message stringlengths 2 57.2k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 61 108k | cluster float64 22 22 | __index_level_0__ int64 122 217k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two positive integers n (1 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 100). Represent the number n as the sum of k positive integers of the same parity (have the same remainder when divided by 2).
In other words, find a_1, a_2, …, a_k such th... | instruction | 0 | 8,510 | 22 | 17,020 |
Tags: constructive algorithms, math
Correct Solution:
```
"""
// Author : snape_here - Susanta Mukherjee
"""
from __future__ import division, print_function
import os,sys
from io import BytesIO, IOBase
if sys.version_info[0] < 3:
from __builtin__ import xrange as range
from future_builtins import a... | output | 1 | 8,510 | 22 | 17,021 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two positive integers n (1 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 100). Represent the number n as the sum of k positive integers of the same parity (have the same remainder when divided by 2).
In other words, find a_1, a_2, …, a_k such th... | instruction | 0 | 8,511 | 22 | 17,022 |
Tags: constructive algorithms, math
Correct Solution:
```
for _ in range(int(input())):
n, k = map(int, input().split())
if n % 2 == 1 and k % 2 == 0:
print("NO")
continue
if n % 2 == k % 2:
if k > n:
print("NO")
continue
res = [1] * (k-1)
r... | output | 1 | 8,511 | 22 | 17,023 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two positive integers n (1 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 100). Represent the number n as the sum of k positive integers of the same parity (have the same remainder when divided by 2).
In other words, find a_1, a_2, …, a_k such th... | instruction | 0 | 8,512 | 22 | 17,024 |
Tags: constructive algorithms, math
Correct Solution:
```
t = int(input())
for tt in range(t):
n, k = (int(i) for i in input().split())
if k <= n and (n-k) % 2 == 0:
print("YES")
ans = [1]*k
ans[0] = n-k+1
print(' '.join((str(i) for i in ans)))
elif 2*k <= n and (n-2*k)%2 =... | output | 1 | 8,512 | 22 | 17,025 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two positive integers n (1 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 100). Represent the number n as the sum of k positive integers of the same parity (have the same remainder when divided by 2).
In other words, find a_1, a_2, …, a_k such th... | instruction | 0 | 8,513 | 22 | 17,026 |
Tags: constructive algorithms, math
Correct Solution:
```
def function(n, k):
l_odd=[1]*(k-1)
l_odd.append(n-sum(l_odd))
condition1=True
for i in l_odd:
if i%2==0 or i<=0:
condition1=False
break
if condition1:
print('YES')
print(*l_odd)
condition2=... | output | 1 | 8,513 | 22 | 17,027 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two positive integers n (1 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 100). Represent the number n as the sum of k positive integers of the same parity (have the same remainder when divided by 2).
In other words, find a_1, a_2, …, a_k such th... | instruction | 0 | 8,514 | 22 | 17,028 |
Tags: constructive algorithms, math
Correct Solution:
```
q=int(input())
for i in range(q):
n,k=[int(i) for i in input().split()]
if k==1:
print('YES')
print(n)
else:
if n%2==1 and k%2==0 or k>n or k+1==n or ((n%2==0 and k%2==1) and n<k*2) :
print('NO')
else:
... | output | 1 | 8,514 | 22 | 17,029 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two positive integers n (1 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 100). Represent the number n as the sum of k positive integers of the same parity (have the same remainder when divided by 2).
In other words, find a_1, a_2, …, a_k such th... | instruction | 0 | 8,515 | 22 | 17,030 |
Tags: constructive algorithms, math
Correct Solution:
```
t = int(input())
for _ in range(t):
n, k = map(int, input().split())
if n < k:
print("NO")
continue
if n % 2 != 0:
if k % 2 == 0:
print("NO")
if k % 2 != 0:
print("YES")
print(str(n ... | output | 1 | 8,515 | 22 | 17,031 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two positive integers n (1 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 100). Represent the number n as the sum of k positive integers of the same parity (have the same remainder when divided by 2).
In other words, find a_1, a_2, …, a_k such th... | instruction | 0 | 8,516 | 22 | 17,032 |
Tags: constructive algorithms, math
Correct Solution:
```
for _ in range(int(input())):
n,k=map(int,input().split())
ans1=[2]*(k-1)
ans1.append(n-2*k+2)
ans2=[1]*(k-1)
ans2.append(n-k+1)
if ans1[-1]>0 and ans1[-1]%2==0:
print("YES")
print(*ans1)
elif ans2[-1]>0 and ans2[... | output | 1 | 8,516 | 22 | 17,033 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two positive integers n (1 ≤ n ≤ 10^9) and k (1 ≤ k ≤ 100). Represent the number n as the sum of k positive integers of the same parity (have the same remainder when divided by 2).
In other words, find a_1, a_2, …, a_k such th... | instruction | 0 | 8,517 | 22 | 17,034 |
Tags: constructive algorithms, math
Correct Solution:
```
t = int(input())
for i in range(t):
n,k = map(int, input().split())
if n==k:
print("YES")
print(*[1]*k)
elif n<k:
print("NO")
else:
if (n-(k-1))%2==1:
print("YES")
print(*[1]*(k-1),n-(k-1))
... | output | 1 | 8,517 | 22 | 17,035 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In order to put away old things and welcome a fresh new year, a thorough cleaning of the house is a must.
Little Tommy finds an old polynomial and cleaned it up by taking it modulo another. But now he regrets doing this...
Given two intege... | instruction | 0 | 8,805 | 22 | 17,610 |
Tags: math
Correct Solution:
```
R=lambda:map(int,input().split())
p, k = R()
a = []
t = p//k
temp = 1
if p >= k:
while k * t >= k:
a.insert(0, (-1)**temp * t)
flag = True
if t%k == 0: flag = False
t = abs(t//k)
if temp % 2 == 1 and flag : t += 1
temp += 1
... | output | 1 | 8,805 | 22 | 17,611 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In order to put away old things and welcome a fresh new year, a thorough cleaning of the house is a must.
Little Tommy finds an old polynomial and cleaned it up by taking it modulo another. But now he regrets doing this...
Given two intege... | instruction | 0 | 8,806 | 22 | 17,612 |
Tags: math
Correct Solution:
```
[p,k]=[int(x) for x in input().split()]
d=1
res=[]
while p:
if d%2==1:
kek=k
res.append(str(p%kek))
p//=kek
else:
kek=k
lol=kek-(p%kek)
while lol>=kek:
lol-=kek
res.append(str(lol))
p=(p+lol)//kek
d+=1
print(len(res))
s=' '
print(s.join(res))
``` | output | 1 | 8,806 | 22 | 17,613 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In order to put away old things and welcome a fresh new year, a thorough cleaning of the house is a must.
Little Tommy finds an old polynomial and cleaned it up by taking it modulo another. But now he regrets doing this...
Given two intege... | instruction | 0 | 8,807 | 22 | 17,614 |
Tags: math
Correct Solution:
```
def solve(n,p,k):
# print(n,p,k)
P=p
cf=1
a=[0]*n
for i in range(n):
if i&1:
p+=cf*(k-1)
a[i]-=k-1
cf*=k
# print(p)
for i in range(n):
a[i]+=p%k
p//=k
# print(n,a)
if p:
return
fo... | output | 1 | 8,807 | 22 | 17,615 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In order to put away old things and welcome a fresh new year, a thorough cleaning of the house is a must.
Little Tommy finds an old polynomial and cleaned it up by taking it modulo another. But now he regrets doing this...
Given two intege... | instruction | 0 | 8,808 | 22 | 17,616 |
Tags: math
Correct Solution:
```
p,k = map(int, input().split())
coeff = [1]
maxi =k-1
kk = k*k
while maxi < p:
for i in range(2):
coeff.append(0)
maxi += kk*(k-1)
kk*=k*2
n = len(coeff)
powk = [0 for i in range(n)]
pos = [0 for i in range(n)]
neg = [0 for i in range(n)]
powk[0] = 1
for i in ran... | output | 1 | 8,808 | 22 | 17,617 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In order to put away old things and welcome a fresh new year, a thorough cleaning of the house is a must.
Little Tommy finds an old polynomial and cleaned it up by taking it modulo another. But now he regrets doing this...
Given two intege... | instruction | 0 | 8,809 | 22 | 17,618 |
Tags: math
Correct Solution:
```
a,b=map(int,input().split())
c=-(a//b)
out=[a%b]
while True:
#print(c)
out.append(c%b)
c=-(c//b)
if out[-1]==c==0:
break
print(len(out)-1)
for i in out[:-1]:
print(i,end=" ")
print()
``` | output | 1 | 8,809 | 22 | 17,619 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In order to put away old things and welcome a fresh new year, a thorough cleaning of the house is a must.
Little Tommy finds an old polynomial and cleaned it up by taking it modulo another. But now he regrets doing this...
Given two intege... | instruction | 0 | 8,810 | 22 | 17,620 |
Tags: math
Correct Solution:
```
n,a = map(int,input().split())
ar = []
j = 1
while n!=0:
q = n%a
n //= a
n = -1*n
#j += 1
ar.append(q)
print(len(ar))
for i in range(len(ar)):
print(ar[i])
``` | output | 1 | 8,810 | 22 | 17,621 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In order to put away old things and welcome a fresh new year, a thorough cleaning of the house is a must.
Little Tommy finds an old polynomial and cleaned it up by taking it modulo another. But now he regrets doing this...
Given two intege... | instruction | 0 | 8,811 | 22 | 17,622 |
Tags: math
Correct Solution:
```
p, k = map(int, input().split())
if p < k:
print(1)
print(p)
else:
ans = [p]
cur = p
while cur < 0 or cur >= k:
cur = - (cur // k)
ans.append(cur)
arr = []
for i in range(1, len(ans)):
arr.append(str(k*ans[i]+ans[i-1]))
a... | output | 1 | 8,811 | 22 | 17,623 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In order to put away old things and welcome a fresh new year, a thorough cleaning of the house is a must.
Little Tommy finds an old polynomial and cleaned it up by taking it modulo another. But now he regrets doing this...
Given two intege... | instruction | 0 | 8,812 | 22 | 17,624 |
Tags: math
Correct Solution:
```
p, k = map(int, input().split())
a = ''
cnt = 0
while p != 0:
cnt += 1
a += str(p % k) + ' '
p -= p % k
p //= -k
print(cnt)
print(a)
``` | output | 1 | 8,812 | 22 | 17,625 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In order to put away old things and welcome a fresh new year, a thorough cleaning of the house is a must.
Little Tommy finds an old polynomial and cleaned it up by taking it modulo another. But... | instruction | 0 | 8,813 | 22 | 17,626 |
Yes | output | 1 | 8,813 | 22 | 17,627 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In order to put away old things and welcome a fresh new year, a thorough cleaning of the house is a must.
Little Tommy finds an old polynomial and cleaned it up by taking it modulo another. But... | instruction | 0 | 8,814 | 22 | 17,628 |
Yes | output | 1 | 8,814 | 22 | 17,629 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In order to put away old things and welcome a fresh new year, a thorough cleaning of the house is a must.
Little Tommy finds an old polynomial and cleaned it up by taking it modulo another. But... | instruction | 0 | 8,815 | 22 | 17,630 |
Yes | output | 1 | 8,815 | 22 | 17,631 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In order to put away old things and welcome a fresh new year, a thorough cleaning of the house is a must.
Little Tommy finds an old polynomial and cleaned it up by taking it modulo another. But... | instruction | 0 | 8,816 | 22 | 17,632 |
Yes | output | 1 | 8,816 | 22 | 17,633 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In order to put away old things and welcome a fresh new year, a thorough cleaning of the house is a must.
Little Tommy finds an old polynomial and cleaned it up by taking it modulo another. But... | instruction | 0 | 8,817 | 22 | 17,634 |
No | output | 1 | 8,817 | 22 | 17,635 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In order to put away old things and welcome a fresh new year, a thorough cleaning of the house is a must.
Little Tommy finds an old polynomial and cleaned it up by taking it modulo another. But... | instruction | 0 | 8,818 | 22 | 17,636 |
No | output | 1 | 8,818 | 22 | 17,637 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In order to put away old things and welcome a fresh new year, a thorough cleaning of the house is a must.
Little Tommy finds an old polynomial and cleaned it up by taking it modulo another. But... | instruction | 0 | 8,819 | 22 | 17,638 |
No | output | 1 | 8,819 | 22 | 17,639 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In order to put away old things and welcome a fresh new year, a thorough cleaning of the house is a must.
Little Tommy finds an old polynomial and cleaned it up by taking it modulo another. But... | instruction | 0 | 8,820 | 22 | 17,640 |
No | output | 1 | 8,820 | 22 | 17,641 |
Provide tags and a correct Python 3 solution for this coding contest problem.
<image> <image>
*The two images are equivalent, feel free to use either one.
Input
The input contains a single integer a (-100 ≤ a ≤ 100).
Output
Output the result – an integer number.
Example
Input
1
Output
1 | instruction | 0 | 9,317 | 22 | 18,634 |
Tags: *special, math
Correct Solution:
```
import sys
import math
from bisect import bisect_left
import heapq
def II():
return int(sys.stdin.readline())
def LI():
return list(map(int, sys.stdin.readline().split()))
def MI():
return map(int, sys.stdin.readline().split())
def SI():
return sys.stdin.readline().s... | output | 1 | 9,317 | 22 | 18,635 |
Provide a correct Python 3 solution for this coding contest problem.
You are a teacher at a cram school for elementary school pupils.
One day, you showed your students how to calculate division of fraction in a class of mathematics. Your lesson was kind and fluent, and it seemed everything was going so well - except ... | instruction | 0 | 9,864 | 22 | 19,728 |
"Correct Solution:
```
def gcd(a,b):
while b:a,b=b,a%b
return a
def f(n,m):
if m==1:return 0
x=1
for i in range(m):
x=(x*n)%m
if x==1:return i+1
while 1:
a,b=map(int,input().split())
if a==0:break
c=gcd(a,b)
a//=c;b//=c
cnt=0;d=gcd(b,10)
while d!=1:
... | output | 1 | 9,864 | 22 | 19,729 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You have given an array a of length n and an integer x to a brand new robot. What the robot does is the following: it iterates over the elements of the array, let the current element be q. If q is divisible by x, the robot adds x copies of t... | instruction | 0 | 10,159 | 22 | 20,318 |
Tags: brute force, greedy, implementation, math
Correct Solution:
```
def main():
t = int(input())
for _ in range(t):
n, x = map(int, input().split())
a = list(map(int, input().split()))
l = []; mx = 0
for i in range(n):
e = a[i]
p = 0
while e ... | output | 1 | 10,159 | 22 | 20,319 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You have given an array a of length n and an integer x to a brand new robot. What the robot does is the following: it iterates over the elements of the array, let the current element be q. If q is divisible by x, the robot adds x copies of t... | instruction | 0 | 10,160 | 22 | 20,320 |
Tags: brute force, greedy, implementation, math
Correct Solution:
```
def strangeList(a,x):
i=0
n=len(a)
count=0
flag=0
while True:
j=0
while j<n:
if a[j]%(x**i)==0:
count+=a[j]
else:
return count
j+=1
... | output | 1 | 10,160 | 22 | 20,321 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You have given an array a of length n and an integer x to a brand new robot. What the robot does is the following: it iterates over the elements of the array, let the current element be q. If q is divisible by x, the robot adds x copies of t... | instruction | 0 | 10,161 | 22 | 20,322 |
Tags: brute force, greedy, implementation, math
Correct Solution:
```
for _ in range(int(input())):
n,x=map(int,input().split())
arr=list(map(int,input().split()))
res=0
tmp=arr.copy()
new_arr=[0]*n
for i in range(n):
cnt=0
while arr[i]%x==0:
cnt+=1
arr[i]... | output | 1 | 10,161 | 22 | 20,323 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You have given an array a of length n and an integer x to a brand new robot. What the robot does is the following: it iterates over the elements of the array, let the current element be q. If q is divisible by x, the robot adds x copies of t... | instruction | 0 | 10,162 | 22 | 20,324 |
Tags: brute force, greedy, implementation, math
Correct Solution:
```
# Code Submission
#
# Author : GuptaSir
# Date : 05:01:2021
# Time : 20:14:45
#
import os
import sys
from io import BytesIO, IOBase
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fi... | output | 1 | 10,162 | 22 | 20,325 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You have given an array a of length n and an integer x to a brand new robot. What the robot does is the following: it iterates over the elements of the array, let the current element be q. If q is divisible by x, the robot adds x copies of t... | instruction | 0 | 10,163 | 22 | 20,326 |
Tags: brute force, greedy, implementation, math
Correct Solution:
```
for i in range(int(input())):
n, x = map(int, input().split())
a = list(map(int, input().split()))
ans, mi, midx = 0, 10**10, n - 1
for i in range(n):
y = a[i]
cnt = 0
while(True):
if(y % x):
break
else:
cnt += 1;
y /= x
... | output | 1 | 10,163 | 22 | 20,327 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You have given an array a of length n and an integer x to a brand new robot. What the robot does is the following: it iterates over the elements of the array, let the current element be q. If q is divisible by x, the robot adds x copies of t... | instruction | 0 | 10,164 | 22 | 20,328 |
Tags: brute force, greedy, implementation, math
Correct Solution:
```
###pyrival template for fast IO
import os
import sys
from io import BytesIO, IOBase
# region fastio
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
... | output | 1 | 10,164 | 22 | 20,329 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You have given an array a of length n and an integer x to a brand new robot. What the robot does is the following: it iterates over the elements of the array, let the current element be q. If q is divisible by x, the robot adds x copies of t... | instruction | 0 | 10,165 | 22 | 20,330 |
Tags: brute force, greedy, implementation, math
Correct Solution:
```
t=int(input())
for _ in range(t):
l=list(map(int,input().split()))
n,x=l[0],l[1]
l=list(map(int,input().split()))
arr=[]
for i in range(n):
k=0
p=l[i]
while(p%x==0):
k+=1
p=p//x
... | output | 1 | 10,165 | 22 | 20,331 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You have given an array a of length n and an integer x to a brand new robot. What the robot does is the following: it iterates over the elements of the array, let the current element be q. If q is divisible by x, the robot adds x copies of t... | instruction | 0 | 10,166 | 22 | 20,332 |
Tags: brute force, greedy, implementation, math
Correct Solution:
```
for _ in range(int(input())):
n, x = [int(i) for i in input().split(' ')]
a = [int(i) for i in input().split(' ')]
m = 0
summ = 0
stop = 0
while True:
for i in a:
if i % x**m == 0:
summ += i... | output | 1 | 10,166 | 22 | 20,333 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an array of positive integers a = [a_0, a_1, ..., a_{n - 1}] (n ≥ 2).
In one step, the array a is replaced with another array of length n, in which each element is the [greatest c... | instruction | 0 | 10,215 | 22 | 20,430 |
Yes | output | 1 | 10,215 | 22 | 20,431 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an array of positive integers a = [a_0, a_1, ..., a_{n - 1}] (n ≥ 2).
In one step, the array a is replaced with another array of length n, in which each element is the [greatest c... | instruction | 0 | 10,216 | 22 | 20,432 |
Yes | output | 1 | 10,216 | 22 | 20,433 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an array of positive integers a = [a_0, a_1, ..., a_{n - 1}] (n ≥ 2).
In one step, the array a is replaced with another array of length n, in which each element is the [greatest c... | instruction | 0 | 10,217 | 22 | 20,434 |
Yes | output | 1 | 10,217 | 22 | 20,435 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an array of positive integers a = [a_0, a_1, ..., a_{n - 1}] (n ≥ 2).
In one step, the array a is replaced with another array of length n, in which each element is the [greatest c... | instruction | 0 | 10,218 | 22 | 20,436 |
Yes | output | 1 | 10,218 | 22 | 20,437 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an array of positive integers a = [a_0, a_1, ..., a_{n - 1}] (n ≥ 2).
In one step, the array a is replaced with another array of length n, in which each element is the [greatest c... | instruction | 0 | 10,219 | 22 | 20,438 |
No | output | 1 | 10,219 | 22 | 20,439 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an array of positive integers a = [a_0, a_1, ..., a_{n - 1}] (n ≥ 2).
In one step, the array a is replaced with another array of length n, in which each element is the [greatest c... | instruction | 0 | 10,220 | 22 | 20,440 |
No | output | 1 | 10,220 | 22 | 20,441 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an array of positive integers a = [a_0, a_1, ..., a_{n - 1}] (n ≥ 2).
In one step, the array a is replaced with another array of length n, in which each element is the [greatest c... | instruction | 0 | 10,221 | 22 | 20,442 |
No | output | 1 | 10,221 | 22 | 20,443 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an array of positive integers a = [a_0, a_1, ..., a_{n - 1}] (n ≥ 2).
In one step, the array a is replaced with another array of length n, in which each element is the [greatest c... | instruction | 0 | 10,222 | 22 | 20,444 |
No | output | 1 | 10,222 | 22 | 20,445 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Btoh yuo adn yuor roomatme lhoate wianshg disehs, btu stlil sdmoeboy msut peorrfm tihs cohre dialy. Oen dya yuo decdie to idourtcne smoe syestm. Yuor rmmotaoe sstgegus teh fooniwllg dael. Yuo argee on tow arayrs of ientgres M adn R, nmebur u... | instruction | 0 | 11,225 | 22 | 22,450 |
Tags: *special, implementation
Correct Solution:
```
from fractions import gcd
from functools import reduce
from operator import mul
n = int(input())
m = [int(x) for x in input().split()]
r = [int(x) for x in input().split()]
lcm = m[0]
if len(m) > 1:
lcm = reduce(mul, m, 1) // reduce(gcd, m, 0)
res = 0
for d in... | output | 1 | 11,225 | 22 | 22,451 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given n integers a1, a2, ..., an. Find the number of pairs of indexes i, j (i < j) that ai + aj is a power of 2 (i. e. some integer x exists so that ai + aj = 2x).
Input
The first line contains the single positive integer n (1 ≤ n ... | instruction | 0 | 11,243 | 22 | 22,486 |
Tags: brute force, data structures, implementation, math
Correct Solution:
```
R = lambda: map(int, input().split())
n = int(input())
res = 0
vsts = {}
for num in R():
res += sum(vsts.get((1 << pwr) - num, 0) for pwr in range(32))
vsts[num] = vsts.get(num, 0) + 1
print(res)
``` | output | 1 | 11,243 | 22 | 22,487 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given n integers a1, a2, ..., an. Find the number of pairs of indexes i, j (i < j) that ai + aj is a power of 2 (i. e. some integer x exists so that ai + aj = 2x).
Input
The first line contains the single positive integer n (1 ≤ n ... | instruction | 0 | 11,244 | 22 | 22,488 |
Tags: brute force, data structures, implementation, math
Correct Solution:
```
from collections import Counter
n = int(input())
arr = list(map(int, input().split()))
cnt = Counter()
ans = 0
for v in arr:
for i in range(32):
ans += cnt[2 ** i - v]
cnt[v] += 1
print(ans)
``` | output | 1 | 11,244 | 22 | 22,489 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given n integers a1, a2, ..., an. Find the number of pairs of indexes i, j (i < j) that ai + aj is a power of 2 (i. e. some integer x exists so that ai + aj = 2x).
Input
The first line contains the single positive integer n (1 ≤ n ... | instruction | 0 | 11,245 | 22 | 22,490 |
Tags: brute force, data structures, implementation, math
Correct Solution:
```
n = int(input())
a = [int(x) for x in input().split()]
p2 = [2**i for i in range(31)]
d = {}
for i in a:
if i in d:
d[i] += 1
else:
d[i] = 1
k = 0
for i in d:
for p in p2:
j = p - i
if j > i:
... | output | 1 | 11,245 | 22 | 22,491 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given n integers a1, a2, ..., an. Find the number of pairs of indexes i, j (i < j) that ai + aj is a power of 2 (i. e. some integer x exists so that ai + aj = 2x).
Input
The first line contains the single positive integer n (1 ≤ n ... | instruction | 0 | 11,246 | 22 | 22,492 |
Tags: brute force, data structures, implementation, math
Correct Solution:
```
n = int(input())
l = list(map(int, input().split()))
dic = {}
for i in range(n):
x = l[i]
dic[x] = 0
for i in range(n):
x = l[i]
dic[x] += 1
s = max(l)
m = 0
num = 0
while 2 ** m <= s:
m += 1
for i in range(n):
a = l[... | output | 1 | 11,246 | 22 | 22,493 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given n integers a1, a2, ..., an. Find the number of pairs of indexes i, j (i < j) that ai + aj is a power of 2 (i. e. some integer x exists so that ai + aj = 2x).
Input
The first line contains the single positive integer n (1 ≤ n ... | instruction | 0 | 11,247 | 22 | 22,494 |
Tags: brute force, data structures, implementation, math
Correct Solution:
```
t = input
p = print
r = range
n = int(t())
a = list(map(int, t().split()))
c = 0
co = {x: 0 for x in range(100000)}
po = [2 ** x for x in range(33)]
for i in range(n):
if a[i] in co:
c += co.get(a[i])
for j in range(len(po)):... | output | 1 | 11,247 | 22 | 22,495 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given n integers a1, a2, ..., an. Find the number of pairs of indexes i, j (i < j) that ai + aj is a power of 2 (i. e. some integer x exists so that ai + aj = 2x).
Input
The first line contains the single positive integer n (1 ≤ n ... | instruction | 0 | 11,248 | 22 | 22,496 |
Tags: brute force, data structures, implementation, math
Correct Solution:
```
n=int(input())
a=list(map(int,input().split()))
dic={}
for i in a:
if i in dic:
dic[i]+=1
else:
dic[i]=1
div=0
for i in range(n):
dic[a[i]]-=1
for j in range(1,32):
if 2**j - a[i] in dic:
d... | output | 1 | 11,248 | 22 | 22,497 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given n integers a1, a2, ..., an. Find the number of pairs of indexes i, j (i < j) that ai + aj is a power of 2 (i. e. some integer x exists so that ai + aj = 2x).
Input
The first line contains the single positive integer n (1 ≤ n ... | instruction | 0 | 11,249 | 22 | 22,498 |
Tags: brute force, data structures, implementation, math
Correct Solution:
```
import io, os
import sys
from atexit import register
from random import randint
DEBUG = False
if not DEBUG:
input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
sys.stdout = io.BytesIO()
register(lambda: os.write(1, sys.stdout.... | output | 1 | 11,249 | 22 | 22,499 |
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