message stringlengths 2 23.8k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 97 109k | cluster float64 0 0 | __index_level_0__ int64 194 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing zeros and ones.
Once he thought about a string of length n consisting of zeroes an... | instruction | 0 | 3,768 | 0 | 7,536 |
Yes | output | 1 | 3,768 | 0 | 7,537 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing zeros and ones.
Once he thought about a string of length n consisting of zeroes an... | instruction | 0 | 3,769 | 0 | 7,538 |
Yes | output | 1 | 3,769 | 0 | 7,539 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing zeros and ones.
Once he thought about a string of length n consisting of zeroes an... | instruction | 0 | 3,770 | 0 | 7,540 |
Yes | output | 1 | 3,770 | 0 | 7,541 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing zeros and ones.
Once he thought about a string of length n consisting of zeroes an... | instruction | 0 | 3,771 | 0 | 7,542 |
No | output | 1 | 3,771 | 0 | 7,543 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing zeros and ones.
Once he thought about a string of length n consisting of zeroes an... | instruction | 0 | 3,772 | 0 | 7,544 |
No | output | 1 | 3,772 | 0 | 7,545 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing zeros and ones.
Once he thought about a string of length n consisting of zeroes an... | instruction | 0 | 3,773 | 0 | 7,546 |
No | output | 1 | 3,773 | 0 | 7,547 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing zeros and ones.
Once he thought about a string of length n consisting of zeroes an... | instruction | 0 | 3,774 | 0 | 7,548 |
No | output | 1 | 3,774 | 0 | 7,549 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is the length of the string.
You are given a string s and a string t, both consisting only of lowercase Latin letters. It is guaranteed that t can be obtained from s by removing some (possi... | instruction | 0 | 4,239 | 0 | 8,478 |
Tags: binary search, greedy, implementation, two pointers
Correct Solution:
```
from sys import stdin
from sys import setrecursionlimit as SRL; SRL(10**7)
rd = stdin.readline
rrd = lambda: map(int, rd().strip().split())
s = str(rd().strip())
t = str(rd().strip())
s = '0' + s
canl = [0] * (len(s) + 10)
canr = [0] * (... | output | 1 | 4,239 | 0 | 8,479 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is the length of the string.
You are given a string s and a string t, both consisting only of lowercase Latin letters. It is guaranteed that t can be obtained from s by removing some (possi... | instruction | 0 | 4,240 | 0 | 8,480 |
Tags: binary search, greedy, implementation, two pointers
Correct Solution:
```
s = input()
t = input()
n = len(s)
m = len(t)
dp1 = [0] * (n + 1)
for i in range(n):
dp1[i + 1] = dp1[i]
if (dp1[i] < m and s[i] == t[dp1[i]]):
dp1[i + 1] += 1
dp2 = [0] * (n + 1)
for i in range(n - 1, -1, -1):
dp2[i] = dp2[i + 1]... | output | 1 | 4,240 | 0 | 8,481 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is the length of the string.
You are given a string s and a string t, both consisting only of lowercase Latin letters. It is guaranteed that t can be obtained from s by removing some (possi... | instruction | 0 | 4,241 | 0 | 8,482 |
Tags: binary search, greedy, implementation, two pointers
Correct Solution:
```
def naiveSolve(n):
return
def main():
# s --> t
s = '$' + input() + '$'
t = '$' + input() + '$'
n = len(t)
left = [-1] * n
right = [-1] * n
m = len(s)
j = 0
for i in ... | output | 1 | 4,241 | 0 | 8,483 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is the length of the string.
You are given a string s and a string t, both consisting only of lowercase Latin letters. It is guaranteed that t can be obtained from s by removing some (possi... | instruction | 0 | 4,242 | 0 | 8,484 |
Tags: binary search, greedy, implementation, two pointers
Correct Solution:
```
s = input()
t = input()
pos = [[-1, -1] for i in range(len(t))]
ptr = 0
for i,c in enumerate(t):
while s[ptr] != c:
ptr += 1
pos[i][0] = ptr
ptr += 1
ptr = len(s) - 1
for i in range(len(t)-1, -1, -1):
c = t[i]
... | output | 1 | 4,242 | 0 | 8,485 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is the length of the string.
You are given a string s and a string t, both consisting only of lowercase Latin letters. It is guaranteed that t can be obtained from s by removing some (possi... | instruction | 0 | 4,243 | 0 | 8,486 |
Tags: binary search, greedy, implementation, two pointers
Correct Solution:
```
def f(n):
for i in range(-1,lt):
if right[i+1]-left[i]>n:
return True
return False
s=input()
t=input()
ls=len(s)
lt=len(t)
right=dict()
left=dict()
i=0
j=0
ls=len(s)
left[-1]=-1
while i<lt:
if s[j]==t[i]:
... | output | 1 | 4,243 | 0 | 8,487 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is the length of the string.
You are given a string s and a string t, both consisting only of lowercase Latin letters. It is guaranteed that t can be obtained from s by removing some (possi... | instruction | 0 | 4,244 | 0 | 8,488 |
Tags: binary search, greedy, implementation, two pointers
Correct Solution:
```
s=input()
t=input()
s_pos=[len(s) for i in range(len(t))]
i,j=len(s)-1,len(t)-1
while i>-1 and j>-1:
if s[i]==t[j]:
s_pos[j]=i
j-=1
i-=1
p,q=0,0
ans=0
while p<len(s):
if q==len(t):
ans=max(ans,len(s)-p)
break
remove=s_pos[q]... | output | 1 | 4,244 | 0 | 8,489 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is the length of the string.
You are given a string s and a string t, both consisting only of lowercase Latin letters. It is guaranteed that t can be obtained from s by removing some (possi... | instruction | 0 | 4,245 | 0 | 8,490 |
Tags: binary search, greedy, implementation, two pointers
Correct Solution:
```
import os
import sys
from io import BytesIO, IOBase
import heapq
def main():
s = input()
t = input()
n, m = len(s), len(t)
i, j = 0, 0
first = []
last = []
while j < m:
if s[i] == t[j]:
firs... | output | 1 | 4,245 | 0 | 8,491 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is the length of the string.
You are given a string s and a string t, both consisting only of lowercase Latin letters. It is guaranteed that t can be obtained from s by removing some (possi... | instruction | 0 | 4,246 | 0 | 8,492 |
Tags: binary search, greedy, implementation, two pointers
Correct Solution:
```
# Author : nitish420 --------------------------------------------------------------------
import os
import sys
from io import BytesIO, IOBase
def main():
s=list(input())
t=list(input())
n=len(s)
m=len(t)
pre=[]
post=[]
r=0
for i in... | output | 1 | 4,246 | 0 | 8,493 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is the length of the string.
You are given a string s and a string t, both consisting only of lowercase Latin letters. It is guaranteed that t... | instruction | 0 | 4,247 | 0 | 8,494 |
Yes | output | 1 | 4,247 | 0 | 8,495 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is the length of the string.
You are given a string s and a string t, both consisting only of lowercase Latin letters. It is guaranteed that t... | instruction | 0 | 4,248 | 0 | 8,496 |
Yes | output | 1 | 4,248 | 0 | 8,497 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is the length of the string.
You are given a string s and a string t, both consisting only of lowercase Latin letters. It is guaranteed that t... | instruction | 0 | 4,249 | 0 | 8,498 |
Yes | output | 1 | 4,249 | 0 | 8,499 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is the length of the string.
You are given a string s and a string t, both consisting only of lowercase Latin letters. It is guaranteed that t... | instruction | 0 | 4,250 | 0 | 8,500 |
Yes | output | 1 | 4,250 | 0 | 8,501 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is the length of the string.
You are given a string s and a string t, both consisting only of lowercase Latin letters. It is guaranteed that t... | instruction | 0 | 4,251 | 0 | 8,502 |
No | output | 1 | 4,251 | 0 | 8,503 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is the length of the string.
You are given a string s and a string t, both consisting only of lowercase Latin letters. It is guaranteed that t... | instruction | 0 | 4,252 | 0 | 8,504 |
No | output | 1 | 4,252 | 0 | 8,505 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is the length of the string.
You are given a string s and a string t, both consisting only of lowercase Latin letters. It is guaranteed that t... | instruction | 0 | 4,253 | 0 | 8,506 |
No | output | 1 | 4,253 | 0 | 8,507 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is the length of the string.
You are given a string s and a string t, both consisting only of lowercase Latin letters. It is guaranteed that t... | instruction | 0 | 4,254 | 0 | 8,508 |
No | output | 1 | 4,254 | 0 | 8,509 |
Provide a correct Python 3 solution for this coding contest problem.
C: Only one subsequence --Unique Subsequence-
problem
One day Ebi-chan noticed that a text string T of length n and a pattern string P (m \ leq n) of length m were placed on the desk. Ebi-chan loves the "only one subsequence" that appears in string... | instruction | 0 | 4,990 | 0 | 9,980 |
"Correct Solution:
```
t=input()
p=input()
mae=[0]*len(p)
cnt=0
for i in range(len(t)):
if t[i]==p[cnt]:
mae[cnt]=i
cnt+=1
if cnt==len(p):
break
if cnt!=len(p):print("no");exit()
cnt-=1
for j in range(len(t)-1,-1,-1):
if t[j]==p[cnt]:
if mae[cnt]!=j:print("no");exit()... | output | 1 | 4,990 | 0 | 9,981 |
Provide a correct Python 3 solution for this coding contest problem.
C: Only one subsequence --Unique Subsequence-
problem
One day Ebi-chan noticed that a text string T of length n and a pattern string P (m \ leq n) of length m were placed on the desk. Ebi-chan loves the "only one subsequence" that appears in string... | instruction | 0 | 4,991 | 0 | 9,982 |
"Correct Solution:
```
t = input()
p = input()
ok = 1
result1 = [0] * len(p); idx = 0
for i, c in enumerate(t):
if idx < len(p) and c == p[idx]:
result1[idx] = i
idx += 1
if idx < len(p):
ok = 0
result2 = [0] * len(p); idx = len(p)-1
for i in range(len(t)-1, -1, -1):
c = t[i]
if idx >= ... | output | 1 | 4,991 | 0 | 9,983 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings s and t, both consisting only of lowercase Latin letters.
The substring s[l..r] is the string which is obtained by taking characters s_l, s_{l + 1}, ..., s_r without changing the order.
Each of the occurrences of ... | instruction | 0 | 5,013 | 0 | 10,026 |
Tags: brute force, implementation
Correct Solution:
```
n, m, q = map(int, input().split())
s = input()
t = input()
flag = [0]*(1007)
prefix = [0]*(1007)
for i in range(n-m+1):
f = 1
for j in range(m):
if s[i+j] != t[j]:
f = 0
flag[i]= f
prefix[i+1]= prefix[i]+flag[i]
for i in range... | output | 1 | 5,013 | 0 | 10,027 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings s and t, both consisting only of lowercase Latin letters.
The substring s[l..r] is the string which is obtained by taking characters s_l, s_{l + 1}, ..., s_r without changing the order.
Each of the occurrences of ... | instruction | 0 | 5,014 | 0 | 10,028 |
Tags: brute force, implementation
Correct Solution:
```
string = ""
array = []
n, m, q = map(int, input().split())
s = input()
t = input()
for i in range(0, n - m + 1) :
if s[ i : i + m] == t :
string += '1'
else :
string += '0'
for i in range(0, q) :
a, b = map(int, input().split... | output | 1 | 5,014 | 0 | 10,029 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings s and t, both consisting only of lowercase Latin letters.
The substring s[l..r] is the string which is obtained by taking characters s_l, s_{l + 1}, ..., s_r without changing the order.
Each of the occurrences of ... | instruction | 0 | 5,015 | 0 | 10,030 |
Tags: brute force, implementation
Correct Solution:
```
n, m, q = [int(i) for i in input().split()]
s = input()
t = input()
positions = ''
for i in range(n-m+1):
if s[i:i + m] == t:
positions += '1'
else:
positions += '0'
for i in range(q):
l,r = map(int, input().split())
if r - l + 1 >=... | output | 1 | 5,015 | 0 | 10,031 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings s and t, both consisting only of lowercase Latin letters.
The substring s[l..r] is the string which is obtained by taking characters s_l, s_{l + 1}, ..., s_r without changing the order.
Each of the occurrences of ... | instruction | 0 | 5,016 | 0 | 10,032 |
Tags: brute force, implementation
Correct Solution:
```
n,m,q = map(int,input().split())
s = input()
t = input()
l = []
r = []
for i in range(n-m+1):
if s[i:i+m] == t:
l.append(i)
r.append(i+m-1)
for i in range(q):
x,y = map(int,input().split())
x-=1
y-=1
ans = 0
for j in range(l... | output | 1 | 5,016 | 0 | 10,033 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings s and t, both consisting only of lowercase Latin letters.
The substring s[l..r] is the string which is obtained by taking characters s_l, s_{l + 1}, ..., s_r without changing the order.
Each of the occurrences of ... | instruction | 0 | 5,017 | 0 | 10,034 |
Tags: brute force, implementation
Correct Solution:
```
def read():
return int(input())
def readlist():
return list(map(int, input().split()))
def readmap():
return map(int, input().split())
n, m, q = readmap()
S = input()
T = input()
L = []
R = []
for _ in range(q):
l, r = readmap()
L.append(... | output | 1 | 5,017 | 0 | 10,035 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings s and t, both consisting only of lowercase Latin letters.
The substring s[l..r] is the string which is obtained by taking characters s_l, s_{l + 1}, ..., s_r without changing the order.
Each of the occurrences of ... | instruction | 0 | 5,018 | 0 | 10,036 |
Tags: brute force, implementation
Correct Solution:
```
n,m,q = map(int, input().split())
s = input()
t =input()
res=""
if n>=m:
for i in range(n):
if (s[i:i+m]==t):
res+="1"
else:
res+="0"
for i in range(q):
c0,c1 = map(int, input().split())
if (m>n) or (c1-c0+1<m):
... | output | 1 | 5,018 | 0 | 10,037 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings s and t, both consisting only of lowercase Latin letters.
The substring s[l..r] is the string which is obtained by taking characters s_l, s_{l + 1}, ..., s_r without changing the order.
Each of the occurrences of ... | instruction | 0 | 5,019 | 0 | 10,038 |
Tags: brute force, implementation
Correct Solution:
```
n,m,q=map(int,input().split())
s,t=input(),input()
a=[0,0]
b=0
for i in range(n):
b+=s[i:i+m]==t
a+=[b]
for _ in[0]*q:
l,r=map(int,input().split())
print(a[max(l,r-m+2)]-a[l])
``` | output | 1 | 5,019 | 0 | 10,039 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings s and t, both consisting only of lowercase Latin letters.
The substring s[l..r] is the string which is obtained by taking characters s_l, s_{l + 1}, ..., s_r without changing the order.
Each of the occurrences of ... | instruction | 0 | 5,020 | 0 | 10,040 |
Tags: brute force, implementation
Correct Solution:
```
n, m, q = map(int, input().split())
s = input()
t = input()
a = [0] * n
for i in range(n - m + 1):
if s[i:i + m] == t:
a[i] = 1
for i in range(q):
k = 0
l, r = map(int, input().split())
for j in range(l - 1, r):
if a[j] == 1 and j +... | output | 1 | 5,020 | 0 | 10,041 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two strings s and t, both consisting only of lowercase Latin letters.
The substring s[l..r] is the string which is obtained by taking characters s_l, s_{l + 1}, ..., s_r without c... | instruction | 0 | 5,021 | 0 | 10,042 |
Yes | output | 1 | 5,021 | 0 | 10,043 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two strings s and t, both consisting only of lowercase Latin letters.
The substring s[l..r] is the string which is obtained by taking characters s_l, s_{l + 1}, ..., s_r without c... | instruction | 0 | 5,022 | 0 | 10,044 |
Yes | output | 1 | 5,022 | 0 | 10,045 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two strings s and t, both consisting only of lowercase Latin letters.
The substring s[l..r] is the string which is obtained by taking characters s_l, s_{l + 1}, ..., s_r without c... | instruction | 0 | 5,023 | 0 | 10,046 |
Yes | output | 1 | 5,023 | 0 | 10,047 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two strings s and t, both consisting only of lowercase Latin letters.
The substring s[l..r] is the string which is obtained by taking characters s_l, s_{l + 1}, ..., s_r without c... | instruction | 0 | 5,024 | 0 | 10,048 |
Yes | output | 1 | 5,024 | 0 | 10,049 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two strings s and t, both consisting only of lowercase Latin letters.
The substring s[l..r] is the string which is obtained by taking characters s_l, s_{l + 1}, ..., s_r without c... | instruction | 0 | 5,025 | 0 | 10,050 |
No | output | 1 | 5,025 | 0 | 10,051 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two strings s and t, both consisting only of lowercase Latin letters.
The substring s[l..r] is the string which is obtained by taking characters s_l, s_{l + 1}, ..., s_r without c... | instruction | 0 | 5,026 | 0 | 10,052 |
No | output | 1 | 5,026 | 0 | 10,053 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two strings s and t, both consisting only of lowercase Latin letters.
The substring s[l..r] is the string which is obtained by taking characters s_l, s_{l + 1}, ..., s_r without c... | instruction | 0 | 5,027 | 0 | 10,054 |
No | output | 1 | 5,027 | 0 | 10,055 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two strings s and t, both consisting only of lowercase Latin letters.
The substring s[l..r] is the string which is obtained by taking characters s_l, s_{l + 1}, ..., s_r without c... | instruction | 0 | 5,028 | 0 | 10,056 |
No | output | 1 | 5,028 | 0 | 10,057 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings s and t consisting of small Latin letters, string s can also contain '?' characters.
Suitability of string s is calculated by following metric:
Any two letters can be swapped positions, these operations can be pe... | instruction | 0 | 5,539 | 0 | 11,078 |
Tags: binary search, greedy, implementation
Correct Solution:
```
def check(mid,ha,has,c):
need=0
for i in range(26):
need+=max(0,ha[i]*mid-has[i])
# print(mid,need)
return c>=need
ss='abcdefghijklmnopqrstuvwxyz'
s = list(input())
t = list(input())
ha=[0]*26
has=[0]*26
m=10000000000
c=0
f... | output | 1 | 5,539 | 0 | 11,079 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings s and t consisting of small Latin letters, string s can also contain '?' characters.
Suitability of string s is calculated by following metric:
Any two letters can be swapped positions, these operations can be pe... | instruction | 0 | 5,540 | 0 | 11,080 |
Tags: binary search, greedy, implementation
Correct Solution:
```
from collections import Counter
A = input()
AC = Counter(A)
B = input()
BC = Counter(B)
letters = [chr(ord('a') + i) for i in range(ord('z') - ord('a') + 1)]
result = 0
a, b, c = 0, len(A) + 1, 0
#for k in range(len(A) - len(B) + 1):
# needed = ... | output | 1 | 5,540 | 0 | 11,081 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings s and t consisting of small Latin letters, string s can also contain '?' characters.
Suitability of string s is calculated by following metric:
Any two letters can be swapped positions, these operations can be pe... | instruction | 0 | 5,541 | 0 | 11,082 |
Tags: binary search, greedy, implementation
Correct Solution:
```
def main():
s = input()
t = input()
nd = {}
hv = {}
for x in t:
if x not in nd:
nd[x]=1
else:
nd[x]+=1
for x in s:
if x not in hv:
hv[x]=1
else:
hv[x]... | output | 1 | 5,541 | 0 | 11,083 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings s and t consisting of small Latin letters, string s can also contain '?' characters.
Suitability of string s is calculated by following metric:
Any two letters can be swapped positions, these operations can be pe... | instruction | 0 | 5,542 | 0 | 11,084 |
Tags: binary search, greedy, implementation
Correct Solution:
```
def solve(mid):
tmp = 0
for i in cnt_t:
if cnt_t[i] * mid <= cnt_s[i]:
pass
else:
tmp += cnt_t[i] * mid - cnt_s[i]
return tmp <= cnt_s["?"]
def solve2(mid):
tmp = deque([])
for i in cnt_t:
... | output | 1 | 5,542 | 0 | 11,085 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings s and t consisting of small Latin letters, string s can also contain '?' characters.
Suitability of string s is calculated by following metric:
Any two letters can be swapped positions, these operations can be pe... | instruction | 0 | 5,543 | 0 | 11,086 |
Tags: binary search, greedy, implementation
Correct Solution:
```
s = input()
t = input()
abc = 'abcdefghijklmnopqrstuvwxyz'
dabc ={}
for i in range(26):
dabc[abc[i]] = i
lt = {}
ls = {}
dd = {}
ls['?'] = 0
for i in abc:
lt[i] = 0
ls[i] = 0
dd[i] = 0
for letter in t:
lt[letter] += 1
for letter in s:
ls[letter] +... | output | 1 | 5,543 | 0 | 11,087 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings s and t consisting of small Latin letters, string s can also contain '?' characters.
Suitability of string s is calculated by following metric:
Any two letters can be swapped positions, these operations can be pe... | instruction | 0 | 5,544 | 0 | 11,088 |
Tags: binary search, greedy, implementation
Correct Solution:
```
s = list(input())
t = input()
abc = 'abcdefghijklmnopqrstuvwxyz'
dabc ={}
for i in range(26):
dabc[abc[i]] = i
lt = {}
ls = {}
dd = {}
ls['?'] = 0
for i in abc:
lt[i] = 0
ls[i] = 0
dd[i] = 0
for letter in t:
lt[letter] += 1
for letter in s:
ls[let... | output | 1 | 5,544 | 0 | 11,089 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings s and t consisting of small Latin letters, string s can also contain '?' characters.
Suitability of string s is calculated by following metric:
Any two letters can be swapped positions, these operations can be pe... | instruction | 0 | 5,545 | 0 | 11,090 |
Tags: binary search, greedy, implementation
Correct Solution:
```
from collections import Counter
import sys
input = sys.stdin.readline
s = list(input().rstrip())
t = input().rstrip()
cnt1 = Counter(s)
cnt2 = Counter(t)
if cnt1['?'] == 0:
print(*s, sep='')
exit()
ok, ng = 0, 10**9
while abs(ok - ng) > 1:
... | output | 1 | 5,545 | 0 | 11,091 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings s and t consisting of small Latin letters, string s can also contain '?' characters.
Suitability of string s is calculated by following metric:
Any two letters can be swapped positions, these operations can be pe... | instruction | 0 | 5,546 | 0 | 11,092 |
Tags: binary search, greedy, implementation
Correct Solution:
```
# @oj: codeforces
# @id: hitwanyang
# @email: 296866643@qq.com
# @date: 2020-11-18 19:10
# @url:https://codeforc.es/contest/825/problem/D
import sys,os
from io import BytesIO, IOBase
import collections,itertools,bisect,heapq,math,string
from decimal impo... | output | 1 | 5,546 | 0 | 11,093 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two strings s and t consisting of small Latin letters, string s can also contain '?' characters.
Suitability of string s is calculated by following metric:
Any two letters can b... | instruction | 0 | 5,547 | 0 | 11,094 |
Yes | output | 1 | 5,547 | 0 | 11,095 |
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