The number of culinarian school in Oakbridge City equals 3. The number of culinarian school in Clearwater Bay equals the sum of the total number of schools in Oakbridge City and the number of private middle school in Oakbridge City. The number of private middle school in Clearwater Bay equals the sum of the number of private middle school in Oakbridge City and the total number of schools in Oakbridge City. The number of private middle school in Oakbridge City equals 2.

Question: What is the total number of schools in Clearwater Bay?

Solution: Define private middle school in Oakbridge City as T; so T = 2. Define culinarian school in Oakbridge City as o; so o = 3. Define total number of schools in Oakbridge City as F; so F = T + o = 2 + 3 = 5. Define culinarian school in Clearwater Bay as G; so G = F + T = 5 + 2 = 7. Define private middle school in Clearwater Bay as d; so d = T + F = 2 + 5 = 7. Define total number of schools in Clearwater Bay as B; so B = d + G = 7 + 7 = 14. Answer: 14.


The number of private middle school in Clearwater Bay equals 3. The number of culinarian school in Clearwater Bay equals 3 plus the number of private middle school in Clearwater Bay. The number of culinarian school in Shoreline City equals 2 times the sum of the total number of schools in Clearwater Bay, the number of private middle school in Clearwater Bay, and the number of culinarian school in Clearwater Bay.

Question: What is the total number of schools in Shoreline City?

Solution: Define private middle school in Clearwater Bay as t; so t = 3. Define culinarian school in Clearwater Bay as O; a = t = 3; so O = 3 + a = 3 + 3 = 6. Define total number of schools in Clearwater Bay as p; so p = O + t = 6 + 3 = 9. Define culinarian school in Shoreline City as A; X = p + t = 9 + 3 = 12; I = X + O = 12 + 6 = 18; so A = 2 * I = 2 * 18 = 36. Define total number of schools in Shoreline City as P; so P = A = 36. Answer: 36.


The number of regional medical school in Ruby Bay equals 3 plus the sum of the total number of schools in Clearwater Bay, the number of regional medical school in Clearwater Bay, and the number of public highschool in Clearwater Bay. The number of public highschool in Clearwater Bay equals 2 plus the number of regional medical school in Clearwater Bay. The number of regional medical school in Clearwater Bay equals 4.

Question: What is the total number of schools in Ruby Bay?

Solution: Define regional medical school in Clearwater Bay as Q; so Q = 4. Define public highschool in Clearwater Bay as M; b = Q = 4; so M = 2 + b = 2 + 4 = 6. Define total number of schools in Clearwater Bay as r; so r = M + Q = 6 + 4 = 10. Define regional medical school in Ruby Bay as X; h = r + Q = 10 + 4 = 14; Z = h + M = 14 + 6 = 20; so X = 3 + Z = 3 + 20 = 23. Define total number of schools in Ruby Bay as s; so s = X = 23. Answer: 23.


The number of solemn period drama in Northwood Movie Festival equals the total number of movies in Verdi Movie Festival. The number of upbeat metropolis comedy in Verdi Movie Festival equals 2 plus the sum of the total number of movies in West Sahara Movie Festival and the number of solemn period drama in West Sahara Movie Festival. The number of futuristic sci-fi movie in Verdi Movie Festival equals the number of solemn period drama in West Sahara Movie Festival. The number of solemn period drama in West Sahara Movie Festival equals 3.

Question: What is the total number of movies in Northwood Movie Festival?

Solution: Define solemn period drama in West Sahara Movie Festival as Z; so Z = 3. Define total number of movies in West Sahara Movie Festival as A; so A = Z = 3. Define upbeat metropolis comedy in Verdi Movie Festival as z; S = A + Z = 3 + 3 = 6; so z = 2 + S = 2 + 6 = 8. Define futuristic sci-fi movie in Verdi Movie Festival as C; so C = Z = 3. Define total number of movies in Verdi Movie Festival as p; so p = z + C = 8 + 3 = 11. Define solemn period drama in Northwood Movie Festival as D; so D = p = 11. Define total number of movies in Northwood Movie Festival as K; so K = D = 11. Answer: 11.


The number of public highschool in Oakbridge City equals 4. The number of public highschool in Clearwater Bay equals 2. The number of culinarian school in Riverton City equals 4. The number of public highschool in Ruby Bay equals the total number of schools in Riverton City. The number of regional medical school in Ruby Bay equals 4 plus the difference between the total number of schools in Oakbridge City and the number of public highschool in Oakbridge City. The number of elementary school in Clearwater Bay equals the difference between the total number of schools in Ruby Bay and the number of public highschool in Oakbridge City. The number of culinarian school in Clearwater Bay equals 4.

Question: What is the total number of schools in Ruby Bay?

Solution: Define public highschool in Oakbridge City as y; so y = 4. Define total number of schools in Oakbridge City as u; so u = y = 4. Define regional medical school in Ruby Bay as S; s = u - y = 4 - 4 = 0; so S = 4 + s = 4 + 0 = 4. Define culinarian school in Riverton City as U; so U = 4. Define total number of schools in Riverton City as v; so v = U = 4. Define public highschool in Ruby Bay as f; so f = v = 4. Define total number of schools in Ruby Bay as P; so P = f + S = 4 + 4 = 8. Answer: 8.


The number of culinarian school in Oakbridge City equals the sum of the total number of schools in Ruby Bay and the number of elementary school in Ruby Bay. The number of culinarian school in Riverton City equals the sum of the total number of schools in Oakbridge City, the number of culinarian school in Oakbridge City, the number of elementary school in Ruby Bay, and the total number of schools in Ruby Bay. The number of elementary school in Ruby Bay equals 4.

Question: What is the total number of schools in Riverton City?

Solution: Define elementary school in Ruby Bay as p; so p = 4. Define total number of schools in Ruby Bay as h; so h = p = 4. Define culinarian school in Oakbridge City as f; so f = h + p = 4 + 4 = 8. Define total number of schools in Oakbridge City as y; so y = f = 8. Define culinarian school in Riverton City as M; X = y + f = 8 + 8 = 16; l = X + p = 16 + 4 = 20; so M = l + h = 20 + 4 = 24. Define total number of schools in Riverton City as D; so D = M = 24. Answer: 24.


The number of regional medical school in Shoreline City equals 2. The number of public highschool in Oakbridge City equals 3 times the sum of the total number of schools in Shoreline City and the number of regional medical school in Shoreline City. The number of culinarian school in Ruby Bay equals 2 times the sum of the total number of schools in Oakbridge City and the total number of schools in Shoreline City.

Question: What is the total number of schools in Ruby Bay?

Solution: Define regional medical school in Shoreline City as t; so t = 2. Define total number of schools in Shoreline City as j; so j = t = 2. Define public highschool in Oakbridge City as G; P = j + t = 2 + 2 = 4; so G = 3 * P = 3 * 4 = 12. Define total number of schools in Oakbridge City as D; so D = G = 12. Define culinarian school in Ruby Bay as b; i = D + j = 12 + 2 = 14; so b = 2 * i = 2 * 14 = 28. Define total number of schools in Ruby Bay as I; so I = b = 28. Answer: 28.


The number of elementary school in Oakbridge City equals 3. The number of culinarian school in Clearwater Bay equals the total number of schools in Oakbridge City. The number of culinarian school in Oakbridge City equals 2. The number of elementary school in Clearwater Bay equals the sum of the total number of schools in Oakbridge City, the number of elementary school in Oakbridge City, and the number of culinarian school in Oakbridge City.

Question: What is the total number of schools in Clearwater Bay?

Solution: Define elementary school in Oakbridge City as H; so H = 3. Define culinarian school in Oakbridge City as j; so j = 2. Define total number of schools in Oakbridge City as T; so T = H + j = 3 + 2 = 5. Define elementary school in Clearwater Bay as a; q = T + H = 5 + 3 = 8; so a = q + j = 8 + 2 = 10. Define culinarian school in Clearwater Bay as B; so B = T = 5. Define total number of schools in Clearwater Bay as V; so V = a + B = 10 + 5 = 15. Answer: 15.


The number of adult fox in Maple Creek equals 4 plus the difference between the total number of adult animals in Beverly Forest and the number of adult deer in Beverly Forest. The number of adult wolf in Maple Creek equals the sum of the total number of adult animals in Beverly Forest, the number of adult fox in Maple Creek, and the number of adult deer in Beverly Forest. The number of adult deer in Beverly Forest equals 3.

Question: What is the total number of adult animals in Maple Creek?

Solution: Define adult deer in Beverly Forest as O; so O = 3. Define total number of adult animals in Beverly Forest as e; so e = O = 3. Define adult fox in Maple Creek as T; b = e - O = 3 - 3 = 0; so T = 4 + b = 4 + 0 = 4. Define adult wolf in Maple Creek as P; Y = e + T = 3 + 4 = 7; so P = Y + O = 7 + 3 = 10. Define total number of adult animals in Maple Creek as R; so R = T + P = 4 + 10 = 14. Answer: 14.


The number of adult bear in Mayer Aquarium equals 1 plus the difference between the total number of adult animals in Hamilton Farm and the number of adult deer in Hamilton Farm. The number of adult wolf in Jefferson Circus equals the sum of the total number of adult animals in Mayer Aquarium, the number of adult deer in Hamilton Farm, and the total number of adult animals in Hamilton Farm. The number of adult deer in Hamilton Farm equals 2.

Question: What is the total number of adult animals in Jefferson Circus?

Solution: Define adult deer in Hamilton Farm as w; so w = 2. Define total number of adult animals in Hamilton Farm as b; so b = w = 2. Define adult bear in Mayer Aquarium as U; p = b - w = 2 - 2 = 0; so U = 1 + p = 1 + 0 = 1. Define total number of adult animals in Mayer Aquarium as Q; so Q = U = 1. Define adult wolf in Jefferson Circus as D; E = Q + w = 1 + 2 = 3; so D = E + b = 3 + 2 = 5. Define total number of adult animals in Jefferson Circus as x; so x = D = 5. Answer: 5.


The number of solemn period drama in Cinéma de Montreval equals 2. The number of intense detective thriller in Festival de Clairmont equals the sum of the total number of movies in Cinéma de Montreval, the number of intense detective thriller in Cinéma de Montreval, and the number of solemn period drama in Cinéma de Montreval. The number of intense detective thriller in Cinéma de Montreval equals the number of solemn period drama in Cinéma de Montreval. The number of solemn period drama in Festival de Clairmont equals 3.

Question: What is the total number of movies in Festival de Clairmont?

Solution: Define solemn period drama in Cinéma de Montreval as u; so u = 2. Define intense detective thriller in Cinéma de Montreval as S; so S = u = 2. Define total number of movies in Cinéma de Montreval as s; so s = S + u = 2 + 2 = 4. Define intense detective thriller in Festival de Clairmont as J; k = s + S = 4 + 2 = 6; so J = k + u = 6 + 2 = 8. Define solemn period drama in Festival de Clairmont as q; so q = 3. Define total number of movies in Festival de Clairmont as o; so o = J + q = 8 + 3 = 11. Answer: 11.


The number of private middle school in Glenfield City equals 3. The number of private middle school in Brightford equals 1 plus the difference between the total number of schools in Glenfield City and the number of private middle school in Glenfield City. The number of elementary school in Glenfield City equals 4. The number of elementary school in Brightford equals the total number of schools in Glenfield City.

Question: What is the total number of schools in Brightford?

Solution: Define private middle school in Glenfield City as w; so w = 3. Define elementary school in Glenfield City as u; so u = 4. Define total number of schools in Glenfield City as Y; so Y = u + w = 4 + 3 = 7. Define private middle school in Brightford as h; O = Y - w = 7 - 3 = 4; so h = 1 + O = 1 + 4 = 5. Define elementary school in Brightford as U; so U = Y = 7. Define total number of schools in Brightford as K; so K = U + h = 7 + 5 = 12. Answer: 12.


The number of calm road movie in Cinéma de Montreval equals 2 plus the difference between the total number of movies in Festival de Clairmont and the number of upbeat metropolis comedy in Festival de Clairmont. The number of upbeat metropolis comedy in Festival de Clairmont equals 2. The number of upbeat metropolis comedy in Cinéma de Montreval equals the sum of the number of upbeat metropolis comedy in Festival de Clairmont, the number of calm road movie in Cinéma de Montreval, and the total number of movies in Festival de Clairmont.

Question: What is the total number of movies in Cinéma de Montreval?

Solution: Define upbeat metropolis comedy in Festival de Clairmont as O; so O = 2. Define total number of movies in Festival de Clairmont as z; so z = O = 2. Define calm road movie in Cinéma de Montreval as d; m = z - O = 2 - 2 = 0; so d = 2 + m = 2 + 0 = 2. Define upbeat metropolis comedy in Cinéma de Montreval as R; A = O + d = 2 + 2 = 4; so R = A + z = 4 + 2 = 6. Define total number of movies in Cinéma de Montreval as W; so W = d + R = 2 + 6 = 8. Answer: 8.


The number of adult blue jay in South Zoo equals 4 plus the difference between the total number of adult animals in Hamilton Farm and the number of adult blue jay in Hamilton Farm. The number of adult crow in South Zoo equals the sum of the total number of adult animals in Hamilton Farm, the number of adult blue jay in Hamilton Farm, and the number of adult blue jay in South Zoo. The number of adult blue jay in Hamilton Farm equals 1.

Question: What is the total number of adult animals in South Zoo?

Solution: Define adult blue jay in Hamilton Farm as Z; so Z = 1. Define total number of adult animals in Hamilton Farm as G; so G = Z = 1. Define adult blue jay in South Zoo as j; Y = G - Z = 1 - 1 = 0; so j = 4 + Y = 4 + 0 = 4. Define adult crow in South Zoo as o; X = G + Z = 1 + 1 = 2; so o = X + j = 2 + 4 = 6. Define total number of adult animals in South Zoo as L; so L = j + o = 4 + 6 = 10. Answer: 10.


The number of upbeat metropolis comedy in Taylor Movie Festival equals 3. The number of solemn period drama in Taylor Movie Festival equals 2. The number of solemn period drama in Golden Banana Movie Festival equals 4. The number of solemn period drama in Verdi Movie Festival equals the number of upbeat metropolis comedy in Taylor Movie Festival. The number of calm road movie in Taylor Movie Festival equals 3 plus the number of calm road movie in Golden Banana Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals 1. The number of upbeat metropolis comedy in Verdi Movie Festival equals 3 plus the difference between the number of upbeat metropolis comedy in Taylor Movie Festival and the number of solemn period drama in Verdi Movie Festival. The number of calm road movie in Verdi Movie Festival equals 2 times the number of upbeat metropolis comedy in Verdi Movie Festival. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 4.

Question: What is the total number of movies in Verdi Movie Festival?

Solution: Define upbeat metropolis comedy in Taylor Movie Festival as B; so B = 3. Define solemn period drama in Verdi Movie Festival as m; so m = B = 3. Define upbeat metropolis comedy in Verdi Movie Festival as D; A = B - m = 3 - 3 = 0; so D = 3 + A = 3 + 0 = 3. Define calm road movie in Verdi Movie Festival as r; y = D = 3; so r = 2 * y = 2 * 3 = 6. Define total number of movies in Verdi Movie Festival as x; q = m + r = 3 + 6 = 9; so x = q + D = 9 + 3 = 12. Answer: 12.


The number of adult parrot in Mayer Aquarium equals 4 times the total number of adult animals in Hamilton Farm. The number of adult crow in Mayer Aquarium equals 2 plus the sum of the number of adult parrot in Mayer Aquarium, the number of adult crow in Hamilton Farm, and the total number of adult animals in Hamilton Farm. The number of adult crow in Hamilton Farm equals 2.

Question: What is the total number of adult animals in Mayer Aquarium?

Solution: Define adult crow in Hamilton Farm as l; so l = 2. Define total number of adult animals in Hamilton Farm as D; so D = l = 2. Define adult parrot in Mayer Aquarium as u; o = D = 2; so u = 4 * o = 4 * 2 = 8. Define adult crow in Mayer Aquarium as X; b = u + l = 8 + 2 = 10; c = b + D = 10 + 2 = 12; so X = 2 + c = 2 + 12 = 14. Define total number of adult animals in Mayer Aquarium as H; so H = X + u = 14 + 8 = 22. Answer: 22.


The number of adult deer in Pine Ridge equals 4. The number of adult deer in Maple Creek equals the total number of adult animals in Pine Ridge. The number of adult deer in Beverly Forest equals 2 plus the total number of adult animals in Maple Creek. The number of adult deer in Cedar Valley equals 4 plus the total number of adult animals in Beverly Forest.

Question: What is the total number of adult animals in Cedar Valley?

Solution: Define adult deer in Pine Ridge as q; so q = 4. Define total number of adult animals in Pine Ridge as L; so L = q = 4. Define adult deer in Maple Creek as D; so D = L = 4. Define total number of adult animals in Maple Creek as Z; so Z = D = 4. Define adult deer in Beverly Forest as O; c = Z = 4; so O = 2 + c = 2 + 4 = 6. Define total number of adult animals in Beverly Forest as H; so H = O = 6. Define adult deer in Cedar Valley as K; j = H = 6; so K = 4 + j = 4 + 6 = 10. Define total number of adult animals in Cedar Valley as B; so B = K = 10. Answer: 10.


The number of adult fox in Hamilton Farm equals 2 times the number of adult bear in Hamilton Farm. The number of adult bear in Hamilton Farm equals 2. The number of adult fox in Jefferson Circus equals the number of adult fox in Hamilton Farm. The number of adult bear in Jefferson Circus equals 4 times the total number of adult animals in Hamilton Farm.

Question: What is the total number of adult animals in Jefferson Circus?

Solution: Define adult bear in Hamilton Farm as Q; so Q = 2. Define adult fox in Hamilton Farm as h; Y = Q = 2; so h = 2 * Y = 2 * 2 = 4. Define total number of adult animals in Hamilton Farm as B; so B = h + Q = 4 + 2 = 6. Define adult bear in Jefferson Circus as I; s = B = 6; so I = 4 * s = 4 * 6 = 24. Define adult fox in Jefferson Circus as E; so E = h = 4. Define total number of adult animals in Jefferson Circus as c; so c = E + I = 4 + 24 = 28. Answer: 28.


The number of elementary school in Glenfield City equals 4. The number of private middle school in Glenfield City equals the sum of the number of private middle school in Hawkesbury, the number of elementary school in Evervale City, and the number of elementary school in Hawkesbury. The number of private middle school in Hawkesbury equals the number of elementary school in Evervale City. The number of elementary school in Westhaven City equals 2 times the sum of the number of private middle school in Glenfield City, the number of elementary school in Evervale City, and the number of private middle school in Hawkesbury. The number of public highschool in Glenfield City equals the number of culinarian school in Glenfield City. The number of culinarian school in Evervale City equals the difference between the total number of schools in Hawkesbury and the total number of schools in Evervale City. The number of culinarian school in Hawkesbury equals 2. The number of culinarian school in Brightford equals the sum of the number of private middle school in Brightford and the number of culinarian school in Glenfield City. The number of private middle school in Westhaven City equals 3. The number of culinarian school in Westhaven City equals 4. The number of culinarian school in Glenfield City equals the number of culinarian school in Hawkesbury. The number of elementary school in Hawkesbury equals 2. The number of elementary school in Evervale City equals the number of elementary school in Hawkesbury. The number of public highschool in Brightford equals 4. The number of private middle school in Evervale City equals 2. The number of private middle school in Brightford equals the total number of schools in Evervale City. The number of public highschool in Hawkesbury equals 3.

Question: How many elementary school does Westhaven City have?

Solution: Define elementary school in Hawkesbury as w; so w = 2. Define elementary school in Evervale City as A; so A = w = 2. Define private middle school in Hawkesbury as C; so C = A = 2. Define private middle school in Glenfield City as h; o = C + A = 2 + 2 = 4; so h = o + w = 4 + 2 = 6. Define elementary school in Westhaven City as e; i = h + A = 6 + 2 = 8; j = i + C = 8 + 2 = 10; so e = 2 * j = 2 * 10 = 20. Answer: 20.


The number of culinarian school in Hawkesbury equals 3 plus the sum of the total number of schools in Brightford and the number of regional medical school in Glenfield City. The number of private middle school in Brightford equals the total number of schools in Glenfield City. The number of regional medical school in Glenfield City equals 4 times the number of culinarian school in Glenfield City. The number of culinarian school in Glenfield City equals 4.

Question: How many culinarian school does Hawkesbury have?

Solution: Define culinarian school in Glenfield City as n; so n = 4. Define regional medical school in Glenfield City as u; M = n = 4; so u = 4 * M = 4 * 4 = 16. Define total number of schools in Glenfield City as f; so f = n + u = 4 + 16 = 20. Define private middle school in Brightford as g; so g = f = 20. Define total number of schools in Brightford as P; so P = g = 20. Define culinarian school in Hawkesbury as O; F = P + u = 20 + 16 = 36; so O = 3 + F = 3 + 36 = 39. Answer: 39.


The number of adult eagle in Cedar Valley equals 3. The number of adult eagle in Beverly Forest equals 3 plus the sum of the total number of adult animals in Cedar Valley, the number of adult eagle in Cedar Valley, and the number of adult blue jay in Cedar Valley. The number of adult blue jay in Cedar Valley equals 2 times the number of adult eagle in Cedar Valley.

Question: What is the total number of adult animals in Beverly Forest?

Solution: Define adult eagle in Cedar Valley as K; so K = 3. Define adult blue jay in Cedar Valley as h; Z = K = 3; so h = 2 * Z = 2 * 3 = 6. Define total number of adult animals in Cedar Valley as G; so G = K + h = 3 + 6 = 9. Define adult eagle in Beverly Forest as T; i = G + K = 9 + 3 = 12; e = i + h = 12 + 6 = 18; so T = 3 + e = 3 + 18 = 21. Define total number of adult animals in Beverly Forest as p; so p = T = 21. Answer: 21.


The number of adult owl in Mayer Aquarium equals 4. The number of adult blue jay in South Zoo equals 3 times the sum of the total number of adult animals in Mayer Aquarium, the number of adult owl in Mayer Aquarium, and the number of adult blue jay in Mayer Aquarium. The number of adult blue jay in Mayer Aquarium equals 2 plus the number of adult owl in Mayer Aquarium.

Question: What is the total number of adult animals in South Zoo?

Solution: Define adult owl in Mayer Aquarium as R; so R = 4. Define adult blue jay in Mayer Aquarium as d; u = R = 4; so d = 2 + u = 2 + 4 = 6. Define total number of adult animals in Mayer Aquarium as D; so D = d + R = 6 + 4 = 10. Define adult blue jay in South Zoo as X; v = D + R = 10 + 4 = 14; P = v + d = 14 + 6 = 20; so X = 3 * P = 3 * 20 = 60. Define total number of adult animals in South Zoo as U; so U = X = 60. Answer: 60.


The number of adult owl in Cedar Valley equals 4. The number of adult parrot in Oakridge Riverside equals the sum of the total number of adult animals in Cedar Valley, the number of adult owl in Oakridge Riverside, and the number of adult owl in Cedar Valley. The number of adult owl in Oakridge Riverside equals 3 plus the difference between the total number of adult animals in Cedar Valley and the number of adult owl in Cedar Valley.

Question: What is the total number of adult animals in Oakridge Riverside?

Solution: Define adult owl in Cedar Valley as H; so H = 4. Define total number of adult animals in Cedar Valley as M; so M = H = 4. Define adult owl in Oakridge Riverside as B; c = M - H = 4 - 4 = 0; so B = 3 + c = 3 + 0 = 3. Define adult parrot in Oakridge Riverside as r; m = M + B = 4 + 3 = 7; so r = m + H = 7 + 4 = 11. Define total number of adult animals in Oakridge Riverside as y; so y = r + B = 11 + 3 = 14. Answer: 14.


The number of adult eagle in Bundle Ranch equals the sum of the number of adult owl in Jefferson Circus and the total number of adult animals in South Zoo. The number of adult parrot in Hamilton Farm equals 1. The number of adult parrot in Bundle Ranch equals 3. The number of adult parrot in South Zoo equals the sum of the total number of adult animals in Jefferson Circus, the number of adult parrot in Bundle Ranch, and the number of adult owl in Jefferson Circus. The number of adult owl in Bundle Ranch equals 4. The number of adult eagle in South Zoo equals 3. The number of adult owl in Jefferson Circus equals 4 times the number of adult parrot in Bundle Ranch. The number of adult crow in Bundle Ranch equals 3 plus the number of adult parrot in Hamilton Farm.

Question: What is the total number of adult animals in South Zoo?

Solution: Define adult parrot in Bundle Ranch as W; so W = 3. Define adult owl in Jefferson Circus as X; H = W = 3; so X = 4 * H = 4 * 3 = 12. Define total number of adult animals in Jefferson Circus as J; so J = X = 12. Define adult parrot in South Zoo as D; u = J + W = 12 + 3 = 15; so D = u + X = 15 + 12 = 27. Define adult eagle in South Zoo as l; so l = 3. Define total number of adult animals in South Zoo as S; so S = l + D = 3 + 27 = 30. Answer: 30.


The number of public highschool in Oakbridge City equals 1 plus the number of culinarian school in Oakbridge City. The number of public highschool in Riverton City equals 2 plus the sum of the total number of schools in Oakbridge City, the number of culinarian school in Oakbridge City, and the number of public highschool in Oakbridge City. The number of culinarian school in Oakbridge City equals 3.

Question: What is the total number of schools in Riverton City?

Solution: Define culinarian school in Oakbridge City as t; so t = 3. Define public highschool in Oakbridge City as T; i = t = 3; so T = 1 + i = 1 + 3 = 4. Define total number of schools in Oakbridge City as O; so O = T + t = 4 + 3 = 7. Define public highschool in Riverton City as K; k = O + t = 7 + 3 = 10; l = k + T = 10 + 4 = 14; so K = 2 + l = 2 + 14 = 16. Define total number of schools in Riverton City as H; so H = K = 16. Answer: 16.


The number of elementary school in Riverton City equals 4. The number of regional medical school in Oakbridge City equals the number of elementary school in Riverton City. The number of culinarian school in Clearwater Bay equals the sum of the total number of schools in Oakbridge City, the number of regional medical school in Oakbridge City, and the number of elementary school in Riverton City. The number of private middle school in Shoreline City equals 2 plus the sum of the number of culinarian school in Clearwater Bay, the total number of schools in Oakbridge City, and the number of elementary school in Riverton City.

Question: How many private middle school does Shoreline City have?

Solution: Define elementary school in Riverton City as U; so U = 4. Define regional medical school in Oakbridge City as L; so L = U = 4. Define total number of schools in Oakbridge City as d; so d = L = 4. Define culinarian school in Clearwater Bay as O; g = d + L = 4 + 4 = 8; so O = g + U = 8 + 4 = 12. Define private middle school in Shoreline City as r; M = O + d = 12 + 4 = 16; w = M + U = 16 + 4 = 20; so r = 2 + w = 2 + 20 = 22. Answer: 22.


The number of solemn period drama in Taylor Movie Festival equals the number of calm road movie in Northwood Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals 4. The number of futuristic sci-fi movie in Taylor Movie Festival equals the sum of the number of calm road movie in Northwood Movie Festival, the number of solemn period drama in Taylor Movie Festival, and the number of calm road movie in Taylor Movie Festival. The number of calm road movie in Northwood Movie Festival equals 4. The number of futuristic sci-fi movie in Golden Banana Movie Festival equals 3 times the difference between the total number of movies in Taylor Movie Festival and the number of solemn period drama in Taylor Movie Festival. The number of solemn period drama in Verdi Movie Festival equals 4. The number of solemn period drama in Northwood Movie Festival equals the sum of the number of calm road movie in Northwood Movie Festival, the number of futuristic sci-fi movie in Taylor Movie Festival, the number of futuristic sci-fi movie in Golden Banana Movie Festival, and the total number of movies in Taylor Movie Festival. The number of calm road movie in Taylor Movie Festival equals 3 times the number of calm road movie in Northwood Movie Festival. The number of futuristic sci-fi movie in Verdi Movie Festival equals the number of solemn period drama in Verdi Movie Festival.

Question: What is the total number of movies in Taylor Movie Festival?

Solution: Define calm road movie in Northwood Movie Festival as C; so C = 4. Define calm road movie in Taylor Movie Festival as i; q = C = 4; so i = 3 * q = 3 * 4 = 12. Define solemn period drama in Taylor Movie Festival as x; so x = C = 4. Define futuristic sci-fi movie in Taylor Movie Festival as K; E = C + x = 4 + 4 = 8; so K = E + i = 8 + 12 = 20. Define total number of movies in Taylor Movie Festival as w; c = K + x = 20 + 4 = 24; so w = c + i = 24 + 12 = 36. Answer: 36.


The number of adult parrot in Beverly Forest equals 2. The number of adult eagle in Pine Ridge equals 2 plus the number of adult parrot in Pine Ridge. The number of adult parrot in Oakridge Riverside equals 4 times the number of adult parrot in Beverly Forest. The number of adult owl in Beverly Forest equals 2 times the number of adult eagle in Pine Ridge. The number of adult eagle in Oakridge Riverside equals 4. The number of adult owl in Pine Ridge equals 2. The number of adult owl in Oakridge Riverside equals 4 times the sum of the total number of adult animals in Pine Ridge and the number of adult owl in Pine Ridge. The number of adult eagle in Beverly Forest equals 4 plus the difference between the total number of adult animals in Pine Ridge and the number of adult owl in Oakridge Riverside. The number of adult parrot in Pine Ridge equals the number of adult owl in Pine Ridge.

Question: How many adult owl does Oakridge Riverside have?

Solution: Define adult owl in Pine Ridge as m; so m = 2. Define adult parrot in Pine Ridge as t; so t = m = 2. Define adult eagle in Pine Ridge as u; d = t = 2; so u = 2 + d = 2 + 2 = 4. Define total number of adult animals in Pine Ridge as O; s = m + t = 2 + 2 = 4; so O = s + u = 4 + 4 = 8. Define adult owl in Oakridge Riverside as E; I = O + m = 8 + 2 = 10; so E = 4 * I = 4 * 10 = 40. Answer: 40.


The number of adult parrot in Cedar Valley equals 3 times the difference between the total number of adult animals in Beverly Forest and the number of adult owl in Beverly Forest. The number of adult owl in Beverly Forest equals 2. The number of adult eagle in Cedar Valley equals the sum of the number of adult parrot in Cedar Valley, the total number of adult animals in Beverly Forest, and the number of adult owl in Beverly Forest.

Question: What is the total number of adult animals in Cedar Valley?

Solution: Define adult owl in Beverly Forest as L; so L = 2. Define total number of adult animals in Beverly Forest as N; so N = L = 2. Define adult parrot in Cedar Valley as G; s = N - L = 2 - 2 = 0; so G = 3 * s = 3 * 0 = 0. Define adult eagle in Cedar Valley as q; P = G + N = 0 + 2 = 2; so q = P + L = 2 + 2 = 4. Define total number of adult animals in Cedar Valley as z; so z = G + q = 0 + 4 = 4. Answer: 4.