instance_id stringlengths 11 13 | prompt stringlengths 115 1.36k | canonical_solution stringlengths 16 864 | test stringlengths 84 2.1k |
|---|---|---|---|
HumanEval/100 |
def make_a_pile(n):
"""
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each lev... | return [n + 2*i for i in range(n)]
| candidate = make_a_pile
def test1():
assert candidate(3) == [3, 5, 7], "Test 3"
def test2():
assert candidate(4) == [4,6,8,10], "Test 4"
def test3():
assert candidate(5) == [5, 7, 9, 11, 13]
def test4():
assert candidate(6) == [6, 8, 10, 12, 14, 16]
def test5():
assert candidate(8) == [8, 10, 1... |
HumanEval/101 |
def words_string(s):
"""
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
words_string("One, two, three, fo... | if not s:
return []
s_list = []
for letter in s:
if letter == ',':
s_list.append(' ')
else:
s_list.append(letter)
s_list = "".join(s_list)
return s_list.split()
| candidate = words_string
def test1():
assert True, "This prints if this assert fails 1 (good for debugging!)"
def test2():
assert candidate("Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
def test3():
assert candidate("One, two, three, four, five, six") == ["One", "two", "three", "four", "fi... |
HumanEval/102 |
def choose_num(x, y):
"""This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
choose_num(12, 15) = 14
choose_num(13, 12) = -1
"""
| if x > y:
return -1
if y % 2 == 0:
return y
if x == y:
return -1
return y - 1
| candidate = choose_num
def test1():
assert candidate(12, 15) == 14
def test2():
assert candidate(13, 12) == -1
def test3():
assert candidate(33, 12354) == 12354
def test4():
assert candidate(5234, 5233) == -1
def test5():
assert candidate(6, 29) == 28
def test6():
assert candidate(27, 10) ... |
HumanEval/103 |
def rounded_avg(n, m):
"""You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
rounded_avg(1, 5)... | if m < n:
return -1
summation = 0
for i in range(n, m+1):
summation += i
return bin(round(summation/(m - n + 1)))
| candidate = rounded_avg
def test1():
assert candidate(1, 5) == "0b11"
def test2():
assert candidate(7, 13) == "0b1010"
def test3():
assert candidate(964,977) == "0b1111001010"
def test4():
assert candidate(996,997) == "0b1111100100"
def test5():
assert candidate(560,851) == "0b1011000010"
def ... |
HumanEval/104 |
def unique_digits(x):
"""Given a list of positive integers x. return a sorted list of all
elements that hasn't any even digit.
Note: Returned list should be sorted in increasing order.
For example:
>>> unique_digits([15, 33, 1422, 1])
[1, 15, 33]
>>> unique_digits([152, 323, 1422, 10... | odd_digit_elements = []
for i in x:
if all (int(c) % 2 == 1 for c in str(i)):
odd_digit_elements.append(i)
return sorted(odd_digit_elements)
| candidate = unique_digits
def test1():
assert candidate([15, 33, 1422, 1]) == [1, 15, 33]
def test2():
assert candidate([152, 323, 1422, 10]) == []
def test3():
assert candidate([12345, 2033, 111, 151]) == [111, 151]
def test4():
assert candidate([135, 103, 31]) == [31, 135]
def test5():
assert... |
HumanEval/105 |
def by_length(arr):
"""
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
arr = [2, 1, ... | dic = {
1: "One",
2: "Two",
3: "Three",
4: "Four",
5: "Five",
6: "Six",
7: "Seven",
8: "Eight",
9: "Nine",
}
sorted_arr = sorted(arr, reverse=True)
new_arr = []
for var in sorted_arr:
try:
new_arr.append(dic[... | candidate = by_length
def test1():
assert True, "This prints if this assert fails 1 (good for debugging!)"
def test2():
assert candidate([2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"], "Error"
def test3():
assert candidate([]) == [], "Error"
def test4():
... |
HumanEval/106 |
def f(n):
""" Implement the function f that takes n as a parameter,
and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers fr... | ret = []
for i in range(1,n+1):
if i%2 == 0:
x = 1
for j in range(1,i+1): x *= j
ret += [x]
else:
x = 0
for j in range(1,i+1): x += j
ret += [x]
return ret
| candidate = f
def test1():
assert candidate(5) == [1, 2, 6, 24, 15]
def test2():
assert candidate(7) == [1, 2, 6, 24, 15, 720, 28]
def test3():
assert candidate(1) == [1]
def test4():
assert candidate(3) == [1, 2, 6] |
HumanEval/107 |
def even_odd_palindrome(n):
"""
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Input: 3
Output: (1, 2)
Explanation:
Integer palindrome are 1, 2, 3. one of them i... | def is_palindrome(n):
return str(n) == str(n)[::-1]
even_palindrome_count = 0
odd_palindrome_count = 0
for i in range(1, n+1):
if i%2 == 1 and is_palindrome(i):
odd_palindrome_count += 1
elif i%2 == 0 and is_palindrome(i):
even_palindrome_count += 1
... | candidate = even_odd_palindrome
def test1():
assert candidate(123) == (8, 13)
def test2():
assert candidate(12) == (4, 6)
def test3():
assert candidate(3) == (1, 2)
def test4():
assert candidate(63) == (6, 8)
def test5():
assert candidate(25) == (5, 6)
def test6():
assert candidate(19) == ... |
HumanEval/108 |
def count_nums(arr):
"""
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
>>> count_nums([]) == 0
>>... | def digits_sum(n):
neg = 1
if n < 0: n, neg = -1 * n, -1
n = [int(i) for i in str(n)]
n[0] = n[0] * neg
return sum(n)
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr])))
| candidate = count_nums
def test1():
assert candidate([]) == 0
def test2():
assert candidate([-1, -2, 0]) == 0
def test3():
assert candidate([1, 1, 2, -2, 3, 4, 5]) == 6
def test4():
assert candidate([1, 6, 9, -6, 0, 1, 5]) == 5
def test5():
assert candidate([1, 100, 98, -7, 1, -1]) == 4
def te... |
HumanEval/109 |
def move_one_ball(arr):
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
Yo... | if len(arr)==0:
return True
sorted_array=sorted(arr)
my_arr=[]
min_value=min(arr)
min_index=arr.index(min_value)
my_arr=arr[min_index:]+arr[0:min_index]
for i in range(len(arr)):
if my_arr[i]!=sorted_array[i]:
return False
return True
| candidate = move_one_ball
def test1():
assert candidate([3, 4, 5, 1, 2])==True, "This prints if this assert fails 1 (good for debugging!)"
def test2():
assert candidate([3, 5, 10, 1, 2])==True
def test3():
assert candidate([4, 3, 1, 2])==False
def test4():
assert candidate([3, 5, 4, 1, 2])==False, "... |
HumanEval/110 |
def exchange(lst1, lst2):
"""In this problem, you will implement a function that takes two lists of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 a list of only even numbers.
There is no limit on the number of exchanged elements between lst1... | odd = 0
even = 0
for i in lst1:
if i%2 == 1:
odd += 1
for i in lst2:
if i%2 == 0:
even += 1
if even >= odd:
return "YES"
return "NO"
| candidate = exchange
def test1():
assert candidate([1, 2, 3, 4], [1, 2, 3, 4]) == "YES"
def test2():
assert candidate([1, 2, 3, 4], [1, 5, 3, 4]) == "NO"
def test3():
assert candidate([1, 2, 3, 4], [2, 1, 4, 3]) == "YES"
def test4():
assert candidate([5, 7, 3], [2, 6, 4]) == "YES"
def test5():
... |
HumanEval/111 |
def histogram(test):
"""Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram('a b c') == {'a': 1, '... | dict1={}
list1=test.split(" ")
t=0
for i in list1:
if(list1.count(i)>t) and i!='':
t=list1.count(i)
if t>0:
for i in list1:
if(list1.count(i)==t):
dict1[i]=t
return dict1
| candidate = histogram
def test1():
assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
def test2():
assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
def test3():
assert candidate('a b c d g'... |
HumanEval/112 |
def reverse_delete(s,c):
"""Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple contai... | s = ''.join([char for char in s if char not in c])
return (s,s[::-1] == s)
| candidate = reverse_delete
def test1():
assert candidate("abcde","ae") == ('bcd',False)
def test2():
assert candidate("abcdef", "b") == ('acdef',False)
def test3():
assert candidate("abcdedcba","ab") == ('cdedc',True)
def test4():
assert candidate("dwik","w") == ('dik',False)
def test5():
asser... |
HumanEval/113 |
def odd_count(lst):
"""Given a list of strings, where each string consists of only digits, return a list.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
... | res = []
for arr in lst:
n = sum(int(d)%2==1 for d in arr)
res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.")
return res
| candidate = odd_count
def test1():
assert candidate(['1234567']) == ["the number of odd elements 4n the str4ng 4 of the 4nput."], "Test 1"
def test2():
assert candidate(['3',"11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."]... |
HumanEval/114 |
def minSubArraySum(nums):
"""
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
minSubArraySum([-1, -2, -3]) == -6
"""
| max_sum = 0
s = 0
for num in nums:
s += -num
if (s < 0):
s = 0
max_sum = max(s, max_sum)
if max_sum == 0:
max_sum = max(-i for i in nums)
min_sum = -max_sum
return min_sum
| candidate = minSubArraySum
def test1():
assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
def test2():
assert candidate([-1, -2, -3]) == -6
def test3():
assert candidate([-1, -2, -3, 2, -10]) == -14
def test4():
assert candidate([-9999999999999999]... |
HumanEval/115 |
def max_fill(grid, capacity):
import math
"""
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capac... | return sum([math.ceil(sum(arr)/capacity) for arr in grid])
| candidate = max_fill
def test1():
assert True, "This prints if this assert fails 1 (good for debugging!)"
def test2():
assert candidate([[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1) == 6, "Error"
def test3():
assert candidate([[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2) == 5, "Error"
def test4():
assert... |
HumanEval/116 |
def sort_array(arr):
"""
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
>>> sort_array([1, 5, 2, 3, 4]) ==... | return sorted(sorted(arr), key=lambda x: bin(x)[2:].count('1'))
| candidate = sort_array
def test1():
assert True, "This prints if this assert fails 1 (good for debugging!)"
def test2():
assert candidate([1,5,2,3,4]) == [1, 2, 4, 3, 5]
def test3():
assert candidate([-2,-3,-4,-5,-6]) == [-4, -2, -6, -5, -3]
def test4():
assert candidate([1,0,2,3,4]) == [0, 1, 2, 4,... |
HumanEval/117 |
def select_words(s, n):
"""Given a string s and a natural number n, you have been tasked to implement
a function that returns a list of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an e... | result = []
for word in s.split():
n_consonants = 0
for i in range(0, len(word)):
if word[i].lower() not in ["a","e","i","o","u"]:
n_consonants += 1
if n_consonants == n:
result.append(word)
return result
| candidate = select_words
def test1():
assert candidate("Mary had a little lamb", 4) == ["little"], "First test error: " + str(candidate("Mary had a little lamb", 4))
def test2():
assert candidate("Mary had a little lamb", 3) == ["Mary", "lamb"], "Second test error: " + str(candidate("Mary had a little l... |
HumanEval/118 |
def get_closest_vowel(word):
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condit... | if len(word) < 3:
return ""
vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
for i in range(len(word)-2, 0, -1):
if word[i] in vowels:
if (word[i+1] not in vowels) and (word[i-1] not in vowels):
return word[i]
return ""
| candidate = get_closest_vowel
def test1():
assert candidate("yogurt") == "u"
def test2():
assert candidate("full") == "u"
def test3():
assert candidate("easy") == ""
def test4():
assert candidate("eAsy") == ""
def test5():
assert candidate("ali") == ""
def test6():
assert candidate("bad") ... |
HumanEval/119 |
def match_parens(lst):
'''
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be... | def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes'... | candidate = match_parens
def test1():
assert candidate(['()(', ')']) == 'Yes'
def test2():
assert candidate([')', ')']) == 'No'
def test3():
assert candidate(['(()(())', '())())']) == 'No'
def test4():
assert candidate([')())', '(()()(']) == 'Yes'
def test5():
assert candidate(['(())))', '(()()... |
HumanEval/120 |
def maximum(arr, k):
"""
Given an array arr of integers and a positive integer k, return a sorted list
of length k with the maximum k numbers in arr.
Example 1:
Input: arr = [-3, -4, 5], k = 3
Output: [-4, -3, 5]
Example 2:
Input: arr = [4, -4, 4], k = 2
Output:... | if k == 0:
return []
arr.sort()
ans = arr[-k:]
return ans
| candidate = maximum
def test1():
assert candidate([-3, -4, 5], 3) == [-4, -3, 5]
def test2():
assert candidate([4, -4, 4], 2) == [4, 4]
def test3():
assert candidate([-3, 2, 1, 2, -1, -2, 1], 1) == [2]
def test4():
assert candidate([123, -123, 20, 0 , 1, 2, -3], 3) == [2, 20, 123]
def test5():
... |
HumanEval/121 |
def solution(lst):
"""Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution([5, 8, 7, 1]) ==> 12
solution([3, 3, 3, 3, 3]) ==> 9
solution([30, 13, 24, 321]) ==>0
"""
| return sum([x for idx, x in enumerate(lst) if idx%2==0 and x%2==1])
| candidate = solution
def test1():
assert candidate([5, 8, 7, 1]) == 12
def test2():
assert candidate([3, 3, 3, 3, 3]) == 9
def test3():
assert candidate([30, 13, 24, 321]) == 0
def test4():
assert candidate([5, 9]) == 5
def test5():
assert candidate([2, 4, 8]) == 0
def test6():
assert c... |
HumanEval/122 |
def add_elements(arr, k):
"""
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Input: arr = [111,21,3,4000,5,6,7,8,9], k = 4
Output: 24 # sum of 21 + 3
Constraints:
... | return sum(elem for elem in arr[:k] if len(str(elem)) <= 2)
| candidate = add_elements
def test1():
assert candidate([1,-2,-3,41,57,76,87,88,99], 3) == -4
def test2():
assert candidate([111,121,3,4000,5,6], 2) == 0
def test3():
assert candidate([11,21,3,90,5,6,7,8,9], 4) == 125
def test4():
assert candidate([111,21,3,4000,5,6,7,8,9], 4) == 24, "This prints if ... |
HumanEval/123 |
def get_odd_collatz(n):
"""
Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
prev... | if n%2==0:
odd_collatz = []
else:
odd_collatz = [n]
while n > 1:
if n % 2 == 0:
n = n/2
else:
n = n*3 + 1
if n%2 == 1:
odd_collatz.append(int(n))
return sorted(odd_collatz)
| candidate = get_odd_collatz
def test1():
assert candidate(14) == [1, 5, 7, 11, 13, 17]
def test2():
assert candidate(5) == [1, 5]
def test3():
assert candidate(12) == [1, 3, 5], "This prints if this assert fails 1 (good for debugging!)"
def test4():
assert candidate(1) == [1], "This prints if this a... |
HumanEval/124 |
def valid_date(date):
"""You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31... | try:
date = date.strip()
month, day, year = date.split('-')
month, day, year = int(month), int(day), int(year)
if month < 1 or month > 12:
return False
if month in [1,3,5,7,8,10,12] and day < 1 or day > 31:
return False
if month in [4,6,9,11] a... | candidate = valid_date
def test1():
assert candidate('03-11-2000') == True
def test2():
assert candidate('15-01-2012') == False
def test3():
assert candidate('04-0-2040') == False
def test4():
assert candidate('06-04-2020') == True
def test5():
assert candidate('01-01-2007') == True
def test6(... |
HumanEval/125 |
def split_words(txt):
'''
Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('... | if " " in txt:
return txt.split()
elif "," in txt:
return txt.replace(',',' ').split()
else:
return len([i for i in txt if i.islower() and ord(i)%2 == 0])
| candidate = split_words
def test1():
assert candidate("Hello world!") == ["Hello","world!"]
def test2():
assert candidate("Hello,world!") == ["Hello","world!"]
def test3():
assert candidate("Hello world,!") == ["Hello","world,!"]
def test4():
assert candidate("Hello,Hello,world !") == ["Hello,Hello,... |
HumanEval/126 |
def is_sorted(lst):
'''
Given a list of numbers, return whether or not they are sorted
in ascending order. If list has more than 1 duplicate of the same
number, return False. Assume no negative numbers and only integers.
Examples
is_sorted([5]) ➞ True
is_sorted([1, 2, 3, 4, 5]) ➞ True
... | count_digit = dict([(i, 0) for i in lst])
for i in lst:
count_digit[i]+=1
if any(count_digit[i] > 2 for i in lst):
return False
if all(lst[i-1] <= lst[i] for i in range(1, len(lst))):
return True
else:
return False
| candidate = is_sorted
def test1():
assert candidate([5]) == True
def test2():
assert candidate([1, 2, 3, 4, 5]) == True
def test3():
assert candidate([1, 3, 2, 4, 5]) == False
def test4():
assert candidate([1, 2, 3, 4, 5, 6]) == True
def test5():
assert candidate([1, 2, 3, 4, 5, 6, 7]) == True
... |
HumanEval/127 |
def intersection(interval1, interval2):
"""You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is ass... | def is_prime(num):
if num == 1 or num == 0:
return False
if num == 2:
return True
for i in range(2, num):
if num%i == 0:
return False
return True
l = max(interval1[0], interval2[0])
r = min(interval1[1], interval2[1])
l... | candidate = intersection
def test1():
assert candidate((1, 2), (2, 3)) == "NO"
def test2():
assert candidate((-1, 1), (0, 4)) == "NO"
def test3():
assert candidate((-3, -1), (-5, 5)) == "YES"
def test4():
assert candidate((-2, 2), (-4, 0)) == "YES"
def test5():
assert candidate((-11, 2), (-1, -... |
HumanEval/128 |
def prod_signs(arr):
"""
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return None for empty arr.
Example:
>>> prod_signs([1, 2, 2, -4]) == -9
... | if not arr: return None
prod = 0 if 0 in arr else (-1) ** len(list(filter(lambda x: x < 0, arr)))
return prod * sum([abs(i) for i in arr])
| candidate = prod_signs
def test1():
assert True, "This prints if this assert fails 1 (good for debugging!)"
def test2():
assert candidate([1, 2, 2, -4]) == -9
def test3():
assert candidate([0, 1]) == 0
def test4():
assert candidate([1, 1, 1, 2, 3, -1, 1]) == -10
def test5():
assert candidate([]... |
HumanEval/129 |
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You... | n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i !... | candidate = minPath
def test1():
assert candidate([[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3) == [1, 2, 1]
def test2():
assert candidate([[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1) == [1]
def test3():
assert candidate([[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4) == [1, 2, 1, 2]
def test4():
... |
HumanEval/130 |
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + ... | if n == 0:
return [1]
my_tri = [1, 3]
for i in range(2, n + 1):
if i % 2 == 0:
my_tri.append(i / 2 + 1)
else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
| candidate = tri
def test1():
assert candidate(3) == [1, 3, 2.0, 8.0]
def test2():
assert candidate(4) == [1, 3, 2.0, 8.0, 3.0]
def test3():
assert candidate(5) == [1, 3, 2.0, 8.0, 3.0, 15.0]
def test4():
assert candidate(6) == [1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]
def test5():
assert candidate(7) ==... |
HumanEval/131 |
def digits(n):
"""Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(1) == 1
digits(4) == 0
digits(235) == 15
"""
| product = 1
odd_count = 0
for digit in str(n):
int_digit = int(digit)
if int_digit%2 == 1:
product= product*int_digit
odd_count+=1
if odd_count ==0:
return 0
else:
return product
| candidate = digits
def test1():
assert candidate(5) == 5
def test2():
assert candidate(54) == 5
def test3():
assert candidate(120) ==1
def test4():
assert candidate(5014) == 5
def test5():
assert candidate(98765) == 315
def test6():
assert candidate(5576543) == 2625
def test7():
asser... |
HumanEval/132 |
def is_nested(string):
'''
Create a function that takes a string as input which contains only square brackets.
The function should return True if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
is_nested('[[]]') ➞ True
is_nested('[... | opening_bracket_index = []
closing_bracket_index = []
for i in range(len(string)):
if string[i] == '[':
opening_bracket_index.append(i)
else:
closing_bracket_index.append(i)
closing_bracket_index.reverse()
cnt = 0
i = 0
l = len(closing_bracket_index)
... | candidate = is_nested
def test1():
assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)"
def test2():
assert candidate('[]]]]]]][[[[[]') == False
def test3():
assert candidate('[][]') == False
def test4():
assert candidate(('[]')) == False
def test5():
ass... |
HumanEval/133 |
def sum_squares(lst):
"""You are given a list of numbers.
You need to return the sum of squared numbers in the given list,
round each element in the list to the upper int(Ceiling) first.
Examples:
For lst = [1,2,3] the output should be 14
For lst = [1,4,9] the output should be 98
For lst =... | import math
squared = 0
for i in lst:
squared += math.ceil(i)**2
return squared
| candidate = sum_squares
def test1():
assert candidate([1,2,3])==14, "This prints if this assert fails 1 (good for debugging!)"
def test2():
assert candidate([1.0,2,3])==14, "This prints if this assert fails 1 (good for debugging!)"
def test3():
assert candidate([1,3,5,7])==84, "This prints if this assert... |
HumanEval/134 |
def check_if_last_char_is_a_letter(txt):
'''
Create a function that returns True if the last character
of a given string is an alphabetical character and is not
a part of a word, and False otherwise.
Note: "word" is a group of characters separated by space.
Examples:
check_if_last_char_is_... |
check = txt.split(' ')[-1]
return True if len(check) == 1 and (97 <= ord(check.lower()) <= 122) else False
| candidate = check_if_last_char_is_a_letter
def test1():
assert candidate("apple") == False
def test2():
assert candidate("apple pi e") == True
def test3():
assert candidate("eeeee") == False
def test4():
assert candidate("A") == True
def test5():
assert candidate("Pumpkin pie ") == False
def t... |
HumanEval/135 |
def can_arrange(arr):
"""Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
can_arrange([1,2,4,3,5]) =... | ind=-1
i=1
while i<len(arr):
if arr[i]<arr[i-1]:
ind=i
i+=1
return ind
| candidate = can_arrange
def test1():
assert candidate([1,2,4,3,5])==3
def test2():
assert candidate([1,2,4,5])==-1
def test3():
assert candidate([1,4,2,5,6,7,8,9,10])==2
def test4():
assert candidate([4,8,5,7,3])==4
def test5():
assert candidate([])==-1 |
HumanEval/136 |
def largest_smallest_integers(lst):
'''
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in a list.
If there is no negative or positive integers, return them as None.
Examples:
largest_smallest_intege... | smallest = list(filter(lambda x: x < 0, lst))
largest = list(filter(lambda x: x > 0, lst))
return (max(smallest) if smallest else None, min(largest) if largest else None)
| candidate = largest_smallest_integers
def test1():
assert candidate([2, 4, 1, 3, 5, 7]) == (None, 1)
def test2():
assert candidate([2, 4, 1, 3, 5, 7, 0]) == (None, 1)
def test3():
assert candidate([1, 3, 2, 4, 5, 6, -2]) == (-2, 1)
def test4():
assert candidate([4, 5, 3, 6, 2, 7, -7]) == (-7, 2)
de... |
HumanEval/137 |
def compare_one(a, b):
"""
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return None if the values are equal.
Note: If a real number is represented as a string, the floating point might be . or ,
... | temp_a, temp_b = a, b
if isinstance(temp_a, str): temp_a = temp_a.replace(',','.')
if isinstance(temp_b, str): temp_b = temp_b.replace(',','.')
if float(temp_a) == float(temp_b): return None
return a if float(temp_a) > float(temp_b) else b
| candidate = compare_one
def test1():
assert candidate(1, 2) == 2
def test2():
assert candidate(1, 2.5) == 2.5
def test3():
assert candidate(2, 3) == 3
def test4():
assert candidate(5, 6) == 6
def test5():
assert candidate(1, "2,3") == "2,3"
def test6():
assert candidate("5,1", "6") == "6"
... |
HumanEval/138 |
def is_equal_to_sum_even(n):
"""Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
is_equal_to_sum_even(4) == False
is_equal_to_sum_even(6) == False
is_equal_to_sum_even(8) == True
"""
| return n%2 == 0 and n >= 8
| candidate = is_equal_to_sum_even
def test1():
assert candidate(4) == False
def test2():
assert candidate(6) == False
def test3():
assert candidate(8) == True
def test4():
assert candidate(10) == True
def test5():
assert candidate(11) == False
def test6():
assert candidate(12) == True
def ... |
HumanEval/139 |
def special_factorial(n):
"""The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
where n > 0
For example:
>>> special_factorial(4)
288
The function will receive an integer as input and should return the special
factorial of this integer.
... | fact_i = 1
special_fact = 1
for i in range(1, n+1):
fact_i *= i
special_fact *= fact_i
return special_fact
| candidate = special_factorial
def test1():
assert candidate(4) == 288, "Test 4"
def test2():
assert candidate(5) == 34560, "Test 5"
def test3():
assert candidate(7) == 125411328000, "Test 7"
def test4():
assert candidate(1) == 1, "Test 1" |
HumanEval/140 |
def fix_spaces(text):
"""
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fix_spaces("Example") == "Example"
fix_spaces("Example 1") == "Example_1"
fix_spaces(" Example 2")... | new_text = ""
i = 0
start, end = 0, 0
while i < len(text):
if text[i] == " ":
end += 1
else:
if end - start > 2:
new_text += "-"+text[i]
elif end - start > 0:
new_text += "_"*(end - start)+text[i]
else:
... | candidate = fix_spaces
def test1():
assert candidate("Example") == "Example", "This prints if this assert fails 1 (good for debugging!)"
def test2():
assert candidate("Mudasir Hanif ") == "Mudasir_Hanif_", "This prints if this assert fails 2 (good for debugging!)"
def test3():
assert candidate("Yellow Ye... |
HumanEval/141 |
def file_name_check(file_name):
"""Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be mo... | suf = ['txt', 'exe', 'dll']
lst = file_name.split(sep='.')
if len(lst) != 2:
return 'No'
if not lst[1] in suf:
return 'No'
if len(lst[0]) == 0:
return 'No'
if not lst[0][0].isalpha():
return 'No'
t = len([x for x in lst[0] if x.isdigit()])
if t > 3:
... | candidate = file_name_check
def test1():
assert candidate("example.txt") == 'Yes'
def test2():
assert candidate("1example.dll") == 'No'
def test3():
assert candidate('s1sdf3.asd') == 'No'
def test4():
assert candidate('K.dll') == 'Yes'
def test5():
assert candidate('MY16FILE3.exe') == 'Yes'
de... |
HumanEval/142 |
def sum_squares(lst):
""""
This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a
multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not
change the e... | result =[]
for i in range(len(lst)):
if i %3 == 0:
result.append(lst[i]**2)
elif i % 4 == 0 and i%3 != 0:
result.append(lst[i]**3)
else:
result.append(lst[i])
return sum(result)
| candidate = sum_squares
def test1():
assert candidate([1,2,3]) == 6
def test2():
assert candidate([1,4,9]) == 14
def test3():
assert candidate([]) == 0
def test4():
assert candidate([1,1,1,1,1,1,1,1,1]) == 9
def test5():
assert candidate([-1,-1,-1,-1,-1,-1,-1,-1,-1]) == -3
def test6():
ass... |
HumanEval/143 |
def words_in_sentence(sentence):
"""
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new stri... | new_lst = []
for word in sentence.split():
flg = 0
if len(word) == 1:
flg = 1
for i in range(2, len(word)):
if len(word)%i == 0:
flg = 1
if flg == 0 or len(word) == 2:
new_lst.append(word)
return " ".join(new_lst)
| candidate = words_in_sentence
def test1():
assert candidate("This is a test") == "is"
def test2():
assert candidate("lets go for swimming") == "go for"
def test3():
assert candidate("there is no place available here") == "there is no place"
def test4():
assert candidate("Hi I am Hussein") == "Hi am ... |
HumanEval/144 |
def simplify(x, n):
"""Your task is to implement a function that will simplify the expression
x * n. The function returns True if x * n evaluates to a whole number and False
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where ... | a, b = x.split("/")
c, d = n.split("/")
numerator = int(a) * int(c)
denom = int(b) * int(d)
if (numerator/denom == int(numerator/denom)):
return True
return False
| candidate = simplify
def test1():
assert candidate("1/5", "5/1") == True, 'test1'
def test2():
assert candidate("1/6", "2/1") == False, 'test2'
def test3():
assert candidate("5/1", "3/1") == True, 'test3'
def test4():
assert candidate("7/10", "10/2") == False, 'test4'
def test5():
assert candid... |
HumanEval/145 |
def order_by_points(nums):
"""
Write a function which sorts the given list of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original list.
For example:
>>> order_by_poi... | def digits_sum(n):
neg = 1
if n < 0: n, neg = -1 * n, -1
n = [int(i) for i in str(n)]
n[0] = n[0] * neg
return sum(n)
return sorted(nums, key=digits_sum)
| candidate = order_by_points
def test1():
assert candidate([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
def test2():
assert candidate([1234,423,463,145,2,423,423,53,6,37,3457,3,56,0,46]) == [0, 2, 3, 6, 53, 423, 423, 423, 1234, 145, 37, 46, 56, 463, 3457]
def test3():
assert candidate([]) == []
def te... |
HumanEval/146 |
def specialFilter(nums):
"""Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter([15, -73, 14, -15]) => 1
specialFilter(... |
count = 0
for num in nums:
if num > 10:
odd_digits = (1, 3, 5, 7, 9)
number_as_string = str(num)
if int(number_as_string[0]) in odd_digits and int(number_as_string[-1]) in odd_digits:
count += 1
return count
| candidate = specialFilter
def test1():
assert candidate([5, -2, 1, -5]) == 0
def test2():
assert candidate([15, -73, 14, -15]) == 1
def test3():
assert candidate([33, -2, -3, 45, 21, 109]) == 2
def test4():
assert candidate([43, -12, 93, 125, 121, 109]) == 4
def test5():
assert candidate([71,... |
HumanEval/147 |
def get_max_triples(n):
"""
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
... | A = [i*i - i + 1 for i in range(1,n+1)]
ans = []
for i in range(n):
for j in range(i+1,n):
for k in range(j+1,n):
if (A[i]+A[j]+A[k])%3 == 0:
ans += [(A[i],A[j],A[k])]
return len(ans)
| candidate = get_max_triples
def test1():
assert candidate(5) == 1
def test2():
assert candidate(6) == 4
def test3():
assert candidate(10) == 36
def test4():
assert candidate(100) == 53361 |
HumanEval/148 |
def bf(planet1, planet2):
'''
There are eight planets in our solar system: the closerst to the Sun
is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn,
Uranus, Neptune.
Write a function that takes two planet names as strings planet1 and planet2.
The function should return a ... | planet_names = ("Mercury", "Venus", "Earth", "Mars", "Jupiter", "Saturn", "Uranus", "Neptune")
if planet1 not in planet_names or planet2 not in planet_names or planet1 == planet2:
return ()
planet1_index = planet_names.index(planet1)
planet2_index = planet_names.index(planet2)
if planet1_ind... | candidate = bf
def test1():
assert candidate("Jupiter", "Neptune") == ("Saturn", "Uranus"), "First test error: " + str(len(candidate("Jupiter", "Neptune")))
def test2():
assert candidate("Earth", "Mercury") == ("Venus",), "Second test error: " + str(candidate("Earth", "Mercury"))
def test3():
ass... |
HumanEval/149 |
def sorted_list_sum(lst):
"""Write a function that accepts a list of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted list with a sorted order,
The list is always a list of strings and never an array of numbers,
and it may contain duplicates.
T... | lst.sort()
new_lst = []
for i in lst:
if len(i)%2 == 0:
new_lst.append(i)
return sorted(new_lst, key=len)
| candidate = sorted_list_sum
def test1():
assert candidate(["aa", "a", "aaa"]) == ["aa"]
def test2():
assert candidate(["school", "AI", "asdf", "b"]) == ["AI", "asdf", "school"]
def test3():
assert candidate(["d", "b", "c", "a"]) == []
def test4():
assert candidate(["d", "dcba", "abcd", "a"]) == ["ab... |
HumanEval/150 |
def x_or_y(n, x, y):
"""A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
for x_or_y(7, 34, 12) == 34
for x_or_y(15, 8, 5) == 5
"""
| if n == 1:
return y
for i in range(2, n):
if n % i == 0:
return y
break
else:
return x
| candidate = x_or_y
def test1():
assert candidate(7, 34, 12) == 34
def test2():
assert candidate(15, 8, 5) == 5
def test3():
assert candidate(3, 33, 5212) == 33
def test4():
assert candidate(1259, 3, 52) == 3
def test5():
assert candidate(7919, -1, 12) == -1
def test6():
assert candidate(36... |
HumanEval/151 |
def double_the_difference(lst):
'''
Given a list of numbers, return the sum of squares of the numbers
in the list that are odd. Ignore numbers that are negative or not integers.
double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10
double_the_difference([-1, -2, 0]) == 0
double_the_dif... | return sum([i**2 for i in lst if i > 0 and i%2!=0 and "." not in str(i)])
| candidate = double_the_difference
def test1():
assert candidate([]) == 0 , "This prints if this assert fails 1 (good for debugging!)"
def test2():
assert candidate([5, 4]) == 25 , "This prints if this assert fails 2 (good for debugging!)"
def test3():
assert candidate([0.1, 0.2, 0.3]) == 0 , "This prints... |
HumanEval/152 |
def compare(game,guess):
"""I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number... | return [abs(x-y) for x,y in zip(game,guess)]
| candidate = compare
def test1():
assert candidate([1,2,3,4,5,1],[1,2,3,4,2,-2])==[0,0,0,0,3,3], "This prints if this assert fails 1 (good for debugging!)"
def test2():
assert candidate([0,0,0,0,0,0],[0,0,0,0,0,0])==[0,0,0,0,0,0], "This prints if this assert fails 1 (good for debugging!)"
def test3():
ass... |
HumanEval/153 |
def Strongest_Extension(class_name, extensions):
"""You will be given the name of a class (a string) and a list of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extens... | strong = extensions[0]
my_val = len([x for x in extensions[0] if x.isalpha() and x.isupper()]) - len([x for x in extensions[0] if x.isalpha() and x.islower()])
for s in extensions:
val = len([x for x in s if x.isalpha() and x.isupper()]) - len([x for x in s if x.isalpha() and x.islower()])
i... | candidate = Strongest_Extension
def test1():
assert candidate('Watashi', ['tEN', 'niNE', 'eIGHt8OKe']) == 'Watashi.eIGHt8OKe'
def test2():
assert candidate('Boku123', ['nani', 'NazeDa', 'YEs.WeCaNe', '32145tggg']) == 'Boku123.YEs.WeCaNe'
def test3():
assert candidate('__YESIMHERE', ['t', 'eMptY', 'nothin... |
HumanEval/154 |
def cycpattern_check(a , b):
"""You are given 2 words. You need to return True if the second word or any of its rotations is a substring in the first word
cycpattern_check("abcd","abd") => False
cycpattern_check("hello","ell") => True
cycpattern_check("whassup","psus") => False
cycpattern_check("ab... | l = len(b)
pat = b + b
for i in range(len(a) - l + 1):
for j in range(l + 1):
if a[i:i+l] == pat[j:j+l]:
return True
return False
| candidate = cycpattern_check
def test1():
assert candidate("xyzw","xyw") == False , "test #0"
def test2():
assert candidate("yello","ell") == True , "test #1"
def test3():
assert candidate("whattup","ptut") == False , "test #2"
def test4():
assert candidate("efef","fee") == True , "test #3"
def... |
HumanEval/155 |
def even_odd_count(num):
"""Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
even_odd_count(-12) ==> (1, 1)
even_odd_count(123) ==> (1, 2)
"""
| even_count = 0
odd_count = 0
for i in str(abs(num)):
if int(i)%2==0:
even_count +=1
else:
odd_count +=1
return (even_count, odd_count)
| candidate = even_odd_count
def test1():
assert candidate(7) == (0, 1)
def test2():
assert candidate(-78) == (1, 1)
def test3():
assert candidate(3452) == (2, 2)
def test4():
assert candidate(346211) == (3, 3)
def test5():
assert candidate(-345821) == (3, 3)
def test6():
assert candidate(-2... |
HumanEval/156 |
def int_to_mini_roman(number):
"""
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
>>> int_to_mini_roman(19) == 'xix'
>>> int_to_mini_roman(152) == 'clii'
>>> int_to_mini_roman(426) == 'cdxx... | num = [1, 4, 5, 9, 10, 40, 50, 90,
100, 400, 500, 900, 1000]
sym = ["I", "IV", "V", "IX", "X", "XL",
"L", "XC", "C", "CD", "D", "CM", "M"]
i = 12
res = ''
while number:
div = number // num[i]
number %= num[i]
while div:
res += sym[i... | candidate = int_to_mini_roman
def test1():
assert candidate(19) == 'xix'
def test2():
assert candidate(152) == 'clii'
def test3():
assert candidate(251) == 'ccli'
def test4():
assert candidate(426) == 'cdxxvi'
def test5():
assert candidate(500) == 'd'
def test6():
assert candidate(1) == 'i... |
HumanEval/157 |
def right_angle_triangle(a, b, c):
'''
Given the lengths of the three sides of a triangle. Return True if the three
sides form a right-angled triangle, False otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
right_angle_triangle(3, 4,... | return a*a == b*b + c*c or b*b == a*a + c*c or c*c == a*a + b*b
| candidate = right_angle_triangle
def test1():
assert candidate(3, 4, 5) == True, "This prints if this assert fails 1 (good for debugging!)"
def test2():
assert candidate(1, 2, 3) == False
def test3():
assert candidate(10, 6, 8) == True
def test4():
assert candidate(2, 2, 2) == False
def test5():
... |
HumanEval/158 |
def find_max(words):
"""Write a function that accepts a list of strings.
The list contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
find_max(["... | return sorted(words, key = lambda x: (-len(set(x)), x))[0]
| candidate = find_max
def test1():
assert (candidate(["name", "of", "string"]) == "string"), "t1"
def test2():
assert (candidate(["name", "enam", "game"]) == "enam"), 't2'
def test3():
assert (candidate(["aaaaaaa", "bb", "cc"]) == "aaaaaaa"), 't3'
def test4():
assert (candidate(["abc", "cba"]) == "ab... |
HumanEval/159 |
def eat(number, need, remaining):
"""
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the... | if(need <= remaining):
return [ number + need , remaining-need ]
else:
return [ number + remaining , 0]
| candidate = eat
def test1():
assert True, "This prints if this assert fails 1 (good for debugging!)"
def test2():
assert candidate(5, 6, 10) == [11, 4], "Error"
def test3():
assert candidate(4, 8, 9) == [12, 1], "Error"
def test4():
assert candidate(1, 10, 10) == [11, 0], "Error"
def test5():
a... |
HumanEval/160 |
def do_algebra(operator, operand):
"""
Given two lists operator, and operand. The first list has basic algebra operations, and
the second list is a list of integers. Use the two given lists to build the algebric
expression and return the evaluation of this expression.
The basic algebra operation... | expression = str(operand[0])
for oprt, oprn in zip(operator, operand[1:]):
expression+= oprt + str(oprn)
return eval(expression)
| candidate = do_algebra
def test1():
assert candidate(['**', '*', '+'], [2, 3, 4, 5]) == 37
def test2():
assert candidate(['+', '*', '-'], [2, 3, 4, 5]) == 9
def test3():
assert candidate(['//', '*'], [7, 3, 4]) == 8, "This prints if this assert fails 1 (good for debugging!)"
def test4():
assert True... |
HumanEval/161 |
def solve(s):
"""You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve("1234") = "4321"
solve("... | flg = 0
idx = 0
new_str = list(s)
for i in s:
if i.isalpha():
new_str[idx] = i.swapcase()
flg = 1
idx += 1
s = ""
for i in new_str:
s += i
if flg == 0:
return s[len(s)::-1]
return s
| candidate = solve
def test1():
assert candidate("AsDf") == "aSdF"
def test2():
assert candidate("1234") == "4321"
def test3():
assert candidate("ab") == "AB"
def test4():
assert candidate("#a@C") == "#A@c"
def test5():
assert candidate("#AsdfW^45") == "#aSDFw^45"
def test6():
assert candid... |
HumanEval/162 |
def string_to_md5(text):
"""
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return None.
>>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'
"""
| import hashlib
return hashlib.md5(text.encode('ascii')).hexdigest() if text else None
| candidate = string_to_md5
def test1():
assert candidate('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'
def test2():
assert candidate('') == None
def test3():
assert candidate('A B C') == '0ef78513b0cb8cef12743f5aeb35f888'
def test4():
assert candidate('password') == '5f4dcc3b5aa765d61d8327deb8... |
HumanEval/163 |
def generate_integers(a, b):
"""
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generate_integers(2, 8) => [2, 4, 6, 8]
generate_integers(8, 2) => [2, 4, 6, 8]
generate_integers(10, 14) => []
"""
| lower = max(2, min(a, b))
upper = min(8, max(a, b))
return [i for i in range(lower, upper+1) if i % 2 == 0]
| candidate = generate_integers
def test1():
assert candidate(2, 10) == [2, 4, 6, 8], "Test 1"
def test2():
assert candidate(10, 2) == [2, 4, 6, 8], "Test 2"
def test3():
assert candidate(132, 2) == [2, 4, 6, 8], "Test 3"
def test4():
assert candidate(17,89) == [], "Test 4"
def test5():
assert Tr... |
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