task_id stringlengths 11 13 | prompt stringlengths 115 1.36k | canonical_solution stringlengths 17 864 | test stringlengths 117 1.8k | entry_point stringlengths 1 30 |
|---|---|---|---|---|
HumanEval/52 |
def below_threshold(l: list, t: int):
"""Return True if all numbers in the list l are below threshold t.
>>> below_threshold([1, 2, 4, 10], 100)
True
>>> below_threshold([1, 20, 4, 10], 5)
False
"""
| for e in l:
if e >= t:
return False
return True
|
METADATA = {}
def check(candidate):
assert candidate([1, 2, 4, 10], 100)
assert not candidate([1, 20, 4, 10], 5)
assert candidate([1, 20, 4, 10], 21)
assert candidate([1, 20, 4, 10], 22)
assert candidate([1, 8, 4, 10], 11)
assert not candidate([1, 8, 4, 10], 10)
| below_threshold |
HumanEval/134 |
def check_if_last_char_is_a_letter(txt):
'''
Create a function that returns True if the last character
of a given string is an alphabetical character and is not
a part of a word, and False otherwise.
Note: "word" is a group of characters separated by space.
Examples:
check_if_last_char_is_... |
check = txt.split(' ')[-1]
return True if len(check) == 1 and (97 <= ord(check.lower()) <= 122) else False
| def check(candidate):
# Check some simple cases
assert candidate("apple") == False
assert candidate("apple pi e") == True
assert candidate("eeeee") == False
assert candidate("A") == True
assert candidate("Pumpkin pie ") == False
assert candidate("Pumpkin pie 1") == False
assert candidat... | check_if_last_char_is_a_letter |
HumanEval/51 |
def remove_vowels(text):
"""
remove_vowels is a function that takes string and returns string without vowels.
>>> remove_vowels('')
''
>>> remove_vowels("abcdef\nghijklm")
'bcdf\nghjklm'
>>> remove_vowels('abcdef')
'bcdf'
>>> remove_vowels('aaaaa')
''
>>> remove_vowels('aaB... | return "".join([s for s in text if s.lower() not in ["a", "e", "i", "o", "u"]])
|
METADATA = {}
def check(candidate):
assert candidate('') == ''
assert candidate("abcdef\nghijklm") == 'bcdf\nghjklm'
assert candidate('fedcba') == 'fdcb'
assert candidate('eeeee') == ''
assert candidate('acBAA') == 'cB'
assert candidate('EcBOO') == 'cB'
assert candidate('ybcd') == 'ybcd'... | remove_vowels |
HumanEval/66 |
def digitSum(s):
"""Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum("") => 0
digitSum("abAB") => 131
digitSum("abcCd") => 67
digitSum("helloE") => 69
digitSum("woArBld") => 131
... | if s == "": return 0
return sum(ord(char) if char.isupper() else 0 for char in s)
| def check(candidate):
# Check some simple cases
assert True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate("") == 0, "Error"
assert candidate("abAB") == 131, "Error"
assert candidate("abcCd") == 67, "Error"
assert candidate("helloE") == 69, "Error"
assert candi... | digitSum |
HumanEval/147 |
def get_max_triples(n):
"""
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
... | A = [i*i - i + 1 for i in range(1,n+1)]
ans = []
for i in range(n):
for j in range(i+1,n):
for k in range(j+1,n):
if (A[i]+A[j]+A[k])%3 == 0:
ans += [(A[i],A[j],A[k])]
return len(ans)
| def check(candidate):
assert candidate(5) == 1
assert candidate(6) == 4
assert candidate(10) == 36
assert candidate(100) == 53361
| get_max_triples |
HumanEval/101 |
def words_string(s):
"""
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
words_string("One, two, three, fo... | if not s:
return []
s_list = []
for letter in s:
if letter == ',':
s_list.append(' ')
else:
s_list.append(letter)
s_list = "".join(s_list)
return s_list.split()
| def check(candidate):
# Check some simple cases
assert True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate("Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
assert candidate("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
... | words_string |
HumanEval/24 |
def largest_divisor(n: int) -> int:
""" For a given number n, find the largest number that divides n evenly, smaller than n
>>> largest_divisor(15)
5
"""
| for i in reversed(range(n)):
if n % i == 0:
return i
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate(3) == 1
assert candidate(7) == 1
assert candidate(10) == 5
assert candidate(100) == 50
assert candidate(49) == 7
| largest_divisor |
HumanEval/125 |
def split_words(txt):
'''
Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('... | if " " in txt:
return txt.split()
elif "," in txt:
return txt.replace(',',' ').split()
else:
return len([i for i in txt if i.islower() and ord(i)%2 == 0])
| def check(candidate):
assert candidate("Hello world!") == ["Hello","world!"]
assert candidate("Hello,world!") == ["Hello","world!"]
assert candidate("Hello world,!") == ["Hello","world,!"]
assert candidate("Hello,Hello,world !") == ["Hello,Hello,world","!"]
assert candidate("abcdef") == 3
asser... | split_words |
HumanEval/145 |
def order_by_points(nums):
"""
Write a function which sorts the given list of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original list.
For example:
>>> order_by_poi... | def digits_sum(n):
neg = 1
if n < 0: n, neg = -1 * n, -1
n = [int(i) for i in str(n)]
n[0] = n[0] * neg
return sum(n)
return sorted(nums, key=digits_sum)
| def check(candidate):
# Check some simple cases
assert candidate([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
assert candidate([1234,423,463,145,2,423,423,53,6,37,3457,3,56,0,46]) == [0, 2, 3, 6, 53, 423, 423, 423, 1234, 145, 37, 46, 56, 463, 3457]
assert candidate([]) == []
assert candidate([1,... | order_by_points |
HumanEval/50 |
def encode_shift(s: str):
"""
returns encoded string by shifting every character by 5 in the alphabet.
"""
return "".join([chr(((ord(ch) + 5 - ord("a")) % 26) + ord("a")) for ch in s])
def decode_shift(s: str):
"""
takes as input string encoded with encode_shift function. Returns decoded str... | return "".join([chr(((ord(ch) - 5 - ord("a")) % 26) + ord("a")) for ch in s])
|
METADATA = {}
def check(candidate):
from random import randint, choice
import copy
import string
letters = string.ascii_lowercase
for _ in range(100):
str = ''.join(choice(letters) for i in range(randint(10, 20)))
encoded_str = encode_shift(str)
assert candidate(copy.dee... | decode_shift |
HumanEval/38 |
def encode_cyclic(s: str):
"""
returns encoded string by cycling groups of three characters.
"""
# split string to groups. Each of length 3.
groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]
# cycle elements in each group. Unless group has fewer elements than 3.
... | return encode_cyclic(encode_cyclic(s))
|
METADATA = {}
def check(candidate):
from random import randint, choice
import string
letters = string.ascii_lowercase
for _ in range(100):
str = ''.join(choice(letters) for i in range(randint(10, 20)))
encoded_str = encode_cyclic(str)
assert candidate(encoded_str) == str
| decode_cyclic |
HumanEval/142 |
def sum_squares(lst):
""""
This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a
multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not
change the e... | result =[]
for i in range(len(lst)):
if i %3 == 0:
result.append(lst[i]**2)
elif i % 4 == 0 and i%3 != 0:
result.append(lst[i]**3)
else:
result.append(lst[i])
return sum(result)
| def check(candidate):
# Check some simple cases
assert candidate([1,2,3]) == 6
assert candidate([1,4,9]) == 14
assert candidate([]) == 0
assert candidate([1,1,1,1,1,1,1,1,1]) == 9
assert candidate([-1,-1,-1,-1,-1,-1,-1,-1,-1]) == -3
assert candidate([0]) == 0
assert candidate([-1,-... | sum_squares |
HumanEval/127 |
def intersection(interval1, interval2):
"""You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is ass... | def is_prime(num):
if num == 1 or num == 0:
return False
if num == 2:
return True
for i in range(2, num):
if num%i == 0:
return False
return True
l = max(interval1[0], interval2[0])
r = min(interval1[1], interval2[1])
l... | def check(candidate):
# Check some simple cases
assert candidate((1, 2), (2, 3)) == "NO"
assert candidate((-1, 1), (0, 4)) == "NO"
assert candidate((-3, -1), (-5, 5)) == "YES"
assert candidate((-2, 2), (-4, 0)) == "YES"
# Check some edge cases that are easy to work out by hand.
assert cand... | intersection |
HumanEval/111 |
def histogram(test):
"""Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram('a b c') == {'a': 1, '... | dict1={}
list1=test.split(" ")
t=0
for i in list1:
if(list1.count(i)>t) and i!='':
t=list1.count(i)
if t>0:
for i in list1:
if(list1.count(i)==t):
dict1[i]=t
return dict1
| def check(candidate):
# Check some simple cases
assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
assert candidate('a b c d g') == {'a': ... | histogram |
HumanEval/46 |
def fib4(n: int):
"""The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th el... | results = [0, 0, 2, 0]
if n < 4:
return results[n]
for _ in range(4, n + 1):
results.append(results[-1] + results[-2] + results[-3] + results[-4])
results.pop(0)
return results[-1]
|
METADATA = {}
def check(candidate):
assert candidate(5) == 4
assert candidate(8) == 28
assert candidate(10) == 104
assert candidate(12) == 386
| fib4 |
HumanEval/7 | from typing import List
def filter_by_substring(strings: List[str], substring: str) -> List[str]:
""" Filter an input list of strings only for ones that contain given substring
>>> filter_by_substring([], 'a')
[]
>>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')
['abc', 'bacd', 'array'... | return [x for x in strings if substring in x]
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([], 'john') == []
assert candidate(['xxx', 'asd', 'xxy', 'john doe', 'xxxAAA', 'xxx'], 'xxx') == ['xxx', 'xxxAAA', 'xxx']
assert candidate(['xxx', 'asd', 'aaaxxy', 'john doe', 'xxxAAA', 'xxx'], 'xx') == ['xxx... | filter_by_substring |
HumanEval/9 | from typing import List, Tuple
def rolling_max(numbers: List[int]) -> List[int]:
""" From a given list of integers, generate a list of rolling maximum element found until given moment
in the sequence.
>>> rolling_max([1, 2, 3, 2, 3, 4, 2])
[1, 2, 3, 3, 3, 4, 4]
"""
| running_max = None
result = []
for n in numbers:
if running_max is None:
running_max = n
else:
running_max = max(running_max, n)
result.append(running_max)
return result
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([]) == []
assert candidate([1, 2, 3, 4]) == [1, 2, 3, 4]
assert candidate([4, 3, 2, 1]) == [4, 4, 4, 4]
assert candidate([3, 2, 3, 100, 3]) == [3, 3, 3, 100, 100]
| rolling_max |
HumanEval/112 |
def reverse_delete(s,c):
"""Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple contai... | s = ''.join([char for char in s if char not in c])
return (s,s[::-1] == s)
| def check(candidate):
assert candidate("abcde","ae") == ('bcd',False)
assert candidate("abcdef", "b") == ('acdef',False)
assert candidate("abcdedcba","ab") == ('cdedc',True)
assert candidate("dwik","w") == ('dik',False)
assert candidate("a","a") == ('',True)
assert candidate("abcdedcba","") == ... | reverse_delete |
HumanEval/157 |
def right_angle_triangle(a, b, c):
'''
Given the lengths of the three sides of a triangle. Return True if the three
sides form a right-angled triangle, False otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
right_angle_triangle(3, 4,... | return a*a == b*b + c*c or b*b == a*a + c*c or c*c == a*a + b*b
| def check(candidate):
# Check some simple cases
assert candidate(3, 4, 5) == True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate(1, 2, 3) == False
assert candidate(10, 6, 8) == True
assert candidate(2, 2, 2) == False
assert candidate(7, 24, 25) == True
assert c... | right_angle_triangle |
HumanEval/70 |
def strange_sort_list(lst):
'''
Given list of integers, return list in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]
strange_sort_list([5, 5... | res, switch = [], True
while lst:
res.append(min(lst) if switch else max(lst))
lst.remove(res[-1])
switch = not switch
return res
| def check(candidate):
# Check some simple cases
assert candidate([1, 2, 3, 4]) == [1, 4, 2, 3]
assert candidate([5, 6, 7, 8, 9]) == [5, 9, 6, 8, 7]
assert candidate([1, 2, 3, 4, 5]) == [1, 5, 2, 4, 3]
assert candidate([5, 6, 7, 8, 9, 1]) == [1, 9, 5, 8, 6, 7]
assert candidate([5, 5, 5, 5]) == [... | strange_sort_list |
HumanEval/133 |
def sum_squares(lst):
"""You are given a list of numbers.
You need to return the sum of squared numbers in the given list,
round each element in the list to the upper int(Ceiling) first.
Examples:
For lst = [1,2,3] the output should be 14
For lst = [1,4,9] the output should be 98
For lst =... | import math
squared = 0
for i in lst:
squared += math.ceil(i)**2
return squared
| def check(candidate):
# Check some simple cases
assert candidate([1,2,3])==14, "This prints if this assert fails 1 (good for debugging!)"
assert candidate([1.0,2,3])==14, "This prints if this assert fails 1 (good for debugging!)"
assert candidate([1,3,5,7])==84, "This prints if this assert fails 1 (goo... | sum_squares |
HumanEval/88 |
def sort_array(array):
"""
Given an array of non-negative integers, return a copy of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) i... | return [] if len(array) == 0 else sorted(array, reverse= (array[0]+array[-1]) % 2 == 0)
| def check(candidate):
# Check some simple cases
assert True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate([]) == [], "Error"
assert candidate([5]) == [5], "Error"
assert candidate([2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5], "Error"
assert candidate([2, 4, 3, 0, 1, ... | sort_array |
HumanEval/25 | from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the produc... | import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate(2) == [2]
assert candidate(4) == [2, 2]
assert candidate(8) == [2, 2, 2]
assert candidate(3 * 19) == [3, 19]
assert candidate(3 * 19 * 3 * 19) == [3, 3, 19, 19]
assert candidate(3 * 19 * 3 * 19 * ... | factorize |
HumanEval/3 | from typing import List
def below_zero(operations: List[int]) -> bool:
""" You're given a list of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return Tru... | balance = 0
for op in operations:
balance += op
if balance < 0:
return True
return False
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([]) == False
assert candidate([1, 2, -3, 1, 2, -3]) == False
assert candidate([1, 2, -4, 5, 6]) == True
assert candidate([1, -1, 2, -2, 5, -5, 4, -4]) == False
assert candidate([1, -1, 2, -2, 5, -5, 4... | below_zero |
HumanEval/117 |
def select_words(s, n):
"""Given a string s and a natural number n, you have been tasked to implement
a function that returns a list of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an e... | result = []
for word in s.split():
n_consonants = 0
for i in range(0, len(word)):
if word[i].lower() not in ["a","e","i","o","u"]:
n_consonants += 1
if n_consonants == n:
result.append(word)
return result
| def check(candidate):
# Check some simple cases
assert candidate("Mary had a little lamb", 4) == ["little"], "First test error: " + str(candidate("Mary had a little lamb", 4))
assert candidate("Mary had a little lamb", 3) == ["Mary", "lamb"], "Second test error: " + str(candidate("Mary had a little l... | select_words |
HumanEval/62 |
def derivative(xs: list):
""" xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 + ....
Return derivative of this polynomial in the same form.
>>> derivative([3, 1, 2, 4, 5])
[1, 4, 12, 20]
>>> derivative([1, 2, 3])
[2, 6]
"""
| return [(i * x) for i, x in enumerate(xs)][1:]
|
METADATA = {}
def check(candidate):
assert candidate([3, 1, 2, 4, 5]) == [1, 4, 12, 20]
assert candidate([1, 2, 3]) == [2, 6]
assert candidate([3, 2, 1]) == [2, 2]
assert candidate([3, 2, 1, 0, 4]) == [2, 2, 0, 16]
assert candidate([1]) == []
| derivative |
HumanEval/8 | from typing import List, Tuple
def sum_product(numbers: List[int]) -> Tuple[int, int]:
""" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.
Empty sum should be equal to 0 and empty product should be equal to 1.
>>> sum_product([])
(0, 1)
... | sum_value = 0
prod_value = 1
for n in numbers:
sum_value += n
prod_value *= n
return sum_value, prod_value
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([]) == (0, 1)
assert candidate([1, 1, 1]) == (3, 1)
assert candidate([100, 0]) == (100, 0)
assert candidate([3, 5, 7]) == (3 + 5 + 7, 3 * 5 * 7)
assert candidate([10]) == (10, 10)
| sum_product |
HumanEval/33 |
def sort_third(l: list):
"""This function takes a list l and returns a list l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
>>> sort_t... | l = list(l)
l[::3] = sorted(l[::3])
return l
|
METADATA = {}
def check(candidate):
assert tuple(candidate([1, 2, 3])) == tuple(sort_third([1, 2, 3]))
assert tuple(candidate([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])) == tuple(sort_third([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]))
assert tuple(candidate([5, 8, -12, 4, 23, 2, 3, 11, 12, -10])) == tuple(so... | sort_third |
HumanEval/119 |
def match_parens(lst):
'''
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be... | def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes'... | def check(candidate):
# Check some simple cases
assert candidate(['()(', ')']) == 'Yes'
assert candidate([')', ')']) == 'No'
assert candidate(['(()(())', '())())']) == 'No'
assert candidate([')())', '(()()(']) == 'Yes'
assert candidate(['(())))', '(()())((']) == 'Yes'
assert candidate(['()'... | match_parens |
HumanEval/155 |
def even_odd_count(num):
"""Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
even_odd_count(-12) ==> (1, 1)
even_odd_count(123) ==> (1, 2)
"""
| even_count = 0
odd_count = 0
for i in str(abs(num)):
if int(i)%2==0:
even_count +=1
else:
odd_count +=1
return (even_count, odd_count)
| def check(candidate):
# Check some simple cases
assert candidate(7) == (0, 1)
assert candidate(-78) == (1, 1)
assert candidate(3452) == (2, 2)
assert candidate(346211) == (3, 3)
assert candidate(-345821) == (3, 3)
assert candidate(-2) == (1, 0)
assert candidate(-45347) == (2, 3)
ass... | even_odd_count |
HumanEval/20 | from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
>>> find_closest_elements([... | closest_pair = None
distance = None
for idx, elem in enumerate(numbers):
for idx2, elem2 in enumerate(numbers):
if idx != idx2:
if distance is None:
distance = abs(elem - elem2)
closest_pair = tuple(sorted([elem, elem2]))
... |
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2]) == (3.9, 4.0)
assert candidate([1.0, 2.0, 5.9, 4.0, 5.0]) == (5.0, 5.9)
assert candidate([1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
assert candidate([1.0, 2.0, 3.0, 4.0,... | find_closest_elements |
HumanEval/161 |
def solve(s):
"""You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve("1234") = "4321"
solve("... | flg = 0
idx = 0
new_str = list(s)
for i in s:
if i.isalpha():
new_str[idx] = i.swapcase()
flg = 1
idx += 1
s = ""
for i in new_str:
s += i
if flg == 0:
return s[len(s)::-1]
return s
| def check(candidate):
# Check some simple cases
assert candidate("AsDf") == "aSdF"
assert candidate("1234") == "4321"
assert candidate("ab") == "AB"
assert candidate("#a@C") == "#A@c"
assert candidate("#AsdfW^45") == "#aSDFw^45"
assert candidate("#6@2") == "2@6#"
# Check some edge case... | solve |
HumanEval/37 |
def sort_even(l: list):
"""This function takes a list l and returns a list l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
>>> sort_even([1, 2, 3])
[1, 2, 3]
>>> sort_even([5, 6, 3, 4])
... | evens = l[::2]
odds = l[1::2]
evens.sort()
ans = []
for e, o in zip(evens, odds):
ans.extend([e, o])
if len(evens) > len(odds):
ans.append(evens[-1])
return ans
|
METADATA = {}
def check(candidate):
assert tuple(candidate([1, 2, 3])) == tuple([1, 2, 3])
assert tuple(candidate([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])) == tuple([-10, 3, -5, 2, -3, 3, 5, 0, 9, 1, 123])
assert tuple(candidate([5, 8, -12, 4, 23, 2, 3, 11, 12, -10])) == tuple([-12, 8, 3, 4, 5, 2, 12, 1... | sort_even |
HumanEval/56 |
def correct_bracketing(brackets: str):
""" brackets is a string of "<" and ">".
return True if every opening bracket has a corresponding closing bracket.
>>> correct_bracketing("<")
False
>>> correct_bracketing("<>")
True
>>> correct_bracketing("<<><>>")
True
>>> correct_bracketin... | depth = 0
for b in brackets:
if b == "<":
depth += 1
else:
depth -= 1
if depth < 0:
return False
return depth == 0
|
METADATA = {}
def check(candidate):
assert candidate("<>")
assert candidate("<<><>>")
assert candidate("<><><<><>><>")
assert candidate("<><><<<><><>><>><<><><<>>>")
assert not candidate("<<<><>>>>")
assert not candidate("><<>")
assert not candidate("<")
assert not candidate("<<<<")
... | correct_bracketing |
HumanEval/122 |
def add_elements(arr, k):
"""
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Input: arr = [111,21,3,4000,5,6,7,8,9], k = 4
Output: 24 # sum of 21 + 3
Constraints:
... | return sum(elem for elem in arr[:k] if len(str(elem)) <= 2)
| def check(candidate):
# Check some simple cases
assert candidate([1,-2,-3,41,57,76,87,88,99], 3) == -4
assert candidate([111,121,3,4000,5,6], 2) == 0
assert candidate([11,21,3,90,5,6,7,8,9], 4) == 125
assert candidate([111,21,3,4000,5,6,7,8,9], 4) == 24, "This prints if this assert fails 1 (good fo... | add_elements |
HumanEval/100 |
def make_a_pile(n):
"""
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each lev... | return [n + 2*i for i in range(n)]
| def check(candidate):
# Check some simple cases
assert candidate(3) == [3, 5, 7], "Test 3"
assert candidate(4) == [4,6,8,10], "Test 4"
assert candidate(5) == [5, 7, 9, 11, 13]
assert candidate(6) == [6, 8, 10, 12, 14, 16]
assert candidate(8) == [8, 10, 12, 14, 16, 18, 20, 22]
# Check some ... | make_a_pile |
HumanEval/144 |
def simplify(x, n):
"""Your task is to implement a function that will simplify the expression
x * n. The function returns True if x * n evaluates to a whole number and False
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where ... | a, b = x.split("/")
c, d = n.split("/")
numerator = int(a) * int(c)
denom = int(b) * int(d)
if (numerator/denom == int(numerator/denom)):
return True
return False
| def check(candidate):
# Check some simple cases
assert candidate("1/5", "5/1") == True, 'test1'
assert candidate("1/6", "2/1") == False, 'test2'
assert candidate("5/1", "3/1") == True, 'test3'
assert candidate("7/10", "10/2") == False, 'test4'
assert candidate("2/10", "50/10") == True, 'test5'
... | simplify |
HumanEval/92 |
def any_int(x, y, z):
'''
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
any_int(5, 2, 7) ➞ True
any_int(3, 2, 2) ➞ False
any_int(3, -2, ... |
if isinstance(x,int) and isinstance(y,int) and isinstance(z,int):
if (x+y==z) or (x+z==y) or (y+z==x):
return True
return False
return False
| def check(candidate):
# Check some simple cases
assert candidate(2, 3, 1)==True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate(2.5, 2, 3)==False, "This prints if this assert fails 2 (good for debugging!)"
assert candidate(1.5, 5, 3.5)==False, "This prints if this assert fa... | any_int |
HumanEval/32 | import math
def poly(xs: list, x: float):
"""
Evaluates polynomial with coefficients xs at point x.
return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n
"""
return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)])
def find_zero(xs: list):
""" xs are coefficients of a polynomia... | begin, end = -1., 1.
while poly(xs, begin) * poly(xs, end) > 0:
begin *= 2.0
end *= 2.0
while end - begin > 1e-10:
center = (begin + end) / 2.0
if poly(xs, center) * poly(xs, begin) > 0:
begin = center
else:
end = center
return begin
|
METADATA = {}
def check(candidate):
import math
import random
rng = random.Random(42)
import copy
for _ in range(100):
ncoeff = 2 * rng.randint(1, 4)
coeffs = []
for _ in range(ncoeff):
coeff = rng.randint(-10, 10)
if coeff == 0:
co... | find_zero |
HumanEval/4 | from typing import List
def mean_absolute_deviation(numbers: List[float]) -> float:
""" For a given list of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this ... | mean = sum(numbers) / len(numbers)
return sum(abs(x - mean) for x in numbers) / len(numbers)
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert abs(candidate([1.0, 2.0, 3.0]) - 2.0/3.0) < 1e-6
assert abs(candidate([1.0, 2.0, 3.0, 4.0]) - 1.0) < 1e-6
assert abs(candidate([1.0, 2.0, 3.0, 4.0, 5.0]) - 6.0/5.0) < 1e-6
| mean_absolute_deviation |
HumanEval/156 |
def int_to_mini_roman(number):
"""
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
>>> int_to_mini_roman(19) == 'xix'
>>> int_to_mini_roman(152) == 'clii'
>>> int_to_mini_roman(426) == 'cdxx... | num = [1, 4, 5, 9, 10, 40, 50, 90,
100, 400, 500, 900, 1000]
sym = ["I", "IV", "V", "IX", "X", "XL",
"L", "XC", "C", "CD", "D", "CM", "M"]
i = 12
res = ''
while number:
div = number // num[i]
number %= num[i]
while div:
res += sym[i... | def check(candidate):
# Check some simple cases
assert candidate(19) == 'xix'
assert candidate(152) == 'clii'
assert candidate(251) == 'ccli'
assert candidate(426) == 'cdxxvi'
assert candidate(500) == 'd'
assert candidate(1) == 'i'
assert candidate(4) == 'iv'
assert candidate(43) ==... | int_to_mini_roman |
HumanEval/54 |
def same_chars(s0: str, s1: str):
"""
Check if two words have the same characters.
>>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')
True
>>> same_chars('abcd', 'dddddddabc')
True
>>> same_chars('dddddddabc', 'abcd')
True
>>> same_chars('eabcd', 'dddddddabc')
False
>>> same... | return set(s0) == set(s1)
|
METADATA = {}
def check(candidate):
assert candidate('eabcdzzzz', 'dddzzzzzzzddeddabc') == True
assert candidate('abcd', 'dddddddabc') == True
assert candidate('dddddddabc', 'abcd') == True
assert candidate('eabcd', 'dddddddabc') == False
assert candidate('abcd', 'dddddddabcf') == False
asse... | same_chars |
HumanEval/2 |
def truncate_number(number: float) -> float:
""" Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
>>> truncate_number(3.5)
0... | return number % 1.0
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate(3.5) == 0.5
assert abs(candidate(1.33) - 0.33) < 1e-6
assert abs(candidate(123.456) - 0.456) < 1e-6
| truncate_number |
HumanEval/104 |
def unique_digits(x):
"""Given a list of positive integers x. return a sorted list of all
elements that hasn't any even digit.
Note: Returned list should be sorted in increasing order.
For example:
>>> unique_digits([15, 33, 1422, 1])
[1, 15, 33]
>>> unique_digits([152, 323, 1422, 10... | odd_digit_elements = []
for i in x:
if all (int(c) % 2 == 1 for c in str(i)):
odd_digit_elements.append(i)
return sorted(odd_digit_elements)
| def check(candidate):
# Check some simple cases
assert candidate([15, 33, 1422, 1]) == [1, 15, 33]
assert candidate([152, 323, 1422, 10]) == []
assert candidate([12345, 2033, 111, 151]) == [111, 151]
assert candidate([135, 103, 31]) == [31, 135]
# Check some edge cases that are easy to work ou... | unique_digits |
HumanEval/126 |
def is_sorted(lst):
'''
Given a list of numbers, return whether or not they are sorted
in ascending order. If list has more than 1 duplicate of the same
number, return False. Assume no negative numbers and only integers.
Examples
is_sorted([5]) ➞ True
is_sorted([1, 2, 3, 4, 5]) ➞ True
... | count_digit = dict([(i, 0) for i in lst])
for i in lst:
count_digit[i]+=1
if any(count_digit[i] > 2 for i in lst):
return False
if all(lst[i-1] <= lst[i] for i in range(1, len(lst))):
return True
else:
return False
| def check(candidate):
# Check some simple cases
assert candidate([5]) == True
assert candidate([1, 2, 3, 4, 5]) == True
assert candidate([1, 3, 2, 4, 5]) == False
assert candidate([1, 2, 3, 4, 5, 6]) == True
assert candidate([1, 2, 3, 4, 5, 6, 7]) == True
assert candidate([1, 3, 2, 4, 5, 6,... | is_sorted |
HumanEval/28 | from typing import List
def concatenate(strings: List[str]) -> str:
""" Concatenate list of strings into a single string
>>> concatenate([])
''
>>> concatenate(['a', 'b', 'c'])
'abc'
"""
| return ''.join(strings)
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([]) == ''
assert candidate(['x', 'y', 'z']) == 'xyz'
assert candidate(['x', 'y', 'z', 'w', 'k']) == 'xyzwk'
| concatenate |
HumanEval/123 |
def get_odd_collatz(n):
"""
Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
prev... | if n%2==0:
odd_collatz = []
else:
odd_collatz = [n]
while n > 1:
if n % 2 == 0:
n = n/2
else:
n = n*3 + 1
if n%2 == 1:
odd_collatz.append(int(n))
return sorted(odd_collatz)
| def check(candidate):
# Check some simple cases
assert candidate(14) == [1, 5, 7, 11, 13, 17]
assert candidate(5) == [1, 5]
assert candidate(12) == [1, 3, 5], "This prints if this assert fails 1 (good for debugging!)"
# Check some edge cases that are easy to work out by hand.
assert candidate(... | get_odd_collatz |
HumanEval/107 |
def even_odd_palindrome(n):
"""
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Input: 3
Output: (1, 2)
Explanation:
Integer palindrome are 1, 2, 3. one of them i... | def is_palindrome(n):
return str(n) == str(n)[::-1]
even_palindrome_count = 0
odd_palindrome_count = 0
for i in range(1, n+1):
if i%2 == 1 and is_palindrome(i):
odd_palindrome_count += 1
elif i%2 == 0 and is_palindrome(i):
even_palindrome_count += 1
... | def check(candidate):
# Check some simple cases
assert candidate(123) == (8, 13)
assert candidate(12) == (4, 6)
assert candidate(3) == (1, 2)
assert candidate(63) == (6, 8)
assert candidate(25) == (5, 6)
assert candidate(19) == (4, 6)
assert candidate(9) == (4, 5), "This prints if this ... | even_odd_palindrome |
HumanEval/75 |
def is_multiply_prime(a):
"""Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100.
Example:
is_multiply_prime(30) == True
30 = 2 * 3 * 5
"""
| def is_prime(n):
for j in range(2,n):
if n%j == 0:
return False
return True
for i in range(2,101):
if not is_prime(i): continue
for j in range(2,101):
if not is_prime(j): continue
for k in range(2,101):
if not i... | def check(candidate):
assert candidate(5) == False
assert candidate(30) == True
assert candidate(8) == True
assert candidate(10) == False
assert candidate(125) == True
assert candidate(3 * 5 * 7) == True
assert candidate(3 * 6 * 7) == False
assert candidate(9 * 9 * 9) == False
asser... | is_multiply_prime |
HumanEval/12 | from typing import List, Optional
def longest(strings: List[str]) -> Optional[str]:
""" Out of list of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return None in case the input list is empty.
>>> longest([])
>>> longest(['a', 'b', 'c'])
'a... | if not strings:
return None
maxlen = max(len(x) for x in strings)
for s in strings:
if len(s) == maxlen:
return s
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([]) == None
assert candidate(['x', 'y', 'z']) == 'x'
assert candidate(['x', 'yyy', 'zzzz', 'www', 'kkkk', 'abc']) == 'zzzz'
| longest |
HumanEval/82 |
def prime_length(string):
"""Write a function that takes a string and returns True if the string
length is a prime number or False otherwise
Examples
prime_length('Hello') == True
prime_length('abcdcba') == True
prime_length('kittens') == True
prime_length('orange') == False
"""
| l = len(string)
if l == 0 or l == 1:
return False
for i in range(2, l):
if l % i == 0:
return False
return True
| def check(candidate):
# Check some simple cases
assert candidate('Hello') == True
assert candidate('abcdcba') == True
assert candidate('kittens') == True
assert candidate('orange') == False
assert candidate('wow') == True
assert candidate('world') == True
assert candidate('MadaM') == Tr... | prime_length |
HumanEval/85 |
def add(lst):
"""Given a non-empty list of integers lst. add the even elements that are at odd indices..
Examples:
add([4, 2, 6, 7]) ==> 2
"""
| return sum([lst[i] for i in range(1, len(lst), 2) if lst[i]%2 == 0])
| def check(candidate):
# Check some simple cases
assert candidate([4, 88]) == 88
assert candidate([4, 5, 6, 7, 2, 122]) == 122
assert candidate([4, 0, 6, 7]) == 0
assert candidate([4, 4, 6, 8]) == 12
# Check some edge cases that are easy to work out by hand.
| add |
HumanEval/93 |
def encode(message):
"""
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Examples:
>>>... | vowels = "aeiouAEIOU"
vowels_replace = dict([(i, chr(ord(i) + 2)) for i in vowels])
message = message.swapcase()
return ''.join([vowels_replace[i] if i in vowels else i for i in message])
| def check(candidate):
# Check some simple cases
assert candidate('TEST') == 'tgst', "This prints if this assert fails 1 (good for debugging!)"
assert candidate('Mudasir') == 'mWDCSKR', "This prints if this assert fails 2 (good for debugging!)"
assert candidate('YES') == 'ygs', "This prints if this asse... | encode |
HumanEval/0 | from typing import List
def has_close_elements(numbers: List[float], threshold: float) -> bool:
""" Check if in given list of numbers, are any two numbers closer to each other than
given threshold.
>>> has_close_elements([1.0, 2.0, 3.0], 0.5)
False
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, ... | for idx, elem in enumerate(numbers):
for idx2, elem2 in enumerate(numbers):
if idx != idx2:
distance = abs(elem - elem2)
if distance < threshold:
return True
return False
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.3) == True
assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.05) == False
assert candidate([1.0, 2.0, 5.9, 4.0, 5.0], 0.95) == True
assert candidate([1.0, 2.0, 5.9, 4.0,... | has_close_elements |
HumanEval/163 |
def generate_integers(a, b):
"""
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generate_integers(2, 8) => [2, 4, 6, 8]
generate_integers(8, 2) => [2, 4, 6, 8]
generate_integers(10, 14) => []
"""
| lower = max(2, min(a, b))
upper = min(8, max(a, b))
return [i for i in range(lower, upper+1) if i % 2 == 0]
| def check(candidate):
# Check some simple cases
assert candidate(2, 10) == [2, 4, 6, 8], "Test 1"
assert candidate(10, 2) == [2, 4, 6, 8], "Test 2"
assert candidate(132, 2) == [2, 4, 6, 8], "Test 3"
assert candidate(17,89) == [], "Test 4"
# Check some edge cases that are easy to work out by ha... | generate_integers |
HumanEval/99 |
def closest_integer(value):
'''
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
>>> closest_integer("10")
10
>>> closest_integer("15.3")
15
... | from math import floor, ceil
if value.count('.') == 1:
# remove trailing zeros
while (value[-1] == '0'):
value = value[:-1]
num = float(value)
if value[-2:] == '.5':
if num > 0:
res = ceil(num)
else:
res = floor(num)
elif len(valu... | def check(candidate):
# Check some simple cases
assert candidate("10") == 10, "Test 1"
assert candidate("14.5") == 15, "Test 2"
assert candidate("-15.5") == -16, "Test 3"
assert candidate("15.3") == 15, "Test 3"
# Check some edge cases that are easy to work out by hand.
assert candidate("0... | closest_integer |
HumanEval/27 |
def flip_case(string: str) -> str:
""" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
>>> flip_case('Hello')
'hELLO'
"""
| return string.swapcase()
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('') == ''
assert candidate('Hello!') == 'hELLO!'
assert candidate('These violent delights have violent ends') == 'tHESE VIOLENT DELIGHTS HAVE VIOLENT ENDS'
| flip_case |
HumanEval/115 |
def max_fill(grid, capacity):
import math
"""
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capac... | return sum([math.ceil(sum(arr)/capacity) for arr in grid])
| def check(candidate):
# Check some simple cases
assert True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate([[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1) == 6, "Error"
assert candidate([[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2) == 5, "Error"
assert candidate([[0,0,0], [0... | max_fill |
HumanEval/68 |
def pluck(arr):
"""
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the no... | if(len(arr) == 0): return []
evens = list(filter(lambda x: x%2 == 0, arr))
if(evens == []): return []
return [min(evens), arr.index(min(evens))]
| def check(candidate):
# Check some simple cases
assert True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate([4,2,3]) == [2, 1], "Error"
assert candidate([1,2,3]) == [2, 1], "Error"
assert candidate([]) == [], "Error"
assert candidate([5, 0, 3, 0, 4, 2]) == [0, 1], "... | pluck |
HumanEval/108 |
def count_nums(arr):
"""
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
>>> count_nums([]) == 0
>>... | def digits_sum(n):
neg = 1
if n < 0: n, neg = -1 * n, -1
n = [int(i) for i in str(n)]
n[0] = n[0] * neg
return sum(n)
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr])))
| def check(candidate):
# Check some simple cases
assert candidate([]) == 0
assert candidate([-1, -2, 0]) == 0
assert candidate([1, 1, 2, -2, 3, 4, 5]) == 6
assert candidate([1, 6, 9, -6, 0, 1, 5]) == 5
assert candidate([1, 100, 98, -7, 1, -1]) == 4
assert candidate([12, 23, 34, -45, -56, 0])... | count_nums |
HumanEval/79 |
def decimal_to_binary(decimal):
"""You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of charac... | return "db" + bin(decimal)[2:] + "db"
| def check(candidate):
# Check some simple cases
assert candidate(0) == "db0db"
assert candidate(32) == "db100000db"
assert candidate(103) == "db1100111db"
assert candidate(15) == "db1111db", "This prints if this assert fails 1 (good for debugging!)"
# Check some edge cases that are easy to wor... | decimal_to_binary |
HumanEval/81 |
def numerical_letter_grade(grades):
"""It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you a list of GPAs for some students a... |
letter_grade = []
for gpa in grades:
if gpa == 4.0:
letter_grade.append("A+")
elif gpa > 3.7:
letter_grade.append("A")
elif gpa > 3.3:
letter_grade.append("A-")
elif gpa > 3.0:
letter_grade.append("B+")
elif gpa > 2.7:
... | def check(candidate):
# Check some simple cases
assert candidate([4.0, 3, 1.7, 2, 3.5]) == ['A+', 'B', 'C-', 'C', 'A-']
assert candidate([1.2]) == ['D+']
assert candidate([0.5]) == ['D-']
assert candidate([0.0]) == ['E']
assert candidate([1, 0.3, 1.5, 2.8, 3.3]) == ['D', 'D-', 'C-', 'B', 'B+']
... | numerical_letter_grade |
HumanEval/135 |
def can_arrange(arr):
"""Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
can_arrange([1,2,4,3,5]) =... | ind=-1
i=1
while i<len(arr):
if arr[i]<arr[i-1]:
ind=i
i+=1
return ind
| def check(candidate):
# Check some simple cases
assert candidate([1,2,4,3,5])==3
assert candidate([1,2,4,5])==-1
assert candidate([1,4,2,5,6,7,8,9,10])==2
assert candidate([4,8,5,7,3])==4
# Check some edge cases that are easy to work out by hand.
assert candidate([])==-1
| can_arrange |
HumanEval/154 |
def cycpattern_check(a , b):
"""You are given 2 words. You need to return True if the second word or any of its rotations is a substring in the first word
cycpattern_check("abcd","abd") => False
cycpattern_check("hello","ell") => True
cycpattern_check("whassup","psus") => False
cycpattern_check("ab... | l = len(b)
pat = b + b
for i in range(len(a) - l + 1):
for j in range(l + 1):
if a[i:i+l] == pat[j:j+l]:
return True
return False
| def check(candidate):
# Check some simple cases
#assert True, "This prints if this assert fails 1 (good for debugging!)"
# Check some edge cases that are easy to work out by hand.
#assert True, "This prints if this assert fails 2 (also good for debugging!)"
assert candidate("xyzw","xyw") == False... | cycpattern_check |
HumanEval/13 |
def greatest_common_divisor(a: int, b: int) -> int:
""" Return a greatest common divisor of two integers a and b
>>> greatest_common_divisor(3, 5)
1
>>> greatest_common_divisor(25, 15)
5
"""
| while b:
a, b = b, a % b
return a
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate(3, 7) == 1
assert candidate(10, 15) == 5
assert candidate(49, 14) == 7
assert candidate(144, 60) == 12
| greatest_common_divisor |
HumanEval/129 |
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You... | n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i !... | def check(candidate):
# Check some simple cases
print
assert candidate([[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3) == [1, 2, 1]
assert candidate([[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1) == [1]
assert candidate([[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4) == [1, 2, 1, 2]
assert can... | minPath |
HumanEval/98 |
def count_upper(s):
"""
Given a string s, count the number of uppercase vowels in even indices.
For example:
count_upper('aBCdEf') returns 1
count_upper('abcdefg') returns 0
count_upper('dBBE') returns 0
"""
| count = 0
for i in range(0,len(s),2):
if s[i] in "AEIOU":
count += 1
return count
| def check(candidate):
# Check some simple cases
assert candidate('aBCdEf') == 1
assert candidate('abcdefg') == 0
assert candidate('dBBE') == 0
assert candidate('B') == 0
assert candidate('U') == 1
assert candidate('') == 0
assert candidate('EEEE') == 2
# Check some edge cases th... | count_upper |
HumanEval/5 | from typing import List
def intersperse(numbers: List[int], delimeter: int) -> List[int]:
""" Insert a number 'delimeter' between every two consecutive elements of input list `numbers'
>>> intersperse([], 4)
[]
>>> intersperse([1, 2, 3], 4)
[1, 4, 2, 4, 3]
"""
| if not numbers:
return []
result = []
for n in numbers[:-1]:
result.append(n)
result.append(delimeter)
result.append(numbers[-1])
return result
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([], 7) == []
assert candidate([5, 6, 3, 2], 8) == [5, 8, 6, 8, 3, 8, 2]
assert candidate([2, 2, 2], 2) == [2, 2, 2, 2, 2]
| intersperse |
HumanEval/87 |
def get_row(lst, x):
"""
You are given a 2 dimensional data, as a nested lists,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the list,
and return list of tuples, [(x1, y1), (x2, y2) ...] su... | coords = [(i, j) for i in range(len(lst)) for j in range(len(lst[i])) if lst[i][j] == x]
return sorted(sorted(coords, key=lambda x: x[1], reverse=True), key=lambda x: x[0])
| def check(candidate):
# Check some simple cases
assert candidate([
[1,2,3,4,5,6],
[1,2,3,4,1,6],
[1,2,3,4,5,1]
], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
assert candidate([
[1,2,3,4,5,6],
[1,2,3,4,5,6],
[1,2,3,4,5,6],
[1,2,3,4,5,6],
... | get_row |
HumanEval/48 |
def is_palindrome(text: str):
"""
Checks if given string is a palindrome
>>> is_palindrome('')
True
>>> is_palindrome('aba')
True
>>> is_palindrome('aaaaa')
True
>>> is_palindrome('zbcd')
False
"""
| for i in range(len(text)):
if text[i] != text[len(text) - 1 - i]:
return False
return True
|
METADATA = {}
def check(candidate):
assert candidate('') == True
assert candidate('aba') == True
assert candidate('aaaaa') == True
assert candidate('zbcd') == False
assert candidate('xywyx') == True
assert candidate('xywyz') == False
assert candidate('xywzx') == False
| is_palindrome |
HumanEval/143 |
def words_in_sentence(sentence):
"""
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new stri... | new_lst = []
for word in sentence.split():
flg = 0
if len(word) == 1:
flg = 1
for i in range(2, len(word)):
if len(word)%i == 0:
flg = 1
if flg == 0 or len(word) == 2:
new_lst.append(word)
return " ".join(new_lst)
| def check(candidate):
# Check some simple cases
assert candidate("This is a test") == "is"
assert candidate("lets go for swimming") == "go for"
assert candidate("there is no place available here") == "there is no place"
assert candidate("Hi I am Hussein") == "Hi am Hussein"
assert candidate("go... | words_in_sentence |
HumanEval/89 |
def encrypt(s):
"""Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated.
The alphabet should be rotated in a manner such that the letters
shift down by two multiplied to two places.
For example:
encrypt('hi') returns 'lm'
... | d = 'abcdefghijklmnopqrstuvwxyz'
out = ''
for c in s:
if c in d:
out += d[(d.index(c)+2*2) % 26]
else:
out += c
return out
| def check(candidate):
# Check some simple cases
assert candidate('hi') == 'lm', "This prints if this assert fails 1 (good for debugging!)"
assert candidate('asdfghjkl') == 'ewhjklnop', "This prints if this assert fails 1 (good for debugging!)"
assert candidate('gf') == 'kj', "This prints if this assert... | encrypt |
HumanEval/120 |
def maximum(arr, k):
"""
Given an array arr of integers and a positive integer k, return a sorted list
of length k with the maximum k numbers in arr.
Example 1:
Input: arr = [-3, -4, 5], k = 3
Output: [-4, -3, 5]
Example 2:
Input: arr = [4, -4, 4], k = 2
Output:... | if k == 0:
return []
arr.sort()
ans = arr[-k:]
return ans
| def check(candidate):
# Check some simple cases
assert candidate([-3, -4, 5], 3) == [-4, -3, 5]
assert candidate([4, -4, 4], 2) == [4, 4]
assert candidate([-3, 2, 1, 2, -1, -2, 1], 1) == [2]
assert candidate([123, -123, 20, 0 , 1, 2, -3], 3) == [2, 20, 123]
assert candidate([-123, 20, 0 , 1, 2,... | maximum |
HumanEval/162 |
def string_to_md5(text):
"""
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return None.
>>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'
"""
| import hashlib
return hashlib.md5(text.encode('ascii')).hexdigest() if text else None
| def check(candidate):
# Check some simple cases
assert candidate('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'
assert candidate('') == None
assert candidate('A B C') == '0ef78513b0cb8cef12743f5aeb35f888'
assert candidate('password') == '5f4dcc3b5aa765d61d8327deb882cf99'
# Check some edg... | string_to_md5 |
HumanEval/149 |
def sorted_list_sum(lst):
"""Write a function that accepts a list of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted list with a sorted order,
The list is always a list of strings and never an array of numbers,
and it may contain duplicates.
T... | lst.sort()
new_lst = []
for i in lst:
if len(i)%2 == 0:
new_lst.append(i)
return sorted(new_lst, key=len)
| def check(candidate):
# Check some simple cases
assert candidate(["aa", "a", "aaa"]) == ["aa"]
assert candidate(["school", "AI", "asdf", "b"]) == ["AI", "asdf", "school"]
assert candidate(["d", "b", "c", "a"]) == []
assert candidate(["d", "dcba", "abcd", "a"]) == ["abcd", "dcba"]
# Check some ... | sorted_list_sum |
HumanEval/114 |
def minSubArraySum(nums):
"""
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
minSubArraySum([-1, -2, -3]) == -6
"""
| max_sum = 0
s = 0
for num in nums:
s += -num
if (s < 0):
s = 0
max_sum = max(s, max_sum)
if max_sum == 0:
max_sum = max(-i for i in nums)
min_sum = -max_sum
return min_sum
| def check(candidate):
# Check some simple cases
assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
assert candidate([-1, -2, -3]) == -6
assert candidate([-1, -2, -3, 2, -10]) == -14
assert candidate([-9999999999999999]) == -9999999999999999
ass... | minSubArraySum |
HumanEval/45 |
def triangle_area(a, h):
"""Given length of a side and high return area for a triangle.
>>> triangle_area(5, 3)
7.5
"""
| return a * h / 2.0
|
METADATA = {}
def check(candidate):
assert candidate(5, 3) == 7.5
assert candidate(2, 2) == 2.0
assert candidate(10, 8) == 40.0
| triangle_area |
HumanEval/90 |
def next_smallest(lst):
"""
You are given a list of integers.
Write a function next_smallest() that returns the 2nd smallest element of the list.
Return None if there is no such element.
next_smallest([1, 2, 3, 4, 5]) == 2
next_smallest([5, 1, 4, 3, 2]) == 2
next_smallest([]) == None
... | lst = sorted(set(lst))
return None if len(lst) < 2 else lst[1]
| def check(candidate):
# Check some simple cases
assert candidate([1, 2, 3, 4, 5]) == 2
assert candidate([5, 1, 4, 3, 2]) == 2
assert candidate([]) == None
assert candidate([1, 1]) == None
assert candidate([1,1,1,1,0]) == 1
assert candidate([1, 0**0]) == None
assert candidate([-35, 34, 1... | next_smallest |
HumanEval/18 |
def how_many_times(string: str, substring: str) -> int:
""" Find how many times a given substring can be found in the original string. Count overlaping cases.
>>> how_many_times('', 'a')
0
>>> how_many_times('aaa', 'a')
3
>>> how_many_times('aaaa', 'aa')
3
"""
| times = 0
for i in range(len(string) - len(substring) + 1):
if string[i:i+len(substring)] == substring:
times += 1
return times
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('', 'x') == 0
assert candidate('xyxyxyx', 'x') == 4
assert candidate('cacacacac', 'cac') == 4
assert candidate('john doe', 'john') == 1
| how_many_times |
HumanEval/148 |
def bf(planet1, planet2):
'''
There are eight planets in our solar system: the closerst to the Sun
is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn,
Uranus, Neptune.
Write a function that takes two planet names as strings planet1 and planet2.
The function should return a ... | planet_names = ("Mercury", "Venus", "Earth", "Mars", "Jupiter", "Saturn", "Uranus", "Neptune")
if planet1 not in planet_names or planet2 not in planet_names or planet1 == planet2:
return ()
planet1_index = planet_names.index(planet1)
planet2_index = planet_names.index(planet2)
if planet1_ind... | def check(candidate):
# Check some simple cases
assert candidate("Jupiter", "Neptune") == ("Saturn", "Uranus"), "First test error: " + str(len(candidate("Jupiter", "Neptune")))
assert candidate("Earth", "Mercury") == ("Venus",), "Second test error: " + str(candidate("Earth", "Mercury"))
assert ... | bf |
HumanEval/78 |
def hex_key(num):
"""You have been tasked to write a function that receives
a hexadecimal number as a string and counts the number of hexadecimal
digits that are primes (prime number, or a prime, is a natural number
greater than 1 that is not a product of two smaller natural numbers).
Hexadecima... | primes = ('2', '3', '5', '7', 'B', 'D')
total = 0
for i in range(0, len(num)):
if num[i] in primes:
total += 1
return total
| def check(candidate):
# Check some simple cases
assert candidate("AB") == 1, "First test error: " + str(candidate("AB"))
assert candidate("1077E") == 2, "Second test error: " + str(candidate("1077E"))
assert candidate("ABED1A33") == 4, "Third test error: " + str(candidate("ABED1A33"))
... | hex_key |
HumanEval/72 |
def will_it_fly(q,w):
'''
Write a function that returns True if the object q will fly, and False otherwise.
The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
will_it_fly([1, 2], 5) ➞ False
... | if sum(q) > w:
return False
i, j = 0, len(q)-1
while i<j:
if q[i] != q[j]:
return False
i+=1
j-=1
return True
| def check(candidate):
# Check some simple cases
assert candidate([3, 2, 3], 9) is True
assert candidate([1, 2], 5) is False
assert candidate([3], 5) is True
assert candidate([3, 2, 3], 1) is False
# Check some edge cases that are easy to work out by hand.
assert candidate([1, 2, 3], 6) is... | will_it_fly |
HumanEval/124 |
def valid_date(date):
"""You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31... | try:
date = date.strip()
month, day, year = date.split('-')
month, day, year = int(month), int(day), int(year)
if month < 1 or month > 12:
return False
if month in [1,3,5,7,8,10,12] and day < 1 or day > 31:
return False
if month in [4,6,9,11] a... | def check(candidate):
# Check some simple cases
assert candidate('03-11-2000') == True
assert candidate('15-01-2012') == False
assert candidate('04-0-2040') == False
assert candidate('06-04-2020') == True
assert candidate('01-01-2007') == True
assert candidate('03-32-2011') == False
... | valid_date |
HumanEval/73 |
def smallest_change(arr):
"""
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For... | ans = 0
for i in range(len(arr) // 2):
if arr[i] != arr[len(arr) - i - 1]:
ans += 1
return ans
| def check(candidate):
# Check some simple cases
assert candidate([1,2,3,5,4,7,9,6]) == 4
assert candidate([1, 2, 3, 4, 3, 2, 2]) == 1
assert candidate([1, 4, 2]) == 1
assert candidate([1, 4, 4, 2]) == 1
# Check some edge cases that are easy to work out by hand.
assert candidate([1, 2, 3, 2... | smallest_change |
HumanEval/86 |
def anti_shuffle(s):
"""
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should ... | return ' '.join([''.join(sorted(list(i))) for i in s.split(' ')])
| def check(candidate):
# Check some simple cases
assert candidate('Hi') == 'Hi'
assert candidate('hello') == 'ehllo'
assert candidate('number') == 'bemnru'
assert candidate('abcd') == 'abcd'
assert candidate('Hello World!!!') == 'Hello !!!Wdlor'
assert candidate('') == ''
assert candidat... | anti_shuffle |
HumanEval/21 | from typing import List
def rescale_to_unit(numbers: List[float]) -> List[float]:
""" Given list of numbers (of at least two elements), apply a linear transform to that list,
such that the smallest number will become 0 and the largest will become 1
>>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])
[0.0, ... | min_number = min(numbers)
max_number = max(numbers)
return [(x - min_number) / (max_number - min_number) for x in numbers]
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([2.0, 49.9]) == [0.0, 1.0]
assert candidate([100.0, 49.9]) == [1.0, 0.0]
assert candidate([1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
assert candidate([2.0, 1.0, 5.0, 3.0, 4.0]) == [0.25, 0.... | rescale_to_unit |
HumanEval/91 |
def is_bored(S):
"""
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
>>> is_bored("Hello world")
0
>>> is_bored("The sky is blue. The ... | import re
sentences = re.split(r'[.?!]\s*', S)
return sum(sentence[0:2] == 'I ' for sentence in sentences)
| def check(candidate):
# Check some simple cases
assert candidate("Hello world") == 0, "Test 1"
assert candidate("Is the sky blue?") == 0, "Test 2"
assert candidate("I love It !") == 1, "Test 3"
assert candidate("bIt") == 0, "Test 4"
assert candidate("I feel good today. I will be productive. wil... | is_bored |
HumanEval/59 |
def largest_prime_factor(n: int):
"""Return the largest prime factor of n. Assume n > 1 and is not a prime.
>>> largest_prime_factor(13195)
29
>>> largest_prime_factor(2048)
2
"""
| def is_prime(k):
if k < 2:
return False
for i in range(2, k - 1):
if k % i == 0:
return False
return True
largest = 1
for j in range(2, n + 1):
if n % j == 0 and is_prime(j):
largest = max(largest, j)
return largest
|
METADATA = {}
def check(candidate):
assert candidate(15) == 5
assert candidate(27) == 3
assert candidate(63) == 7
assert candidate(330) == 11
assert candidate(13195) == 29
| largest_prime_factor |
HumanEval/65 |
def circular_shift(x, shift):
"""Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
>>> circular_shift(12, 1)
"21"
>>> circular_shift(12, 2)
"12"
"""
| s = str(x)
if shift > len(s):
return s[::-1]
else:
return s[len(s) - shift:] + s[:len(s) - shift]
| def check(candidate):
# Check some simple cases
assert candidate(100, 2) == "001"
assert candidate(12, 2) == "12"
assert candidate(97, 8) == "79"
assert candidate(12, 1) == "21", "This prints if this assert fails 1 (good for debugging!)"
# Check some edge cases that are easy to work out by han... | circular_shift |
HumanEval/94 |
def skjkasdkd(lst):
"""You are given a list of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
For lst = [0,3,2,1,3,5,7,4,5,5,5,2,181,32,4,32,3,2,32,324,4,3] the output should be 10
For lst = [1,0,1,8,2,4597,2,1,3,40,1,2,1,2,4,2,5,1] the output shoul... | def isPrime(n):
for i in range(2,int(n**0.5)+1):
if n%i==0:
return False
return True
maxx = 0
i = 0
while i < len(lst):
if(lst[i] > maxx and isPrime(lst[i])):
maxx = lst[i]
i+=1
result = sum(int(digit) for digit in str(maxx))
... | def check(candidate):
# Check some simple cases
assert candidate([0,3,2,1,3,5,7,4,5,5,5,2,181,32,4,32,3,2,32,324,4,3]) == 10, "This prints if this assert fails 1 (good for debugging!)"
# Check some edge cases that are easy to work out by hand.
assert candidate([1,0,1,8,2,4597,2,1,3,40,1,2,1,2,4,2,5,1]... | skjkasdkd |
HumanEval/71 |
def triangle_area(a, b, c):
'''
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle.
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater
than the thi... | if a + b <= c or a + c <= b or b + c <= a:
return -1
s = (a + b + c)/2
area = (s * (s - a) * (s - b) * (s - c)) ** 0.5
area = round(area, 2)
return area
| def check(candidate):
# Check some simple cases
assert candidate(3, 4, 5) == 6.00, "This prints if this assert fails 1 (good for debugging!)"
assert candidate(1, 2, 10) == -1
assert candidate(4, 8, 5) == 8.18
assert candidate(2, 2, 2) == 1.73
assert candidate(1, 2, 3) == -1
assert candidate... | triangle_area |
HumanEval/131 |
def digits(n):
"""Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(1) == 1
digits(4) == 0
digits(235) == 15
"""
| product = 1
odd_count = 0
for digit in str(n):
int_digit = int(digit)
if int_digit%2 == 1:
product= product*int_digit
odd_count+=1
if odd_count ==0:
return 0
else:
return product
| def check(candidate):
# Check some simple cases
assert candidate(5) == 5
assert candidate(54) == 5
assert candidate(120) ==1
assert candidate(5014) == 5
assert candidate(98765) == 315
assert candidate(5576543) == 2625
# Check some edge cases that are easy to work out by hand.
asser... | digits |
HumanEval/116 |
def sort_array(arr):
"""
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
>>> sort_array([1, 5, 2, 3, 4]) ==... | return sorted(sorted(arr), key=lambda x: bin(x)[2:].count('1'))
| def check(candidate):
# Check some simple cases
assert True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate([1,5,2,3,4]) == [1, 2, 4, 3, 5]
assert candidate([-2,-3,-4,-5,-6]) == [-4, -2, -6, -5, -3]
assert candidate([1,0,2,3,4]) == [0, 1, 2, 4, 3]
assert candidate([... | sort_array |
HumanEval/26 | from typing import List
def remove_duplicates(numbers: List[int]) -> List[int]:
""" From a list of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
>>> remove_duplicates([1, 2, 3, 2, 4])
[1, 3, 4]
"""
| import collections
c = collections.Counter(numbers)
return [n for n in numbers if c[n] <= 1]
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([]) == []
assert candidate([1, 2, 3, 4]) == [1, 2, 3, 4]
assert candidate([1, 2, 3, 2, 4, 3, 5]) == [1, 4, 5]
| remove_duplicates |
HumanEval/103 |
def rounded_avg(n, m):
"""You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
rounded_avg(1, 5)... | if m < n:
return -1
summation = 0
for i in range(n, m+1):
summation += i
return bin(round(summation/(m - n + 1)))
| def check(candidate):
# Check some simple cases
assert candidate(1, 5) == "0b11"
assert candidate(7, 13) == "0b1010"
assert candidate(964,977) == "0b1111001010"
assert candidate(996,997) == "0b1111100100"
assert candidate(560,851) == "0b1011000010"
assert candidate(185,546) == "0b101101110"... | rounded_avg |
HumanEval/146 |
def specialFilter(nums):
"""Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter([15, -73, 14, -15]) => 1
specialFilter(... |
count = 0
for num in nums:
if num > 10:
odd_digits = (1, 3, 5, 7, 9)
number_as_string = str(num)
if int(number_as_string[0]) in odd_digits and int(number_as_string[-1]) in odd_digits:
count += 1
return count
| def check(candidate):
# Check some simple cases
assert candidate([5, -2, 1, -5]) == 0
assert candidate([15, -73, 14, -15]) == 1
assert candidate([33, -2, -3, 45, 21, 109]) == 2
assert candidate([43, -12, 93, 125, 121, 109]) == 4
assert candidate([71, -2, -33, 75, 21, 19]) == 3
# Check s... | specialFilter |
HumanEval/96 |
def count_up_to(n):
"""Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
count_up_to(5) => [2,3]
count_up_to(11) => [2,3,5,7]
count_up_to(0) => []
count_up_to(20) => [2,3,5,7,11,13,17,19]... | primes = []
for i in range(2, n):
is_prime = True
for j in range(2, i):
if i % j == 0:
is_prime = False
break
if is_prime:
primes.append(i)
return primes
| def check(candidate):
assert candidate(5) == [2,3]
assert candidate(6) == [2,3,5]
assert candidate(7) == [2,3,5]
assert candidate(10) == [2,3,5,7]
assert candidate(0) == []
assert candidate(22) == [2,3,5,7,11,13,17,19]
assert candidate(1) == []
assert candidate(18) == [2,3,5,7,11,13,17]... | count_up_to |
HumanEval/153 |
def Strongest_Extension(class_name, extensions):
"""You will be given the name of a class (a string) and a list of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extens... | strong = extensions[0]
my_val = len([x for x in extensions[0] if x.isalpha() and x.isupper()]) - len([x for x in extensions[0] if x.isalpha() and x.islower()])
for s in extensions:
val = len([x for x in s if x.isalpha() and x.isupper()]) - len([x for x in s if x.isalpha() and x.islower()])
i... | def check(candidate):
# Check some simple cases
assert candidate('Watashi', ['tEN', 'niNE', 'eIGHt8OKe']) == 'Watashi.eIGHt8OKe'
assert candidate('Boku123', ['nani', 'NazeDa', 'YEs.WeCaNe', '32145tggg']) == 'Boku123.YEs.WeCaNe'
assert candidate('__YESIMHERE', ['t', 'eMptY', 'nothing', 'zeR00', 'NuLl__'... | Strongest_Extension |
HumanEval/74 |
def total_match(lst1, lst2):
'''
Write a function that accepts two lists of strings and returns the list that has
total number of chars in the all strings of the list less than the other list.
if the two lists have the same number of chars, return the first list.
Examples
total_match([], [])... | l1 = 0
for st in lst1:
l1 += len(st)
l2 = 0
for st in lst2:
l2 += len(st)
if l1 <= l2:
return lst1
else:
return lst2
| def check(candidate):
# Check some simple cases
assert True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate([], []) == []
assert candidate(['hi', 'admin'], ['hi', 'hi']) == ['hi', 'hi']
assert candidate(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) == ['hi', 'admin... | total_match |
HumanEval/10 |
def is_palindrome(string: str) -> bool:
""" Test if given string is a palindrome """
return string == string[::-1]
def make_palindrome(string: str) -> str:
""" Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string... | if not string:
return ''
beginning_of_suffix = 0
while not is_palindrome(string[beginning_of_suffix:]):
beginning_of_suffix += 1
return string + string[:beginning_of_suffix][::-1]
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('') == ''
assert candidate('x') == 'x'
assert candidate('xyz') == 'xyzyx'
assert candidate('xyx') == 'xyx'
assert candidate('jerry') == 'jerryrrej'
| make_palindrome |
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