message stringlengths 2 23.4k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 129 108k | cluster float64 6 6 | __index_level_0__ int64 258 216k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
The Beroil corporation structure is hierarchical, that is it can be represented as a tree. Let's examine the presentation of this structure as follows:
* employee ::= name. | name:employee1,employee2, ... ,employeek.
* name ::= name of ... | instruction | 0 | 101,609 | 6 | 203,218 |
Tags: data structures, expression parsing, implementation
Correct Solution:
```
def main():
alpha = "QWERTYUIOPLKJHGFDSAZXCVBNM"
s = input()
n = len(s)
i = 0
st = []
ans = 0
while i < n:
j = i
if s[i] in alpha:
while j+1 < n and s[j+1] in alpha:
j ... | output | 1 | 101,609 | 6 | 203,219 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The Beroil corporation structure is hierarchical, that is it can be represented as a tree. Let's examine the presentation of this structure as follows:
* employee ::= name. | name:employee1,employee2, ... ,employeek.
* name ::= name of ... | instruction | 0 | 101,610 | 6 | 203,220 |
Tags: data structures, expression parsing, implementation
Correct Solution:
```
s = input()
a = []
cnt = 0
s = ':' + s
s1 = ''
flag = False
for i in range(len(s)):
if flag:
if s[i] != '.' and s[i] != ':' and s[i] != ',':
s1 += s[i]
continue
else:
a.app... | output | 1 | 101,610 | 6 | 203,221 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The Beroil corporation structure is hierarchical, that is it can be represented as a tree. Let's examine the presentation of this structure as follows:
* employee ::= name. | name:employee1,employee2, ... ,employeek.
* name ::= name of ... | instruction | 0 | 101,611 | 6 | 203,222 |
Tags: data structures, expression parsing, implementation
Correct Solution:
```
#!/usr/bin/env python3
tree = input().strip()
def get_answer(tree, start_index = 0, prev = []):
colon_index = tree.find(':', start_index)
period_index = tree.find('.', start_index)
name_end_index = colon_index if ((colon_index != -... | output | 1 | 101,611 | 6 | 203,223 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The Beroil corporation structure is hierarchical, that is it can be represented as a tree. Let's examine the presentation of this structure as follows:
* employee ::= name. | name:employee1,employee2, ... ,employeek.
* name ::= name of ... | instruction | 0 | 101,612 | 6 | 203,224 |
Tags: data structures, expression parsing, implementation
Correct Solution:
```
def main():
alpha = "QWERTYUIOPLKJHGFDSAZXCVBNM"
s = input()
n = len(s)
i = 0
st = ["root-0"]
name = ""
ans = 0
first = True
while i < n:
j = i
if s[i] in alpha:
while j+1 < n ... | output | 1 | 101,612 | 6 | 203,225 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The Beroil corporation structure is hierarchical, that is it can be represented as a tree. Let's examine the presentation of this structure as follows:
* employee ::= name. | name:employee1,employee2, ... ,employeek.
* name ::= name of ... | instruction | 0 | 101,613 | 6 | 203,226 |
Tags: data structures, expression parsing, implementation
Correct Solution:
```
import sys
from array import array # noqa: F401
from collections import Counter
def input():
return sys.stdin.buffer.readline().decode('utf-8')
class Employee(object):
def __init__(self, name: str):
self.name = name
... | output | 1 | 101,613 | 6 | 203,227 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The Beroil corporation structure is hierarchical, that is it can be represented as a tree. Let's examine the presentation of this structure as follows:
* employee ::= name. | name:employee1,employee2, ... ,employeek.
* name ::= name of ... | instruction | 0 | 101,614 | 6 | 203,228 |
Tags: data structures, expression parsing, implementation
Correct Solution:
```
######directed
def dfs(graph,n,currnode,match):
visited=[False for x in range(n+1)]
stack=[currnode]
ans=0
while stack:
currnode=stack[-1]
if visited[currnode]==False:
visited[currnode]=True
... | output | 1 | 101,614 | 6 | 203,229 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The Beroil corporation structure is hierarchical, that is it can be represented as a tree. Let's examine the presentation of this structure as follows:
* employee ::= name. | name:employee1,employee2, ... ,employeek.
* name ::= name of ... | instruction | 0 | 101,615 | 6 | 203,230 |
Tags: data structures, expression parsing, implementation
Correct Solution:
```
s = input()
a = []
cnt = 0
s = ':' + s
s1 = ''
flag = False
for i in range(len(s)):
if flag:
if s[i] != '.' and s[i] != ':' and s[i] != ',':
s1 += s[i]
continue
else:
a.append(s1)
... | output | 1 | 101,615 | 6 | 203,231 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The Beroil corporation structure is hierarchical, that is it can be represented as a tree. Let's examine the presentation of this structure as follows:
* employee ::= name. | name:employee1,employee2, ... ,employeek.
* name ::= name of ... | instruction | 0 | 101,616 | 6 | 203,232 |
Tags: data structures, expression parsing, implementation
Correct Solution:
```
import re
a,ans=[],0
for x in re.split('[:,]',input()):
dl=x.count(".")
if dl==0:
ans+=a.count(x)
a+=[x]
else:
x=x[:-dl]
ans+=a.count(x)
a+=[x]
a=a[:-dl]
print(ans)
``` | output | 1 | 101,616 | 6 | 203,233 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Beroil corporation structure is hierarchical, that is it can be represented as a tree. Let's examine the presentation of this structure as follows:
* employee ::= name. | name:employee1,e... | instruction | 0 | 101,617 | 6 | 203,234 |
Yes | output | 1 | 101,617 | 6 | 203,235 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Beroil corporation structure is hierarchical, that is it can be represented as a tree. Let's examine the presentation of this structure as follows:
* employee ::= name. | name:employee1,e... | instruction | 0 | 101,618 | 6 | 203,236 |
Yes | output | 1 | 101,618 | 6 | 203,237 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Beroil corporation structure is hierarchical, that is it can be represented as a tree. Let's examine the presentation of this structure as follows:
* employee ::= name. | name:employee1,e... | instruction | 0 | 101,619 | 6 | 203,238 |
Yes | output | 1 | 101,619 | 6 | 203,239 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Beroil corporation structure is hierarchical, that is it can be represented as a tree. Let's examine the presentation of this structure as follows:
* employee ::= name. | name:employee1,e... | instruction | 0 | 101,620 | 6 | 203,240 |
No | output | 1 | 101,620 | 6 | 203,241 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a boolean function of three variables which is defined by its truth table. You need to find an expression of minimum length that equals to this function. The expression may consist of:
* Operation AND ('&', ASCII code 38)
... | instruction | 0 | 101,746 | 6 | 203,492 |
Tags: bitmasks, dp, shortest paths
Correct Solution:
```
table = "!x&x x&y&z !z&x&y x&y !y&x&z x&z !y&x&z|!z&x&y (y|z)&x !y&!z&x !y&!z&x|x&y&z !z&x !z&x|x&y !y&x !y&x|x&z !(y&z)&x x !x&y&z y&z !x&y&z|!z&x&y (x|z)&y !x&y&z|!y&x&z (x|y)&z !x&y&z|!y&x&z|!z&x&y (x|y)&z|x&y !x&y&z|!y&!z&x !y&!z&x|y&z !x&y&z|!z&x !z&x|y&z !x... | output | 1 | 101,746 | 6 | 203,493 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a boolean function of three variables which is defined by its truth table. You need to find an expression of minimum length that equals to this function. The expression may consist of:
* Operation AND ('&', ASCII code 38)
... | instruction | 0 | 101,747 | 6 | 203,494 |
Tags: bitmasks, dp, shortest paths
Correct Solution:
```
answers = [
'!x&x',
'x&y&z',
'!z&x&y',
'x&y',
'!y&x&z',
'x&z',
'!y&x&z|!z&x&y',
'(y|z)&x',
'!y&!z&x',
'!y&!z&x|x&y&z',
'!z&x',
'!z&x|x&y',
'!y&x',
'!y&x|x&z',
'!(y&z)&x',
'x',
'!x&y&z',
'y&z',
'!x&y&z|!z&x&y',
'(x|z)&y',
'!x&y&z|!y&x&z',
'(x|y)&z',
'!x&y&z|!y&x&z... | output | 1 | 101,747 | 6 | 203,495 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a boolean function of three variables which is defined by its truth table. You need to find an expression of minimum length that equals to this function. The expression may consist of:
* Operation AND ('&', ASCII code 38)
... | instruction | 0 | 101,748 | 6 | 203,496 |
Tags: bitmasks, dp, shortest paths
Correct Solution:
```
sol = {'01010101': 'z', '00110011': 'y', '00001111': 'x', '10101010': '!z', '11001100': '!y', '11110000': '!x', '01110111': 'y|z', '01011111': 'x|z', '00010001': 'y&z', '00000101': 'x&z', '00111111': 'x|y', '00000011': 'x&y', '11111111': '!x|x', '11011101': '!y|z... | output | 1 | 101,748 | 6 | 203,497 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a boolean function of three variables which is defined by its truth table. You need to find an expression of minimum length that equals to this function. The expression may consist of:
* Operation AND ('&', ASCII code 38)
... | instruction | 0 | 101,749 | 6 | 203,498 |
Tags: bitmasks, dp, shortest paths
Correct Solution:
```
import zlib, base64
exec(zlib.decompress(base64.b64decode(b'eJyFV8lu2zAQPTdfIenAUGhR9FygXxLk4MJu4SJwAscJSIEfX4nLzHtDpT0kGM6+j3w83IYfw8M0BhemL8M0+pBiWuYMBzdGtwjYgMUpWGRWtnFJq6Srkh7g4JqSjW9Jm3wKjdYohIzALkivfuX/m02nYBUJ2ZNVLjZPAM5hrFTR5BFGasLg/RbOvPniIsSU0AXAtMgMnan... | output | 1 | 101,749 | 6 | 203,499 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a boolean function of three variables which is defined by its truth table. You need to find an expression of minimum length that equals to this function. The expression may consist of:
* Operation AND ('&', ASCII code 38)
... | instruction | 0 | 101,750 | 6 | 203,500 |
Tags: bitmasks, dp, shortest paths
Correct Solution:
```
val='''!x&x
x&y&z
!z&x&y
x&y
!y&x&z
x&z
!y&x&z|!z&x&y
(y|z)&x
!y&!z&x
!y&!z&x|x&y&z
!z&x
!z&x|x&y
!y&x
!y&x|x&z
!(y&z)&x
x
!x&y&z
y&z
!x&y&z|!z&x&y
(x|z)&y
!x&y&z|!y&x&z
(x|y)&z
!x&y&z|!y&x&z|!z&x&y
(x|y)&z|x&y
!x&y&z|!y&!z&x
!y&!z&x|y&z
!x&y&z|!z&x
!z&x|y&z
!x&y... | output | 1 | 101,750 | 6 | 203,501 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a boolean function of three variables which is defined by its truth table. You need to find an expression of minimum length that equals to this function. The expression may consist of:
* Operation AND ('&', ASCII code 38)
... | instruction | 0 | 101,751 | 6 | 203,502 |
Tags: bitmasks, dp, shortest paths
Correct Solution:
```
f =['!x&x', '!(x|y|z)', '!x&!y&z', '!x&!y', '!x&!z&y', '!x&!z', '!(!y&!z|x|y&z)', '!(x|y&z)', '!x&y&z', '!(!y&z|!z&y|x)', '!x&z', '!(!z&y|x)', '!x&y', '!(!y&z|x)', '!x&(y|z)', '!x', '!y&!z&x', '!y&!z', '!(!x&!z|x&z|y)', '!(x&z|y)', '!(!x&!y|x&y|z)', '!(x&y|z)', '... | output | 1 | 101,751 | 6 | 203,503 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a boolean function of three variables which is defined by its truth table. You need to find an expression of minimum length that equals to this function. The expression may consist of:
* Operation AND ('&', ASCII code 38)
... | instruction | 0 | 101,752 | 6 | 203,504 |
Tags: bitmasks, dp, shortest paths
Correct Solution:
```
# -*- coding: utf-8 -*-
dat = "硼磷碳磷溴硼氧磷氮硫氮氯氟溴硼磷碳硼硫碳氯溴硼磷碳硼硫溴硼磷碳硼氯碳硫溴硼磷碳硼氯溴硼氧硼硫碳硼氯氮磷氮硫碳氯氟溴硼氧磷氮硫碳氯氟溴硼磷碳硫碳氯溴硼氧硼硫碳氯氮硼氯碳硫氮磷氟溴硼磷碳氯溴硼氧硼氯碳硫氮磷氟溴硼磷碳硫溴硼氧硼硫碳氯氮磷氟溴硼磷碳氧硫氮氯氟溴硼磷溴硼硫碳硼氯碳磷溴硼硫碳硼氯溴硼氧硼磷碳硼氯氮磷碳氯氮硫氟溴硼氧磷碳氯氮硫氟溴硼氧硼磷碳硼硫氮磷碳硫氮氯氟溴硼氧磷碳硫氮氯氟溴硼氧硼磷碳硼硫氮磷碳硫氮氯氟氮硼磷碳硼硫碳氯溴硼氧氧磷氮硫氟碳氯氮磷碳硫氟溴硼磷... | output | 1 | 101,752 | 6 | 203,505 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The letters shop showcase is a string s, consisting of n lowercase Latin letters. As the name tells, letters are sold in the shop.
Letters are sold one by one from the leftmost to the rightmost. Any customer can only buy some prefix of lett... | instruction | 0 | 102,072 | 6 | 204,144 |
Tags: binary search, implementation, strings
Correct Solution:
```
from collections import Counter
def contains(a, b):
for k in a.keys():
if a[k] > b[k]:
return False
return True
_ = int(input())
letters = input()
T = int(input())
memo = {}
for t in range(T):
name = input()
ctr =... | output | 1 | 102,072 | 6 | 204,145 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The letters shop showcase is a string s, consisting of n lowercase Latin letters. As the name tells, letters are sold in the shop.
Letters are sold one by one from the leftmost to the rightmost. Any customer can only buy some prefix of lett... | instruction | 0 | 102,073 | 6 | 204,146 |
Tags: binary search, implementation, strings
Correct Solution:
```
import copy
n = int(input())
s = input()
d = {}
for i in range(n):
if s[i] not in d:
d[s[i]] = [i]
else:
d[s[i]].append(i)
m = int(input())
for _ in range(m):
t = input()
dx = {i:0 for i in d}
ma = 0
for i in t:
... | output | 1 | 102,073 | 6 | 204,147 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The letters shop showcase is a string s, consisting of n lowercase Latin letters. As the name tells, letters are sold in the shop.
Letters are sold one by one from the leftmost to the rightmost. Any customer can only buy some prefix of lett... | instruction | 0 | 102,074 | 6 | 204,148 |
Tags: binary search, implementation, strings
Correct Solution:
```
#------------------------template--------------------------#
import os
import sys
from math import *
from collections import *
from fractions import *
from bisect import *
from heapq import*
from io import BytesIO, IOBase
def vsInput():
sys.stdin = ... | output | 1 | 102,074 | 6 | 204,149 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The letters shop showcase is a string s, consisting of n lowercase Latin letters. As the name tells, letters are sold in the shop.
Letters are sold one by one from the leftmost to the rightmost. Any customer can only buy some prefix of lett... | instruction | 0 | 102,075 | 6 | 204,150 |
Tags: binary search, implementation, strings
Correct Solution:
```
n =int(input())
main = input()
dic ={}
for i in range(n):
if main[i] in dic:
dic[main[i]].append(i)
else:
dic[main[i]]=[i]
num = int(input())
for i in range(num):
a = 0
name = input()
dic_name ={}
for i in range(len(name)):
if name[i] in di... | output | 1 | 102,075 | 6 | 204,151 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The letters shop showcase is a string s, consisting of n lowercase Latin letters. As the name tells, letters are sold in the shop.
Letters are sold one by one from the leftmost to the rightmost. Any customer can only buy some prefix of lett... | instruction | 0 | 102,076 | 6 | 204,152 |
Tags: binary search, implementation, strings
Correct Solution:
```
n=int(input())
s=input()
d={}
for i in range(len(s)):
if(s[i] in d):
d[s[i]].append(i+1)
else:
d[s[i]]=[i+1]
for _ in range(int(input())):
res=[]
s=input()
f={}
for i in range(len(s)):
if(s[i] in f):
... | output | 1 | 102,076 | 6 | 204,153 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The letters shop showcase is a string s, consisting of n lowercase Latin letters. As the name tells, letters are sold in the shop.
Letters are sold one by one from the leftmost to the rightmost. Any customer can only buy some prefix of lett... | instruction | 0 | 102,077 | 6 | 204,154 |
Tags: binary search, implementation, strings
Correct Solution:
```
from collections import Counter,defaultdict
n=int(input())
s=str(input())
a=defaultdict(list)
for i in range(len(s)):
a[s[i]].append(i)
for j in range(int(input())):
t=Counter(input())
#print(t)
p=max([a[o][t[o]-1]for o in t])
print(... | output | 1 | 102,077 | 6 | 204,155 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The letters shop showcase is a string s, consisting of n lowercase Latin letters. As the name tells, letters are sold in the shop.
Letters are sold one by one from the leftmost to the rightmost. Any customer can only buy some prefix of lett... | instruction | 0 | 102,078 | 6 | 204,156 |
Tags: binary search, implementation, strings
Correct Solution:
```
n=int(input())
s=input()
dic={}
for i in range(n):
if(s[i] in dic):
dic[s[i]].append(i+1)
else:
dic[s[i]]=[i+1]
# print(d)
q=int(input())
while(q>0):
x=input()
temp=0
aux={}
for i in range(len(x)):
if(x[i]... | output | 1 | 102,078 | 6 | 204,157 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The letters shop showcase is a string s, consisting of n lowercase Latin letters. As the name tells, letters are sold in the shop.
Letters are sold one by one from the leftmost to the rightmost. Any customer can only buy some prefix of lett... | instruction | 0 | 102,079 | 6 | 204,158 |
Tags: binary search, implementation, strings
Correct Solution:
```
n = int(input())
l = list(input())
d = dict()
for i in set(l):
d[i] = ([k for k, n in enumerate(l) if n == i])
for i in range(int(input())):
s = input()
mx = 0
dc = dict()
for i in s:
j = dc.get(i, 0)
mx = max(mx,... | output | 1 | 102,079 | 6 | 204,159 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The letters shop showcase is a string s, consisting of n lowercase Latin letters. As the name tells, letters are sold in the shop.
Letters are sold one by one from the leftmost to the rightmost... | instruction | 0 | 102,080 | 6 | 204,160 |
Yes | output | 1 | 102,080 | 6 | 204,161 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The letters shop showcase is a string s, consisting of n lowercase Latin letters. As the name tells, letters are sold in the shop.
Letters are sold one by one from the leftmost to the rightmost... | instruction | 0 | 102,081 | 6 | 204,162 |
Yes | output | 1 | 102,081 | 6 | 204,163 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The letters shop showcase is a string s, consisting of n lowercase Latin letters. As the name tells, letters are sold in the shop.
Letters are sold one by one from the leftmost to the rightmost... | instruction | 0 | 102,082 | 6 | 204,164 |
Yes | output | 1 | 102,082 | 6 | 204,165 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The letters shop showcase is a string s, consisting of n lowercase Latin letters. As the name tells, letters are sold in the shop.
Letters are sold one by one from the leftmost to the rightmost... | instruction | 0 | 102,083 | 6 | 204,166 |
Yes | output | 1 | 102,083 | 6 | 204,167 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The letters shop showcase is a string s, consisting of n lowercase Latin letters. As the name tells, letters are sold in the shop.
Letters are sold one by one from the leftmost to the rightmost... | instruction | 0 | 102,084 | 6 | 204,168 |
No | output | 1 | 102,084 | 6 | 204,169 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The letters shop showcase is a string s, consisting of n lowercase Latin letters. As the name tells, letters are sold in the shop.
Letters are sold one by one from the leftmost to the rightmost... | instruction | 0 | 102,085 | 6 | 204,170 |
No | output | 1 | 102,085 | 6 | 204,171 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The letters shop showcase is a string s, consisting of n lowercase Latin letters. As the name tells, letters are sold in the shop.
Letters are sold one by one from the leftmost to the rightmost... | instruction | 0 | 102,086 | 6 | 204,172 |
No | output | 1 | 102,086 | 6 | 204,173 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The letters shop showcase is a string s, consisting of n lowercase Latin letters. As the name tells, letters are sold in the shop.
Letters are sold one by one from the leftmost to the rightmost... | instruction | 0 | 102,087 | 6 | 204,174 |
No | output | 1 | 102,087 | 6 | 204,175 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You have a description of a lever as string s. We'll represent the string length as record |s|, then the lever looks as a horizontal bar with weights of length |s| - 1 with exactly one pivot. We will assume that the bar is a segment on the O... | instruction | 0 | 102,402 | 6 | 204,804 |
Tags: implementation, math
Correct Solution:
```
s1, s2 = map(str, input().split('^'))
l1, l2 = 0, 0
for i in range(len(s1)):
if s1[i].isdigit():
l1 += int(s1[i]) * (len(s1) - i)
for i in range(len(s2)):
if s2[i].isdigit():
l2 += int(s2[i]) * (i + 1)
if l1 == l2:
print('balance')
elif l1 > l2:
print('left')
els... | output | 1 | 102,402 | 6 | 204,805 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You have a description of a lever as string s. We'll represent the string length as record |s|, then the lever looks as a horizontal bar with weights of length |s| - 1 with exactly one pivot. We will assume that the bar is a segment on the O... | instruction | 0 | 102,403 | 6 | 204,806 |
Tags: implementation, math
Correct Solution:
```
s = input()
pivot = s.find('^')
value = 0
for i in range(len(s)):
if s[i].isdigit():
value += int(s[i]) * (i - pivot)
if value < 0:
print('left')
elif value == 0:
print('balance')
else:
print('right')
``` | output | 1 | 102,403 | 6 | 204,807 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You have a description of a lever as string s. We'll represent the string length as record |s|, then the lever looks as a horizontal bar with weights of length |s| - 1 with exactly one pivot. We will assume that the bar is a segment on the O... | instruction | 0 | 102,404 | 6 | 204,808 |
Tags: implementation, math
Correct Solution:
```
s = input().strip()
n = len(s)
i = s.find('^')
left = 0
right = 0
l = i - 1
r = i + 1
while l >= 0 or r < n:
if l >= 0 and s[l] != '=':
left += int(s[l])*(i - l)
l -= 1
else:
l -= 1
if r < n and s[r] != '=':
right += int(s[... | output | 1 | 102,404 | 6 | 204,809 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You have a description of a lever as string s. We'll represent the string length as record |s|, then the lever looks as a horizontal bar with weights of length |s| - 1 with exactly one pivot. We will assume that the bar is a segment on the O... | instruction | 0 | 102,405 | 6 | 204,810 |
Tags: implementation, math
Correct Solution:
```
a=input()
p=a.index('^')
c=sum((i-p)*int(y) for i,y in enumerate(a) if y.isdigit())
print([['balance','right'][c>0],'left'][c<0])
``` | output | 1 | 102,405 | 6 | 204,811 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You have a description of a lever as string s. We'll represent the string length as record |s|, then the lever looks as a horizontal bar with weights of length |s| - 1 with exactly one pivot. We will assume that the bar is a segment on the O... | instruction | 0 | 102,406 | 6 | 204,812 |
Tags: implementation, math
Correct Solution:
```
s = input()
p = s.index('^')
f = 0
for i in range(len(s)):
if s[i]=='1':
f = f-((p-i)*1)
elif s[i]=='2':
f = f - ((p-i)*2)
elif s[i]=='3':
f = f - ((p-i)*3)
elif s[i]=='4':
f = f - ((p-i)*4)
elif s[i]=='5':
f = ... | output | 1 | 102,406 | 6 | 204,813 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You have a description of a lever as string s. We'll represent the string length as record |s|, then the lever looks as a horizontal bar with weights of length |s| - 1 with exactly one pivot. We will assume that the bar is a segment on the O... | instruction | 0 | 102,407 | 6 | 204,814 |
Tags: implementation, math
Correct Solution:
```
s=[n for n in input()]
k=s.index('^')
a=s[:k][::-1]
b=s[k+1:]
m=0
for n in range(len(a)):
if ord('0')<=ord(a[n])<=ord('9'):
m+=int(a[n])*(n+1)
p=0
for n in range(len(b)):
if ord('0')<=ord(b[n])<=ord('9'):
p+=int(b[n])*(n+1)
if m==p:
print('balance')
elif m>p:
pri... | output | 1 | 102,407 | 6 | 204,815 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You have a description of a lever as string s. We'll represent the string length as record |s|, then the lever looks as a horizontal bar with weights of length |s| - 1 with exactly one pivot. We will assume that the bar is a segment on the O... | instruction | 0 | 102,408 | 6 | 204,816 |
Tags: implementation, math
Correct Solution:
```
a = input()
i = 0
r = 0
l = 0
while(a[i] != "^"):
i = i+1
k = i
for j in range(i):
if(a[j]!= "="):
l = l +k*int(a[j])
k = k-1
k = 1
i +=1
while(i<len(a)):
if(a[i]!= "="):
r = r+k*int(a[i])
i = i+1
k = k+1
if(r==l):
print("bala... | output | 1 | 102,408 | 6 | 204,817 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You have a description of a lever as string s. We'll represent the string length as record |s|, then the lever looks as a horizontal bar with weights of length |s| - 1 with exactly one pivot. We will assume that the bar is a segment on the O... | instruction | 0 | 102,409 | 6 | 204,818 |
Tags: implementation, math
Correct Solution:
```
# -*- coding: utf-8 -*-
s1, s2 = input().split('^')
s1 = s1[::-1]
l1 = sum([(i+1) * int(s1[i]) for i in range(len(s1)) if s1[i] != '='])
l2 = sum([(i+1) * int(s2[i]) for i in range(len(s2)) if s2[i] != '='])
print('balance' if l1==l2 else 'left' if l1>l2 else 'right')... | output | 1 | 102,409 | 6 | 204,819 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Programmer Vasya is studying a new programming language &K*. The &K* language resembles the languages of the C family in its syntax. However, it is more powerful, which is why the rules of the actual C-like languages are unapplicable to it. ... | instruction | 0 | 102,619 | 6 | 205,238 |
Tags: implementation, strings
Correct Solution:
```
import sys
from array import array # noqa: F401
def input():
return sys.stdin.buffer.readline().decode('utf-8')
n = int(input())
name = {'void': 'void'}
errtype = 'errtype'
def resolve(t):
nest = 0
while t[-1] == '*':
nest += 1
t = t... | output | 1 | 102,619 | 6 | 205,239 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Programmer Vasya is studying a new programming language &K*. The &K* language resembles the languages of the C family in its syntax. However, it is more powerful, which is why the rules of the actual C-like languages are unapplicable to it. ... | instruction | 0 | 102,620 | 6 | 205,240 |
Tags: implementation, strings
Correct Solution:
```
#------------------------template--------------------------#
import os
import sys
# from math import *
from collections import *
# from fractions import *
# from heapq import*
from bisect import *
from io import BytesIO, IOBase
def vsInput():
sys.stdin = open('inp... | output | 1 | 102,620 | 6 | 205,241 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Programmer Vasya is studying a new programming language &K*. The &K* language resembles the languages of the C family in its syntax. However, it is more powerful, which is why the rules of the actual C-like languages are unapplicable to it. ... | instruction | 0 | 102,621 | 6 | 205,242 |
Tags: implementation, strings
Correct Solution:
```
n=int(input())
def Ref(v):
stars=0
ands=0
nam=""
for item in v:
if(item=='*'):
stars+=1
elif(item=='&'):
ands+=1
else:
nam+=item
if(nam not in T):
return "errtype"
x=T[nam]
... | output | 1 | 102,621 | 6 | 205,243 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Programmer Vasya is studying a new programming language &K*. The &K* language resembles the languages of the C family in its syntax. However, it is more powerful, which is why the rules of the actual C-like languages are unapplicable to it. ... | instruction | 0 | 102,622 | 6 | 205,244 |
Tags: implementation, strings
Correct Solution:
```
types = {'void':'void', 'errtype':'errtype'}
def getRealType(type_expr):
expr_type = type_expr.strip('&*')
full_type_name = type_expr.replace(expr_type, types.get(expr_type, "errtype"))
base_type = full_type_name.strip('&*')
if base_type == "void":
... | output | 1 | 102,622 | 6 | 205,245 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Programmer Vasya is studying a new programming language &K*. The &K* language resembles the languages of the C family in its syntax. However, it is more powerful, which is why the rules of the actual C-like languages are unapplicable to it. ... | instruction | 0 | 102,623 | 6 | 205,246 |
Tags: implementation, strings
Correct Solution:
```
types = {'void':'void', 'errtype':'errtype'}
def getRealType(type_expr):
expr_type = type_expr.strip('&*')
full_type_name = type_expr.replace(expr_type, types.get(expr_type, "errtype"))
base_type = full_type_name.strip('&*')
if base_type == "void":
addr_c... | output | 1 | 102,623 | 6 | 205,247 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Programmer Vasya is studying a new programming language &K*. The &K* language resembles the languages of the C family in its syntax. However, it is more powerful, which is why the rules of the a... | instruction | 0 | 102,624 | 6 | 205,248 |
No | output | 1 | 102,624 | 6 | 205,249 |
Provide tags and a correct Python 3 solution for this coding contest problem.
When Serezha was three years old, he was given a set of cards with letters for his birthday. They were arranged into words in the way which formed the boy's mother favorite number in binary notation. Serezha started playing with them immedia... | instruction | 0 | 103,001 | 6 | 206,002 |
Tags: implementation, sortings, strings
Correct Solution:
```
length = int(input())
string = input()
contador_0 = 0
contador_1 = 0
for letter in string:
if letter == 'z':
contador_0 += 1
elif letter == 'n':
contador_1 += 1
string = ''
for contador in range(contador_1):
string += '1 '
for con... | output | 1 | 103,001 | 6 | 206,003 |
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