The number of culinarian school in Shoreline City equals 4. The number of elementary school in Riverton City equals 4 times the sum of the total number of schools in Shoreline City, the number of culinarian school in Shoreline City, and the number of culinarian school in Riverton City. The number of elementary school in Shoreline City equals 3 times the number of culinarian school in Riverton City. The number of culinarian school in Riverton City equals 3.

Question: How many elementary school does Riverton City have?

Solution: Define culinarian school in Riverton City as x; so x = 3. Define elementary school in Shoreline City as D; o = x = 3; so D = 3 * o = 3 * 3 = 9. Define culinarian school in Shoreline City as X; so X = 4. Define total number of schools in Shoreline City as B; so B = X + D = 4 + 9 = 13. Define elementary school in Riverton City as f; n = B + X = 13 + 4 = 17; T = n + x = 17 + 3 = 20; so f = 4 * T = 4 * 20 = 80. Answer: 80.


The number of intense detective thriller in Festival Lumière de Valmont equals 2 times the sum of the total number of movies in Festival de Clairmont and the number of calm road movie in Festival de Clairmont. The number of futuristic sci-fi movie in Festival Lumière de Valmont equals the sum of the number of intense detective thriller in Festival Lumière de Valmont, the number of calm road movie in Festival de Clairmont, and the total number of movies in Festival de Clairmont. The number of calm road movie in Festival de Clairmont equals 2. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals 3.

Question: What is the total number of movies in Festival Lumière de Valmont?

Solution: Define calm road movie in Festival de Clairmont as o; so o = 2. Define total number of movies in Festival de Clairmont as v; so v = o = 2. Define intense detective thriller in Festival Lumière de Valmont as X; r = v + o = 2 + 2 = 4; so X = 2 * r = 2 * 4 = 8. Define futuristic sci-fi movie in Festival Lumière de Valmont as i; B = X + o = 8 + 2 = 10; so i = B + v = 10 + 2 = 12. Define total number of movies in Festival Lumière de Valmont as U; so U = X + i = 8 + 12 = 20. Answer: 20.


The number of elementary school in Hawkesbury equals 3 times the sum of the total number of schools in Evervale City and the number of public highschool in Evervale City. The number of public highschool in Evervale City equals 1. The number of public highschool in Hawkesbury equals 2 plus the sum of the total number of schools in Evervale City and the number of elementary school in Hawkesbury.

Question: What is the total number of schools in Hawkesbury?

Solution: Define public highschool in Evervale City as o; so o = 1. Define total number of schools in Evervale City as Y; so Y = o = 1. Define elementary school in Hawkesbury as E; V = Y + o = 1 + 1 = 2; so E = 3 * V = 3 * 2 = 6. Define public highschool in Hawkesbury as k; O = Y + E = 1 + 6 = 7; so k = 2 + O = 2 + 7 = 9. Define total number of schools in Hawkesbury as M; so M = E + k = 6 + 9 = 15. Answer: 15.


The number of adult deer in Maple Creek equals 2. The number of adult racoon in Maple Creek equals 4 plus the number of adult deer in Beverly Forest. The number of adult racoon in Beverly Forest equals 4 plus the sum of the total number of adult animals in Maple Creek, the number of adult deer in Maple Creek, and the number of adult deer in Beverly Forest. The number of adult deer in Beverly Forest equals 4.

Question: How many adult racoon does Beverly Forest have?

Solution: Define adult deer in Beverly Forest as i; so i = 4. Define adult racoon in Maple Creek as n; X = i = 4; so n = 4 + X = 4 + 4 = 8. Define adult deer in Maple Creek as w; so w = 2. Define total number of adult animals in Maple Creek as s; so s = w + n = 2 + 8 = 10. Define adult racoon in Beverly Forest as x; o = s + w = 10 + 2 = 12; R = o + i = 12 + 4 = 16; so x = 4 + R = 4 + 16 = 20. Answer: 20.


The number of adult blue jay in Mayer Aquarium equals the sum of the number of adult crow in Bundle Ranch, the total number of adult animals in Bundle Ranch, and the number of adult crow in Mayer Aquarium. The number of adult crow in Mayer Aquarium equals 2 plus the sum of the total number of adult animals in Bundle Ranch and the number of adult crow in Bundle Ranch. The number of adult crow in Bundle Ranch equals 1.

Question: What is the total number of adult animals in Mayer Aquarium?

Solution: Define adult crow in Bundle Ranch as m; so m = 1. Define total number of adult animals in Bundle Ranch as g; so g = m = 1. Define adult crow in Mayer Aquarium as v; B = g + m = 1 + 1 = 2; so v = 2 + B = 2 + 2 = 4. Define adult blue jay in Mayer Aquarium as e; C = m + g = 1 + 1 = 2; so e = C + v = 2 + 4 = 6. Define total number of adult animals in Mayer Aquarium as b; so b = e + v = 6 + 4 = 10. Answer: 10.


The number of public highschool in Oakbridge City equals 4. The number of elementary school in Shoreline City equals the sum of the total number of schools in Clearwater Bay, the number of culinarian school in Clearwater Bay, the number of public highschool in Shoreline City, and the total number of schools in Shoreline City. The number of culinarian school in Clearwater Bay equals 3 times the number of public highschool in Shoreline City. The number of elementary school in Ruby Bay equals 1 plus the sum of the total number of schools in Clearwater Bay, the number of public highschool in Shoreline City, and the number of private middle school in Clearwater Bay. The number of private middle school in Clearwater Bay equals the number of public highschool in Shoreline City. The number of public highschool in Ruby Bay equals 3 plus the sum of the number of elementary school in Shoreline City, the number of elementary school in Ruby Bay, and the number of private middle school in Clearwater Bay. The number of culinarian school in Oakbridge City equals the number of public highschool in Riverton City. The number of private middle school in Oakbridge City equals the sum of the number of public highschool in Ruby Bay, the total number of schools in Shoreline City, the number of elementary school in Ruby Bay, and the total number of schools in Clearwater Bay. The number of private middle school in Ruby Bay equals 1. The number of public highschool in Shoreline City equals 2. The number of public highschool in Riverton City equals the number of private middle school in Ruby Bay. The number of elementary school in Riverton City equals the number of private middle school in Ruby Bay.

Question: How many elementary school does Ruby Bay have?

Solution: Define public highschool in Shoreline City as a; so a = 2. Define culinarian school in Clearwater Bay as i; l = a = 2; so i = 3 * l = 3 * 2 = 6. Define private middle school in Clearwater Bay as m; so m = a = 2. Define total number of schools in Clearwater Bay as p; so p = m + i = 2 + 6 = 8. Define elementary school in Ruby Bay as P; Y = p + a = 8 + 2 = 10; z = Y + m = 10 + 2 = 12; so P = 1 + z = 1 + 12 = 13. Answer: 13.


The number of adult eagle in Bundle Ranch equals 2 plus the number of adult eagle in South Zoo. The number of adult parrot in South Zoo equals the number of adult eagle in South Zoo. The number of adult parrot in Bundle Ranch equals 3 plus the total number of adult animals in South Zoo. The number of adult eagle in South Zoo equals 4.

Question: What is the total number of adult animals in Bundle Ranch?

Solution: Define adult eagle in South Zoo as A; so A = 4. Define adult parrot in South Zoo as J; so J = A = 4. Define total number of adult animals in South Zoo as U; so U = A + J = 4 + 4 = 8. Define adult parrot in Bundle Ranch as D; q = U = 8; so D = 3 + q = 3 + 8 = 11. Define adult eagle in Bundle Ranch as M; p = A = 4; so M = 2 + p = 2 + 4 = 6. Define total number of adult animals in Bundle Ranch as n; so n = M + D = 6 + 11 = 17. Answer: 17.


The number of futuristic sci-fi movie in Festival de Saint-Rivage equals 1 plus the sum of the total number of movies in Cinéma de Montreval, the number of solemn period drama in Cinéma de Montreval, and the number of futuristic sci-fi movie in Cinéma de Montreval. The number of solemn period drama in Cinéma de Montreval equals 2. The number of futuristic sci-fi movie in Cinéma de Montreval equals 3 plus the number of solemn period drama in Cinéma de Montreval.

Question: What is the total number of movies in Festival de Saint-Rivage?

Solution: Define solemn period drama in Cinéma de Montreval as J; so J = 2. Define futuristic sci-fi movie in Cinéma de Montreval as Q; b = J = 2; so Q = 3 + b = 3 + 2 = 5. Define total number of movies in Cinéma de Montreval as A; so A = J + Q = 2 + 5 = 7. Define futuristic sci-fi movie in Festival de Saint-Rivage as k; i = A + J = 7 + 2 = 9; s = i + Q = 9 + 5 = 14; so k = 1 + s = 1 + 14 = 15. Define total number of movies in Festival de Saint-Rivage as W; so W = k = 15. Answer: 15.


The number of private middle school in Glenfield City equals the total number of schools in Brightford. The number of elementary school in Brightford equals the number of private middle school in Brightford. The number of private middle school in Brightford equals 4. The number of elementary school in Glenfield City equals the sum of the number of private middle school in Brightford, the total number of schools in Brightford, and the number of elementary school in Brightford.

Question: What is the total number of schools in Glenfield City?

Solution: Define private middle school in Brightford as Z; so Z = 4. Define elementary school in Brightford as D; so D = Z = 4. Define total number of schools in Brightford as s; so s = Z + D = 4 + 4 = 8. Define private middle school in Glenfield City as Y; so Y = s = 8. Define elementary school in Glenfield City as I; d = Z + s = 4 + 8 = 12; so I = d + D = 12 + 4 = 16. Define total number of schools in Glenfield City as B; so B = Y + I = 8 + 16 = 24. Answer: 24.