message stringlengths 2 59.7k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 37 108k | cluster float64 20 20 | __index_level_0__ int64 74 217k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasily has a number a, which he wants to turn into a number b. For this purpose, he can do two types of operations:
* multiply the current number by 2 (that is, replace the number x by 2·x);
* append the digit 1 to the right of current... | instruction | 0 | 12,114 | 20 | 24,228 |
Tags: brute force, dfs and similar, math
Correct Solution:
```
a,b=[int(i) for i in input().split()]
res=[b]
n=b
while n>a:
if n%2==0:
n=n//2
res.insert(0,n)
elif n%10==1:
n=(n-1)//10
res.insert(0,n)
else:
print('NO')
break
else:
if n==a:
print('YE... | output | 1 | 12,114 | 20 | 24,229 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasily has a number a, which he wants to turn into a number b. For this purpose, he can do two types of operations:
* multiply the current number by 2 (that is, replace the number x by 2·x);
* append the digit 1 to the right of current... | instruction | 0 | 12,115 | 20 | 24,230 |
Tags: brute force, dfs and similar, math
Correct Solution:
```
import math
a = []
def dfs( pos, need ):
x = a[pos]
# print( x )
if x > need:
return
if x == need:
print( "YES" )
print( pos + 1 )
print( *a )
# for i in a:
# print( i )
exit( 0 )
a.append( x * 2 )
dfs( pos + 1, need )
a.pop()
a.app... | output | 1 | 12,115 | 20 | 24,231 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasily has a number a, which he wants to turn into a number b. For this purpose, he can do two types of operations:
* multiply the current number by 2 (that is, replace the number x by 2·x);
* append the digit 1 to the right of current... | instruction | 0 | 12,116 | 20 | 24,232 |
Tags: brute force, dfs and similar, math
Correct Solution:
```
a,b=input().split(' ')
a=int(a)
b=int(b)
c=[]
d=0
flag=0
c.append(b)
while True:
if (b-1)%10==0:
b=(b-1)/10
d+=1
flag=1
c.append(b)
elif b%2==0:
b=b/2
flag=1
c.append(b)
... | output | 1 | 12,116 | 20 | 24,233 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasily has a number a, which he wants to turn into a number b. For this purpose, he can do two types of operations:
* multiply the current number by 2 (that is, replace the number x by 2·x);
* append the digit 1 to the right of current... | instruction | 0 | 12,117 | 20 | 24,234 |
Tags: brute force, dfs and similar, math
Correct Solution:
```
a, b = map(int, input().split())
A = [b]
while b > a:
if b % 2 == 0:
b //= 2
elif b % 10 == 1:
b //= 10
else:
break
A.append(b)
if A[-1] == a:
print('YES')
print(len(A))
print(*A[::-1])
else:
print('NO... | output | 1 | 12,117 | 20 | 24,235 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasily has a number a, which he wants to turn into a number b. For this purpose, he can do two types of operations:
* multiply the current number by 2 (that is, replace the number x by 2·x);
* append the digit 1 to the right of current... | instruction | 0 | 12,118 | 20 | 24,236 |
Tags: brute force, dfs and similar, math
Correct Solution:
```
f, n = map(int, input().split())
flag = True
lst = [n]
k = ''
while n > f:
if n % 10 == 1:
k = str(n)
n = int(k[:len(k)-1])
if n < f:
flag = False
break
elif n % 2 == 0:
n //= 2
if n <... | output | 1 | 12,118 | 20 | 24,237 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasily has a number a, which he wants to turn into a number b. For this purpose, he can do two types of operations:
* multiply the current number by 2 (that is, replace the number x by 2·x);
* append the digit 1 to the right of current... | instruction | 0 | 12,119 | 20 | 24,238 |
Tags: brute force, dfs and similar, math
Correct Solution:
```
num_possuido, num_desejado = map(int, input().split())
aux = []
aux.append(num_desejado)
while(num_desejado > num_possuido):
if (num_desejado % 10) == 1:
num_desejado = num_desejado // 10
aux.append(num_desejado)
elif (num_desejado % 2 == 0):
... | output | 1 | 12,119 | 20 | 24,239 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasily has a number a, which he wants to turn into a number b. For this purpose, he can do two types of operations:
* multiply the current number by 2 (that is, replace the number x by 2·x);
* append the digit 1 to the right of current... | instruction | 0 | 12,120 | 20 | 24,240 |
Tags: brute force, dfs and similar, math
Correct Solution:
```
n = []
def a_to_b(a, b):
if b % 2 == 0:
b = b / 2
if b >= a:
n.insert(0, int(b))
a_to_b(a, b)
elif b % 10 == 1:
b = b // 10
if b >= a:
n.insert(0, int(b))
a_to_b(a, b... | output | 1 | 12,120 | 20 | 24,241 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasily has a number a, which he wants to turn into a number b. For this purpose, he can do two types of operations:
* multiply the current number by 2 (that is, replace the number x by 2·x);
* append the digit 1 to the right of current... | instruction | 0 | 12,121 | 20 | 24,242 |
Tags: brute force, dfs and similar, math
Correct Solution:
```
a,b=map(int,input("").split())
oplst=[]
oplst.append(b)
for i in range(b):
if(b%10==1):
b=b//10
oplst.append(b)
if(b==a):
print("YES")
print(len(oplst))
oplst.reverse()
print(*oplst... | output | 1 | 12,121 | 20 | 24,243 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasily has a number a, which he wants to turn into a number b. For this purpose, he can do two types of operations:
* multiply the current number by 2 (that is, replace the number x by 2·x); ... | instruction | 0 | 12,122 | 20 | 24,244 |
Yes | output | 1 | 12,122 | 20 | 24,245 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasily has a number a, which he wants to turn into a number b. For this purpose, he can do two types of operations:
* multiply the current number by 2 (that is, replace the number x by 2·x); ... | instruction | 0 | 12,123 | 20 | 24,246 |
Yes | output | 1 | 12,123 | 20 | 24,247 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasily has a number a, which he wants to turn into a number b. For this purpose, he can do two types of operations:
* multiply the current number by 2 (that is, replace the number x by 2·x); ... | instruction | 0 | 12,124 | 20 | 24,248 |
Yes | output | 1 | 12,124 | 20 | 24,249 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasily has a number a, which he wants to turn into a number b. For this purpose, he can do two types of operations:
* multiply the current number by 2 (that is, replace the number x by 2·x); ... | instruction | 0 | 12,125 | 20 | 24,250 |
Yes | output | 1 | 12,125 | 20 | 24,251 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasily has a number a, which he wants to turn into a number b. For this purpose, he can do two types of operations:
* multiply the current number by 2 (that is, replace the number x by 2·x); ... | instruction | 0 | 12,126 | 20 | 24,252 |
No | output | 1 | 12,126 | 20 | 24,253 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasily has a number a, which he wants to turn into a number b. For this purpose, he can do two types of operations:
* multiply the current number by 2 (that is, replace the number x by 2·x); ... | instruction | 0 | 12,127 | 20 | 24,254 |
No | output | 1 | 12,127 | 20 | 24,255 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasily has a number a, which he wants to turn into a number b. For this purpose, he can do two types of operations:
* multiply the current number by 2 (that is, replace the number x by 2·x); ... | instruction | 0 | 12,128 | 20 | 24,256 |
No | output | 1 | 12,128 | 20 | 24,257 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasily has a number a, which he wants to turn into a number b. For this purpose, he can do two types of operations:
* multiply the current number by 2 (that is, replace the number x by 2·x); ... | instruction | 0 | 12,129 | 20 | 24,258 |
No | output | 1 | 12,129 | 20 | 24,259 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Mahmoud and Ehab are on the third stage of their adventures now. As you know, Dr. Evil likes sets. This time he won't show them any set from his large collection, but will ask them to create a new set to replenish his beautiful collection of... | instruction | 0 | 12,217 | 20 | 24,434 |
Tags: constructive algorithms
Correct Solution:
```
def readints():
return [int(s) for s in input().strip().split()]
def to_s(int_objs):
return [str(obj) for obj in int_objs]
class Solver:
def main(self):
n, x = readints()
if n == 1:
print('Yes\n{}'.format(x))
elif x ... | output | 1 | 12,217 | 20 | 24,435 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two huge binary integer numbers a and b of lengths n and m respectively. You will repeat the following process: if b > 0, then add to the answer the value a~ \&~ b and divide b by 2 rounding down (i.e. remove the last digit of ... | instruction | 0 | 12,473 | 20 | 24,946 |
Tags: data structures, implementation, math
Correct Solution:
```
md=998244353
n,m=map(int,input().split())
a=input()
b=input()
aa=[]
bb=[]
for i in a:
aa.append(int(i))
for i in b:
bb.append(int(i))
for i in range (1,len(bb)):
bb[i]+=bb[i-1]
aa.reverse()
bb.reverse()
tp=[1]
for i in range (1,len(aa))... | output | 1 | 12,473 | 20 | 24,947 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two huge binary integer numbers a and b of lengths n and m respectively. You will repeat the following process: if b > 0, then add to the answer the value a~ \&~ b and divide b by 2 rounding down (i.e. remove the last digit of ... | instruction | 0 | 12,474 | 20 | 24,948 |
Tags: data structures, implementation, math
Correct Solution:
```
import math
N = 2e5 + 10
PI = math.acos(-1.0);
EXP = 1E-8;
INF = 0x3f3f3f3f;
MOD = 998244353;
def add(a, b):
a += b
if (a < 0):
a += MOD
if (a >= MOD):
a -= MOD
return a
n, m = map(int, input().split())
s = input()
t = i... | output | 1 | 12,474 | 20 | 24,949 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two huge binary integer numbers a and b of lengths n and m respectively. You will repeat the following process: if b > 0, then add to the answer the value a~ \&~ b and divide b by 2 rounding down (i.e. remove the last digit of ... | instruction | 0 | 12,475 | 20 | 24,950 |
Tags: data structures, implementation, math
Correct Solution:
```
n,m = map(int,input().split())
a = input()[::-1]
b = input()[::-1]
c = 0
f = b.count('1')
wer = 1
for i in range(min(m,n)):
if a[i] == '1':
c += f * wer
c %= 998244353
if b[i] == '1':
f -= 1
wer *= 2
wer %= 998244... | output | 1 | 12,475 | 20 | 24,951 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two huge binary integer numbers a and b of lengths n and m respectively. You will repeat the following process: if b > 0, then add to the answer the value a~ \&~ b and divide b by 2 rounding down (i.e. remove the last digit of ... | instruction | 0 | 12,476 | 20 | 24,952 |
Tags: data structures, implementation, math
Correct Solution:
```
n, m = map(int,input().split())
a = input()
b = input()
if n > m:
b = (n-m)*'0' + b
if m > n:
a = (m - n)*'0' + a
n = max(m, n)
c = []
mod = 998244353
for i in range(0, n):
c.append(int(b[i]))
if i:
c[i] += c[i-1]
val = 1
ans = 0
... | output | 1 | 12,476 | 20 | 24,953 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two huge binary integer numbers a and b of lengths n and m respectively. You will repeat the following process: if b > 0, then add to the answer the value a~ \&~ b and divide b by 2 rounding down (i.e. remove the last digit of ... | instruction | 0 | 12,477 | 20 | 24,954 |
Tags: data structures, implementation, math
Correct Solution:
```
#####################################
import atexit, io, sys, collections, math, heapq, fractions,copy, os, functools
import sys
import random
import collections
from io import BytesIO, IOBase
##################################### python 3 START
... | output | 1 | 12,477 | 20 | 24,955 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two huge binary integer numbers a and b of lengths n and m respectively. You will repeat the following process: if b > 0, then add to the answer the value a~ \&~ b and divide b by 2 rounding down (i.e. remove the last digit of ... | instruction | 0 | 12,478 | 20 | 24,956 |
Tags: data structures, implementation, math
Correct Solution:
```
n,m = map(int,input().split())
a = input()
b = input()
if n > m: b = '0'*(n-m) + b
elif m > n: a = '0'*(m-n) + a
ans = cnt = 0
mod = 998244353
for i in range(max(n,m)):
if b[i] == '1': cnt += 1
if a[i] == '1':
ans = (ans+cnt*pow(2,max(n,m... | output | 1 | 12,478 | 20 | 24,957 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two huge binary integer numbers a and b of lengths n and m respectively. You will repeat the following process: if b > 0, then add to the answer the value a~ \&~ b and divide b by 2 rounding down (i.e. remove the last digit of ... | instruction | 0 | 12,479 | 20 | 24,958 |
Tags: data structures, implementation, math
Correct Solution:
```
def modular_pow(base, exponent, modulus):
result = 1
base = base % modulus
while exponent > 0:
if exponent % 2 == 1:
result = (result * base) % modulus
exponent = exponent >> 1
base = (base * base) % modulu... | output | 1 | 12,479 | 20 | 24,959 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two huge binary integer numbers a and b of lengths n and m respectively. You will repeat the following process: if b > 0, then add to the answer the value a~ \&~ b and divide b by 2 rounding down (i.e. remove the last digit of ... | instruction | 0 | 12,480 | 20 | 24,960 |
Tags: data structures, implementation, math
Correct Solution:
```
def solve(a, b):
res = 0
preprocess = 0
pw = 1
for i in range(len(b)):
if i < len(a) and a[-i - 1] == '1':
preprocess = (pw + preprocess) % 998244353
if b[-i - 1] == '1':
res = (res + preprocess) % ... | output | 1 | 12,480 | 20 | 24,961 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two huge binary integer numbers a and b of lengths n and m respectively. You will repeat the following process: if b > 0, then add to the answer the value a~ \&~ b and divide b by ... | instruction | 0 | 12,481 | 20 | 24,962 |
Yes | output | 1 | 12,481 | 20 | 24,963 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two huge binary integer numbers a and b of lengths n and m respectively. You will repeat the following process: if b > 0, then add to the answer the value a~ \&~ b and divide b by ... | instruction | 0 | 12,482 | 20 | 24,964 |
Yes | output | 1 | 12,482 | 20 | 24,965 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two huge binary integer numbers a and b of lengths n and m respectively. You will repeat the following process: if b > 0, then add to the answer the value a~ \&~ b and divide b by ... | instruction | 0 | 12,483 | 20 | 24,966 |
Yes | output | 1 | 12,483 | 20 | 24,967 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two huge binary integer numbers a and b of lengths n and m respectively. You will repeat the following process: if b > 0, then add to the answer the value a~ \&~ b and divide b by ... | instruction | 0 | 12,484 | 20 | 24,968 |
Yes | output | 1 | 12,484 | 20 | 24,969 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two huge binary integer numbers a and b of lengths n and m respectively. You will repeat the following process: if b > 0, then add to the answer the value a~ \&~ b and divide b by ... | instruction | 0 | 12,485 | 20 | 24,970 |
No | output | 1 | 12,485 | 20 | 24,971 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two huge binary integer numbers a and b of lengths n and m respectively. You will repeat the following process: if b > 0, then add to the answer the value a~ \&~ b and divide b by ... | instruction | 0 | 12,486 | 20 | 24,972 |
No | output | 1 | 12,486 | 20 | 24,973 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two huge binary integer numbers a and b of lengths n and m respectively. You will repeat the following process: if b > 0, then add to the answer the value a~ \&~ b and divide b by ... | instruction | 0 | 12,487 | 20 | 24,974 |
No | output | 1 | 12,487 | 20 | 24,975 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two huge binary integer numbers a and b of lengths n and m respectively. You will repeat the following process: if b > 0, then add to the answer the value a~ \&~ b and divide b by ... | instruction | 0 | 12,488 | 20 | 24,976 |
No | output | 1 | 12,488 | 20 | 24,977 |
Provide a correct Python 3 solution for this coding contest problem.
Professor Matsuzaki is a scientist studying the truth of the universe. Life, the universe, all the answers are said to be 42, but Professor Matsuzaki thinks that this alone is not enough to elucidate the truth of the universe. Professor Matsuzaki bel... | instruction | 0 | 13,242 | 20 | 26,484 |
"Correct Solution:
```
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools
sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**10
mod = 998244353
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LI_(): return [int(x)-1 for x in sys.stdin.rea... | output | 1 | 13,242 | 20 | 26,485 |
Provide a correct Python 3 solution for this coding contest problem.
Professor Matsuzaki is a scientist studying the truth of the universe. Life, the universe, all the answers are said to be 42, but Professor Matsuzaki thinks that this alone is not enough to elucidate the truth of the universe. Professor Matsuzaki bel... | instruction | 0 | 13,243 | 20 | 26,486 |
"Correct Solution:
```
from itertools import *
N=101198;n=range(N);a=list(n);a[1]=0
for i in range(2,int(N**.5)+1):a[i*2::i]=[0]*len(a[i*2::i])
for e in iter(input, '-1 -1'):
qN, qP = map(int, e.split())
p=[x for x in a[qN+1:]if x][:qP+1]
print(sorted(p[i]+p[j]for i in range(qP)for j in range(i,qP))[qP-1])... | output | 1 | 13,243 | 20 | 26,487 |
Provide a correct Python 3 solution for this coding contest problem.
Professor Matsuzaki is a scientist studying the truth of the universe. Life, the universe, all the answers are said to be 42, but Professor Matsuzaki thinks that this alone is not enough to elucidate the truth of the universe. Professor Matsuzaki bel... | instruction | 0 | 13,244 | 20 | 26,488 |
"Correct Solution:
```
import bisect
pr=[]
for i in range(2,110000):
for j in range(2,int(i**0.5)+1):
if not i%j:break
else:pr+=[i]
while 1:
n,p=map(int,input().split())
if n<0:break
a=bisect.bisect_right(pr,n)
print(sorted([pr[i]+pr[j] for i in range(a,a+p) for j in range(i,a+p)])[p-1])... | output | 1 | 13,244 | 20 | 26,489 |
Provide a correct Python 3 solution for this coding contest problem.
Professor Matsuzaki is a scientist studying the truth of the universe. Life, the universe, all the answers are said to be 42, but Professor Matsuzaki thinks that this alone is not enough to elucidate the truth of the universe. Professor Matsuzaki bel... | instruction | 0 | 13,245 | 20 | 26,490 |
"Correct Solution:
```
from bisect import bisect_right as br
from itertools import combinations_with_replacement as cwr
MAX = 110000
ROOT = 340
tf = [True] * MAX
tf[0] = tf[1] = False
for i in range(2, ROOT + 1):
if tf[i]:
for j in range(i * i, MAX, i):
tf[j] = False
primes = [i for i in range(MAX) if tf[i... | output | 1 | 13,245 | 20 | 26,491 |
Provide a correct Python 3 solution for this coding contest problem.
Professor Matsuzaki is a scientist studying the truth of the universe. Life, the universe, all the answers are said to be 42, but Professor Matsuzaki thinks that this alone is not enough to elucidate the truth of the universe. Professor Matsuzaki bel... | instruction | 0 | 13,246 | 20 | 26,492 |
"Correct Solution:
```
def prime(n):
primes = [True] * (n+1)
primes[0] = False
primes[1] = False
for i in range(2, int(n**0.5)+1):
if not primes[i]:
continue
for j in range(i*2, n+1, i):
primes[j] = False
return [i for i in range(n+1) if primes[i]]
while ... | output | 1 | 13,246 | 20 | 26,493 |
Provide a correct Python 3 solution for this coding contest problem.
Professor Matsuzaki is a scientist studying the truth of the universe. Life, the universe, all the answers are said to be 42, but Professor Matsuzaki thinks that this alone is not enough to elucidate the truth of the universe. Professor Matsuzaki bel... | instruction | 0 | 13,247 | 20 | 26,494 |
"Correct Solution:
```
def eratosthenes(n):
prime_table = [False,False,True]+[False if i%2!=0 else True for i in range(n-2)]
i=3
pn=[2]
while i*i<=n:
if prime_table[i]:
j=i*i
pn.append(i)
while j<=n:
prime_table[j]=False
j+=i
... | output | 1 | 13,247 | 20 | 26,495 |
Provide a correct Python 3 solution for this coding contest problem.
Professor Matsuzaki is a scientist studying the truth of the universe. Life, the universe, all the answers are said to be 42, but Professor Matsuzaki thinks that this alone is not enough to elucidate the truth of the universe. Professor Matsuzaki bel... | instruction | 0 | 13,248 | 20 | 26,496 |
"Correct Solution:
```
prime = [True for i in range(200001)]
prime[0] = False
prime[1] = False
p = 2
while p * p <= 200000:
if prime[p]:
for i in range(p * 2, 200001, p):
prime[i] = False
p += 1
while True:
N, P = map(int, input().split())
if N < 0:
exit()
li = []
fo... | output | 1 | 13,248 | 20 | 26,497 |
Provide a correct Python 3 solution for this coding contest problem.
Professor Matsuzaki is a scientist studying the truth of the universe. Life, the universe, all the answers are said to be 42, but Professor Matsuzaki thinks that this alone is not enough to elucidate the truth of the universe. Professor Matsuzaki bel... | instruction | 0 | 13,249 | 20 | 26,498 |
"Correct Solution:
```
import sys
from math import sqrt
from bisect import bisect
inf = 1<<30
def solve():
primes = eratos(2 * 10**5)
while 1:
N, P = map(int, sys.stdin.readline().split())
if N == P == -1:
return
j = bisect(primes, N)
lprimes = primes[j:j + 100]... | output | 1 | 13,249 | 20 | 26,499 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Professor Matsuzaki is a scientist studying the truth of the universe. Life, the universe, all the answers are said to be 42, but Professor Matsuzaki thinks that this alone is not enough to eluc... | instruction | 0 | 13,250 | 20 | 26,500 |
Yes | output | 1 | 13,250 | 20 | 26,501 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Professor Matsuzaki is a scientist studying the truth of the universe. Life, the universe, all the answers are said to be 42, but Professor Matsuzaki thinks that this alone is not enough to eluc... | instruction | 0 | 13,251 | 20 | 26,502 |
Yes | output | 1 | 13,251 | 20 | 26,503 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Professor Matsuzaki is a scientist studying the truth of the universe. Life, the universe, all the answers are said to be 42, but Professor Matsuzaki thinks that this alone is not enough to eluc... | instruction | 0 | 13,252 | 20 | 26,504 |
Yes | output | 1 | 13,252 | 20 | 26,505 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Professor Matsuzaki is a scientist studying the truth of the universe. Life, the universe, all the answers are said to be 42, but Professor Matsuzaki thinks that this alone is not enough to eluc... | instruction | 0 | 13,253 | 20 | 26,506 |
Yes | output | 1 | 13,253 | 20 | 26,507 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Professor Matsuzaki is a scientist studying the truth of the universe. Life, the universe, all the answers are said to be 42, but Professor Matsuzaki thinks that this alone is not enough to eluc... | instruction | 0 | 13,254 | 20 | 26,508 |
No | output | 1 | 13,254 | 20 | 26,509 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya loves lucky numbers very much. Everybody knows that lucky numbers are positive integers whose decimal record contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya has two strin... | instruction | 0 | 13,516 | 20 | 27,032 |
Tags: greedy, implementation
Correct Solution:
```
a=input()
b=input()
sum1=0
sum2=0
for i in range(len(a)):
if(a[i]!=b[i]):
if(a[i]=='4'):
sum1=sum1+1
else:
sum2=sum2+1
print(max(sum1,sum2))
``` | output | 1 | 13,516 | 20 | 27,033 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya loves lucky numbers very much. Everybody knows that lucky numbers are positive integers whose decimal record contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya has two strin... | instruction | 0 | 13,517 | 20 | 27,034 |
Tags: greedy, implementation
Correct Solution:
```
def question3():
A = list(input())
B = list(input())
count_7_4 = 0
count_4_7 = 0
for i in range(len(A)):
if A[i] != B[i]:
if A[i] == "4":
count_4_7 += 1
else:
count_7_4 += 1
count... | output | 1 | 13,517 | 20 | 27,035 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya loves lucky numbers very much. Everybody knows that lucky numbers are positive integers whose decimal record contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya has two strin... | instruction | 0 | 13,518 | 20 | 27,036 |
Tags: greedy, implementation
Correct Solution:
```
def luckyConversion():
count1 = 0
count2 = 0
for i in range(len(a)):
if a[i] == b[i]:
pass
else:
if a[i] == '4':
count1 += 1
if a[i] == '7':
count2 += 1
... | output | 1 | 13,518 | 20 | 27,037 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya loves lucky numbers very much. Everybody knows that lucky numbers are positive integers whose decimal record contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya has two strin... | instruction | 0 | 13,519 | 20 | 27,038 |
Tags: greedy, implementation
Correct Solution:
```
def main():
l = [x == '7' for x, y in zip(input(), input()) if x != y]
x = sum(l)
print(max(x, len(l) - x))
if __name__ == '__main__':
main()
# Made By Mostafa_Khaled
``` | output | 1 | 13,519 | 20 | 27,039 |
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