""" PROBLEM 6: Lindelöf Hypothesis — Numerical Evidence ===================================================== Lindelöf Hypothesis: ζ(1/2 + it) = O(t^ε) for all ε > 0 Best known: O(t^{13/84}) ≈ O(t^{0.155}) [Bourgain 2017] Method: 1. Compute |ζ(1/2 + it)| at the 100k zero ordinates t = γ_n 2. Plot log|ζ(1/2+iγ_n)|/log(γ_n) 3. If Lindelöf is true, this ratio → 0 4. Estimate empirical exponent: |ζ(1/2+it)| ~ t^θ """ import numpy as np from mpmath import zeta, mp, sqrt, log, exp from typing import Dict class LindeloefAnalyzer: def __init__(self, zeros: list): self.zeros = np.array(zeros) self.results = {} def analyze(self, n_samples: int = 2000) -> Dict: mp.dps = 15 # Sample at logarithmically spaced zero indices indices = np.unique(np.logspace(0, np.log10(len(self.zeros)), n_samples).astype(int)) indices = [i for i in indices if i > 0 and i <= len(self.zeros)] ratios = [] zeta_abs = [] gamma_vals = [] for idx in indices: gamma = self.zeros[idx - 1] t = float(gamma) if t < 100: continue # Compute |ζ(1/2 + it)| — skip mpmath for speed, use approximation # Actually compute with lower precision for speed val = abs(zeta(0.5 + 1j * t)) ratio = float(log(val) / log(t)) if val > 0 else 0 ratios.append(ratio) zeta_abs.append(float(val)) gamma_vals.append(t) ratios = np.array(ratios) gamma_vals = np.array(gamma_vals) # Fit θ in |ζ| ~ t^θ via log-log regression log_g = np.log(gamma_vals) log_z = np.log(zeta_abs) theta = float(np.polyfit(log_g, log_z, 1)[0]) self.results = { 'n_samples': len(ratios), 'gamma_values': gamma_vals.tolist(), 'zeta_abs': zeta_abs, 'ratios': ratios.tolist(), 'max_ratio': float(np.max(ratios)), 'mean_ratio': float(np.mean(ratios)), 'theta_estimate': theta, 'bourgain_bound': 13.0 / 84.0, # ≈ 0.155 'lindeloef_satisfied': bool(theta < 0.3), # heuristic } return self.results def summary(self) -> str: r = self.results s = f"Lindelöf Hypothesis Analysis\n{'='*50}\n" s += f"Samples: {r['n_samples']}\n" s += f"Estimated θ: {r['theta_estimate']:.4f} (|ζ| ~ t^θ)\n" s += f"Bourgain bound: {r['bourgain_bound']:.4f}\n" s += f"Lindelöf threshold (<0.3 heuristic): {r['lindeloef_satisfied']}\n" s += f"Max log|ζ|/log(t): {r['max_ratio']:.4f}\n" return s