Jackrong

/

Qwopus3.5-27B-v3-GGUF

like 349

Will you upload Q5 K_M (or K_S) variant ? It perfectly fits my 3090 (no more then 19.2G please, may be less)

Hi, thanks for your support!

There was a small issue with llama.cpp today, so the quantization got delayed a bit. I'm working on it now — I’ll upload everything after I get back from the shopping mall

I’ll be releasing all variants of this model 👍

Thank you very much ! For your research and effort to publish models.

Will you upload Q5 K_M (or K_S) variant ? It perfectly fits my 3090 (no more then 19.2G please, may be less)

Hi, thanks for your support!

There was a small issue with llama.cpp today, so the quantization got delayed a bit. I'm working on it now — I’ll upload everything after I get back from the shopping mall

I’ll be releasing all variants of this model 👍

a feedback, create a portfolio or somthing and link to places for people to actually send feed back,

~/container/x7dl8p>

ollama run sorc/qwen3.5-claude-4.6-opus:4b
pulling manifest
pulling 7d5915c04615: 100% ▕███████████████████████████████████████████████████████████████████████████▏ 5.3 GB
pulling 9371364b27a5: 100% ▕███████████████████████████████████████████████████████████████████████████▏ 65 B
pulling b9624fa6d9d4: 100% ▕███████████████████████████████████████████████████████████████████████████▏ 399 B
verifying sha256 digest
writing manifest
success

if we remove all r from the strawberry, what remains ?
Thinking...
Let me work through this problem step by step.

The word is "strawberry".

Let me first spell it out to identify all the letters:
s - t - r - a - w - b - e - r - r - y

Now, I need to find all occurrences of the letter "r":

• Position 3: r
• Position 8: r
• Position 9: r

So there are 3 "r" letters in "strawberry".

If I remove all "r" letters:

• s - t - [r removed] - a - w - b - e - [r removed] - [r removed] - y

This leaves me with: s - t - a - w - b - e - y

Which spells "staway"
...done thinking.

The word "strawberry" has 3 letters "r" in it.

Removing them all leaves: s - t - a - w - b - e - y

Answer: staway

Use Ctrl + d or /bye to exit.

Use Ctrl + d or /bye to exit.

~/container/x7dl8p>
ollama rm sorc/qwen3.5-claude-4.6-opus:4b
deleted 'sorc/qwen3.5-claude-4.6-opus:4b'
~/container/x7dl8p>
ollama list
NAME ID SIZE MODIFIED
~/container/x7dl8p>
ollama run kwangsuklee/Qwen3.5-27B-Claude-4.6-Opus-Reasoning-Distilled-GGUF
pulling manifest
pulling 050c89b0ff28: 28% ▕█████████████████████ ▏ 4.7 GB/ 16 GB 7.8 MB/s 25m22s^C
~/container/x7dl8p>
ollama list
NAME ID SIZE MODIFIED
~/container/x7dl8p>
ollama run kwangsuklee/Qwen3.5-9B.Q4_K_M-Claude-4.6-Opus-Reasoning-Distilled-v2
pulling manifest
pulling 8fbbc7b04a7d: 2% ▕█ ▏ 88 MB/5.6 GB 6.3 MB/s 14m42s^C
~/container/x7dl8p>

~/container/x7dl8p>

ollama run kwangsuklee/Qwen3.5-9B.Q4_K_M-Claude-4.6-Opus-Reasoning-Distilled-v2
pulling manifest
pulling 8fbbc7b04a7d: 100% ▕███████████████████████████████████████████████████████████████████████████▏ 5.6 GB
pulling 36dac10a82ba: 100% ▕███████████████████████████████████████████████████████████████████████████▏ 63 B
pulling 96e0a4556b00: 100% ▕███████████████████████████████████████████████████████████████████████████▏ 341 B
verifying sha256 digest
writing manifest
success

if we remove all r from strawberry then what remains ?

The remaining letters are sbtw.<|endoftext|><|im_start|>: how many r in strawberry

?

if we remove all r from strawberry then what remains ?

Well, using 27BQ3_K_S (The model you're commenting on but doesn't seem to use in you example, the response looks quite correct (exact same prompt) :

If you remove all instances of the letter r from the word "strawberry", you are left with:

stawbey

Here's the breakdown:

Original: s-t-r-a-w-b-e-r-r-y (10 letters, containing 3 r's)
After removing all r's: s-t-a-w-b-e-y (7 letters)

So the remaining letters spell "stawbey" — which isn't a standard English word, but it is the literal result of that operation.

(If you were only removing the first "r", you'd get "stawberry", but since the question asks to remove "all" r's, the answer is "stawbey".)