The number of culinarian school in Riverton City equals 2 times the number of public highschool in Riverton City. The number of culinarian school in Ruby Bay equals the total number of schools in Riverton City. The number of public highschool in Ruby Bay equals the sum of the number of public highschool in Riverton City and the total number of schools in Riverton City. The number of public highschool in Riverton City equals 3.

Question: What is the total number of schools in Ruby Bay?

Solution: Define public highschool in Riverton City as m; so m = 3. Define culinarian school in Riverton City as y; x = m = 3; so y = 2 * x = 2 * 3 = 6. Define total number of schools in Riverton City as D; so D = y + m = 6 + 3 = 9. Define culinarian school in Ruby Bay as v; so v = D = 9. Define public highschool in Ruby Bay as t; so t = m + D = 3 + 9 = 12. Define total number of schools in Ruby Bay as w; so w = v + t = 9 + 12 = 21. Answer: 21.


The number of adult racoon in Oakridge Riverside equals 4 times the sum of the number of adult wolf in Cedar Valley and the number of adult racoon in Cedar Valley. The number of adult bear in Maple Creek equals 3 times the sum of the total number of adult animals in Oakridge Riverside and the number of adult racoon in Cedar Valley. The number of adult racoon in Cedar Valley equals 4. The number of adult wolf in Cedar Valley equals the number of adult racoon in Cedar Valley.

Question: What is the total number of adult animals in Maple Creek?

Solution: Define adult racoon in Cedar Valley as a; so a = 4. Define adult wolf in Cedar Valley as i; so i = a = 4. Define adult racoon in Oakridge Riverside as x; g = i + a = 4 + 4 = 8; so x = 4 * g = 4 * 8 = 32. Define total number of adult animals in Oakridge Riverside as r; so r = x = 32. Define adult bear in Maple Creek as X; I = r + a = 32 + 4 = 36; so X = 3 * I = 3 * 36 = 108. Define total number of adult animals in Maple Creek as F; so F = X = 108. Answer: 108.


The number of adult blue jay in Pine Ridge equals 4 times the number of adult parrot in Pine Ridge. The number of adult parrot in Pine Ridge equals 4. The number of adult blue jay in Beverly Forest equals 3 times the sum of the total number of adult animals in Pine Ridge, the number of adult parrot in Pine Ridge, and the number of adult blue jay in Pine Ridge.

Question: What is the total number of adult animals in Beverly Forest?

Solution: Define adult parrot in Pine Ridge as f; so f = 4. Define adult blue jay in Pine Ridge as C; B = f = 4; so C = 4 * B = 4 * 4 = 16. Define total number of adult animals in Pine Ridge as k; so k = C + f = 16 + 4 = 20. Define adult blue jay in Beverly Forest as j; Z = k + f = 20 + 4 = 24; Y = Z + C = 24 + 16 = 40; so j = 3 * Y = 3 * 40 = 120. Define total number of adult animals in Beverly Forest as m; so m = j = 120. Answer: 120.


The number of adult fox in Jefferson Circus equals 2 plus the sum of the total number of adult animals in South Zoo, the number of adult fox in South Zoo, and the number of adult wolf in South Zoo. The number of adult fox in South Zoo equals 1. The number of adult wolf in South Zoo equals 4 times the number of adult fox in South Zoo.

Question: What is the total number of adult animals in Jefferson Circus?

Solution: Define adult fox in South Zoo as x; so x = 1. Define adult wolf in South Zoo as d; M = x = 1; so d = 4 * M = 4 * 1 = 4. Define total number of adult animals in South Zoo as R; so R = d + x = 4 + 1 = 5. Define adult fox in Jefferson Circus as h; V = R + x = 5 + 1 = 6; X = V + d = 6 + 4 = 10; so h = 2 + X = 2 + 10 = 12. Define total number of adult animals in Jefferson Circus as J; so J = h = 12. Answer: 12.


The number of adult owl in Beverly Forest equals 2 plus the difference between the number of adult eagle in Beverly Forest and the number of adult parrot in Oakridge Riverside. The number of adult owl in Pine Ridge equals 2 times the sum of the number of adult eagle in Beverly Forest and the number of adult parrot in Oakridge Riverside. The number of adult parrot in Pine Ridge equals the number of adult eagle in Pine Ridge. The number of adult blue jay in Maple Creek equals 2 times the number of adult eagle in Beverly Forest. The number of adult blue jay in Pine Ridge equals the number of adult parrot in Maple Creek. The number of adult owl in Oakridge Riverside equals the number of adult owl in Maple Creek. The number of adult parrot in Oakridge Riverside equals 2. The number of adult owl in Maple Creek equals the number of adult parrot in Oakridge Riverside. The number of adult eagle in Maple Creek equals the number of adult parrot in Oakridge Riverside. The number of adult parrot in Maple Creek equals 4. The number of adult parrot in Beverly Forest equals the number of adult owl in Beverly Forest. The number of adult blue jay in Oakridge Riverside equals the sum of the number of adult owl in Pine Ridge and the number of adult owl in Beverly Forest. The number of adult eagle in Pine Ridge equals 3. The number of adult eagle in Oakridge Riverside equals 3 times the number of adult owl in Beverly Forest. The number of adult eagle in Beverly Forest equals 3 times the number of adult parrot in Oakridge Riverside.

Question: What is the total number of adult animals in Beverly Forest?

Solution: Define adult parrot in Oakridge Riverside as U; so U = 2. Define adult eagle in Beverly Forest as N; g = U = 2; so N = 3 * g = 3 * 2 = 6. Define adult owl in Beverly Forest as Q; C = N - U = 6 - 2 = 4; so Q = 2 + C = 2 + 4 = 6. Define adult parrot in Beverly Forest as o; so o = Q = 6. Define total number of adult animals in Beverly Forest as j; n = o + Q = 6 + 6 = 12; so j = n + N = 12 + 6 = 18. Answer: 18.


The number of adult blue jay in Maple Creek equals 4 times the sum of the total number of adult animals in Cedar Valley, the number of adult blue jay in Cedar Valley, and the number of adult parrot in Cedar Valley. The number of adult blue jay in Cedar Valley equals 1. The number of adult parrot in Cedar Valley equals 3 times the number of adult blue jay in Cedar Valley.

Question: What is the total number of adult animals in Maple Creek?

Solution: Define adult blue jay in Cedar Valley as C; so C = 1. Define adult parrot in Cedar Valley as c; k = C = 1; so c = 3 * k = 3 * 1 = 3. Define total number of adult animals in Cedar Valley as A; so A = C + c = 1 + 3 = 4. Define adult blue jay in Maple Creek as E; S = A + C = 4 + 1 = 5; o = S + c = 5 + 3 = 8; so E = 4 * o = 4 * 8 = 32. Define total number of adult animals in Maple Creek as X; so X = E = 32. Answer: 32.


The number of futuristic sci-fi movie in Festival de Clairmont equals 1 plus the sum of the total number of movies in Festival de Saint-Rivage and the number of futuristic sci-fi movie in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals 2. The number of upbeat metropolis comedy in Festival de Clairmont equals the sum of the number of futuristic sci-fi movie in Festival de Clairmont, the total number of movies in Festival de Saint-Rivage, and the number of futuristic sci-fi movie in Festival de Saint-Rivage.

Question: What is the total number of movies in Festival de Clairmont?

Solution: Define futuristic sci-fi movie in Festival de Saint-Rivage as Z; so Z = 2. Define total number of movies in Festival de Saint-Rivage as r; so r = Z = 2. Define futuristic sci-fi movie in Festival de Clairmont as h; A = r + Z = 2 + 2 = 4; so h = 1 + A = 1 + 4 = 5. Define upbeat metropolis comedy in Festival de Clairmont as u; j = h + r = 5 + 2 = 7; so u = j + Z = 7 + 2 = 9. Define total number of movies in Festival de Clairmont as T; so T = h + u = 5 + 9 = 14. Answer: 14.


The number of calm road movie in Verdi Movie Festival equals the number of solemn period drama in Verdi Movie Festival. The number of solemn period drama in Verdi Movie Festival equals 2. The number of solemn period drama in West Sahara Movie Festival equals 1. The number of calm road movie in West Sahara Movie Festival equals the sum of the total number of movies in Verdi Movie Festival, the number of calm road movie in Verdi Movie Festival, and the number of solemn period drama in Verdi Movie Festival.

Question: What is the total number of movies in West Sahara Movie Festival?

Solution: Define solemn period drama in Verdi Movie Festival as N; so N = 2. Define calm road movie in Verdi Movie Festival as d; so d = N = 2. Define total number of movies in Verdi Movie Festival as Y; so Y = N + d = 2 + 2 = 4. Define calm road movie in West Sahara Movie Festival as W; p = Y + d = 4 + 2 = 6; so W = p + N = 6 + 2 = 8. Define solemn period drama in West Sahara Movie Festival as D; so D = 1. Define total number of movies in West Sahara Movie Festival as V; so V = D + W = 1 + 8 = 9. Answer: 9.


The number of adult racoon in Cedar Valley equals the sum of the number of adult bear in Beverly Forest, the number of adult deer in Beverly Forest, the total number of adult animals in Pine Ridge, and the number of adult wolf in Oakridge Riverside. The number of adult bear in Oakridge Riverside equals the number of adult racoon in Pine Ridge. The number of adult bear in Beverly Forest equals 3. The number of adult deer in Pine Ridge equals 3. The number of adult racoon in Pine Ridge equals 2 plus the number of adult deer in Pine Ridge. The number of adult deer in Beverly Forest equals 4 times the number of adult racoon in Pine Ridge. The number of adult deer in Cedar Valley equals 4. The number of adult wolf in Oakridge Riverside equals 1 plus the total number of adult animals in Pine Ridge.

Question: What is the total number of adult animals in Oakridge Riverside?

Solution: Define adult deer in Pine Ridge as l; so l = 3. Define adult racoon in Pine Ridge as h; i = l = 3; so h = 2 + i = 2 + 3 = 5. Define total number of adult animals in Pine Ridge as m; so m = l + h = 3 + 5 = 8. Define adult bear in Oakridge Riverside as G; so G = h = 5. Define adult wolf in Oakridge Riverside as H; u = m = 8; so H = 1 + u = 1 + 8 = 9. Define total number of adult animals in Oakridge Riverside as b; so b = G + H = 5 + 9 = 14. Answer: 14.


The number of futuristic sci-fi movie in Festival Lumière de Valmont equals the sum of the number of upbeat metropolis comedy in Cinéma de Montreval and the number of futuristic sci-fi movie in Cinéma de Montreval. The number of futuristic sci-fi movie in Cinéma de Montreval equals 3 times the number of upbeat metropolis comedy in Cinéma de Montreval. The number of upbeat metropolis comedy in Cinéma de Montreval equals 2. The number of upbeat metropolis comedy in Festival Lumière de Valmont equals the total number of movies in Cinéma de Montreval.

Question: What is the total number of movies in Festival Lumière de Valmont?

Solution: Define upbeat metropolis comedy in Cinéma de Montreval as m; so m = 2. Define futuristic sci-fi movie in Cinéma de Montreval as p; X = m = 2; so p = 3 * X = 3 * 2 = 6. Define total number of movies in Cinéma de Montreval as c; so c = p + m = 6 + 2 = 8. Define futuristic sci-fi movie in Festival Lumière de Valmont as C; so C = m + p = 2 + 6 = 8. Define upbeat metropolis comedy in Festival Lumière de Valmont as A; so A = c = 8. Define total number of movies in Festival Lumière de Valmont as g; so g = C + A = 8 + 8 = 16. Answer: 16.


The number of adult bear in Jefferson Circus equals 4 plus the total number of adult animals in South Zoo. The number of adult bear in South Zoo equals 3 times the number of adult fox in South Zoo. The number of adult fox in Jefferson Circus equals the total number of adult animals in South Zoo. The number of adult fox in South Zoo equals 4.

Question: What is the total number of adult animals in Jefferson Circus?

Solution: Define adult fox in South Zoo as o; so o = 4. Define adult bear in South Zoo as k; G = o = 4; so k = 3 * G = 3 * 4 = 12. Define total number of adult animals in South Zoo as v; so v = k + o = 12 + 4 = 16. Define adult fox in Jefferson Circus as p; so p = v = 16. Define adult bear in Jefferson Circus as m; n = v = 16; so m = 4 + n = 4 + 16 = 20. Define total number of adult animals in Jefferson Circus as Y; so Y = m + p = 20 + 16 = 36. Answer: 36.


The number of calm road movie in Festival Lumière de Valmont equals 2. The number of intense detective thriller in Festival de Clairmont equals 4 plus the sum of the number of calm road movie in Festival Lumière de Valmont and the total number of movies in Festival Lumière de Valmont. The number of calm road movie in Festival de Clairmont equals 4 plus the sum of the total number of movies in Festival Lumière de Valmont and the number of calm road movie in Festival Lumière de Valmont.

Question: What is the total number of movies in Festival de Clairmont?

Solution: Define calm road movie in Festival Lumière de Valmont as X; so X = 2. Define total number of movies in Festival Lumière de Valmont as S; so S = X = 2. Define calm road movie in Festival de Clairmont as F; V = S + X = 2 + 2 = 4; so F = 4 + V = 4 + 4 = 8. Define intense detective thriller in Festival de Clairmont as q; d = X + S = 2 + 2 = 4; so q = 4 + d = 4 + 4 = 8. Define total number of movies in Festival de Clairmont as N; so N = q + F = 8 + 8 = 16. Answer: 16.


The number of calm road movie in Festival Lumière de Valmont equals the number of solemn period drama in Festival Lumière de Valmont. The number of solemn period drama in Festival de Saint-Rivage equals 1 plus the number of calm road movie in Festival de Saint-Rivage. The number of solemn period drama in Festival Lumière de Valmont equals 2. The number of calm road movie in Festival de Saint-Rivage equals 2 plus the total number of movies in Festival Lumière de Valmont.

Question: What is the total number of movies in Festival de Saint-Rivage?

Solution: Define solemn period drama in Festival Lumière de Valmont as K; so K = 2. Define calm road movie in Festival Lumière de Valmont as F; so F = K = 2. Define total number of movies in Festival Lumière de Valmont as u; so u = F + K = 2 + 2 = 4. Define calm road movie in Festival de Saint-Rivage as q; H = u = 4; so q = 2 + H = 2 + 4 = 6. Define solemn period drama in Festival de Saint-Rivage as d; y = q = 6; so d = 1 + y = 1 + 6 = 7. Define total number of movies in Festival de Saint-Rivage as N; so N = q + d = 6 + 7 = 13. Answer: 13.


The number of adult owl in South Zoo equals 3. The number of adult owl in Bundle Ranch equals 2. The number of adult blue jay in South Zoo equals the number of adult owl in South Zoo. The number of adult blue jay in Bundle Ranch equals 2 plus the sum of the total number of adult animals in South Zoo and the number of adult owl in South Zoo.

Question: What is the total number of adult animals in Bundle Ranch?

Solution: Define adult owl in South Zoo as K; so K = 3. Define adult blue jay in South Zoo as Q; so Q = K = 3. Define total number of adult animals in South Zoo as P; so P = K + Q = 3 + 3 = 6. Define adult blue jay in Bundle Ranch as W; U = P + K = 6 + 3 = 9; so W = 2 + U = 2 + 9 = 11. Define adult owl in Bundle Ranch as o; so o = 2. Define total number of adult animals in Bundle Ranch as x; so x = o + W = 2 + 11 = 13. Answer: 13.


The number of calm road movie in West Sahara Movie Festival equals 2. The number of solemn period drama in West Sahara Movie Festival equals the sum of the total number of movies in Northwood Movie Festival, the number of calm road movie in Northwood Movie Festival, and the number of solemn period drama in Northwood Movie Festival. The number of solemn period drama in Northwood Movie Festival equals 4. The number of calm road movie in Northwood Movie Festival equals the number of solemn period drama in Northwood Movie Festival.

Question: What is the total number of movies in West Sahara Movie Festival?

Solution: Define solemn period drama in Northwood Movie Festival as R; so R = 4. Define calm road movie in Northwood Movie Festival as f; so f = R = 4. Define total number of movies in Northwood Movie Festival as X; so X = f + R = 4 + 4 = 8. Define solemn period drama in West Sahara Movie Festival as o; P = X + f = 8 + 4 = 12; so o = P + R = 12 + 4 = 16. Define calm road movie in West Sahara Movie Festival as p; so p = 2. Define total number of movies in West Sahara Movie Festival as Y; so Y = p + o = 2 + 16 = 18. Answer: 18.


The number of adult owl in Oakridge Riverside equals 3. The number of adult crow in Oakridge Riverside equals 3 times the difference between the total number of adult animals in Pine Ridge and the number of adult owl in Pine Ridge. The number of adult owl in Pine Ridge equals 2 times the number of adult owl in Oakridge Riverside. The number of adult crow in Pine Ridge equals 3 times the number of adult owl in Oakridge Riverside.

Question: How many adult crow does Oakridge Riverside have?

Solution: Define adult owl in Oakridge Riverside as t; so t = 3. Define adult crow in Pine Ridge as T; p = t = 3; so T = 3 * p = 3 * 3 = 9. Define adult owl in Pine Ridge as K; J = t = 3; so K = 2 * J = 2 * 3 = 6. Define total number of adult animals in Pine Ridge as l; so l = K + T = 6 + 9 = 15. Define adult crow in Oakridge Riverside as b; G = l - K = 15 - 6 = 9; so b = 3 * G = 3 * 9 = 27. Answer: 27.


The number of private middle school in Riverton City equals 4. The number of private middle school in Clearwater Bay equals the sum of the number of culinarian school in Clearwater Bay, the number of private middle school in Riverton City, and the total number of schools in Riverton City. The number of elementary school in Oakbridge City equals 4. The number of culinarian school in Oakbridge City equals 3. The number of culinarian school in Clearwater Bay equals 2 times the sum of the total number of schools in Riverton City and the number of private middle school in Riverton City.

Question: What is the total number of schools in Clearwater Bay?

Solution: Define private middle school in Riverton City as v; so v = 4. Define total number of schools in Riverton City as N; so N = v = 4. Define culinarian school in Clearwater Bay as w; S = N + v = 4 + 4 = 8; so w = 2 * S = 2 * 8 = 16. Define private middle school in Clearwater Bay as a; f = w + v = 16 + 4 = 20; so a = f + N = 20 + 4 = 24. Define total number of schools in Clearwater Bay as i; so i = a + w = 24 + 16 = 40. Answer: 40.


The number of elementary school in Shoreline City equals 1 plus the sum of the total number of schools in Clearwater Bay, the number of culinarian school in Clearwater Bay, and the number of private middle school in Clearwater Bay. The number of private middle school in Clearwater Bay equals 3 times the number of culinarian school in Clearwater Bay. The number of culinarian school in Clearwater Bay equals 4.

Question: What is the total number of schools in Shoreline City?

Solution: Define culinarian school in Clearwater Bay as n; so n = 4. Define private middle school in Clearwater Bay as J; U = n = 4; so J = 3 * U = 3 * 4 = 12. Define total number of schools in Clearwater Bay as m; so m = n + J = 4 + 12 = 16. Define elementary school in Shoreline City as O; N = m + n = 16 + 4 = 20; c = N + J = 20 + 12 = 32; so O = 1 + c = 1 + 32 = 33. Define total number of schools in Shoreline City as B; so B = O = 33. Answer: 33.


The number of culinarian school in Westhaven City equals 4. The number of public highschool in Westhaven City equals 3. The number of culinarian school in Hawkesbury equals the total number of schools in Westhaven City. The number of culinarian school in Glenfield City equals 2 times the number of culinarian school in Brightford. The number of culinarian school in Brightford equals 4. The number of public highschool in Brightford equals 3. The number of public highschool in Hawkesbury equals 4 times the difference between the total number of schools in Westhaven City and the number of culinarian school in Westhaven City. The number of public highschool in Glenfield City equals the number of culinarian school in Brightford.

Question: What is the total number of schools in Hawkesbury?

Solution: Define culinarian school in Westhaven City as a; so a = 4. Define public highschool in Westhaven City as E; so E = 3. Define total number of schools in Westhaven City as Y; so Y = E + a = 3 + 4 = 7. Define public highschool in Hawkesbury as L; u = Y - a = 7 - 4 = 3; so L = 4 * u = 4 * 3 = 12. Define culinarian school in Hawkesbury as H; so H = Y = 7. Define total number of schools in Hawkesbury as C; so C = L + H = 12 + 7 = 19. Answer: 19.


The number of adult fox in Cedar Valley equals 4. The number of adult deer in Beverly Forest equals 3 plus the number of adult fox in Cedar Valley. The number of adult fox in Beverly Forest equals 3 plus the number of adult fox in Cedar Valley. The number of adult deer in Cedar Valley equals 4 plus the difference between the total number of adult animals in Beverly Forest and the number of adult deer in Beverly Forest.

Question: How many adult deer does Cedar Valley have?

Solution: Define adult fox in Cedar Valley as H; so H = 4. Define adult deer in Beverly Forest as J; Z = H = 4; so J = 3 + Z = 3 + 4 = 7. Define adult fox in Beverly Forest as G; t = H = 4; so G = 3 + t = 3 + 4 = 7. Define total number of adult animals in Beverly Forest as C; so C = J + G = 7 + 7 = 14. Define adult deer in Cedar Valley as d; Q = C - J = 14 - 7 = 7; so d = 4 + Q = 4 + 7 = 11. Answer: 11.


The number of public highschool in Clearwater Bay equals 2. The number of elementary school in Clearwater Bay equals the number of public highschool in Clearwater Bay. The number of public highschool in Shoreline City equals 4 times the number of public highschool in Clearwater Bay. The number of elementary school in Shoreline City equals the sum of the total number of schools in Clearwater Bay and the number of elementary school in Clearwater Bay.

Question: What is the total number of schools in Shoreline City?

Solution: Define public highschool in Clearwater Bay as E; so E = 2. Define elementary school in Clearwater Bay as h; so h = E = 2. Define public highschool in Shoreline City as V; t = E = 2; so V = 4 * t = 4 * 2 = 8. Define total number of schools in Clearwater Bay as W; so W = E + h = 2 + 2 = 4. Define elementary school in Shoreline City as j; so j = W + h = 4 + 2 = 6. Define total number of schools in Shoreline City as u; so u = V + j = 8 + 6 = 14. Answer: 14.


The number of adult racoon in South Zoo equals 4. The number of adult deer in South Zoo equals 4 times the difference between the total number of adult animals in Hamilton Farm and the number of adult deer in Hamilton Farm. The number of adult deer in Hamilton Farm equals the number of adult racoon in Hamilton Farm. The number of adult racoon in Hamilton Farm equals 2.

Question: What is the total number of adult animals in South Zoo?

Solution: Define adult racoon in Hamilton Farm as S; so S = 2. Define adult deer in Hamilton Farm as W; so W = S = 2. Define total number of adult animals in Hamilton Farm as U; so U = W + S = 2 + 2 = 4. Define adult deer in South Zoo as y; b = U - W = 4 - 2 = 2; so y = 4 * b = 4 * 2 = 8. Define adult racoon in South Zoo as X; so X = 4. Define total number of adult animals in South Zoo as k; so k = y + X = 8 + 4 = 12. Answer: 12.


The number of adult crow in Pine Ridge equals 2 times the number of adult owl in Pine Ridge. The number of adult owl in Pine Ridge equals 4. The number of adult crow in Oakridge Riverside equals 2 times the sum of the total number of adult animals in Pine Ridge, the number of adult owl in Pine Ridge, and the number of adult crow in Pine Ridge.

Question: What is the total number of adult animals in Oakridge Riverside?

Solution: Define adult owl in Pine Ridge as L; so L = 4. Define adult crow in Pine Ridge as C; b = L = 4; so C = 2 * b = 2 * 4 = 8. Define total number of adult animals in Pine Ridge as m; so m = L + C = 4 + 8 = 12. Define adult crow in Oakridge Riverside as e; X = m + L = 12 + 4 = 16; G = X + C = 16 + 8 = 24; so e = 2 * G = 2 * 24 = 48. Define total number of adult animals in Oakridge Riverside as k; so k = e = 48. Answer: 48.


The number of regional medical school in Shoreline City equals 3 times the number of culinarian school in Shoreline City. The number of culinarian school in Shoreline City equals 4. The number of private middle school in Clearwater Bay equals 2 times the sum of the total number of schools in Shoreline City, the number of culinarian school in Shoreline City, and the number of regional medical school in Shoreline City.

Question: What is the total number of schools in Clearwater Bay?

Solution: Define culinarian school in Shoreline City as Z; so Z = 4. Define regional medical school in Shoreline City as d; r = Z = 4; so d = 3 * r = 3 * 4 = 12. Define total number of schools in Shoreline City as s; so s = d + Z = 12 + 4 = 16. Define private middle school in Clearwater Bay as h; z = s + Z = 16 + 4 = 20; S = z + d = 20 + 12 = 32; so h = 2 * S = 2 * 32 = 64. Define total number of schools in Clearwater Bay as w; so w = h = 64. Answer: 64.


The number of culinarian school in Glenfield City equals 3. The number of culinarian school in Brightford equals 4 times the total number of schools in Westhaven City. The number of regional medical school in Hawkesbury equals the number of culinarian school in Hawkesbury. The number of private middle school in Westhaven City equals 2. The number of elementary school in Glenfield City equals the number of regional medical school in Hawkesbury. The number of culinarian school in Hawkesbury equals 3 times the sum of the number of private middle school in Hawkesbury and the number of elementary school in Hawkesbury. The number of elementary school in Hawkesbury equals 4. The number of regional medical school in Westhaven City equals 4 plus the number of public highschool in Brightford. The number of public highschool in Evervale City equals the total number of schools in Westhaven City. The number of elementary school in Brightford equals 4. The number of public highschool in Brightford equals 3. The number of culinarian school in Evervale City equals 2 times the difference between the number of public highschool in Brightford and the number of regional medical school in Westhaven City. The number of private middle school in Hawkesbury equals 4.

Question: What is the total number of schools in Hawkesbury?

Solution: Define private middle school in Hawkesbury as Y; so Y = 4. Define elementary school in Hawkesbury as C; so C = 4. Define culinarian school in Hawkesbury as k; G = Y + C = 4 + 4 = 8; so k = 3 * G = 3 * 8 = 24. Define regional medical school in Hawkesbury as e; so e = k = 24. Define total number of schools in Hawkesbury as f; u = C + k = 4 + 24 = 28; L = u + Y = 28 + 4 = 32; so f = L + e = 32 + 24 = 56. Answer: 56.


The number of public highschool in Brightford equals 2 times the number of private middle school in Brightford. The number of private middle school in Brightford equals 2. The number of private middle school in Hawkesbury equals 4 times the sum of the total number of schools in Brightford, the number of private middle school in Brightford, and the number of public highschool in Brightford.

Question: What is the total number of schools in Hawkesbury?

Solution: Define private middle school in Brightford as L; so L = 2. Define public highschool in Brightford as g; D = L = 2; so g = 2 * D = 2 * 2 = 4. Define total number of schools in Brightford as F; so F = L + g = 2 + 4 = 6. Define private middle school in Hawkesbury as h; d = F + L = 6 + 2 = 8; J = d + g = 8 + 4 = 12; so h = 4 * J = 4 * 12 = 48. Define total number of schools in Hawkesbury as v; so v = h = 48. Answer: 48.