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id int64 1 44.4k | title stringlengths 3 986 | slug stringlengths 9 159 | question stringlengths 34 62.2k | tags stringlengths 23 126 | options stringlengths 4 149k | correct_option stringlengths 4 50.2k | answer stringlengths 29 69.3k | source_db stringclasses 14
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1 | 2.5 mL of 5 2 â M weak monoacidic base ( K b â = 1 Ã 1 0 â 12 at 2 5 â C ) is titrated with 15 2 â M HCl in water at 2 5 â C . The concentration of H + at equivalence point is ( K w â = 1 Ã 1 0 â 14 at 2 5 â C ) | 2-5-ml-of-5-2-m-weak-monoacidic-base-k-b-1-1-0-12-at-2-5-c-is-titrated-with-59646 | <div class="question">$2.5 \mathrm{~mL}$ of $\frac{2}{5} \mathrm{M}$ weak monoacidic base $\left(K_b=1 \times 10^{-12}\right.$ at $\left.25^{\circ} \mathrm{C}\right)$ is titrated with $\frac{2}{15}$ $\mathrm{M} \mathrm{HCl}$ in water at $25^{\circ} \mathrm{C}$. The concentration of $\mathrm{H}^{+}$at equivalence point ... | ['Chemistry', 'Ionic Equilibrium', 'JEE Advanced', 'JEE Advanced 2008 (Paper 1)'] | <ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data"><br/>$3.7 \times 10^{-13} \mathrm{M}$<br/></span> </li><li class=""> <span class="option-label">B</span> <span class="option-data"><br/>$3.2 \times 10^{-7} \mathrm{M}$<br/></span> </li><li class=""> <span class="option-labe... | <div class="correct-answer">
The correct answer is:
<span class="option-value"><br/>$2.7 \times 10^{-2} \mathrm{M}$</span> </div> | <div class="solution">Weak monoacidic base, e.g. $\mathrm{BOH}$ is neutralised.<br/>$$<br/>\mathrm{BOH}+\mathrm{HCl} \longrightarrow \mathrm{BCl}+\mathrm{H}_2 \mathrm{O}<br/>$$<br/>At equivalence point all $\mathrm{BOH}$ gets converted into salt and remember! the concentration of $\mathrm{H}^{+}$(or $\mathrm{pH}$ of so... | MarksBatch0.db |
2 | 5.6 L of helium gas at STP is adiabatically compressed to 0.7 L . Taking the initial temperature to be T 1 â , the work done in the process is | 5-6-l-of-helium-gas-at-stp-is-adiabatically-compressed-to-0-7-l-taking-the-initial-temperature-to-45466 | <div class="question">$5.6 \mathrm{~L}$ of helium gas at STP is adiabatically compressed to $0.7 \mathrm{~L}$. Taking the initial temperature to be $T_1$, the work done in the process is</div> | ['Physics', 'Thermodynamics', 'JEE Advanced', 'JEE Advanced 2011 (Paper 1)'] | <ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data"><br/>$\frac{9}{8} R T_1$<br/></span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73... | <div class="correct-answer">
The correct answer is:
<span class="option-value"><br/>$\frac{9}{8} R T_1$<br/></span> </div> | <div class="solution">At STP, 22.4 L of any gas is 1 mole.<br/>$$<br/>\therefore \quad 5.6 \mathrm{~L}=\frac{5.6}{22.4}=\frac{1}{4} \text { moles }=n<br/>$$<br/><br/>In adiabatic process,<br/>$$<br/>\begin{array}{rlrl} <br/>& T V^{\gamma-1} & =\text { constant } \\<br/>& \therefore & T_2 V_2^{\gamma-1} ... | MarksBatch0.db |
3 | 29.2% ( w / w ) HCl stock solution has a density of 1.25 gmL â 1 . The molecular weight of HCl is 36.5 g mol â 1 . The volume ( mL ) of stock solution required to prepare a 200 mL solution of 0.4 M HCl is : | 29-2-w-w-hcl-stock-solution-has-a-density-of-1-25-gml-1-the-molecular-weight-of-hcl-is-67767 | <div class="question">$29.2 \%(\mathrm{w} / \mathrm{w}) \mathrm{HCl}$ stock solution has a density of $1.25 \mathrm{gmL}^{-1}$. The molecular weight of $\mathrm{HCl}$ is $36.5 \mathrm{~g} \mathrm{~mol}^{-1}$. The volume $(\mathrm{mL})$ of stock solution required to prepare a 200 $\mathrm{mL}$ solution of $0.4 \mathrm{M... | ['Chemistry', 'Some Basic Concepts of Chemistry', 'JEE Advanced', 'JEE Advanced 2012 (Paper 1)'] | None | <div class="correct-answer">
The correct answer is:
<span class="option-value">8</span> </div> | <div class="solution">Molarity of stock solution of $\mathrm{HCl}$
<br/> <br/>$=\frac{29.2 \times 1000 \times 1.25}{100 \times 36.5}$
<br/> <br/>Let the volume of stock solution required $=V \mathrm{~mL}$
<br/> <br/>Thus, $V \times \frac{29.2 \times 1000 \times 1.25}{100 \times 36.5}=200 \times 0.4$ $\Rightarrow V=8 \m... | MarksBatch0.db |
4 | 75.2 g of C 6 â H 5 â OH (phenol) is dissolved in a solvent of K f â = 14 . If the depression in freezing point is 7 K , then find the % of phenol that dimerises. | 75-2-g-of-c-6-h-5-oh-phenol-is-dissolved-in-a-solvent-of-k-f-14-if-the-depression-64934 | <div class="question">$75.2 \mathrm{~g}$ of $\mathrm{C}_6 \mathrm{H}_5 \mathrm{OH}$ (phenol) is dissolved in a solvent of $K_f=14$. If the depression in freezing point is $7 \mathrm{~K}$, then find the $\%$ of phenol that dimerises.</div> | ['Chemistry', 'Solutions', 'JEE Advanced', 'JEE Advanced 2006'] | None | <div class="correct-answer">
The correct answer is:
<span class="option-value">35</span> </div> | <div class="solution">Phenol is dimerised as follows<br/>At $t=0$<br/>$$<br/>2 \mathrm{C}_6 \mathrm{H}_5 \mathrm{OH} \rightleftharpoons\left(\mathrm{C}_6 \mathrm{H}_5 \mathrm{OH}\right)_2<br/>$$<br/>At equilibrium<br/>$$<br/>(1-\alpha) \quad \alpha / 2<br/>$$<br/>Total moles after dimerisation $=1-\alpha+\alpha / 2=1-\... | MarksBatch0.db |
5 | A 0.1 kg mass is suspended from a wire of negligible mass. The length of the wire is 1 m and its cross-sectional area is 4.9 Ã 1 0 â 7 m 2 . If the mass is pulled a little in the vertically downward direction and released, it performs simple harmonic motion of angular frequency 140 rad s â 1 . If the Young's modul... | a-0-1-kg-mass-is-suspended-from-a-wire-of-negligible-mass-the-length-of-the-wire-is-1-m-and-its-cro-90065 | <div class="question">A $0.1 \mathrm{~kg}$ mass is suspended from a wire of negligible mass. The length of the wire is $1 \mathrm{~m}$ and its cross-sectional area is $4.9 \times 10^{-7} \mathrm{~m}^2$. If the mass is pulled a little in the vertically downward direction and released, it performs simple harmonic motion ... | ['Physics', 'Mechanical Properties of Solids', 'JEE Advanced', 'JEE Advanced 2010 (Paper 1)'] | None | <div class="correct-answer">
The correct answer is:
<span class="option-value">4</span> </div> | <div class="solution">$\omega=\sqrt{\frac{K}{m}}=\sqrt{\frac{Y A}{l m}}=\sqrt{\frac{\left(n \times 10^9\right)\left(4.9 \times 10^{-7}\right)}{1 \times 0.1}}$<br/>Putting, $\omega=140 \operatorname{rad} \mathrm{s}^{-1}$ in above equation we get,<br/>$$<br/>n=4<br/>$$<br/>$\therefore$ Answer is 4 .</div> | MarksBatch0.db |
6 | A 2 μ F capacitor is charged as shown in the figure. The percentage of its stored energy dissipated after the switch S is turned to position 2 , is | a-2-f-capacitor-is-charged-as-shown-in-the-figure-the-percentage-of-its-stored-energy-dissipated-51052 | <div class="question">A $2 \mu \mathrm{F}$ capacitor is charged as shown in the figure. The percentage of its stored energy dissipated after the switch $S$ is turned to position 2 , is<br/><img src="https://cdn-question-pool.getmarks.app/pyq/jee_advanced/-pmB3YN7s_jnLXaMuH5hC5HdHc5c4gtUiS-FBt_xaDw.original.fullsize.png... | ['Physics', 'Capacitance', 'JEE Advanced', 'JEE Advanced 2011 (Paper 1)'] | <ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data"><br/>$0 \%$<br/></span> </li><li class=""> <span class="option-label">B</span> <span class="option-data"><br/>$20 \%$<br/></span> </li><li class=""> <span class="option-label">C</span> <span class="option-data"><br/>$75 \%$... | <div class="correct-answer">
The correct answer is:
<span class="option-value"><br/>$80 \%$</span> </div> | <div class="solution">$q_i=C_i V=2 V=q$ (say)<br/>This charge will remain constant after switch is shifted from position 1 to position 2.<br/>$$<br/>\begin{aligned}<br/>U_i & =\frac{1}{2} \frac{q^2}{C_i}=\frac{q^2}{2 \times 2}=\frac{q^2}{4} \\<br/>U_f & =\frac{1}{2} \frac{q^2}{C_f}=\frac{q^2}{2 \times 10}=\frac... | MarksBatch0.db |
7 | A 20 cm long string, having a mass of 1.0 g , is fixed at both the ends. The tension in the string is 0.5 N . The string is set into vibration using an external vibrator of frequency 100 Hz . Find the separation (in cm ) between the successive nodes on the string. | a-20-cm-long-string-having-a-mass-of-1-0-g-is-fixed-at-both-the-ends-the-tension-in-the-string-i-98746 | <div class="question">A $20 \mathrm{~cm}$ long string, having a mass of $1.0 \mathrm{~g}$, is fixed at both the ends. The tension in the string is $0.5 \mathrm{~N}$. The string is set into vibration using an external vibrator of frequency 100 $\mathrm{Hz}$. Find the separation (in $\mathrm{cm}$ ) between the successive... | ['Physics', 'Waves and Sound', 'JEE Advanced', 'JEE Advanced 2009 (Paper 2)'] | None | <div class="correct-answer">
The correct answer is:
<span class="option-value">5</span> </div> | <div class="solution">Distance between the successive nodes,<br/>$$<br/>\begin{aligned}<br/>d & =\frac{\lambda}{2}=\frac{v}{2 f} \\<br/>& =\frac{\sqrt{T / \mu}}{2 f}<br/>\end{aligned}<br/>$$<br/>Substituting the values we get<br/>$$<br/>d=5 \mathrm{~cm}<br/>$$</div> | MarksBatch0.db |
8 | A ball is dropped from a height of 20 m above the surface of water in a lake. The refractive index of water is 3 4 â . A fish inside the lake, in the line of fall of the ball, is looking at the ball. At an instant, when the ball is 12.8 m above the water surface, the fish sees the speed of ball as | a-ball-is-dropped-from-a-height-of-20-m-above-the-surface-of-water-in-a-lake-the-refractive-index-o-53117 | <div class="question">A ball is dropped from a height of $20 \mathrm{~m}$ above the surface of water in a lake. The refractive index of water is $\frac{4}{3}$. A fish inside the lake, in the line of fall of the ball, is looking at the ball. At an instant, when the ball is $12.8 \mathrm{~m}$ above the water surface, the... | ['Physics', 'Ray Optics', 'JEE Advanced', 'JEE Advanced 2009 (Paper 1)'] | <ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data"><br/>$9 \mathrm{~ms}^{-1}$<br/></span> </li><li class=""> <span class="option-label">B</span> <span class="option-data"><br/>$12 \mathrm{~ms}^{-1}$<br/></span> </li><li class="correct"> <span class="option-label">C</span> <... | <div class="correct-answer">
The correct answer is:
<span class="option-value"><br/>$16 \mathrm{~ms}^{-1}$<br/></span> </div> | <div class="solution">$v=\sqrt{2 g h}=\sqrt{2 \times 10 \times 7}=12 \mathrm{~ms}^{-1}$<br/><img src="https://cdn-question-pool.getmarks.app/pyq/jee_advanced/9vv6DsUIJzmaAOO7gLXW75DQeYmehCNseQnPs5bdTx4.original.fullsize.png"/><br/><br/>In this case when eye is inside water, $x_{\text {app. }}=\mu x \Rightarrow \frac{d ... | MarksBatch0.db |
9 | A ball moves over a fixed track as shown in the figure. From A to B the ball rolls without slipping. If surface BC is frictionless and K A â , K B â and K C â are kinetic energies of the ball at A , B and C respectively, then | a-ball-moves-over-a-fixed-track-as-shown-in-the-figure-from-a-to-b-the-ball-rolls-without-slipping-54634 | <div class="question">A ball moves over a fixed track as shown in the figure. From $A$ to $B$ the ball rolls without slipping. If surface $B C$ is frictionless and $K_A, K_B$ and $K_C$ are kinetic energies of the ball at $A, B$ and $C$ respectively, then<br/><img src="https://cdn-question-pool.getmarks.app/pyq/jee_adva... | ['Physics', 'Work Power Energy', 'JEE Main'] | <ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data"><br/>$h_A>h_C ; K_B>K_c$<br/></span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.9645... | <div class="correct-answer">
The correct answers are:
<span class="option-value"><br/>$h_A>h_C ; K_B>K_c$<br/></span> </div> | <div class="solution">In smooth part $B C$, due to zero torque, angular velocity and hence the rotational kinetic energy remains constant. While moving from $B$ to $C$ translational kinetic energy converts into gravitational energy.</div> | MarksBatch0.db |
10 | A ball moves over a fixed track as shown in the figure. From A to B the ball rolls without slipping. If surface BC is frictionless and K A â , K B â and K C â are kinetic energies of the ball at A , B and C respectively, then | a-ball-moves-over-a-fixed-track-as-shown-in-the-figure-from-a-to-b-the-ball-rolls-without-slipping-18134 | <div class="question">A ball moves over a fixed track as shown in the figure. From $A$ to $B$ the ball rolls without slipping. If surface $B C$ is frictionless and $K_A, K_B$ and $K_C$ are kinetic energies of the ball at $A, B$ and $C$ respectively, then<br/><img src="https://cdn-question-pool.getmarks.app/pyq/jee_adva... | ['Physics', 'Work Power Energy', 'JEE Advanced', 'JEE Advanced 2006'] | <ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data"><br/>$h_A>h_C ; K_B>K_c$<br/></span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.9645... | <div class="correct-answer">
The correct answers are:
<span class="option-value"><br/>$h_A>h_C ; K_B>K_c$<br/></span> </div> | <div class="solution">In smooth part $B C$, due to zero torque, angular velocity and hence the rotational kinetic energy remains constant. While moving from $B$ to $C$ translational kinetic energy converts into gravitational energy.</div> | MarksBatch0.db |
11 | A ball of mass 0.2 kg rests on a vertical post of height 5 m . A bullet of mass 0.01 kg , travelling with a velocity v m / s in a horizontal direction, hits the centre of the ball. After the collision, the ball and bullet travel independently. The ball hits the ground at a distance of 20 m and the bullet at a distance ... | a-ball-of-mass-0-2-kg-rests-on-a-vertical-post-of-height-5-m-a-bullet-of-mass-0-01-kg-travelling-33601 | <div class="question">A ball of mass $0.2 \mathrm{~kg}$ rests on a vertical post of height $5 \mathrm{~m}$. A bullet of mass $0.01 \mathrm{~kg}$, travelling with a velocity $v \mathrm{~m} / \mathrm{s}$ in a horizontal direction, hits the centre of the ball. After the collision, the ball and bullet travel independently.... | ['Physics', 'Center of Mass Momentum and Collision', 'JEE Main'] | <ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data"><br/>$250 \mathrm{~m} / \mathrm{s}$<br/></span> </li><li class=""> <span class="option-label">B</span> <span class="option-data"><br/>$250 \sqrt{2} \mathrm{~m} / \mathrm{s}$<br/></span> </li><li class=""> <span class="optio... | <div class="correct-answer">
The correct answer is:
<span class="option-value"><br/>$500 \mathrm{~m} / \mathrm{s}$</span> </div> | <div class="solution">Time taken by the bullet and ball to strike the ground is<br/>$$<br/>t=\sqrt{\frac{2 h}{g}}=\sqrt{\frac{2 \times 5}{10}}=1 \mathrm{~s}<br/>$$<br/>Let $v_1$ and $v_2$ are the velocities of ball and bullet after collision.<br/>Then applying<br/>We have, $20=v_1 \times 1$<br/>or $v_1=20 \mathrm{~ms}^... | MarksBatch0.db |
12 | A ball of mass 0.2 kg rests on a vertical post of height 5 m . A bullet of mass 0.01 kg , travelling with a velocity v m / s in a horizontal direction, hits the centre of the ball. After the collision, the ball and bullet travel independently. The ball hits the ground at a distance of 20 m and the bullet at a distance ... | a-ball-of-mass-0-2-kg-rests-on-a-vertical-post-of-height-5-m-a-bullet-of-mass-0-01-kg-travelling-27996 | <div class="question">A ball of mass $0.2 \mathrm{~kg}$ rests on a vertical post of height $5 \mathrm{~m}$. A bullet of mass $0.01 \mathrm{~kg}$, travelling with a velocity $v \mathrm{~m} / \mathrm{s}$ in a horizontal direction, hits the centre of the ball. After the collision, the ball and bullet travel independently.... | ['Physics', 'Center of Mass Momentum and Collision', 'JEE Advanced', 'JEE Advanced 2011 (Paper 2)'] | <ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data"><br/>$250 \mathrm{~m} / \mathrm{s}$<br/></span> </li><li class=""> <span class="option-label">B</span> <span class="option-data"><br/>$250 \sqrt{2} \mathrm{~m} / \mathrm{s}$<br/></span> </li><li class=""> <span class="optio... | <div class="correct-answer">
The correct answer is:
<span class="option-value"><br/>$500 \mathrm{~m} / \mathrm{s}$</span> </div> | <div class="solution">Time taken by the bullet and ball to strike the ground is<br/>$$<br/>t=\sqrt{\frac{2 h}{g}}=\sqrt{\frac{2 \times 5}{10}}=1 \mathrm{~s}<br/>$$<br/>Let $v_1$ and $v_2$ are the velocities of ball and bullet after collision.<br/>Then applying<br/>We have, $20=v_1 \times 1$<br/>or $v_1=20 \mathrm{~ms}^... | MarksBatch0.db |
13 | A ball of mass ( m ) 0.5 kg is attached to the end of a string having length ( L ) 0.5 m . The ball is rotated on a horizontal circular path about vertical axis. The maximum tension that the string can bear is 324 N . The maximum possible value of angular velocity of ball (in rad/s) is | a-ball-of-mass-m-0-5-kg-is-attached-to-the-end-of-a-string-having-length-l-0-5-m-the-ball-81767 | <div class="question">A ball of mass $(m) 0.5 \mathrm{~kg}$ is attached to the end of a string having length $(L) 0.5 \mathrm{~m}$. The ball is rotated on a horizontal circular path about vertical axis. The maximum tension that the string can bear is $324 \mathrm{~N}$. The maximum possible value of angular velocity of ... | ['Physics', 'Motion In Two Dimensions', 'JEE Advanced', 'JEE Advanced 2011 (Paper 1)'] | <ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data"><br/>9<br/></span> </li><li class=""> <span class="option-label">B</span> <span class="option-data"><br/>18<br/></span> </li><li class=""> <span class="option-label">C</span> <span class="option-data"><br/>27<br/></span> </... | <div class="correct-answer">
The correct answer is:
<span class="option-value"><br/>36</span> </div> | <div class="solution"><img src="https://cdn-question-pool.getmarks.app/pyq/jee_advanced/hQ-PiqB_orrFBgFTj13vssd112-QatgeCTIXhpgU2G8.original.fullsize.png"/><br/><br/><br/>$T \cos \theta$ component will cancel $\mathrm{mg}$.<br/>$T \sin \theta$ component will provide necessary centripetal force to the ball towards centr... | MarksBatch0.db |
14 | A bi-convex lens is formed with two thin plano-convex lenses as shown in the figure. Refractive index n of the first lens is 1.5 and that of the second lens is 1.2 . Both the curved surface are of the same radius of curvature R = 14 cm . For this bi-convex lens, for an object distance of 40 cm , the image distance will... | a-bi-convex-lens-is-formed-with-two-thin-plano-convex-lenses-as-shown-in-the-figure-refractive-inde-62619 | <div class="question">A bi-convex lens is formed with two thin plano-convex lenses as shown in the figure. Refractive index $n$ of the first lens is $1.5$ and that of the second lens is $1.2$. Both the curved surface are of the same radius of curvature $R=14$ $\mathrm{cm}$. For this bi-convex lens, for an object distan... | ['Physics', 'Ray Optics', 'JEE Advanced', 'JEE Advanced 2012 (Paper 1)'] | <ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$-280.0 \mathrm{~cm}$</span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data">$40.0 \mathrm{~cm}$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w... | <div class="correct-answer">
The correct answer is:
<span class="option-value">$40.0 \mathrm{~cm}$</span> </div> | <div class="solution">The focal length $\left(f_{1}\right)$ of the plano-cöneex Tens with $n=1.5$ using lens-maker formula
<br/> <br/>$\frac{1}{f_{1}}=\left(n_{1}-1\right)\left[\frac{1}{R_{1}}-\frac{1}{R_{2}}\right]=(1.5-1)\left[\frac{1}{14}-\frac{1}{\infty}\right]=\frac{1}{28}$
<br/> <br/>The focal length $\left(f_... | MarksBatch0.db |
15 | A biconvex lens of focal length 15 cm is in front of a plane mirror. The distance between the lens and the mirror is 10 cm . A small object is kept at a distance of 30 cm from the lens. The final image is | a-biconvex-lens-of-focal-length-15-cm-is-in-front-of-a-plane-mirror-the-distance-between-the-lens-a-21563 | <div class="question">A biconvex lens of focal length $15 \mathrm{~cm}$ is in front of a plane mirror. The distance between the lens and the mirror is 10 $\mathrm{cm}$. A small object is kept at a distance of $30 \mathrm{~cm}$ from the lens. The final image is</div> | ['Physics', 'Ray Optics', 'JEE Advanced', 'JEE Advanced 2010 (Paper 2)'] | <ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data"><br/>virtual and at a distance of $16 \mathrm{~cm}$ from the mirror<br/></span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data"><br/>real and at a distance of $16 \mathrm{~cm}$ from t... | <div class="correct-answer">
The correct answer is:
<span class="option-value"><br/>real and at a distance of $16 \mathrm{~cm}$ from the mirror<br/></span> </div> | <div class="solution">Object is placed at distance $2 f$ from the lens. So first image $I_1$ will be formed at distance $2 f$ on other side. This image $I_1$ will behave like a virtual object for mirror. The second image $I_2$ will be formed at distance $20 \mathrm{~cm}$ in front of the mirror, or at distance $10 \math... | MarksBatch0.db |
16 | A biconvex lens of focal length f forms a circular image of radius r of sun in focal plane. Then, which option is correct? | a-biconvex-lens-of-focal-length-f-forms-a-circular-image-of-radius-r-of-sun-in-focal-plane-then-wh-79833 | <div class="question">A biconvex lens of focal length $f$ forms a circular image of radius $r$ of sun in focal plane. Then, which option is correct?</div> | ['Physics', 'Ray Optics', 'JEE Advanced', 'JEE Advanced 2006'] | <ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data"><br/>$\pi r^2 \propto f$<br/></span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data"><br/>$\pi r^2 \propto f^2$ <br/></span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24... | <div class="correct-answer">
The correct answer is:
<span class="option-value"><br/>$\pi r^2 \propto f^2$ <br/></span> </div> | <div class="solution">$$<br/>r=f \tan \theta<br/>$$<br/>or<br/>$$<br/>\begin{array}{lc}<br/>\text { or } & r \propto f \\<br/>\therefore & \pi r^2 \propto f^2<br/>\end{array}<br/>$$<br/><img src="https://cdn-question-pool.getmarks.app/pyq/jee_advanced/yxHNcSn-WGr9bnkl3vlH8HqgkKoxf5WWI77ydI4twbQ.original.fullsiz... | MarksBatch0.db |
17 | A binary star consists of two stars A (mass 2.2 M S â ) and B (mass 11 M s â ), where M S â is the mass of the sun. They are separated by distance d and are rotating about their centre of mass, which is stationary. The ratio of the total angular momentum of the binary star to the angular momentum of star B about ... | a-binary-star-consists-of-two-stars-a-mass-2-2-m-s-and-b-mass-11-m-s-where-m-s-is-71459 | <div class="question">A binary star consists of two stars $A$ (mass $2.2 M_S$ ) and $B$ (mass $11 M_s$ ), where $M_S$ is the mass of the sun. They are separated by distance $d$ and are rotating about their centre of mass, which is stationary. The ratio of the total angular momentum of the binary star to the angular mom... | ['Physics', 'Gravitation', 'JEE Advanced', 'JEE Advanced 2010 (Paper 1)'] | None | <div class="correct-answer">
The correct answer is:
<span class="option-value">6</span> </div> | <div class="solution">$\frac{L_{\text {Total }}}{L_B}=\frac{\left(I_A+I_B\right) \omega}{I_B \cdot \omega}$ (as $\omega$ will be same in both cases)<br/>$$<br/>\begin{aligned}<br/>& =\frac{I_A}{I_B}+1=\frac{m_A r_A^2}{m_B r_B^2}+1 \\<br/>& \left.=\frac{r_A}{r_B}+1 \quad \quad \text { (as } m_A r_A=m_B r_B\right... | MarksBatch0.db |
18 | A black body of temperature T is inside chamber of temperature T 0 â . Now, the closed chamber is slightly opened to sun such that temperature of black body ( T ) and chamber ( T 0 â ) remains constant. | a-black-body-of-temperature-t-is-inside-chamber-of-temperature-t-0-now-the-closed-chamber-is-63485 | <div class="question">A black body of temperature $T$ is inside chamber of temperature $T_0$. Now, the closed chamber is slightly opened to sun such that temperature of black body $(T)$ and chamber $\left(T_0\right)$ remains constant.<br/><img src="https://cdn-question-pool.getmarks.app/pyq/jee_advanced/nmdq3Fzc9vK4geU... | ['Physics', 'Thermal Properties of Matter', 'JEE Advanced', 'JEE Advanced 2006'] | <ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data"><br/>Black body will absorb more radiation<br/></span> </li><li class=""> <span class="option-label">B</span> <span class="option-data"><br/>Black body will absorb less radiation<br/></span> </li><li class=""> <span class="... | <div class="correct-answer">
The correct answers are:
<span class="option-value"><br/>None of these</span> </div> | <div class="solution">Since, the temperature of black body is constant, total heat absorbed $=$ total heat radiated.</div> | MarksBatch0.db |
19 | A block ( B ) is attached to two unstretched S 1 â and S 2 â with spring constants k and 4 k , respectively (see figure I). The other ends are attached to identical supports M 1 â and M 2 â not attached to the walls. The springs and supports have negligible mass. There is no friction anywhere. The block B is di... | a-block-b-is-attached-to-two-unstretched-s-1-and-s-2-with-spring-constants-k-and-4-k-r-56544 | <div class="question">A block $(B)$ is attached to two unstretched $S_1$ and $S_2$ with spring constants $k$ and $4 k$, respectively (see figure I). The other ends are attached to identical supports $M_1$ and $M_2$ not attached to the walls. The springs and supports have negligible mass. There is no friction anywhere. ... | ['Physics', 'Oscillations', 'JEE Advanced', 'JEE Advanced 2008 (Paper 2)'] | <ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data"><br/>4<br/></span> </li><li class=""> <span class="option-label">B</span> <span class="option-data"><br/>2<br/></span> </li><li class="correct"> <span class="option-label">C</span> <span class="option-data"><br/>$\frac{1}{2... | <div class="correct-answer">
The correct answer is:
<span class="option-value"><br/>$\frac{1}{2}$<br/></span> </div> | <div class="solution">From energy conservation,<br/>$$<br/>\begin{aligned}<br/>\frac{1}{2} k x^2 & =\frac{1}{2}(4 k) y^2 \\<br/>\frac{y}{x} & =\frac{1}{2}<br/>\end{aligned}<br/>$$<br/>$\therefore$ correct option is (c).</div> | MarksBatch0.db |
20 | A block is moving on an inclined plane making an angle 4 5 â with the horizontal and the coefficient of friction is μ . The force required to just push it up the inclined plane is 3 times the force required to just prevent it from sliding down. If we define N = 10 μ , then N is | a-block-is-moving-on-an-inclined-plane-making-an-angle-4-5-with-the-horizontal-and-the-coefficie-97964 | <div class="question">A block is moving on an inclined plane making an angle $45^{\circ}$ with the horizontal and the coefficient of friction is $\mu$. The force required to just push it up the inclined plane is 3 times the force required to just prevent it from sliding down. If we define $N=10 \mu$, then $N$ is</div> | ['Physics', 'Laws of Motion', 'JEE Advanced', 'JEE Advanced 2011 (Paper 1)'] | None | <div class="correct-answer">
The correct answer is:
<span class="option-value">5</span> </div> | <div class="solution"><img src="https://cdn-question-pool.getmarks.app/pyq/jee_advanced/eySCplq6WaN-Uw5HFXL6SyXyNMZS2BoAPDicdUpjwso.original.fullsize.png"/><br/><img src="https://cdn-question-pool.getmarks.app/pyq/jee_advanced/A_tLk_dZ6J3lFdcrTO-XBum_JPxphlYFyCaGnc_1-iE.original.fullsize.png"/><br/><br/>$$<br/>\begin{a... | MarksBatch0.db |
21 | A block of base 10 cm à 10 cm and height 15 cm is kept on an inclined plane. The coefficient of friction between them is 3 â . The inclination θ of this inclined plane from the horizontal plane is gradually increased from 0 â . Then, | a-block-of-base-10-cm-10-cm-and-height-15-cm-is-kept-on-an-inclined-plane-the-coefficient-of-fri-50173 | <div class="question">A block of base $10 \mathrm{~cm} \times 10 \mathrm{~cm}$ and height $15 \mathrm{~cm}$ is kept on an inclined plane. The coefficient of friction between them is $\sqrt{3}$. The inclination $\theta$ of this inclined plane from the horizontal plane is gradually increased from $0^{\circ}$. Then,</div> | ['Physics', 'Laws of Motion', 'JEE Advanced', 'JEE Advanced 2009 (Paper 1)'] | <ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data"><br/>at $\theta=30^{\circ}$, the block will start sliding down the plane<br/></span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data"><br/>the block will remain at rest on the plane up... | <div class="correct-answer">
The correct answer is:
<span class="option-value"><br/>the block will remain at rest on the plane up to certain $\theta$ and then it will topple<br/></span> </div> | <div class="solution">Condition of sliding is $m g \sin \theta>\mu m g \cos \theta$<br/>or $\tan \theta>\mu$<br/>or $\quad \tan \theta>\sqrt{3}$<br/>Condition of toppling is<br/><img src="https://cdn-question-pool.getmarks.app/pyq/jee_advanced/cM4kLzRjOM5W0qj3dToc8zuVthq00TqewrB6onmam7I.original.fullsize.png"/... | MarksBatch0.db |
22 | A block of mass 2 kg is free to move along the x -axis. It is at rest and from t = 0 onwards it is subjected to a time-dependent force F ( t ) in the x direction. The force F ( t ) varies with t as shown in the figure. The kinetic energy of the block after 4.5 s is | a-block-of-mass-2-kg-is-free-to-move-along-the-x-axis-it-is-at-rest-and-from-t-0-onwards-it-is-s-41352 | <div class="question">A block of mass $2 \mathrm{~kg}$ is free to move along the $x$-axis. It is at rest and from $t$ $=0$ onwards it is subjected to a time-dependent force $F(t)$ in the $x$ direction. The force $F(t)$ varies with $t$ as shown in the figure. The kinetic energy of the block after $4.5 \mathrm{~s}$ is<br... | ['Physics', 'Work Power Energy', 'JEE Advanced', 'JEE Advanced 2010 (Paper 2)'] | <ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data"><br/>$4.50 \mathrm{~J}$<br/></span> </li><li class=""> <span class="option-label">B</span> <span class="option-data"><br/>$7.50 \mathrm{~J}$<br/></span> </li><li class="correct"> <span class="option-label">C</span> <span cl... | <div class="correct-answer">
The correct answer is:
<span class="option-value"><br/>$5.06 \mathrm{~J}$<br/></span> </div> | <div class="solution">Area under $F$ - $t$ graph $=$ momentum<br/>$$<br/>\begin{aligned}<br/>&=P=\sqrt{2 k m} \\<br/>& \therefore \quad k=\frac{A^2}{2 m} \\<br/>&(A=\text { net area of } F-t \text { graph) } \\<br/>&=\frac{\left\{\left(\frac{4 \times 3}{2}\right)-\left(\frac{1.5 \times 2}{2}\right)\righ... | MarksBatch0.db |
23 | A block of mass 2 M is attached to a massless spring with spring-constant k . This block is connected to two other blocks of masses M and 2 M using two massless pulleys and strings. The accelerations of the blocks are a 1 , a 2 and a 3 as shown in figure. The system is released from rest with the spring in its unstretc... | a-block-of-mass-2-m-is-attached-to-a-massless-spring-with-spring-constant-k-this-block-is-connecte-15478 | <div class="question"><p>A block of mass <math><mn>2</mn><mi mathvariant="normal">M</mi></math> is attached to a massless spring with spring-constant <math><mi mathvariant="normal">k</mi><mo>.</mo></math> This block is connected to two other blocks of masses <math><mi mathvariant="normal">M</mi></math> and <math><mn>2<... | ['Physics', 'Laws of Motion', 'JEE Advanced', 'JEE Advanced 2019 (Paper 2)'] | <ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data"><math><msub><mrow><mi mathvariant="normal">x</mi></mrow><mrow><mn>0</mn></mrow></msub><mo>=</mo><mfrac><mrow><mn>4</mn><mi mathvariant="normal">M</mi><mi mathvariant="normal">g</mi></mrow><mrow><mi mathvariant="normal">k</m... | <div class="correct-answer">
The correct answers are:
<span class="option-value"><math><msub><mrow><mi mathvariant="normal">a</mi></mrow><mrow><mn>2</mn></mrow></msub><mo>-</mo><msub><mrow><mi mathvariant="normal">a</mi></mrow><mrow><mn>1</mn></mrow></msub><mo>=</mo><msub><mrow><mi mathvariant="normal">a</mi></mrow><mr... | <div class="solution"><img src="https://cdn-question-pool.getmarks.app/pyq/jee_advanced/09b699d9-7e83-4187-8ccd-3ca9c9e42d6c-image21.png"/> <br/>Using string constraint <br/><math><msub><mrow><mi>a</mi></mrow><mrow><mn>1</mn></mrow></msub><mo>=</mo><mfrac><mrow><msub><mrow><mi>a</mi></mrow><mrow><mn>2</mn></mrow></msub... | MarksBatch0.db |
24 | A block of mass 0.18 kg is attached to a spring of force constant 2 N / m . The coefficient of friction between the block and the floor is 0.1. Initially, the block is at rest and the spring is unstretched. An impulse is given to the block as shown in the figure. The block slides a distance of 0.06 m and comes to rest ... | a-block-of-mass-0-18-kg-is-attached-to-a-spring-of-force-constant-2-n-m-the-coefficient-of-frict-39134 | <div class="question">A block of mass $0.18 \mathrm{~kg}$ is attached to a spring of force constant $2 \mathrm{~N} / \mathrm{m}$. The coefficient of friction between the block and the floor is 0.1. Initially, the block is at rest and the spring is unstretched. An impulse is given to the block as shown in the figure. Th... | ['Physics', 'Work Power Energy', 'JEE Advanced', 'JEE Advanced 2011 (Paper 2)'] | None | <div class="correct-answer">
The correct answer is:
<span class="option-value">4</span> </div> | <div class="solution">Decrease in mechanical energy<br/>$=$ Work done against friction<br/>$\therefore \quad \frac{1}{2} m v^2-\frac{1}{2} k x^2=\mu m g x$<br/>or $v=\sqrt{\frac{2 \mu m g x+k x^2}{m}}$<br/>Substituting the values, we get<br/>$$<br/>v=0.4 \mathrm{~ms}^{-1}=\left(\frac{4}{10}\right) \mathrm{ms}^{-1}<br/>... | MarksBatch0.db |
25 | A block of mass m is on an inclined plane of angle θ . The coefficient of friction between the block and the plane is μ and tan θ > μ . The block is held stationary by applying a force P parallel to the plane. The direction of force pointing up the plane is taken to be positive. As P is varied from P 1 â = m g ( ... | a-block-of-mass-m-is-on-an-inclined-plane-of-angle-the-coefficient-of-friction-between-the-bloc-27808 | <div class="question">A block of mass $m$ is on an inclined plane of angle $\theta$. The coefficient of friction between the block and the plane is $\mu$ and $\tan \theta>\mu$. The block is held stationary by applying a force $P$ parallel to the plane. The direction of force pointing up the plane is taken to be posi... | ['Physics', 'Laws of Motion', 'JEE Advanced', 'JEE Advanced 2010 (Paper 1)'] | <ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data"><br/><img src="https://cdn-question-pool.getmarks.app/pyq/jee_advanced/3J8uASe6iZWz0DOcTxIPzedKr7ohmEX9FABVqk8QJ8o.original.fullsize.png"/><br/></span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmln... | <div class="correct-answer">
The correct answer is:
<span class="option-value"><br/><img src="https://cdn-question-pool.getmarks.app/pyq/jee_advanced/3J8uASe6iZWz0DOcTxIPzedKr7ohmEX9FABVqk8QJ8o.original.fullsize.png"/><br/></span> </div> | <div class="solution">When<br/>$$<br/>\begin{aligned}<br/>P & =m g(\sin \theta-\mu \cos \theta) \\<br/>f & =\mu m g \cos \theta \quad \text { (upwards) } \\<br/>\text { when } \quad P & =m g \sin \theta \\<br/>f & =0<br/>\end{aligned}<br/>$$<br/>and when $P=m g(\sin \theta+\mu \cos \theta)$<br/>$$<br/>f... | MarksBatch0.db |
26 | A bob of mass M is suspended by a massless string of length L . The horizontal velocity v at position A is just sufficient to make it reach the point B . The angle θ at which the speed of the bob is half of that at A , satisfies | a-bob-of-mass-m-is-suspended-by-a-massless-string-of-length-l-the-horizontal-velocity-v-at-positio-22404 | <div class="question">A bob of mass $M$ is suspended by a massless string of length $L$. The horizontal velocity $v$ at position $A$ is just sufficient to make it reach the point $B$. The angle $\theta$ at which the speed of the bob is half of that at $A$, satisfies<br/><img src="https://cdn-question-pool.getmarks.app/... | ['Physics', 'Motion In Two Dimensions', 'JEE Advanced', 'JEE Advanced 2008 (Paper 2)'] | <ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data"><br/>$\theta=\frac{\pi}{4}$<br/></span> </li><li class=""> <span class="option-label">B</span> <span class="option-data"><br/>$\frac{\pi}{4} < \theta < \frac{\pi}{2}$</span> </li><li class=""> <span class="option-labe... | <div class="correct-answer">
The correct answer is:
<span class="option-value"><br/>$\frac{3 \pi}{4} < \theta < \pi$</span> </div> | <div class="solution">$v=\sqrt{5 g L}$<br/>Solving Eqs. (i), (ii) and (iii) we get,<br/>$$<br/>\cos \theta=-\frac{7}{8} \quad \text { or } \theta=\cos ^{-1}\left(-\frac{7}{8}\right)=151^{\circ}<br/>$$<br/>$\therefore$ correct option is (d).</div> | MarksBatch0.db |
27 | A bob of mass m , suspended by a string of length l 1 , is given a minimum velocity required to complete a full circle in the vertical plane. At the highest point, it collides elastically with another bob of mass m , suspended by a string of length l 2 , which is initially at rest. Both the strings are mass-less and in... | a-bob-of-mass-m-suspended-by-a-string-of-length-l-1-is-given-a-minimum-velocity-required-to-comp-50092 | <div class="question">A bob of mass <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>m</mi></math>, suspended by a string of length <math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>l</mi><mn>1</mn></msub></math>, is given a minimum velocity required to complete a full circle in the vertical plane. At the ... | ['Physics', 'Laws of Motion', 'JEE Advanced', 'JEE Advanced 2013 (Paper 1)'] | None | <div class="correct-answer">
The correct answer is:
<span class="option-value">5</span> </div> | <div class="solution"><p style="text-align: justify;"><img src="https://cdn-question-pool.getmarks.app/pyq/jee_advanced/EM0012552_AnsExp1_1..jpg"/><br/>As shown in the figure shown above, the minimum speed required by the bob of mass <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>m</mi></math> attached to the s... | MarksBatch0.db |
28 | A boy is pushing a ring of mass 2 kg and radius 0.5 m with a stick as shown in the figure. The stick applies a force of 2 N on the ring and rolls it without slipping with an acceleration of 0.3 m / s 2 . The coefficient of friction between the ground and the ring is large enough that rolling always occurs and the coeff... | a-boy-is-pushing-a-ring-of-mass-2-kg-and-radius-0-5-m-with-a-stick-as-shown-in-the-figure-the-stick-22732 | <div class="question">A boy is pushing a ring of mass $2 \mathrm{~kg}$ and radius $0.5 \mathrm{~m}$ with a stick as shown in the figure. The stick applies a force of $2 \mathrm{~N}$ on the ring and rolls it without slipping with an acceleration of $0.3 \mathrm{~m} / \mathrm{s}^2$. The coefficient of friction between th... | ['Physics', 'Rotational Motion', 'JEE Advanced', 'JEE Advanced 2011 (Paper 1)'] | None | <div class="correct-answer">
The correct answer is:
<span class="option-value">4</span> </div> | <div class="solution"><img src="https://cdn-question-pool.getmarks.app/pyq/jee_advanced/bZnr6gPHUpcK9KztXUjb3pyuleRikKc7WEgAbAi8fIU.original.fullsize.png"/><br/><br/>There is no slipping between ring and ground. Hence, $f_2$ is not maximum. But there is slipping between ring and stick. Therefore, $f_1$ is maximum. Now,... | MarksBatch0.db |
29 | A circuit is connected as shown in the figure with the switch S open. When the switch is closed, the total amount of charge that flows from Y to X is | a-circuit-is-connected-as-shown-in-the-figure-with-the-switch-s-open-when-the-switch-is-closed-the-75616 | <div class="question">A circuit is connected as shown in the figure with the switch $S$ open. When the switch is closed, the total amount of charge that flows from $Y$ to $X$ is<br/><img src="https://cdn-question-pool.getmarks.app/pyq/jee_advanced/gVNmoMqCTlpc9kjg3AHBkN3h3FpoDB_xQ_LN2wyvCFU.original.fullsize.png"/><br/... | ['Physics', 'Capacitance', 'JEE Main'] | <ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data"><br/>zero<br/></span> </li><li class=""> <span class="option-label">B</span> <span class="option-data"><br/>$54 \mu \mathrm{C}$<br/></span> </li><li class="correct"> <span class="option-label">C</span> <span class="option-d... | <div class="correct-answer">
The correct answer is:
<span class="option-value"><br/>$27 \mu \mathrm{C}$<br/></span> </div> | <div class="solution">From $Y$ to $X$ charge flows to plates $a$ and $b$.<br/>$$<br/>\left(q_0+q_b\right)_i=0,\left(q_0+q_b\right)_f=27 \mu \mathrm{C}<br/>$$<br/><img src="https://cdn-question-pool.getmarks.app/pyq/jee_advanced/U9y-IpNMTnta5hFfTFwh-2QOoznAart4eldMPFAg-5M.original.fullsize.png"/><br/><img src="https://c... | MarksBatch0.db |
30 | A circuit is connected as shown in the figure with the switch S open. When the switch is closed, the total amount of charge that flows from Y to X is | a-circuit-is-connected-as-shown-in-the-figure-with-the-switch-s-open-when-the-switch-is-closed-the-76341 | <div class="question">A circuit is connected as shown in the figure with the switch $S$ open. When the switch is closed, the total amount of charge that flows from $Y$ to $X$ is<br/><img src="https://cdn-question-pool.getmarks.app/pyq/jee_advanced/gVNmoMqCTlpc9kjg3AHBkN3h3FpoDB_xQ_LN2wyvCFU.original.fullsize.png"/><br/... | ['Physics', 'Capacitance', 'JEE Advanced', 'JEE Advanced 2007 (Paper 1)'] | <ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data"><br/>zero<br/></span> </li><li class=""> <span class="option-label">B</span> <span class="option-data"><br/>$54 \mu \mathrm{C}$<br/></span> </li><li class="correct"> <span class="option-label">C</span> <span class="option-d... | <div class="correct-answer">
The correct answer is:
<span class="option-value"><br/>$27 \mu \mathrm{C}$<br/></span> </div> | <div class="solution">From $Y$ to $X$ charge flows to plates $a$ and $b$.<br/>$$<br/>\left(q_0+q_b\right)_i=0,\left(q_0+q_b\right)_f=27 \mu \mathrm{C}<br/>$$<br/><img src="https://cdn-question-pool.getmarks.app/pyq/jee_advanced/U9y-IpNMTnta5hFfTFwh-2QOoznAart4eldMPFAg-5M.original.fullsize.png"/><br/><img src="https://c... | MarksBatch0.db |
31 | A circular disc with a groove along its diameter is placed horizontally. A block of mass 1 kg is placed as shown. The coefficient of friction between the block and all surfaces of groove in contact is μ = 2/5 . The disc has an acceleration of 25 m / s 2 . Find the acceleration of the block with respect to disc. | a-circular-disc-with-a-groove-along-its-diameter-is-placed-horizontally-a-block-of-mass-1-kg-is-pla-72553 | <div class="question">A circular disc with a groove along its diameter is placed horizontally. A block of mass $1 \mathrm{~kg}$ is placed as shown. The coefficient of friction between the block and all surfaces of groove in contact is $\mu=2 / 5$. The disc has an acceleration of $25 \mathrm{~m} / \mathrm{s}^2$. Find th... | ['Physics', 'Laws of Motion', 'JEE Advanced', 'JEE Advanced 2006'] | None | <div class="correct-answer">
The correct answer is:
<span class="option-value">10</span> </div> | <div class="solution">Normal reaction in vertical direction $N_1=m g$<br/>Normal reaction from side to the groove $N_2=m a \sin 37^{\circ}$<br/>Therefore, acceleration of block with respect to discs<br/>$$<br/>a_r=\frac{m a \cos 37^{\circ}-\mu N_1-\mu N_2}{m}<br/>$$<br/>Substituting the values we get, $\quad a_r=10 \ma... | MarksBatch0.db |
32 | A circular wire loop of radius R is placed in the x â y plane centered at the origin O . A square loop of side a ( a R ) having two turns is placed with its centre at z = 3 â R along the axis of the circular wire loop, as shown in figure. The plane of the square loop makes an angle of 4 5 â with respect to the z ... | a-circular-wire-loop-of-radius-r-is-placed-in-the-x-y-plane-centered-at-the-origin-o-a-square-38180 | <div class="question">A circular wire loop of radius $R$ is placed in the $x-y$ plane centered at the origin $O$. A square loop of side $a(a< < R)$ having two turns is placed with its centre at $z=\sqrt{3} R$ along the axis of the circular wire loop, as shown in figure.<img src="https://cdn-question-pool.getmarks... | ['Physics', 'Electromagnetic Induction', 'JEE Main'] | None | <div class="correct-answer">
The correct answer is:
<span class="option-value">7</span> </div> | <div class="solution">The magnetic field due to current carrying wire at the location of square loop is
<br/> <br/>$B=\frac{\mu_{0}}{4 \pi} \frac{2 \pi i R^{2}}{\left(R^{2}+3 R^{2}\right)^{3 / 2}}=\frac{\mu_{0} i}{16 R}$
<br/> <br/>The mutual induction
<br/> <br/>$\begin{array}{l}
<br/> <br/>M=\frac{N \phi}{i}=\frac{2}... | MarksBatch0.db |
33 | A circular wire loop of radius R is placed in the x â y plane centered at the origin O . A square loop of side a ( a R ) having two turns is placed with its centre at z = 3 â R along the axis of the circular wire loop, as shown in figure. The plane of the square loop makes an angle of 4 5 â with respect to the z ... | a-circular-wire-loop-of-radius-r-is-placed-in-the-x-y-plane-centered-at-the-origin-o-a-square-80632 | <div class="question">A circular wire loop of radius $R$ is placed in the $x-y$ plane centered at the origin $O$. A square loop of side $a(a< < R)$ having two turns is placed with its centre at $z=\sqrt{3} R$ along the axis of the circular wire loop, as shown in figure.<img src="https://cdn-question-pool.getmarks... | ['Physics', 'Electromagnetic Induction', 'JEE Advanced', 'JEE Advanced 2012 (Paper 1)'] | None | <div class="correct-answer">
The correct answer is:
<span class="option-value">7</span> </div> | <div class="solution">The magnetic field due to current carrying wire at the location of square loop is
<br/> <br/>$B=\frac{\mu_{0}}{4 \pi} \frac{2 \pi i R^{2}}{\left(R^{2}+3 R^{2}\right)^{3 / 2}}=\frac{\mu_{0} i}{16 R}$
<br/> <br/>The mutual induction
<br/> <br/>$\begin{array}{l}
<br/> <br/>M=\frac{N \phi}{i}=\frac{2}... | MarksBatch0.db |
34 | A composite block is made of slabs A , B , C , D and E of different thermal conductivities (given in terms of a constant, K ) and sizes (given in terms of length, L ) as shown in the figure. All slabs are of same width. Heat Q flows only from left to right through the blocks. Then, in steady state | a-composite-block-is-made-of-slabs-a-b-c-d-and-e-of-different-thermal-conductivities-given-in-25555 | <div class="question">A composite block is made of slabs $A, B, C, D$ and $E$ of different thermal conductivities (given in terms of a constant, $K$ ) and sizes (given in terms of length, $L$ ) as shown in the figure. All slabs are of same width. Heat $Q$ flows only from left to right through the blocks. Then, in stead... | ['Physics', 'Thermal Properties of Matter', 'JEE Advanced', 'JEE Advanced 2011 (Paper 1)'] | <ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data"><br/>heat flow through $A$ and $E$ slabs are same<br/></span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.8... | <div class="correct-answer">
The correct answers are:
<span class="option-value"><br/>heat flow through $A$ and $E$ slabs are same<br/>, <br/>temperature difference across slab $E$ is smallest<br/>, <br/>heat flow through $C=$ heat flow through $B$ + heat flow through $D$</span> </div> | <div class="solution">Thermal resistance<br/>$$<br/>\begin{aligned}<br/>& R=\frac{l}{K A} \\<br/>& \therefore \quad R_A=\frac{L}{(2 K)(4 L w)}=\frac{1}{8 K w} \\<br/>& \text { (Here, } w=\text { width) } \\<br/>& R_B=\frac{4 L}{3 K(L w)}=\frac{4}{3 K w} \\<br/>& R_C=\frac{4 L}{(4 K)(2 L w)}=\frac{1}... | MarksBatch0.db |
35 | A compound M p â X q â has cubic close packing (ccp) arrangement of X . Its unit cell structure is shown below. The empirical formula of the compound is | a-compound-m-p-x-q-has-cubic-close-packing-ccp-arrangement-of-x-its-unit-cell-structure-48724 | <div class="question">A compound $\mathrm{M}_{\mathrm{p}} \mathrm{X}_{\mathrm{q}}$ has cubic close packing (ccp) arrangement of $\mathrm{X}$. Its unit cell structure is shown below. The empirical formula of the compound is
<br/> <br/><img src="https://cdn-question-pool.getmarks.app/pyq/jee_advanced/0OaasNwsPUCQ9ofdG8mP... | ['Chemistry', 'Solid State', 'JEE Advanced', 'JEE Advanced 2012 (Paper 1)'] | <ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data">$\mathrm{MX}$</span> </li><li class="correct"> <span class="option-label">B</span> <span class="option-data">$\mathrm{MX}_{2}$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000... | <div class="correct-answer">
The correct answer is:
<span class="option-value">$\mathrm{MX}_{2}$</span> </div> | <div class="solution">No. of $M$ atoms $=\frac{1}{4} \times 4+1=1+1=2$
<br/> <br/>No. of $X$ atoms $=\frac{1}{2} \times 6+\frac{1}{8} \times 8=3+1=4$
<br/> <br/>So, formula $=M_{2} X_{4}=M X_{2}$</div> | MarksBatch0.db |
36 | A cubical region of side a has its centre at the origin. It encloses three fixed point charges, â q at ( 0 , â a /4 , 0 ) , + 3 q at ( 0 , 0 , 0 ) and â q at ( 0 , + a /4 , 0 ) . Choose the correct options(s) | a-cubical-region-of-side-a-has-its-centre-at-the-origin-it-encloses-three-fixed-point-charges-26810 | <div class="question">A cubical region of side $a$ has its centre at the origin. It encloses three fixed point charges, $-q$ at $(0,-a / 4,0),+3 q$ at $(0,0,0)$ and $-q$ at $(0,+a / 4,0)$. Choose the correct options(s)
<br/> <br/><img src="https://cdn-question-pool.getmarks.app/pyq/jee_advanced/u23N_x2xO_WSWDxMB8NBywx7... | ['Physics', 'Electrostatics', 'JEE Advanced', 'JEE Advanced 2012 (Paper 1)'] | <ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data">The net electric flux crossing the plane $x=+a / 2$ is equal to the net electric flux crossing the plane $x=-$ $a / 2$</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/... | <div class="correct-answer">
The correct answers are:
<span class="option-value">The net electric flux crossing the plane $x=+a / 2$ is equal to the net electric flux crossing the plane $x=-$ $a / 2$, The net electric flux crossing the entire region is $\frac{q}{\varepsilon_{0}}$, The net electric flux crossing the pla... | <div class="solution">Due to symmetry, the net electric flux passing through $x=+\frac{a}{2}$, $x=-\frac{a}{2}, z=+\frac{a}{2}$ is same
<br/> <br/>According to Gauss's theorem, net electric flux net electric flux crossing through any closed surface $\phi=\frac{q_{\text {in }}}{\varepsilon_{0}}=$ $\frac{-q+3 q-q}{\varep... | MarksBatch0.db |
37 | A current carrying infinitely long wire is kept along the diameter of a circular wire loop, without touching it, the correct statement(s) is(are) | a-current-carrying-infinitely-long-wire-is-kept-along-the-diameter-of-a-circular-wire-loop-without-19618 | <div class="question">A current carrying infinitely long wire is kept along the diameter of a circular wire loop, without touching it, the correct statement(s) is(are)</div> | ['Physics', 'Electromagnetic Induction', 'JEE Advanced', 'JEE Advanced 2012 (Paper 2)'] | <ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data">The emf induced in the loop is zero if the current is constant.</span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.... | <div class="correct-answer">
The correct answers are:
<span class="option-value">The emf induced in the loop is zero if the current is constant., The emf induced in the loop is zero if the current decreases at a steady rate.</span> </div> | <div class="solution">If the current is constant, the emf induced in the loop zero. Emf will be induced in the circular wire loop when flux through it changes with time.
<br/> <br/>$\mathrm{e}=-\frac{\Delta \phi}{\Delta \mathrm{t}}$
<br/> <br/>when the current is constant, the flux changing through it will be zero.
<br... | MarksBatch0.db |
38 | A cylindrical cavity of diameter a exists inside a cylinder of diameter 2 a as shown in the figure. Both the cylinder and the cavity are infinity long. A uniform current density J flows along the length. If the magnitude of the magnetic field at the point P is given by 12 N â μ 0 â a J , then the value of N is | a-cylindrical-cavity-of-diameter-a-exists-inside-a-cylinder-of-diameter-2-a-as-shown-in-the-figure-39143 | <div class="question">A cylindrical cavity of diameter a exists inside a cylinder of diameter $2 a$ as shown in the figure. Both the cylinder and the cavity are infinity long. A uniform current density $J$ flows along the length. If the magnitude of the magnetic field at the point $P$ is given by $\frac{N}{12} \mu_{0} ... | ['Physics', 'Magnetic Effects of Current', 'JEE Advanced', 'JEE Advanced 2012 (Paper 1)'] | None | <div class="correct-answer">
The correct answer is:
<span class="option-value">5</span> </div> | <div class="solution">Current density $J=\frac{\text { current }}{\text { area }}=\frac{I}{A} \Rightarrow I=\mathrm{JA}$ Magnetic field $\mathrm{B}_{\mathrm{R}}$ after removing cavity $(\mathrm{C})$ $\mathrm{B}_{\mathrm{R}}=\mathrm{B}_{\text {total }}-\mathrm{B}_{\text {cavity }}$
<br/> <br/>$\begin{array}{l}
<br/> <br... | MarksBatch0.db |
39 | A cylindrical furnace has height H and diameter D both 1 m . It is maintained at temperature 360 K . The air gets heated inside the furnace at constant pressure P a and its temperature becomes T = 360 K . The hot air with density Ï rises up a vertical chimney of diameter d = 0 . 1 m and height h = 9 m above the furnac... | a-cylindrical-furnace-has-height-h-and-diameter-d-both-1-m-it-is-maintained-at-temperature-360-k-78555 | <div class="question"><p>A cylindrical furnace has height <math xmlns="http://www.w3.org/1998/Math/MathML"><mfenced><mi>H</mi></mfenced></math> and diameter <math xmlns="http://www.w3.org/1998/Math/MathML"><mfenced><mi>D</mi></mfenced></math> both <math xmlns="http://www.w3.org/1998/Math/MathML"><mn>1</mn><mo> </mo><mi... | ['Physics', 'Mechanical Properties of Fluids', 'JEE Advanced', 'JEE Advanced 2023 (Paper 2)'] | None | <div class="correct-answer">
The correct answer is:
<span class="option-value">7850</span> </div> | <div class="solution"><blockquote><p>Applying Bernoulli’s theorem between top and bottom points of furnace :</p><p><math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>P</mi><mi>a</mi></msub><mo>+</mo><mfrac><mn>1</mn><mn>2</mn></mfrac><msub><mi>ρ</mi><mi>a</mi></msub><msup><mi>V</mi><mn>2</mn></msup><mo>=</mo><m... | MarksBatch0.db |
40 | A cylindrical furnace has height H and diameter D both 1 m . It is maintained at temperature 360 K . The air gets heated inside the furnace at constant pressure P a and its temperature becomes T = 360 K . The hot air with density Ï rises up a vertical chimney of diameter d = 0 . 1 m and height h = 9 m above the furnac... | a-cylindrical-furnace-has-height-h-and-diameter-d-both-1-m-it-is-maintained-at-temperature-360-k-53309 | <div class="question"><p>A cylindrical furnace has height <math xmlns="http://www.w3.org/1998/Math/MathML"><mfenced><mi>H</mi></mfenced></math> and diameter <math xmlns="http://www.w3.org/1998/Math/MathML"><mfenced><mi>D</mi></mfenced></math> both <math xmlns="http://www.w3.org/1998/Math/MathML"><mn>1</mn><mo> </mo><mi... | ['Physics', 'Mechanical Properties of Fluids', 'JEE Advanced', 'JEE Advanced 2023 (Paper 2)'] | None | <div class="correct-answer">
The correct answer is:
<span class="option-value">7850</span> </div> | <div class="solution"><blockquote><p>Applying Bernoulli’s theorem between top and bottom points of furnace :</p><p><math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>P</mi><mi>a</mi></msub><mo>+</mo><mfrac><mn>1</mn><mn>2</mn></mfrac><msub><mi>ρ</mi><mi>a</mi></msub><msup><mi>V</mi><mn>2</mn></msup><mo>=</mo><m... | MarksBatch0.db |
41 | A cylindrical vessel of height 500 mm has an orifice (small hole) at its bottom. The orifice is initially closed and water is filled in it upto height H . Now the top is completely sealed with a cap and the orifice at the bottom is opened. Some water comes out from the orifice and the water level in the vessel becomes ... | a-cylindrical-vessel-of-height-500-mm-has-an-orifice-small-hole-at-its-bottom-the-orifice-is-init-59533 | <div class="question">A cylindrical vessel of height $500 \mathrm{~mm}$ has an orifice (small hole) at its bottom. The orifice is initially closed and water is filled in it upto height $H$. Now the top is completely sealed with a cap and the orifice at the bottom is opened. Some water comes out from the orifice and the... | ['Physics', 'Mechanical Properties of Fluids', 'JEE Advanced', 'JEE Advanced 2009 (Paper 2)'] | None | <div class="correct-answer">
The correct answer is:
<span class="option-value">6</span> </div> | <div class="solution">In this question we will have to assume that temperature of enclosed air about water is constant (or $p V=$ constant)<br/><img src="https://cdn-question-pool.getmarks.app/pyq/jee_advanced/8dM8QYJxDmaHvc7TZMSYMcDZb9J5Qzf03BYUgRzDGn4.original.fullsize.png"/><br/><br/><br/>$$<br/>\begin{gathered}<br/... | MarksBatch0.db |
42 | A decapeptide (molecular weight 796) on complete hydrolysis gives glycine (molecular weight 75), alanine and phenylalanine. Glycine contributes 47.0% to the total weight of the hydrolysed products. The number of glycine units present in the decapeptide is | a-decapeptide-molecular-weight-796-on-complete-hydrolysis-gives-glycine-molecular-weight-75-ala-21183 | <div class="question">A decapeptide (molecular weight 796) on complete hydrolysis gives glycine (molecular weight 75), alanine and phenylalanine. Glycine contributes $47.0 \%$ to the total weight of the hydrolysed products. The number of glycine units present in the decapeptide is</div> | ['Chemistry', 'Biomolecules', 'JEE Advanced', 'JEE Advanced 2011 (Paper 1)'] | None | <div class="correct-answer">
The correct answer is:
<span class="option-value">6</span> </div> | <div class="solution">$$<br/>\text { A decapeptide has nine peptide (amide) linkage as }<br/>$$<br/><img src="https://cdn-question-pool.getmarks.app/pyq/jee_advanced/QRsCQ14li6NT9gp0NOovuoPzTGcmi68dMG0a74dUtUg.original.fullsize.png"/><br/><br/>Therefore, no hydrolysis, it will absorb nine water molecules.<br/>Hence, to... | MarksBatch0.db |
43 | A diatomic ideal gas is compressed adiabatically to 32 1 â of its initial volume. If the initial temperature of the gas is T i â T i â (in kelvin) and the final temperature is a T i â , the value of a is | a-diatomic-ideal-gas-is-compressed-adiabatically-to-32-1-of-its-initial-volume-if-the-initial-t-29573 | <div class="question">A diatomic ideal gas is compressed adiabatically to $\frac{1}{32}$ of its initial volume. If the initial temperature of the gas is $T_i$ $T_i$ (in kelvin) and the final temperature is $a T_i$, the value of $a$ is</div> | ['Physics', 'Thermodynamics', 'JEE Advanced', 'JEE Advanced 2010 (Paper 2)'] | None | <div class="correct-answer">
The correct answer is:
<span class="option-value">4</span> </div> | <div class="solution">In adiabatic process,<br/>$$<br/>\begin{aligned}<br/>& T V^{\gamma-1}=\text { constant } \\<br/>& \therefore T_i V_i^{0.4}=T_f V_f^{0.4} \\<br/>& \text { (as } \gamma=1.4 \text { for diatomic gas) } \\<br/>& \text { or } \quad T_i V_i^{0.4}=\left(\alpha T_i\right)\left(\frac{V_i}{3... | MarksBatch0.db |
44 | A disk of radius 4 a â having a uniformly distributed charge 6 C is placed in the x â y plane with its centre at ( 2 â a â , 0 , 0 ) . A rod of length a carrying a uniformly distributed charge 8 C is placed on the x -axis from x = 4 a â to x = 4 5 a â . Two point charges â 7 C and 3 C are placed at ( 4 a ... | a-disk-of-radius-4-a-having-a-uniformly-distributed-charge-6-c-is-placed-in-the-x-y-plane-wi-97430 | <div class="question">A disk of radius $\frac{a}{4}$ having a uniformly distributed charge $6 \mathrm{C}$ is placed in the $x-y$ plane with its centre at $\left(\frac{-a}{2}, 0,0\right)$. A rod of length a carrying a uniformly distributed charge $8 \mathrm{C}$ is placed on the $x$-axis from $x=\frac{a}{4}$ to $x=\frac{... | ['Physics', 'Electrostatics', 'JEE Main'] | <ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data"><br/>$\frac{-2 C}{\varepsilon_0}$<br/></span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.9... | <div class="correct-answer">
The correct answer is:
<span class="option-value"><br/>$\frac{-2 C}{\varepsilon_0}$<br/></span> </div> | <div class="solution">Total enclosed charge as already shown is<br/>$$<br/>q_{\text {net }}=\frac{6 C}{2}+\frac{8 C}{4}-7 C=-2 C<br/>$$<br/>From Gauss-theorem, net flux,<br/>$$<br/>\varphi_{\text {net }}=\frac{q_{\text {net }}}{\varepsilon_0}=\frac{-2 C}{\varepsilon_0}<br/>$$</div> | MarksBatch0.db |
45 | A disk of radius 4 a â having a uniformly distributed charge 6 C is placed in the x â y plane with its centre at ( 2 â a â , 0 , 0 ) . A rod of length a carrying a uniformly distributed charge 8 C is placed on the x -axis from x = 4 a â to x = 4 5 a â . Two point charges â 7 C and 3 C are placed at ( 4 a ... | a-disk-of-radius-4-a-having-a-uniformly-distributed-charge-6-c-is-placed-in-the-x-y-plane-wi-33837 | <div class="question">A disk of radius $\frac{a}{4}$ having a uniformly distributed charge $6 \mathrm{C}$ is placed in the $x-y$ plane with its centre at $\left(\frac{-a}{2}, 0,0\right)$. A rod of length a carrying a uniformly distributed charge $8 \mathrm{C}$ is placed on the $x$-axis from $x=\frac{a}{4}$ to $x=\frac{... | ['Physics', 'Electrostatics', 'JEE Advanced', 'JEE Advanced 2009 (Paper 1)'] | <ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data"><br/>$\frac{-2 C}{\varepsilon_0}$<br/></span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.9... | <div class="correct-answer">
The correct answer is:
<span class="option-value"><br/>$\frac{-2 C}{\varepsilon_0}$<br/></span> </div> | <div class="solution">Total enclosed charge as already shown is<br/>$$<br/>q_{\text {net }}=\frac{6 C}{2}+\frac{8 C}{4}-7 C=-2 C<br/>$$<br/>From Gauss-theorem, net flux,<br/>$$<br/>\varphi_{\text {net }}=\frac{q_{\text {net }}}{\varepsilon_0}=\frac{-2 C}{\varepsilon_0}<br/>$$</div> | MarksBatch0.db |
46 | A disk of radius R with uniform positive charge density Ï is placed on the x y plane with its center at the origin. The Coulomb potential along the z -axis is V z = Ï 2 ϵ 0 R 2 + z 2 - z A particle of positive charge q is placed initially at rest at a point on the z -axis with z = z 0 and z 0 > 0 . In addition to th... | a-disk-of-radius-r-with-uniform-positive-charge-density-is-placed-on-the-x-y-plane-with-its-cente-24247 | <div class="question"><p>A disk of radius <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>R</mi></math> with uniform positive charge density <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>σ</mi></math> is placed on the <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>x</mi><mi>y</mi></math> plane with it... | ['Physics', 'Electrostatics', 'JEE Advanced', 'JEE Advanced 2022 (Paper 2)'] | <ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data">For <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>β</mi><mo>=</mo><mfrac><mn>1</mn><mn>4</mn></mfrac></math> and <math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>z</mi><mn>0</mn></msub><mo>=</mo><mfr... | <div class="correct-answer">
The correct answers are:
<span class="option-value">For <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>β</mi><mo>=</mo><mfrac><mn>1</mn><mn>4</mn></mfrac></math> and <math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>z</mi><mn>0</mn></msub><mo>=</mo><mfrac><mn>25</mn><mn>7</mn... | <div class="solution"><p>For the particle to reach at origin, work done by the force should be greater than the increase in the potential energy of the charged particle. Therefore,</p><p><math xmlns="http://www.w3.org/1998/Math/MathML"><mi>c</mi><mi>z</mi><mo>≥</mo><mfrac><mrow><mi>σ</mi><mi>q</mi></mrow><mrow><mn>2</m... | MarksBatch0.db |
47 | A double star system consists of two stars A and B which have time period T A â and T B â . Radius R A â and R B â and mass M A â and M B â . Choose the correct option. | a-double-star-system-consists-of-two-stars-a-and-b-which-have-time-period-t-a-and-t-b-radi-89463 | <div class="question">A double star system consists of two stars $A$ and $B$ which have time period $T_A$ and $T_B$. Radius $R_A$ and $R_B$ and mass $M_A$ and $M_B$. Choose the correct option.</div> | ['Physics', 'Gravitation', 'JEE Advanced', 'JEE Advanced 2006'] | <ul class="options"> <li class=""> <span class="option-label">A</span> <span class="option-data"><br/>If $T_A>T_B$, then $R_A>R_B$<br/></span> </li><li class=""> <span class="option-label">B</span> <span class="option-data"><br/>If $T_A>T_B$, then $M_A>M_B$<br/></span> </li><li class=""> <span class="option... | <div class="correct-answer">
The correct answer is:
<span class="option-value"><br/>$T_A=T_B$</span> </div> | <div class="solution">In case of binary star system angular velocity and hence the time period of both the stars are equal.</div> | MarksBatch0.db |
48 | A few electric field lines for a system of two charges Q 1 â and Q 2 â fixed at two different points on the x -axis are shown in the figure. These lines suggest that | a-few-electric-field-lines-for-a-system-of-two-charges-q-1-and-q-2-fixed-at-two-different-po-67686 | <div class="question">A few electric field lines for a system of two charges $Q_1$ and $Q_2$ fixed at two different points on the $x$-axis are shown in the figure. These lines suggest that<br/><img src="https://cdn-question-pool.getmarks.app/pyq/jee_advanced/R5lzBNcidnS01bSprkXrbMp3l9bUBkdMt6YycbuULb8.original.fullsize... | ['Physics', 'Electrostatics', 'JEE Advanced', 'JEE Advanced 2010 (Paper 1)'] | <ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data"><br/>$\left|Q_1\right|>\left|Q_2\right|$<br/></span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4... | <div class="correct-answer">
The correct answers are:
<span class="option-value"><br/>$\left|Q_1\right|>\left|Q_2\right|$<br/>, <br/>at a finite distance to the right of $Q_2$ the electric field is zero</span> </div> | <div class="solution">From the behaviour of electric lines, we can say that $Q_1$ is positive and $Q_2$ is negative. Further, $\left|Q_1\right|>\left|Q_2\right|$<br/>At some finite distance to the right of $Q_2$, electric field will be zero. Because electric field due to $Q_1$ is towards right (away from $Q_1$ ) and... | MarksBatch0.db |
49 | A field line is shown in the figure. This field cannot represent | a-field-line-is-shown-in-the-figure-this-field-cannot-represent-34016 | <div class="question">A field line is shown in the figure. This field cannot represent<br/><img src="https://cdn-question-pool.getmarks.app/pyq/jee_advanced/sBuAndXrVPaCS8wD88iMYjym52y85QgiPtevdojilzs.original.fullsize.png"/><br/></div> | ['Physics', 'Magnetic Effects of Current', 'JEE Advanced', 'JEE Advanced 2006'] | <ul class="options"> <li class="correct"> <span class="option-label">A</span> <span class="option-data"><br/>Magnetic field<br/></span> <svg fill="none" height="24" viewbox="0 0 24 24" width="24" xmlns="http://www.w3.org/2000/svg"> <path d="M12 2.25C10.0716 2.25 8.18657 2.82183 6.58319 3.89317C4.97982 4.96452 3.73013 6... | <div class="correct-answer">
The correct answers are:
<span class="option-value"><br/>Magnetic field<br/>, <br/>Gravitational field</span> </div> | <div class="solution">Electrostatic and gravitational field do not make closed loops.</div> | MarksBatch0.db |
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