message
stringlengths
2
23.4k
message_type
stringclasses
2 values
message_id
int64
0
1
conversation_id
int64
129
108k
cluster
float64
6
6
__index_level_0__
int64
258
216k
Provide tags and a correct Python 3 solution for this coding contest problem. As technologies develop, manufacturers are making the process of unlocking a phone as user-friendly as possible. To unlock its new phone, Arkady's pet dog Mu-mu has to bark the password once. The phone represents a password as a string of tw...
instruction
0
86,218
6
172,436
Tags: brute force, implementation, strings Correct Solution: ``` passwd = input() words = [] for _ in range(int(input())): word = input() for i in word: if i in passwd: words.append(word) break for i in words: for j in words: if passwd in i + j: print('...
output
1
86,218
6
172,437
Provide tags and a correct Python 3 solution for this coding contest problem. As technologies develop, manufacturers are making the process of unlocking a phone as user-friendly as possible. To unlock its new phone, Arkady's pet dog Mu-mu has to bark the password once. The phone represents a password as a string of tw...
instruction
0
86,219
6
172,438
Tags: brute force, implementation, strings Correct Solution: ``` s = input() n = int(input()) a = [input() for i in range(n)] for i in range(n): for j in range(n): if a[i] == s or a[i][1] + a[j][0] == s: print("YES") exit(0) print("NO") ```
output
1
86,219
6
172,439
Provide tags and a correct Python 3 solution for this coding contest problem. As technologies develop, manufacturers are making the process of unlocking a phone as user-friendly as possible. To unlock its new phone, Arkady's pet dog Mu-mu has to bark the password once. The phone represents a password as a string of tw...
instruction
0
86,220
6
172,440
Tags: brute force, implementation, strings Correct Solution: ``` password =input() n = int(input()) n1 = n li = [] i = 1 check = False while n != 0: temp = input() li.append(temp) n -= 1 for i in range(0,n1): for j in range(0,n1): a = li[i] + li[j] b = li[j] + li[i] if password i...
output
1
86,220
6
172,441
Provide tags and a correct Python 3 solution for this coding contest problem. As technologies develop, manufacturers are making the process of unlocking a phone as user-friendly as possible. To unlock its new phone, Arkady's pet dog Mu-mu has to bark the password once. The phone represents a password as a string of tw...
instruction
0
86,221
6
172,442
Tags: brute force, implementation, strings Correct Solution: ``` password = input() n = int(input()) firstLetter = 0 secondLetter = 0 found = 0 for i in range(n): inputStr = input() if inputStr == password: found = 1 if inputStr[1] == password[0]: firstLetter = 1 if inputStr[0] == ...
output
1
86,221
6
172,443
Provide tags and a correct Python 3 solution for this coding contest problem. As technologies develop, manufacturers are making the process of unlocking a phone as user-friendly as possible. To unlock its new phone, Arkady's pet dog Mu-mu has to bark the password once. The phone represents a password as a string of tw...
instruction
0
86,222
6
172,444
Tags: brute force, implementation, strings Correct Solution: ``` s=input();n=int(input());x=0;y=0;k='';pd=0 for i in range(0,n): k=input() if k==s: print('YES') pd=1 break else: if k[0]==s[1]: x=1 if k[1]==s[0]: y=1 if x==1 and y==1: ...
output
1
86,222
6
172,445
Provide a correct Python 3 solution for this coding contest problem. Short Phrase A Short Phrase (aka. Tanku) is a fixed verse, inspired by Japanese poetry Tanka and Haiku. It is a sequence of words, each consisting of lowercase letters 'a' to 'z', and must satisfy the following condition: > (The Condition for a Sho...
instruction
0
86,492
6
172,984
"Correct Solution: ``` class CheckError(Exception): pass def check(wclist, count): c = 0 while True: c += wclist.pop(0) if c == count: return wclist elif c > count: raise CheckError def tanku_check(wclist): for i in range(len(wclist)): try: ...
output
1
86,492
6
172,985
Provide a correct Python 3 solution for this coding contest problem. Short Phrase A Short Phrase (aka. Tanku) is a fixed verse, inspired by Japanese poetry Tanka and Haiku. It is a sequence of words, each consisting of lowercase letters 'a' to 'z', and must satisfy the following condition: > (The Condition for a Sho...
instruction
0
86,493
6
172,986
"Correct Solution: ``` while True: n = int(input()) if n==0: break w = [len(input()) for i in range(n)] a = [5,7,5,7,7] ans = n+1 for i in range(n): k,s = 0,0 for j in range(i,n): s += w[j] if s==a[k]: s,k=0,k+1 elif s>a...
output
1
86,493
6
172,987
Provide a correct Python 3 solution for this coding contest problem. Short Phrase A Short Phrase (aka. Tanku) is a fixed verse, inspired by Japanese poetry Tanka and Haiku. It is a sequence of words, each consisting of lowercase letters 'a' to 'z', and must satisfy the following condition: > (The Condition for a Sho...
instruction
0
86,494
6
172,988
"Correct Solution: ``` while True: n = int(input()) if n == 0: break else: phlist=[] phflag=0 for i in range(n): phlist.append(input()) for i in range(len(phlist)-4): cur=0 state=0 for j in range(i, len(phlist)): ...
output
1
86,494
6
172,989
Provide a correct Python 3 solution for this coding contest problem. Short Phrase A Short Phrase (aka. Tanku) is a fixed verse, inspired by Japanese poetry Tanka and Haiku. It is a sequence of words, each consisting of lowercase letters 'a' to 'z', and must satisfy the following condition: > (The Condition for a Sho...
instruction
0
86,495
6
172,990
"Correct Solution: ``` from collections import defaultdict,deque import sys,heapq,bisect,math,itertools,string,queue,datetime sys.setrecursionlimit(10**8) INF = float('inf') mod = 10**9+7 eps = 10**-7 def inpl(): return list(map(int, input().split())) def inpl_str(): return list(input().split()) while True: n = in...
output
1
86,495
6
172,991
Provide a correct Python 3 solution for this coding contest problem. Short Phrase A Short Phrase (aka. Tanku) is a fixed verse, inspired by Japanese poetry Tanka and Haiku. It is a sequence of words, each consisting of lowercase letters 'a' to 'z', and must satisfy the following condition: > (The Condition for a Sho...
instruction
0
86,496
6
172,992
"Correct Solution: ``` while True: n = int(input()) if n == 0: break count = [0] * n for i in range(n): count[i] = len(input()) for i in range(n-4): ind = i fin = True for tmp in [5, 7, 5, 7, 7]: while tmp > 0 and ind < n: tmp -= co...
output
1
86,496
6
172,993
Provide a correct Python 3 solution for this coding contest problem. Short Phrase A Short Phrase (aka. Tanku) is a fixed verse, inspired by Japanese poetry Tanka and Haiku. It is a sequence of words, each consisting of lowercase letters 'a' to 'z', and must satisfy the following condition: > (The Condition for a Sho...
instruction
0
86,497
6
172,994
"Correct Solution: ``` while True: n = int(input()) if n == 0: break a = [] for i in range(n): p = list(input()) a.append(len(p)) def solve(a): N = len(a) for i in range(N): judge = 0 rest = 5 for j in range(i,N): ...
output
1
86,497
6
172,995
Provide a correct Python 3 solution for this coding contest problem. Short Phrase A Short Phrase (aka. Tanku) is a fixed verse, inspired by Japanese poetry Tanka and Haiku. It is a sequence of words, each consisting of lowercase letters 'a' to 'z', and must satisfy the following condition: > (The Condition for a Sho...
instruction
0
86,498
6
172,996
"Correct Solution: ``` # AOJ 1601: Short Phrase # Python3 2018.7.13 bal4u a = [5,7,5,7,7] while True: n = int(input()) if n == 0: break ans = 0 w = [len(input()) for i in range(n)] for i in range(n): k = s = 0 for j in range(i, n): s += w[j] if s == a[k]: s, k = 0, k+1 if k == 5: ans = i+1; bre...
output
1
86,498
6
172,997
Provide a correct Python 3 solution for this coding contest problem. Short Phrase A Short Phrase (aka. Tanku) is a fixed verse, inspired by Japanese poetry Tanka and Haiku. It is a sequence of words, each consisting of lowercase letters 'a' to 'z', and must satisfy the following condition: > (The Condition for a Sho...
instruction
0
86,499
6
172,998
"Correct Solution: ``` def solve(): n = int(input()) if n == 0: return False ok = [5, 7, 5, 7, 7] inputs = [input() for x in range(n)] for i in range(n): target = 0 cnt = i for v in ok: while target < v: s = inputs[cnt] target +=...
output
1
86,499
6
172,999
Provide tags and a correct Python 3 solution for this coding contest problem. Sherlock Holmes found a mysterious correspondence of two VIPs and made up his mind to read it. But there is a problem! The correspondence turned out to be encrypted. The detective tried really hard to decipher the correspondence, but he coul...
instruction
0
86,901
6
173,802
Tags: combinatorics, dp Correct Solution: ``` S, N = 2505, 105 m = 1000000007 k = 26 p = [[0] * (S + k) for i in range(N)] p[0][0] = 1 for n in range(1, N): for s in range(S): p[n][s] = (p[n][s - 1] + p[n - 1][s] - p[n - 1][s - k]) % m r = [] for j in range(int(input())): t = input() s = sum(ord(q) ...
output
1
86,901
6
173,803
Provide tags and a correct Python 3 solution for this coding contest problem. Sherlock Holmes found a mysterious correspondence of two VIPs and made up his mind to read it. But there is a problem! The correspondence turned out to be encrypted. The detective tried really hard to decipher the correspondence, but he coul...
instruction
0
86,902
6
173,804
Tags: combinatorics, dp Correct Solution: ``` S, N = 2501, 101 m = 1000000007 k = 26 p = [[0] * (S + k) for i in range(N)] p[0][0] = 1 for n in range(1, N): for s in range(S): p[n][s] = (p[n][s - 1] + p[n - 1][s] - p[n - 1][s - k]) % m r = [] for j in range(int(input())): t = input() s = sum(ord(q) ...
output
1
86,902
6
173,805
Provide tags and a correct Python 3 solution for this coding contest problem. Sherlock Holmes found a mysterious correspondence of two VIPs and made up his mind to read it. But there is a problem! The correspondence turned out to be encrypted. The detective tried really hard to decipher the correspondence, but he coul...
instruction
0
86,903
6
173,806
Tags: combinatorics, dp Correct Solution: ``` p = [[0] * 2527 for i in range(101)] p[0][0] = 1 for n in range(100): for s in range(2501): p[n + 1][s] = (p[n + 1][s - 1] + p[n][s] - p[n][s - 26]) % 1000000007 for j in range(int(input())): t = input() s = sum(ord(q) - 97 for q in t) print(p[len(t)...
output
1
86,903
6
173,807
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Vasya is a born Berland film director, he is currently working on a new blockbuster, "The Unexpected". Vasya knows from his own experience how important it is to choose the main characters' name...
instruction
0
87,032
6
174,064
No
output
1
87,032
6
174,065
Provide tags and a correct Python 3 solution for this coding contest problem. Harry Potter is on a mission to destroy You-Know-Who's Horcruxes. The first Horcrux that he encountered in the Chamber of Secrets is Tom Riddle's diary. The diary was with Ginny and it forced her to open the Chamber of Secrets. Harry wants t...
instruction
0
87,206
6
174,412
Tags: brute force, implementation, strings Correct Solution: ``` import sys names = sys.stdin.readlines()[1:] for n, name in enumerate(names): if name in names[:n]: print('YES') else: print('NO') ```
output
1
87,206
6
174,413
Provide tags and a correct Python 3 solution for this coding contest problem. Harry Potter is on a mission to destroy You-Know-Who's Horcruxes. The first Horcrux that he encountered in the Chamber of Secrets is Tom Riddle's diary. The diary was with Ginny and it forced her to open the Chamber of Secrets. Harry wants t...
instruction
0
87,209
6
174,418
Tags: brute force, implementation, strings Correct Solution: ``` n = int(input()) a = [] for i in range(n): a.append(input()) for i in range(n): f = 0 for j in range(i): if a[i] == a[j]: print("YES") f = 1 break if f == 0: print("NO") ```
output
1
87,209
6
174,419
Provide tags and a correct Python 3 solution for this coding contest problem. Harry Potter is on a mission to destroy You-Know-Who's Horcruxes. The first Horcrux that he encountered in the Chamber of Secrets is Tom Riddle's diary. The diary was with Ginny and it forced her to open the Chamber of Secrets. Harry wants t...
instruction
0
87,210
6
174,420
Tags: brute force, implementation, strings Correct Solution: ``` n=int(input()) l=[] for i in range(n): a=input() if a not in l: print('NO') l.append(a) else: print('YES') ```
output
1
87,210
6
174,421
Provide tags and a correct Python 3 solution for this coding contest problem. Harry Potter is on a mission to destroy You-Know-Who's Horcruxes. The first Horcrux that he encountered in the Chamber of Secrets is Tom Riddle's diary. The diary was with Ginny and it forced her to open the Chamber of Secrets. Harry wants t...
instruction
0
87,211
6
174,422
Tags: brute force, implementation, strings Correct Solution: ``` # import sys # sys.stdin=open('input.in','r') # sys.stdout=open('output.out','w') n=int(input()) p=[] for x in range(n): k=input() if k not in p: print('NO') p.append(k) else: print('YES') ```
output
1
87,211
6
174,423
Provide tags and a correct Python 3 solution for this coding contest problem. Harry Potter is on a mission to destroy You-Know-Who's Horcruxes. The first Horcrux that he encountered in the Chamber of Secrets is Tom Riddle's diary. The diary was with Ginny and it forced her to open the Chamber of Secrets. Harry wants t...
instruction
0
87,212
6
174,424
Tags: brute force, implementation, strings Correct Solution: ``` # import sys # sys.stdin=open("input.in","r") # sys.stdout=open("output.out","w") x=int(input()) L=[] X={} FLAG=0 for i in range(x): FLAG=0 L.append(input()) for j in range(i): if L[i]==L[j]: print("YES") FLAG=1 break if FLAG==0: print("N...
output
1
87,212
6
174,425
Provide tags and a correct Python 3 solution for this coding contest problem. Harry Potter is on a mission to destroy You-Know-Who's Horcruxes. The first Horcrux that he encountered in the Chamber of Secrets is Tom Riddle's diary. The diary was with Ginny and it forced her to open the Chamber of Secrets. Harry wants t...
instruction
0
87,213
6
174,426
Tags: brute force, implementation, strings Correct Solution: ``` number=int(input()) lst=[] for i in range(number): x=input() lst.append(x) for i in range (number): for j in range(0,i): if lst[i]==lst[j]: print ("Yes") break; else: print ( "NO") ```
output
1
87,213
6
174,427
Provide a correct Python 3 solution for this coding contest problem. Emacs is a text editor which is widely used by many programmers. The advantage of Emacs is that we can move a cursor without arrow keys and the mice. For example, the cursor can be moved right, left, down, and up by pushing f, b, n, p with the Contr...
instruction
0
87,448
6
174,896
"Correct Solution: ``` import sys class Cursor: BOL = (0,1) def __init__(self, text): assert isinstance(text, list) self.text = text for i in range(len(self.text)): self.text[i] = list(self.text[i]) self.buffer = "" self.line = 1 self.pos = self.B...
output
1
87,448
6
174,897
Provide a correct Python 3 solution for this coding contest problem. Emacs is a text editor which is widely used by many programmers. The advantage of Emacs is that we can move a cursor without arrow keys and the mice. For example, the cursor can be moved right, left, down, and up by pushing f, b, n, p with the Contr...
instruction
0
87,449
6
174,898
"Correct Solution: ``` text = [] while True: s = input() if s == "END_OF_TEXT": break text.append(s) x, y = 0, 0 buff = "" while True: c = input() if c == "-": break elif c == "a": x = 0 elif c == "e": x = len(text[y]) elif c == "p": if y == 0: x = 0 else: x = 0 ...
output
1
87,449
6
174,899
Provide a correct Python 3 solution for this coding contest problem. Emacs is a text editor which is widely used by many programmers. The advantage of Emacs is that we can move a cursor without arrow keys and the mice. For example, the cursor can be moved right, left, down, and up by pushing f, b, n, p with the Contr...
instruction
0
87,450
6
174,900
"Correct Solution: ``` class Editer: def __init__(self, text): # カーソルの位置 self.row = 0 #行 self.col = 0 #列 # 編集中のテキスト self.text = [list(t) + ['\n'] for t in text] # バッファー self.buffer = [] def row_head(self): return 0 def row_tail(self): ...
output
1
87,450
6
174,901
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Sonya had a birthday recently. She was presented with the matrix of size n× m and consist of lowercase Latin letters. We assume that the rows are numbered by integers from 1 to n from bottom to ...
instruction
0
87,573
6
175,146
No
output
1
87,573
6
175,147
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Sonya had a birthday recently. She was presented with the matrix of size n× m and consist of lowercase Latin letters. We assume that the rows are numbered by integers from 1 to n from bottom to ...
instruction
0
87,574
6
175,148
No
output
1
87,574
6
175,149
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Sonya had a birthday recently. She was presented with the matrix of size n× m and consist of lowercase Latin letters. We assume that the rows are numbered by integers from 1 to n from bottom to ...
instruction
0
87,575
6
175,150
No
output
1
87,575
6
175,151
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Sonya had a birthday recently. She was presented with the matrix of size n× m and consist of lowercase Latin letters. We assume that the rows are numbered by integers from 1 to n from bottom to ...
instruction
0
87,576
6
175,152
No
output
1
87,576
6
175,153
Provide tags and a correct Python 3 solution for this coding contest problem. After observing the results of Spy Syndrome, Yash realised the errors of his ways. He now believes that a super spy such as Siddhant can't use a cipher as basic and ancient as Caesar cipher. After many weeks of observation of Siddhant’s sent...
instruction
0
87,991
6
175,982
Tags: data structures, dp, hashing, implementation, sortings, string suffix structures, strings Correct Solution: ``` #!/usr/bin/env python3 # http://codeforces.com/contest/633/problem/C from collections import deque # import sys # sys.setrecursionlimit(10001) n = int(input()) s = input() m = int(input()) words = [...
output
1
87,991
6
175,983
Provide tags and a correct Python 3 solution for this coding contest problem. After observing the results of Spy Syndrome, Yash realised the errors of his ways. He now believes that a super spy such as Siddhant can't use a cipher as basic and ancient as Caesar cipher. After many weeks of observation of Siddhant’s sent...
instruction
0
87,992
6
175,984
Tags: data structures, dp, hashing, implementation, sortings, string suffix structures, strings Correct Solution: ``` def main(): stop, s, words, stack = int(input()), input()[::-1], {}, [] for _ in range(int(input())): w = input() words[w.lower()] = w lel = tuple(sorted(set(map(len, words.k...
output
1
87,992
6
175,985
Provide tags and a correct Python 3 solution for this coding contest problem. After observing the results of Spy Syndrome, Yash realised the errors of his ways. He now believes that a super spy such as Siddhant can't use a cipher as basic and ancient as Caesar cipher. After many weeks of observation of Siddhant’s sent...
instruction
0
87,993
6
175,986
Tags: data structures, dp, hashing, implementation, sortings, string suffix structures, strings Correct Solution: ``` def main(): stop, s, words, stack = int(input()), input()[::-1], {}, [] for _ in range(int(input())): w = input() words[w.lower()] = w lel = tuple(sorted(set(map(len, words.k...
output
1
87,993
6
175,987
Provide tags and a correct Python 3 solution for this coding contest problem. After observing the results of Spy Syndrome, Yash realised the errors of his ways. He now believes that a super spy such as Siddhant can't use a cipher as basic and ancient as Caesar cipher. After many weeks of observation of Siddhant’s sent...
instruction
0
87,994
6
175,988
Tags: data structures, dp, hashing, implementation, sortings, string suffix structures, strings Correct Solution: ``` # [https://codeforces.com/contest/633/submission/33363209] n = int(input()) t = input()[::-1] m = int(input()) d = {q.lower(): q for q in [input() for i in range(m)]} k = 0 s = [] l = sorted(set(map(le...
output
1
87,994
6
175,989
Provide tags and a correct Python 3 solution for this coding contest problem. After observing the results of Spy Syndrome, Yash realised the errors of his ways. He now believes that a super spy such as Siddhant can't use a cipher as basic and ancient as Caesar cipher. After many weeks of observation of Siddhant’s sent...
instruction
0
87,995
6
175,990
Tags: data structures, dp, hashing, implementation, sortings, string suffix structures, strings Correct Solution: ``` import sys p = sys.stdin.read().split() n, t = int(p[0]), p[1][::-1] d = {q.lower(): q for q in p[3:]} k, s = 0, [] l = sorted(set(map(len, d))) while n: k -= 1 if len(l) + k < 0: k, n = s.pop()...
output
1
87,995
6
175,991
Provide tags and a correct Python 3 solution for this coding contest problem. Polycarp thinks about the meaning of life very often. He does this constantly, even when typing in the editor. Every time he starts brooding he can no longer fully concentrate and repeatedly presses the keys that need to be pressed only once...
instruction
0
88,035
6
176,070
Tags: implementation Correct Solution: ``` string = input() stack = [len(string)] for letter in string: if letter == stack[-1]: stack.pop() else: stack.append(letter) print(''.join(stack[1:])) ```
output
1
88,035
6
176,071
Provide tags and a correct Python 3 solution for this coding contest problem. Polycarp thinks about the meaning of life very often. He does this constantly, even when typing in the editor. Every time he starts brooding he can no longer fully concentrate and repeatedly presses the keys that need to be pressed only once...
instruction
0
88,036
6
176,072
Tags: implementation Correct Solution: ``` ##############--->>>>> Deepcoder Amit Kumar Bhuyan <<<<<---############## """ Perfection is achieved not when there is nothing more to add, but rather when there is nothing more to take away. """ from __future__ import division, print_function import os,sys from io import ...
output
1
88,036
6
176,073
Provide tags and a correct Python 3 solution for this coding contest problem. Polycarp thinks about the meaning of life very often. He does this constantly, even when typing in the editor. Every time he starts brooding he can no longer fully concentrate and repeatedly presses the keys that need to be pressed only once...
instruction
0
88,037
6
176,074
Tags: implementation Correct Solution: ``` s = input() stack = [] for char in s: # print("Comparing", char, "&", stack) if len(stack)==0: stack.append(char) else: if(char == stack[-1]): stack.pop() else: stack.append(char) print("".join(stack)) ```
output
1
88,037
6
176,075
Provide tags and a correct Python 3 solution for this coding contest problem. Polycarp thinks about the meaning of life very often. He does this constantly, even when typing in the editor. Every time he starts brooding he can no longer fully concentrate and repeatedly presses the keys that need to be pressed only once...
instruction
0
88,038
6
176,076
Tags: implementation Correct Solution: ``` s = [] for i in input(): if s and s[-1] == i: s.pop() else: s.append(i) print("".join(s)) ```
output
1
88,038
6
176,077
Provide tags and a correct Python 3 solution for this coding contest problem. Polycarp thinks about the meaning of life very often. He does this constantly, even when typing in the editor. Every time he starts brooding he can no longer fully concentrate and repeatedly presses the keys that need to be pressed only once...
instruction
0
88,039
6
176,078
Tags: implementation Correct Solution: ``` s = input() l = [""]*200000 li = 0 for c in s: li += 1 if len(l) > 0 and l[li-1] == c: l[li-1] = "" li -= 2 else: l[li] = c print(*l[:li+1], sep="") ```
output
1
88,039
6
176,079
Provide tags and a correct Python 3 solution for this coding contest problem. Polycarp thinks about the meaning of life very often. He does this constantly, even when typing in the editor. Every time he starts brooding he can no longer fully concentrate and repeatedly presses the keys that need to be pressed only once...
instruction
0
88,040
6
176,080
Tags: implementation Correct Solution: ``` p=list(input()) a=[ ] #Creacion d euna lista vacia a.append(p[0]) #incluir el primer elemnto de p a la lista a m=len(p) #tamaño de p i=1 while i<m: if (len(a)==0): a.append(p[i]) else: if(a[-1]==p[i]): a.pop() ...
output
1
88,040
6
176,081
Provide tags and a correct Python 3 solution for this coding contest problem. Polycarp thinks about the meaning of life very often. He does this constantly, even when typing in the editor. Every time he starts brooding he can no longer fully concentrate and repeatedly presses the keys that need to be pressed only once...
instruction
0
88,041
6
176,082
Tags: implementation Correct Solution: ``` s=input() ans=[s[0]] for i in range(1,len(s)): if len(ans) and ans[-1]==s[i]: ans.pop() else: ans.append(s[i]) print("".join(ans)) ```
output
1
88,041
6
176,083
Provide tags and a correct Python 3 solution for this coding contest problem. Polycarp thinks about the meaning of life very often. He does this constantly, even when typing in the editor. Every time he starts brooding he can no longer fully concentrate and repeatedly presses the keys that need to be pressed only once...
instruction
0
88,042
6
176,084
Tags: implementation Correct Solution: ``` string = input() def plugInX(string): stringNew = [] for i in string: if i not in stringNew: stringNew.append(i) elif i == stringNew[-1]: stringNew.pop() else: stringNew.append(i) if len(stringNew) > 0: ...
output
1
88,042
6
176,085
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Polycarp thinks about the meaning of life very often. He does this constantly, even when typing in the editor. Every time he starts brooding he can no longer fully concentrate and repeatedly pre...
instruction
0
88,045
6
176,090
Yes
output
1
88,045
6
176,091
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Polycarp thinks about the meaning of life very often. He does this constantly, even when typing in the editor. Every time he starts brooding he can no longer fully concentrate and repeatedly pre...
instruction
0
88,047
6
176,094
No
output
1
88,047
6
176,095
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Polycarp thinks about the meaning of life very often. He does this constantly, even when typing in the editor. Every time he starts brooding he can no longer fully concentrate and repeatedly pre...
instruction
0
88,050
6
176,100
No
output
1
88,050
6
176,101
Provide tags and a correct Python 3 solution for this coding contest problem. Welcome to another task about breaking the code lock! Explorers Whitfield and Martin came across an unusual safe, inside of which, according to rumors, there are untold riches, among which one can find the solution of the problem of discrete...
instruction
0
88,099
6
176,198
Tags: constructive algorithms, implementation, strings Correct Solution: ``` n, s, t = int(input()), input(), input() #print n, s, t if sorted(s)!=sorted(t): print(-1) else: ans = [] def shift(k, cur): if k == 0: return cur return cur[:-k-1:-1] + cur [:-k] def DO_SWA...
output
1
88,099
6
176,199
Provide tags and a correct Python 3 solution for this coding contest problem. Welcome to another task about breaking the code lock! Explorers Whitfield and Martin came across an unusual safe, inside of which, according to rumors, there are untold riches, among which one can find the solution of the problem of discrete...
instruction
0
88,100
6
176,200
Tags: constructive algorithms, implementation, strings Correct Solution: ``` def reverse(s,k): if not k: return s return s[-1:-k-1:-1]+s[:-k] n=int(input()) s=input() t=input() cnt=[0]*26 for i in s: cnt[ord(i)-ord('a')]+=1 for i in t: cnt[ord(i)-ord('a')]-=1 for i in cnt: if i!=0: print(-1) exit(0) print...
output
1
88,100
6
176,201
Provide tags and a correct Python 3 solution for this coding contest problem. Welcome to another task about breaking the code lock! Explorers Whitfield and Martin came across an unusual safe, inside of which, according to rumors, there are untold riches, among which one can find the solution of the problem of discrete...
instruction
0
88,101
6
176,202
Tags: constructive algorithms, implementation, strings Correct Solution: ``` import math import sys input = sys.stdin.readline result = [] def move(s, x): result.append(x) # print(s[-1:-1-x:-1] + s[:len(s) - x]) return s[-1:-1-x:-1] + s[:len(s) - x] def getFirst(s, need, size): piv = -1 for i in ran...
output
1
88,101
6
176,203
Provide tags and a correct Python 3 solution for this coding contest problem. Welcome to another task about breaking the code lock! Explorers Whitfield and Martin came across an unusual safe, inside of which, according to rumors, there are untold riches, among which one can find the solution of the problem of discrete...
instruction
0
88,102
6
176,204
Tags: constructive algorithms, implementation, strings Correct Solution: ``` n = int(input()) s = input() t = input() if sorted(s) != sorted(t): print(-1) else: res = [] for i in range(n): k = 0; while(s[k] != t[i]): k += 1 res += [n-k-1, 1, n] s = "".join(revers...
output
1
88,102
6
176,205