The number of calm road movie in Cinéma de Montreval equals 3. The number of solemn period drama in Festival de Clairmont equals 3. The number of solemn period drama in Festival de Saint-Rivage equals the sum of the number of upbeat metropolis comedy in Festival de Saint-Rivage and the total number of movies in Festival de Clairmont. The number of calm road movie in Festival de Clairmont equals 1 plus the number of solemn period drama in Festival de Clairmont. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals 3 plus the total number of movies in Festival de Clairmont. The number of intense detective thriller in Rêves de Belleville equals 4. The number of solemn period drama in Rêves de Belleville equals 3. The number of solemn period drama in Cinéma de Montreval equals 4 times the number of calm road movie in Cinéma de Montreval. The number of calm road movie in Festival de Saint-Rivage equals the number of solemn period drama in Festival de Clairmont. The number of intense detective thriller in Festival de Clairmont equals the number of solemn period drama in Festival de Clairmont.

Question: What is the total number of movies in Festival de Saint-Rivage?

Solution: Define solemn period drama in Festival de Clairmont as A; so A = 3. Define calm road movie in Festival de Clairmont as y; B = A = 3; so y = 1 + B = 1 + 3 = 4. Define intense detective thriller in Festival de Clairmont as v; so v = A = 3. Define total number of movies in Festival de Clairmont as P; a = y + A = 4 + 3 = 7; so P = a + v = 7 + 3 = 10. Define upbeat metropolis comedy in Festival de Saint-Rivage as R; H = P = 10; so R = 3 + H = 3 + 10 = 13. Define solemn period drama in Festival de Saint-Rivage as Y; so Y = R + P = 13 + 10 = 23. Define calm road movie in Festival de Saint-Rivage as V; so V = A = 3. Define total number of movies in Festival de Saint-Rivage as X; W = V + Y = 3 + 23 = 26; so X = W + R = 26 + 13 = 39. Answer: 39.


The number of elementary school in Shoreline City equals 2. The number of public highschool in Clearwater Bay equals the difference between the total number of schools in Riverton City and the number of private middle school in Oakbridge City. The number of public highschool in Riverton City equals 1. The number of private middle school in Shoreline City equals 4. The number of private middle school in Oakbridge City equals 3. The number of culinarian school in Oakbridge City equals the number of public highschool in Riverton City. The number of elementary school in Riverton City equals the number of culinarian school in Oakbridge City. The number of private middle school in Riverton City equals 1 plus the difference between the total number of schools in Oakbridge City and the number of elementary school in Riverton City.

Question: What is the total number of schools in Clearwater Bay?

Solution: Define public highschool in Riverton City as l; so l = 1. Define culinarian school in Oakbridge City as n; so n = l = 1. Define elementary school in Riverton City as e; so e = n = 1. Define private middle school in Oakbridge City as q; so q = 3. Define total number of schools in Oakbridge City as K; so K = q + n = 3 + 1 = 4. Define private middle school in Riverton City as p; r = K - e = 4 - 1 = 3; so p = 1 + r = 1 + 3 = 4. Define total number of schools in Riverton City as Z; Y = e + l = 1 + 1 = 2; so Z = Y + p = 2 + 4 = 6. Define public highschool in Clearwater Bay as g; so g = Z - q = 6 - 3 = 3. Define total number of schools in Clearwater Bay as P; so P = g = 3. Answer: 3.


The number of adult bear in Pine Ridge equals the difference between the total number of adult animals in Oakridge Riverside and the number of adult racoon in Oakridge Riverside. The number of adult racoon in Cedar Valley equals the number of adult bear in Oakridge Riverside. The number of adult bear in Oakridge Riverside equals 4 plus the number of adult racoon in Oakridge Riverside. The number of adult bear in Cedar Valley equals 2 plus the total number of adult animals in Pine Ridge. The number of adult racoon in Pine Ridge equals the number of adult racoon in Oakridge Riverside. The number of adult racoon in Oakridge Riverside equals 1.

Question: What is the total number of adult animals in Cedar Valley?

Solution: Define adult racoon in Oakridge Riverside as Y; so Y = 1. Define adult bear in Oakridge Riverside as A; d = Y = 1; so A = 4 + d = 4 + 1 = 5. Define total number of adult animals in Oakridge Riverside as i; so i = Y + A = 1 + 5 = 6. Define adult racoon in Pine Ridge as g; so g = Y = 1. Define adult bear in Pine Ridge as P; so P = i - Y = 6 - 1 = 5. Define total number of adult animals in Pine Ridge as S; so S = g + P = 1 + 5 = 6. Define adult bear in Cedar Valley as t; s = S = 6; so t = 2 + s = 2 + 6 = 8. Define adult racoon in Cedar Valley as f; so f = A = 5. Define total number of adult animals in Cedar Valley as C; so C = f + t = 5 + 8 = 13. Answer: 13.


The number of calm road movie in Cinéma de Montreval equals the difference between the total number of movies in Festival de Saint-Rivage and the number of intense detective thriller in Festival Lumière de Valmont. The number of solemn period drama in Festival de Saint-Rivage equals 2 times the total number of movies in Rêves de Belleville. The number of intense detective thriller in Festival Lumière de Valmont equals 2. The number of futuristic sci-fi movie in Festival de Clairmont equals the total number of movies in Cinéma de Montreval. The number of calm road movie in Rêves de Belleville equals 3 times the total number of movies in Festival Lumière de Valmont. The number of upbeat metropolis comedy in Festival Lumière de Valmont equals the number of intense detective thriller in Festival Lumière de Valmont.

Question: What is the total number of movies in Festival de Clairmont?

Solution: Define intense detective thriller in Festival Lumière de Valmont as x; so x = 2. Define upbeat metropolis comedy in Festival Lumière de Valmont as H; so H = x = 2. Define total number of movies in Festival Lumière de Valmont as c; so c = H + x = 2 + 2 = 4. Define calm road movie in Rêves de Belleville as w; g = c = 4; so w = 3 * g = 3 * 4 = 12. Define total number of movies in Rêves de Belleville as K; so K = w = 12. Define solemn period drama in Festival de Saint-Rivage as j; f = K = 12; so j = 2 * f = 2 * 12 = 24. Define total number of movies in Festival de Saint-Rivage as Y; so Y = j = 24. Define calm road movie in Cinéma de Montreval as B; so B = Y - x = 24 - 2 = 22. Define total number of movies in Cinéma de Montreval as I; so I = B = 22. Define futuristic sci-fi movie in Festival de Clairmont as P; so P = I = 22. Define total number of movies in Festival de Clairmont as k; so k = P = 22. Answer: 22.


The number of adult bear in Pine Ridge equals 2 times the sum of the total number of adult animals in Cedar Valley, the total number of adult animals in Maple Creek, and the number of adult bear in Maple Creek. The number of adult wolf in Oakridge Riverside equals the number of adult bear in Pine Ridge. The number of adult wolf in Cedar Valley equals the sum of the total number of adult animals in Maple Creek and the number of adult bear in Maple Creek. The number of adult bear in Oakridge Riverside equals 1 plus the total number of adult animals in Pine Ridge. The number of adult bear in Maple Creek equals 2.

Question: What is the total number of adult animals in Oakridge Riverside?

Solution: Define adult bear in Maple Creek as l; so l = 2. Define total number of adult animals in Maple Creek as V; so V = l = 2. Define adult wolf in Cedar Valley as n; so n = V + l = 2 + 2 = 4. Define total number of adult animals in Cedar Valley as F; so F = n = 4. Define adult bear in Pine Ridge as r; g = F + V = 4 + 2 = 6; j = g + l = 6 + 2 = 8; so r = 2 * j = 2 * 8 = 16. Define total number of adult animals in Pine Ridge as m; so m = r = 16. Define adult bear in Oakridge Riverside as q; R = m = 16; so q = 1 + R = 1 + 16 = 17. Define adult wolf in Oakridge Riverside as e; so e = r = 16. Define total number of adult animals in Oakridge Riverside as b; so b = q + e = 17 + 16 = 33. Answer: 33.


The number of adult parrot in Cedar Valley equals 4 times the total number of adult animals in Oakridge Riverside. The number of adult parrot in Oakridge Riverside equals 1. The number of adult owl in Oakridge Riverside equals 1 plus the number of adult parrot in Oakridge Riverside. The number of adult owl in Cedar Valley equals 2 plus the number of adult crow in Oakridge Riverside. The number of adult crow in Oakridge Riverside equals 4 times the difference between the number of adult owl in Oakridge Riverside and the number of adult parrot in Oakridge Riverside.

Question: What is the total number of adult animals in Cedar Valley?

Solution: Define adult parrot in Oakridge Riverside as o; so o = 1. Define adult owl in Oakridge Riverside as T; a = o = 1; so T = 1 + a = 1 + 1 = 2. Define adult crow in Oakridge Riverside as i; W = T - o = 2 - 1 = 1; so i = 4 * W = 4 * 1 = 4. Define total number of adult animals in Oakridge Riverside as J; h = i + o = 4 + 1 = 5; so J = h + T = 5 + 2 = 7. Define adult parrot in Cedar Valley as K; w = J = 7; so K = 4 * w = 4 * 7 = 28. Define adult owl in Cedar Valley as x; U = i = 4; so x = 2 + U = 2 + 4 = 6. Define total number of adult animals in Cedar Valley as r; so r = K + x = 28 + 6 = 34. Answer: 34.


The number of adult fox in Hamilton Farm equals the difference between the total number of adult animals in Mayer Aquarium and the number of adult deer in Mayer Aquarium. The number of adult deer in Mayer Aquarium equals 3 times the sum of the number of adult fox in Mayer Aquarium and the number of adult bear in Hamilton Farm. The number of adult bear in Hamilton Farm equals 2. The number of adult fox in Mayer Aquarium equals 2 times the number of adult bear in Hamilton Farm. The number of adult deer in Hamilton Farm equals 2. The number of adult deer in South Zoo equals the number of adult fox in Hamilton Farm. The number of adult bear in South Zoo equals 3. The number of adult bear in Mayer Aquarium equals 3 times the sum of the number of adult deer in Mayer Aquarium, the number of adult bear in Hamilton Farm, and the number of adult fox in Mayer Aquarium. The number of adult fox in South Zoo equals the number of adult deer in Mayer Aquarium.

Question: How many adult fox does Hamilton Farm have?

Solution: Define adult bear in Hamilton Farm as C; so C = 2. Define adult fox in Mayer Aquarium as z; y = C = 2; so z = 2 * y = 2 * 2 = 4. Define adult deer in Mayer Aquarium as e; n = z + C = 4 + 2 = 6; so e = 3 * n = 3 * 6 = 18. Define adult bear in Mayer Aquarium as Q; m = e + C = 18 + 2 = 20; J = m + z = 20 + 4 = 24; so Q = 3 * J = 3 * 24 = 72. Define total number of adult animals in Mayer Aquarium as V; f = z + e = 4 + 18 = 22; so V = f + Q = 22 + 72 = 94. Define adult fox in Hamilton Farm as N; so N = V - e = 94 - 18 = 76. Answer: 76.


The number of elementary school in Glenfield City equals 2. The number of private middle school in Brightford equals the total number of schools in Hawkesbury. The number of elementary school in Hawkesbury equals 3 plus the number of private middle school in Hawkesbury. The number of elementary school in Westhaven City equals the number of private middle school in Hawkesbury. The number of private middle school in Hawkesbury equals 2. The number of private middle school in Glenfield City equals 4 times the number of elementary school in Glenfield City. The number of elementary school in Brightford equals 2 plus the number of private middle school in Brightford. The number of private middle school in Westhaven City equals 2 times the total number of schools in Brightford.

Question: What is the total number of schools in Westhaven City?

Solution: Define private middle school in Hawkesbury as l; so l = 2. Define elementary school in Hawkesbury as q; O = l = 2; so q = 3 + O = 3 + 2 = 5. Define total number of schools in Hawkesbury as B; so B = l + q = 2 + 5 = 7. Define private middle school in Brightford as a; so a = B = 7. Define elementary school in Brightford as c; p = a = 7; so c = 2 + p = 2 + 7 = 9. Define total number of schools in Brightford as u; so u = a + c = 7 + 9 = 16. Define private middle school in Westhaven City as x; W = u = 16; so x = 2 * W = 2 * 16 = 32. Define elementary school in Westhaven City as T; so T = l = 2. Define total number of schools in Westhaven City as V; so V = x + T = 32 + 2 = 34. Answer: 34.


The number of calm road movie in Northwood Movie Festival equals 2 plus the total number of movies in West Sahara Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals 2. The number of intense detective thriller in Taylor Movie Festival equals 2 times the total number of movies in Northwood Movie Festival. The number of futuristic sci-fi movie in West Sahara Movie Festival equals 2. The number of intense detective thriller in West Sahara Movie Festival equals 4 plus the total number of movies in Golden Banana Movie Festival. The number of upbeat metropolis comedy in Verdi Movie Festival equals the total number of movies in Taylor Movie Festival.

Question: What is the total number of movies in Verdi Movie Festival?

Solution: Define solemn period drama in Golden Banana Movie Festival as T; so T = 2. Define total number of movies in Golden Banana Movie Festival as h; so h = T = 2. Define intense detective thriller in West Sahara Movie Festival as o; I = h = 2; so o = 4 + I = 4 + 2 = 6. Define futuristic sci-fi movie in West Sahara Movie Festival as W; so W = 2. Define total number of movies in West Sahara Movie Festival as J; so J = W + o = 2 + 6 = 8. Define calm road movie in Northwood Movie Festival as B; m = J = 8; so B = 2 + m = 2 + 8 = 10. Define total number of movies in Northwood Movie Festival as S; so S = B = 10. Define intense detective thriller in Taylor Movie Festival as Q; y = S = 10; so Q = 2 * y = 2 * 10 = 20. Define total number of movies in Taylor Movie Festival as d; so d = Q = 20. Define upbeat metropolis comedy in Verdi Movie Festival as t; so t = d = 20. Define total number of movies in Verdi Movie Festival as c; so c = t = 20. Answer: 20.