The number of private middle school in Riverton City equals the sum of the number of private middle school in Clearwater Bay and the total number of schools in Clearwater Bay. The number of culinarian school in Riverton City equals the sum of the total number of schools in Clearwater Bay and the number of private middle school in Clearwater Bay. The number of private middle school in Clearwater Bay equals 4. The number of culinarian school in Clearwater Bay equals 2.

Question: What is the total number of schools in Riverton City?

Solution: Define culinarian school in Clearwater Bay as z; so z = 2. Define private middle school in Clearwater Bay as E; so E = 4. Define total number of schools in Clearwater Bay as C; so C = z + E = 2 + 4 = 6. Define culinarian school in Riverton City as W; so W = C + E = 6 + 4 = 10. Define private middle school in Riverton City as c; so c = E + C = 4 + 6 = 10. Define total number of schools in Riverton City as f; so f = W + c = 10 + 10 = 20. Answer: 20.


The number of adult racoon in Bundle Ranch equals 4. The number of adult bear in South Zoo equals 2. The number of adult racoon in South Zoo equals 3 times the sum of the total number of adult animals in Bundle Ranch and the number of adult bear in South Zoo. The number of adult bear in Bundle Ranch equals the number of adult racoon in Bundle Ranch.

Question: What is the total number of adult animals in South Zoo?

Solution: Define adult racoon in Bundle Ranch as Q; so Q = 4. Define adult bear in Bundle Ranch as t; so t = Q = 4. Define adult bear in South Zoo as u; so u = 2. Define total number of adult animals in Bundle Ranch as G; so G = t + Q = 4 + 4 = 8. Define adult racoon in South Zoo as D; p = G + u = 8 + 2 = 10; so D = 3 * p = 3 * 10 = 30. Define total number of adult animals in South Zoo as q; so q = u + D = 2 + 30 = 32. Answer: 32.


The number of adult blue jay in Mayer Aquarium equals 2. The number of adult eagle in Jefferson Circus equals the sum of the total number of adult animals in Hamilton Farm, the number of adult blue jay in Mayer Aquarium, and the total number of adult animals in Mayer Aquarium. The number of adult owl in Hamilton Farm equals 4 plus the difference between the total number of adult animals in Mayer Aquarium and the number of adult blue jay in Mayer Aquarium.

Question: What is the total number of adult animals in Jefferson Circus?

Solution: Define adult blue jay in Mayer Aquarium as F; so F = 2. Define total number of adult animals in Mayer Aquarium as r; so r = F = 2. Define adult owl in Hamilton Farm as E; d = r - F = 2 - 2 = 0; so E = 4 + d = 4 + 0 = 4. Define total number of adult animals in Hamilton Farm as W; so W = E = 4. Define adult eagle in Jefferson Circus as H; N = W + F = 4 + 2 = 6; so H = N + r = 6 + 2 = 8. Define total number of adult animals in Jefferson Circus as G; so G = H = 8. Answer: 8.


The number of intense detective thriller in Festival Lumière de Valmont equals 4. The number of solemn period drama in Festival Lumière de Valmont equals the sum of the total number of movies in Rêves de Belleville, the number of intense detective thriller in Festival Lumière de Valmont, and the number of solemn period drama in Rêves de Belleville. The number of calm road movie in Cinéma de Montreval equals 2. The number of intense detective thriller in Cinéma de Montreval equals the sum of the number of calm road movie in Festival Lumière de Valmont, the number of solemn period drama in Rêves de Belleville, and the total number of movies in Rêves de Belleville. The number of calm road movie in Festival Lumière de Valmont equals 4. The number of solemn period drama in Cinéma de Montreval equals the sum of the total number of movies in Rêves de Belleville, the number of solemn period drama in Festival Lumière de Valmont, and the number of solemn period drama in Rêves de Belleville. The number of solemn period drama in Rêves de Belleville equals the number of intense detective thriller in Festival Lumière de Valmont.

Question: What is the total number of movies in Festival Lumière de Valmont?

Solution: Define intense detective thriller in Festival Lumière de Valmont as J; so J = 4. Define solemn period drama in Rêves de Belleville as h; so h = J = 4. Define total number of movies in Rêves de Belleville as M; so M = h = 4. Define solemn period drama in Festival Lumière de Valmont as j; B = M + J = 4 + 4 = 8; so j = B + h = 8 + 4 = 12. Define calm road movie in Festival Lumière de Valmont as W; so W = 4. Define total number of movies in Festival Lumière de Valmont as G; T = j + W = 12 + 4 = 16; so G = T + J = 16 + 4 = 20. Answer: 20.


The number of public highschool in Oakbridge City equals the number of culinarian school in Shoreline City. The number of private middle school in Riverton City equals 1. The number of regional medical school in Riverton City equals 2. The number of regional medical school in Shoreline City equals 4. The number of private middle school in Oakbridge City equals 1 plus the number of culinarian school in Shoreline City. The number of culinarian school in Oakbridge City equals 3 plus the difference between the number of private middle school in Oakbridge City and the number of culinarian school in Shoreline City. The number of public highschool in Riverton City equals the total number of schools in Oakbridge City. The number of culinarian school in Riverton City equals 2 plus the sum of the number of public highschool in Riverton City and the total number of schools in Riverton City. The number of private middle school in Shoreline City equals 2. The number of culinarian school in Shoreline City equals 3.

Question: What is the total number of schools in Oakbridge City?

Solution: Define culinarian school in Shoreline City as u; so u = 3. Define private middle school in Oakbridge City as k; J = u = 3; so k = 1 + J = 1 + 3 = 4. Define culinarian school in Oakbridge City as E; O = k - u = 4 - 3 = 1; so E = 3 + O = 3 + 1 = 4. Define public highschool in Oakbridge City as N; so N = u = 3. Define total number of schools in Oakbridge City as h; g = k + N = 4 + 3 = 7; so h = g + E = 7 + 4 = 11. Answer: 11.


The number of solemn period drama in Cinéma de Montreval equals the difference between the total number of movies in Festival de Saint-Rivage and the number of solemn period drama in Rêves de Belleville. The number of intense detective thriller in Rêves de Belleville equals the number of solemn period drama in Rêves de Belleville. The number of calm road movie in Festival de Saint-Rivage equals the sum of the total number of movies in Rêves de Belleville and the number of solemn period drama in Rêves de Belleville. The number of solemn period drama in Rêves de Belleville equals 3.

Question: What is the total number of movies in Cinéma de Montreval?

Solution: Define solemn period drama in Rêves de Belleville as N; so N = 3. Define intense detective thriller in Rêves de Belleville as O; so O = N = 3. Define total number of movies in Rêves de Belleville as E; so E = N + O = 3 + 3 = 6. Define calm road movie in Festival de Saint-Rivage as k; so k = E + N = 6 + 3 = 9. Define total number of movies in Festival de Saint-Rivage as U; so U = k = 9. Define solemn period drama in Cinéma de Montreval as I; so I = U - N = 9 - 3 = 6. Define total number of movies in Cinéma de Montreval as Y; so Y = I = 6. Answer: 6.


The number of calm road movie in Festival Lumière de Valmont equals the total number of movies in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Festival Lumière de Valmont equals 3 plus the total number of movies in Festival de Saint-Rivage. The number of calm road movie in Festival de Saint-Rivage equals 2 times the number of futuristic sci-fi movie in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals 1.

Question: What is the total number of movies in Festival Lumière de Valmont?

Solution: Define futuristic sci-fi movie in Festival de Saint-Rivage as E; so E = 1. Define calm road movie in Festival de Saint-Rivage as L; U = E = 1; so L = 2 * U = 2 * 1 = 2. Define total number of movies in Festival de Saint-Rivage as R; so R = L + E = 2 + 1 = 3. Define calm road movie in Festival Lumière de Valmont as X; so X = R = 3. Define futuristic sci-fi movie in Festival Lumière de Valmont as Q; j = R = 3; so Q = 3 + j = 3 + 3 = 6. Define total number of movies in Festival Lumière de Valmont as y; so y = X + Q = 3 + 6 = 9. Answer: 9.


The number of calm road movie in Northwood Movie Festival equals 3. The number of calm road movie in Taylor Movie Festival equals the number of solemn period drama in Taylor Movie Festival. The number of solemn period drama in West Sahara Movie Festival equals 3 plus the difference between the number of upbeat metropolis comedy in Golden Banana Movie Festival and the total number of movies in Golden Banana Movie Festival. The number of futuristic sci-fi movie in Northwood Movie Festival equals 2 plus the number of upbeat metropolis comedy in Golden Banana Movie Festival. The number of upbeat metropolis comedy in Taylor Movie Festival equals 2. The number of upbeat metropolis comedy in Northwood Movie Festival equals the number of futuristic sci-fi movie in West Sahara Movie Festival. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 4. The number of upbeat metropolis comedy in West Sahara Movie Festival equals 2 times the number of upbeat metropolis comedy in Taylor Movie Festival. The number of solemn period drama in Taylor Movie Festival equals 3 times the number of calm road movie in Northwood Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals 4 times the number of solemn period drama in Taylor Movie Festival. The number of solemn period drama in Northwood Movie Festival equals 4. The number of calm road movie in West Sahara Movie Festival equals 2. The number of futuristic sci-fi movie in Taylor Movie Festival equals the number of solemn period drama in Taylor Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals 2. The number of futuristic sci-fi movie in Golden Banana Movie Festival equals the sum of the total number of movies in Golden Banana Movie Festival, the number of solemn period drama in Taylor Movie Festival, the number of solemn period drama in Golden Banana Movie Festival, and the number of upbeat metropolis comedy in Golden Banana Movie Festival. The number of futuristic sci-fi movie in West Sahara Movie Festival equals 1 plus the number of upbeat metropolis comedy in Golden Banana Movie Festival.

Question: What is the total number of movies in Taylor Movie Festival?

Solution: Define calm road movie in Northwood Movie Festival as S; so S = 3. Define solemn period drama in Taylor Movie Festival as H; Q = S = 3; so H = 3 * Q = 3 * 3 = 9. Define calm road movie in Taylor Movie Festival as X; so X = H = 9. Define upbeat metropolis comedy in Taylor Movie Festival as x; so x = 2. Define futuristic sci-fi movie in Taylor Movie Festival as i; so i = H = 9. Define total number of movies in Taylor Movie Festival as p; n = i + H = 9 + 9 = 18; C = n + X = 18 + 9 = 27; so p = C + x = 27 + 2 = 29. Answer: 29.


The number of adult eagle in Bundle Ranch equals the number of adult owl in Bundle Ranch. The number of adult owl in Bundle Ranch equals 3. The number of adult owl in South Zoo equals the sum of the number of adult eagle in South Zoo, the number of adult eagle in Bundle Ranch, and the number of adult owl in Bundle Ranch. The number of adult eagle in South Zoo equals 2 plus the difference between the number of adult eagle in Bundle Ranch and the number of adult owl in Bundle Ranch.

Question: What is the total number of adult animals in South Zoo?

Solution: Define adult owl in Bundle Ranch as q; so q = 3. Define adult eagle in Bundle Ranch as y; so y = q = 3. Define adult eagle in South Zoo as I; n = y - q = 3 - 3 = 0; so I = 2 + n = 2 + 0 = 2. Define adult owl in South Zoo as E; R = I + y = 2 + 3 = 5; so E = R + q = 5 + 3 = 8. Define total number of adult animals in South Zoo as P; so P = E + I = 8 + 2 = 10. Answer: 10.


The number of public highschool in Shoreline City equals 1 plus the total number of schools in Ruby Bay. The number of culinarian school in Clearwater Bay equals 1 plus the sum of the number of public highschool in Ruby Bay and the number of public highschool in Clearwater Bay. The number of culinarian school in Ruby Bay equals 1. The number of public highschool in Ruby Bay equals the number of public highschool in Clearwater Bay. The number of culinarian school in Shoreline City equals 3. The number of public highschool in Clearwater Bay equals 2. The number of private middle school in Clearwater Bay equals the sum of the number of culinarian school in Clearwater Bay and the number of public highschool in Clearwater Bay. The number of private middle school in Ruby Bay equals 2. The number of private middle school in Shoreline City equals 2 plus the sum of the total number of schools in Ruby Bay, the total number of schools in Clearwater Bay, and the number of public highschool in Ruby Bay.

Question: What is the total number of schools in Clearwater Bay?

Solution: Define public highschool in Clearwater Bay as Q; so Q = 2. Define public highschool in Ruby Bay as e; so e = Q = 2. Define culinarian school in Clearwater Bay as l; X = e + Q = 2 + 2 = 4; so l = 1 + X = 1 + 4 = 5. Define private middle school in Clearwater Bay as p; so p = l + Q = 5 + 2 = 7. Define total number of schools in Clearwater Bay as g; b = p + Q = 7 + 2 = 9; so g = b + l = 9 + 5 = 14. Answer: 14.


The number of adult parrot in Oakridge Riverside equals 2. The number of adult parrot in Pine Ridge equals 3 times the sum of the total number of adult animals in Oakridge Riverside and the number of adult parrot in Oakridge Riverside. The number of adult crow in Pine Ridge equals 3 plus the difference between the number of adult parrot in Pine Ridge and the total number of adult animals in Oakridge Riverside.

Question: What is the total number of adult animals in Pine Ridge?

Solution: Define adult parrot in Oakridge Riverside as j; so j = 2. Define total number of adult animals in Oakridge Riverside as C; so C = j = 2. Define adult parrot in Pine Ridge as Z; Q = C + j = 2 + 2 = 4; so Z = 3 * Q = 3 * 4 = 12. Define adult crow in Pine Ridge as y; k = Z - C = 12 - 2 = 10; so y = 3 + k = 3 + 10 = 13. Define total number of adult animals in Pine Ridge as o; so o = Z + y = 12 + 13 = 25. Answer: 25.


The number of adult wolf in Hamilton Farm equals the sum of the number of adult wolf in Mayer Aquarium and the number of adult fox in Hamilton Farm. The number of adult fox in Hamilton Farm equals the total number of adult animals in Mayer Aquarium. The number of adult fox in Mayer Aquarium equals 3 times the number of adult wolf in Mayer Aquarium. The number of adult wolf in Mayer Aquarium equals 3.

Question: What is the total number of adult animals in Hamilton Farm?

Solution: Define adult wolf in Mayer Aquarium as s; so s = 3. Define adult fox in Mayer Aquarium as G; z = s = 3; so G = 3 * z = 3 * 3 = 9. Define total number of adult animals in Mayer Aquarium as L; so L = s + G = 3 + 9 = 12. Define adult fox in Hamilton Farm as S; so S = L = 12. Define adult wolf in Hamilton Farm as u; so u = s + S = 3 + 12 = 15. Define total number of adult animals in Hamilton Farm as W; so W = u + S = 15 + 12 = 27. Answer: 27.


The number of adult deer in Jefferson Circus equals 1. The number of adult deer in Mayer Aquarium equals 1 plus the sum of the total number of adult animals in Jefferson Circus, the number of adult deer in Jefferson Circus, and the number of adult fox in Mayer Aquarium. The number of adult fox in Mayer Aquarium equals 2 times the number of adult deer in Jefferson Circus.

Question: What is the total number of adult animals in Mayer Aquarium?

Solution: Define adult deer in Jefferson Circus as z; so z = 1. Define adult fox in Mayer Aquarium as J; m = z = 1; so J = 2 * m = 2 * 1 = 2. Define total number of adult animals in Jefferson Circus as F; so F = z = 1. Define adult deer in Mayer Aquarium as q; x = F + z = 1 + 1 = 2; t = x + J = 2 + 2 = 4; so q = 1 + t = 1 + 4 = 5. Define total number of adult animals in Mayer Aquarium as K; so K = J + q = 2 + 5 = 7. Answer: 7.


The number of public highschool in Evervale City equals the sum of the number of regional medical school in Evervale City and the number of regional medical school in Hawkesbury. The number of public highschool in Hawkesbury equals the number of regional medical school in Hawkesbury. The number of regional medical school in Evervale City equals 4 plus the total number of schools in Hawkesbury. The number of regional medical school in Hawkesbury equals 2.

Question: What is the total number of schools in Evervale City?

Solution: Define regional medical school in Hawkesbury as t; so t = 2. Define public highschool in Hawkesbury as g; so g = t = 2. Define total number of schools in Hawkesbury as s; so s = g + t = 2 + 2 = 4. Define regional medical school in Evervale City as P; Z = s = 4; so P = 4 + Z = 4 + 4 = 8. Define public highschool in Evervale City as o; so o = P + t = 8 + 2 = 10. Define total number of schools in Evervale City as Q; so Q = o + P = 10 + 8 = 18. Answer: 18.


The number of public highschool in Glenfield City equals 4. The number of private middle school in Glenfield City equals the difference between the total number of schools in Westhaven City and the number of public highschool in Westhaven City. The number of private middle school in Westhaven City equals 3. The number of public highschool in Westhaven City equals 1 plus the number of private middle school in Westhaven City.

Question: What is the total number of schools in Glenfield City?

Solution: Define private middle school in Westhaven City as r; so r = 3. Define public highschool in Westhaven City as H; i = r = 3; so H = 1 + i = 1 + 3 = 4. Define total number of schools in Westhaven City as p; so p = r + H = 3 + 4 = 7. Define public highschool in Glenfield City as C; so C = 4. Define private middle school in Glenfield City as v; so v = p - H = 7 - 4 = 3. Define total number of schools in Glenfield City as B; so B = v + C = 3 + 4 = 7. Answer: 7.


The number of adult parrot in Pine Ridge equals 2. The number of adult crow in Pine Ridge equals 3. The number of adult crow in Cedar Valley equals the number of adult parrot in Cedar Valley. The number of adult parrot in Cedar Valley equals the sum of the total number of adult animals in Pine Ridge, the number of adult crow in Pine Ridge, and the number of adult parrot in Pine Ridge.

Question: What is the total number of adult animals in Cedar Valley?

Solution: Define adult crow in Pine Ridge as w; so w = 3. Define adult parrot in Pine Ridge as j; so j = 2. Define total number of adult animals in Pine Ridge as g; so g = j + w = 2 + 3 = 5. Define adult parrot in Cedar Valley as m; x = g + w = 5 + 3 = 8; so m = x + j = 8 + 2 = 10. Define adult crow in Cedar Valley as K; so K = m = 10. Define total number of adult animals in Cedar Valley as Q; so Q = m + K = 10 + 10 = 20. Answer: 20.