post_href stringlengths 57 213 | python_solutions stringlengths 71 22.3k | slug stringlengths 3 77 | post_title stringlengths 1 100 | user stringlengths 3 29 | upvotes int64 -20 1.2k | views int64 0 60.9k | problem_title stringlengths 3 77 | number int64 1 2.48k | acceptance float64 0.14 0.91 | difficulty stringclasses 3
values | __index_level_0__ int64 0 34k |
|---|---|---|---|---|---|---|---|---|---|---|---|
https://leetcode.com/problems/number-of-beautiful-partitions/discuss/2846874/Python-oror-DP%2BMemoization-oror-Explained | class Solution:
def beautifulPartitions(self, s: str, k: int, min_len: int) -> int:
n=len(s)
mod=10**9+7
prime=set(['2','3','5','7'])
if s[0] not in prime or s[-1] in prime: return 0
arr=[]
last,i=0,1
while i<n:
if (i==n-1) or (s[i] not in prime an... | number-of-beautiful-partitions | Python || DP+Memoization || Explained | ketan_raut | 0 | 5 | number of beautiful partitions | 2,478 | 0.294 | Hard | 34,000 |
https://leetcode.com/problems/number-of-beautiful-partitions/discuss/2835340/My-Python3-solution | class Solution:
def beautifulPartitions(self, s: str, k: int, minLength: int) -> int:
n, primes, mod = len(s), set('2357'), (10 ** 9) + 7
@cache
def dp(i, at_start, k):
if i == n: return int(k == 0)
if i > n or k == 0 or s[i] not in primes and at_start: return 0
... | number-of-beautiful-partitions | My Python3 solution | Chiki1601 | 0 | 7 | number of beautiful partitions | 2,478 | 0.294 | Hard | 34,001 |
https://leetcode.com/problems/number-of-beautiful-partitions/discuss/2834324/Python3-bottom-up-dp | class Solution:
def beautifulPartitions(self, s: str, k: int, minLength: int) -> int:
prime = "2357"
dp = [[0]*(len(s)+1) for _ in range(k)]
if s[0] in prime and s[-1] not in prime:
for j in range(len(s)+1): dp[0][j] = 1
for i in range(1, k):
for j i... | number-of-beautiful-partitions | [Python3] bottom-up dp | ye15 | 0 | 14 | number of beautiful partitions | 2,478 | 0.294 | Hard | 34,002 |
https://leetcode.com/problems/number-of-beautiful-partitions/discuss/2832507/Over-optimized-O(nk)-dp-solution-~400-ms | class Solution:
def beautifulPartitions(self, s: str, k: int, minLength: int) -> int:
mod = 10 ** 9 + 7
n = len(s)
prime = {'2', '3', '5', '7'}
if s[0] in prime and s[-1] not in prime:
op = []
for i in range(1, n - 1):
if s[i] not in prime and ... | number-of-beautiful-partitions | Over-optimized O(nk) dp solution, ~400 ms | chuan-chih | 0 | 21 | number of beautiful partitions | 2,478 | 0.294 | Hard | 34,003 |
https://leetcode.com/problems/number-of-beautiful-partitions/discuss/2832418/python3-DP-%2B-accumulative-sum-O(n*k) | class Solution:
def beautifulPartitions(self, s: str, k: int, minLength: int) -> int:
primes = {'2','3','5','7'}
# prunning
if len(s) < k*minLength or s[0] not in primes or s[-1] in primes:
return 0
dd_int = functools.partial(defaultdict, int)
dp = defaultdict(dd... | number-of-beautiful-partitions | [python3] DP + accumulative sum O(n*k) | hieuvpm | 0 | 18 | number of beautiful partitions | 2,478 | 0.294 | Hard | 34,004 |
https://leetcode.com/problems/number-of-beautiful-partitions/discuss/2832064/O(nk)-time-complexity-O(n)-space-complexity-DP | class Solution:
def beautifulPartitions(self, s: str, k: int, minLength: int) -> int:
n = len(s)
mod = 10 ** 9 + 7
if k * minLength > n:
return 0
dp = [[0] * (2) for _ in range(n+1)]
dp[0][0] = 1
prime_indices = [i + 1 for i in range(n) if s[i] in '2357'... | number-of-beautiful-partitions | O(nk) time complexity, O(n) space complexity DP | zhanghaotian19 | 0 | 20 | number of beautiful partitions | 2,478 | 0.294 | Hard | 34,005 |
https://leetcode.com/problems/number-of-beautiful-partitions/discuss/2831967/Fastest-Python-solution-so-far | class Solution:
def beautifulPartitions(self, s: str, k: int, minLength: int) -> int:
s=list(s)
l0=len(s)
prime={'2', '3', '5', '7'}
for i in range(l0):
s[i]=s[i] in prime
if not s[0]:
return 0
if s[-1]:
return 0
p=10**9+7
... | number-of-beautiful-partitions | Fastest Python solution so far | mbeceanu | 0 | 40 | number of beautiful partitions | 2,478 | 0.294 | Hard | 34,006 |
Subsets and Splits
Top 2 Solutions by Upvotes
Identifies the top 2 highest upvoted Python solutions for each problem, providing insight into popular approaches.