message
stringlengths
2
30.5k
message_type
stringclasses
2 values
message_id
int64
0
1
conversation_id
int64
237
109k
cluster
float64
10
10
__index_level_0__
int64
474
217k
Provide a correct Python 3 solution for this coding contest problem. Dutch treat You have organized a party to pray for the good performance of the ICPC 2019 Yokohama Regional Domestic Qualifiers. There are N participants in this party. Since it costs M yen in total to hold this party, we decided to collect M / N ye...
instruction
0
98,575
10
197,150
"Correct Solution: ``` while True: n,m=map(int,input().split()) if n==0 and m==0: break a=[int(x) for x in input().split()] ans=0 for i in a: if i<m//n: ans+=i else: ans+=m//n print(ans) ```
output
1
98,575
10
197,151
Provide a correct Python 3 solution for this coding contest problem. You have 4 bags A, B, C and D each of which includes N coins (there are totally 4N coins). Values of the coins in each bag are ai, bi, ci and di respectively. Find the number of combinations that result when you choose one coin from each bag (totall...
instruction
0
98,576
10
197,152
"Correct Solution: ``` import sys,collections as cl,bisect as bs sys.setrecursionlimit(100000) Max = sys.maxsize def l(): return list(map(int,input().split())) def m(): return map(int,input().split()) def onem(): return int(input()) def s(x): a = [] aa = x[0] su = 1 for i in range(len(x)-1): if aa == x[i+1]: ...
output
1
98,576
10
197,153
Provide a correct Python 3 solution for this coding contest problem. You have 4 bags A, B, C and D each of which includes N coins (there are totally 4N coins). Values of the coins in each bag are ai, bi, ci and di respectively. Find the number of combinations that result when you choose one coin from each bag (totall...
instruction
0
98,577
10
197,154
"Correct Solution: ``` N, V = (int(x) for x in input().split()) A = [int(x) for x in input().split()] B = [int(x) for x in input().split()] C = [int(x) for x in input().split()] D = [int(x) for x in input().split()] AB = {} for a in A: for b in B: AB.setdefault(a + b, 0) AB[a + b] += 1 CD = {} for...
output
1
98,577
10
197,155
Provide a correct Python 3 solution for this coding contest problem. You have 4 bags A, B, C and D each of which includes N coins (there are totally 4N coins). Values of the coins in each bag are ai, bi, ci and di respectively. Find the number of combinations that result when you choose one coin from each bag (totall...
instruction
0
98,578
10
197,156
"Correct Solution: ``` import bisect n,v=map(int,input().split( )) A=list(map(int,input().split( ))) B=list(map(int,input().split( ))) C=list(map(int,input().split( ))) D=list(map(int,input().split( ))) AB=[] for i in range(n): for j in range(n): AB.append(A[i]+B[j]) CD=[] for i in range(n): for j in ...
output
1
98,578
10
197,157
Provide a correct Python 3 solution for this coding contest problem. You have 4 bags A, B, C and D each of which includes N coins (there are totally 4N coins). Values of the coins in each bag are ai, bi, ci and di respectively. Find the number of combinations that result when you choose one coin from each bag (totall...
instruction
0
98,579
10
197,158
"Correct Solution: ``` from bisect import * N, V = map(int, input().split()) boxs = [] for i in range(4): boxs.append(list(map(int, input().split()))) pre = [a+b for a in boxs[0] for b in boxs[1]] af = [c+d for c in boxs[2] for d in boxs[3]] pre.sort() af.sort() ans = 0 for ab in pre: target = V - ab ...
output
1
98,579
10
197,159
Provide a correct Python 3 solution for this coding contest problem. You have 4 bags A, B, C and D each of which includes N coins (there are totally 4N coins). Values of the coins in each bag are ai, bi, ci and di respectively. Find the number of combinations that result when you choose one coin from each bag (totall...
instruction
0
98,580
10
197,160
"Correct Solution: ``` import bisect, collections, copy, heapq, itertools, math, string, sys input = lambda: sys.stdin.readline().rstrip() sys.setrecursionlimit(10**7) INF = float('inf') def I(): return int(input()) def F(): return float(input()) def SS(): return input() def LI(): return [int(x) for x in input().split...
output
1
98,580
10
197,161
Provide a correct Python 3 solution for this coding contest problem. You have 4 bags A, B, C and D each of which includes N coins (there are totally 4N coins). Values of the coins in each bag are ai, bi, ci and di respectively. Find the number of combinations that result when you choose one coin from each bag (totall...
instruction
0
98,581
10
197,162
"Correct Solution: ``` # -*- coding: utf-8 -*- """ http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=DPL_4_A AC """ import sys from sys import stdin from bisect import bisect_right, bisect_left input = stdin.readline def main(args): N, V = map(int, input().split()) A = [int(x) for x in input().split()]...
output
1
98,581
10
197,163
Provide a correct Python 3 solution for this coding contest problem. You have 4 bags A, B, C and D each of which includes N coins (there are totally 4N coins). Values of the coins in each bag are ai, bi, ci and di respectively. Find the number of combinations that result when you choose one coin from each bag (totall...
instruction
0
98,582
10
197,164
"Correct Solution: ``` #!usr/bin/env python3 from collections import defaultdict import math import bisect def LI(): return list(map(int, input().split())) def II(): return int(input()) def LS(): return input().split() def S(): return input() def IIR(n): return [II() for i in range(n)] def LIR(n): return [LI() for i in...
output
1
98,582
10
197,165
Provide a correct Python 3 solution for this coding contest problem. You have 4 bags A, B, C and D each of which includes N coins (there are totally 4N coins). Values of the coins in each bag are ai, bi, ci and di respectively. Find the number of combinations that result when you choose one coin from each bag (totall...
instruction
0
98,583
10
197,166
"Correct Solution: ``` from collections import Counter if __name__ == "__main__": N, V = map(lambda x: int(x), input().split()) bags = [list(map(lambda x: int(x), input().split())) for _ in range(4)] merged_0_1 = Counter(v1 + v2 for v1 in bags[0] for v2 in bags[1]) merged_2_3 = Counter(v1 + v2 for v1...
output
1
98,583
10
197,167
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You have 4 bags A, B, C and D each of which includes N coins (there are totally 4N coins). Values of the coins in each bag are ai, bi, ci and di respectively. Find the number of combinations th...
instruction
0
98,584
10
197,168
Yes
output
1
98,584
10
197,169
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You have 4 bags A, B, C and D each of which includes N coins (there are totally 4N coins). Values of the coins in each bag are ai, bi, ci and di respectively. Find the number of combinations th...
instruction
0
98,585
10
197,170
Yes
output
1
98,585
10
197,171
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You have 4 bags A, B, C and D each of which includes N coins (there are totally 4N coins). Values of the coins in each bag are ai, bi, ci and di respectively. Find the number of combinations th...
instruction
0
98,586
10
197,172
Yes
output
1
98,586
10
197,173
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You have 4 bags A, B, C and D each of which includes N coins (there are totally 4N coins). Values of the coins in each bag are ai, bi, ci and di respectively. Find the number of combinations th...
instruction
0
98,587
10
197,174
Yes
output
1
98,587
10
197,175
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You have 4 bags A, B, C and D each of which includes N coins (there are totally 4N coins). Values of the coins in each bag are ai, bi, ci and di respectively. Find the number of combinations th...
instruction
0
98,588
10
197,176
No
output
1
98,588
10
197,177
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You have 4 bags A, B, C and D each of which includes N coins (there are totally 4N coins). Values of the coins in each bag are ai, bi, ci and di respectively. Find the number of combinations th...
instruction
0
98,589
10
197,178
No
output
1
98,589
10
197,179
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You have 4 bags A, B, C and D each of which includes N coins (there are totally 4N coins). Values of the coins in each bag are ai, bi, ci and di respectively. Find the number of combinations th...
instruction
0
98,590
10
197,180
No
output
1
98,590
10
197,181
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You have 4 bags A, B, C and D each of which includes N coins (there are totally 4N coins). Values of the coins in each bag are ai, bi, ci and di respectively. Find the number of combinations th...
instruction
0
98,591
10
197,182
No
output
1
98,591
10
197,183
Provide a correct Python 3 solution for this coding contest problem. We have N gemstones labeled 1 through N. You can perform the following operation any number of times (possibly zero). * Select a positive integer x, and smash all the gems labeled with multiples of x. Then, for each i, if the gem labeled i remai...
instruction
0
100,177
10
200,354
"Correct Solution: ``` from collections import deque N = int(input()) A = list(map(int,input().split())) P = N+2 es = [[] for i in range(P)] # [[to1,cap1,rev1], ...] def add_edge(fr,to,cap): es[fr].append([to,cap,len(es[to])]) es[to].append([fr,0,len(es[fr])-1]) INF = float('inf') score = 0 for i,a in enume...
output
1
100,177
10
200,355
Provide a correct Python 3 solution for this coding contest problem. We have N gemstones labeled 1 through N. You can perform the following operation any number of times (possibly zero). * Select a positive integer x, and smash all the gems labeled with multiples of x. Then, for each i, if the gem labeled i remai...
instruction
0
100,178
10
200,356
"Correct Solution: ``` def edmonds_karp(s, t, C): import copy import collections r = copy.deepcopy(c) maxf = 0 while True: q, found = collections.deque(), False q.append(([S], 10 ** 15)) while len(q) > 0 and not found: p, minf = q.popleft() for to, f...
output
1
100,178
10
200,357
Provide a correct Python 3 solution for this coding contest problem. We have N gemstones labeled 1 through N. You can perform the following operation any number of times (possibly zero). * Select a positive integer x, and smash all the gems labeled with multiples of x. Then, for each i, if the gem labeled i remai...
instruction
0
100,179
10
200,358
"Correct Solution: ``` from collections import deque class Dinic: def __init__(self, N): self.N = N self.G = [[] for i in range(N)] def add_edge(self, fr, to, cap): forward = [to, cap, None] forward[2] = backward = [fr, 0, forward] self.G[fr].append(forward) self...
output
1
100,179
10
200,359
Provide a correct Python 3 solution for this coding contest problem. We have N gemstones labeled 1 through N. You can perform the following operation any number of times (possibly zero). * Select a positive integer x, and smash all the gems labeled with multiples of x. Then, for each i, if the gem labeled i remai...
instruction
0
100,180
10
200,360
"Correct Solution: ``` from collections import defaultdict, deque, Counter from heapq import heappush, heappop, heapify import math import bisect import random from itertools import permutations, accumulate, combinations, product import sys import string from bisect import bisect_left, bisect_right from math import fac...
output
1
100,180
10
200,361
Provide a correct Python 3 solution for this coding contest problem. We have N gemstones labeled 1 through N. You can perform the following operation any number of times (possibly zero). * Select a positive integer x, and smash all the gems labeled with multiples of x. Then, for each i, if the gem labeled i remai...
instruction
0
100,181
10
200,362
"Correct Solution: ``` # グラフに辺を追加する def addEdge(adjL, vFr, vTo, cap): adjL[vFr].append([vTo, cap, len(adjL[vTo])]) adjL[vTo].append([vFr, 0, len(adjL[vFr]) - 1]) # 逆辺 # Ford-Fulkerson法(最大フローを求める) def Ford_Fulkerson(adjL, vSt, vEn): # 残余グラフの始点から終点までの経路(増加パス)を、DFSで探索する def DFS(vNow, vEn, fNow): ...
output
1
100,181
10
200,363
Provide a correct Python 3 solution for this coding contest problem. We have N gemstones labeled 1 through N. You can perform the following operation any number of times (possibly zero). * Select a positive integer x, and smash all the gems labeled with multiples of x. Then, for each i, if the gem labeled i remai...
instruction
0
100,182
10
200,364
"Correct Solution: ``` from collections import deque import sys sys.setrecursionlimit(200000) n = int(input()) houseki = list(map(int,input().split())) g = [[] for i in range(n+2)] INF = float("inf") MAX = 0 for i in range(n): if houseki[i] <= 0: g[0].append([i+1,-houseki[i],len(g[i+1])]) g[i+1].append([0,0,l...
output
1
100,182
10
200,365
Provide a correct Python 3 solution for this coding contest problem. We have N gemstones labeled 1 through N. You can perform the following operation any number of times (possibly zero). * Select a positive integer x, and smash all the gems labeled with multiples of x. Then, for each i, if the gem labeled i remai...
instruction
0
100,183
10
200,366
"Correct Solution: ``` """ https://atcoder.jp/contests/arc085/tasks/arc085_c """ from collections import defaultdict from collections import deque def Ford_Fulkerson_Func(s,g,lines,cost): N = len(cost) ans = 0 queue = deque([ [s,float("inf")] ]) ed = [True] * N ed[s] = False route = [0] ...
output
1
100,183
10
200,367
Provide a correct Python 3 solution for this coding contest problem. We have N gemstones labeled 1 through N. You can perform the following operation any number of times (possibly zero). * Select a positive integer x, and smash all the gems labeled with multiples of x. Then, for each i, if the gem labeled i remai...
instruction
0
100,184
10
200,368
"Correct Solution: ``` import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,copy,functools import time,random sys.setrecursionlimit(10**7) inf = 10**20 eps = 1.0 / 10**10 mod = 10**9+7 mod2 = 998244353 dd = [(-1,0),(0,1),(1,0),(0,-1)] ddn = [(-1,0),(-1,1),(0,1),(1,1),(1,0),(1,-1),(0,-1),(-1,-1)...
output
1
100,184
10
200,369
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. We have N gemstones labeled 1 through N. You can perform the following operation any number of times (possibly zero). * Select a positive integer x, and smash all the gems labeled with multipl...
instruction
0
100,185
10
200,370
Yes
output
1
100,185
10
200,371
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. We have N gemstones labeled 1 through N. You can perform the following operation any number of times (possibly zero). * Select a positive integer x, and smash all the gems labeled with multipl...
instruction
0
100,186
10
200,372
Yes
output
1
100,186
10
200,373
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. We have N gemstones labeled 1 through N. You can perform the following operation any number of times (possibly zero). * Select a positive integer x, and smash all the gems labeled with multipl...
instruction
0
100,187
10
200,374
Yes
output
1
100,187
10
200,375
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. We have N gemstones labeled 1 through N. You can perform the following operation any number of times (possibly zero). * Select a positive integer x, and smash all the gems labeled with multipl...
instruction
0
100,188
10
200,376
Yes
output
1
100,188
10
200,377
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. We have N gemstones labeled 1 through N. You can perform the following operation any number of times (possibly zero). * Select a positive integer x, and smash all the gems labeled with multipl...
instruction
0
100,189
10
200,378
No
output
1
100,189
10
200,379
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. We have N gemstones labeled 1 through N. You can perform the following operation any number of times (possibly zero). * Select a positive integer x, and smash all the gems labeled with multipl...
instruction
0
100,190
10
200,380
No
output
1
100,190
10
200,381
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. We have N gemstones labeled 1 through N. You can perform the following operation any number of times (possibly zero). * Select a positive integer x, and smash all the gems labeled with multipl...
instruction
0
100,191
10
200,382
No
output
1
100,191
10
200,383
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. We have N gemstones labeled 1 through N. You can perform the following operation any number of times (possibly zero). * Select a positive integer x, and smash all the gems labeled with multipl...
instruction
0
100,192
10
200,384
No
output
1
100,192
10
200,385
Provide a correct Python 3 solution for this coding contest problem. Better things, cheaper. There is a fierce battle at the time sale held in some supermarkets today. "LL-do" here in Aizu is one such supermarket, and we are holding a slightly unusual time sale to compete with other chain stores. In a general time sal...
instruction
0
100,255
10
200,510
"Correct Solution: ``` from heapq import heappush, heappop from string import digits import sys readline = sys.stdin.readline write = sys.stdout.write dd = ((-1, 0), (0, -1), (1, 0), (0, 1)) INF = 10**9 while 1: X, Y = map(int, readline().split()) if X == Y == 0: break MP = [readline().split() for ...
output
1
100,255
10
200,511
Provide tags and a correct Python 3 solution for this coding contest problem. The only difference between easy and hard versions is constraints. Now elections are held in Berland and you want to win them. More precisely, you want everyone to vote for you. There are n voters, and two ways to convince each of them to ...
instruction
0
100,436
10
200,872
Tags: binary search, data structures, greedy Correct Solution: ``` import sys import heapq def solve(pr, mm): omm = [] n = len(mm) for i in range(n + 1): omm.append([]) for i in range(n): omm[mm[i]].append(pr[i]) heap = [] c = 0 t = n p = 0 for i in rang...
output
1
100,436
10
200,873
Provide tags and a correct Python 3 solution for this coding contest problem. The only difference between easy and hard versions is constraints. Now elections are held in Berland and you want to win them. More precisely, you want everyone to vote for you. There are n voters, and two ways to convince each of them to ...
instruction
0
100,437
10
200,874
Tags: binary search, data structures, greedy Correct Solution: ``` import sys import heapq as hq readline = sys.stdin.readline read = sys.stdin.read ns = lambda: readline().rstrip() ni = lambda: int(readline().rstrip()) nm = lambda: map(int, readline().split()) nl = lambda: list(map(int, readline().split())) prn = lam...
output
1
100,437
10
200,875
Provide tags and a correct Python 3 solution for this coding contest problem. The only difference between easy and hard versions is constraints. Now elections are held in Berland and you want to win them. More precisely, you want everyone to vote for you. There are n voters, and two ways to convince each of them to ...
instruction
0
100,438
10
200,876
Tags: binary search, data structures, greedy Correct Solution: ``` import sys from heapq import heappop, heappush reader = (line.rstrip() for line in sys.stdin) input = reader.__next__ t = int(input()) for _ in range(t): n = int(input()) mp = [] for i in range(n): mi, pi = map(int, input().split(...
output
1
100,438
10
200,877
Provide tags and a correct Python 3 solution for this coding contest problem. The only difference between easy and hard versions is constraints. Now elections are held in Berland and you want to win them. More precisely, you want everyone to vote for you. There are n voters, and two ways to convince each of them to ...
instruction
0
100,439
10
200,878
Tags: binary search, data structures, greedy Correct Solution: ``` import sys input = sys.stdin.readline import heapq from itertools import accumulate t=int(input()) for test in range(t): n=int(input()) M=[[] for i in range(n)] MCOUNT=[0]*(n) for i in range(n): m,p=map(int,input().split()) ...
output
1
100,439
10
200,879
Provide tags and a correct Python 3 solution for this coding contest problem. The only difference between easy and hard versions is constraints. Now elections are held in Berland and you want to win them. More precisely, you want everyone to vote for you. There are n voters, and two ways to convince each of them to ...
instruction
0
100,440
10
200,880
Tags: binary search, data structures, greedy Correct Solution: ``` import sys input = sys.stdin.readline import heapq as hq t = int(input()) for _ in range(t): n = int(input()) vt = [list(map(int,input().split())) for i in range(n)] vt.sort(reverse=True) q = [] hq.heapify(q) ans = 0 cnt = 0 for i in ran...
output
1
100,440
10
200,881
Provide tags and a correct Python 3 solution for this coding contest problem. The only difference between easy and hard versions is constraints. Now elections are held in Berland and you want to win them. More precisely, you want everyone to vote for you. There are n voters, and two ways to convince each of them to ...
instruction
0
100,441
10
200,882
Tags: binary search, data structures, greedy Correct Solution: ``` import heapq import sys input = sys.stdin.readline t = int(input()) for _ in range(t): n = int(input()) info = [list(map(int, input().split())) for i in range(n)] info = sorted(info) cnt = [0] * n for i in range(n): ind = i...
output
1
100,441
10
200,883
Provide tags and a correct Python 3 solution for this coding contest problem. The only difference between easy and hard versions is constraints. Now elections are held in Berland and you want to win them. More precisely, you want everyone to vote for you. There are n voters, and two ways to convince each of them to ...
instruction
0
100,442
10
200,884
Tags: binary search, data structures, greedy Correct Solution: ``` from sys import stdin, stdout import heapq class MyHeap(object): def __init__(self, initial=None, key=lambda x:x): self.key = key if initial: self._data = [(key(item), item) for item in initial] heapq.heapify(self...
output
1
100,442
10
200,885
Provide tags and a correct Python 3 solution for this coding contest problem. The only difference between easy and hard versions is constraints. Now elections are held in Berland and you want to win them. More precisely, you want everyone to vote for you. There are n voters, and two ways to convince each of them to ...
instruction
0
100,443
10
200,886
Tags: binary search, data structures, greedy Correct Solution: ``` import sys from array import array # noqa: F401 import typing as Tp # noqa: F401 def input(): return sys.stdin.buffer.readline().decode('utf-8') def main(): from collections import defaultdict from heapq import heappop, heappush t ...
output
1
100,443
10
200,887
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The only difference between easy and hard versions is constraints. Now elections are held in Berland and you want to win them. More precisely, you want everyone to vote for you. There are n vo...
instruction
0
100,444
10
200,888
Yes
output
1
100,444
10
200,889
Provide tags and a correct Python 3 solution for this coding contest problem. Right now she actually isn't. But she will be, if you don't solve this problem. You are given integers n, k, A and B. There is a number x, which is initially equal to n. You are allowed to perform two types of operations: 1. Subtract 1 ...
instruction
0
100,902
10
201,804
Tags: dp, greedy Correct Solution: ``` n = int(input()) k = int(input()) A = int(input()) B = int(input()) ans = 0 if k==1: print((n-1)*A) exit() while n>1: if n%k!=0: if n<k: ans += (n-1)*A n = 1 else: ans += (n-n//k*k)*A n = n//k*k else...
output
1
100,902
10
201,805
Provide tags and a correct Python 3 solution for this coding contest problem. Right now she actually isn't. But she will be, if you don't solve this problem. You are given integers n, k, A and B. There is a number x, which is initially equal to n. You are allowed to perform two types of operations: 1. Subtract 1 ...
instruction
0
100,903
10
201,806
Tags: dp, greedy Correct Solution: ``` n=int(input()) k=int(input()) a=int(input()) b=int(input()) x=n c=0 if k==1: c=a*(n-1) else: while x>=k: y=x%k c+=y*a x-=y c+=min(b,a*(x-x//k)) x=(x//k) c+=a*(x-1) print(c) ```
output
1
100,903
10
201,807
Provide tags and a correct Python 3 solution for this coding contest problem. Right now she actually isn't. But she will be, if you don't solve this problem. You are given integers n, k, A and B. There is a number x, which is initially equal to n. You are allowed to perform two types of operations: 1. Subtract 1 ...
instruction
0
100,904
10
201,808
Tags: dp, greedy Correct Solution: ``` n=int(input()) k=int(input()) a=int(input()) b=int(input()) s=0 while n!=1: if k==1: s=(n-1)*a break if n>=k: if n%k==0: if b<a*(n-(n//k)): n=n//k s+=b else: s+=a*(n-(n//k)) ...
output
1
100,904
10
201,809
Provide tags and a correct Python 3 solution for this coding contest problem. Right now she actually isn't. But she will be, if you don't solve this problem. You are given integers n, k, A and B. There is a number x, which is initially equal to n. You are allowed to perform two types of operations: 1. Subtract 1 ...
instruction
0
100,905
10
201,810
Tags: dp, greedy Correct Solution: ``` x = int(input()) k = int(input()) A = int(input()) B = int(input()) p = 0 while x>1: if k==1: print(A*(x-1)) exit() if x%k == 0: p += min(B,(x-x/k)*A) x =x/k else: if x-x%k==0: p+=(x%k-1)*A print(int(p)) exit() else: p+=(x%k)*A x-=x%k print(int...
output
1
100,905
10
201,811
Provide tags and a correct Python 3 solution for this coding contest problem. Right now she actually isn't. But she will be, if you don't solve this problem. You are given integers n, k, A and B. There is a number x, which is initially equal to n. You are allowed to perform two types of operations: 1. Subtract 1 ...
instruction
0
100,906
10
201,812
Tags: dp, greedy Correct Solution: ``` n = int(input()) k = int(input()) A = int(input()) B = int(input()) res = 0 while n>k: if n % k >0: res += (n%k) * A n -= (n%k) dif = n - (n//k) if dif*A > B: res += B n = n//k else: res += (n-1)*A n = 1 if n == k...
output
1
100,906
10
201,813
Provide tags and a correct Python 3 solution for this coding contest problem. Right now she actually isn't. But she will be, if you don't solve this problem. You are given integers n, k, A and B. There is a number x, which is initially equal to n. You are allowed to perform two types of operations: 1. Subtract 1 ...
instruction
0
100,907
10
201,814
Tags: dp, greedy Correct Solution: ``` n, k, A, B = tuple(map(int, (input(), input(), input(), input()))) ans = 0 while(n != 1 and k != 1): if(n % k == 0): ans += min(B, (n - (n // k)) * A) n //= k elif(n > k): ans += (n % k) * A n -= n % k else: ans += (n-1) * A n -= (n-1) if(k == 1): ans = (n - 1)...
output
1
100,907
10
201,815
Provide tags and a correct Python 3 solution for this coding contest problem. Right now she actually isn't. But she will be, if you don't solve this problem. You are given integers n, k, A and B. There is a number x, which is initially equal to n. You are allowed to perform two types of operations: 1. Subtract 1 ...
instruction
0
100,908
10
201,816
Tags: dp, greedy Correct Solution: ``` n,k,a,b=(int(input()) for i in range(4)) x,s=n,0 if k<=1: print((x-1)*a) quit() while x!=1: if k>x: s,x=s+(x-1)*a,1 elif x%k!=0: s,x=s+(x%k)*a,x-x%k elif x*(k-1)//k*a>b: s,x=s+b,x//k else: s,x=s+x*(k-1)//k*a,x//k print(s) ``...
output
1
100,908
10
201,817