The number of adult bear in South Zoo equals the sum of the number of adult fox in Mayer Aquarium and the number of adult bear in Jefferson Circus. The number of adult deer in Mayer Aquarium equals 2 times the total number of adult animals in South Zoo. The number of adult fox in Mayer Aquarium equals 2. The number of adult racoon in Hamilton Farm equals 3. The number of adult bear in Jefferson Circus equals 3 plus the total number of adult animals in Hamilton Farm. The number of adult deer in South Zoo equals the total number of adult animals in Jefferson Circus.

Question: What is the total number of adult animals in Mayer Aquarium?

Solution: Define adult racoon in Hamilton Farm as B; so B = 3. Define total number of adult animals in Hamilton Farm as b; so b = B = 3. Define adult bear in Jefferson Circus as Y; f = b = 3; so Y = 3 + f = 3 + 3 = 6. Define total number of adult animals in Jefferson Circus as x; so x = Y = 6. Define adult deer in South Zoo as r; so r = x = 6. Define adult fox in Mayer Aquarium as v; so v = 2. Define adult bear in South Zoo as t; so t = v + Y = 2 + 6 = 8. Define total number of adult animals in South Zoo as u; so u = r + t = 6 + 8 = 14. Define adult deer in Mayer Aquarium as G; h = u = 14; so G = 2 * h = 2 * 14 = 28. Define total number of adult animals in Mayer Aquarium as D; so D = v + G = 2 + 28 = 30. Answer: 30.


The number of adult wolf in Cedar Valley equals 2. The number of adult wolf in Oakridge Riverside equals 2 times the number of adult racoon in Beverly Forest. The number of adult racoon in Oakridge Riverside equals 2 times the sum of the number of adult wolf in Oakridge Riverside, the number of adult wolf in Cedar Valley, and the number of adult racoon in Beverly Forest. The number of adult fox in Beverly Forest equals the sum of the number of adult deer in Beverly Forest, the number of adult wolf in Cedar Valley, the number of adult wolf in Oakridge Riverside, and the number of adult racoon in Oakridge Riverside. The number of adult fox in Oakridge Riverside equals 2 plus the difference between the number of adult racoon in Oakridge Riverside and the number of adult deer in Beverly Forest. The number of adult deer in Beverly Forest equals 2 times the number of adult racoon in Oakridge Riverside. The number of adult racoon in Beverly Forest equals 3 times the number of adult wolf in Cedar Valley. The number of adult fox in Cedar Valley equals 4. The number of adult deer in Oakridge Riverside equals 4. The number of adult wolf in Beverly Forest equals 2. The number of adult deer in Cedar Valley equals the sum of the total number of adult animals in Beverly Forest and the number of adult fox in Oakridge Riverside. The number of adult racoon in Cedar Valley equals the number of adult wolf in Cedar Valley.

Question: How many adult fox does Beverly Forest have?

Solution: Define adult wolf in Cedar Valley as N; so N = 2. Define adult racoon in Beverly Forest as z; e = N = 2; so z = 3 * e = 3 * 2 = 6. Define adult wolf in Oakridge Riverside as C; O = z = 6; so C = 2 * O = 2 * 6 = 12. Define adult racoon in Oakridge Riverside as Q; g = C + N = 12 + 2 = 14; m = g + z = 14 + 6 = 20; so Q = 2 * m = 2 * 20 = 40. Define adult deer in Beverly Forest as V; t = Q = 40; so V = 2 * t = 2 * 40 = 80. Define adult fox in Beverly Forest as K; r = V + N = 80 + 2 = 82; j = r + C = 82 + 12 = 94; so K = j + Q = 94 + 40 = 134. Answer: 134.


The number of calm road movie in Verdi Movie Festival equals 3 plus the sum of the number of solemn period drama in West Sahara Movie Festival and the number of intense detective thriller in West Sahara Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals 2. The number of solemn period drama in Golden Banana Movie Festival equals the number of calm road movie in Golden Banana Movie Festival. The number of intense detective thriller in Golden Banana Movie Festival equals 4 times the sum of the number of calm road movie in Golden Banana Movie Festival and the number of solemn period drama in Golden Banana Movie Festival. The number of solemn period drama in West Sahara Movie Festival equals the number of calm road movie in West Sahara Movie Festival. The number of calm road movie in West Sahara Movie Festival equals 2. The number of intense detective thriller in West Sahara Movie Festival equals 2. The number of intense detective thriller in Verdi Movie Festival equals the difference between the total number of movies in West Sahara Movie Festival and the number of intense detective thriller in West Sahara Movie Festival. The number of solemn period drama in Verdi Movie Festival equals the number of intense detective thriller in Verdi Movie Festival.

Question: What is the total number of movies in Verdi Movie Festival?

Solution: Define calm road movie in West Sahara Movie Festival as i; so i = 2. Define intense detective thriller in West Sahara Movie Festival as s; so s = 2. Define solemn period drama in West Sahara Movie Festival as I; so I = i = 2. Define total number of movies in West Sahara Movie Festival as P; Y = i + I = 2 + 2 = 4; so P = Y + s = 4 + 2 = 6. Define intense detective thriller in Verdi Movie Festival as y; so y = P - s = 6 - 2 = 4. Define calm road movie in Verdi Movie Festival as g; G = I + s = 2 + 2 = 4; so g = 3 + G = 3 + 4 = 7. Define solemn period drama in Verdi Movie Festival as F; so F = y = 4. Define total number of movies in Verdi Movie Festival as l; M = g + F = 7 + 4 = 11; so l = M + y = 11 + 4 = 15. Answer: 15.


The number of culinarian school in Shoreline City equals 4 times the sum of the number of culinarian school in Clearwater Bay and the number of public highschool in Clearwater Bay. The number of public highschool in Oakbridge City equals 2 times the total number of schools in Riverton City. The number of culinarian school in Clearwater Bay equals 2. The number of elementary school in Riverton City equals the total number of schools in Clearwater Bay. The number of elementary school in Shoreline City equals 4 times the sum of the total number of schools in Oakbridge City, the number of culinarian school in Clearwater Bay, and the number of public highschool in Clearwater Bay. The number of public highschool in Clearwater Bay equals 1. The number of private middle school in Riverton City equals the difference between the number of culinarian school in Shoreline City and the total number of schools in Clearwater Bay.

Question: What is the total number of schools in Oakbridge City?

Solution: Define public highschool in Clearwater Bay as s; so s = 1. Define culinarian school in Clearwater Bay as V; so V = 2. Define total number of schools in Clearwater Bay as k; so k = V + s = 2 + 1 = 3. Define elementary school in Riverton City as T; so T = k = 3. Define culinarian school in Shoreline City as d; L = V + s = 2 + 1 = 3; so d = 4 * L = 4 * 3 = 12. Define private middle school in Riverton City as c; so c = d - k = 12 - 3 = 9. Define total number of schools in Riverton City as x; so x = T + c = 3 + 9 = 12. Define public highschool in Oakbridge City as l; n = x = 12; so l = 2 * n = 2 * 12 = 24. Define total number of schools in Oakbridge City as y; so y = l = 24. Answer: 24.


The number of calm road movie in Festival de Saint-Rivage equals the sum of the number of calm road movie in Rêves de Belleville and the number of solemn period drama in Rêves de Belleville. The number of intense detective thriller in Festival Lumière de Valmont equals 1 plus the number of solemn period drama in Rêves de Belleville. The number of solemn period drama in Festival Lumière de Valmont equals the number of solemn period drama in Rêves de Belleville. The number of solemn period drama in Festival de Saint-Rivage equals the number of calm road movie in Festival de Saint-Rivage. The number of calm road movie in Festival Lumière de Valmont equals the number of intense detective thriller in Festival Lumière de Valmont. The number of solemn period drama in Rêves de Belleville equals 2. The number of calm road movie in Rêves de Belleville equals 4 plus the total number of movies in Festival Lumière de Valmont.

Question: What is the total number of movies in Festival de Saint-Rivage?

Solution: Define solemn period drama in Rêves de Belleville as q; so q = 2. Define intense detective thriller in Festival Lumière de Valmont as V; a = q = 2; so V = 1 + a = 1 + 2 = 3. Define solemn period drama in Festival Lumière de Valmont as K; so K = q = 2. Define calm road movie in Festival Lumière de Valmont as g; so g = V = 3. Define total number of movies in Festival Lumière de Valmont as L; D = K + V = 2 + 3 = 5; so L = D + g = 5 + 3 = 8. Define calm road movie in Rêves de Belleville as s; I = L = 8; so s = 4 + I = 4 + 8 = 12. Define calm road movie in Festival de Saint-Rivage as l; so l = s + q = 12 + 2 = 14. Define solemn period drama in Festival de Saint-Rivage as U; so U = l = 14. Define total number of movies in Festival de Saint-Rivage as n; so n = U + l = 14 + 14 = 28. Answer: 28.


The number of elementary school in Clearwater Bay equals the sum of the total number of schools in Riverton City and the number of public highschool in Riverton City. The number of public highschool in Riverton City equals 3. The number of public highschool in Clearwater Bay equals 2. The number of private middle school in Clearwater Bay equals 4 plus the number of public highschool in Riverton City. The number of private middle school in Shoreline City equals the difference between the total number of schools in Clearwater Bay and the number of public highschool in Clearwater Bay. The number of elementary school in Shoreline City equals the number of public highschool in Clearwater Bay.

Question: What is the total number of schools in Shoreline City?

Solution: Define public highschool in Riverton City as r; so r = 3. Define total number of schools in Riverton City as H; so H = r = 3. Define elementary school in Clearwater Bay as t; so t = H + r = 3 + 3 = 6. Define public highschool in Clearwater Bay as h; so h = 2. Define private middle school in Clearwater Bay as M; A = r = 3; so M = 4 + A = 4 + 3 = 7. Define total number of schools in Clearwater Bay as Q; m = h + t = 2 + 6 = 8; so Q = m + M = 8 + 7 = 15. Define private middle school in Shoreline City as O; so O = Q - h = 15 - 2 = 13. Define elementary school in Shoreline City as v; so v = h = 2. Define total number of schools in Shoreline City as n; so n = v + O = 2 + 13 = 15. Answer: 15.


The number of adult blue jay in Beverly Forest equals the total number of adult animals in Pine Ridge. The number of adult parrot in Beverly Forest equals the number of adult blue jay in Pine Ridge. The number of adult parrot in Pine Ridge equals the sum of the number of adult blue jay in Pine Ridge and the number of adult blue jay in Maple Creek. The number of adult blue jay in Pine Ridge equals 4 times the total number of adult animals in Maple Creek. The number of adult parrot in Maple Creek equals 1 plus the number of adult blue jay in Maple Creek. The number of adult blue jay in Maple Creek equals 2.

Question: What is the total number of adult animals in Beverly Forest?

Solution: Define adult blue jay in Maple Creek as g; so g = 2. Define adult parrot in Maple Creek as G; J = g = 2; so G = 1 + J = 1 + 2 = 3. Define total number of adult animals in Maple Creek as P; so P = G + g = 3 + 2 = 5. Define adult blue jay in Pine Ridge as y; Y = P = 5; so y = 4 * Y = 4 * 5 = 20. Define adult parrot in Pine Ridge as v; so v = y + g = 20 + 2 = 22. Define total number of adult animals in Pine Ridge as q; so q = v + y = 22 + 20 = 42. Define adult blue jay in Beverly Forest as C; so C = q = 42. Define adult parrot in Beverly Forest as d; so d = y = 20. Define total number of adult animals in Beverly Forest as p; so p = d + C = 20 + 42 = 62. Answer: 62.


The number of adult wolf in Pine Ridge equals the number of adult racoon in Pine Ridge. The number of adult racoon in Beverly Forest equals the sum of the total number of adult animals in Pine Ridge and the number of adult fox in Pine Ridge. The number of adult wolf in Oakridge Riverside equals the sum of the number of adult fox in Pine Ridge, the number of adult fox in Beverly Forest, the number of adult wolf in Beverly Forest, and the total number of adult animals in Pine Ridge. The number of adult racoon in Oakridge Riverside equals 2. The number of adult racoon in Pine Ridge equals 4. The number of adult wolf in Beverly Forest equals 3 plus the total number of adult animals in Pine Ridge. The number of adult fox in Pine Ridge equals the number of adult racoon in Oakridge Riverside. The number of adult fox in Oakridge Riverside equals 2. The number of adult fox in Beverly Forest equals 4.

Question: What is the total number of adult animals in Beverly Forest?

Solution: Define adult racoon in Oakridge Riverside as s; so s = 2. Define adult fox in Pine Ridge as k; so k = s = 2. Define adult racoon in Pine Ridge as L; so L = 4. Define adult wolf in Pine Ridge as p; so p = L = 4. Define total number of adult animals in Pine Ridge as G; x = k + L = 2 + 4 = 6; so G = x + p = 6 + 4 = 10. Define adult wolf in Beverly Forest as m; c = G = 10; so m = 3 + c = 3 + 10 = 13. Define adult fox in Beverly Forest as V; so V = 4. Define adult racoon in Beverly Forest as N; so N = G + k = 10 + 2 = 12. Define total number of adult animals in Beverly Forest as C; B = V + N = 4 + 12 = 16; so C = B + m = 16 + 13 = 29. Answer: 29.


The number of adult eagle in Bundle Ranch equals 1. The number of adult blue jay in Bundle Ranch equals the sum of the number of adult eagle in Bundle Ranch, the number of adult crow in South Zoo, the number of adult eagle in Mayer Aquarium, and the number of adult eagle in South Zoo. The number of adult crow in Bundle Ranch equals 4. The number of adult crow in Mayer Aquarium equals the total number of adult animals in South Zoo. The number of adult eagle in South Zoo equals 3 plus the number of adult blue jay in Mayer Aquarium. The number of adult eagle in Mayer Aquarium equals the number of adult crow in Bundle Ranch. The number of adult blue jay in Mayer Aquarium equals 3 times the number of adult crow in Bundle Ranch. The number of adult blue jay in South Zoo equals the number of adult eagle in South Zoo. The number of adult crow in South Zoo equals 2 times the sum of the number of adult eagle in Mayer Aquarium, the number of adult crow in Bundle Ranch, and the number of adult blue jay in Mayer Aquarium.

Question: How many adult crow does Mayer Aquarium have?

Solution: Define adult crow in Bundle Ranch as M; so M = 4. Define adult blue jay in Mayer Aquarium as q; n = M = 4; so q = 3 * n = 3 * 4 = 12. Define adult eagle in South Zoo as e; O = q = 12; so e = 3 + O = 3 + 12 = 15. Define adult eagle in Mayer Aquarium as a; so a = M = 4. Define adult crow in South Zoo as K; i = a + M = 4 + 4 = 8; C = i + q = 8 + 12 = 20; so K = 2 * C = 2 * 20 = 40. Define adult blue jay in South Zoo as p; so p = e = 15. Define total number of adult animals in South Zoo as u; w = K + p = 40 + 15 = 55; so u = w + e = 55 + 15 = 70. Define adult crow in Mayer Aquarium as c; so c = u = 70. Answer: 70.


The number of elementary school in Shoreline City equals the number of private middle school in Ruby Bay. The number of regional medical school in Riverton City equals 3. The number of elementary school in Oakbridge City equals the number of culinarian school in Ruby Bay. The number of culinarian school in Shoreline City equals 1. The number of elementary school in Ruby Bay equals the sum of the number of public highschool in Ruby Bay and the number of culinarian school in Ruby Bay. The number of private middle school in Ruby Bay equals 1 plus the total number of schools in Riverton City. The number of public highschool in Shoreline City equals 3. The number of regional medical school in Shoreline City equals 1 plus the number of regional medical school in Riverton City. The number of culinarian school in Riverton City equals the number of regional medical school in Riverton City. The number of culinarian school in Ruby Bay equals the number of culinarian school in Riverton City. The number of private middle school in Clearwater Bay equals the difference between the total number of schools in Ruby Bay and the number of culinarian school in Shoreline City. The number of public highschool in Oakbridge City equals the difference between the total number of schools in Riverton City and the number of elementary school in Oakbridge City. The number of public highschool in Ruby Bay equals 2 plus the total number of schools in Riverton City. The number of private middle school in Oakbridge City equals 4.

Question: What is the total number of schools in Ruby Bay?

Solution: Define regional medical school in Riverton City as R; so R = 3. Define culinarian school in Riverton City as S; so S = R = 3. Define total number of schools in Riverton City as g; so g = R + S = 3 + 3 = 6. Define public highschool in Ruby Bay as z; v = g = 6; so z = 2 + v = 2 + 6 = 8. Define culinarian school in Ruby Bay as H; so H = S = 3. Define private middle school in Ruby Bay as G; t = g = 6; so G = 1 + t = 1 + 6 = 7. Define elementary school in Ruby Bay as q; so q = z + H = 8 + 3 = 11. Define total number of schools in Ruby Bay as d; W = G + z = 7 + 8 = 15; O = W + q = 15 + 11 = 26; so d = O + H = 26 + 3 = 29. Answer: 29.


The number of adult parrot in Pine Ridge equals 3 plus the number of adult crow in Pine Ridge. The number of adult crow in Pine Ridge equals 3. The number of adult crow in Cedar Valley equals the sum of the total number of adult animals in Pine Ridge, the number of adult parrot in Pine Ridge, and the number of adult crow in Pine Ridge. The number of adult blue jay in Cedar Valley equals the number of adult crow in Cedar Valley. The number of adult parrot in Cedar Valley equals 2 plus the difference between the number of adult crow in Cedar Valley and the total number of adult animals in Pine Ridge.

Question: What is the total number of adult animals in Cedar Valley?

Solution: Define adult crow in Pine Ridge as Y; so Y = 3. Define adult parrot in Pine Ridge as c; j = Y = 3; so c = 3 + j = 3 + 3 = 6. Define total number of adult animals in Pine Ridge as R; so R = c + Y = 6 + 3 = 9. Define adult crow in Cedar Valley as L; M = R + c = 9 + 6 = 15; so L = M + Y = 15 + 3 = 18. Define adult parrot in Cedar Valley as v; P = L - R = 18 - 9 = 9; so v = 2 + P = 2 + 9 = 11. Define adult blue jay in Cedar Valley as s; so s = L = 18. Define total number of adult animals in Cedar Valley as A; J = s + v = 18 + 11 = 29; so A = J + L = 29 + 18 = 47. Answer: 47.


The number of regional medical school in Shoreline City equals the sum of the total number of schools in Oakbridge City and the number of private middle school in Clearwater Bay. The number of private middle school in Clearwater Bay equals 4. The number of elementary school in Oakbridge City equals 3 times the number of private middle school in Clearwater Bay. The number of private middle school in Oakbridge City equals 3 plus the sum of the total number of schools in Clearwater Bay, the number of private middle school in Clearwater Bay, and the number of elementary school in Oakbridge City. The number of elementary school in Shoreline City equals 3.

Question: What is the total number of schools in Shoreline City?

Solution: Define private middle school in Clearwater Bay as n; so n = 4. Define elementary school in Oakbridge City as l; H = n = 4; so l = 3 * H = 3 * 4 = 12. Define total number of schools in Clearwater Bay as N; so N = n = 4. Define private middle school in Oakbridge City as V; e = N + n = 4 + 4 = 8; K = e + l = 8 + 12 = 20; so V = 3 + K = 3 + 20 = 23. Define total number of schools in Oakbridge City as R; so R = V + l = 23 + 12 = 35. Define regional medical school in Shoreline City as i; so i = R + n = 35 + 4 = 39. Define elementary school in Shoreline City as W; so W = 3. Define total number of schools in Shoreline City as x; so x = i + W = 39 + 3 = 42. Answer: 42.


The number of solemn period drama in Festival de Saint-Rivage equals the sum of the total number of movies in Rêves de Belleville and the number of upbeat metropolis comedy in Festival de Saint-Rivage. The number of upbeat metropolis comedy in Cinéma de Montreval equals 1 plus the number of futuristic sci-fi movie in Festival de Saint-Rivage. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals the number of upbeat metropolis comedy in Cinéma de Montreval. The number of upbeat metropolis comedy in Rêves de Belleville equals 1 plus the sum of the number of solemn period drama in Rêves de Belleville and the number of upbeat metropolis comedy in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Rêves de Belleville equals 3. The number of solemn period drama in Rêves de Belleville equals the sum of the number of upbeat metropolis comedy in Festival de Saint-Rivage and the number of upbeat metropolis comedy in Cinéma de Montreval. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals 4.

Question: How many solemn period drama does Festival de Saint-Rivage have?

Solution: Define futuristic sci-fi movie in Festival de Saint-Rivage as s; so s = 4. Define upbeat metropolis comedy in Cinéma de Montreval as o; q = s = 4; so o = 1 + q = 1 + 4 = 5. Define upbeat metropolis comedy in Festival de Saint-Rivage as x; so x = o = 5. Define solemn period drama in Rêves de Belleville as Q; so Q = x + o = 5 + 5 = 10. Define futuristic sci-fi movie in Rêves de Belleville as G; so G = 3. Define upbeat metropolis comedy in Rêves de Belleville as P; E = Q + x = 10 + 5 = 15; so P = 1 + E = 1 + 15 = 16. Define total number of movies in Rêves de Belleville as u; W = P + G = 16 + 3 = 19; so u = W + Q = 19 + 10 = 29. Define solemn period drama in Festival de Saint-Rivage as b; so b = u + x = 29 + 5 = 34. Answer: 34.


The number of adult fox in Cedar Valley equals the difference between the number of adult deer in Cedar Valley and the number of adult fox in Beverly Forest. The number of adult racoon in Maple Creek equals the number of adult deer in Cedar Valley. The number of adult deer in Cedar Valley equals 2 times the number of adult fox in Beverly Forest. The number of adult fox in Beverly Forest equals 4. The number of adult bear in Beverly Forest equals the sum of the total number of adult animals in Maple Creek, the number of adult fox in Beverly Forest, and the number of adult racoon in Maple Creek. The number of adult fox in Maple Creek equals 2 plus the total number of adult animals in Cedar Valley.

Question: How many adult bear does Beverly Forest have?

Solution: Define adult fox in Beverly Forest as f; so f = 4. Define adult deer in Cedar Valley as S; B = f = 4; so S = 2 * B = 2 * 4 = 8. Define adult fox in Cedar Valley as R; so R = S - f = 8 - 4 = 4. Define total number of adult animals in Cedar Valley as M; so M = S + R = 8 + 4 = 12. Define adult fox in Maple Creek as l; d = M = 12; so l = 2 + d = 2 + 12 = 14. Define adult racoon in Maple Creek as y; so y = S = 8. Define total number of adult animals in Maple Creek as O; so O = l + y = 14 + 8 = 22. Define adult bear in Beverly Forest as o; N = O + f = 22 + 4 = 26; so o = N + y = 26 + 8 = 34. Answer: 34.


The number of adult fox in Maple Creek equals 4 plus the difference between the number of adult bear in Beverly Forest and the number of adult fox in Beverly Forest. The number of adult fox in Oakridge Riverside equals the sum of the number of adult bear in Beverly Forest, the number of adult fox in Maple Creek, and the total number of adult animals in Maple Creek. The number of adult fox in Beverly Forest equals 4. The number of adult wolf in Oakridge Riverside equals the sum of the total number of adult animals in Maple Creek, the number of adult fox in Maple Creek, and the number of adult bear in Beverly Forest. The number of adult bear in Beverly Forest equals 2 times the number of adult fox in Beverly Forest.

Question: What is the total number of adult animals in Oakridge Riverside?

Solution: Define adult fox in Beverly Forest as e; so e = 4. Define adult bear in Beverly Forest as N; R = e = 4; so N = 2 * R = 2 * 4 = 8. Define adult fox in Maple Creek as w; q = N - e = 8 - 4 = 4; so w = 4 + q = 4 + 4 = 8. Define total number of adult animals in Maple Creek as r; so r = w = 8. Define adult wolf in Oakridge Riverside as Y; B = r + w = 8 + 8 = 16; so Y = B + N = 16 + 8 = 24. Define adult fox in Oakridge Riverside as o; v = N + w = 8 + 8 = 16; so o = v + r = 16 + 8 = 24. Define total number of adult animals in Oakridge Riverside as k; so k = Y + o = 24 + 24 = 48. Answer: 48.


The number of adult fox in Mayer Aquarium equals the difference between the total number of adult animals in South Zoo and the total number of adult animals in Hamilton Farm. The number of adult fox in Hamilton Farm equals 4. The number of adult deer in South Zoo equals 2 times the total number of adult animals in Hamilton Farm. The number of adult racoon in Mayer Aquarium equals 3. The number of adult deer in Hamilton Farm equals 3 times the number of adult racoon in Hamilton Farm. The number of adult racoon in Hamilton Farm equals 3.

Question: What is the total number of adult animals in Mayer Aquarium?

Solution: Define adult racoon in Hamilton Farm as n; so n = 3. Define adult deer in Hamilton Farm as z; M = n = 3; so z = 3 * M = 3 * 3 = 9. Define adult fox in Hamilton Farm as a; so a = 4. Define total number of adult animals in Hamilton Farm as v; e = a + n = 4 + 3 = 7; so v = e + z = 7 + 9 = 16. Define adult deer in South Zoo as Z; H = v = 16; so Z = 2 * H = 2 * 16 = 32. Define total number of adult animals in South Zoo as T; so T = Z = 32. Define adult fox in Mayer Aquarium as b; so b = T - v = 32 - 16 = 16. Define adult racoon in Mayer Aquarium as g; so g = 3. Define total number of adult animals in Mayer Aquarium as Q; so Q = b + g = 16 + 3 = 19. Answer: 19.


The number of futuristic sci-fi movie in Rêves de Belleville equals 4 times the difference between the number of intense detective thriller in Rêves de Belleville and the number of upbeat metropolis comedy in Rêves de Belleville. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals the number of futuristic sci-fi movie in Rêves de Belleville. The number of futuristic sci-fi movie in Festival de Clairmont equals the sum of the total number of movies in Festival Lumière de Valmont and the number of upbeat metropolis comedy in Rêves de Belleville. The number of upbeat metropolis comedy in Rêves de Belleville equals 2. The number of intense detective thriller in Rêves de Belleville equals 3 plus the number of upbeat metropolis comedy in Rêves de Belleville. The number of intense detective thriller in Festival Lumière de Valmont equals the sum of the total number of movies in Festival de Saint-Rivage, the number of intense detective thriller in Rêves de Belleville, the number of futuristic sci-fi movie in Festival de Saint-Rivage, and the number of upbeat metropolis comedy in Rêves de Belleville.

Question: How many futuristic sci-fi movie does Festival de Clairmont have?

Solution: Define upbeat metropolis comedy in Rêves de Belleville as h; so h = 2. Define intense detective thriller in Rêves de Belleville as b; H = h = 2; so b = 3 + H = 3 + 2 = 5. Define futuristic sci-fi movie in Rêves de Belleville as m; Y = b - h = 5 - 2 = 3; so m = 4 * Y = 4 * 3 = 12. Define futuristic sci-fi movie in Festival de Saint-Rivage as P; so P = m = 12. Define total number of movies in Festival de Saint-Rivage as l; so l = P = 12. Define intense detective thriller in Festival Lumière de Valmont as p; T = l + b = 12 + 5 = 17; S = T + P = 17 + 12 = 29; so p = S + h = 29 + 2 = 31. Define total number of movies in Festival Lumière de Valmont as F; so F = p = 31. Define futuristic sci-fi movie in Festival de Clairmont as e; so e = F + h = 31 + 2 = 33. Answer: 33.