The number of upbeat metropolis comedy in Rêves de Belleville equals 4 times the sum of the total number of movies in Festival de Clairmont, the number of upbeat metropolis comedy in Festival de Clairmont, and the number of solemn period drama in Festival de Clairmont. The number of solemn period drama in Festival de Clairmont equals 4 plus the number of upbeat metropolis comedy in Festival de Clairmont. The number of upbeat metropolis comedy in Festival de Clairmont equals 2.

Question: What is the total number of movies in Rêves de Belleville?

Solution: Define upbeat metropolis comedy in Festival de Clairmont as M; so M = 2. Define solemn period drama in Festival de Clairmont as A; Z = M = 2; so A = 4 + Z = 4 + 2 = 6. Define total number of movies in Festival de Clairmont as Y; so Y = M + A = 2 + 6 = 8. Define upbeat metropolis comedy in Rêves de Belleville as v; G = Y + M = 8 + 2 = 10; u = G + A = 10 + 6 = 16; so v = 4 * u = 4 * 16 = 64. Define total number of movies in Rêves de Belleville as a; so a = v = 64. Answer: 64.


The number of calm road movie in Golden Banana Movie Festival equals 2 plus the difference between the total number of movies in West Sahara Movie Festival and the number of solemn period drama in West Sahara Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals the number of solemn period drama in West Sahara Movie Festival. The number of calm road movie in West Sahara Movie Festival equals the number of solemn period drama in West Sahara Movie Festival. The number of solemn period drama in West Sahara Movie Festival equals 3.

Question: What is the total number of movies in Golden Banana Movie Festival?

Solution: Define solemn period drama in West Sahara Movie Festival as o; so o = 3. Define calm road movie in West Sahara Movie Festival as m; so m = o = 3. Define total number of movies in West Sahara Movie Festival as J; so J = o + m = 3 + 3 = 6. Define calm road movie in Golden Banana Movie Festival as C; F = J - o = 6 - 3 = 3; so C = 2 + F = 2 + 3 = 5. Define solemn period drama in Golden Banana Movie Festival as Z; so Z = o = 3. Define total number of movies in Golden Banana Movie Festival as w; so w = Z + C = 3 + 5 = 8. Answer: 8.


The number of public highschool in Clearwater Bay equals the total number of schools in Ruby Bay. The number of public highschool in Ruby Bay equals the sum of the number of private middle school in Ruby Bay and the number of private middle school in Oakbridge City. The number of public highschool in Oakbridge City equals 2. The number of public highschool in Riverton City equals the sum of the number of private middle school in Ruby Bay and the number of regional medical school in Ruby Bay. The number of regional medical school in Oakbridge City equals the difference between the number of public highschool in Oakbridge City and the number of private middle school in Riverton City. The number of regional medical school in Riverton City equals the difference between the number of public highschool in Ruby Bay and the number of private middle school in Oakbridge City. The number of regional medical school in Ruby Bay equals 1 plus the number of private middle school in Ruby Bay. The number of regional medical school in Clearwater Bay equals 2. The number of private middle school in Riverton City equals the number of public highschool in Oakbridge City. The number of private middle school in Oakbridge City equals 4. The number of private middle school in Ruby Bay equals 4 times the number of private middle school in Oakbridge City.

Question: What is the total number of schools in Ruby Bay?

Solution: Define private middle school in Oakbridge City as i; so i = 4. Define private middle school in Ruby Bay as z; q = i = 4; so z = 4 * q = 4 * 4 = 16. Define regional medical school in Ruby Bay as C; g = z = 16; so C = 1 + g = 1 + 16 = 17. Define public highschool in Ruby Bay as b; so b = z + i = 16 + 4 = 20. Define total number of schools in Ruby Bay as T; F = z + C = 16 + 17 = 33; so T = F + b = 33 + 20 = 53. Answer: 53.


The number of adult deer in Oakridge Riverside equals 3 times the sum of the total number of adult animals in Pine Ridge, the number of adult racoon in Pine Ridge, and the number of adult deer in Pine Ridge. The number of adult racoon in Pine Ridge equals 3. The number of adult deer in Maple Creek equals the number of adult wolf in Cedar Valley. The number of adult bear in Beverly Forest equals 2 plus the sum of the total number of adult animals in Oakridge Riverside and the total number of adult animals in Pine Ridge. The number of adult fox in Cedar Valley equals the number of adult wolf in Cedar Valley. The number of adult wolf in Maple Creek equals 1 plus the sum of the total number of adult animals in Maple Creek, the total number of adult animals in Oakridge Riverside, and the number of adult deer in Oakridge Riverside. The number of adult wolf in Cedar Valley equals 1. The number of adult deer in Pine Ridge equals 2 times the number of adult racoon in Pine Ridge.

Question: What is the total number of adult animals in Oakridge Riverside?

Solution: Define adult racoon in Pine Ridge as G; so G = 3. Define adult deer in Pine Ridge as E; y = G = 3; so E = 2 * y = 2 * 3 = 6. Define total number of adult animals in Pine Ridge as x; so x = E + G = 6 + 3 = 9. Define adult deer in Oakridge Riverside as d; k = x + G = 9 + 3 = 12; q = k + E = 12 + 6 = 18; so d = 3 * q = 3 * 18 = 54. Define total number of adult animals in Oakridge Riverside as M; so M = d = 54. Answer: 54.


The number of public highschool in Clearwater Bay equals the total number of schools in Oakbridge City. The number of regional medical school in Oakbridge City equals 2. The number of culinarian school in Oakbridge City equals the number of regional medical school in Oakbridge City. The number of public highschool in Oakbridge City equals the number of regional medical school in Oakbridge City. The number of culinarian school in Clearwater Bay equals the number of public highschool in Oakbridge City.

Question: What is the total number of schools in Clearwater Bay?

Solution: Define regional medical school in Oakbridge City as n; so n = 2. Define public highschool in Oakbridge City as e; so e = n = 2. Define culinarian school in Clearwater Bay as q; so q = e = 2. Define culinarian school in Oakbridge City as S; so S = n = 2. Define total number of schools in Oakbridge City as J; v = e + S = 2 + 2 = 4; so J = v + n = 4 + 2 = 6. Define public highschool in Clearwater Bay as c; so c = J = 6. Define total number of schools in Clearwater Bay as N; so N = q + c = 2 + 6 = 8. Answer: 8.


The number of adult bear in Mayer Aquarium equals 3. The number of adult bear in Hamilton Farm equals the number of adult wolf in Bundle Ranch. The number of adult fox in Mayer Aquarium equals 3 times the sum of the total number of adult animals in Hamilton Farm and the number of adult wolf in Hamilton Farm. The number of adult wolf in Mayer Aquarium equals 2 plus the number of adult bear in Mayer Aquarium. The number of adult wolf in Bundle Ranch equals 3. The number of adult wolf in Hamilton Farm equals 4 plus the difference between the number of adult bear in Hamilton Farm and the number of adult wolf in Bundle Ranch. The number of adult fox in Bundle Ranch equals the difference between the number of adult wolf in Mayer Aquarium and the number of adult bear in Mayer Aquarium.

Question: How many adult fox does Mayer Aquarium have?

Solution: Define adult wolf in Bundle Ranch as h; so h = 3. Define adult bear in Hamilton Farm as A; so A = h = 3. Define adult wolf in Hamilton Farm as z; X = A - h = 3 - 3 = 0; so z = 4 + X = 4 + 0 = 4. Define total number of adult animals in Hamilton Farm as c; so c = A + z = 3 + 4 = 7. Define adult fox in Mayer Aquarium as S; F = c + z = 7 + 4 = 11; so S = 3 * F = 3 * 11 = 33. Answer: 33.


The number of culinarian school in Clearwater Bay equals 1 plus the sum of the total number of schools in Oakbridge City, the number of culinarian school in Oakbridge City, and the number of public highschool in Oakbridge City. The number of culinarian school in Oakbridge City equals 1. The number of public highschool in Oakbridge City equals 4 plus the number of culinarian school in Oakbridge City.

Question: What is the total number of schools in Clearwater Bay?

Solution: Define culinarian school in Oakbridge City as y; so y = 1. Define public highschool in Oakbridge City as o; P = y = 1; so o = 4 + P = 4 + 1 = 5. Define total number of schools in Oakbridge City as a; so a = y + o = 1 + 5 = 6. Define culinarian school in Clearwater Bay as S; j = a + y = 6 + 1 = 7; k = j + o = 7 + 5 = 12; so S = 1 + k = 1 + 12 = 13. Define total number of schools in Clearwater Bay as s; so s = S = 13. Answer: 13.


The number of regional medical school in Clearwater Bay equals 2. The number of private middle school in Riverton City equals the number of elementary school in Riverton City. The number of elementary school in Clearwater Bay equals the total number of schools in Riverton City. The number of elementary school in Riverton City equals 1. The number of private middle school in Clearwater Bay equals 2.

Question: What is the total number of schools in Clearwater Bay?

Solution: Define elementary school in Riverton City as c; so c = 1. Define private middle school in Riverton City as V; so V = c = 1. Define total number of schools in Riverton City as d; so d = c + V = 1 + 1 = 2. Define regional medical school in Clearwater Bay as k; so k = 2. Define elementary school in Clearwater Bay as o; so o = d = 2. Define private middle school in Clearwater Bay as B; so B = 2. Define total number of schools in Clearwater Bay as u; b = o + B = 2 + 2 = 4; so u = b + k = 4 + 2 = 6. Answer: 6.


The number of culinarian school in Ruby Bay equals 1 plus the total number of schools in Shoreline City. The number of elementary school in Ruby Bay equals 2 times the sum of the number of elementary school in Shoreline City, the total number of schools in Shoreline City, and the number of culinarian school in Ruby Bay. The number of elementary school in Shoreline City equals 4.

Question: What is the total number of schools in Ruby Bay?

Solution: Define elementary school in Shoreline City as H; so H = 4. Define total number of schools in Shoreline City as G; so G = H = 4. Define culinarian school in Ruby Bay as D; Z = G = 4; so D = 1 + Z = 1 + 4 = 5. Define elementary school in Ruby Bay as A; M = H + G = 4 + 4 = 8; w = M + D = 8 + 5 = 13; so A = 2 * w = 2 * 13 = 26. Define total number of schools in Ruby Bay as U; so U = D + A = 5 + 26 = 31. Answer: 31.


The number of culinarian school in Riverton City equals 3. The number of elementary school in Riverton City equals 3 plus the number of culinarian school in Riverton City. The number of elementary school in Ruby Bay equals 4 plus the sum of the total number of schools in Riverton City, the number of culinarian school in Riverton City, and the number of elementary school in Riverton City.

Question: What is the total number of schools in Ruby Bay?

Solution: Define culinarian school in Riverton City as u; so u = 3. Define elementary school in Riverton City as H; b = u = 3; so H = 3 + b = 3 + 3 = 6. Define total number of schools in Riverton City as r; so r = H + u = 6 + 3 = 9. Define elementary school in Ruby Bay as T; k = r + u = 9 + 3 = 12; x = k + H = 12 + 6 = 18; so T = 4 + x = 4 + 18 = 22. Define total number of schools in Ruby Bay as c; so c = T = 22. Answer: 22.


The number of adult owl in South Zoo equals 2 plus the sum of the total number of adult animals in Bundle Ranch, the number of adult crow in South Zoo, and the number of adult owl in Bundle Ranch. The number of adult owl in Bundle Ranch equals 3 plus the number of adult crow in South Zoo. The number of adult crow in South Zoo equals 2.

Question: What is the total number of adult animals in South Zoo?

Solution: Define adult crow in South Zoo as f; so f = 2. Define adult owl in Bundle Ranch as k; z = f = 2; so k = 3 + z = 3 + 2 = 5. Define total number of adult animals in Bundle Ranch as a; so a = k = 5. Define adult owl in South Zoo as D; P = a + f = 5 + 2 = 7; K = P + k = 7 + 5 = 12; so D = 2 + K = 2 + 12 = 14. Define total number of adult animals in South Zoo as U; so U = D + f = 14 + 2 = 16. Answer: 16.


The number of adult racoon in Mayer Aquarium equals the sum of the total number of adult animals in South Zoo, the number of adult racoon in Jefferson Circus, and the number of adult racoon in South Zoo. The number of adult racoon in Bundle Ranch equals the sum of the number of adult racoon in Mayer Aquarium and the total number of adult animals in Jefferson Circus. The number of adult racoon in Jefferson Circus equals 1. The number of adult racoon in South Zoo equals 3 plus the sum of the total number of adult animals in Jefferson Circus and the number of adult racoon in Jefferson Circus.

Question: What is the total number of adult animals in Mayer Aquarium?

Solution: Define adult racoon in Jefferson Circus as C; so C = 1. Define total number of adult animals in Jefferson Circus as a; so a = C = 1. Define adult racoon in South Zoo as S; M = a + C = 1 + 1 = 2; so S = 3 + M = 3 + 2 = 5. Define total number of adult animals in South Zoo as s; so s = S = 5. Define adult racoon in Mayer Aquarium as x; E = s + C = 5 + 1 = 6; so x = E + S = 6 + 5 = 11. Define total number of adult animals in Mayer Aquarium as c; so c = x = 11. Answer: 11.