊ณ  ํ•œ๋‹ค. 954๊ฐœ์˜ ํฐ์ƒ‰ ๋Œ์ด ์žˆ์Šต๋‹ˆ๋‹ค. ๋ฐ”๋‘‘๋Œ์˜ ์ˆ˜๋ฅผ ๋ชจ๋‘ ๊ตฌํ•˜์‹ญ์‹œ์˜ค.
Correspondence
var_a = 10 var_b = 11 var_c = 12 var_d = 13 list_a= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)...
23
23
[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_ADD]
var_a = 10 var_b = 11 var_c = 12 var_d = 13 list_a= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)...
[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_ADD]
There are four numbers 10, 11, 12, and 13. What is the sum of the second largest number and the second smallest number?
4๊ฐœ์˜ ์ˆ˜ 10, 11, 12, 13์ด ์žˆ์Šต๋‹ˆ๋‹ค. ๊ทธ ์ค‘์—์„œ 2๋ฒˆ์งธ๋กœ ํฐ ์ˆ˜์™€ 2๋ฒˆ์งธ๋กœ ์ž‘์€ ์ˆ˜์˜ ํ•ฉ์€ ์–ผ๋งˆ์ž…๋‹ˆ๊นŒ?
Arithmetic calculation
var_a = 1 var_b = 3 var_c = 0 var_d = 5 list_a= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) li...
5013
5013
[OP_LIST_SOL] 1 3 0 5 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 6 [OP_LIST_MAX]
var_a = 1 var_b = 3 var_c = 0 var_d = 5 list_a= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) li...
[OP_LIST_SOL] 1 3 0 5 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 6 [OP_LIST_MAX]
There are cards each with the numbers 1, 3, 0, and 5 on it. When making a four-digit number using the cards once, what is the 6th largest number?
1, 3, 0, 5๊ฐ€ ์ ํžŒ ์นด๋“œ๊ฐ€ ๊ฐ๊ฐ ํ•œ ์žฅ์”ฉ ์žˆ์Šต๋‹ˆ๋‹ค. ์นด๋“œ๋ฅผ ํ•œ๋ฒˆ์”ฉ๋งŒ ์‚ฌ์šฉํ•ด์„œ ๋„ค ์ž๋ฆฌ ์ˆ˜๋ฅผ ๋งŒ๋“ค ๋•Œ, 6๋ฒˆ์งธ๋กœ ํฐ ์ˆ˜๋Š” ๋ฌด์—‡์ž…๋‹ˆ๊นŒ?
Possibility
var_a = 25 var_b = 13 var_c = var_a - var_b var_d = 1 var_e = var_c - var_d print(int(var_e))
11
11
25 13 [OP_SUB] 1 [OP_SUB]
var_a = 25 var_b = 13 var_c = var_a - var_b var_d = 1 var_e = var_c - var_d print(int(var_e))
25 13 [OP_SUB] 1 [OP_SUB]
25 students stand in a line. Thirteen students are standing behind Seokjin. How many students are standing in front of Seokjin?
ํ•™์ƒ 25๋ช…์ด ํ•œ ์ค„๋กœ ์„œ ์žˆ์Šต๋‹ˆ๋‹ค. ์„์ง„์ด์˜ ๋’ค์— 13๋ช…์˜ ํ•™์ƒ๋“ค์ด ์„œ ์žˆ์Šต๋‹ˆ๋‹ค. ์„์ง„์ด์˜ ์•ž์— ์„œ ์žˆ๋Š” ํ•™์ƒ์€ ๋ช‡ ๋ช…์ž…๋‹ˆ๊นŒ?
Comparison
var_a = 10 var_b = 11 var_c = 12 list_a= [] if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_d = 1 list_b=list_a.copy() list_b.sort(...
21
21
[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_ADD]
var_a = 10 var_b = 11 var_c = 12 list_a= [] if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_d = 1 list_b=list_a.copy() list_b.sort(...
[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_ADD]
There are three numbers: 10, 11 and 12. What is the sum of the smallest number and the second smallest number?
3๊ฐœ์˜ ์ˆ˜ 10, 11, 12๊ฐ€ ์žˆ์Šต๋‹ˆ๋‹ค. ๊ทธ ์ค‘์—์„œ ๊ฐ€์žฅ ์ž‘์€ ์ˆ˜์™€ 2๋ฒˆ์งธ๋กœ ์ž‘์€ ์ˆ˜์˜ ํ•ฉ์€ ์–ผ๋งˆ์ž…๋‹ˆ๊นŒ?
Arithmetic calculation
var_a = 12 var_b = 11 var_c = var_a + var_b var_d = 1 var_e = var_c - var_d var_f = 18 var_g = 8 var_h = var_f + var_g var_i = 1 var_j = var_h - var_i var_k = var_e * var_j print(int(var_k))
550
550
12 11 [OP_ADD] 1 [OP_SUB] 18 8 [OP_ADD] 1 [OP_SUB] [OP_MUL]
var_a = 12 var_b = 11 var_c = var_a + var_b var_d = 1 var_e = var_c - var_d var_f = 18 var_g = 8 var_h = var_f + var_g var_i = 1 var_j = var_h - var_i var_k = var_e * var_j print(int(var_k))
12 11 [OP_ADD] 1 [OP_SUB] 18 8 [OP_ADD] 1 [OP_SUB] [OP_MUL]
Students are sitting on the playground. Yujeong is seated in the 12th row from the left, 11th row from the right, 18th row from the front, and 8th row from the back. How many students are sitting on the playground, assuming the same number of students are in each row?
์šด๋™์žฅ์— ํ•™์ƒ๋“ค์ด ์•‰์•„ ์žˆ์Šต๋‹ˆ๋‹ค. ์œ ์ •์ด๋Š” ์™ผ์ชฝ์—์„œ 12๋ฒˆ์งธ ์—ด, ์˜ค๋ฅธ์ชฝ์—์„œ 11๋ฒˆ์งธ ์—ด, ์•ž์—์„œ 18๋ฒˆ์งธ ์ค„, ๋’ค์—์„œ 8๋ฒˆ์งธ ์ค„์— ์•‰์•„ ์žˆ์Šต๋‹ˆ๋‹ค. ๊ฐ ์ค„๋งˆ๋‹ค ํ•™์ƒ์˜ ์ˆ˜๊ฐ€ ๊ฐ™๋‹ค๊ณ  ํ•  ๋•Œ, ์šด๋™์žฅ์— ์•‰์•„ ์žˆ๋Š” ํ•™์ƒ์€ ๋ชจ๋‘ ๋ช‡ ๋ช…์ž…๋‹ˆ๊นŒ?
Comparison
var_a = 25 var_b = 9 var_c = var_a * var_b var_d = 7 var_e = var_c + var_d var_f = 9 var_g = var_e * var_f print(int(var_g))
2088
2088
25 9 [OP_MUL] 7 [OP_ADD] 9 [OP_MUL]
var_a = 25 var_b = 9 var_c = var_a * var_b var_d = 7 var_e = var_c + var_d var_f = 9 var_g = var_e * var_f print(int(var_g))
25 9 [OP_MUL] 7 [OP_ADD] 9 [OP_MUL]
When a number is divided by 9, the quotient is divisible by 25. What do you get when the number is added to 7 and multiplied by 9?
์–ด๋–ค ์ˆ˜๋ฅผ 9๋กœ ๋‚˜๋ˆ„์—ˆ๋”๋‹ˆ ๋ชซ์ด 25๋กœ ๋‚˜๋ˆ„์–ด๋–จ์–ด์กŒ์Šต๋‹ˆ๋‹ค. ์–ด๋–ค ์ˆ˜์— 7์„ ๋”ํ•˜๊ณ  9๋ฅผ ๊ณฑํ•œ ๊ฐ’์€ ์–ผ๋งˆ์ž…๋‹ˆ๊นŒ?
Correspondence
var_a = 2 var_b = 5 var_c = var_a + var_b print(int(var_c))
7
7
2 5 [OP_ADD]
var_a = 2 var_b = 5 var_c = var_a + var_b print(int(var_c))
2 5 [OP_ADD]
Yoojung bought 2 motorcycles and 5 bicycles. How many motorcycles and bicycles did Yoojung buy?
์œ ์ •์ด๋Š” ์˜คํ† ๋ฐ”์ด 2๋Œ€์™€ ์ž์ „๊ฑฐ 5๋Œ€๋ฅผ ๊ตฌ๋งคํ•˜์˜€์Šต๋‹ˆ๋‹ค. ์œ ์ •์ด๊ฐ€ ๊ตฌ๋งคํ•œ ์˜คํ† ๋ฐ”์ด์™€ ์ž์ „๊ฑฐ๋Š” ๋ช‡ ๋Œ€ ์ธ๊ฐ€์š”?
Arithmetic calculation
var_a = 155.2 var_b = 53 var_c = var_a / var_b var_d = 17 var_e = var_c * var_d var_f = 2 var_g = var_e / var_f var_h = 1 var_i=int(((var_g+9*10**(var_h-2))//(10**(var_h-1)))*10**(var_h-1)) print(int(var_i))
25
25
155.2 53 [OP_DIV] 17 [OP_MUL] 2 [OP_DIV] 1 [OP_CEIL]
var_a = 155.2 var_b = 53 var_c = var_a / var_b var_d = 17 var_e = var_c * var_d var_f = 2 var_g = var_e / var_f var_h = 1 var_i=int(((var_g+9*10**(var_h-2))//(10**(var_h-1)))*10**(var_h-1)) print(int(var_i))
155.2 53 [OP_DIV] 17 [OP_MUL] 2 [OP_DIV] 1 [OP_CEIL]
It is said that one person needs 155.2 liters (l) of water to live for 53 days, and the amount of water in one bucket is 2 liters (l). If a person lives 17 days, how many buckets of water does a person need?
ํ•œ ์‚ฌ๋žŒ์ด 53์ผ์„ ์‚ฌ๋Š” ๋ฐ 155.2๋ฆฌํ„ฐ(L)์˜ ๋ฌผ์ด ํ•„์š”ํ•˜๋‹ค๊ณ  ํ•˜๊ณ , ํ•œ ๋ฌผํ†ต์— ๋“ค์–ด์žˆ๋Š” ๋ฌผ์˜ ์–‘์€ 2๋ฆฌํ„ฐ(L)์ž…๋‹ˆ๋‹ค. ๋งŒ์•ฝ ์‚ฌ๋žŒ์ด 17์ผ์„ ์‚ฐ๋‹ค๊ณ  ํ•œ๋‹ค๋ฉด ์‚ฌ๋žŒ์—๊ฒŒ ํ•„์š”ํ•œ ๋ฌผํ†ต์€ ๋ชจ๋‘ ๋ช‡ ๊ฐœ์ž…๋‹ˆ๊นŒ?
Arithmetic calculation
var_a = 2 print(int(var_a))
2
2
2
var_a = 2 print(int(var_a))
2
Jungkook has 3 red balls and 2 yellow balls. When Jungkook gives Yoongi 1 red ball, how many yellow balls does Jungkook have?
์ •๊ตญ์ด๋Š” ๋นจ๊ฐ„ ๊ณต 3๊ฐœ์™€ ๋…ธ๋ž€ ๊ณต 2๊ฐœ๋ฅผ ๊ฐ€์ง€๊ณ  ์žˆ์Šต๋‹ˆ๋‹ค. ์ •๊ตญ์ด๊ฐ€ ์œค๊ธฐ์—๊ฒŒ ๋นจ๊ฐ„ ๊ณต 1๊ฐœ๋ฅผ ์ฃผ์—ˆ์„ ๋•Œ, ์ •๊ตญ์ด๊ฐ€ ๊ฐ€์ง€๊ณ  ์žˆ๋Š” ๋…ธ๋ž€ ๊ณต์˜ ๊ฐœ์ˆ˜๋Š”?
Arithmetic calculation
var_a = 4 var_b = 3 var_c = var_a + var_b print(int(var_c))
7
7
4 3 [OP_ADD]
var_a = 4 var_b = 3 var_c = var_a + var_b print(int(var_c))
4 3 [OP_ADD]
Dongwi is going to go to another school to see the festival. If only one school is allowed to go to play, and there are 4 boys' high schools and 3 girls' high schools, find the number of cases in which Dongwi go to play.
๋™์œ„๋Š” ์ถ•์ œ๋ฅผ ๋ณด๊ธฐ ์œ„ํ•ด ๋‹ค๋ฅธ ํ•™๊ต์— ๋†€๋Ÿฌ๊ฐ€๋ ค๊ณ  ํ•ฉ๋‹ˆ๋‹ค. ํ•˜๋‚˜์˜ ํ•™๊ต์—๋งŒ ๋†€๋Ÿฌ๊ฐˆ ์ˆ˜ ์žˆ๊ณ , ๋‚จ๊ณ ๊ฐ€ 4๊ฐœ, ์—ฌ๊ณ ๊ฐ€ 3๊ฐœ ์žˆ์„ ๋•Œ ๋™์œ„๊ฐ€ ๋†€๋Ÿฌ๊ฐ€๋Š” ๊ฒฝ์šฐ์˜ ์ˆ˜๋ฅผ ๊ตฌํ•˜์‹œ์˜ค.
Possibility
var_a = 100 var_b = 5 var_c = var_a / var_b var_d = 10 var_e = var_c / var_d print(int(var_e))
2
2
100 5 [OP_DIV] 10 [OP_DIV]
var_a = 100 var_b = 5 var_c = var_a / var_b var_d = 10 var_e = var_c / var_d print(int(var_e))
100 5 [OP_DIV] 10 [OP_DIV]
Multiply a number by 5 to get 100. What is the value of the number when divided by 10?
์–ด๋–ค ์ˆ˜์— 5๋ฅผ ๊ณฑํ•ด ๊ฒฐ๊ณผ๋กœ 100์„ ์–ป์—ˆ์Šต๋‹ˆ๋‹ค. 10์œผ๋กœ ์–ด๋–ค ์ˆ˜๋ฅผ ๋‚˜๋ˆ„๋ฉด ์–ผ๋งˆ์ž…๋‹ˆ๊นŒ?
Correspondence
var_a = 1 var_b = 0 var_c = 5 var_d = 8 list_a= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) li...
4
4
[OP_LIST_SOL] 1 0 5 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_SUB]
var_a = 1 var_b = 0 var_c = 5 var_d = 8 list_a= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) li...
[OP_LIST_SOL] 1 0 5 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_SUB]
Of the two digits that can be created by taking two different numbers out of 1, 0, 5, and 8, what is the largest minus the second largest?
1, 0, 5, 8 ์ค‘์—์„œ ์„œ๋กœ ๋‹ค๋ฅธ ์ˆซ์ž 2๊ฐœ๋ฅผ ๋ฝ‘์•„ ๋งŒ๋“ค ์ˆ˜ ์žˆ๋Š” ๋‘ ์ž๋ฆฌ ์ˆ˜ ์ค‘ ๊ฐ€์žฅ ํฐ ์ˆ˜์—์„œ 2๋ฒˆ์งธ๋กœ ํฐ ์ˆ˜๋ฅผ ๋บ€ ๊ฐ’์€ ์–ผ๋งˆ์ž…๋‹ˆ๊นŒ?
Possibility
var_a = 21.12 var_b = 6 var_c = var_a / var_b print('{:.2f}'.format(round(var_c+1e-10,2)))
3.52
3.52
21.12 6 [OP_DIV]
var_a = 21.12 var_b = 6 var_c = var_a / var_b print('{:.2f}'.format(round(var_c+1e-10,2)))
21.12 6 [OP_DIV]
A regular hexagon with an area of 21.12 square centimeters (cm2) is divided into 6 equal parts. What is the area of the divided part?
๋„“์ด๊ฐ€ 21.12์ œ๊ณฑ์„ผํ‹ฐ๋ฏธํ„ฐ(ใŽ )์ธ ์ •์œก๊ฐํ˜•์„ 6๋“ฑ๋ถ„ํ•˜์˜€์Šต๋‹ˆ๋‹ค. ํ•œ ๋“ฑ๋ถ„์˜ ๋„“์ด๋Š” ์–ผ๋งˆ์ž…๋‹ˆ๊นŒ?
Geometry
var_a = 6 var_b = 6 var_c = var_a * var_b var_d = 7 var_e = 3 var_f = var_d * var_e var_g = var_c - var_f print(int(var_g))
15
15
6 6 [OP_MUL] 7 3 [OP_MUL] [OP_SUB]
var_a = 6 var_b = 6 var_c = var_a * var_b var_d = 7 var_e = 3 var_f = var_d * var_e var_g = var_c - var_f print(int(var_g))
6 6 [OP_MUL] 7 3 [OP_MUL] [OP_SUB]
Namjoon has 3 sets of 7 marbles. He is going to make these marbles into 6 groups of 6 each. How many more marbles does he need?
๋‚จ์ค€์ด๋Š” ๊ตฌ์Šฌ์„ 7๊ฐœ์”ฉ 3๋ฌถ์Œ ๊ฐ€์ง€๊ณ  ์žˆ์Šต๋‹ˆ๋‹ค. ์ด ๊ตฌ์Šฌ์„ 6๊ฐœ์”ฉ 6๋ฌถ์Œ์œผ๋กœ ๋งŒ๋“ค๋ ค๊ณ  ํ•ฉ๋‹ˆ๋‹ค. ๋ช‡ ๊ฐœ์˜ ๊ตฌ์Šฌ์ด ๋” ํ•„์š”ํ•ฉ๋‹ˆ๊นŒ?
Arithmetic calculation
var_a = 49 var_b = 7 var_c = var_a / var_b print(int(var_c))
7
7
49 7 [OP_DIV]
var_a = 49 var_b = 7 var_c = var_a / var_b print(int(var_c))
49 7 [OP_DIV]
A figure has a perimeter of 49 centimeters (cm) and a side length of 7 centimeters (cm). How many sides are there in total?
๋„ํ˜•์˜ ๋‘˜๋ ˆ๊ฐ€ 49์„ผํ‹ฐ๋ฏธํ„ฐ(ใŽ)์ด๋ฉฐ ํ•œ ๋ณ€์˜ ๊ธธ์ด๊ฐ€ 7์„ผํ‹ฐ๋ฏธํ„ฐ(ใŽ)์ธ ๋„ํ˜•์ด ์žˆ์Šต๋‹ˆ๋‹ค. ์ด ๋ช‡ ๊ฐœ์˜ ๋ณ€์ด ์žˆ์Šต๋‹ˆ๊นŒ?
Geometry
var_a = 'DCBA+ABCD=ABCD0' var_b = 'A' ans_dict = dict() var_a = var_a.replace('ร—','*') var_a = var_a.replace('x','*') var_a = var_a.replace('รท','/') variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']) for v in set(var_a...
18
18
DCBA+ABCD=ABCD0 A [OP_DIGIT_UNK_SOLVER] DCBA+ABCD=ABCD0 B [OP_DIGIT_UNK_SOLVER] DCBA+ABCD=ABCD0 C [OP_DIGIT_UNK_SOLVER] DCBA+ABCD=ABCD0 D [OP_DIGIT_UNK_SOLVER] [OP_ADD] [OP_ADD] [OP_ADD]
var_a = 'DCBA+ABCD=ABCD0' var_b = 'A' ans_dict = dict() var_a = var_a.replace('ร—','*') var_a = var_a.replace('x','*') var_a = var_a.replace('รท','/') variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']) for v in set(var_a...
DCBA+ABCD=ABCD0 A [OP_DIGIT_UNK_SOLVER] DCBA+ABCD=ABCD0 B [OP_DIGIT_UNK_SOLVER] DCBA+ABCD=ABCD0 C [OP_DIGIT_UNK_SOLVER] DCBA+ABCD=ABCD0 D [OP_DIGIT_UNK_SOLVER] [OP_ADD] [OP_ADD] [OP_ADD]
There are different numbers A, B, C, and D. Find the sum of A, B, C, and D in the four-digit addition formula DCBA+ABCD=ABCD0.
์„œ๋กœ ๋‹ค๋ฅธ ์ˆซ์ž A, B, C, D๊ฐ€ ์žˆ์Šต๋‹ˆ๋‹ค. ๋„ค ์ž๋ฆฌ ์ˆ˜๋ผ๋ฆฌ์˜ ๋ง์…ˆ์‹ DCBA+ABCD=ABCD0์—์„œ A, B, C, D์˜ ํ•ฉ์„ ๊ตฌํ•˜์‹œ์˜ค.
Correspondence
var_a = 20 var_b = 1 var_c = 2 var_d = var_b * var_c var_e = var_a - var_d var_f = 7 var_g = 1 var_h = var_f - var_g var_i = var_e / var_h print(int(var_i))
3
3
20 1 2 [OP_MUL] [OP_SUB] 7 1 [OP_SUB] [OP_DIV]
var_a = 20 var_b = 1 var_c = 2 var_d = var_b * var_c var_e = var_a - var_d var_f = 7 var_g = 1 var_h = var_f - var_g var_i = var_e / var_h print(int(var_i))
20 1 2 [OP_MUL] [OP_SUB] 7 1 [OP_SUB] [OP_DIV]
I am trying to put 7 posters on a wall that is 20 meters (m) wide. The posters were pasted at equal intervals, starting at 1 meter (m) apart from each end of the wall. Find the space between the posters.
๊ฐ€๋กœ๊ฐ€ 20๋ฏธํ„ฐ(m)์ธ ๋ฒฝ์— 7๊ฐœ์˜ ํฌ์Šคํ„ฐ๋ฅผ ๋ถ™ํžˆ๋ ค๊ณ  ํ•œ๋‹ค. ๋ฒฝ์˜ ์–‘์ชฝ ๋์—์„œ 1๋ฏธํ„ฐ(m)์”ฉ ๋–จ์–ด๋œจ๋ ค์„œ ๋ถ™์ด๊ธฐ ์‹œ์ž‘ํ•˜์—ฌ ๊ฐ™์€ ๊ฐ„๊ฒฉ์œผ๋กœ ํฌ์Šคํ„ฐ๋ฅผ ๋ถ™ํ˜”๋‹ค. ํฌ์Šคํ„ฐ ์‚ฌ์ด์˜ ๊ฐ„๊ฒฉ์„ ๊ตฌํ•˜์‹œ์˜ค
Arithmetic calculation
var_a = 0.1 var_b = 8 var_c = 0.9 var_d = 0.7 var_e = 5 list_a= [] if "/" in str(var_e): var_e = eval(str(var_e)) list_a.append(var_e) if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eva...
3
3
[OP_LIST_SOL] 1/10 8 0.9 7/10 5 [OP_LIST_EOL] 1 [OP_LIST_LESS] [OP_LIST_LEN]
var_a = 0.1 var_b = 8 var_c = 0.9 var_d = 0.7 var_e = 5 list_a= [] if "/" in str(var_e): var_e = eval(str(var_e)) list_a.append(var_e) if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eva...
[OP_LIST_SOL] 1/10 8 0.9 7/10 5 [OP_LIST_EOL] 1 [OP_LIST_LESS] [OP_LIST_LEN]
How many of the following numbers are less than 1? 1/10, 8, 0.9, 7/10, 5.
๋‹ค์Œ ์ค‘ 1๋ณด๋‹ค ์ž‘์€ ์ˆ˜๋Š” ๋ช‡ ๊ฐœ์ธ์ง€ ๊ณ ๋ฅด์‹œ์˜ค. 1/10, 8, 0.9, 7/10, 5.
Comparison
var_a = 156 var_b = 8 var_c = var_a * var_b var_d = 2 var_e = var_c + var_d var_f = 5 var_g = var_e / var_f print(int(var_g))
250
250
156 8 [OP_MUL] 2 [OP_ADD] 5 [OP_DIV]
var_a = 156 var_b = 8 var_c = var_a * var_b var_d = 2 var_e = var_c + var_d var_f = 5 var_g = var_e / var_f print(int(var_g))
156 8 [OP_MUL] 2 [OP_ADD] 5 [OP_DIV]
A number needs to be divided by 5, but when it was accidentally divided by 8, the quotient was 156 and the remainder 2. Find the value that comes out when the calculation is done correctly.
์–ด๋–ค ์ˆ˜๋ฅผ 5๋กœ ๋‚˜๋ˆ„์–ด์•ผ ํ•˜๋Š”๋ฐ ์‹ค์ˆ˜๋กœ 8๋กœ ๋‚˜๋ˆ„์—ˆ๋”๋‹ˆ ๋ชซ์ด 156์ด๊ณ  ๋‚˜๋จธ์ง€๊ฐ€ 2์˜€์Šต๋‹ˆ๋‹ค. ๊ณ„์‚ฐ์„ ์ œ๋Œ€๋กœ ํ–ˆ์„ ๋•Œ ๋‚˜์˜ค๋Š” ๊ฐ’์„ ๊ตฌํ•˜์‹œ์˜ค.
Correspondence
var_a = 502 var_b = 18 var_c = 57 var_d = var_b + var_c var_e = 44 var_f = var_d - var_e var_g = var_a - var_f var_h = 17 var_i = var_g - var_h var_j = 2 var_k = var_i / var_j print(int(var_k))
227
227
502 18 57 [OP_ADD] 44 [OP_SUB] [OP_SUB] 17 [OP_SUB] 2 [OP_DIV]
var_a = 502 var_b = 18 var_c = 57 var_d = var_b + var_c var_e = 44 var_f = var_d - var_e var_g = var_a - var_f var_h = 17 var_i = var_g - var_h var_j = 2 var_k = var_i / var_j print(int(var_k))
502 18 57 [OP_ADD] 44 [OP_SUB] [OP_SUB] 17 [OP_SUB] 2 [OP_DIV]
At the first stop, there were 17 men fewer than women that took the subway. At the next station, 57 women and 18 men got on and 44 people got off. If there are 502 people on the subway right now, how many men got on the subway at the first stop?
์ฒซ ๋ฒˆ์งธ ์ •๋ฅ˜์žฅ์—์„œ ์ง€ํ•˜์ฒ ์„ ํƒ„ ๋‚จ์ž๋Š” ์—ฌ์ž๋ณด๋‹ค 17๋ช…์ด ์ ์—ˆ์Šต๋‹ˆ๋‹ค. ๋‹ค์Œ ์—ญ์—์„œ ์—ฌ์ž 57๋ช…๊ณผ ๋‚จ์ž 18๋ช…์ด ํƒ€๊ณ  44๋ช…์ด ๋‚ด๋ ธ์Šต๋‹ˆ๋‹ค. ์ง€๊ธˆ ์ง€ํ•˜์ฒ ์„ ํƒ€๊ณ  ์žˆ๋Š” ์‚ฌ๋žŒ์ด 502๋ช…์ด๋ผ๋ฉด ์ฒซ ๋ฒˆ์งธ ์ •๋ฅ˜์žฅ์—์„œ ์ง€ํ•˜์ฒ  ํƒ„ ๋‚จ์ž๋Š” ๋ช‡ ๋ช…์ธ์ง€ ๊ตฌํ•˜์‹œ์˜ค
Comparison
var_a = 60 var_b = 6 var_c = var_a * var_b var_d = 12 var_e = var_c + var_d var_f = 3 var_g = var_e / var_f var_h = 3 var_i = var_g / var_h var_j = 12 var_k = var_i + var_j print('{:.2f}'.format(round(var_k+1e-10,2)))
53.33
53.33
60 6 [OP_MUL] 12 [OP_ADD] 3 [OP_DIV] 3 [OP_DIV] 12 [OP_ADD]
var_a = 60 var_b = 6 var_c = var_a * var_b var_d = 12 var_e = var_c + var_d var_f = 3 var_g = var_e / var_f var_h = 3 var_i = var_g / var_h var_j = 12 var_k = var_i + var_j print('{:.2f}'.format(round(var_k+1e-10,2)))
60 6 [OP_MUL] 12 [OP_ADD] 3 [OP_DIV] 3 [OP_DIV] 12 [OP_ADD]
I was supposed to divide a certain number by 3 and add 12 to it, but I multiplied this number by 3, subtracted 12 and then divided it by 6 accidentally, getting 60 as a result. How much will I get if I calculate correctly?
์–ด๋–ค ์ˆ˜๋ฅผ 3 ์œผ๋กœ ๋‚˜๋ˆˆ ๋‹ค์Œ 12 ๋ฅผ ๋”ํ•ด์•ผ ํ•  ๊ฒƒ์„ ์ž˜๋ชปํ•˜์—ฌ 3 ์„ ๊ณฑํ•œ ๋‹ค์Œ 12 ๋ฅผ ๋นผ๊ณ ๋‚˜์„œ 6์œผ๋กœ ๋‚˜๋ˆด๋”๋‹ˆ 60 ์ด ๋˜์—ˆ์Šต๋‹ˆ๋‹ค. ๋ฐ”๋ฅด๊ฒŒ ๊ณ„์‚ฐํ•˜๋ฉด ์–ผ๋งˆ์ž…๋‹ˆ๊นŒ?
Correspondence
var_a = 8 var_b = 1 var_c = 6 list_a= [] if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_d = 3 list_b = [str(i) for i in list_a] li...
1542
1542
[OP_LIST_SOL] 8 1 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_ADD]
var_a = 8 var_b = 1 var_c = 6 list_a= [] if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_d = 3 list_b = [str(i) for i in list_a] li...
[OP_LIST_SOL] 8 1 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_ADD]
Find the sum of the largest and third largest three-digit numbers with different digits that can be made with the natural numbers 8, 1, and 6.
์ž์—ฐ์ˆ˜ 8, 1, 6์œผ๋กœ ๋งŒ๋“ค ์ˆ˜ ์žˆ๋Š”, ๊ฐ ์ž๋ฆฟ์ˆ˜๊ฐ€ ๋ชจ๋‘ ๋‹ค๋ฅธ ์„ธ ์ž๋ฆฌ ์ˆ˜ ์ค‘ ๊ฐ€์žฅ ํฐ ๊ฒƒ๊ณผ ์„ธ ๋ฒˆ์งธ๋กœ ํฐ ๊ฒƒ์˜ ํ•ฉ์„ ๊ตฌํ•˜์‹œ์˜ค.
Possibility
var_a = 9.28 var_b = 2.95 var_c = var_a - var_b var_d = 2.95 var_e = var_c - var_d print('{:.2f}'.format(round(var_e+1e-10,2)))
3.38
3.38
9.28 2.95 [OP_SUB] 2.95 [OP_SUB]
var_a = 9.28 var_b = 2.95 var_c = var_a - var_b var_d = 2.95 var_e = var_c - var_d print('{:.2f}'.format(round(var_e+1e-10,2)))
9.28 2.95 [OP_SUB] 2.95 [OP_SUB]
Each of the two beakers contains a liquid. The sum of the solutions contained in the two beakers is 9.28 milliliters (ml). If one beaker contains 2.95 milliliters (ml), what is the difference in milliliters (ml) between the two beakers?
๋‘ ๊ฐœ์˜ ๋น„์ปค ์•ˆ์— ๊ฐ๊ฐ ์•ก์ฒด๊ฐ€ ๋‹ด๊ฒจ์žˆ๋‹ค. ๋‘ ๋น„์ปค์•ˆ์— ๋‹ด๊ฒจ์žˆ๋Š” ์šฉ์•ก์˜ ํ•ฉ์ด 9.28๋ฐ€๋ฆฌ๋ฆฌํ„ฐ(ใŽ–)์ด๋‹ค. ํ•œ ๋น„์ปค์— 2.95๋ฐ€๋ฆฌ๋ฆฌํ„ฐ(ใŽ–)๊ฐ€ ๋“ค์–ด์žˆ์„ ๋•Œ, ๋‘ ๋น„์ปค์— ๋“ค์–ด์žˆ๋Š” ์šฉ์•ก์˜ ์ฐจ๋Š” ๋ช‡ ๋ฐ€๋ฆฌ๋ฆฌํ„ฐ(ใŽ–)์ธ์ง€ ๊ตฌํ•˜์‹œ์˜ค.
Correspondence
var_a = 'A' var_b = 'B' var_c = 'C' var_d = 'D' var_e = 'E' var_f = 'F' list_a= [] if "/" in str(var_f): var_f = eval(str(var_f)) list_a.append(var_f) if "/" in str(var_e): var_e = eval(str(var_e)) list_a.append(var_e) if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c):...
144
144
[OP_LIST_SOL] A B C D E F [OP_LIST_EOL] [OP_LIST_SOL] B C [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]
var_a = 'A' var_b = 'B' var_c = 'C' var_d = 'D' var_e = 'E' var_f = 'F' list_a= [] if "/" in str(var_f): var_f = eval(str(var_f)) list_a.append(var_f) if "/" in str(var_e): var_e = eval(str(var_e)) list_a.append(var_e) if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c):...
[OP_LIST_SOL] A B C D E F [OP_LIST_EOL] [OP_LIST_SOL] B C [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]
When 6 people A, B, C, D, E, and F are lined up in a line, find the number of ways in which A, B, and C can be placed next to each other.
A, B, C, D, E, F 6๋ช…์„ ํ•œ ์ค„๋กœ ์„ธ์šธ ๋•Œ, A, B, C๋ฅผ ์„œ๋กœ ์ด์›ƒํ•˜๊ฒŒ ํ•˜์—ฌ ์„ธ์šฐ๋Š” ๊ฒฝ์šฐ์˜ ์ˆ˜๋ฅผ ๊ตฌํ•˜์‹œ์˜ค.
Possibility
var_a = 40 var_b = 42 var_c = var_a + var_b var_d = 45 var_e = var_c - var_d print(int(var_e))
37
37
40 42 [OP_ADD] 45 [OP_SUB]
var_a = 40 var_b = 42 var_c = var_a + var_b var_d = 45 var_e = var_c - var_d print(int(var_e))
40 42 [OP_ADD] 45 [OP_SUB]
Among the 45 students, 42 students raised their hands to say they like art, and 40 students raised their hands to say they like science. If all students participated in the survey, how many students raised their hands in both subjects?
45๋ช…์˜ ํ•™์ƒ ์ค‘ ๋ฏธ์ˆ ์„ ์ข‹์•„ํ•œ๋‹ค๊ณ  ๊ฑฐ์ˆ˜ํ•œ ํ•™์ƒ์ด 42๋ช…์ด๊ณ  ๊ณผํ•™์„ ์ข‹์•„ํ•œ๋‹ค๊ณ  ๊ฑฐ์ˆ˜ํ•œ ํ•™์ƒ์€ 40๋ช…์ž…๋‹ˆ๋‹ค. ๋ชจ๋“  ํ•™์ƒ์ด ์กฐ์‚ฌ์— ์ฐธ์—ฌํ•˜์˜€์„ ๋•Œ, ๋‘ ๊ณผ๋ชฉ ๋ชจ๋‘ ์†์„ ๋“  ํ•™์ƒ์€ ๋ช‡ ๋ช…์ธ๊ฐ€์š”?
Arithmetic calculation
var_a = 0 var_b = 1 var_c = 2 var_d = 3 var_e = 4 var_f = 5 list_a= [] if "/" in str(var_f): var_f = eval(str(var_f)) list_a.append(var_f) if "/" in str(var_e): var_e = eval(str(var_e)) list_a.append(var_e) if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c =...
100
100
[OP_LIST_SOL] 0 1 2 3 4 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]
var_a = 0 var_b = 1 var_c = 2 var_d = 3 var_e = 4 var_f = 5 list_a= [] if "/" in str(var_f): var_f = eval(str(var_f)) list_a.append(var_f) if "/" in str(var_e): var_e = eval(str(var_e)) list_a.append(var_e) if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c =...
[OP_LIST_SOL] 0 1 2 3 4 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]
How many three-digit integers can be created by pressing 3 of the 6 buttons on a calculator with the numbers 0, 1, 2, 3, 4, and 5 on them?
๊ณ„์‚ฐ๊ธฐ์—์„œ 0, 1, 2, 3, 4, 5์˜ ์ˆซ์ž๊ฐ€ ๊ฐ๊ฐ ์ ํžŒ 6๊ฐœ์˜ ๋ฒ„ํŠผ ์ค‘ 3๊ฐœ๋ฅผ ๋ˆŒ๋Ÿฌ์„œ ๋งŒ๋“ค ์ˆ˜ ์žˆ๋Š” ์„ธ ์ž๋ฆฌ ์ •์ˆ˜์˜ ๊ฐœ์ˆ˜๋Š”?
Possibility
var_a = 25 var_b = 25 var_c = 6 var_d = var_b - var_c var_e = 30 var_f = 1 var_g = var_e - var_f var_h = var_d * var_g var_i = var_a + var_h print(int(var_i))
576
576
25 25 6 [OP_SUB] 30 1 [OP_SUB] [OP_MUL] [OP_ADD]
var_a = 25 var_b = 25 var_c = 6 var_d = var_b - var_c var_e = 30 var_f = 1 var_g = var_e - var_f var_h = var_d * var_g var_i = var_a + var_h print(int(var_i))
25 25 6 [OP_SUB] 30 1 [OP_SUB] [OP_MUL] [OP_ADD]
What is the total length in centimeters (cm) of 30 wooden sticks 25 centimeters (cm) long when 6 centimeters (cm) are overlapped?
25์„ผํ‹ฐ๋ฏธํ„ฐ(ใŽ) ๊ธธ์ด์˜ ๋‚˜๋ฌด๋ง‰๋Œ€ 30์žฅ์„ 6์„ผํ‹ฐ๋ฏธํ„ฐ(ใŽ)๊ฒน์ณ ์ด์–ด๋ถ™์˜€์„ ์‹œ ์ „์ฒด ๊ธธ์ด๋Š” ๋ช‡ ์„ผํ‹ฐ๋ฏธํ„ฐ(ใŽ)์ž…๋‹ˆ๊นŒ?
Arithmetic calculation
var_a = 0 var_b = 8 var_c = 7 list_a= [] if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_d = len(list_a) list_b = [str(i) for i in ...
870
870
[OP_LIST_SOL] 0 8 7 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]
var_a = 0 var_b = 8 var_c = 7 list_a= [] if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_d = len(list_a) list_b = [str(i) for i in ...
[OP_LIST_SOL] 0 8 7 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]
Write the largest number that can be made by using all of the figures 0, 8, and 7 once.
์ฃผ์–ด์ง„ ์ˆซ์ž์นด๋“œ 0, 8, 7๋ฅผ ํ•œ ๋ฒˆ์”ฉ ๋ชจ๋‘ ์‚ฌ์šฉํ•˜์—ฌ ๋งŒ๋“ค ์ˆ˜ ์žˆ๋Š” ๊ฐ€์žฅ ํฐ ์ˆ˜๋ฅผ ์“ฐ์‹œ์˜ค.
Possibility
var_a = 33 var_b = 3 var_c = var_a / var_b print(int(var_c))
11
11
33 3 [OP_DIV]
var_a = 33 var_b = 3 var_c = var_a / var_b print(int(var_c))
33 3 [OP_DIV]
When you multiply a number by 3, you get 33. What number is that?
์–ด๋–ค ์ˆ˜์— 3์„ ๊ณฑํ–ˆ๋”๋‹ˆ 33์ด ๋˜์—ˆ์Šต๋‹ˆ๋‹ค. ์–ด๋–ค ์ˆ˜๋Š” ์–ผ๋งˆ์ผ๊นŒ์š”?
Correspondence
var_a = 5 var_b = 6 var_c = 7 list_a= [] if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_d = 3 list_b = [str(i) for i in list_a] li...
4
4
[OP_LIST_SOL] 5 6 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] [OP_LIST_LEN]
var_a = 5 var_b = 6 var_c = 7 list_a= [] if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_d = 3 list_b = [str(i) for i in list_a] li...
[OP_LIST_SOL] 5 6 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] [OP_LIST_LEN]
Find the number of odd numbers in a three-digit number that can be formed by using 5, 6, or 7 only once.
5, 6, 7 ์ค‘์—์„œ ํ•œ ๋ฒˆ์”ฉ๋งŒ ์‚ฌ์šฉํ•˜์—ฌ ๋งŒ๋“ค ์ˆ˜ ์žˆ๋Š” ์„ธ ์ž๋ฆฌ ์ˆ˜์ค‘์—์„œ ํ™€์ˆ˜์˜ ๊ฐœ์ˆ˜๋ฅผ ๊ตฌํ•˜์‹œ์˜ค.
Possibility
var_a = 73 var_b = 28 var_c = var_a - var_b var_d = 3 var_e = var_c / var_d var_f = 4 var_g = var_e * var_f var_h = 50 var_i = var_g + var_h print(int(var_i))
110
110
73 28 [OP_SUB] 3 [OP_DIV] 4 [OP_MUL] 50 [OP_ADD]
var_a = 73 var_b = 28 var_c = var_a - var_b var_d = 3 var_e = var_c / var_d var_f = 4 var_g = var_e * var_f var_h = 50 var_i = var_g + var_h print(int(var_i))
73 28 [OP_SUB] 3 [OP_DIV] 4 [OP_MUL] 50 [OP_ADD]
When you subtract 50 from a number, divide it by 4, multiply it by 3, and add 28, it becomes 73. Find out what number this is.
์–ด๋–ค ์ˆ˜์—์„œ 50์„ ๋บ€ ํ›„ 4๋กœ ๋‚˜๋ˆ„๊ณ , 3์„ ๊ณฑํ•œ ๊ฐ’์— 28์„ ๋”ํ•œ ๊ฐ’์ด 73์ž…๋‹ˆ๋‹ค. ์–ด๋–ค ์ˆ˜๋ฅผ ๊ตฌํ•˜์‹œ์˜ค.
Correspondence
var_a = 145 var_b = 139 var_c = 155 var_d = 160 var_e = 143 list_a= [] if "/" in str(var_e): var_e = eval(str(var_e)) list_a.append(var_e) if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b =...
155.60
155.6
[OP_LIST_SOL] 145 139 155 160 143 [OP_LIST_EOL] [OP_LIST_MEAN] [OP_LIST_LEN] 1 [OP_ADD] 1.2 [OP_MUL] [OP_ADD]
var_a = 145 var_b = 139 var_c = 155 var_d = 160 var_e = 143 list_a= [] if "/" in str(var_e): var_e = eval(str(var_e)) list_a.append(var_e) if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b =...
[OP_LIST_SOL] 145 139 155 160 143 [OP_LIST_EOL] [OP_LIST_MEAN] [OP_LIST_LEN] 1 [OP_ADD] 1.2 [OP_MUL] [OP_ADD]
Taehyung's group has five students with a height of 145 centimeters (cm), 139 centimeters (cm), 155 centimeters (cm), 160 centimeters (cm), and 143 centimeters (cm). When one more student joined the group, the average height increased by 1.2 centimeters (cm). Find the height of the new student in centimeters (cm) inclu...
ํƒœํ˜•์ด๋„ค ๋ชจ๋‘  ํ•™์ƒ 5๋ช…์˜ ํ‚ค๋Š” 145์„ผํ‹ฐ๋ฏธํ„ฐ(ใŽ), 139์„ผํ‹ฐ๋ฏธํ„ฐ(ใŽ), 155์„ผํ‹ฐ๋ฏธํ„ฐ(ใŽ), 160์„ผํ‹ฐ๋ฏธํ„ฐ(ใŽ), 143์„ผํ‹ฐ๋ฏธํ„ฐ(ใŽ)์ž…๋‹ˆ๋‹ค. ๋ชจ๋‘ ์— 1๋ช…์ด ๋” ๋Š˜์–ด์„œ ํ‚ค์˜ ํ‰๊ท ์ด 1.2์„ผํ‹ฐ๋ฏธํ„ฐ(ใŽ) ๋Š˜์–ด๋‚ฌ์Šต๋‹ˆ๋‹ค. ์ƒˆ๋กœ ์˜จ ํ•™์ƒ์˜ ํ‚ค๋Š” ๋ช‡ ์„ผํ‹ฐ๋ฏธํ„ฐ(ใŽ)์ธ์ง€ ์†Œ์ˆ˜์ ์„ ํฌํ•จํ•˜์—ฌ ๋‹ต์„ ๊ตฌํ•˜์‹œ์˜ค.
Arithmetic calculation