The number of futuristic sci-fi movie in West Sahara Movie Festival equals 4. The number of futuristic sci-fi movie in Northwood Movie Festival equals the number of futuristic sci-fi movie in Verdi Movie Festival. The number of calm road movie in Verdi Movie Festival equals the sum of the total number of movies in Northwood Movie Festival, the number of futuristic sci-fi movie in Northwood Movie Festival, the number of intense detective thriller in Northwood Movie Festival, and the number of futuristic sci-fi movie in Verdi Movie Festival. The number of futuristic sci-fi movie in Verdi Movie Festival equals 3. The number of intense detective thriller in West Sahara Movie Festival equals the sum of the total number of movies in West Sahara Movie Festival, the number of futuristic sci-fi movie in Northwood Movie Festival, and the number of intense detective thriller in Northwood Movie Festival. The number of intense detective thriller in Northwood Movie Festival equals 3 plus the difference between the number of futuristic sci-fi movie in Verdi Movie Festival and the number of futuristic sci-fi movie in Northwood Movie Festival. The number of intense detective thriller in Verdi Movie Festival equals the sum of the total number of movies in Northwood Movie Festival, the number of intense detective thriller in Northwood Movie Festival, and the number of futuristic sci-fi movie in Verdi Movie Festival. The number of calm road movie in West Sahara Movie Festival equals 3.

Question: How many intense detective thriller does Verdi Movie Festival have?

Solution: Define futuristic sci-fi movie in Verdi Movie Festival as Y; so Y = 3. Define futuristic sci-fi movie in Northwood Movie Festival as T; so T = Y = 3. Define intense detective thriller in Northwood Movie Festival as s; D = Y - T = 3 - 3 = 0; so s = 3 + D = 3 + 0 = 3. Define total number of movies in Northwood Movie Festival as H; so H = T + s = 3 + 3 = 6. Define intense detective thriller in Verdi Movie Festival as M; i = H + s = 6 + 3 = 9; so M = i + Y = 9 + 3 = 12. Answer: 12.


The number of upbeat metropolis comedy in Festival de Saint-Rivage equals 2 times the sum of the number of calm road movie in Cinéma de Montreval and the number of upbeat metropolis comedy in Cinéma de Montreval. The number of upbeat metropolis comedy in Cinéma de Montreval equals 2. The number of calm road movie in Festival de Saint-Rivage equals 1 plus the sum of the number of upbeat metropolis comedy in Cinéma de Montreval and the number of upbeat metropolis comedy in Festival de Saint-Rivage. The number of calm road movie in Cinéma de Montreval equals the number of upbeat metropolis comedy in Cinéma de Montreval.

Question: What is the total number of movies in Festival de Saint-Rivage?

Solution: Define upbeat metropolis comedy in Cinéma de Montreval as T; so T = 2. Define calm road movie in Cinéma de Montreval as Z; so Z = T = 2. Define upbeat metropolis comedy in Festival de Saint-Rivage as m; I = Z + T = 2 + 2 = 4; so m = 2 * I = 2 * 4 = 8. Define calm road movie in Festival de Saint-Rivage as S; W = T + m = 2 + 8 = 10; so S = 1 + W = 1 + 10 = 11. Define total number of movies in Festival de Saint-Rivage as B; so B = S + m = 11 + 8 = 19. Answer: 19.


The number of adult racoon in Mayer Aquarium equals 3 times the total number of adult animals in South Zoo. The number of adult fox in South Zoo equals 3. The number of adult racoon in South Zoo equals 2 plus the number of adult fox in South Zoo. The number of adult fox in Mayer Aquarium equals the number of adult racoon in South Zoo.

Question: What is the total number of adult animals in Mayer Aquarium?

Solution: Define adult fox in South Zoo as V; so V = 3. Define adult racoon in South Zoo as P; F = V = 3; so P = 2 + F = 2 + 3 = 5. Define total number of adult animals in South Zoo as l; so l = P + V = 5 + 3 = 8. Define adult racoon in Mayer Aquarium as H; G = l = 8; so H = 3 * G = 3 * 8 = 24. Define adult fox in Mayer Aquarium as Y; so Y = P = 5. Define total number of adult animals in Mayer Aquarium as t; so t = H + Y = 24 + 5 = 29. Answer: 29.


The number of adult parrot in Bundle Ranch equals the sum of the number of adult crow in South Zoo, the number of adult parrot in South Zoo, and the total number of adult animals in Hamilton Farm. The number of adult parrot in Jefferson Circus equals 4. The number of adult crow in South Zoo equals 3. The number of adult blue jay in South Zoo equals the sum of the number of adult crow in South Zoo and the number of adult parrot in South Zoo. The number of adult owl in Mayer Aquarium equals 4 plus the number of adult eagle in Jefferson Circus. The number of adult eagle in Jefferson Circus equals 3. The number of adult parrot in South Zoo equals 4. The number of adult eagle in Hamilton Farm equals 3 times the total number of adult animals in South Zoo.

Question: What is the total number of adult animals in Hamilton Farm?

Solution: Define adult parrot in South Zoo as x; so x = 4. Define adult crow in South Zoo as P; so P = 3. Define adult blue jay in South Zoo as h; so h = P + x = 3 + 4 = 7. Define total number of adult animals in South Zoo as b; G = h + x = 7 + 4 = 11; so b = G + P = 11 + 3 = 14. Define adult eagle in Hamilton Farm as Y; d = b = 14; so Y = 3 * d = 3 * 14 = 42. Define total number of adult animals in Hamilton Farm as p; so p = Y = 42. Answer: 42.


The number of adult racoon in Mayer Aquarium equals 4 times the number of adult racoon in Jefferson Circus. The number of adult racoon in Jefferson Circus equals 4. The number of adult bear in Mayer Aquarium equals 3 plus the sum of the total number of adult animals in Jefferson Circus, the number of adult racoon in Jefferson Circus, and the number of adult racoon in Mayer Aquarium.

Question: What is the total number of adult animals in Mayer Aquarium?

Solution: Define adult racoon in Jefferson Circus as Q; so Q = 4. Define adult racoon in Mayer Aquarium as W; C = Q = 4; so W = 4 * C = 4 * 4 = 16. Define total number of adult animals in Jefferson Circus as u; so u = Q = 4. Define adult bear in Mayer Aquarium as n; i = u + Q = 4 + 4 = 8; j = i + W = 8 + 16 = 24; so n = 3 + j = 3 + 24 = 27. Define total number of adult animals in Mayer Aquarium as d; so d = W + n = 16 + 27 = 43. Answer: 43.


The number of futuristic sci-fi movie in West Sahara Movie Festival equals 4. The number of solemn period drama in Northwood Movie Festival equals 4 times the sum of the total number of movies in West Sahara Movie Festival and the number of futuristic sci-fi movie in West Sahara Movie Festival. The number of futuristic sci-fi movie in Northwood Movie Festival equals 4 plus the sum of the number of solemn period drama in Northwood Movie Festival and the total number of movies in West Sahara Movie Festival.

Question: What is the total number of movies in Northwood Movie Festival?

Solution: Define futuristic sci-fi movie in West Sahara Movie Festival as D; so D = 4. Define total number of movies in West Sahara Movie Festival as V; so V = D = 4. Define solemn period drama in Northwood Movie Festival as s; z = V + D = 4 + 4 = 8; so s = 4 * z = 4 * 8 = 32. Define futuristic sci-fi movie in Northwood Movie Festival as t; C = s + V = 32 + 4 = 36; so t = 4 + C = 4 + 36 = 40. Define total number of movies in Northwood Movie Festival as O; so O = t + s = 40 + 32 = 72. Answer: 72.


The number of adult wolf in Jefferson Circus equals 3. The number of adult racoon in Hamilton Farm equals the difference between the total number of adult animals in Jefferson Circus and the number of adult racoon in Jefferson Circus. The number of adult wolf in Hamilton Farm equals 2. The number of adult racoon in Jefferson Circus equals 1 plus the number of adult wolf in Jefferson Circus.

Question: What is the total number of adult animals in Hamilton Farm?

Solution: Define adult wolf in Jefferson Circus as h; so h = 3. Define adult racoon in Jefferson Circus as f; c = h = 3; so f = 1 + c = 1 + 3 = 4. Define total number of adult animals in Jefferson Circus as V; so V = h + f = 3 + 4 = 7. Define adult racoon in Hamilton Farm as G; so G = V - f = 7 - 4 = 3. Define adult wolf in Hamilton Farm as I; so I = 2. Define total number of adult animals in Hamilton Farm as J; so J = I + G = 2 + 3 = 5. Answer: 5.


The number of adult parrot in Bundle Ranch equals 3. The number of adult crow in South Zoo equals the sum of the total number of adult animals in Jefferson Circus and the number of adult owl in Jefferson Circus. The number of adult parrot in Hamilton Farm equals 2 plus the number of adult crow in South Zoo. The number of adult owl in Jefferson Circus equals 2 times the number of adult parrot in Jefferson Circus. The number of adult crow in Bundle Ranch equals 2 plus the number of adult parrot in Bundle Ranch. The number of adult parrot in Jefferson Circus equals 3. The number of adult blue jay in Hamilton Farm equals the difference between the total number of adult animals in Bundle Ranch and the total number of adult animals in Jefferson Circus. The number of adult owl in South Zoo equals the number of adult owl in Jefferson Circus.

Question: What is the total number of adult animals in South Zoo?

Solution: Define adult parrot in Jefferson Circus as d; so d = 3. Define adult owl in Jefferson Circus as T; z = d = 3; so T = 2 * z = 2 * 3 = 6. Define total number of adult animals in Jefferson Circus as h; so h = d + T = 3 + 6 = 9. Define adult crow in South Zoo as E; so E = h + T = 9 + 6 = 15. Define adult owl in South Zoo as R; so R = T = 6. Define total number of adult animals in South Zoo as x; so x = R + E = 6 + 15 = 21. Answer: 21.


The number of adult parrot in Mayer Aquarium equals 4 plus the difference between the total number of adult animals in Bundle Ranch and the number of adult parrot in Bundle Ranch. The number of adult eagle in Mayer Aquarium equals 1 plus the sum of the number of adult parrot in Mayer Aquarium and the total number of adult animals in Bundle Ranch. The number of adult parrot in Bundle Ranch equals 2.

Question: What is the total number of adult animals in Mayer Aquarium?

Solution: Define adult parrot in Bundle Ranch as u; so u = 2. Define total number of adult animals in Bundle Ranch as F; so F = u = 2. Define adult parrot in Mayer Aquarium as o; S = F - u = 2 - 2 = 0; so o = 4 + S = 4 + 0 = 4. Define adult eagle in Mayer Aquarium as y; B = o + F = 4 + 2 = 6; so y = 1 + B = 1 + 6 = 7. Define total number of adult animals in Mayer Aquarium as A; so A = o + y = 4 + 7 = 11. Answer: 11.


The number of public highschool in Riverton City equals 4. The number of regional medical school in Ruby Bay equals 2. The number of private middle school in Oakbridge City equals the sum of the total number of schools in Clearwater Bay, the number of regional medical school in Clearwater Bay, the number of culinarian school in Clearwater Bay, and the number of public highschool in Clearwater Bay. The number of culinarian school in Clearwater Bay equals the number of public highschool in Clearwater Bay. The number of regional medical school in Clearwater Bay equals the number of culinarian school in Clearwater Bay. The number of private middle school in Ruby Bay equals 3. The number of culinarian school in Oakbridge City equals the number of public highschool in Clearwater Bay. The number of culinarian school in Riverton City equals the sum of the number of private middle school in Oakbridge City, the number of regional medical school in Clearwater Bay, the total number of schools in Ruby Bay, and the total number of schools in Clearwater Bay. The number of public highschool in Ruby Bay equals 4. The number of culinarian school in Ruby Bay equals 1. The number of regional medical school in Oakbridge City equals the number of regional medical school in Ruby Bay. The number of public highschool in Clearwater Bay equals 3.

Question: How many private middle school does Oakbridge City have?

Solution: Define public highschool in Clearwater Bay as b; so b = 3. Define culinarian school in Clearwater Bay as Q; so Q = b = 3. Define regional medical school in Clearwater Bay as Y; so Y = Q = 3. Define total number of schools in Clearwater Bay as o; v = b + Q = 3 + 3 = 6; so o = v + Y = 6 + 3 = 9. Define private middle school in Oakbridge City as M; t = o + Y = 9 + 3 = 12; k = t + Q = 12 + 3 = 15; so M = k + b = 15 + 3 = 18. Answer: 18.


The number of private middle school in Ruby Bay equals 2 plus the difference between the number of private middle school in Riverton City and the number of culinarian school in Ruby Bay. The number of elementary school in Oakbridge City equals 3. The number of culinarian school in Riverton City equals 2 times the number of private middle school in Riverton City. The number of regional medical school in Clearwater Bay equals 2 plus the difference between the total number of schools in Oakbridge City and the number of elementary school in Oakbridge City. The number of culinarian school in Clearwater Bay equals 2. The number of regional medical school in Riverton City equals 4. The number of elementary school in Riverton City equals 2. The number of culinarian school in Oakbridge City equals 1. The number of private middle school in Riverton City equals 3. The number of culinarian school in Ruby Bay equals the number of culinarian school in Riverton City.

Question: What is the total number of schools in Clearwater Bay?

Solution: Define elementary school in Oakbridge City as w; so w = 3. Define culinarian school in Oakbridge City as c; so c = 1. Define total number of schools in Oakbridge City as e; so e = c + w = 1 + 3 = 4. Define regional medical school in Clearwater Bay as V; z = e - w = 4 - 3 = 1; so V = 2 + z = 2 + 1 = 3. Define culinarian school in Clearwater Bay as q; so q = 2. Define total number of schools in Clearwater Bay as E; so E = V + q = 3 + 2 = 5. Answer: 5.


The number of futuristic sci-fi movie in Northwood Movie Festival equals 3. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 2 times the sum of the total number of movies in Northwood Movie Festival, the number of futuristic sci-fi movie in Northwood Movie Festival, and the number of upbeat metropolis comedy in Northwood Movie Festival. The number of upbeat metropolis comedy in Northwood Movie Festival equals 1 plus the number of futuristic sci-fi movie in Northwood Movie Festival.

Question: What is the total number of movies in Golden Banana Movie Festival?

Solution: Define futuristic sci-fi movie in Northwood Movie Festival as u; so u = 3. Define upbeat metropolis comedy in Northwood Movie Festival as j; c = u = 3; so j = 1 + c = 1 + 3 = 4. Define total number of movies in Northwood Movie Festival as U; so U = u + j = 3 + 4 = 7. Define upbeat metropolis comedy in Golden Banana Movie Festival as n; B = U + u = 7 + 3 = 10; G = B + j = 10 + 4 = 14; so n = 2 * G = 2 * 14 = 28. Define total number of movies in Golden Banana Movie Festival as d; so d = n = 28. Answer: 28.


The number of adult owl in Jefferson Circus equals 3 plus the sum of the total number of adult animals in South Zoo, the number of adult blue jay in South Zoo, and the number of adult owl in South Zoo. The number of adult blue jay in South Zoo equals 4. The number of adult owl in South Zoo equals 1 plus the number of adult blue jay in South Zoo.

Question: What is the total number of adult animals in Jefferson Circus?

Solution: Define adult blue jay in South Zoo as C; so C = 4. Define adult owl in South Zoo as y; l = C = 4; so y = 1 + l = 1 + 4 = 5. Define total number of adult animals in South Zoo as e; so e = C + y = 4 + 5 = 9. Define adult owl in Jefferson Circus as n; U = e + C = 9 + 4 = 13; h = U + y = 13 + 5 = 18; so n = 3 + h = 3 + 18 = 21. Define total number of adult animals in Jefferson Circus as x; so x = n = 21. Answer: 21.


The number of private middle school in Evervale City equals 2 plus the total number of schools in Glenfield City. The number of culinarian school in Glenfield City equals 1. The number of culinarian school in Evervale City equals 4 plus the number of culinarian school in Glenfield City. The number of private middle school in Glenfield City equals the number of culinarian school in Glenfield City.

Question: What is the total number of schools in Evervale City?

Solution: Define culinarian school in Glenfield City as t; so t = 1. Define private middle school in Glenfield City as w; so w = t = 1. Define total number of schools in Glenfield City as p; so p = t + w = 1 + 1 = 2. Define private middle school in Evervale City as j; U = p = 2; so j = 2 + U = 2 + 2 = 4. Define culinarian school in Evervale City as G; N = t = 1; so G = 4 + N = 4 + 1 = 5. Define total number of schools in Evervale City as g; so g = G + j = 5 + 4 = 9. Answer: 9.


The number of futuristic sci-fi movie in West Sahara Movie Festival equals 2 times the number of solemn period drama in Northwood Movie Festival. The number of futuristic sci-fi movie in Northwood Movie Festival equals the sum of the total number of movies in West Sahara Movie Festival and the number of solemn period drama in Northwood Movie Festival. The number of solemn period drama in West Sahara Movie Festival equals the number of futuristic sci-fi movie in West Sahara Movie Festival. The number of solemn period drama in Northwood Movie Festival equals 3.

Question: What is the total number of movies in Northwood Movie Festival?

Solution: Define solemn period drama in Northwood Movie Festival as r; so r = 3. Define futuristic sci-fi movie in West Sahara Movie Festival as X; i = r = 3; so X = 2 * i = 2 * 3 = 6. Define solemn period drama in West Sahara Movie Festival as w; so w = X = 6. Define total number of movies in West Sahara Movie Festival as W; so W = X + w = 6 + 6 = 12. Define futuristic sci-fi movie in Northwood Movie Festival as q; so q = W + r = 12 + 3 = 15. Define total number of movies in Northwood Movie Festival as j; so j = q + r = 15 + 3 = 18. Answer: 18.


The number of upbeat metropolis comedy in Northwood Movie Festival equals 3. The number of intense detective thriller in Verdi Movie Festival equals the number of calm road movie in Verdi Movie Festival. The number of solemn period drama in Verdi Movie Festival equals the number of calm road movie in Northwood Movie Festival. The number of calm road movie in Verdi Movie Festival equals the number of upbeat metropolis comedy in Verdi Movie Festival. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals the sum of the number of solemn period drama in Taylor Movie Festival, the number of solemn period drama in Golden Banana Movie Festival, and the number of intense detective thriller in Golden Banana Movie Festival. The number of calm road movie in Northwood Movie Festival equals 2. The number of calm road movie in Taylor Movie Festival equals 3. The number of intense detective thriller in Golden Banana Movie Festival equals 3. The number of solemn period drama in Golden Banana Movie Festival equals the number of intense detective thriller in Golden Banana Movie Festival. The number of upbeat metropolis comedy in Taylor Movie Festival equals 3 times the number of upbeat metropolis comedy in Verdi Movie Festival. The number of solemn period drama in Taylor Movie Festival equals 3. The number of upbeat metropolis comedy in Verdi Movie Festival equals the number of calm road movie in Northwood Movie Festival. The number of solemn period drama in Northwood Movie Festival equals the total number of movies in Verdi Movie Festival.

Question: How many solemn period drama does Northwood Movie Festival have?

Solution: Define calm road movie in Northwood Movie Festival as x; so x = 2. Define solemn period drama in Verdi Movie Festival as k; so k = x = 2. Define upbeat metropolis comedy in Verdi Movie Festival as j; so j = x = 2. Define calm road movie in Verdi Movie Festival as B; so B = j = 2. Define intense detective thriller in Verdi Movie Festival as X; so X = B = 2. Define total number of movies in Verdi Movie Festival as b; Z = X + B = 2 + 2 = 4; o = Z + k = 4 + 2 = 6; so b = o + j = 6 + 2 = 8. Define solemn period drama in Northwood Movie Festival as M; so M = b = 8. Answer: 8.


The number of public highschool in Riverton City equals 1 plus the number of culinarian school in Riverton City. The number of public highschool in Clearwater Bay equals 2 times the sum of the total number of schools in Riverton City, the number of culinarian school in Riverton City, and the number of public highschool in Riverton City. The number of culinarian school in Riverton City equals 2.

Question: What is the total number of schools in Clearwater Bay?

Solution: Define culinarian school in Riverton City as I; so I = 2. Define public highschool in Riverton City as t; D = I = 2; so t = 1 + D = 1 + 2 = 3. Define total number of schools in Riverton City as f; so f = I + t = 2 + 3 = 5. Define public highschool in Clearwater Bay as o; U = f + I = 5 + 2 = 7; Q = U + t = 7 + 3 = 10; so o = 2 * Q = 2 * 10 = 20. Define total number of schools in Clearwater Bay as e; so e = o = 20. Answer: 20.


The number of upbeat metropolis comedy in Cinéma de Montreval equals 4 plus the difference between the total number of movies in Festival de Saint-Rivage and the number of futuristic sci-fi movie in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Cinéma de Montreval equals 1. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals 4. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals the number of futuristic sci-fi movie in Cinéma de Montreval.

Question: What is the total number of movies in Cinéma de Montreval?

Solution: Define futuristic sci-fi movie in Cinéma de Montreval as W; so W = 1. Define futuristic sci-fi movie in Festival de Saint-Rivage as L; so L = 4. Define upbeat metropolis comedy in Festival de Saint-Rivage as Y; so Y = W = 1. Define total number of movies in Festival de Saint-Rivage as u; so u = Y + L = 1 + 4 = 5. Define upbeat metropolis comedy in Cinéma de Montreval as q; I = u - L = 5 - 4 = 1; so q = 4 + I = 4 + 1 = 5. Define total number of movies in Cinéma de Montreval as t; so t = q + W = 5 + 1 = 6. Answer: 6.


The number of calm road movie in Rêves de Belleville equals 3. The number of intense detective thriller in Cinéma de Montreval equals the sum of the number of calm road movie in Cinéma de Montreval, the total number of movies in Rêves de Belleville, and the number of calm road movie in Rêves de Belleville. The number of calm road movie in Cinéma de Montreval equals 4 plus the sum of the total number of movies in Rêves de Belleville and the number of calm road movie in Rêves de Belleville.

Question: What is the total number of movies in Cinéma de Montreval?

Solution: Define calm road movie in Rêves de Belleville as z; so z = 3. Define total number of movies in Rêves de Belleville as B; so B = z = 3. Define calm road movie in Cinéma de Montreval as a; b = B + z = 3 + 3 = 6; so a = 4 + b = 4 + 6 = 10. Define intense detective thriller in Cinéma de Montreval as y; F = a + B = 10 + 3 = 13; so y = F + z = 13 + 3 = 16. Define total number of movies in Cinéma de Montreval as S; so S = a + y = 10 + 16 = 26. Answer: 26.


The number of adult crow in Pine Ridge equals 2. The number of adult blue jay in Oakridge Riverside equals 4 plus the sum of the total number of adult animals in Pine Ridge and the number of adult crow in Pine Ridge. The number of adult eagle in Beverly Forest equals 4 times the sum of the total number of adult animals in Oakridge Riverside and the number of adult blue jay in Oakridge Riverside.

Question: What is the total number of adult animals in Beverly Forest?

Solution: Define adult crow in Pine Ridge as y; so y = 2. Define total number of adult animals in Pine Ridge as l; so l = y = 2. Define adult blue jay in Oakridge Riverside as M; k = l + y = 2 + 2 = 4; so M = 4 + k = 4 + 4 = 8. Define total number of adult animals in Oakridge Riverside as b; so b = M = 8. Define adult eagle in Beverly Forest as h; Q = b + M = 8 + 8 = 16; so h = 4 * Q = 4 * 16 = 64. Define total number of adult animals in Beverly Forest as A; so A = h = 64. Answer: 64.


The number of adult crow in Mayer Aquarium equals 3. The number of adult parrot in Mayer Aquarium equals 4. The number of adult crow in South Zoo equals 3 times the difference between the total number of adult animals in Mayer Aquarium and the number of adult parrot in Mayer Aquarium. The number of adult parrot in South Zoo equals 4.

Question: What is the total number of adult animals in South Zoo?

Solution: Define adult parrot in Mayer Aquarium as f; so f = 4. Define adult crow in Mayer Aquarium as n; so n = 3. Define total number of adult animals in Mayer Aquarium as I; so I = n + f = 3 + 4 = 7. Define adult crow in South Zoo as Q; c = I - f = 7 - 4 = 3; so Q = 3 * c = 3 * 3 = 9. Define adult parrot in South Zoo as O; so O = 4. Define total number of adult animals in South Zoo as d; so d = Q + O = 9 + 4 = 13. Answer: 13.


The number of adult bear in South Zoo equals the sum of the total number of adult animals in Bundle Ranch and the number of adult bear in Bundle Ranch. The number of adult bear in Bundle Ranch equals 1. The number of adult fox in South Zoo equals 3. The number of adult fox in Bundle Ranch equals 2 times the number of adult bear in Bundle Ranch.

Question: What is the total number of adult animals in South Zoo?

Solution: Define adult bear in Bundle Ranch as t; so t = 1. Define adult fox in Bundle Ranch as z; l = t = 1; so z = 2 * l = 2 * 1 = 2. Define total number of adult animals in Bundle Ranch as i; so i = t + z = 1 + 2 = 3. Define adult bear in South Zoo as j; so j = i + t = 3 + 1 = 4. Define adult fox in South Zoo as E; so E = 3. Define total number of adult animals in South Zoo as m; so m = j + E = 4 + 3 = 7. Answer: 7.


The number of calm road movie in Rêves de Belleville equals 3 plus the sum of the number of calm road movie in Cinéma de Montreval, the number of solemn period drama in Rêves de Belleville, and the number of upbeat metropolis comedy in Rêves de Belleville. The number of solemn period drama in Cinéma de Montreval equals the number of calm road movie in Cinéma de Montreval. The number of intense detective thriller in Festival Lumière de Valmont equals 1. The number of solemn period drama in Festival de Clairmont equals the number of intense detective thriller in Festival Lumière de Valmont. The number of solemn period drama in Rêves de Belleville equals 4. The number of upbeat metropolis comedy in Cinéma de Montreval equals the difference between the number of upbeat metropolis comedy in Rêves de Belleville and the number of calm road movie in Rêves de Belleville. The number of calm road movie in Festival de Clairmont equals 2. The number of calm road movie in Festival Lumière de Valmont equals 4. The number of intense detective thriller in Festival de Clairmont equals the number of upbeat metropolis comedy in Festival de Clairmont. The number of upbeat metropolis comedy in Festival de Clairmont equals the sum of the number of solemn period drama in Festival de Clairmont and the number of intense detective thriller in Festival Lumière de Valmont. The number of calm road movie in Cinéma de Montreval equals 4. The number of intense detective thriller in Cinéma de Montreval equals the sum of the number of solemn period drama in Cinéma de Montreval, the number of solemn period drama in Rêves de Belleville, the number of upbeat metropolis comedy in Rêves de Belleville, and the number of calm road movie in Rêves de Belleville. The number of solemn period drama in Festival Lumière de Valmont equals the sum of the number of solemn period drama in Rêves de Belleville, the total number of movies in Festival de Clairmont, the number of solemn period drama in Festival de Clairmont, and the number of intense detective thriller in Festival Lumière de Valmont. The number of intense detective thriller in Rêves de Belleville equals 4. The number of upbeat metropolis comedy in Rêves de Belleville equals 2 times the sum of the number of calm road movie in Cinéma de Montreval and the number of solemn period drama in Rêves de Belleville.

Question: What is the total number of movies in Festival de Clairmont?

Solution: Define intense detective thriller in Festival Lumière de Valmont as H; so H = 1. Define solemn period drama in Festival de Clairmont as V; so V = H = 1. Define calm road movie in Festival de Clairmont as y; so y = 2. Define upbeat metropolis comedy in Festival de Clairmont as r; so r = V + H = 1 + 1 = 2. Define intense detective thriller in Festival de Clairmont as Q; so Q = r = 2. Define total number of movies in Festival de Clairmont as a; m = V + y = 1 + 2 = 3; u = m + r = 3 + 2 = 5; so a = u + Q = 5 + 2 = 7. Answer: 7.


The number of adult bear in Hamilton Farm equals 1 plus the sum of the total number of adult animals in Jefferson Circus, the number of adult wolf in Jefferson Circus, and the number of adult bear in Mayer Aquarium. The number of adult bear in Mayer Aquarium equals 3. The number of adult fox in Mayer Aquarium equals the sum of the number of adult deer in Jefferson Circus, the total number of adult animals in Jefferson Circus, and the number of adult wolf in Jefferson Circus. The number of adult wolf in Jefferson Circus equals the number of adult deer in Jefferson Circus. The number of adult deer in Jefferson Circus equals 4 times the number of adult bear in Mayer Aquarium.

Question: How many adult bear does Hamilton Farm have?

Solution: Define adult bear in Mayer Aquarium as O; so O = 3. Define adult deer in Jefferson Circus as W; q = O = 3; so W = 4 * q = 4 * 3 = 12. Define adult wolf in Jefferson Circus as u; so u = W = 12. Define total number of adult animals in Jefferson Circus as F; so F = W + u = 12 + 12 = 24. Define adult bear in Hamilton Farm as N; j = F + u = 24 + 12 = 36; p = j + O = 36 + 3 = 39; so N = 1 + p = 1 + 39 = 40. Answer: 40.


The number of calm road movie in Taylor Movie Festival equals 2 plus the difference between the total number of movies in West Sahara Movie Festival and the number of calm road movie in West Sahara Movie Festival. The number of calm road movie in West Sahara Movie Festival equals 4. The number of intense detective thriller in Taylor Movie Festival equals the sum of the total number of movies in West Sahara Movie Festival, the number of calm road movie in West Sahara Movie Festival, and the number of calm road movie in Taylor Movie Festival.

Question: What is the total number of movies in Taylor Movie Festival?

Solution: Define calm road movie in West Sahara Movie Festival as x; so x = 4. Define total number of movies in West Sahara Movie Festival as k; so k = x = 4. Define calm road movie in Taylor Movie Festival as O; u = k - x = 4 - 4 = 0; so O = 2 + u = 2 + 0 = 2. Define intense detective thriller in Taylor Movie Festival as W; a = k + x = 4 + 4 = 8; so W = a + O = 8 + 2 = 10. Define total number of movies in Taylor Movie Festival as q; so q = O + W = 2 + 10 = 12. Answer: 12.


The number of upbeat metropolis comedy in Cinéma de Montreval equals 4. The number of solemn period drama in Cinéma de Montreval equals 4. The number of solemn period drama in Festival Lumière de Valmont equals the sum of the total number of movies in Cinéma de Montreval, the number of solemn period drama in Cinéma de Montreval, and the number of upbeat metropolis comedy in Cinéma de Montreval. The number of upbeat metropolis comedy in Festival Lumière de Valmont equals the number of solemn period drama in Festival Lumière de Valmont.

Question: What is the total number of movies in Festival Lumière de Valmont?

Solution: Define solemn period drama in Cinéma de Montreval as T; so T = 4. Define upbeat metropolis comedy in Cinéma de Montreval as R; so R = 4. Define total number of movies in Cinéma de Montreval as q; so q = T + R = 4 + 4 = 8. Define solemn period drama in Festival Lumière de Valmont as Z; s = q + T = 8 + 4 = 12; so Z = s + R = 12 + 4 = 16. Define upbeat metropolis comedy in Festival Lumière de Valmont as w; so w = Z = 16. Define total number of movies in Festival Lumière de Valmont as U; so U = Z + w = 16 + 16 = 32. Answer: 32.


The number of adult blue jay in Pine Ridge equals 4. The number of adult owl in Oakridge Riverside equals 1 plus the sum of the total number of adult animals in Pine Ridge and the number of adult blue jay in Pine Ridge. The number of adult blue jay in Oakridge Riverside equals 3 times the difference between the number of adult owl in Oakridge Riverside and the number of adult blue jay in Pine Ridge.

Question: What is the total number of adult animals in Oakridge Riverside?

Solution: Define adult blue jay in Pine Ridge as B; so B = 4. Define total number of adult animals in Pine Ridge as Y; so Y = B = 4. Define adult owl in Oakridge Riverside as S; A = Y + B = 4 + 4 = 8; so S = 1 + A = 1 + 8 = 9. Define adult blue jay in Oakridge Riverside as y; g = S - B = 9 - 4 = 5; so y = 3 * g = 3 * 5 = 15. Define total number of adult animals in Oakridge Riverside as H; so H = y + S = 15 + 9 = 24. Answer: 24.


The number of regional medical school in Westhaven City equals 1. The number of regional medical school in Hawkesbury equals 4 plus the sum of the total number of schools in Westhaven City and the number of regional medical school in Westhaven City. The number of public highschool in Hawkesbury equals 3 plus the difference between the number of regional medical school in Hawkesbury and the total number of schools in Westhaven City.

Question: What is the total number of schools in Hawkesbury?

Solution: Define regional medical school in Westhaven City as u; so u = 1. Define total number of schools in Westhaven City as y; so y = u = 1. Define regional medical school in Hawkesbury as G; o = y + u = 1 + 1 = 2; so G = 4 + o = 4 + 2 = 6. Define public highschool in Hawkesbury as Y; M = G - y = 6 - 1 = 5; so Y = 3 + M = 3 + 5 = 8. Define total number of schools in Hawkesbury as C; so C = Y + G = 8 + 6 = 14. Answer: 14.


The number of regional medical school in Oakbridge City equals 1 plus the sum of the total number of schools in Shoreline City and the number of regional medical school in Shoreline City. The number of regional medical school in Riverton City equals 4. The number of regional medical school in Shoreline City equals 3 plus the sum of the total number of schools in Riverton City and the number of regional medical school in Riverton City.

Question: What is the total number of schools in Oakbridge City?

Solution: Define regional medical school in Riverton City as F; so F = 4. Define total number of schools in Riverton City as S; so S = F = 4. Define regional medical school in Shoreline City as r; D = S + F = 4 + 4 = 8; so r = 3 + D = 3 + 8 = 11. Define total number of schools in Shoreline City as K; so K = r = 11. Define regional medical school in Oakbridge City as t; z = K + r = 11 + 11 = 22; so t = 1 + z = 1 + 22 = 23. Define total number of schools in Oakbridge City as O; so O = t = 23. Answer: 23.


The number of regional medical school in Evervale City equals 3 plus the number of culinarian school in Evervale City. The number of regional medical school in Brightford equals the total number of schools in Hawkesbury. The number of private middle school in Westhaven City equals the sum of the number of culinarian school in Hawkesbury, the number of culinarian school in Evervale City, the number of regional medical school in Brightford, and the total number of schools in Hawkesbury. The number of culinarian school in Evervale City equals 3. The number of culinarian school in Westhaven City equals 3. The number of private middle school in Evervale City equals 3 times the total number of schools in Brightford. The number of private middle school in Hawkesbury equals 4. The number of regional medical school in Westhaven City equals the total number of schools in Brightford. The number of culinarian school in Brightford equals the sum of the number of private middle school in Hawkesbury and the total number of schools in Hawkesbury. The number of private middle school in Glenfield City equals the total number of schools in Hawkesbury. The number of culinarian school in Hawkesbury equals 2.

Question: How many regional medical school does Westhaven City have?

Solution: Define culinarian school in Hawkesbury as F; so F = 2. Define private middle school in Hawkesbury as I; so I = 4. Define total number of schools in Hawkesbury as p; so p = I + F = 4 + 2 = 6. Define regional medical school in Brightford as y; so y = p = 6. Define culinarian school in Brightford as w; so w = I + p = 4 + 6 = 10. Define total number of schools in Brightford as q; so q = w + y = 10 + 6 = 16. Define regional medical school in Westhaven City as B; so B = q = 16. Answer: 16.


The number of public highschool in Evervale City equals 4. The number of public highschool in Hawkesbury equals the total number of schools in Westhaven City. The number of elementary school in Westhaven City equals the number of public highschool in Westhaven City. The number of public highschool in Westhaven City equals 1 plus the sum of the total number of schools in Evervale City and the number of public highschool in Evervale City.

Question: What is the total number of schools in Hawkesbury?

Solution: Define public highschool in Evervale City as y; so y = 4. Define total number of schools in Evervale City as D; so D = y = 4. Define public highschool in Westhaven City as U; Z = D + y = 4 + 4 = 8; so U = 1 + Z = 1 + 8 = 9. Define elementary school in Westhaven City as E; so E = U = 9. Define total number of schools in Westhaven City as J; so J = U + E = 9 + 9 = 18. Define public highschool in Hawkesbury as i; so i = J = 18. Define total number of schools in Hawkesbury as a; so a = i = 18. Answer: 18.