The number of solemn period drama in Golden Banana Movie Festival equals 2. The number of solemn period drama in Taylor Movie Festival equals 3 plus the difference between the total number of movies in Golden Banana Movie Festival and the number of solemn period drama in Golden Banana Movie Festival. The number of solemn period drama in Verdi Movie Festival equals the sum of the total number of movies in Taylor Movie Festival, the number of solemn period drama in Taylor Movie Festival, and the total number of movies in Golden Banana Movie Festival.

Question: What is the total number of movies in Verdi Movie Festival?

Solution: Define solemn period drama in Golden Banana Movie Festival as p; so p = 2. Define total number of movies in Golden Banana Movie Festival as f; so f = p = 2. Define solemn period drama in Taylor Movie Festival as E; x = f - p = 2 - 2 = 0; so E = 3 + x = 3 + 0 = 3. Define total number of movies in Taylor Movie Festival as t; so t = E = 3. Define solemn period drama in Verdi Movie Festival as m; j = t + E = 3 + 3 = 6; so m = j + f = 6 + 2 = 8. Define total number of movies in Verdi Movie Festival as T; so T = m = 8. Answer: 8.


The number of adult blue jay in Pine Ridge equals 1 plus the total number of adult animals in Beverly Forest. The number of adult parrot in Beverly Forest equals 2. The number of adult blue jay in Beverly Forest equals 3. The number of adult parrot in Pine Ridge equals 4 plus the total number of adult animals in Beverly Forest.

Question: What is the total number of adult animals in Pine Ridge?

Solution: Define adult blue jay in Beverly Forest as l; so l = 3. Define adult parrot in Beverly Forest as f; so f = 2. Define total number of adult animals in Beverly Forest as F; so F = f + l = 2 + 3 = 5. Define adult blue jay in Pine Ridge as R; S = F = 5; so R = 1 + S = 1 + 5 = 6. Define adult parrot in Pine Ridge as v; e = F = 5; so v = 4 + e = 4 + 5 = 9. Define total number of adult animals in Pine Ridge as H; so H = v + R = 9 + 6 = 15. Answer: 15.


The number of adult parrot in Bundle Ranch equals 2. The number of adult owl in Bundle Ranch equals 4 times the number of adult parrot in Bundle Ranch. The number of adult crow in Mayer Aquarium equals 3 times the sum of the total number of adult animals in Bundle Ranch, the number of adult parrot in Bundle Ranch, and the number of adult owl in Bundle Ranch.

Question: What is the total number of adult animals in Mayer Aquarium?

Solution: Define adult parrot in Bundle Ranch as m; so m = 2. Define adult owl in Bundle Ranch as A; b = m = 2; so A = 4 * b = 4 * 2 = 8. Define total number of adult animals in Bundle Ranch as g; so g = m + A = 2 + 8 = 10. Define adult crow in Mayer Aquarium as a; w = g + m = 10 + 2 = 12; Z = w + A = 12 + 8 = 20; so a = 3 * Z = 3 * 20 = 60. Define total number of adult animals in Mayer Aquarium as B; so B = a = 60. Answer: 60.


The number of futuristic sci-fi movie in Golden Banana Movie Festival equals 3 plus the difference between the total number of movies in Verdi Movie Festival and the number of futuristic sci-fi movie in Verdi Movie Festival. The number of futuristic sci-fi movie in Verdi Movie Festival equals 4. The number of futuristic sci-fi movie in Northwood Movie Festival equals the sum of the total number of movies in Golden Banana Movie Festival, the number of futuristic sci-fi movie in Verdi Movie Festival, and the number of futuristic sci-fi movie in Golden Banana Movie Festival.

Question: What is the total number of movies in Northwood Movie Festival?

Solution: Define futuristic sci-fi movie in Verdi Movie Festival as T; so T = 4. Define total number of movies in Verdi Movie Festival as C; so C = T = 4. Define futuristic sci-fi movie in Golden Banana Movie Festival as F; G = C - T = 4 - 4 = 0; so F = 3 + G = 3 + 0 = 3. Define total number of movies in Golden Banana Movie Festival as k; so k = F = 3. Define futuristic sci-fi movie in Northwood Movie Festival as H; l = k + T = 3 + 4 = 7; so H = l + F = 7 + 3 = 10. Define total number of movies in Northwood Movie Festival as D; so D = H = 10. Answer: 10.


The number of regional medical school in Shoreline City equals 2 plus the difference between the total number of schools in Riverton City and the number of private middle school in Ruby Bay. The number of public highschool in Riverton City equals the total number of schools in Ruby Bay. The number of private middle school in Ruby Bay equals 1. The number of private middle school in Riverton City equals the total number of schools in Ruby Bay.

Question: What is the total number of schools in Shoreline City?

Solution: Define private middle school in Ruby Bay as e; so e = 1. Define total number of schools in Ruby Bay as E; so E = e = 1. Define private middle school in Riverton City as B; so B = E = 1. Define public highschool in Riverton City as d; so d = E = 1. Define total number of schools in Riverton City as P; so P = B + d = 1 + 1 = 2. Define regional medical school in Shoreline City as T; U = P - e = 2 - 1 = 1; so T = 2 + U = 2 + 1 = 3. Define total number of schools in Shoreline City as o; so o = T = 3. Answer: 3.


The number of adult racoon in Pine Ridge equals 2. The number of adult bear in Pine Ridge equals the number of adult deer in Pine Ridge. The number of adult bear in Maple Creek equals 3 plus the total number of adult animals in Pine Ridge. The number of adult bear in Beverly Forest equals the sum of the number of adult bear in Maple Creek and the number of adult bear in Pine Ridge. The number of adult deer in Beverly Forest equals 3. The number of adult deer in Pine Ridge equals 3.

Question: How many adult bear does Beverly Forest have?

Solution: Define adult deer in Pine Ridge as c; so c = 3. Define adult racoon in Pine Ridge as n; so n = 2. Define adult bear in Pine Ridge as z; so z = c = 3. Define total number of adult animals in Pine Ridge as j; r = c + n = 3 + 2 = 5; so j = r + z = 5 + 3 = 8. Define adult bear in Maple Creek as p; P = j = 8; so p = 3 + P = 3 + 8 = 11. Define adult bear in Beverly Forest as b; so b = p + z = 11 + 3 = 14. Answer: 14.


The number of adult racoon in Cedar Valley equals the sum of the number of adult bear in Pine Ridge, the number of adult deer in Cedar Valley, and the total number of adult animals in Pine Ridge. The number of adult deer in Cedar Valley equals 2 plus the difference between the total number of adult animals in Pine Ridge and the number of adult bear in Pine Ridge. The number of adult bear in Pine Ridge equals 3.

Question: What is the total number of adult animals in Cedar Valley?

Solution: Define adult bear in Pine Ridge as U; so U = 3. Define total number of adult animals in Pine Ridge as p; so p = U = 3. Define adult deer in Cedar Valley as W; A = p - U = 3 - 3 = 0; so W = 2 + A = 2 + 0 = 2. Define adult racoon in Cedar Valley as m; t = U + W = 3 + 2 = 5; so m = t + p = 5 + 3 = 8. Define total number of adult animals in Cedar Valley as R; so R = W + m = 2 + 8 = 10. Answer: 10.


The number of elementary school in Riverton City equals 3 times the number of elementary school in Oakbridge City. The number of culinarian school in Oakbridge City equals the sum of the total number of schools in Riverton City and the number of culinarian school in Riverton City. The number of elementary school in Oakbridge City equals 4. The number of culinarian school in Riverton City equals the number of elementary school in Oakbridge City.

Question: What is the total number of schools in Oakbridge City?

Solution: Define elementary school in Oakbridge City as m; so m = 4. Define culinarian school in Riverton City as s; so s = m = 4. Define elementary school in Riverton City as G; V = m = 4; so G = 3 * V = 3 * 4 = 12. Define total number of schools in Riverton City as X; so X = s + G = 4 + 12 = 16. Define culinarian school in Oakbridge City as F; so F = X + s = 16 + 4 = 20. Define total number of schools in Oakbridge City as T; so T = F + m = 20 + 4 = 24. Answer: 24.


The number of regional medical school in Glenfield City equals 4. The number of regional medical school in Evervale City equals 4 plus the difference between the number of culinarian school in Evervale City and the number of culinarian school in Glenfield City. The number of culinarian school in Glenfield City equals the number of regional medical school in Glenfield City. The number of culinarian school in Evervale City equals the total number of schools in Glenfield City.

Question: What is the total number of schools in Evervale City?

Solution: Define regional medical school in Glenfield City as M; so M = 4. Define culinarian school in Glenfield City as E; so E = M = 4. Define total number of schools in Glenfield City as n; so n = M + E = 4 + 4 = 8. Define culinarian school in Evervale City as Z; so Z = n = 8. Define regional medical school in Evervale City as I; P = Z - E = 8 - 4 = 4; so I = 4 + P = 4 + 4 = 8. Define total number of schools in Evervale City as J; so J = I + Z = 8 + 8 = 16. Answer: 16.


The number of elementary school in Brightford equals 2 times the sum of the total number of schools in Hawkesbury, the number of elementary school in Hawkesbury, and the number of regional medical school in Hawkesbury. The number of regional medical school in Hawkesbury equals 4 times the number of elementary school in Hawkesbury. The number of elementary school in Hawkesbury equals 3.

Question: What is the total number of schools in Brightford?

Solution: Define elementary school in Hawkesbury as L; so L = 3. Define regional medical school in Hawkesbury as Z; C = L = 3; so Z = 4 * C = 4 * 3 = 12. Define total number of schools in Hawkesbury as R; so R = L + Z = 3 + 12 = 15. Define elementary school in Brightford as G; l = R + L = 15 + 3 = 18; K = l + Z = 18 + 12 = 30; so G = 2 * K = 2 * 30 = 60. Define total number of schools in Brightford as g; so g = G = 60. Answer: 60.


The number of culinarian school in Ruby Bay equals 3. The number of public highschool in Shoreline City equals 4. The number of public highschool in Ruby Bay equals 3 times the difference between the total number of schools in Shoreline City and the number of culinarian school in Shoreline City. The number of culinarian school in Shoreline City equals the number of public highschool in Shoreline City.

Question: What is the total number of schools in Ruby Bay?

Solution: Define public highschool in Shoreline City as m; so m = 4. Define culinarian school in Shoreline City as X; so X = m = 4. Define total number of schools in Shoreline City as T; so T = m + X = 4 + 4 = 8. Define public highschool in Ruby Bay as H; G = T - X = 8 - 4 = 4; so H = 3 * G = 3 * 4 = 12. Define culinarian school in Ruby Bay as l; so l = 3. Define total number of schools in Ruby Bay as P; so P = H + l = 12 + 3 = 15. Answer: 15.


The number of adult eagle in Hamilton Farm equals 3. The number of adult eagle in South Zoo equals 2 times the difference between the total number of adult animals in Mayer Aquarium and the number of adult eagle in Hamilton Farm. The number of adult eagle in Mayer Aquarium equals 3 times the sum of the total number of adult animals in Hamilton Farm and the number of adult eagle in Hamilton Farm.

Question: What is the total number of adult animals in South Zoo?

Solution: Define adult eagle in Hamilton Farm as D; so D = 3. Define total number of adult animals in Hamilton Farm as O; so O = D = 3. Define adult eagle in Mayer Aquarium as e; k = O + D = 3 + 3 = 6; so e = 3 * k = 3 * 6 = 18. Define total number of adult animals in Mayer Aquarium as C; so C = e = 18. Define adult eagle in South Zoo as W; L = C - D = 18 - 3 = 15; so W = 2 * L = 2 * 15 = 30. Define total number of adult animals in South Zoo as m; so m = W = 30. Answer: 30.


The number of regional medical school in Oakbridge City equals the total number of schools in Riverton City. The number of regional medical school in Riverton City equals 2. The number of private middle school in Riverton City equals the number of regional medical school in Riverton City. The number of private middle school in Oakbridge City equals 4 times the difference between the total number of schools in Riverton City and the number of private middle school in Riverton City.

Question: What is the total number of schools in Oakbridge City?

Solution: Define regional medical school in Riverton City as m; so m = 2. Define private middle school in Riverton City as E; so E = m = 2. Define total number of schools in Riverton City as W; so W = E + m = 2 + 2 = 4. Define private middle school in Oakbridge City as B; g = W - E = 4 - 2 = 2; so B = 4 * g = 4 * 2 = 8. Define regional medical school in Oakbridge City as j; so j = W = 4. Define total number of schools in Oakbridge City as K; so K = B + j = 8 + 4 = 12. Answer: 12.


The number of adult fox in Cedar Valley equals 2 plus the number of adult racoon in Cedar Valley. The number of adult racoon in Oakridge Riverside equals the total number of adult animals in Maple Creek. The number of adult deer in Maple Creek equals 4 times the total number of adult animals in Cedar Valley. The number of adult racoon in Cedar Valley equals 1.

Question: What is the total number of adult animals in Oakridge Riverside?

Solution: Define adult racoon in Cedar Valley as q; so q = 1. Define adult fox in Cedar Valley as M; x = q = 1; so M = 2 + x = 2 + 1 = 3. Define total number of adult animals in Cedar Valley as t; so t = q + M = 1 + 3 = 4. Define adult deer in Maple Creek as F; P = t = 4; so F = 4 * P = 4 * 4 = 16. Define total number of adult animals in Maple Creek as p; so p = F = 16. Define adult racoon in Oakridge Riverside as l; so l = p = 16. Define total number of adult animals in Oakridge Riverside as K; so K = l = 16. Answer: 16.


The number of adult crow in Mayer Aquarium equals 3 times the sum of the total number of adult animals in Bundle Ranch, the number of adult eagle in Bundle Ranch, and the number of adult crow in Bundle Ranch. The number of adult crow in Bundle Ranch equals 3 times the number of adult eagle in Bundle Ranch. The number of adult eagle in Bundle Ranch equals 2.

Question: What is the total number of adult animals in Mayer Aquarium?

Solution: Define adult eagle in Bundle Ranch as e; so e = 2. Define adult crow in Bundle Ranch as D; s = e = 2; so D = 3 * s = 3 * 2 = 6. Define total number of adult animals in Bundle Ranch as c; so c = e + D = 2 + 6 = 8. Define adult crow in Mayer Aquarium as n; L = c + e = 8 + 2 = 10; k = L + D = 10 + 6 = 16; so n = 3 * k = 3 * 16 = 48. Define total number of adult animals in Mayer Aquarium as A; so A = n = 48. Answer: 48.


The number of public highschool in Oakbridge City equals the number of private middle school in Oakbridge City. The number of private middle school in Riverton City equals 1 plus the sum of the total number of schools in Oakbridge City and the number of regional medical school in Oakbridge City. The number of regional medical school in Riverton City equals the difference between the number of private middle school in Ruby Bay and the number of culinarian school in Ruby Bay. The number of public highschool in Riverton City equals 2 plus the sum of the number of private middle school in Oakbridge City and the number of public highschool in Oakbridge City. The number of culinarian school in Riverton City equals 4 times the number of private middle school in Oakbridge City. The number of culinarian school in Ruby Bay equals 4. The number of private middle school in Ruby Bay equals 3. The number of private middle school in Oakbridge City equals 2 times the number of regional medical school in Oakbridge City. The number of regional medical school in Ruby Bay equals 4 plus the sum of the number of regional medical school in Riverton City and the number of private middle school in Ruby Bay. The number of regional medical school in Oakbridge City equals 3.

Question: How many private middle school does Riverton City have?

Solution: Define regional medical school in Oakbridge City as S; so S = 3. Define private middle school in Oakbridge City as O; D = S = 3; so O = 2 * D = 2 * 3 = 6. Define public highschool in Oakbridge City as q; so q = O = 6. Define total number of schools in Oakbridge City as G; d = S + q = 3 + 6 = 9; so G = d + O = 9 + 6 = 15. Define private middle school in Riverton City as N; I = G + S = 15 + 3 = 18; so N = 1 + I = 1 + 18 = 19. Answer: 19.


The number of public highschool in Clearwater Bay equals 3. The number of public highschool in Oakbridge City equals 4 plus the number of elementary school in Oakbridge City. The number of elementary school in Clearwater Bay equals 3. The number of regional medical school in Clearwater Bay equals 2. The number of public highschool in Riverton City equals the sum of the number of elementary school in Riverton City, the number of regional medical school in Riverton City, the number of regional medical school in Oakbridge City, and the number of public highschool in Oakbridge City. The number of regional medical school in Riverton City equals the sum of the number of regional medical school in Oakbridge City, the number of elementary school in Oakbridge City, and the number of public highschool in Oakbridge City. The number of elementary school in Riverton City equals 4. The number of elementary school in Oakbridge City equals 4 times the number of elementary school in Riverton City. The number of regional medical school in Oakbridge City equals 2 plus the number of elementary school in Oakbridge City.

Question: What is the total number of schools in Oakbridge City?

Solution: Define elementary school in Riverton City as F; so F = 4. Define elementary school in Oakbridge City as S; l = F = 4; so S = 4 * l = 4 * 4 = 16. Define public highschool in Oakbridge City as W; u = S = 16; so W = 4 + u = 4 + 16 = 20. Define regional medical school in Oakbridge City as y; s = S = 16; so y = 2 + s = 2 + 16 = 18. Define total number of schools in Oakbridge City as R; H = y + S = 18 + 16 = 34; so R = H + W = 34 + 20 = 54. Answer: 54.


The number of adult deer in Bundle Ranch equals the number of adult deer in Hamilton Farm. The number of adult bear in Hamilton Farm equals 4 plus the number of adult deer in Hamilton Farm. The number of adult deer in Hamilton Farm equals 4. The number of adult bear in Bundle Ranch equals the sum of the total number of adult animals in Hamilton Farm and the number of adult deer in Hamilton Farm.

Question: What is the total number of adult animals in Bundle Ranch?

Solution: Define adult deer in Hamilton Farm as e; so e = 4. Define adult bear in Hamilton Farm as m; s = e = 4; so m = 4 + s = 4 + 4 = 8. Define total number of adult animals in Hamilton Farm as X; so X = m + e = 8 + 4 = 12. Define adult bear in Bundle Ranch as F; so F = X + e = 12 + 4 = 16. Define adult deer in Bundle Ranch as G; so G = e = 4. Define total number of adult animals in Bundle Ranch as u; so u = F + G = 16 + 4 = 20. Answer: 20.


The number of adult bear in South Zoo equals 2. The number of adult wolf in Mayer Aquarium equals 2 times the sum of the total number of adult animals in Bundle Ranch, the total number of adult animals in South Zoo, and the number of adult bear in South Zoo. The number of adult deer in Bundle Ranch equals 4 times the total number of adult animals in South Zoo.

Question: What is the total number of adult animals in Mayer Aquarium?

Solution: Define adult bear in South Zoo as Q; so Q = 2. Define total number of adult animals in South Zoo as s; so s = Q = 2. Define adult deer in Bundle Ranch as d; w = s = 2; so d = 4 * w = 4 * 2 = 8. Define total number of adult animals in Bundle Ranch as e; so e = d = 8. Define adult wolf in Mayer Aquarium as l; C = e + s = 8 + 2 = 10; N = C + Q = 10 + 2 = 12; so l = 2 * N = 2 * 12 = 24. Define total number of adult animals in Mayer Aquarium as H; so H = l = 24. Answer: 24.


The number of elementary school in Riverton City equals 3 plus the number of culinarian school in Ruby Bay. The number of culinarian school in Riverton City equals 2 times the total number of schools in Ruby Bay. The number of culinarian school in Ruby Bay equals 4. The number of elementary school in Ruby Bay equals the number of culinarian school in Ruby Bay.

Question: What is the total number of schools in Riverton City?

Solution: Define culinarian school in Ruby Bay as d; so d = 4. Define elementary school in Ruby Bay as m; so m = d = 4. Define total number of schools in Ruby Bay as e; so e = m + d = 4 + 4 = 8. Define culinarian school in Riverton City as K; Z = e = 8; so K = 2 * Z = 2 * 8 = 16. Define elementary school in Riverton City as O; E = d = 4; so O = 3 + E = 3 + 4 = 7. Define total number of schools in Riverton City as J; so J = O + K = 7 + 16 = 23. Answer: 23.


The number of upbeat metropolis comedy in Rêves de Belleville equals 3 times the sum of the number of upbeat metropolis comedy in Festival Lumière de Valmont, the number of calm road movie in Festival de Saint-Rivage, and the total number of movies in Festival de Saint-Rivage. The number of upbeat metropolis comedy in Festival Lumière de Valmont equals 3 plus the difference between the total number of movies in Festival de Saint-Rivage and the number of calm road movie in Festival de Saint-Rivage. The number of calm road movie in Festival de Saint-Rivage equals 3.

Question: What is the total number of movies in Rêves de Belleville?

Solution: Define calm road movie in Festival de Saint-Rivage as z; so z = 3. Define total number of movies in Festival de Saint-Rivage as j; so j = z = 3. Define upbeat metropolis comedy in Festival Lumière de Valmont as B; n = j - z = 3 - 3 = 0; so B = 3 + n = 3 + 0 = 3. Define upbeat metropolis comedy in Rêves de Belleville as u; r = B + z = 3 + 3 = 6; S = r + j = 6 + 3 = 9; so u = 3 * S = 3 * 9 = 27. Define total number of movies in Rêves de Belleville as e; so e = u = 27. Answer: 27.


The number of solemn period drama in Golden Banana Movie Festival equals 2 times the number of solemn period drama in Verdi Movie Festival. The number of calm road movie in Verdi Movie Festival equals the number of calm road movie in West Sahara Movie Festival. The number of solemn period drama in West Sahara Movie Festival equals 4. The number of calm road movie in West Sahara Movie Festival equals 2. The number of solemn period drama in Verdi Movie Festival equals 1. The number of futuristic sci-fi movie in Verdi Movie Festival equals 4. The number of futuristic sci-fi movie in Golden Banana Movie Festival equals 3. The number of calm road movie in Golden Banana Movie Festival equals 3 times the sum of the number of solemn period drama in Verdi Movie Festival and the number of solemn period drama in Golden Banana Movie Festival. The number of futuristic sci-fi movie in West Sahara Movie Festival equals 2 times the sum of the number of calm road movie in Verdi Movie Festival, the total number of movies in Verdi Movie Festival, and the number of solemn period drama in Golden Banana Movie Festival.

Question: What is the total number of movies in Golden Banana Movie Festival?

Solution: Define solemn period drama in Verdi Movie Festival as z; so z = 1. Define solemn period drama in Golden Banana Movie Festival as g; X = z = 1; so g = 2 * X = 2 * 1 = 2. Define calm road movie in Golden Banana Movie Festival as G; r = z + g = 1 + 2 = 3; so G = 3 * r = 3 * 3 = 9. Define futuristic sci-fi movie in Golden Banana Movie Festival as H; so H = 3. Define total number of movies in Golden Banana Movie Festival as I; K = g + G = 2 + 9 = 11; so I = K + H = 11 + 3 = 14. Answer: 14.


The number of private middle school in Riverton City equals the number of elementary school in Riverton City. The number of elementary school in Oakbridge City equals the total number of schools in Riverton City. The number of culinarian school in Riverton City equals 2 times the number of private middle school in Riverton City. The number of elementary school in Ruby Bay equals 4. The number of culinarian school in Clearwater Bay equals 3. The number of culinarian school in Ruby Bay equals 2 times the sum of the total number of schools in Riverton City and the number of culinarian school in Riverton City. The number of elementary school in Riverton City equals 2. The number of public highschool in Oakbridge City equals the difference between the number of culinarian school in Riverton City and the number of elementary school in Riverton City. The number of private middle school in Ruby Bay equals 3. The number of private middle school in Oakbridge City equals 2. The number of private middle school in Clearwater Bay equals 2. The number of public highschool in Clearwater Bay equals the number of private middle school in Ruby Bay. The number of culinarian school in Oakbridge City equals the sum of the total number of schools in Riverton City, the number of private middle school in Riverton City, the total number of schools in Ruby Bay, and the number of culinarian school in Ruby Bay. The number of elementary school in Clearwater Bay equals 3 plus the sum of the number of private middle school in Clearwater Bay and the number of culinarian school in Ruby Bay.

Question: How many culinarian school does Ruby Bay have?

Solution: Define elementary school in Riverton City as W; so W = 2. Define private middle school in Riverton City as v; so v = W = 2. Define culinarian school in Riverton City as Z; E = v = 2; so Z = 2 * E = 2 * 2 = 4. Define total number of schools in Riverton City as n; c = Z + W = 4 + 2 = 6; so n = c + v = 6 + 2 = 8. Define culinarian school in Ruby Bay as i; O = n + Z = 8 + 4 = 12; so i = 2 * O = 2 * 12 = 24. Answer: 24.


The number of adult crow in Jefferson Circus equals 3 times the number of adult owl in South Zoo. The number of adult owl in South Zoo equals the number of adult owl in Jefferson Circus. The number of adult owl in Jefferson Circus equals 3. The number of adult crow in South Zoo equals 3 times the sum of the number of adult crow in Jefferson Circus, the number of adult owl in Jefferson Circus, and the number of adult owl in South Zoo.

Question: What is the total number of adult animals in South Zoo?

Solution: Define adult owl in Jefferson Circus as L; so L = 3. Define adult owl in South Zoo as G; so G = L = 3. Define adult crow in Jefferson Circus as Q; B = G = 3; so Q = 3 * B = 3 * 3 = 9. Define adult crow in South Zoo as V; w = Q + L = 9 + 3 = 12; P = w + G = 12 + 3 = 15; so V = 3 * P = 3 * 15 = 45. Define total number of adult animals in South Zoo as T; so T = G + V = 3 + 45 = 48. Answer: 48.


The number of private middle school in Evervale City equals 2. The number of public highschool in Westhaven City equals the sum of the number of elementary school in Westhaven City, the number of elementary school in Evervale City, and the total number of schools in Brightford. The number of elementary school in Westhaven City equals 2 times the sum of the total number of schools in Brightford, the number of elementary school in Evervale City, and the number of public highschool in Brightford. The number of public highschool in Brightford equals the number of elementary school in Evervale City. The number of elementary school in Evervale City equals 2. The number of public highschool in Evervale City equals 4 times the number of private middle school in Evervale City.

Question: How many public highschool does Westhaven City have?

Solution: Define elementary school in Evervale City as E; so E = 2. Define public highschool in Brightford as D; so D = E = 2. Define total number of schools in Brightford as I; so I = D = 2. Define elementary school in Westhaven City as s; n = I + E = 2 + 2 = 4; q = n + D = 4 + 2 = 6; so s = 2 * q = 2 * 6 = 12. Define public highschool in Westhaven City as P; o = s + E = 12 + 2 = 14; so P = o + I = 14 + 2 = 16. Answer: 16.


The number of public highschool in Brightford equals 2. The number of public highschool in Hawkesbury equals the sum of the number of private middle school in Hawkesbury, the number of public highschool in Brightford, and the total number of schools in Brightford. The number of private middle school in Hawkesbury equals 4 plus the difference between the total number of schools in Brightford and the number of public highschool in Brightford.

Question: What is the total number of schools in Hawkesbury?

Solution: Define public highschool in Brightford as z; so z = 2. Define total number of schools in Brightford as B; so B = z = 2. Define private middle school in Hawkesbury as d; P = B - z = 2 - 2 = 0; so d = 4 + P = 4 + 0 = 4. Define public highschool in Hawkesbury as k; V = d + z = 4 + 2 = 6; so k = V + B = 6 + 2 = 8. Define total number of schools in Hawkesbury as M; so M = d + k = 4 + 8 = 12. Answer: 12.


The number of elementary school in Shoreline City equals the sum of the total number of schools in Riverton City, the number of elementary school in Riverton City, and the number of private middle school in Riverton City. The number of private middle school in Shoreline City equals the total number of schools in Riverton City. The number of private middle school in Riverton City equals the number of elementary school in Riverton City. The number of elementary school in Riverton City equals 3.

Question: What is the total number of schools in Shoreline City?

Solution: Define elementary school in Riverton City as W; so W = 3. Define private middle school in Riverton City as v; so v = W = 3. Define total number of schools in Riverton City as z; so z = W + v = 3 + 3 = 6. Define elementary school in Shoreline City as I; F = z + W = 6 + 3 = 9; so I = F + v = 9 + 3 = 12. Define private middle school in Shoreline City as f; so f = z = 6. Define total number of schools in Shoreline City as R; so R = f + I = 6 + 12 = 18. Answer: 18.


The number of adult parrot in Beverly Forest equals 2. The number of adult parrot in Maple Creek equals 3 times the number of adult parrot in Beverly Forest. The number of adult owl in Maple Creek equals the difference between the number of adult parrot in Maple Creek and the number of adult parrot in Beverly Forest. The number of adult owl in Beverly Forest equals the total number of adult animals in Maple Creek.

Question: What is the total number of adult animals in Beverly Forest?

Solution: Define adult parrot in Beverly Forest as p; so p = 2. Define adult parrot in Maple Creek as S; Q = p = 2; so S = 3 * Q = 3 * 2 = 6. Define adult owl in Maple Creek as k; so k = S - p = 6 - 2 = 4. Define total number of adult animals in Maple Creek as h; so h = k + S = 4 + 6 = 10. Define adult owl in Beverly Forest as O; so O = h = 10. Define total number of adult animals in Beverly Forest as v; so v = O + p = 10 + 2 = 12. Answer: 12.


The number of adult bear in South Zoo equals 3 times the sum of the number of adult racoon in South Zoo and the total number of adult animals in Bundle Ranch. The number of adult bear in Bundle Ranch equals 4. The number of adult racoon in South Zoo equals 2 plus the difference between the total number of adult animals in Bundle Ranch and the number of adult bear in Bundle Ranch.

Question: What is the total number of adult animals in South Zoo?

Solution: Define adult bear in Bundle Ranch as F; so F = 4. Define total number of adult animals in Bundle Ranch as q; so q = F = 4. Define adult racoon in South Zoo as n; h = q - F = 4 - 4 = 0; so n = 2 + h = 2 + 0 = 2. Define adult bear in South Zoo as R; c = n + q = 2 + 4 = 6; so R = 3 * c = 3 * 6 = 18. Define total number of adult animals in South Zoo as Z; so Z = n + R = 2 + 18 = 20. Answer: 20.


The number of adult eagle in Mayer Aquarium equals 1. The number of adult crow in Mayer Aquarium equals 4 plus the number of adult eagle in Mayer Aquarium. The number of adult crow in Bundle Ranch equals 3 times the sum of the total number of adult animals in Mayer Aquarium, the number of adult eagle in Mayer Aquarium, and the number of adult crow in Mayer Aquarium.

Question: What is the total number of adult animals in Bundle Ranch?

Solution: Define adult eagle in Mayer Aquarium as A; so A = 1. Define adult crow in Mayer Aquarium as f; q = A = 1; so f = 4 + q = 4 + 1 = 5. Define total number of adult animals in Mayer Aquarium as H; so H = f + A = 5 + 1 = 6. Define adult crow in Bundle Ranch as K; n = H + A = 6 + 1 = 7; C = n + f = 7 + 5 = 12; so K = 3 * C = 3 * 12 = 36. Define total number of adult animals in Bundle Ranch as x; so x = K = 36. Answer: 36.


The number of adult blue jay in Hamilton Farm equals 2 times the number of adult parrot in Hamilton Farm. The number of adult blue jay in Mayer Aquarium equals 4 times the total number of adult animals in Hamilton Farm. The number of adult parrot in Hamilton Farm equals 2. The number of adult parrot in Mayer Aquarium equals the number of adult blue jay in Hamilton Farm.

Question: What is the total number of adult animals in Mayer Aquarium?

Solution: Define adult parrot in Hamilton Farm as v; so v = 2. Define adult blue jay in Hamilton Farm as P; O = v = 2; so P = 2 * O = 2 * 2 = 4. Define total number of adult animals in Hamilton Farm as U; so U = v + P = 2 + 4 = 6. Define adult blue jay in Mayer Aquarium as X; j = U = 6; so X = 4 * j = 4 * 6 = 24. Define adult parrot in Mayer Aquarium as i; so i = P = 4. Define total number of adult animals in Mayer Aquarium as I; so I = i + X = 4 + 24 = 28. Answer: 28.


The number of intense detective thriller in Northwood Movie Festival equals 2 times the number of futuristic sci-fi movie in Northwood Movie Festival. The number of upbeat metropolis comedy in West Sahara Movie Festival equals 4. The number of calm road movie in Northwood Movie Festival equals 2. The number of solemn period drama in West Sahara Movie Festival equals the number of upbeat metropolis comedy in West Sahara Movie Festival. The number of solemn period drama in Northwood Movie Festival equals 2. The number of upbeat metropolis comedy in Northwood Movie Festival equals 1 plus the sum of the number of intense detective thriller in Northwood Movie Festival and the number of solemn period drama in West Sahara Movie Festival. The number of futuristic sci-fi movie in Northwood Movie Festival equals the total number of movies in West Sahara Movie Festival.

Question: How many upbeat metropolis comedy does Northwood Movie Festival have?

Solution: Define upbeat metropolis comedy in West Sahara Movie Festival as a; so a = 4. Define solemn period drama in West Sahara Movie Festival as q; so q = a = 4. Define total number of movies in West Sahara Movie Festival as y; so y = a + q = 4 + 4 = 8. Define futuristic sci-fi movie in Northwood Movie Festival as t; so t = y = 8. Define intense detective thriller in Northwood Movie Festival as S; u = t = 8; so S = 2 * u = 2 * 8 = 16. Define upbeat metropolis comedy in Northwood Movie Festival as C; i = S + q = 16 + 4 = 20; so C = 1 + i = 1 + 20 = 21. Answer: 21.


The number of adult blue jay in Cedar Valley equals 2. The number of adult crow in Beverly Forest equals 3 times the sum of the total number of adult animals in Cedar Valley and the number of adult crow in Cedar Valley. The number of adult crow in Cedar Valley equals 4. The number of adult blue jay in Beverly Forest equals the number of adult blue jay in Cedar Valley.

Question: What is the total number of adult animals in Beverly Forest?

Solution: Define adult blue jay in Cedar Valley as Y; so Y = 2. Define adult crow in Cedar Valley as G; so G = 4. Define total number of adult animals in Cedar Valley as q; so q = G + Y = 4 + 2 = 6. Define adult crow in Beverly Forest as e; w = q + G = 6 + 4 = 10; so e = 3 * w = 3 * 10 = 30. Define adult blue jay in Beverly Forest as B; so B = Y = 2. Define total number of adult animals in Beverly Forest as i; so i = e + B = 30 + 2 = 32. Answer: 32.


The number of intense detective thriller in Verdi Movie Festival equals 3 plus the difference between the total number of movies in West Sahara Movie Festival and the number of calm road movie in West Sahara Movie Festival. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 2 times the sum of the total number of movies in Verdi Movie Festival and the number of intense detective thriller in Verdi Movie Festival. The number of calm road movie in West Sahara Movie Festival equals 3.

Question: What is the total number of movies in Golden Banana Movie Festival?

Solution: Define calm road movie in West Sahara Movie Festival as I; so I = 3. Define total number of movies in West Sahara Movie Festival as e; so e = I = 3. Define intense detective thriller in Verdi Movie Festival as j; D = e - I = 3 - 3 = 0; so j = 3 + D = 3 + 0 = 3. Define total number of movies in Verdi Movie Festival as i; so i = j = 3. Define upbeat metropolis comedy in Golden Banana Movie Festival as y; h = i + j = 3 + 3 = 6; so y = 2 * h = 2 * 6 = 12. Define total number of movies in Golden Banana Movie Festival as r; so r = y = 12. Answer: 12.


The number of culinarian school in Glenfield City equals 2 plus the sum of the total number of schools in Hawkesbury, the number of culinarian school in Hawkesbury, and the number of private middle school in Hawkesbury. The number of culinarian school in Hawkesbury equals 3. The number of private middle school in Hawkesbury equals 3 plus the number of culinarian school in Hawkesbury.

Question: What is the total number of schools in Glenfield City?

Solution: Define culinarian school in Hawkesbury as m; so m = 3. Define private middle school in Hawkesbury as u; y = m = 3; so u = 3 + y = 3 + 3 = 6. Define total number of schools in Hawkesbury as V; so V = u + m = 6 + 3 = 9. Define culinarian school in Glenfield City as e; t = V + m = 9 + 3 = 12; d = t + u = 12 + 6 = 18; so e = 2 + d = 2 + 18 = 20. Define total number of schools in Glenfield City as l; so l = e = 20. Answer: 20.


The number of adult racoon in Pine Ridge equals 2 times the number of adult wolf in Pine Ridge. The number of adult deer in Pine Ridge equals 2. The number of adult wolf in Pine Ridge equals 4 times the number of adult deer in Pine Ridge. The number of adult wolf in Maple Creek equals the total number of adult animals in Pine Ridge.

Question: What is the total number of adult animals in Maple Creek?

Solution: Define adult deer in Pine Ridge as T; so T = 2. Define adult wolf in Pine Ridge as c; b = T = 2; so c = 4 * b = 4 * 2 = 8. Define adult racoon in Pine Ridge as J; G = c = 8; so J = 2 * G = 2 * 8 = 16. Define total number of adult animals in Pine Ridge as w; W = J + T = 16 + 2 = 18; so w = W + c = 18 + 8 = 26. Define adult wolf in Maple Creek as s; so s = w = 26. Define total number of adult animals in Maple Creek as V; so V = s = 26. Answer: 26.


The number of elementary school in Evervale City equals 4 plus the number of elementary school in Westhaven City. The number of private middle school in Evervale City equals the total number of schools in Westhaven City. The number of elementary school in Westhaven City equals 2. The number of private middle school in Westhaven City equals 2 times the number of elementary school in Westhaven City.

Question: What is the total number of schools in Evervale City?

Solution: Define elementary school in Westhaven City as j; so j = 2. Define private middle school in Westhaven City as N; g = j = 2; so N = 2 * g = 2 * 2 = 4. Define total number of schools in Westhaven City as l; so l = N + j = 4 + 2 = 6. Define private middle school in Evervale City as s; so s = l = 6. Define elementary school in Evervale City as E; c = j = 2; so E = 4 + c = 4 + 2 = 6. Define total number of schools in Evervale City as h; so h = s + E = 6 + 6 = 12. Answer: 12.