The number of adult racoon in Cedar Valley equals the number of adult racoon in Pine Ridge. The number of adult deer in Cedar Valley equals 4 times the total number of adult animals in Pine Ridge. The number of adult fox in Cedar Valley equals 2 plus the number of adult racoon in Beverly Forest. The number of adult deer in Pine Ridge equals the total number of adult animals in Beverly Forest. The number of adult racoon in Beverly Forest equals 3. The number of adult racoon in Pine Ridge equals 2 plus the number of adult deer in Pine Ridge.

Question: What is the total number of adult animals in Cedar Valley?

Solution: Define adult racoon in Beverly Forest as X; so X = 3. Define total number of adult animals in Beverly Forest as R; so R = X = 3. Define adult deer in Pine Ridge as Q; so Q = R = 3. Define adult racoon in Pine Ridge as H; N = Q = 3; so H = 2 + N = 2 + 3 = 5. Define total number of adult animals in Pine Ridge as d; so d = H + Q = 5 + 3 = 8. Define adult deer in Cedar Valley as D; V = d = 8; so D = 4 * V = 4 * 8 = 32. Define adult racoon in Cedar Valley as i; so i = H = 5. Define adult fox in Cedar Valley as j; E = X = 3; so j = 2 + E = 2 + 3 = 5. Define total number of adult animals in Cedar Valley as p; L = i + j = 5 + 5 = 10; so p = L + D = 10 + 32 = 42. Answer: 42.


The number of adult parrot in Mayer Aquarium equals 4. The number of adult parrot in Hamilton Farm equals 2 plus the total number of adult animals in Bundle Ranch. The number of adult eagle in Bundle Ranch equals the difference between the number of adult crow in Bundle Ranch and the total number of adult animals in Mayer Aquarium. The number of adult crow in Bundle Ranch equals 3 plus the total number of adult animals in Mayer Aquarium. The number of adult blue jay in South Zoo equals 4 times the sum of the total number of adult animals in Hamilton Farm and the total number of adult animals in Mayer Aquarium.

Question: What is the total number of adult animals in South Zoo?

Solution: Define adult parrot in Mayer Aquarium as R; so R = 4. Define total number of adult animals in Mayer Aquarium as w; so w = R = 4. Define adult crow in Bundle Ranch as Z; N = w = 4; so Z = 3 + N = 3 + 4 = 7. Define adult eagle in Bundle Ranch as C; so C = Z - w = 7 - 4 = 3. Define total number of adult animals in Bundle Ranch as v; so v = C + Z = 3 + 7 = 10. Define adult parrot in Hamilton Farm as W; D = v = 10; so W = 2 + D = 2 + 10 = 12. Define total number of adult animals in Hamilton Farm as H; so H = W = 12. Define adult blue jay in South Zoo as V; A = H + w = 12 + 4 = 16; so V = 4 * A = 4 * 16 = 64. Define total number of adult animals in South Zoo as l; so l = V = 64. Answer: 64.


The number of public highschool in Clearwater Bay equals 1 plus the number of elementary school in Ruby Bay. The number of private middle school in Oakbridge City equals the sum of the number of regional medical school in Ruby Bay, the number of regional medical school in Riverton City, and the number of public highschool in Riverton City. The number of public highschool in Ruby Bay equals the number of regional medical school in Riverton City. The number of culinarian school in Clearwater Bay equals 4. The number of public highschool in Riverton City equals 3 plus the number of regional medical school in Riverton City. The number of elementary school in Shoreline City equals the sum of the number of private middle school in Riverton City and the number of regional medical school in Ruby Bay. The number of private middle school in Clearwater Bay equals the sum of the number of private middle school in Oakbridge City, the total number of schools in Riverton City, and the number of culinarian school in Clearwater Bay. The number of private middle school in Shoreline City equals the number of regional medical school in Ruby Bay. The number of regional medical school in Ruby Bay equals the total number of schools in Riverton City. The number of private middle school in Riverton City equals the number of public highschool in Riverton City. The number of public highschool in Oakbridge City equals the difference between the number of private middle school in Oakbridge City and the total number of schools in Riverton City. The number of culinarian school in Ruby Bay equals 1. The number of regional medical school in Shoreline City equals 4 times the sum of the number of elementary school in Ruby Bay and the number of public highschool in Oakbridge City. The number of regional medical school in Riverton City equals 2. The number of elementary school in Ruby Bay equals 1 plus the number of culinarian school in Clearwater Bay.

Question: What is the total number of schools in Oakbridge City?

Solution: Define regional medical school in Riverton City as w; so w = 2. Define public highschool in Riverton City as J; Q = w = 2; so J = 3 + Q = 3 + 2 = 5. Define private middle school in Riverton City as o; so o = J = 5. Define total number of schools in Riverton City as j; M = J + w = 5 + 2 = 7; so j = M + o = 7 + 5 = 12. Define regional medical school in Ruby Bay as e; so e = j = 12. Define private middle school in Oakbridge City as g; c = e + w = 12 + 2 = 14; so g = c + J = 14 + 5 = 19. Define public highschool in Oakbridge City as R; so R = g - j = 19 - 12 = 7. Define total number of schools in Oakbridge City as G; so G = R + g = 7 + 19 = 26. Answer: 26.


The number of intense detective thriller in Golden Banana Movie Festival equals the sum of the number of solemn period drama in Taylor Movie Festival and the number of intense detective thriller in Taylor Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals 4 plus the number of futuristic sci-fi movie in Taylor Movie Festival. The number of intense detective thriller in Taylor Movie Festival equals 4. The number of futuristic sci-fi movie in Taylor Movie Festival equals 4. The number of solemn period drama in Taylor Movie Festival equals 3 times the number of futuristic sci-fi movie in Taylor Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals the total number of movies in Taylor Movie Festival.

Question: What is the total number of movies in Golden Banana Movie Festival?

Solution: Define futuristic sci-fi movie in Taylor Movie Festival as X; so X = 4. Define intense detective thriller in Taylor Movie Festival as A; so A = 4. Define solemn period drama in Taylor Movie Festival as c; l = X = 4; so c = 3 * l = 3 * 4 = 12. Define total number of movies in Taylor Movie Festival as W; t = A + c = 4 + 12 = 16; so W = t + X = 16 + 4 = 20. Define calm road movie in Golden Banana Movie Festival as a; so a = W = 20. Define solemn period drama in Golden Banana Movie Festival as e; K = X = 4; so e = 4 + K = 4 + 4 = 8. Define intense detective thriller in Golden Banana Movie Festival as h; so h = c + A = 12 + 4 = 16. Define total number of movies in Golden Banana Movie Festival as j; R = a + h = 20 + 16 = 36; so j = R + e = 36 + 8 = 44. Answer: 44.


The number of private middle school in Westhaven City equals 1 plus the total number of schools in Glenfield City. The number of private middle school in Brightford equals the total number of schools in Westhaven City. The number of private middle school in Evervale City equals the sum of the total number of schools in Brightford, the total number of schools in Glenfield City, and the number of regional medical school in Brightford. The number of public highschool in Westhaven City equals the number of private middle school in Westhaven City. The number of regional medical school in Brightford equals the total number of schools in Glenfield City. The number of regional medical school in Glenfield City equals 3.

Question: What is the total number of schools in Evervale City?

Solution: Define regional medical school in Glenfield City as e; so e = 3. Define total number of schools in Glenfield City as t; so t = e = 3. Define private middle school in Westhaven City as d; D = t = 3; so d = 1 + D = 1 + 3 = 4. Define public highschool in Westhaven City as P; so P = d = 4. Define total number of schools in Westhaven City as J; so J = d + P = 4 + 4 = 8. Define private middle school in Brightford as f; so f = J = 8. Define regional medical school in Brightford as a; so a = t = 3. Define total number of schools in Brightford as Y; so Y = a + f = 3 + 8 = 11. Define private middle school in Evervale City as c; j = Y + t = 11 + 3 = 14; so c = j + a = 14 + 3 = 17. Define total number of schools in Evervale City as p; so p = c = 17. Answer: 17.


The number of intense detective thriller in Taylor Movie Festival equals 3. The number of calm road movie in West Sahara Movie Festival equals 2 times the sum of the number of calm road movie in Golden Banana Movie Festival, the number of intense detective thriller in West Sahara Movie Festival, and the number of solemn period drama in West Sahara Movie Festival. The number of upbeat metropolis comedy in West Sahara Movie Festival equals the difference between the number of intense detective thriller in Taylor Movie Festival and the number of calm road movie in West Sahara Movie Festival. The number of solemn period drama in Taylor Movie Festival equals 2 times the sum of the number of upbeat metropolis comedy in Golden Banana Movie Festival and the number of intense detective thriller in Northwood Movie Festival. The number of calm road movie in Northwood Movie Festival equals the sum of the number of calm road movie in Golden Banana Movie Festival, the number of intense detective thriller in West Sahara Movie Festival, and the number of solemn period drama in West Sahara Movie Festival. The number of intense detective thriller in Golden Banana Movie Festival equals the number of upbeat metropolis comedy in Northwood Movie Festival. The number of intense detective thriller in West Sahara Movie Festival equals 3 times the number of calm road movie in Golden Banana Movie Festival. The number of solemn period drama in West Sahara Movie Festival equals 3 plus the sum of the number of calm road movie in Golden Banana Movie Festival and the number of intense detective thriller in West Sahara Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals 3. The number of solemn period drama in Golden Banana Movie Festival equals the sum of the number of intense detective thriller in West Sahara Movie Festival and the number of solemn period drama in West Sahara Movie Festival. The number of intense detective thriller in Northwood Movie Festival equals 2. The number of solemn period drama in Northwood Movie Festival equals 4. The number of calm road movie in Taylor Movie Festival equals the sum of the number of intense detective thriller in Northwood Movie Festival, the number of upbeat metropolis comedy in Golden Banana Movie Festival, and the number of solemn period drama in Taylor Movie Festival. The number of upbeat metropolis comedy in Northwood Movie Festival equals 2. The number of upbeat metropolis comedy in Taylor Movie Festival equals 3. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 4 plus the number of intense detective thriller in Northwood Movie Festival.

Question: What is the total number of movies in Taylor Movie Festival?

Solution: Define intense detective thriller in Northwood Movie Festival as K; so K = 2. Define upbeat metropolis comedy in Golden Banana Movie Festival as S; B = K = 2; so S = 4 + B = 4 + 2 = 6. Define solemn period drama in Taylor Movie Festival as A; k = S + K = 6 + 2 = 8; so A = 2 * k = 2 * 8 = 16. Define calm road movie in Taylor Movie Festival as G; R = K + S = 2 + 6 = 8; so G = R + A = 8 + 16 = 24. Define upbeat metropolis comedy in Taylor Movie Festival as o; so o = 3. Define intense detective thriller in Taylor Movie Festival as i; so i = 3. Define total number of movies in Taylor Movie Festival as Z; a = A + o = 16 + 3 = 19; f = a + i = 19 + 3 = 22; so Z = f + G = 22 + 24 = 46. Answer: 46.


The number of regional medical school in Glenfield City equals the number of regional medical school in Evervale City. The number of elementary school in Glenfield City equals the number of elementary school in Evervale City. The number of private middle school in Glenfield City equals the number of regional medical school in Evervale City. The number of elementary school in Evervale City equals 3. The number of private middle school in Brightford equals the number of regional medical school in Westhaven City. The number of culinarian school in Brightford equals 1 plus the sum of the number of regional medical school in Westhaven City, the number of culinarian school in Westhaven City, and the number of elementary school in Brightford. The number of private middle school in Evervale City equals the number of elementary school in Evervale City. The number of culinarian school in Westhaven City equals 1 plus the number of regional medical school in Westhaven City. The number of private middle school in Westhaven City equals 4 times the number of elementary school in Glenfield City. The number of regional medical school in Evervale City equals the number of private middle school in Evervale City. The number of culinarian school in Glenfield City equals 1 plus the total number of schools in Evervale City. The number of elementary school in Brightford equals the number of regional medical school in Westhaven City. The number of regional medical school in Westhaven City equals 4. The number of elementary school in Westhaven City equals 3.

Question: What is the total number of schools in Glenfield City?

Solution: Define elementary school in Evervale City as o; so o = 3. Define private middle school in Evervale City as T; so T = o = 3. Define regional medical school in Evervale City as h; so h = T = 3. Define total number of schools in Evervale City as Y; a = T + h = 3 + 3 = 6; so Y = a + o = 6 + 3 = 9. Define elementary school in Glenfield City as s; so s = o = 3. Define private middle school in Glenfield City as E; so E = h = 3. Define culinarian school in Glenfield City as G; v = Y = 9; so G = 1 + v = 1 + 9 = 10. Define regional medical school in Glenfield City as e; so e = h = 3. Define total number of schools in Glenfield City as k; z = E + G = 3 + 10 = 13; y = z + e = 13 + 3 = 16; so k = y + s = 16 + 3 = 19. Answer: 19.


The number of adult wolf in Bundle Ranch equals 4. The number of adult wolf in Mayer Aquarium equals 1 plus the total number of adult animals in Bundle Ranch. The number of adult racoon in South Zoo equals the total number of adult animals in Mayer Aquarium. The number of adult deer in South Zoo equals the sum of the total number of adult animals in Mayer Aquarium and the total number of adult animals in Bundle Ranch. The number of adult bear in Bundle Ranch equals 2. The number of adult bear in South Zoo equals 4 times the total number of adult animals in Mayer Aquarium.

Question: What is the total number of adult animals in South Zoo?

Solution: Define adult wolf in Bundle Ranch as t; so t = 4. Define adult bear in Bundle Ranch as L; so L = 2. Define total number of adult animals in Bundle Ranch as Q; so Q = t + L = 4 + 2 = 6. Define adult wolf in Mayer Aquarium as A; M = Q = 6; so A = 1 + M = 1 + 6 = 7. Define total number of adult animals in Mayer Aquarium as p; so p = A = 7. Define adult deer in South Zoo as V; so V = p + Q = 7 + 6 = 13. Define adult racoon in South Zoo as q; so q = p = 7. Define adult bear in South Zoo as z; W = p = 7; so z = 4 * W = 4 * 7 = 28. Define total number of adult animals in South Zoo as U; n = q + V = 7 + 13 = 20; so U = n + z = 20 + 28 = 48. Answer: 48.


The number of adult racoon in Oakridge Riverside equals the sum of the total number of adult animals in Cedar Valley, the number of adult deer in Cedar Valley, the number of adult wolf in Cedar Valley, and the number of adult racoon in Cedar Valley. The number of adult wolf in Oakridge Riverside equals the number of adult deer in Oakridge Riverside. The number of adult deer in Oakridge Riverside equals the number of adult deer in Cedar Valley. The number of adult deer in Cedar Valley equals 2. The number of adult racoon in Cedar Valley equals the number of adult wolf in Cedar Valley. The number of adult wolf in Cedar Valley equals 3.

Question: What is the total number of adult animals in Oakridge Riverside?

Solution: Define adult wolf in Cedar Valley as D; so D = 3. Define adult racoon in Cedar Valley as h; so h = D = 3. Define adult deer in Cedar Valley as c; so c = 2. Define total number of adult animals in Cedar Valley as Q; z = h + D = 3 + 3 = 6; so Q = z + c = 6 + 2 = 8. Define adult racoon in Oakridge Riverside as A; V = Q + c = 8 + 2 = 10; F = V + D = 10 + 3 = 13; so A = F + h = 13 + 3 = 16. Define adult deer in Oakridge Riverside as s; so s = c = 2. Define adult wolf in Oakridge Riverside as q; so q = s = 2. Define total number of adult animals in Oakridge Riverside as E; I = A + q = 16 + 2 = 18; so E = I + s = 18 + 2 = 20. Answer: 20.


The number of adult crow in Cedar Valley equals the number of adult crow in Maple Creek. The number of adult owl in Beverly Forest equals 3 plus the total number of adult animals in Maple Creek. The number of adult blue jay in Beverly Forest equals 1 plus the number of adult owl in Beverly Forest. The number of adult crow in Maple Creek equals 3. The number of adult blue jay in Cedar Valley equals the total number of adult animals in Beverly Forest. The number of adult blue jay in Maple Creek equals 4 plus the number of adult crow in Maple Creek.

Question: What is the total number of adult animals in Cedar Valley?

Solution: Define adult crow in Maple Creek as Q; so Q = 3. Define adult blue jay in Maple Creek as M; X = Q = 3; so M = 4 + X = 4 + 3 = 7. Define total number of adult animals in Maple Creek as O; so O = Q + M = 3 + 7 = 10. Define adult owl in Beverly Forest as m; x = O = 10; so m = 3 + x = 3 + 10 = 13. Define adult blue jay in Beverly Forest as f; u = m = 13; so f = 1 + u = 1 + 13 = 14. Define adult crow in Cedar Valley as G; so G = Q = 3. Define total number of adult animals in Beverly Forest as L; so L = m + f = 13 + 14 = 27. Define adult blue jay in Cedar Valley as J; so J = L = 27. Define total number of adult animals in Cedar Valley as Y; so Y = G + J = 3 + 27 = 30. Answer: 30.


The number of adult crow in Jefferson Circus equals 2 times the difference between the number of adult parrot in Jefferson Circus and the number of adult parrot in South Zoo. The number of adult blue jay in Jefferson Circus equals the sum of the number of adult parrot in Jefferson Circus, the number of adult crow in Jefferson Circus, and the number of adult owl in Jefferson Circus. The number of adult owl in Hamilton Farm equals 3 times the number of adult blue jay in Jefferson Circus. The number of adult owl in Jefferson Circus equals 3 plus the number of adult parrot in South Zoo. The number of adult blue jay in Hamilton Farm equals 3 times the sum of the number of adult crow in Jefferson Circus, the number of adult eagle in South Zoo, and the number of adult parrot in Jefferson Circus. The number of adult eagle in Jefferson Circus equals 3. The number of adult parrot in Jefferson Circus equals 4 plus the sum of the number of adult eagle in South Zoo and the number of adult parrot in South Zoo. The number of adult crow in South Zoo equals 3. The number of adult parrot in South Zoo equals 1. The number of adult crow in Hamilton Farm equals the sum of the number of adult blue jay in Hamilton Farm, the number of adult owl in Jefferson Circus, the total number of adult animals in South Zoo, and the number of adult crow in Jefferson Circus. The number of adult eagle in Hamilton Farm equals 4 plus the number of adult crow in Jefferson Circus. The number of adult eagle in South Zoo equals 3 times the number of adult owl in Jefferson Circus. The number of adult parrot in Hamilton Farm equals 4.

Question: How many adult blue jay does Hamilton Farm have?

Solution: Define adult parrot in South Zoo as r; so r = 1. Define adult owl in Jefferson Circus as Q; J = r = 1; so Q = 3 + J = 3 + 1 = 4. Define adult eagle in South Zoo as V; F = Q = 4; so V = 3 * F = 3 * 4 = 12. Define adult parrot in Jefferson Circus as T; z = V + r = 12 + 1 = 13; so T = 4 + z = 4 + 13 = 17. Define adult crow in Jefferson Circus as W; q = T - r = 17 - 1 = 16; so W = 2 * q = 2 * 16 = 32. Define adult blue jay in Hamilton Farm as U; w = W + V = 32 + 12 = 44; h = w + T = 44 + 17 = 61; so U = 3 * h = 3 * 61 = 183. Answer: 183.


The number of elementary school in Ruby Bay equals 4. The number of private middle school in Clearwater Bay equals 3. The number of private middle school in Ruby Bay equals the sum of the total number of schools in Oakbridge City, the total number of schools in Clearwater Bay, and the number of elementary school in Oakbridge City. The number of regional medical school in Clearwater Bay equals 1 plus the number of private middle school in Clearwater Bay. The number of elementary school in Oakbridge City equals the total number of schools in Shoreline City. The number of elementary school in Shoreline City equals the total number of schools in Clearwater Bay. The number of regional medical school in Oakbridge City equals 2. The number of regional medical school in Ruby Bay equals 4 times the number of elementary school in Ruby Bay. The number of public highschool in Riverton City equals the number of culinarian school in Oakbridge City. The number of regional medical school in Shoreline City equals 3. The number of culinarian school in Oakbridge City equals the number of regional medical school in Shoreline City.

Question: What is the total number of schools in Oakbridge City?

Solution: Define private middle school in Clearwater Bay as C; so C = 3. Define regional medical school in Clearwater Bay as A; m = C = 3; so A = 1 + m = 1 + 3 = 4. Define total number of schools in Clearwater Bay as S; so S = A + C = 4 + 3 = 7. Define elementary school in Shoreline City as P; so P = S = 7. Define regional medical school in Shoreline City as b; so b = 3. Define total number of schools in Shoreline City as L; so L = b + P = 3 + 7 = 10. Define elementary school in Oakbridge City as d; so d = L = 10. Define culinarian school in Oakbridge City as T; so T = b = 3. Define regional medical school in Oakbridge City as H; so H = 2. Define total number of schools in Oakbridge City as J; Y = H + T = 2 + 3 = 5; so J = Y + d = 5 + 10 = 15. Answer: 15.


The number of solemn period drama in Golden Banana Movie Festival equals the number of intense detective thriller in Golden Banana Movie Festival. The number of solemn period drama in Taylor Movie Festival equals 2 times the total number of movies in Golden Banana Movie Festival. The number of upbeat metropolis comedy in Taylor Movie Festival equals 3 plus the number of intense detective thriller in Golden Banana Movie Festival. The number of intense detective thriller in Taylor Movie Festival equals the number of solemn period drama in Taylor Movie Festival. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 4. The number of intense detective thriller in Golden Banana Movie Festival equals 3 times the number of upbeat metropolis comedy in Golden Banana Movie Festival.

Question: What is the total number of movies in Taylor Movie Festival?

Solution: Define upbeat metropolis comedy in Golden Banana Movie Festival as U; so U = 4. Define intense detective thriller in Golden Banana Movie Festival as E; w = U = 4; so E = 3 * w = 3 * 4 = 12. Define solemn period drama in Golden Banana Movie Festival as Q; so Q = E = 12. Define total number of movies in Golden Banana Movie Festival as T; K = Q + E = 12 + 12 = 24; so T = K + U = 24 + 4 = 28. Define solemn period drama in Taylor Movie Festival as s; u = T = 28; so s = 2 * u = 2 * 28 = 56. Define upbeat metropolis comedy in Taylor Movie Festival as R; r = E = 12; so R = 3 + r = 3 + 12 = 15. Define intense detective thriller in Taylor Movie Festival as y; so y = s = 56. Define total number of movies in Taylor Movie Festival as o; L = s + y = 56 + 56 = 112; so o = L + R = 112 + 15 = 127. Answer: 127.


The number of intense detective thriller in Taylor Movie Festival equals the number of solemn period drama in Golden Banana Movie Festival. The number of upbeat metropolis comedy in Taylor Movie Festival equals the number of intense detective thriller in Taylor Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals 3 plus the number of intense detective thriller in Verdi Movie Festival. The number of solemn period drama in Verdi Movie Festival equals 4 times the total number of movies in Taylor Movie Festival. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals the difference between the number of upbeat metropolis comedy in Taylor Movie Festival and the number of intense detective thriller in Taylor Movie Festival. The number of calm road movie in Verdi Movie Festival equals 2. The number of upbeat metropolis comedy in Verdi Movie Festival equals 4 times the total number of movies in Taylor Movie Festival. The number of solemn period drama in Taylor Movie Festival equals 4. The number of intense detective thriller in Golden Banana Movie Festival equals the number of calm road movie in Verdi Movie Festival. The number of calm road movie in Taylor Movie Festival equals 2 times the difference between the number of solemn period drama in Golden Banana Movie Festival and the number of intense detective thriller in Verdi Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals the sum of the number of upbeat metropolis comedy in Taylor Movie Festival and the number of calm road movie in Taylor Movie Festival. The number of intense detective thriller in Verdi Movie Festival equals 3.

Question: How many upbeat metropolis comedy does Verdi Movie Festival have?

Solution: Define intense detective thriller in Verdi Movie Festival as g; so g = 3. Define solemn period drama in Golden Banana Movie Festival as D; p = g = 3; so D = 3 + p = 3 + 3 = 6. Define calm road movie in Taylor Movie Festival as d; K = D - g = 6 - 3 = 3; so d = 2 * K = 2 * 3 = 6. Define intense detective thriller in Taylor Movie Festival as U; so U = D = 6. Define upbeat metropolis comedy in Taylor Movie Festival as r; so r = U = 6. Define solemn period drama in Taylor Movie Festival as C; so C = 4. Define total number of movies in Taylor Movie Festival as s; Z = r + d = 6 + 6 = 12; L = Z + U = 12 + 6 = 18; so s = L + C = 18 + 4 = 22. Define upbeat metropolis comedy in Verdi Movie Festival as h; n = s = 22; so h = 4 * n = 4 * 22 = 88. Answer: 88.


The number of solemn period drama in Festival de Clairmont equals 1. The number of calm road movie in Festival Lumière de Valmont equals the sum of the total number of movies in Rêves de Belleville, the number of solemn period drama in Rêves de Belleville, and the number of upbeat metropolis comedy in Festival Lumière de Valmont. The number of solemn period drama in Rêves de Belleville equals 3 plus the difference between the number of calm road movie in Rêves de Belleville and the number of upbeat metropolis comedy in Festival Lumière de Valmont. The number of calm road movie in Festival de Clairmont equals 3 times the number of upbeat metropolis comedy in Festival de Clairmont. The number of upbeat metropolis comedy in Festival Lumière de Valmont equals 4 times the number of upbeat metropolis comedy in Rêves de Belleville. The number of upbeat metropolis comedy in Festival de Clairmont equals 4. The number of calm road movie in Rêves de Belleville equals 2 times the sum of the number of upbeat metropolis comedy in Festival Lumière de Valmont and the number of upbeat metropolis comedy in Rêves de Belleville. The number of upbeat metropolis comedy in Rêves de Belleville equals 4.

Question: How many calm road movie does Festival Lumière de Valmont have?

Solution: Define upbeat metropolis comedy in Rêves de Belleville as l; so l = 4. Define upbeat metropolis comedy in Festival Lumière de Valmont as Y; H = l = 4; so Y = 4 * H = 4 * 4 = 16. Define calm road movie in Rêves de Belleville as B; F = Y + l = 16 + 4 = 20; so B = 2 * F = 2 * 20 = 40. Define solemn period drama in Rêves de Belleville as T; h = B - Y = 40 - 16 = 24; so T = 3 + h = 3 + 24 = 27. Define total number of movies in Rêves de Belleville as g; L = l + B = 4 + 40 = 44; so g = L + T = 44 + 27 = 71. Define calm road movie in Festival Lumière de Valmont as V; u = g + T = 71 + 27 = 98; so V = u + Y = 98 + 16 = 114. Answer: 114.


The number of calm road movie in Cinéma de Montreval equals the difference between the number of futuristic sci-fi movie in Cinéma de Montreval and the number of intense detective thriller in Festival Lumière de Valmont. The number of calm road movie in Festival de Saint-Rivage equals 3 times the number of futuristic sci-fi movie in Festival de Saint-Rivage. The number of intense detective thriller in Festival de Saint-Rivage equals 2. The number of calm road movie in Festival Lumière de Valmont equals the number of futuristic sci-fi movie in Festival Lumière de Valmont. The number of futuristic sci-fi movie in Festival Lumière de Valmont equals the number of intense detective thriller in Festival Lumière de Valmont. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals 1. The number of intense detective thriller in Festival Lumière de Valmont equals the number of calm road movie in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Cinéma de Montreval equals 2 times the total number of movies in Festival Lumière de Valmont.

Question: What is the total number of movies in Cinéma de Montreval?

Solution: Define futuristic sci-fi movie in Festival de Saint-Rivage as p; so p = 1. Define calm road movie in Festival de Saint-Rivage as V; j = p = 1; so V = 3 * j = 3 * 1 = 3. Define intense detective thriller in Festival Lumière de Valmont as w; so w = V = 3. Define futuristic sci-fi movie in Festival Lumière de Valmont as O; so O = w = 3. Define calm road movie in Festival Lumière de Valmont as f; so f = O = 3. Define total number of movies in Festival Lumière de Valmont as a; y = O + f = 3 + 3 = 6; so a = y + w = 6 + 3 = 9. Define futuristic sci-fi movie in Cinéma de Montreval as W; m = a = 9; so W = 2 * m = 2 * 9 = 18. Define calm road movie in Cinéma de Montreval as x; so x = W - w = 18 - 3 = 15. Define total number of movies in Cinéma de Montreval as A; so A = W + x = 18 + 15 = 33. Answer: 33.


The number of elementary school in Clearwater Bay equals the sum of the total number of schools in Shoreline City and the number of culinarian school in Shoreline City. The number of elementary school in Oakbridge City equals the number of private middle school in Oakbridge City. The number of private middle school in Clearwater Bay equals 3 plus the difference between the total number of schools in Shoreline City and the number of culinarian school in Shoreline City. The number of private middle school in Ruby Bay equals 3 plus the number of private middle school in Clearwater Bay. The number of culinarian school in Shoreline City equals 3. The number of regional medical school in Ruby Bay equals 4. The number of private middle school in Oakbridge City equals the sum of the total number of schools in Clearwater Bay, the total number of schools in Shoreline City, and the number of elementary school in Clearwater Bay. The number of elementary school in Ruby Bay equals 3 times the sum of the number of elementary school in Oakbridge City, the total number of schools in Clearwater Bay, and the number of culinarian school in Shoreline City. The number of culinarian school in Ruby Bay equals 4.

Question: What is the total number of schools in Oakbridge City?

Solution: Define culinarian school in Shoreline City as R; so R = 3. Define total number of schools in Shoreline City as e; so e = R = 3. Define private middle school in Clearwater Bay as I; B = e - R = 3 - 3 = 0; so I = 3 + B = 3 + 0 = 3. Define elementary school in Clearwater Bay as p; so p = e + R = 3 + 3 = 6. Define total number of schools in Clearwater Bay as s; so s = I + p = 3 + 6 = 9. Define private middle school in Oakbridge City as C; r = s + e = 9 + 3 = 12; so C = r + p = 12 + 6 = 18. Define elementary school in Oakbridge City as c; so c = C = 18. Define total number of schools in Oakbridge City as T; so T = C + c = 18 + 18 = 36. Answer: 36.


The number of private middle school in Oakbridge City equals 3. The number of public highschool in Shoreline City equals 2. The number of regional medical school in Shoreline City equals the number of public highschool in Shoreline City. The number of private middle school in Shoreline City equals the number of regional medical school in Shoreline City. The number of culinarian school in Oakbridge City equals the total number of schools in Riverton City. The number of culinarian school in Riverton City equals 4 times the total number of schools in Shoreline City. The number of regional medical school in Oakbridge City equals 2.

Question: What is the total number of schools in Oakbridge City?

Solution: Define public highschool in Shoreline City as X; so X = 2. Define regional medical school in Shoreline City as S; so S = X = 2. Define private middle school in Shoreline City as u; so u = S = 2. Define total number of schools in Shoreline City as Q; y = u + X = 2 + 2 = 4; so Q = y + S = 4 + 2 = 6. Define culinarian school in Riverton City as G; z = Q = 6; so G = 4 * z = 4 * 6 = 24. Define total number of schools in Riverton City as s; so s = G = 24. Define culinarian school in Oakbridge City as i; so i = s = 24. Define regional medical school in Oakbridge City as W; so W = 2. Define private middle school in Oakbridge City as T; so T = 3. Define total number of schools in Oakbridge City as w; A = T + W = 3 + 2 = 5; so w = A + i = 5 + 24 = 29. Answer: 29.