The total number of movies in Northwood Movie Festival equals 63. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 1 plus the number of upbeat metropolis comedy in Verdi Movie Festival. The number of futuristic sci-fi movie in Northwood Movie Festival equals the number of upbeat metropolis comedy in Golden Banana Movie Festival. The number of upbeat metropolis comedy in Verdi Movie Festival equals the difference between the number of solemn period drama in Golden Banana Movie Festival and the number of futuristic sci-fi movie in Golden Banana Movie Festival. The number of upbeat metropolis comedy in Northwood Movie Festival equals the number of solemn period drama in Northwood Movie Festival. The number of solemn period drama in Northwood Movie Festival equals 4 times the number of upbeat metropolis comedy in Golden Banana Movie Festival. The number of futuristic sci-fi movie in Golden Banana Movie Festival exists, and its number is greater than 0. The number of solemn period drama in Golden Banana Movie Festival equals the number of solemn period drama in Verdi Movie Festival. The number of solemn period drama in Verdi Movie Festival equals 3 times the number of futuristic sci-fi movie in Golden Banana Movie Festival.

Question: How many futuristic sci-fi movie does Golden Banana Movie Festival have?

Solution: The question is difficult, so we use equations to solve it. Define futuristic sci-fi movie in Golden Banana Movie Festival as x; we don't know its value yet but will find it out later. Define solemn period drama in Verdi Movie Festival as M; Z = x = x; so M = 3 * Z = (3) * (x) = 3*x. Define solemn period drama in Golden Banana Movie Festival as d; so d = M = 3*x. Define upbeat metropolis comedy in Verdi Movie Festival as u; so u = d - x = (3*x) - (x) = 2*x. Define upbeat metropolis comedy in Golden Banana Movie Festival as D; L = u = 2*x; so D = 1 + L = 1 + 2*x = 2*x + 1. Define futuristic sci-fi movie in Northwood Movie Festival as C; so C = D = 2*x + 1. Define solemn period drama in Northwood Movie Festival as w; j = D = 2*x + 1; so w = 4 * j = (4) * (2*x + 1) = 8*x + 4. Define upbeat metropolis comedy in Northwood Movie Festival as J; so J = w = 8*x + 4. Define total number of movies in Northwood Movie Festival as V; O = C + J = 2*x + 1 + 8*x + 4 = 10*x + 5; so V = O + w = 10*x + 5 + 8*x + 4 = 18*x + 9. We know V = 63, so we have 18*x + 9 = 63 and we solve it through the following steps: Simplifying the equation: 18*x + 9 = 63. Move all terms to one side: 18*x - 54 = 0. Isolate the term with x: 18*x = 54. Divide both sides by 18: x = 54 / 18. Solution: x = 3. Answer: 3.


The number of adult fox in Jefferson Circus equals the sum of the number of adult fox in South Zoo and the number of adult wolf in Jefferson Circus. The number of adult bear in South Zoo exists, and its number is greater than 0. The number of adult fox in South Zoo equals the sum of the number of adult fox in Bundle Ranch, the number of adult wolf in Jefferson Circus, and the number of adult bear in South Zoo. The number of adult bear in Jefferson Circus equals 3 plus the number of adult wolf in South Zoo. The number of adult fox in Bundle Ranch equals the number of adult wolf in Jefferson Circus. The number of adult wolf in Bundle Ranch equals 3 plus the number of adult bear in Jefferson Circus. The number of adult bear in Bundle Ranch equals 4. The number of adult wolf in South Zoo equals 4 times the difference between the number of adult fox in Jefferson Circus and the number of adult fox in Bundle Ranch. The number of adult wolf in Jefferson Circus equals the number of adult bear in South Zoo. The number of adult wolf in Bundle Ranch equals 54.

Question: How many adult bear does South Zoo have?

Solution: The question is difficult, so we use equations to solve it. Define adult bear in South Zoo as x; we don't know its value yet but will find it out later. Define adult wolf in Jefferson Circus as g; so g = x = x. Define adult fox in Bundle Ranch as s; so s = g = x. Define adult fox in South Zoo as R; I = s + g = x + x = 2*x; so R = I + x = 2*x + x = 3*x. Define adult fox in Jefferson Circus as U; so U = R + g = 3*x + x = 4*x. Define adult wolf in South Zoo as d; j = U - s = (4*x) - (x) = 3*x; so d = 4 * j = (4) * (3*x) = 12*x. Define adult bear in Jefferson Circus as y; S = d = 12*x; so y = 3 + S = 3 + 12*x = 12*x + 3. Define adult wolf in Bundle Ranch as r; E = y = 12*x + 3; so r = 3 + E = 3 + 12*x + 3 = 12*x + 6. We know r = 54, so we have 12*x + 6 = 54 and we solve it through the following steps: Simplifying the equation: 12*x + 6 = 54. Move all terms to one side: 12*x - 48 = 0. Isolate the term with x: 12*x = 48. Divide both sides by 12: x = 48 / 12. Solution: x = 4. Answer: 4.


The number of adult parrot in Hamilton Farm equals 4 times the number of adult owl in Hamilton Farm. The number of adult parrot in South Zoo equals the sum of the number of adult eagle in Bundle Ranch, the number of adult eagle in Hamilton Farm, and the number of adult crow in South Zoo. The number of adult eagle in Bundle Ranch equals the difference between the total number of adult animals in Hamilton Farm and the number of adult eagle in Hamilton Farm. The number of adult eagle in Hamilton Farm equals the sum of the number of adult owl in Hamilton Farm and the number of adult parrot in Hamilton Farm. The number of adult crow in Jefferson Circus equals 2. The number of adult crow in Bundle Ranch equals 4 times the number of adult eagle in Bundle Ranch. The number of adult owl in Jefferson Circus equals 3. The number of adult parrot in Bundle Ranch equals 4. The number of adult parrot in Jefferson Circus equals 4 plus the number of adult parrot in Hamilton Farm. The number of adult owl in Hamilton Farm equals 4 plus the number of adult crow in South Zoo. The number of adult owl in South Zoo equals the number of adult owl in Jefferson Circus. The number of adult crow in South Zoo equals 2. The number of adult eagle in Jefferson Circus equals the number of adult crow in Jefferson Circus. The number of adult eagle in South Zoo equals 2.

Question: How many adult parrot does South Zoo have?

Solution: Define adult crow in South Zoo as V; so V = 2. Define adult owl in Hamilton Farm as Y; l = V = 2; so Y = 4 + l = 4 + 2 = 6. Define adult parrot in Hamilton Farm as L; H = Y = 6; so L = 4 * H = 4 * 6 = 24. Define adult eagle in Hamilton Farm as w; so w = Y + L = 6 + 24 = 30. Define total number of adult animals in Hamilton Farm as g; q = L + w = 24 + 30 = 54; so g = q + Y = 54 + 6 = 60. Define adult eagle in Bundle Ranch as a; so a = g - w = 60 - 30 = 30. Define adult parrot in South Zoo as c; J = a + w = 30 + 30 = 60; so c = J + V = 60 + 2 = 62. Answer: 62.


The number of adult fox in Pine Ridge equals 2. The number of adult wolf in Pine Ridge equals the sum of the total number of adult animals in Oakridge Riverside, the number of adult bear in Beverly Forest, and the number of adult fox in Oakridge Riverside. The number of adult bear in Beverly Forest equals 2. The number of adult fox in Oakridge Riverside equals 4 plus the number of adult bear in Beverly Forest. The number of adult wolf in Beverly Forest equals 2 plus the total number of adult animals in Maple Creek. The number of adult fox in Beverly Forest equals 2. The number of adult racoon in Maple Creek equals 3 plus the total number of adult animals in Pine Ridge.

Question: How many adult wolf does Beverly Forest have?

Solution: Define adult bear in Beverly Forest as g; so g = 2. Define adult fox in Oakridge Riverside as J; A = g = 2; so J = 4 + A = 4 + 2 = 6. Define total number of adult animals in Oakridge Riverside as S; so S = J = 6. Define adult wolf in Pine Ridge as l; O = S + g = 6 + 2 = 8; so l = O + J = 8 + 6 = 14. Define adult fox in Pine Ridge as R; so R = 2. Define total number of adult animals in Pine Ridge as d; so d = R + l = 2 + 14 = 16. Define adult racoon in Maple Creek as c; y = d = 16; so c = 3 + y = 3 + 16 = 19. Define total number of adult animals in Maple Creek as i; so i = c = 19. Define adult wolf in Beverly Forest as L; E = i = 19; so L = 2 + E = 2 + 19 = 21. Answer: 21.


The number of futuristic sci-fi movie in Festival Lumière de Valmont equals the number of calm road movie in Festival de Saint-Rivage. The number of calm road movie in Festival de Saint-Rivage equals 4. The number of calm road movie in Festival Lumière de Valmont equals 2 plus the number of solemn period drama in Festival de Saint-Rivage. The total number of movies in Rêves de Belleville equals 86. The number of futuristic sci-fi movie in Rêves de Belleville equals the number of solemn period drama in Festival de Saint-Rivage. The number of solemn period drama in Festival Lumière de Valmont equals 3 plus the number of calm road movie in Festival Lumière de Valmont. The number of solemn period drama in Festival de Saint-Rivage equals the number of futuristic sci-fi movie in Festival de Saint-Rivage. The number of calm road movie in Rêves de Belleville equals the sum of the number of futuristic sci-fi movie in Festival de Saint-Rivage, the number of solemn period drama in Rêves de Belleville, and the number of calm road movie in Festival Lumière de Valmont. The number of futuristic sci-fi movie in Festival de Saint-Rivage exists, and its number is greater than 0. The number of solemn period drama in Rêves de Belleville equals 4 times the number of solemn period drama in Festival Lumière de Valmont.

Question: How many futuristic sci-fi movie does Festival de Saint-Rivage have?

Solution: The question is difficult, so we use equations to solve it. Define futuristic sci-fi movie in Festival de Saint-Rivage as x; we don't know its value yet but will find it out later. Define solemn period drama in Festival de Saint-Rivage as s; so s = x = x. Define calm road movie in Festival Lumière de Valmont as U; W = s = x; so U = 2 + W = 2 + x = x + 2. Define solemn period drama in Festival Lumière de Valmont as h; c = U = x + 2; so h = 3 + c = 3 + x + 2 = x + 5. Define solemn period drama in Rêves de Belleville as w; L = h = x + 5; so w = 4 * L = (4) * (x + 5) = 4*x + 20. Define calm road movie in Rêves de Belleville as Y; H = x + w = x + 4*x + 20 = 5*x + 20; so Y = H + U = 5*x + 20 + x + 2 = 6*x + 22. Define futuristic sci-fi movie in Rêves de Belleville as j; so j = s = x. Define total number of movies in Rêves de Belleville as b; f = j + Y = x + 6*x + 22 = 7*x + 22; so b = f + w = 7*x + 22 + 4*x + 20 = 11*x + 42. We know b = 86, so we have 11*x + 42 = 86 and we solve it through the following steps: Simplifying the equation: 11*x + 42 = 86. Move all terms to one side: 11*x - 44 = 0. Isolate the term with x: 11*x = 44. Divide both sides by 11: x = 44 / 11. Solution: x = 4. Answer: 4.


The number of adult racoon in Beverly Forest exists, and its number is greater than 0. The total number of adult animals in Pine Ridge equals 42. The number of adult racoon in Oakridge Riverside equals 3 plus the total number of adult animals in Beverly Forest. The number of adult bear in Pine Ridge equals 3 times the difference between the total number of adult animals in Oakridge Riverside and the number of adult racoon in Beverly Forest. The number of adult racoon in Pine Ridge equals 2 plus the sum of the total number of adult animals in Oakridge Riverside and the total number of adult animals in Beverly Forest. The number of adult wolf in Beverly Forest equals 4.

Question: How many adult racoon does Beverly Forest have?

Solution: The question is difficult, so we use equations to solve it. Define adult wolf in Beverly Forest as l; so l = 4. Define adult racoon in Beverly Forest as x; we don't know its value yet but will find it out later. Define total number of adult animals in Beverly Forest as T; so T = l + x = 4 + x = x + 4. Define adult racoon in Oakridge Riverside as e; N = T = x + 4; so e = 3 + N = 3 + x + 4 = x + 7. Define total number of adult animals in Oakridge Riverside as k; so k = e = x + 7. Define adult bear in Pine Ridge as C; R = k - x = (x + 7) - (x) = 7; so C = 3 * R = (3) * (7) = 21. Define adult racoon in Pine Ridge as q; i = k + T = x + 7 + x + 4 = 2*x + 11; so q = 2 + i = 2 + 2*x + 11 = 2*x + 13. Define total number of adult animals in Pine Ridge as A; so A = q + C = 2*x + 13 + 21 = 2*x + 34. We know A = 42, so we have 2*x + 34 = 42 and we solve it through the following steps: Simplifying the equation: 2*x + 34 = 42. Move all terms to one side: 2*x - 8 = 0. Isolate the term with x: 2*x = 8. Divide both sides by 2: x = 8 / 2. Solution: x = 4. Answer: 4.