input stringlengths 122 2.7k | output stringlengths 24 805 |
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[INST] Here is a database schema:
category :
category_id [ INTEGER ] primary_key
name [ TEXT ]
last_update [ DATETIME ]
film :
film_id [ INTEGER ] primary_key
title [ TEXT ]
description [ TEXT ]
release_year [ TEXT ]
language_id [ INTEGER ]
original_language_id [ INTEGER ]
rental_duration [ INTEGER ]
rental_rate [ REAL... | SELECT T1.title FROM film AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id WHERE T3.name = 'Horror'; |
[INST] Here is a database schema:
actor :
actor_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
last_update [ DATETIME ]
film :
film_id [ INTEGER ] primary_key
title [ TEXT ]
description [ TEXT ]
release_year [ TEXT ]
language_id [ INTEGER ]
original_language_id [ INTEGER ]
rental_duration [ INTEGER ]... | SELECT T1.last_name FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T3.rating = 'NC-17'; |
[INST] Here is a database schema:
actor :
actor_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
last_update [ DATETIME ]
film :
film_id [ INTEGER ] primary_key
title [ TEXT ]
description [ TEXT ]
release_year [ TEXT ]
language_id [ INTEGER ]
original_language_id [ INTEGER ]
rental_duration [ INTEGER ]... | SELECT AVG(T3.rental_rate) FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T1.first_name = 'LUCILLE' AND T1.last_name = 'TRACY'; |
[INST] Here is a database schema:
film :
film_id [ INTEGER ] primary_key
title [ TEXT ]
description [ TEXT ]
release_year [ TEXT ]
language_id [ INTEGER ]
original_language_id [ INTEGER ]
rental_duration [ INTEGER ]
rental_rate [ REAL ]
length [ INTEGER ]
replacement_cost [ REAL ]
rating [ TEXT ]
special_features [ TEX... | SELECT COUNT(film_id) FROM film WHERE length BETWEEN 100 AND 110; |
[INST] Here is a database schema:
actor :
actor_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
last_update [ DATETIME ]
Please write me a SQL statement that answers the following question: List down the actor ID of actors with Dee as their last name. [/INST] [/INST] | SELECT actor_id FROM actor WHERE last_name = 'Dee'; |
[INST] Here is a database schema:
customer :
customer_id [ INTEGER ] primary_key
store_id [ INTEGER ]
first_name [ TEXT ]
last_name [ TEXT ]
email [ TEXT ]
address_id [ INTEGER ]
active [ INTEGER ]
create_date [ DATETIME ]
last_update [ DATETIME ]
Please write me a SQL statement that answers the following question: Am... | SELECT COUNT(customer_id) FROM customer WHERE first_name = 'Nina' AND active = 1; |
[INST] Here is a database schema:
film :
film_id [ INTEGER ] primary_key
title [ TEXT ]
description [ TEXT ]
release_year [ TEXT ]
language_id [ INTEGER ]
original_language_id [ INTEGER ]
rental_duration [ INTEGER ]
rental_rate [ REAL ]
length [ INTEGER ]
replacement_cost [ REAL ]
rating [ TEXT ]
special_features [ TEX... | SELECT COUNT(T1.film_id) FROM film AS T1 INNER JOIN inventory AS T2 ON T1.film_id = T2.film_id WHERE T2.store_id = 2 AND T1.rating = 'R'; |
[INST] Here is a database schema:
actor :
actor_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
last_update [ DATETIME ]
film :
film_id [ INTEGER ] primary_key
title [ TEXT ]
description [ TEXT ]
release_year [ TEXT ]
language_id [ INTEGER ]
original_language_id [ INTEGER ]
rental_duration [ INTEGER ]... | SELECT T4.store_id FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id INNER JOIN inventory AS T4 ON T3.film_id = T4.film_id WHERE T3.length < 100 AND T1.first_name = 'Reese' AND T1.last_name = 'West'; |
[INST] Here is a database schema:
actor :
actor_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
last_update [ DATETIME ]
film :
film_id [ INTEGER ] primary_key
title [ TEXT ]
description [ TEXT ]
release_year [ TEXT ]
language_id [ INTEGER ]
original_language_id [ INTEGER ]
rental_duration [ INTEGER ]... | SELECT T3.title FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T1.first_name = 'Nick' AND T1.last_name = 'Wahlberg' ORDER BY T3.rental_rate DESC LIMIT 1; |
[INST] Here is a database schema:
actor :
actor_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
last_update [ DATETIME ]
film :
film_id [ INTEGER ] primary_key
title [ TEXT ]
description [ TEXT ]
release_year [ TEXT ]
language_id [ INTEGER ]
original_language_id [ INTEGER ]
rental_duration [ INTEGER ]... | SELECT T3.title FROM film_actor AS T1 INNER JOIN actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T1.film_id = T3.film_id WHERE T2.first_name = 'Russell' AND T2.last_name = 'Close'; |
[INST] Here is a database schema:
film :
film_id [ INTEGER ] primary_key
title [ TEXT ]
description [ TEXT ]
release_year [ TEXT ]
language_id [ INTEGER ]
original_language_id [ INTEGER ]
rental_duration [ INTEGER ]
rental_rate [ REAL ]
length [ INTEGER ]
replacement_cost [ REAL ]
rating [ TEXT ]
special_features [ TEX... | SELECT T2.store_id FROM film AS T1 INNER JOIN inventory AS T2 ON T1.film_id = T2.film_id WHERE T1.title = 'Amadeus Holy'; |
[INST] Here is a database schema:
actor :
actor_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
last_update [ DATETIME ]
film :
film_id [ INTEGER ] primary_key
title [ TEXT ]
description [ TEXT ]
release_year [ TEXT ]
language_id [ INTEGER ]
original_language_id [ INTEGER ]
rental_duration [ INTEGER ]... | SELECT COUNT(T1.film_id) FROM film_actor AS T1 INNER JOIN actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T1.film_id = T3.film_id WHERE T3.rental_rate = 2.99 AND T2.first_name = 'Nina' AND T2.last_name = 'Soto'; |
[INST] Here is a database schema:
actor :
actor_id [ INTEGER ] primary_key
first_name [ TEXT ]
last_name [ TEXT ]
last_update [ DATETIME ]
film :
film_id [ INTEGER ] primary_key
title [ TEXT ]
description [ TEXT ]
release_year [ TEXT ]
language_id [ INTEGER ]
original_language_id [ INTEGER ]
rental_duration [ INTEGER ]... | SELECT SUM(IIF(T4.film_id = 1, 1, 0)) - SUM(IIF(T4.film_id = 2, 1, 0)) AS diff FROM film_actor AS T1 INNER JOIN actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T1.film_id = T3.film_id INNER JOIN inventory AS T4 ON T3.film_id = T4.film_id WHERE T2.first_name = 'Reese' AND T2.last_name = 'West'; |
[INST] Here is a database schema:
address :
address_id [ INTEGER ] primary_key
address [ TEXT ]
address2 [ TEXT ]
district [ TEXT ]
city_id [ INTEGER ]
postal_code [ TEXT ]
phone [ TEXT ]
last_update [ DATETIME ]
Please write me a SQL statement that answers the following question: What is the postal code of the addres... | SELECT postal_code FROM address WHERE address = '692 Joliet Street'; |
[INST] Here is a database schema:
customer :
customer_id [ INTEGER ] primary_key
store_id [ INTEGER ]
first_name [ TEXT ]
last_name [ TEXT ]
email [ TEXT ]
address_id [ INTEGER ]
active [ INTEGER ]
create_date [ DATETIME ]
last_update [ DATETIME ]
Please write me a SQL statement that answers the following question: Ho... | SELECT COUNT(customer_id) FROM customer WHERE active = 1; |
[INST] Here is a database schema:
customer :
customer_id [ INTEGER ] primary_key
store_id [ INTEGER ]
first_name [ TEXT ]
last_name [ TEXT ]
email [ TEXT ]
address_id [ INTEGER ]
active [ INTEGER ]
create_date [ DATETIME ]
last_update [ DATETIME ]
Please write me a SQL statement that answers the following question: Am... | SELECT COUNT(customer_id) FROM customer WHERE active = 1 AND store_id = 1; |
[INST] Here is a database schema:
address :
address_id [ INTEGER ] primary_key
address [ TEXT ]
address2 [ TEXT ]
district [ TEXT ]
city_id [ INTEGER ]
postal_code [ TEXT ]
phone [ TEXT ]
last_update [ DATETIME ]
customer :
customer_id [ INTEGER ] primary_key
store_id [ INTEGER ]
first_name [ TEXT ]
last_name [ TEXT ]
... | SELECT T1.address FROM address AS T1 INNER JOIN customer AS T2 ON T1.address_id = T2.address_id WHERE T2.first_name = 'MARY' AND T2.last_name = 'SMITH'; |
[INST] Here is a database schema:
address :
address_id [ INTEGER ] primary_key
address [ TEXT ]
address2 [ TEXT ]
district [ TEXT ]
city_id [ INTEGER ]
postal_code [ TEXT ]
phone [ TEXT ]
last_update [ DATETIME ]
city :
city_id [ INTEGER ] primary_key
city [ TEXT ]
country_id [ INTEGER ]
last_update [ DATETIME ]
custom... | SELECT COUNT(T2.customer_id) FROM address AS T1 INNER JOIN customer AS T2 ON T1.address_id = T2.address_id INNER JOIN city AS T3 ON T1.city_id = T3.city_id WHERE T2.active = 1 AND T3.city = 'Arlington'; |
[INST] Here is a database schema:
address :
address_id [ INTEGER ] primary_key
address [ TEXT ]
address2 [ TEXT ]
district [ TEXT ]
city_id [ INTEGER ]
postal_code [ TEXT ]
phone [ TEXT ]
last_update [ DATETIME ]
city :
city_id [ INTEGER ] primary_key
city [ TEXT ]
country_id [ INTEGER ]
last_update [ DATETIME ]
countr... | SELECT T4.first_name, T4.last_name FROM address AS T1 INNER JOIN city AS T2 ON T1.city_id = T2.city_id INNER JOIN country AS T3 ON T2.country_id = T3.country_id INNER JOIN customer AS T4 ON T1.address_id = T4.address_id WHERE T3.country = 'Italy'; |
[INST] Here is a database schema:
address :
address_id [ INTEGER ] primary_key
address [ TEXT ]
address2 [ TEXT ]
district [ TEXT ]
city_id [ INTEGER ]
postal_code [ TEXT ]
phone [ TEXT ]
last_update [ DATETIME ]
city :
city_id [ INTEGER ] primary_key
city [ TEXT ]
country_id [ INTEGER ]
last_update [ DATETIME ]
countr... | SELECT T3.country FROM address AS T1 INNER JOIN city AS T2 ON T1.city_id = T2.city_id INNER JOIN country AS T3 ON T2.country_id = T3.country_id INNER JOIN customer AS T4 ON T1.address_id = T4.address_id WHERE T4.first_name = 'MARY' AND T4.last_name = 'SMITH'; |
[INST] Here is a database schema:
customer :
customer_id [ INTEGER ] primary_key
store_id [ INTEGER ]
first_name [ TEXT ]
last_name [ TEXT ]
email [ TEXT ]
address_id [ INTEGER ]
active [ INTEGER ]
create_date [ DATETIME ]
last_update [ DATETIME ]
payment :
payment_id [ INTEGER ] primary_key
customer_id [ INTEGER ]
sta... | SELECT T1.amount FROM payment AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = 'MARY' AND T2.last_name = 'SMITH' ORDER BY T1.amount DESC LIMIT 1; |
[INST] Here is a database schema:
customer :
customer_id [ INTEGER ] primary_key
store_id [ INTEGER ]
first_name [ TEXT ]
last_name [ TEXT ]
email [ TEXT ]
address_id [ INTEGER ]
active [ INTEGER ]
create_date [ DATETIME ]
last_update [ DATETIME ]
payment :
payment_id [ INTEGER ] primary_key
customer_id [ INTEGER ]
sta... | SELECT COUNT(T1.customer_id) FROM payment AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = 'MARY' AND T2.last_name = 'SMITH'; |
[INST] Here is a database schema:
customer :
customer_id [ INTEGER ] primary_key
store_id [ INTEGER ]
first_name [ TEXT ]
last_name [ TEXT ]
email [ TEXT ]
address_id [ INTEGER ]
active [ INTEGER ]
create_date [ DATETIME ]
last_update [ DATETIME ]
payment :
payment_id [ INTEGER ] primary_key
customer_id [ INTEGER ]
sta... | SELECT SUM(T1.amount) FROM payment AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = 'MARY' AND T2.last_name = 'SMITH'; |
[INST] Here is a database schema:
customer :
customer_id [ INTEGER ] primary_key
store_id [ INTEGER ]
first_name [ TEXT ]
last_name [ TEXT ]
email [ TEXT ]
address_id [ INTEGER ]
active [ INTEGER ]
create_date [ DATETIME ]
last_update [ DATETIME ]
payment :
payment_id [ INTEGER ] primary_key
customer_id [ INTEGER ]
sta... | SELECT COUNT(T1.customer_id) FROM payment AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = 'MARY' AND T2.last_name = 'SMITH' AND STRFTIME('%Y',T1.payment_date) = '2005' AND STRFTIME('%Y', T1.payment_date) = '6'; |
[INST] Here is a database schema:
customer :
customer_id [ INTEGER ] primary_key
store_id [ INTEGER ]
first_name [ TEXT ]
last_name [ TEXT ]
email [ TEXT ]
address_id [ INTEGER ]
active [ INTEGER ]
create_date [ DATETIME ]
last_update [ DATETIME ]
payment :
payment_id [ INTEGER ] primary_key
customer_id [ INTEGER ]
sta... | SELECT T2.first_name, T2.last_name FROM payment AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id ORDER BY T1.amount DESC LIMIT 1; |
[INST] Here is a database schema:
address :
address_id [ INTEGER ] primary_key
address [ TEXT ]
address2 [ TEXT ]
district [ TEXT ]
city_id [ INTEGER ]
postal_code [ TEXT ]
phone [ TEXT ]
last_update [ DATETIME ]
city :
city_id [ INTEGER ] primary_key
city [ TEXT ]
country_id [ INTEGER ]
last_update [ DATETIME ]
countr... | SELECT SUM(T5.amount) FROM address AS T1 INNER JOIN city AS T2 ON T1.city_id = T2.city_id INNER JOIN country AS T3 ON T2.country_id = T3.country_id INNER JOIN customer AS T4 ON T1.address_id = T4.address_id INNER JOIN payment AS T5 ON T4.customer_id = T5.customer_id WHERE T3.country = 'Italy'; |
[INST] Here is a database schema:
customer :
customer_id [ INTEGER ] primary_key
store_id [ INTEGER ]
first_name [ TEXT ]
last_name [ TEXT ]
email [ TEXT ]
address_id [ INTEGER ]
active [ INTEGER ]
create_date [ DATETIME ]
last_update [ DATETIME ]
payment :
payment_id [ INTEGER ] primary_key
customer_id [ INTEGER ]
sta... | SELECT COUNT(T1.amount) FROM payment AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = 'MARY' AND T2.last_name = 'SMITH' AND T1.amount > 4.99; |
[INST] Here is a database schema:
address :
address_id [ INTEGER ] primary_key
address [ TEXT ]
address2 [ TEXT ]
district [ TEXT ]
city_id [ INTEGER ]
postal_code [ TEXT ]
phone [ TEXT ]
last_update [ DATETIME ]
city :
city_id [ INTEGER ] primary_key
city [ TEXT ]
country_id [ INTEGER ]
last_update [ DATETIME ]
countr... | SELECT AVG(T5.amount) FROM address AS T1 INNER JOIN city AS T2 ON T1.city_id = T2.city_id INNER JOIN country AS T3 ON T2.country_id = T3.country_id INNER JOIN customer AS T4 ON T1.address_id = T4.address_id INNER JOIN payment AS T5 ON T4.customer_id = T5.customer_id WHERE T3.country = 'Italy'; |
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