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RELATIVE OSCILLATION THEORY FOR JACOBI MATRICES EXTENDED

KERSTIN AMMANN

ABSTRACT. We present a comprehensive treatment of relative oscillation theory for finite Jacobi matrices. We show that the difference of the number of eigenvalues of two Jacobi matrices in an interval equals the number of weighted sign-changes of the Wronskian of suitable solutions of the two underlying difference equations. Until now only the case of perturbations of the main diagonal was known. We extend the known results to arbitrary perturbations, allow any (half-)open and closed spectral intervals, simplify the proof, and establish the comparison theorem.

1. INTRODUCTION

Jacobi operators appear at numerous occasions in mathematics as well as in physical models. For example, they are intimately related to the theory of orthogonal polynomials or constitute as a simple one-band tight binding model in quantum mechanics. They can be viewed as the discrete analog of Sturm–Liouville operators and their investigation has many similarities with Sturm–Liouville theory. Moreover, spectral and inverse spectral theory for Jacobi operators plays a fundamental role in the investigation of the Toda lattice and its modified counterpart, the Kac–van Moerbeke lattice. For further information we refer, e.g., to [16]. Let $a, b \in \ell(\mathbb{Z}) = {\varphi \mid \varphi : \mathbb{Z} \rightarrow \mathbb{R}}$ , where $a(n) < 0$ holds for all $n \in \mathbb{Z}$ . Then, the Jacobi matrix

J=(b(1)a(1)000a(1)b(2)000000b(N2)a(N2)000a(N2)b(N1))(1.1)J = \begin{pmatrix} b(1) & a(1) & 0 & 0 & 0 \\ a(1) & b(2) & \ddots & 0 & 0 \\ 0 & & \ddots & & 0 \\ 0 & 0 & \ddots & b(N-2) & a(N-2) \\ 0 & 0 & 0 & a(N-2) & b(N-1) \end{pmatrix} \quad (1.1)

is self-adjoint and $\sigma(J)$ is real and simple. The corresponding Jacobi difference equation

τu=zu,(1.2)\tau u = zu, \quad (1.2)

where

τ:(Z)(Z)u(n)(τu)(n)=a(n)u(n+1)+a(n1)u(n1)+b(n)u(n)=(a(n1)u(n1))+(b(n)+a(n)+a(n1))u(n),\begin{aligned} \tau : \ell(\mathbb{Z}) &\rightarrow \ell(\mathbb{Z}) \\ u(n) &\mapsto (\tau u)(n) = a(n)u(n+1) + a(n-1)u(n-1) + b(n)u(n) \\ &= \partial(a(n-1)\partial u(n-1)) + (b(n) + a(n) + a(n-1))u(n), \end{aligned}


2000 Mathematics Subject Classification. Primary 39A21, 47B36; Secondary 34C10, 34L05.

Key words and phrases. Jacobi matrices, oscillation theory, Wronskian.

Research supported by the Austrian Science Fund (FWF) under Grant No. Y330.$z \in \mathbb{R}$ , and $\partial u(n) = u(n+1) - u(n)$ is the usual forward difference operator, is the discrete analog of the Sturm-Liouville differential equation.

We call $u(z)$ a solution of (1.2) if $(\tau - z)u(z) = 0$ and $u(z) \not\equiv 0$ . Whenever the spectral parameter is evident from the context we abbreviate $u = u(z)$ . To any two initial values $u(n_0), u(n_0+1), n_0 \in \mathbb{Z}$ , there exists a unique 'solution' $u$ of (1.2) which vanishes if and only if $(u(n_0), u(n_0+1)) = (0, 0)$ . We exclude this case and thus, a solution of (1.2) cannot have two consecutive zeros. We call $n$ a node of $u$ if

u(n)=0ora(n)u(n)u(n+1)>0(1.3)u(n) = 0 \quad \text{or} \quad a(n)u(n)u(n+1) > 0 \quad (1.3)

and say that a node $n$ of $u$ lies between $m$ and $l$ if either $m < n < l$ or if $n = m$ and $u(m) \neq 0$ . The number of nodes of $u$ between $m$ and $l$ is denoted as $#_{(m,l)}(u)$ . From classical oscillation theory originating in the seminal work of Sturm from 1836 [15] we know that the $n$ -th eigenfunction of a Sturm-Liouville operator has $n-1$ nodes. This also holds for eigensequences of Jacobi operators, cf. e.g. [6], [12], or [18]. Our aim now is to show that the number of nodes of the Wronskian determinant of two (suitable) solutions $u_j(\lambda_j)$ of $(\tau_j - \lambda_j)u_j = 0$ , $j = 0, 1$ , equals the difference of the number of eigenvalues of $J_0$ and $J_1$ in $(\lambda_0, \lambda_1)$ .

In [2] (cf. also [1]) Teschl and myself considered the special case $a_0 = a_1$ which is now generalized to arbitrary perturbations. We still assume $a_0, a_1 < 0$ . This is no restriction since altering the sign of one or more elements of $a$ does not affect the spectrum of the corresponding matrices, their similarity can easily be shown. Nevertheless, the signs of the solutions of the underlying difference equations depend on the signs of $a$ and therefore we assume $a < 0$ to simplify (1.5).

The Wronskian is given by $W(u_0, u_1) \in \ell(\mathbb{Z})$ , where

Wn(u0,u1)=u0(n)a1(n)u1(n+1)u1(n)a0(n)u0(n+1).(1.4)W_n(u_0, u_1) = u_0(n)a_1(n)u_1(n+1) - u_1(n)a_0(n)u_0(n+1). \quad (1.4)

We set

#n(u0,u1)={1if Wn+1(u0,u1)u0(n+1)u1(n+1)>0 andeither Wn(u0,u1)Wn+1(u0,u1)<0or Wn(u0,u1)=0 and Wn+1(u0,u1)01if Wn(u0,u1)u0(n+1)u1(n+1)>0 andeither Wn(u0,u1)Wn+1(u0,u1)<0or Wn(u0,u1)0 and Wn+1(u0,u1)=00otherwise(1.5)\#_n(u_0, u_1) = \begin{cases} 1 & \text{if } W_{n+1}(u_0, u_1)u_0(n+1)u_1(n+1) > 0 \text{ and} \\ & \text{either } W_n(u_0, u_1)W_{n+1}(u_0, u_1) < 0 \\ & \text{or } W_n(u_0, u_1) = 0 \text{ and } W_{n+1}(u_0, u_1) \neq 0 \\ -1 & \text{if } W_n(u_0, u_1)u_0(n+1)u_1(n+1) > 0 \text{ and} \\ & \text{either } W_n(u_0, u_1)W_{n+1}(u_0, u_1) < 0 \\ & \text{or } W_n(u_0, u_1) \neq 0 \text{ and } W_{n+1}(u_0, u_1) = 0 \\ 0 & \text{otherwise} \end{cases} \quad (1.5)

and say the Wronskian has a (weighted) node at $n$ if $#_n(u_0, u_1) \neq 0$ . We denote the number of weighted nodes of the Wronskian between $m$ and $n$ , $m < n$ , by

#[m,n](u0,u1)=j=mn1#j(u0,u1)(1.6)\#_{[m,n]}(u_0, u_1) = \sum_{j=m}^{n-1} \#_j(u_0, u_1) \quad (1.6)

and set

#(m,n](u0,u1)=#[m,n](u0,u1){1if Wm(u0,u1)=00otherwise,#[m,n)(u0,u1)=#[m,n](u0,u1)+{1if Wn(u0,u1)=00otherwise,(1.7)\begin{aligned} \#_{(m,n]}(u_0, u_1) &= \#_{[m,n]}(u_0, u_1) - \begin{cases} 1 & \text{if } W_m(u_0, u_1) = 0 \\ 0 & \text{otherwise,} \end{cases} \\ \#_{[m,n)}(u_0, u_1) &= \#_{[m,n]}(u_0, u_1) + \begin{cases} 1 & \text{if } W_n(u_0, u_1) = 0 \\ 0 & \text{otherwise,} \end{cases} \end{aligned} \quad (1.7)and

#(m,n)(u0,u1)=#[m,n](u0,u1){1if Wm(u0,u1)=00otherwise+{1if Wn(u0,u1)=00otherwise.(1.8)\begin{aligned} & \#_{(m,n)}(u_0, u_1) \\ &= \#_{[m,n]}(u_0, u_1) - \begin{cases} 1 & \text{if } W_m(u_0, u_1) = 0 \\ 0 & \text{otherwise} \end{cases} + \begin{cases} 1 & \text{if } W_n(u_0, u_1) = 0 \\ 0 & \text{otherwise.} \end{cases} \end{aligned} \quad (1.8)

Here we slightly changed the notation compared to [2]: $#{(m,n)}$ from [2] is now denoted as $#{[m,n]}$ .

We find the following

Theorem 1.1 (Relative Oscillation Theorem). Let $a_0, a_1 < 0$ , then,

E(,λ1)(J1)E(,λ0)(J0)=#(0,N](u0,+(λ0),u1,(λ1))=#(0,N](u0,(λ0),u1,+(λ1))(1.9)\begin{aligned} & E_{(-\infty, \lambda_1)}(J_1) - E_{(-\infty, \lambda_0)}(J_0) \\ &= \#_{(0,N]}(u_{0,+}(\lambda_0), u_{1,-}(\lambda_1)) = \#_{(0,N]}(u_{0,-}(\lambda_0), u_{1,+}(\lambda_1)) \end{aligned} \quad (1.9)

and

E(,λ1)(J1)E(,λ0)(J0)=#[0,N](u0,+(λ0),u1,(λ1))=#(0,N](u0,(λ0),u1,+(λ1)),E(,λ1](J1)E(,λ0](J0)=#(0,N)(u0,+(λ0),u1,(λ1))=#[0,N](u0,(λ0),u1,+(λ1)),(1.10)\begin{aligned} & E_{(-\infty, \lambda_1)}(J_1) - E_{(-\infty, \lambda_0)}(J_0) \\ &= \#_{[0,N]}(u_{0,+}(\lambda_0), u_{1,-}(\lambda_1)) = \#_{(0,N]}(u_{0,-}(\lambda_0), u_{1,+}(\lambda_1)), \\ & E_{(-\infty, \lambda_1]}(J_1) - E_{(-\infty, \lambda_0]}(J_0) \\ &= \#_{(0,N)}(u_{0,+}(\lambda_0), u_{1,-}(\lambda_1)) = \#_{[0,N]}(u_{0,-}(\lambda_0), u_{1,+}(\lambda_1)), \end{aligned} \quad (1.10)

E(,λ1](J1)E(,λ0)(J0)=#[0,N](u0,+(λ0),u1,(λ1))=#[0,N](u0,(λ0),u1,+(λ1)),\begin{aligned} & E_{(-\infty, \lambda_1]}(J_1) - E_{(-\infty, \lambda_0)}(J_0) \\ &= \#_{[0,N]}(u_{0,+}(\lambda_0), u_{1,-}(\lambda_1)) = \#_{[0,N]}(u_{0,-}(\lambda_0), u_{1,+}(\lambda_1)), \end{aligned}

where $E_\Omega(J)$ is the number of eigenvalues of $J$ in $\Omega \subseteq \mathbb{R}$ and $u_{-/+}$ are solutions fulfilling the left/right Dirichlet boundary condition of $J$ , i.e. $u_-(0) = u_+(N) = 0$ .

Equation (1.9) generalizes Theorem 1.2 from [2] to different $a$ 's. Analogous results for Sturm–Liouville operators were first given by Krüger and Teschl [9, 10]. For the case of Dirac operators see Stadler and Teschl in [14]. For extensions to symplectic eigenvalue problems see Elyseeva [3–5].

In the sequel (Sections 2–4) we prove Theorem 1.1 using the discrete Prüfer transformation. Compared to [2, 9, 10, 14] we also present a simplified proof which eliminates the need to interpolate between operators. This is of particular importance in the present case, since $a_0 < a_1$ does not imply the corresponding relation for the operators, which would make the interpolation step more difficult. In addition, (1.10) is new. The proofs for regular Sturm–Liouville operators [9, Theorem 2.3] and regular Dirac operators [14, Theorem 3.3] can be shortened in the same manner and both theorems can be extended to (half-)open and closed spectral intervals analogously to (1.10) (for the first case cf. also [17]).

An extension of Sturm's classical comparison theorem for nodes of solutions to nodes of Wronskians has first been established for Sturm–Liouville operators by Krüger and Teschl in [9, 10]. In Section 5 we show that an analogous comparison theorem holds for Wronskians of solutions of Jacobi difference equations in the case $a_0 = a_1$ , therefore confer also [1]. Moreover, we give Sturm-type comparison theorems for arbitrary perturbations of Jacobi matrices, where, unlike the case of Sturm–Liouville operators, we do not obtain a direct dependence on the coefficients of the operators because $a_0 \leq a_1$ doesn't imply $J_0 \leq J_1$ .

An extension of Theorem 1.1 to Jacobi operators on the half line and on the line is in preparation. This will fill the gap that classical oscillation theory is only applicable below the essential spectrum, while relative oscillation theory works perfectly insidegaps of the essential spectrum. We hope that this will stimulate further research, e.g. to find new relative oscillation criteria as in the Sturm–Liouville–case, [7, 8]. We’d be remiss not to mention that several other extensions of relative oscillation theory are thinkable, e.g. to CMV matrices. Only recently, Šimon Hilscher pointed out in [13] that an extension to the case of Jacobi difference equations with a nonlinear dependence on the spectral parameter would be of particular interest.

2. THE WRONSKIAN

Definition 2.1. We define the (modified) Wronskian (also referred to as Wronski determinant or Casorati determinant) by

W:D2×(Z)2(Z)(τ0,τ1,φ,ψ)Wτ0,τ1(φ,ψ),(2.1)\begin{aligned} W : \mathbb{D}^2 \times \ell(\mathbb{Z})^2 &\rightarrow \ell(\mathbb{Z}) \\ (\tau_0, \tau_1, \varphi, \psi) &\mapsto W^{\tau_0, \tau_1}(\varphi, \psi), \end{aligned} \quad (2.1)

where $\mathbb{D}$ denotes the space of difference equations, such that

Wnτ0,τ1(φ,ψ)=φ(n)a1(n)ψ(n+1)ψ(n)a0(n)φ(n+1)=φ(n)ψ(n)a0(n)φ(n+1)a1(n)ψ(n+1).(2.2)\begin{aligned} W_n^{\tau_0, \tau_1}(\varphi, \psi) &= \varphi(n)a_1(n)\psi(n+1) - \psi(n)a_0(n)\varphi(n+1) \\ &= \begin{vmatrix} \varphi(n) & \psi(n) \\ a_0(n)\varphi(n+1) & a_1(n)\psi(n+1) \end{vmatrix}. \end{aligned} \quad (2.2)

We abbreviate $\Delta b := b_0 - b_1$ , $\Delta a := a_0 - a_1$ , and $W_n(\varphi, \psi) = W_n^{\tau_0, \tau_1}(\varphi, \psi)$ whenever the corresponding difference equations are evident from the context. Clearly, if $a_0 = a_1$ holds, then $W$ equals the Wronskian from [2]. We have

Wτ0,τ0(φ,φ)0,Wτ0,τ1(φ,ψ)=Wτ1,τ0(ψ,φ),Wτ0,τ1(cφ,ψ)=Wτ0,τ1(φ,cψ)=cWτ0,τ1(φ,ψ),Wτ0,τ1(φ+φ~,ψ)=Wτ0,τ1(φ,ψ)+Wτ0,τ1(φ~,ψ),Wτ0,τ1(φ,ψ+ψ~)=Wτ0,τ1(φ,ψ)+Wτ0,τ1(φ,ψ~)(2.3)\begin{aligned} W^{\tau_0, \tau_0}(\varphi, \varphi) &\equiv 0, \\ W^{\tau_0, \tau_1}(\varphi, \psi) &= -W^{\tau_1, \tau_0}(\psi, \varphi), \\ W^{\tau_0, \tau_1}(c\varphi, \psi) &= W^{\tau_0, \tau_1}(\varphi, c\psi) = c W^{\tau_0, \tau_1}(\varphi, \psi), \\ W^{\tau_0, \tau_1}(\varphi + \tilde{\varphi}, \psi) &= W^{\tau_0, \tau_1}(\varphi, \psi) + W^{\tau_0, \tau_1}(\tilde{\varphi}, \psi), \\ W^{\tau_0, \tau_1}(\varphi, \psi + \tilde{\psi}) &= W^{\tau_0, \tau_1}(\varphi, \psi) + W^{\tau_0, \tau_1}(\varphi, \tilde{\psi}) \end{aligned} \quad (2.3)

for all $c \in \mathbb{R}$ and $\varphi, \tilde{\varphi}, \psi, \tilde{\psi} \in \ell(\mathbb{Z})$ .

Lemma 2.2. Green’s Formula. We find

j=nm(φ(τ1ψ)ψ(τ0φ))(j)=Wm(φ,ψ)Wn1(φ,ψ)j=n1m1Δa(j)(φ(j+1)ψ(j)+φ(j)ψ(j+1))j=nmΔb(j)φ(j)ψ(j).(2.4)\begin{aligned} \sum_{j=n}^m (\varphi(\tau_1\psi) - \psi(\tau_0\varphi))(j) &= W_m(\varphi, \psi) - W_{n-1}(\varphi, \psi) \\ &\quad - \sum_{j=n-1}^{m-1} \Delta a(j)(\varphi(j+1)\psi(j) + \varphi(j)\psi(j+1)) - \sum_{j=n}^m \Delta b(j)\varphi(j)\psi(j). \end{aligned} \quad (2.4)

Proof. Just a short calculation. $\square$

Corollary 2.3. Let $(\tau_j - z)u_j = 0$ , then

Wm(u0,u1)Wn1(u0,u1)(2.5)W_m(u_0, u_1) - W_{n-1}(u_0, u_1) \quad (2.5)

=j=n1m1Δa(j)(u0(j+1)u1(j)+u0(j)u1(j+1))+j=nmΔb(j)u0(j)u1(j),Wn(u0,u1)Wn1(u0,u1)=Δa(n1)(u0(n)u1(n1)+u0(n1)u1(n))+Δb(n)u0(n)u1(n).(2.6)\begin{aligned} &= \sum_{j=n-1}^{m-1} \Delta a(j)(u_0(j+1)u_1(j) + u_0(j)u_1(j+1)) + \sum_{j=n}^m \Delta b(j)u_0(j)u_1(j), \\ W_n(u_0, u_1) - W_{n-1}(u_0, u_1) &= \Delta a(n-1)(u_0(n)u_1(n-1) + u_0(n-1)u_1(n)) + \Delta b(n)u_0(n)u_1(n). \end{aligned} \quad (2.6)

If $u$ and $\tilde{u}$ solve $\tau u = zu$ , then $W(u, \tilde{u})$ is constant (and vanishes iff $u$ and $\tilde{u}$ are linearly dependent).3. PRÜFER TRANSFORMATION

From now on let $u$ be a solution of (1.2) and let $u_{-/+}$ moreover fulfill the left/right Dirichlet boundary condition of $J$ .

Lemma 3.1. [16]. The Jacobi matrix $J$ has $N - 1$ real and simple eigenvalues. Moreover,

zσ(J)    u(z,N)=0    u+(z,0)=0.(3.1)z \in \sigma(J) \iff u_-(z, N) = 0 \iff u_+(z, 0) = 0. \quad (3.1)

Proof. Since $J$ is Hermitian all eigenvalues are real: let $z \in \sigma(J)$ , $Jv = zv$ and $|v| = 1$ . Then $z = \langle v, zv \rangle = \langle v, Jv \rangle = \langle Jv, v \rangle = \overline{z}$ . It can easily be seen that every eigenvector $u$ corresponding to $z$ fulfills $\tau u = zu$ and $u(0) = 0$ . Hence, by $W_0(u_-(z), u) = 0$ , $u_-(z)$ and $u$ are linearly dependent. $\square$

Theorem 3.2. [18], [16, Theorem 4.7]. For all $\lambda \in \mathbb{R}$

E(,λ)(J)=#(0,N)(u(λ))=#(0,N)(u+(λ))(3.2)E_{(-\infty, \lambda)}(J) = \#_{(0, N)}(u_-(\lambda)) = \#_{(0, N)}(u_+(\lambda)) \quad (3.2)

holds.

Lemma 3.3. If $u(n) = 0$ , then $u(n - 1)u(n + 1) < 0$ .

Proof. Since (1.2) is a three-term-recursion and $u \not\equiv 0$ , all zeros of $u$ are simple and

u(n+1)=a(n)1>0(a(n1))<0u(n1)+(b(n)z)u(n)=00(3.3)u(n + 1) = \underbrace{-a(n)^{-1}}_{>0} \underbrace{(a(n - 1))}_{<0} u(n - 1) + \underbrace{(b(n) - z)u(n)}_{=0} \neq 0 \quad (3.3)

holds. $\square$

By $(u(n), u(n + 1)) \neq (0, 0)$ for all $n \in \mathbb{Z}$ we can introduce Prüfer variables: let $\rho_u, \theta_u \in \ell(\mathbb{Z})$ denote sequences so that

u(n)=ρu(n)sinθu(n),a(n)u(n+1)=ρu(n)cosθu(n),(3.4)\begin{aligned} u(n) &= \rho_u(n) \sin \theta_u(n), \\ -a(n)u(n + 1) &= \rho_u(n) \cos \theta_u(n), \end{aligned} \quad (3.4)

and $\rho_u(n) > 0$ holds for all $n \in \mathbb{Z}$ . Choose $\theta_u(n_0) \in (-\pi, \pi]$ at the initial position $n_0$ and assume

θu(n)/πθu(n+1)/πθu(n)/π+1(3.5)\lceil \theta_u(n)/\pi \rceil \leq \lceil \theta_u(n + 1)/\pi \rceil \leq \lceil \theta_u(n)/\pi \rceil + 1 \quad (3.5)

for all $n \in \mathbb{Z}$ , then both sequences are well-defined and unique. Here, $x \mapsto \lceil x \rceil = \min{n \in \mathbb{Z} \mid n \geq x}$ denotes the ceiling function, a left-continuous analog to the well-known floor function $x \mapsto \lfloor x \rfloor = \max{n \in \mathbb{Z} \mid n \leq x}$ which itself is a right-continuous step function.

We follow [9] and use the slightly refined (compared to [2, 16, 18]) definition of Prüfer variables by taking the secondary diagonals $a$ into account. By $-a > 0$ this will not influence the herein recalled claims on the nodes of solutions, but it simplifies our calculations as soon as we look at the nodes of the Wronskian.

Lemma 3.4. Fix some $n \in \mathbb{Z}$ , then $\exists k \in \mathbb{Z}$ s.t. $\theta_u(n) = k\pi + \gamma$ and $\theta_u(n + 1) = k\pi + \Gamma$ , where

γ(0,π2],Γ(0,π]    n is not a node of u,γ(π2,π],Γ(π,2π)    n is a node of u(3.6)\begin{aligned} \gamma \in (0, \frac{\pi}{2}], \quad \Gamma \in (0, \pi] &\iff n \text{ is not a node of } u, \\ \gamma \in (\frac{\pi}{2}, \pi], \quad \Gamma \in (\pi, 2\pi) &\iff n \text{ is a node of } u \end{aligned} \quad (3.6)

holds. Moreover,

θu(n)=kπ+π2    θu(n+1)=(k+1)π.(3.7)\theta_u(n) = k\pi + \frac{\pi}{2} \iff \theta_u(n + 1) = (k + 1)\pi. \quad (3.7)Proof. Abbreviate $\theta = \theta_u$ . Choose $k \in \mathbb{Z}$ such that $\theta(n) = k\pi + \gamma$ , $\gamma \in (0, \pi]$ holds. By (3.5) we have $\Gamma \in (0, 2\pi]$ . If $u(n)u(n+1) \neq 0$ , then $\sin \gamma \cos \gamma > 0$ iff $n$ is not a node of $u$ and $\sin \gamma \cos \gamma < 0$ iff $n$ is a node of $u$ , hence (3.6) clearly holds for $\gamma$ . By $\sin \Gamma \cos \gamma > 0$ we have $\sin \Gamma > 0$ iff $n$ is not a node of $u$ and $\sin \Gamma < 0$ iff $n$ is a node of $u$ , thus, (3.6) also holds for $\Gamma$ .

Now, suppose we have $u(n+1) = 0$ , then $n$ is not a node of $u$ and either $\Gamma = \pi$ or $\Gamma = 2\pi$ holds. By Lemma 3.3 we have $u(n)u(n+2) < 0$ , hence $\sin \theta(n) \cos \theta(n+1) = (-1)^k \sin \gamma (-1)^k \cos \Gamma < 0$ . Thus, by $\cos \Gamma < 0$ , we have $\Gamma = \pi$ . From $-a(n)u(n+1) = \rho(n) \cos \theta(n) = 0$ we conclude that $(-1)^k \cos \gamma = 0$ , thus $\gamma = \frac{\pi}{2}$ and hence (3.6) and (3.7) hold. If $u(n) = 0$ , then $n$ is a node of $u$ , $\gamma = \pi$ , and (3.6) holds by $\sin \theta(n+1) \cos \theta(n) > 0$ , i.e. $(-1)^k \sin \Gamma (-1)^k \cos \gamma > 0$ . $\square$

Corollary 3.5. For all $n \in \mathbb{Z}$ we have

θu(n+1)/π={θu(n)/π+1if n is a node of uθu(n)/πotherwise.(3.8)\lceil \theta_u(n+1)/\pi \rceil = \begin{cases} \lceil \theta_u(n)/\pi \rceil + 1 & \text{if } n \text{ is a node of } u \\ \lceil \theta_u(n)/\pi \rceil & \text{otherwise.} \end{cases} \quad (3.8)

Now we are able to count nodes of solutions of the Jacobi difference equation using Prüfer variables and the number of nodes in an interval $(m, n)$ is given by

Theorem 3.6. [18, Lemma 2.5]. We have

#(m,n)(u)=θu(n)/πθu(m)/π1.(3.9)\#_{(m,n)}(u) = \lceil \theta_u(n)/\pi \rceil - \lfloor \theta_u(m)/\pi \rfloor - 1. \quad (3.9)

Proof. We use mathematical induction: let $n = m+1$ , then if $u(m) = 0$ , $u(n) \neq 0$ we have $#_{(m,n)}(u) = 0$ and by Corollary 3.5

θu(n)/π=θu(m+1)/π=θu(m)/πZ+1=θu(m)/π+1(3.10)\lceil \theta_u(n)/\pi \rceil = \lceil \theta_u(m+1)/\pi \rceil = \underbrace{\lceil \theta_u(m)/\pi \rceil}_{\in \mathbb{Z}} + 1 = \lfloor \theta_u(m)/\pi \rfloor + 1 \quad (3.10)

holds. If $u(m) \neq 0$ holds, then by Corollary 3.5 we have

θu(m)/πZ=θu(m)/π1={θu(n)/π2if m is a nodeθu(n)/π1otherwise.(3.11)\underbrace{\lfloor \theta_u(m)/\pi \rfloor}_{\notin \mathbb{Z}} = \lceil \theta_u(m)/\pi \rceil - 1 = \begin{cases} \lceil \theta_u(n)/\pi \rceil - 2 & \text{if } m \text{ is a node} \\ \lceil \theta_u(n)/\pi \rceil - 1 & \text{otherwise.} \end{cases} \quad (3.11)

The inductive step follows again from Corollary 3.5. $\square$

Let $s_{-/+}(z)$ denote the solution of $\tau s = zs$ fulfilling

s(z,0)=0,s(z,1)=1,resp. s+(z,N)=0,s+(z,N+1)=1(3.12)s_-(z, 0) = 0, s_-(z, 1) = 1, \quad \text{resp. } s_+(z, N) = 0, s_+(z, N+1) = 1 \quad (3.12)

and let $n_0$ denote the base point, i.e. $n_0 = 0$ , resp. $n_0 = N$ . Then, by $s_{\pm}(n_0) = 0$ we have $\sin \theta_{\pm}(n_0) = 0$ and by $s_{\pm}(n_0+1) = 1$ we have $-a(n_0)s_{\pm}(n_0+1) = \rho_s(n_0) \cos \theta_{\pm}(n_0) > 0$ , hence $\theta_{\pm}(n_0) = 0$ holds by $\theta_{\pm}(n_0) \in (-\pi, \pi]$ .

Corollary 3.7. We have

#(0,N)(s)=θs(N)/π1and#(0,N)(s+)=θs+(0)/π1.(3.13)\#_{(0,N)}(s_-) = \lceil \theta_{s_-}(N)/\pi \rceil - 1 \quad \text{and} \quad \#_{(0,N)}(s_+) = -\lfloor \theta_{s_+}(0)/\pi \rfloor - 1. \quad (3.13)Lemma 3.8. We find

E(,λ1)(J1)E(,λ0)(J0)=Δs0,+(λ0),s1,(λ1)(N)/πΔs0,+(λ0),s1,(λ1)(0)/π=Δs0,(λ0),s1,+(λ1)(N)/πΔs0,(λ0),s1,+(λ1)(0)/π,E(,λ1)(J1)E(,λ0)(J0)=Δs0,±(λ0),s1,(λ1)(N)/πΔs0,±(λ0),s1,(λ1)(0)/π1,E(,λ1](J1)E(,λ0)(J0)=Δs0,±(λ0),s1,(λ1)(N)/πΔs0,±(λ0),s1,(λ1)(0)/π+1, andE(,λ1](J1)E(,λ0](J0)=Δs0,(λ0),s1,+(λ1)(N)/πΔs0,(λ0),s1,+(λ1)(0)/π=Δs0,+(λ0),s1,(λ1)(N)/πΔs0,+(λ0),s1,(λ1)(0)/π,(3.14)\begin{aligned} & E_{(-\infty, \lambda_1)}(J_1) - E_{(-\infty, \lambda_0)}(J_0) \\ &= \lceil \Delta_{s_{0,+}(\lambda_0), s_{1,-}(\lambda_1)}(N)/\pi \rceil - \lceil \Delta_{s_{0,+}(\lambda_0), s_{1,-}(\lambda_1)}(0)/\pi \rceil \\ &= \lceil \Delta_{s_{0,-}(\lambda_0), s_{1,+}(\lambda_1)}(N)/\pi \rceil - \lceil \Delta_{s_{0,-}(\lambda_0), s_{1,+}(\lambda_1)}(0)/\pi \rceil, \\ & E_{(-\infty, \lambda_1)}(J_1) - E_{(-\infty, \lambda_0)}(J_0) \\ &= \lceil \Delta_{s_{0,\pm}(\lambda_0), s_{1,\mp}(\lambda_1)}(N)/\pi \rceil - \lceil \Delta_{s_{0,\pm}(\lambda_0), s_{1,\mp}(\lambda_1)}(0)/\pi \rceil - 1, \\ & E_{(-\infty, \lambda_1]}(J_1) - E_{(-\infty, \lambda_0)}(J_0) \\ &= \lceil \Delta_{s_{0,\pm}(\lambda_0), s_{1,\mp}(\lambda_1)}(N)/\pi \rceil - \lceil \Delta_{s_{0,\pm}(\lambda_0), s_{1,\mp}(\lambda_1)}(0)/\pi \rceil + 1, \text{ and} \\ & E_{(-\infty, \lambda_1]}(J_1) - E_{(-\infty, \lambda_0]}(J_0) \\ &= \lceil \Delta_{s_{0,-}(\lambda_0), s_{1,+}(\lambda_1)}(N)/\pi \rceil - \lceil \Delta_{s_{0,-}(\lambda_0), s_{1,+}(\lambda_1)}(0)/\pi \rceil \\ &= \lceil \Delta_{s_{0,+}(\lambda_0), s_{1,-}(\lambda_1)}(N)/\pi \rceil - \lceil \Delta_{s_{0,+}(\lambda_0), s_{1,-}(\lambda_1)}(0)/\pi \rceil, \end{aligned} \tag{3.14}

where $\Delta_{u,v} = \theta_v - \theta_u \in \ell(\mathbb{Z})$ .

Proof. Abbreviate $s_{j,\pm} = s_{j,\pm}(\lambda_j)$ . By Theorem 3.2, Corollary 3.7, and $-[x] = \lfloor -x \rfloor$ for all $x \in \mathbb{R}$ we have

E(,λ1)(J1)E(,λ0)(J0)=#(0,N)(s1,)#(0,N)(s0,+)=θs1,(N)/πθs0,+(0)/π=Δs0,+,s1,(N)/πΔs0,+,s1,(0)/π=(E(,λ0)(J0)E(,λ1)(J1))=Δs0,,s1,+(N)/πΔs0,,s1,+(0)/π.\begin{aligned} & E_{(-\infty, \lambda_1)}(J_1) - E_{(-\infty, \lambda_0)}(J_0) = \#_{(0,N)}(s_{1,-}) - \#_{(0,N)}(s_{0,+}) \\ &= \lceil \theta_{s_{1,-}}(N)/\pi \rceil - \lceil -\theta_{s_{0,+}}(0)/\pi \rceil = \lceil \Delta_{s_{0,+}, s_{1,-}}(N)/\pi \rceil - \lceil \Delta_{s_{0,+}, s_{1,-}}(0)/\pi \rceil \\ &= -(E_{(-\infty, \lambda_0)}(J_0) - E_{(-\infty, \lambda_1)}(J_1)) = \lceil \Delta_{s_{0,-}, s_{1,+}}(N)/\pi \rceil - \lceil \Delta_{s_{0,-}, s_{1,+}}(0)/\pi \rceil. \end{aligned}

By Lemma 3.1 and (3.4) we have

λ0σ(J0)    Δs0,,s1,+(N)/πZ    Δs0,+,s1,(0)/πZ,λ1σ(J1)    Δs0,+,s1,(N)/πZ    Δs0,,s1,+(0)/πZ\begin{aligned} \lambda_0 \in \sigma(J_0) &\iff \Delta_{s_{0,-}, s_{1,+}}(N)/\pi \in \mathbb{Z} &\iff \Delta_{s_{0,+}, s_{1,-}}(0)/\pi \in \mathbb{Z}, \\ \lambda_1 \in \sigma(J_1) &\iff \Delta_{s_{0,+}, s_{1,-}}(N)/\pi \in \mathbb{Z} &\iff \Delta_{s_{0,-}, s_{1,+}}(0)/\pi \in \mathbb{Z} \end{aligned}

and hence

E(,λ1)(J1)E(,λ0)(J0)=Δs0,±,s1,(N)/πΔs0,±,s1,(0)/π1(3.15)E_{(-\infty, \lambda_1)}(J_1) - E_{(-\infty, \lambda_0)}(J_0) = \lceil \Delta_{s_{0,\pm}, s_{1,\mp}}(N)/\pi \rceil - \lceil \Delta_{s_{0,\pm}, s_{1,\mp}}(0)/\pi \rceil - 1 \tag{3.15}

holds by

E(,λ1)(J1)E(,λ0)(J0)=Δs0,±,s1,(N)/πΔs0,±,s1,(0)/π{1if λ0σ(J0)0if λ0σ(J0).(3.16)\begin{aligned} & E_{(-\infty, \lambda_1)}(J_1) - E_{(-\infty, \lambda_0)}(J_0) \\ &= \lceil \Delta_{s_{0,\pm}, s_{1,\mp}}(N)/\pi \rceil - \lceil \Delta_{s_{0,\pm}, s_{1,\mp}}(0)/\pi \rceil - \begin{cases} 1 & \text{if } \lambda_0 \notin \sigma(J_0) \\ 0 & \text{if } \lambda_0 \in \sigma(J_0). \end{cases} \end{aligned} \tag{3.16}

The rest now follows analogously. $\square$

4. NODES OF THE WRONSKIAN

It remains to investigate the sign-changes of $W(u_0, u_1)$ . We will express them in terms of Prüfer angles of the involved solutions to finally gain their connection to the difference of the spectra of the corresponding matrices by Lemma 3.8.

Therefore let $u_j$ be solutions of $\tau_j - z$ , $j = 0, 1$ , where $\rho_j, \theta_j \in \ell(\mathbb{Z})$ are their Prüfer variables from (3.4). They correspond to the same spectral parameter $z$ , which is no restriction, since we can always replace $b_1$ by $b_1 - (z_1 - z_0)$ . We abbreviate

Δ:=Δu0,u1=θ1θ0(Z)(4.1)\Delta := \Delta_{u_0, u_1} = \theta_1 - \theta_0 \in \ell(\mathbb{Z}) \tag{4.1}

and adopt Lemma 4.1 and Lemma 4.2 from [2]:

Lemma 4.1. [2]. Fix some $n \in \mathbb{Z}$ , then $\exists k_j \in \mathbb{Z}, j = 0, 1$ , s.t.

θj(n)=kjπ+γj,γj(0,π],θj(n+1)=kjπ+Γj,Γj(0,2π),(4.2)\begin{aligned} \theta_j(n) &= k_j\pi + \gamma_j, & \gamma_j &\in (0, \pi], \\ \theta_j(n+1) &= k_j\pi + \Gamma_j, & \Gamma_j &\in (0, 2\pi), \end{aligned} \tag{4.2}

where(1): either $u_0$ and $u_1$ have a node at $n$ or both do not have a node at $n$ , then

γ1γ0(π2,π2)andΓ1Γ0(π,π).(4.3)\gamma_1 - \gamma_0 \in \left(-\frac{\pi}{2}, \frac{\pi}{2}\right) \quad \text{and} \quad \Gamma_1 - \Gamma_0 \in (-\pi, \pi). \quad (4.3)

(2): $u_1$ has no node at $n$ , but $u_0$ has a node at $n$ , then

γ1γ0(π,0)andΓ1Γ0(2π,0).(4.4)\gamma_1 - \gamma_0 \in (-\pi, 0) \quad \text{and} \quad \Gamma_1 - \Gamma_0 \in (-2\pi, 0). \quad (4.4)

(3): $u_1$ has a node at $n$ , but $u_0$ has no node at $n$ , then

γ1γ0(0,π)andΓ1Γ0(0,2π).(4.5)\gamma_1 - \gamma_0 \in (0, \pi) \quad \text{and} \quad \Gamma_1 - \Gamma_0 \in (0, 2\pi). \quad (4.5)

Proof. Use Lemma 3.4. $\square$

Lemma 4.2. [2]. We have

Δ(n)/π1Δ(n+1)/πΔ(n)/π+1.(4.6)\lceil \Delta(n)/\pi \rceil - 1 \leq \lceil \Delta(n+1)/\pi \rceil \leq \lceil \Delta(n)/\pi \rceil + 1. \quad (4.6)

Proof. Let $k := k_1 - k_0$ , $n \in \mathbb{Z}$ . By Lemma 4.1 we have either

Δ(n)(kππ2,kπ+π2)andΔ(n+1)(kππ,kπ+π),Δ(n)(kππ,kπ)andΔ(n+1)(kπ2π,kπ), orΔ(n)(kπ,kπ+π)andΔ(n+1)(kπ,kπ+2π).(4.7)\begin{aligned} \Delta(n) \in (k\pi - \frac{\pi}{2}, k\pi + \frac{\pi}{2}) \quad \text{and} \quad \Delta(n+1) \in (k\pi - \pi, k\pi + \pi), \\ \Delta(n) \in (k\pi - \pi, k\pi) \quad \text{and} \quad \Delta(n+1) \in (k\pi - 2\pi, k\pi), \text{ or} \\ \Delta(n) \in (k\pi, k\pi + \pi) \quad \text{and} \quad \Delta(n+1) \in (k\pi, k\pi + 2\pi). \end{aligned} \quad (4.7)

In each case the lemma holds. $\square$

Lemma 4.3. We have

Wn(u0,u1)=ρ0(n)ρ1(n)sinΔ(n),(4.8)W_n(u_0, u_1) = \rho_0(n)\rho_1(n) \sin \Delta(n), \quad (4.8)

Wn(u0,u1)u0(n+1)u1(n+1)=psin(γ1γ0)cosγ0cosγ1,(4.9)W_n(u_0, u_1)u_0(n+1)u_1(n+1) = p \sin(\gamma_1 - \gamma_0) \cos \gamma_0 \cos \gamma_1, \quad (4.9)

Wn+1(u0,u1)u0(n+1)u1(n+1)=p~sin(Γ1Γ0)cosγ0cosγ1,(4.10)W_{n+1}(u_0, u_1)u_0(n+1)u_1(n+1) = \tilde{p} \sin(\Gamma_1 - \Gamma_0) \cos \gamma_0 \cos \gamma_1, \quad (4.10)

where $p, \tilde{p} > 0$ .

Proof. Consider

Wn(u0,u1)=u0(n)a1(n)u1(n+1)u1(n)a0(n)u0(n+1)=ρ0(n)ρ1(n)sin(θ1(n)θ0(n))=ρ0(n)ρ1(n)(1)k1k0sin(γ1(n)γ0(n))(4.11)\begin{aligned} W_n(u_0, u_1) &= u_0(n)a_1(n)u_1(n+1) - u_1(n)a_0(n)u_0(n+1) \\ &= \rho_0(n)\rho_1(n) \sin(\theta_1(n) - \theta_0(n)) \\ &= \rho_0(n)\rho_1(n)(-1)^{k_1-k_0} \sin(\gamma_1(n) - \gamma_0(n)) \end{aligned} \quad (4.11)

and set $p = \frac{\rho_0(n)^2 \rho_1(n)^2}{a_0(n)a_1(n)}$ and $\tilde{p} = \frac{\rho_0(n)\rho_1(n)\rho_0(n+1)\rho_1(n+1)}{a_0(n)a_1(n)}$ . $\square$

Lemma 4.4. We have

u0(n+1)=u1(n+1)=0    Wn(u0,u1)=Wn+1(u0,u1)=0,u0(n+1)=0,u1(n+1)0    Wn(u0,u1)Wn+1(u0,u1)>0,u0(n+1)0,u1(n+1)=0    Wn(u0,u1)Wn+1(u0,u1)>0.(4.12)\begin{aligned} u_0(n+1) = u_1(n+1) = 0 &\implies W_n(u_0, u_1) = W_{n+1}(u_0, u_1) = 0, \\ u_0(n+1) = 0, u_1(n+1) \neq 0 &\implies W_n(u_0, u_1)W_{n+1}(u_0, u_1) > 0, \\ u_0(n+1) \neq 0, u_1(n+1) = 0 &\implies W_n(u_0, u_1)W_{n+1}(u_0, u_1) > 0. \end{aligned} \quad (4.12)

Proof. The first claim holds trivially. For the second claim just observe that by Lemma 3.3

Wn(u0,u1)Wn+1(u0,u1)=u0(n)u0(n+2)a0(n+1)a1(n)u1(n+1)2>0(4.13)W_n(u_0, u_1)W_{n+1}(u_0, u_1) = -u_0(n)u_0(n+2)a_0(n+1)a_1(n)u_1(n+1)^2 > 0 \quad (4.13)

holds if $u_0(n+1) = 0, u_1(n+1) \neq 0$ and

Wn(u0,u1)Wn+1(u0,u1)=u1(n)u1(n+2)a0(n)a1(n+1)u0(n+1)2>0(4.14)W_n(u_0, u_1)W_{n+1}(u_0, u_1) = -u_1(n)u_1(n+2)a_0(n)a_1(n+1)u_0(n+1)^2 > 0 \quad (4.14)

holds if $u_0(n+1) \neq 0, u_1(n+1) = 0$ . $\square$Corollary 4.5. If $W_n(u_0, u_1)W_{n+1}(u_0, u_1) < 0$ or $W_n(u_0, u_1) = 0, W_{n+1}(u_0, u_1) \neq 0$ or $W_n(u_0, u_1) \neq 0, W_{n+1}(u_0, u_1) = 0$ , then

u0(n+1)u1(n+1)0(4.15)u_0(n+1)u_1(n+1) \neq 0 \quad (4.15)

and moreover $\Delta a(n) \neq 0$ or $\Delta b(n+1) \neq 0$ holds.

To shorten notation we denote

(+1) if Δ(n+1)/π=Δ(n)/π+1,(0) if Δ(n+1)/π=Δ(n)/π, and(1) if Δ(n+1)/π=Δ(n)/π1.(4.16)\begin{aligned} (+1) & \text{ if } \lceil \Delta(n+1)/\pi \rceil = \lceil \Delta(n)/\pi \rceil + 1, \\ (0) & \text{ if } \lceil \Delta(n+1)/\pi \rceil = \lceil \Delta(n)/\pi \rceil, \text{ and} \\ (-1) & \text{ if } \lceil \Delta(n+1)/\pi \rceil = \lceil \Delta(n)/\pi \rceil - 1. \end{aligned} \quad (4.16)

Lemma 4.6. Let $n \in \mathbb{Z}$ , then

(+1)    Wn+1(u0,u1)u0(n+1)u1(n+1)>0 andeither Wn(u0,u1)Wn+1(u0,u1)<0or Wn(u0,u1)=0,Wn+1(u0,u1)0,(4.17)\begin{aligned} (+1) & \iff W_{n+1}(u_0, u_1)u_0(n+1)u_1(n+1) > 0 \text{ and} \\ & \text{either } W_n(u_0, u_1)W_{n+1}(u_0, u_1) < 0 \\ & \text{or } W_n(u_0, u_1) = 0, W_{n+1}(u_0, u_1) \neq 0, \end{aligned} \quad (4.17)

(1)    Wn(u0,u1)u0(n+1)u1(n+1)>0 andeither Wn(u0,u1)Wn+1(u0,u1)<0or Wn(u0,u1)0,Wn+1(u0,u1)=0,(4.18)\begin{aligned} (-1) & \iff W_n(u_0, u_1)u_0(n+1)u_1(n+1) > 0 \text{ and} \\ & \text{either } W_n(u_0, u_1)W_{n+1}(u_0, u_1) < 0 \\ & \text{or } W_n(u_0, u_1) \neq 0, W_{n+1}(u_0, u_1) = 0, \end{aligned} \quad (4.18)

(0)    otherwise.(4.19)(0) \iff \text{otherwise.} \quad (4.19)

Proof. If (+1), then we either have case (1) of Lemma 4.1 and $\gamma_1 - \gamma_0 \in (-\frac{\pi}{2}, 0]$ , $\Gamma_1 - \Gamma_0 \in (0, \pi)$ or we have case (3) of Lemma 4.1 and $\gamma_1 - \gamma_0 \in (0, \pi)$ , $\Gamma_1 - \Gamma_0 \in (\pi, 2\pi)$ . Clearly, by (4.8), in either case we have

Wn(u0,u1)Wn+1(u0,u1)<0orWn(u0,u1)=0,Wn+1(u0,u1)0.(4.20)W_n(u_0, u_1)W_{n+1}(u_0, u_1) < 0 \quad \text{or} \quad W_n(u_0, u_1) = 0, W_{n+1}(u_0, u_1) \neq 0. \quad (4.20)

Hence, by Corollary 4.5 we have $u_0(n+1)u_1(n+1) \neq 0$ and thus $\cos \gamma_0 \cos \gamma_1 \neq 0$ . In case (1) of Lemma 4.1 we have $\sin(\Gamma_1 - \Gamma_0) > 0$ and $\cos \gamma_0 \cos \gamma_1 > 0$ by Lemma 3.4. Hence, by (4.10) $W_{n+1}(u_0, u_1)u_0(n+1)u_1(n+1) > 0$ holds. In case (3) of Lemma 4.1 we have $\sin(\Gamma_1 - \Gamma_0) < 0$ and $\cos \gamma_0 \cos \gamma_1 < 0$ by Lemma 3.4. Hence, by (4.10)

Wn+1(u0,u1)u0(n+1)u1(n+1)>0(4.21)W_{n+1}(u_0, u_1)u_0(n+1)u_1(n+1) > 0 \quad (4.21)

holds.

If (-1), then we either have case (1) of Lemma 4.1 and $\gamma_1 - \gamma_0 \in (0, \frac{\pi}{2})$ , $\Gamma_1 - \Gamma_0 \in (-\pi, 0]$ or we have case (2) of Lemma 4.1 and $\gamma_1 - \gamma_0 \in (-\pi, 0)$ , $\Gamma_1 - \Gamma_0 \in (-2\pi, -\pi]$ . Clearly, by (4.8), in either case we have

Wn(u0,u1)Wn+1(u0,u1)<0orWn(u0,u1)0,Wn+1(u0,u1)=0.(4.22)W_n(u_0, u_1)W_{n+1}(u_0, u_1) < 0 \quad \text{or} \quad W_n(u_0, u_1) \neq 0, W_{n+1}(u_0, u_1) = 0. \quad (4.22)

Hence, by Corollary 4.5 we have $u_0(n+1)u_1(n+1) \neq 0$ and thus $\cos \gamma_0 \cos \gamma_1 \neq 0$ . In case (1) of Lemma 4.1 we have $\sin(\gamma_1 - \gamma_0) > 0$ and $\cos \gamma_0 \cos \gamma_1 > 0$ by Lemma 3.4. Hence, by (4.9) $W_n(u_0, u_1)u_0(n+1)u_1(n+1) > 0$ holds. In case (2) of Lemma 4.1 we have $\sin(\gamma_1 - \gamma_0) < 0$ and $\cos \gamma_0 \cos \gamma_1 < 0$ by Lemma 3.4. Hence, by (4.9)

Wn(u0,u1)u0(n+1)u1(n+1)>0(4.23)W_n(u_0, u_1)u_0(n+1)u_1(n+1) > 0 \quad (4.23)

holds.

On the other hand, if $W_n(u_0, u_1)W_{n+1}(u_0, u_1) < 0$ by (4.8) we have either (+1) or (-1). If, use (4.9),

Wn(u0,u1)u0(n+1)u1(n+1)=psin(γ1γ0)cosγ0cosγ1>0,(4.24)W_n(u_0, u_1)u_0(n+1)u_1(n+1) = p \sin(\gamma_1 - \gamma_0) \cos \gamma_0 \cos \gamma_1 > 0, \quad (4.24)then we have either case (1) or case (2) of Lemma 4.1 and in each case we have (0) or $(-1)$ . Hence,

Wn(u0,u1)Wn+1(u0,u1)<0 and Wn(u0,u1)u0(n+1)u1(n+1)>0    (1).W_n(u_0, u_1)W_{n+1}(u_0, u_1) < 0 \text{ and } W_n(u_0, u_1)u_0(n+1)u_1(n+1) > 0 \implies (-1).

If, use (4.9),

Wn(u0,u1)u0(n+1)u1(n+1)=psin(γ1γ0)cosγ0cosγ1<0,(4.25)W_n(u_0, u_1)u_0(n+1)u_1(n+1) = p \sin(\gamma_1 - \gamma_0) \cos \gamma_0 \cos \gamma_1 < 0, \quad (4.25)

then we have either case (1) or case (3) of Lemma 4.1 and in each case we have (0) or $(+1)$ . Hence,

Wn(u0,u1)Wn+1(u0,u1)<0 and Wn+1(u0,u1)u0(n+1)u1(n+1)>0    (+1).W_n(u_0, u_1)W_{n+1}(u_0, u_1) < 0 \text{ and } W_{n+1}(u_0, u_1)u_0(n+1)u_1(n+1) > 0 \implies (+1).

If $W_n(u_0, u_1) = 0$ , $W_{n+1}(u_0, u_1) \neq 0$ , then we have case (1) of Lemma 4.1 and by Corollary 4.5 we have $\cos \gamma_0 \cos \gamma_1 > 0$ . Hence, if $W_{n+1}(u_0, u_1)u_0(n+1)u_1(n+1) > 0$ , then (4.10) implies $\sin(\Gamma_1 - \Gamma_0) > 0$ , thus, $(+1)$ holds by case (1) of Lemma 4.1. If $W_n(u_0, u_1) \neq 0$ , $W_{n+1}(u_0, u_1) = 0$ , then by Corollary 4.5 we have $\cos \gamma_0 \cos \gamma_1 \neq 0$ . If additionally $W_n(u_0, u_1)u_0(n+1)u_1(n+1) > 0$ holds, then by (4.9) $\cos \gamma_0 \cos \gamma_1$ and $\sin(\gamma_1 - \gamma_0)$ are of the same sign. Hence, we have case (1) of Lemma 4.1 and $(-1)$ or case (2) of Lemma 4.1 and $(-1)$ .

Thus, (4.17) and (4.18) hold and clearly by Lemma 4.2 we have (0) otherwise. $\square$

Remark 4.7. Consider (1.5), then

Wn(u0,u1)Wn+1(u0,u1)0 or Wn(u0,u1)=Wn+1(u0,u1)=0    #n(u0,u1)=#n(u1,u0),Wn(u0,u1)Wn+1(u0,u1)<0    #n(u0,u1)0(4.26)\begin{aligned} W_n(u_0, u_1)W_{n+1}(u_0, u_1) &\neq 0 \text{ or } W_n(u_0, u_1) = W_{n+1}(u_0, u_1) = 0 \\ &\implies \#_n(u_0, u_1) = -\#_n(u_1, u_0), \\ W_n(u_0, u_1)W_{n+1}(u_0, u_1) &< 0 \implies \#_n(u_0, u_1) \neq 0 \end{aligned} \quad (4.26)

by Corollary 4.5. Moreover, if $W_n(u_0, u_1) = 0$ and $W_{n+1}(u_0, u_1) \neq 0$ holds, then $u_0(n) = 0 \iff u_1(n) = 0$ .

That (1.5) is a generalization of the counting method established in [2, (1.8)], where $\Delta a = 0$ holds, follows from (2.6). From Lemma 4.6 we conclude

#n(u0,u1)=Δ(n+1)/πΔ(n)/π,(4.27)\#_n(u_0, u_1) = \lceil \Delta(n+1)/\pi \rceil - \lceil \Delta(n)/\pi \rceil, \quad (4.27)

#[m,n](u0,u1)=Δ(n)/πΔ(m)/π.(4.28)\#_{[m,n]}(u_0, u_1) = \lceil \Delta(n)/\pi \rceil - \lceil \Delta(m)/\pi \rceil. \quad (4.28)

Lemma 4.8. We have

#(m,n](u0,u1)=Δ(n)/πΔ(m)/π1,(4.29)\#_{(m,n]}(u_0, u_1) = \lceil \Delta(n)/\pi \rceil - \lfloor \Delta(m)/\pi \rfloor - 1, \quad (4.29)

#[m,n)(u0,u1)=Δ(n)/πΔ(m)/π+1, and(4.30)\#_{[m,n)}(u_0, u_1) = \lfloor \Delta(n)/\pi \rfloor - \lceil \Delta(m)/\pi \rceil + 1, \text{ and} \quad (4.30)

#(m,n)(u0,u1)=Δ(n)/πΔ(m)/π.(4.31)\#_{(m,n)}(u_0, u_1) = \lfloor \Delta(n)/\pi \rfloor - \lfloor \Delta(m)/\pi \rfloor. \quad (4.31)

Proof. By (4.8) we have $W_j(u_0, u_1) = 0 \iff \Delta(j)/\pi \in \mathbb{Z}$ and hence by (4.28)

#(m,n](u0,u1)=Δ(n)/πΔ(m)/π{0if Wm(u0,u1)01if Wm(u0,u1)=0=Δ(n)/πΔ(m)/π1(4.32)\begin{aligned} \#_{(m,n]}(u_0, u_1) &= \lceil \Delta(n)/\pi \rceil - \lceil \Delta(m)/\pi \rceil - \begin{cases} 0 & \text{if } W_m(u_0, u_1) \neq 0 \\ 1 & \text{if } W_m(u_0, u_1) = 0 \end{cases} \\ &= \lceil \Delta(n)/\pi \rceil - \lfloor \Delta(m)/\pi \rfloor - 1 \end{aligned} \quad (4.32)

holds. The second and the third claim follow analogously. $\square$

Lemma 4.9. We have

#[m,n](u0,u1)=#(m,n)(u1,u0),#(m,n](u0,u1)=#[m,n)(u1,u0).(4.33)\#_{[m,n]}(u_0, u_1) = -\#_{(m,n)}(u_1, u_0), \quad \#_{(m,n]}(u_0, u_1) = -\#_{[m,n)}(u_1, u_0). \quad (4.33)

If $W_m(u_0, u_1) \neq 0$ and $W_n(u_0, u_1) \neq 0$ , then $#{[m,n]}(u_0, u_1) = -#{[m,n]}(u_1, u_0)$ .

Proof. Use $\lceil x \rceil = -\lfloor -x \rfloor$ and Lemma 4.8. $\square$Proof of Theorem 1.1. By Lemma 3.8 and Lemma 4.8 we have

E(,λ1)(J1)E(,λ0)(J0)=Δs0,±(λ0),s1,(λ1)(N)/πΔs0,±(λ0),s1,(λ1)(0)/π1=#(0,N](s0,±(λ0),s1,(λ1))=#(0,N](u0,±(λ0),u1,(λ1)).(4.34)\begin{aligned} E_{(-\infty, \lambda_1)}(J_1) - E_{(-\infty, \lambda_0)}(J_0) \\ = \lceil \Delta_{s_0, \pm(\lambda_0), s_{1, \mp}(\lambda_1)}(N)/\pi \rceil - \lfloor \Delta_{s_0, \pm(\lambda_0), s_{1, \mp}(\lambda_1)}(0)/\pi \rfloor - 1 \\ = \#_{(0, N]}(s_{0, \pm}(\lambda_0), s_{1, \mp}(\lambda_1)) = \#_{(0, N]}(u_{0, \pm}(\lambda_0), u_{1, \mp}(\lambda_1)). \end{aligned} \quad (4.34)

Equations (1.10) can be shown analogously. $\square$

Remark 4.10. By Theorem 1.1 we have

#[0,N](u0,±(λ),u1,(λ1))=#[0,N](u1,±(λ),u0,(λ)),(4.35)\#_{[0, N]}(u_{0, \pm}(\lambda), u_{1, \mp}(\lambda_1)) = -\#_{[0, N]}(u_{1, \pm}(\lambda), u_{0, \mp}(\lambda)), \quad (4.35)

#[0,N](u0,+(λ),u3,(λ))=#[0,N](u0,+(λ),u1,(λ))+#[0,N](u1,(λ),u2,+(λ))+#(0,N](u2,+(λ),u3,(λ)),\begin{aligned} \#_{[0, N]}(u_{0, +}(\lambda), u_{3, -}(\lambda)) \\ = \#_{[0, N]}(u_{0, +}(\lambda), u_{1, -}(\lambda)) + \#_{[0, N]}(u_{1, -}(\lambda), u_{2, +}(\lambda)) + \#_{(0, N]}(u_{2, +}(\lambda), u_{3, -}(\lambda)), \end{aligned}

and

#[0,N](u0,(λ),u3,+(λ))=#(0,N](u0,(λ),u1,+(λ))+#[0,N](u1,+(λ),u2,(λ))+#[0,N](u2,(λ),u3,+(λ)).\begin{aligned} \#_{[0, N]}(u_{0, -}(\lambda), u_{3, +}(\lambda)) \\ = \#_{(0, N]}(u_{0, -}(\lambda), u_{1, +}(\lambda)) + \#_{[0, N]}(u_{1, +}(\lambda), u_{2, -}(\lambda)) + \#_{[0, N]}(u_{2, -}(\lambda), u_{3, +}(\lambda)). \end{aligned}

5. TRIANGLE INEQUALITY AND COMPARISON THEOREM

In this section we establish the Triangle Inequality and the Comparison Theorem for Wronskians which generalize Theorem 5.12 and Theorem 5.13 from [1] to different $a$ 's. Moreover, Theorem 5.3 generalizes and sharpens Theorem 5.11 from [1].

Theorem 5.1 (Comparison Theorem for Wronskians I). Let $J_1 \geq J_2$ , then,

#[0,N](u0,±(λ),u2,(λ))#[0,N](u0,±(λ),u1,(λ)),(5.1)\#_{[0, N]}(u_{0, \pm}(\lambda), u_{2, \mp}(\lambda)) \geq \#_{[0, N]}(u_{0, \pm}(\lambda), u_{1, \mp}(\lambda)), \quad (5.1)

where $#{[0, N]}$ can be replaced by $#{(0, N]}$ , $#{[0, N]}$ , or $#{(0, N]}$ .

Proof. Let $\sigma(J_1) = {\lambda_1, \dots, \lambda_{N-1}}$ and $\sigma(J_2) = {\tilde{\lambda}1, \dots, \tilde{\lambda}{N-1}}$ , then $\lambda_i \geq \tilde{\lambda}i$ for all $i$ by $J_1 \geq J_2$ , cf. [11, Theorem 8.7.1], and hence we have $E{(-\infty, \lambda)}(J_2) \geq E_{(-\infty, \lambda)}(J_1)$ . Thus, by Theorem 1.1

#[0,N](u0,+(λ),u2,(λ))=E(,λ)(J2)E(,λ)(J0)E(,λ)(J1)E(,λ)(J0)=#[0,N](u0,+(λ),u1,(λ)).(5.2)\begin{aligned} \#_{[0, N]}(u_{0, +}(\lambda), u_{2, -}(\lambda)) &= E_{(-\infty, \lambda)}(J_2) - E_{(-\infty, \lambda)}(J_0) \\ &\geq E_{(-\infty, \lambda)}(J_1) - E_{(-\infty, \lambda)}(J_0) = \#_{[0, N]}(u_{0, +}(\lambda), u_{1, -}(\lambda)). \end{aligned} \quad (5.2)

The other claims follow analogously from $E_{(-\infty, \lambda]}(J_2) \geq E_{(-\infty, \lambda]}(J_1)$ and Theorem 1.1. $\square$

Corollary 5.2. Let $a_0 = a_1 = a_2$ and $b_0(j) \geq b_1(j) \geq b_2(j)$ for all $j = 1, \dots, N-1$ . If 0 and $N-1$ are positive nodes of $W(u_{0, \pm}(\lambda), u_{1, \mp}(\lambda))$ , then $W(u_{0, \pm}(\lambda), u_{2, \mp}(\lambda))$ has at least two positive nodes at $0, \dots, N-1$ .

Theorem 5.3. Let $m < n$ , then

#[m,n](u0,u1)(#(m,n)(u1)#(m,n)(u0))1,(5.3)|\#_{[m, n]}(u_0, u_1) - (\#_{(m, n)}(u_1) - \#_{(m, n)}(u_0))| \leq 1, \quad (5.3)

where $#{[m, n]}$ can be replaced by $#{(m, n]}$ or $#_{[m, n]}$ .

Proof. For all $x, y \in \mathbb{R}$ we have

0xy(xy)1and1xy(xy)0.(5.4)0 \leq \lceil x - y \rceil - (\lceil x \rceil - \lceil y \rceil) \leq 1 \quad \text{and} \quad -1 \leq \lfloor x - y \rfloor - (\lfloor x \rfloor - \lfloor y \rfloor) \leq 0. \quad (5.4)

Hence, by (4.28), Theorem 3.6, and $-\lceil x \rceil = \lfloor -x \rfloor$ we have

#[m,n](u0,u1)(#(m,n)(u1)#(m,n)(u0))=θ1(n)θ0(n)π(θ1(n)πθ0(n)π)+θ0(m)θ1(m)π(θ0(m)πθ1(m)π)1.\begin{aligned} &|\#_{[m, n]}(u_0, u_1) - (\#_{(m, n)}(u_1) - \#_{(m, n)}(u_0))| \\ &= \left| \left\lceil \frac{\theta_1(n) - \theta_0(n)}{\pi} \right\rceil - \left( \left\lceil \frac{\theta_1(n)}{\pi} \right\rceil - \left\lceil \frac{\theta_0(n)}{\pi} \right\rceil \right) + \left\lfloor \frac{\theta_0(m) - \theta_1(m)}{\pi} \right\rfloor - \left( \left\lfloor \frac{\theta_0(m)}{\pi} \right\rfloor - \left\lfloor \frac{\theta_1(m)}{\pi} \right\rfloor \right) \right| \\ &\leq 1. \end{aligned}Moreover, by Lemma 4.8 and Theorem 3.6 we have

#(m,n](u0,u1)(#(m,n](u1)#(m,n](u0))=Δ(n)π(θ1(n)πθ0(n)π)(Δ(m)π(θ1(m)πθ0(m)π))1(5.5)\begin{aligned} & \#_{(m,n]}(u_0, u_1) - (\#_{(m,n]}(u_1) - \#_{(m,n]}(u_0)) \\ &= \lceil \frac{\Delta(n)}{\pi} \rceil - (\lceil \frac{\theta_1(n)}{\pi} \rceil - \lceil \frac{\theta_0(n)}{\pi} \rceil) - (\lfloor \frac{\Delta(m)}{\pi} \rfloor - (\lfloor \frac{\theta_1(m)}{\pi} \rfloor - \lfloor \frac{\theta_0(m)}{\pi} \rfloor)) - 1 \end{aligned} \quad (5.5)

and

#[m,n](u0,u1)(#[m,n](u1)#[m,n](u0))=1+θ0(m)θ1(m)π(θ0(m)πθ1(m)π)(θ0(n)θ1(n)π(θ0(n)πθ1(n)π)).\begin{aligned} & \#_{[m,n]}(u_0, u_1) - (\#_{[m,n]}(u_1) - \#_{[m,n]}(u_0)) \\ &= 1 + \lfloor \frac{\theta_0(m) - \theta_1(m)}{\pi} \rfloor - (\lfloor \frac{\theta_0(m)}{\pi} \rfloor - \lfloor \frac{\theta_1(m)}{\pi} \rfloor) - (\lceil \frac{\theta_0(n) - \theta_1(n)}{\pi} \rceil - (\lceil \frac{\theta_0(n)}{\pi} \rceil - \lceil \frac{\theta_1(n)}{\pi} \rceil)). \end{aligned}

Theorem 5.4 (Triangle Inequality for Wronskians). We have

#[m,n](u0,u2)(#[m,n](u0,u1)+#[m,n](u1,u2))1,(5.6)|\#_{[m,n]}(u_0, u_2) - (\#_{[m,n]}(u_0, u_1) + \#_{[m,n]}(u_1, u_2))| \leq 1, \quad (5.6)

where $#{[m,n]}$ can be replaced by $#{(m,n]}$ .

Proof. Abbreviate $\Delta_{i,j} := \Delta_{u_i, u_j}$ , then $\Delta_{0,1} + \Delta_{1,2} = \Delta_{0,2}$ . By (4.28) we have $#{[m,n]}(u_0, u_2) = \lceil \Delta{0,2}(n)/\pi \rceil - \lceil \Delta_{0,2}(m)/\pi \rceil$ , hence

#[m,n](u0,u1)+#[m,n](u1,u2)Δ0,2(n)/π+1Δ0,2(m)/π=#[m,n](u0,u2)+1,#[m,n](u0,u1)+#[m,n](u1,u2)Δ0,2(n)/π(Δ0,2(m)/π+1)=#[m,n](u0,u2)1(5.7)\begin{aligned} & \#_{[m,n]}(u_0, u_1) + \#_{[m,n]}(u_1, u_2) \\ & \leq \lceil \Delta_{0,2}(n)/\pi \rceil + 1 - \lceil \Delta_{0,2}(m)/\pi \rceil = \#_{[m,n]}(u_0, u_2) + 1, \\ & \#_{[m,n]}(u_0, u_1) + \#_{[m,n]}(u_1, u_2) \\ & \geq \lceil \Delta_{0,2}(n)/\pi \rceil - (\lceil \Delta_{0,2}(m)/\pi \rceil + 1) = \#_{[m,n]}(u_0, u_2) - 1 \end{aligned} \quad (5.7)

holds by $\lceil x + y \rceil \leq \lceil x \rceil + \lceil y \rceil \leq \lceil x + y \rceil + 1$ for all $x, y \in \mathbb{R}$ . Further, by Lemma 4.8 and $\lfloor x + y \rfloor - 1 \leq \lfloor x \rfloor + \lfloor y \rfloor \leq \lfloor x + y \rfloor$ we have

#(m,n](u0,u1)+#(m,n](u1,u2)Δ0,2(n)/πΔ0,2(m)/π=#(m,n](u0,u2)+1(5.8)\begin{aligned} & \#_{(m,n]}(u_0, u_1) + \#_{(m,n]}(u_1, u_2) \\ & \leq \lceil \Delta_{0,2}(n)/\pi \rceil - \lfloor \Delta_{0,2}(m)/\pi \rfloor = \#_{(m,n]}(u_0, u_2) + 1 \end{aligned} \quad (5.8)

and $#{(m,n]}(u_0, u_2) \leq #{(m,n]}(u_0, u_1) + #_{(m,n]}(u_1, u_2) + 1$ . □

Theorem 5.5 (Comparison Theorem for Wronskians II). If either

A: $W_j(u_0, u_1)u_0(j+1)u_1(j+1) \leq 0$ and $W_j(u_1, u_2)u_1(j+1)u_2(j+1) \leq 0$ for all $j = 0, \dots, N-2$ or

B: $a_0 = a_1 = a_2$ and $b_0(j) \geq b_1(j) \geq b_2(j)$ for all $j = 1, \dots, N-1$

holds and 0 and $N-2$ are (positive) nodes of $W(u_0, u_1)$ , then $W(u_0, u_2)$ has at least one positive node at $0, \dots, N-2$ .

Proof. In either case we have $#_j(u_0, u_1) \geq 0$ and $#_j(u_1, u_2) \geq 0$ for all $j = 0, \dots, N-2$ and hence from Theorem 5.4 we conclude

#[0,N1](u0,u2)#[0,N1](u0,u1)2+#[0,N1](u1,u2)01.(5.9)\#_{[0,N-1]}(u_0, u_2) \geq \underbrace{\#_{[0,N-1]}(u_0, u_1)}_{\geq 2} + \underbrace{\#_{[0,N-1]}(u_1, u_2)}_{\geq 0} - 1. \quad (5.9)

Acknowledgments. I wish to thank Gerald Teschl for several useful discussions.REFERENCES

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FACULTY OF MATHEMATICS, UNIVERSITY OF VIENNA, NORDBERGSTRASSE 15, 1090 WIEN, AUSTRIA

E-mail address: Kerstin.Ammann@univie.ac.at

URL: http://www.mat.univie.ac.at/~kerstin/

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