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| "text": "so...how to find the proper \"shift\"?" |
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| "text": "How do we get A2 from A1 ??" |
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| "text": "Should we not use A0 = QR , A1=RQ => A0 = QRQ^-1 since we know Q is orthogonal and hence invertible? Where as R is not invertible unless A is?" |
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| "text": "Is he talking about Galois or Abel?" |
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| "text": "why cannot simple steps to get upper triangle? still don't get it from this lecture" |
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| "text": "At around the 21 minute mark, he says that it\u2019s too much to hope for to reduce the matrix A0 to an upper triangular matrix. He immediately follows up with a statement that it\u2019s impossible to solve a 5x5 system with simple steps. And this is why you instead reduce A0 to an upper Hessenberg matrix instead.\n\nI got lost trying to follow this argument, so I did a bit of research. Can someone tell me if I've got it right:\n1) The eigenvalues of a triangular matrix are just its diagonal elements.\n2) The Abel-Ruffini theorem says that's impossible, using radicals, to find the roots of a 5th order polynomial.\n3) If you were to try to solve det(A - lambda I) = 0 for a 5x5 triangular matrix, you'd be trying to find the roots of a 5th order polynomial. Though doesn't it automatically come perfectly factored for you to read off the eigenvalues?\n\nCombining all of these, does the Abel-Ruffini theorem imply that you can't transform a 5x5 matrix into triangular form via orthogonal transformations (e.g. Householder reflections) which preserve the eigenvalues? This doesn't sit right with me, so I'm thinking that can't be it." |
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| "text": "What happens when the eigenvalues are complex? It doesn't seem like the QR method would converge as all the numbers resulting from this method would be real." |
| } |
| ] |