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The dataset generation failed
Error code: DatasetGenerationError
Exception: CastError
Message: Couldn't cast
text: string
tokens: int64
score: halffloat
score_float: halffloat
-- schema metadata --
pandas: '{"index_columns": [], "column_indexes": [], "columns": [{"name":' + 526
to
{'text': Value('string')}
because column names don't match
Traceback: Traceback (most recent call last):
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 1404, in compute_config_parquet_and_info_response
fill_builder_info(builder, hf_endpoint=hf_endpoint, hf_token=hf_token, validate=validate)
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 577, in fill_builder_info
) = retry_validate_get_features_num_examples_size_and_compression_ratio(
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 496, in retry_validate_get_features_num_examples_size_and_compression_ratio
validate(pf)
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 534, in validate
raise TooBigRowGroupsError(
worker.job_runners.config.parquet_and_info.TooBigRowGroupsError: Parquet file has too big row groups. First row group has 409079573 which exceeds the limit of 300000000
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "/src/services/worker/.venv/lib/python3.12/site-packages/datasets/builder.py", line 1815, in _prepare_split_single
for _, table in generator:
^^^^^^^^^
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 691, in wrapped
for item in generator(*args, **kwargs):
^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/src/services/worker/.venv/lib/python3.12/site-packages/datasets/packaged_modules/parquet/parquet.py", line 106, in _generate_tables
yield f"{file_idx}_{batch_idx}", self._cast_table(pa_table)
^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/src/services/worker/.venv/lib/python3.12/site-packages/datasets/packaged_modules/parquet/parquet.py", line 73, in _cast_table
pa_table = table_cast(pa_table, self.info.features.arrow_schema)
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/src/services/worker/.venv/lib/python3.12/site-packages/datasets/table.py", line 2272, in table_cast
return cast_table_to_schema(table, schema)
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/src/services/worker/.venv/lib/python3.12/site-packages/datasets/table.py", line 2218, in cast_table_to_schema
raise CastError(
datasets.table.CastError: Couldn't cast
text: string
tokens: int64
score: halffloat
score_float: halffloat
-- schema metadata --
pandas: '{"index_columns": [], "column_indexes": [], "columns": [{"name":' + 526
to
{'text': Value('string')}
because column names don't match
The above exception was the direct cause of the following exception:
Traceback (most recent call last):
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 1427, in compute_config_parquet_and_info_response
parquet_operations, partial, estimated_dataset_info = stream_convert_to_parquet(
^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 993, in stream_convert_to_parquet
builder._prepare_split(
File "/src/services/worker/.venv/lib/python3.12/site-packages/datasets/builder.py", line 1702, in _prepare_split
for job_id, done, content in self._prepare_split_single(
^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/src/services/worker/.venv/lib/python3.12/site-packages/datasets/builder.py", line 1858, in _prepare_split_single
raise DatasetGenerationError("An error occurred while generating the dataset") from e
datasets.exceptions.DatasetGenerationError: An error occurred while generating the datasetNeed help to make the dataset viewer work? Make sure to review how to configure the dataset viewer, and open a discussion for direct support.
text string |
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# 2 SHA1和MD5的算法说明
SHA1和MD5的算法都是从MD4算法改进而来的2种算法，基本思路都是将信息分成N个分组，每组64个字节，每个分组都进行摘要运算。当一个分组的摘要运算完毕后，将上一个分组的结果也用于下一个分组的运算。
MD5最后生成的摘要信息是16个字节，SHA1是20个字节。
MD5和SHA1的分组信息运算，分组里面的的数据都会被视为16个DWORD，而MD5算法认为这些DWORD的字节序列是LITTLE-ENDIAN,而SHA1的算法认为DWORD是BIG-ENDIAN的。所以在不同字节序的主机上要进行转换。
61 62 63 80 00 00 00 00 00 00 00 00 0... |
• 这是一套导购月报表汇总表excel模版下载，喜欢的人都来下载吧。该文档为导购月报表汇总表excel模版下载，是一份很不错的参考资料，具有较高参考价值，感兴趣的可以下载看看
• //佣金净收入 desSalary.setSalYxtc(oriSalary.getSalYxtc()+(desSalary.getSalYxtc()==null?0:desSalary.getSalYxtc())); desSalary.setSalJbgzBefore(oriSalary.getSalJbgzBefore()+(desSalary....
参考代码
public List<SalaryDetail> monthFormListForma... |
# 大叔学ML第二：线性回归
## 基本形式
$$\begin x_1^{(1)} & x_2^{(1)} & \cdots &x_n^{(1)}\ x_1^{(2)} & x_2^{(2)} & \cdots & x_n^{(2)}\ \vdots & \vdots & \vdots & \vdots\ x_1^{(m)} & x_2^{(m)} & \cdots & x_n^{(m)}\ \end$$
$$\begin y^{(1)} \ y^{(2)} \ \vdots \ y^{(m)} \ \end$$
$$h(x_1,x_2 \dots x_n)= \theta_0 + \theta_1 x_1 + \theta... |
舰炮身管长度的确定方法
舰船科学技术 2022, Vol. 44 Issue (23): 185-189 DOI: 10.3404/j.issn.1672-7649.2022.23.039 PDF
The determination method on the barrel length of naval gun
LI Xiang, PENG Song-jiang, WANG Lin-lin
The 713 Research Institute of CSSC, Zhengzhou 450015, China
Abstract: From the mission of naval gun , studied on t... |
• Index
关于作者
函数
\mathrm{πr}^2
var r1 = 12.34;
var r2 = 9.08;
var r3 = 73.1;
var s1 = 3.14 * r1 * r1;
var s2 = 3.14 * r2 * r2;
var s3 = 3.14 * r3 * r3;
抽象
\sum_{n=1}^{100}n
\sum_{n=1}^{100}n^2+1
(1\times1+1)+(2\times2+1)+(3\times3+1)+\dots+(100\times100+1) |
# Codeforces Round #616 (Div. 2)
## A. Even But Not Even
time limit per test1 second memory limit per test256 megabytes
Let's define a number ebne (even but not even) if and only if its sum of digits is divisible by 2 but the number itself is not divisible by 2. For example, 13, 1227, 185217 are ebne numbers, while ... |
# # Leetcode 第195场周赛题解
## # Problem A - 判断路径是否相交 (opens new window)
class Solution:
def isPathCrossing(self, path: str) -> bool:
s = set()
x = 0
y = 0
dx = {"N": 0, "S": 0, "E": 1, "W": -1};
dy = {"N": 1, "S": -1, "E": 0, "W": 0};
for c in path:
x += dx[c]
y += dy[c]
if (x, y) in s:
return True;
return False
1
2
3
4... |
2013
12-04
The Snail
A snail is at the bottom of a 6-foot well and wants to climb to the top. The snail can climb 3 feet while the sun is up, but slides down 1 foot at night while sleeping. The snail has a fatigue factor of 10%, which means that on each successive day the snail climbs 10% * 3 = 0.3 feet less than it ... |
[提交][状态][讨论版]
## 题目描述
The Princess has been abducted by the BEelzebub feng5166, our hero Ignatius has to rescue our pretty Princess. Now he gets into feng5166's castle. The castle is a large labyrinth. To make the problem simply, we assume the labyrinth is a N*M two-dimensional array which left-top corner is (0,0) an... |
2013
11-10
# Lagrange’s Four-Square Theorem
The fact that any positive integer has a representation as the sum of at most four positive squares (i.e. squares of positive integers) is known as Lagrange’s Four-Square Theorem. The first published proof of the theorem was given by Joseph-Louis Lagrange in 1770. Your miss... |
## 留言板
引用本文: 陈乾君，蒋媛，刘子建，谭远顺. 具有Gilpin-Ayala增长的随机捕食-食饵模型的动力学行为 [J]. 应用数学和力学，2022，43（4）：453-468
CHEN Qianjun, JIANG Yuan, LIU Zijian, TAN Yuanshun. Dynamic Behavior of a Stochastic Predator Prey Model With the Gilpin-Ayala Growth[J]. Applied Mathematics and Mechanics, 2022, 43(4): 453-468. doi: 10.21656/1000-0887.42020... |
assignmentutor™您的专属作业导师
assignmentutor-lab™ 为您的留学生涯保驾护航 在代写编码理论Coding theory方面已经树立了自己的口碑, 保证靠谱, 高质且原创的统计Statistics代写服务。我们的专家在代写编码理论Coding theory代写方面经验极为丰富，各种代写编码理论Coding theory相关的作业也就用不着说。
• Statistical Inference 统计推断
• Statistical Computing 统计计算
• Advanced Probability Theory 高等概率论
• Advanced Mathematical Statistics ... |
(1) 已知二次函数 $f(x)$ 满足条件 $f(0)=1$ 及 $f(x+1)-f(x)=2 x$, 求 $f(x)$.
(2) 若 $f(x)$ 满足关系式 $f(x)+2 f\left(\frac{1}{x}\right)=3 x$, 求 $f(x)$.
$\because f(x+1)-f(x)=2x$
,
$\therefore\left\{\begin{array}{c}2 a=2 \\ a+b=0\end{array}\right.$, 解得: $\left\{\begin{array}{c}a=1 \\ b=-1\end{array}\right.$,
$\therefore f(x)=x^2-x+1$;
(2... |
### 金融代写|利率建模代写Interest Rate Modeling代考|MATH5985
Vasicek利率模型一词是指一种对利率的运动和演变进行建模的数学方法。它是一种基于市场风险的单因素短利率模型。瓦西克利率模型常用于经济学中，以确定利率在未来的移动方向。
statistics-lab™ 为您的留学生涯保驾护航 在代写利率建模Interest Rate Modeling方面已经树立了自己的口碑, 保证靠谱, 高质且原创的统计Statistics代写服务。我们的专家在代写利率建模Interest Rate Modeling代写方面经验极为丰富，各种代写利率建模Interest Rate Modeling相关的作业也就用... |
ZOJ3203 Light Bulb[三分/推公式]
Light Bulb
Time Limit:1000MS Memory Limit:32768KB
Description
Compared to wildleopard's wealthiness, his brother mildleopard is rather poor. His house is narrow and he has only one light bulb in his house. Every night, he is wandering in his incommodious house, thinking of how to earn ... |
# 小学生都能看懂的生成函数入门教程
## 生成函数
### 普通生成函数
f[0][0] = 1;
for(int i = 1; i <= 3; i++)
for(int j = 0; j <= 8; j++) //当前总共要选出j个
for(int k = 0; k <= j; k++) //已经选了k个
if(j - k <= v[i]) //此时要选j-k个
f[i][j] += f[i - 1][k];
\begin{aligned} G(x) &= (1+x+x^2+x^3)(1+x+x^2)(1+x+x^2+x^3) \\ &= (1+2x+3x^2+3x^3+2x^4+x^5)(1+x+x^2+x^3)\\... |
# 2.3.1: Numbers (模块一- 数字)
$$\newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} }$$
$$\newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}}$$
$$\newcommand{\id}{\mathrm{id}}$$ $$\newcommand{\Span}{\mathrm{span}}$$
( \newcommand{\kernel}{\mathrm{null}\,}\) $$\newco... |
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You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
You may assume the two numbers do not contain any leading zero, except the number 0 i... |
基于全站仪交会测量的空间距离校准装置测量方法
文章快速检索 高级检索
大地测量与地球动力学 2020, Vol. 40 Issue (9): 985-990 DOI: 10.14075/j.jgg.2020.09.021
### 引用本文
PENG Youzhi, ZHANG Xin, HE Haopeng. A Measuring Method for Space Distance Calibration Field Based on Total Station Intersection Survey[J]. Journal of Geodesy and Geodynamics, 2020, 40(9): 985-... |
Posted on Categories:Riemann surface, 数学代写, 黎曼曲面
# 数学代写|黎曼曲面代写Riemann surface代考|The Wolff lemma
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# Quod Erat Demonstrandum
## 2010/07/26
### MVT 某推廣
Filed under: HKALE,Pure Mathematics — johnmayhk @ 11:54 上午
Tags: ,
$F(x) = -3x + \frac{\pi}{2}\cos(\frac{\pi}{2}x) + \frac{e^x}{e - 1} + \frac{1}{(x + 2)\ln 2}$ 在區間 (0,1) 存在零點 ………. (*)
$F(0) , F(1)$ 皆大於零，故不宜用介值定理（Intermediate Value Theorem）。
$F(1) \approx$ -0.69... |
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