The number of adult owl in South Zoo equals 2 times the number of adult parrot in Bundle Ranch. The number of adult blue jay in Hamilton Farm equals 3 plus the difference between the number of adult owl in Hamilton Farm and the number of adult owl in South Zoo. The number of adult owl in Bundle Ranch equals the sum of the number of adult owl in South Zoo, the number of adult blue jay in Hamilton Farm, and the number of adult owl in Hamilton Farm. The number of adult parrot in Hamilton Farm equals the sum of the number of adult blue jay in South Zoo, the number of adult parrot in Bundle Ranch, and the number of adult owl in South Zoo. The number of adult parrot in Bundle Ranch equals 4. The number of adult blue jay in Bundle Ranch equals 3 times the number of adult parrot in South Zoo. The number of adult blue jay in South Zoo equals 4 plus the number of adult owl in South Zoo. The number of adult parrot in South Zoo equals 3. The number of adult owl in Hamilton Farm equals the number of adult parrot in Hamilton Farm.

Question: What is the total number of adult animals in Hamilton Farm?

Solution: Define adult parrot in Bundle Ranch as M; so M = 4. Define adult owl in South Zoo as y; D = M = 4; so y = 2 * D = 2 * 4 = 8. Define adult blue jay in South Zoo as u; k = y = 8; so u = 4 + k = 4 + 8 = 12. Define adult parrot in Hamilton Farm as L; q = u + M = 12 + 4 = 16; so L = q + y = 16 + 8 = 24. Define adult owl in Hamilton Farm as v; so v = L = 24. Define adult blue jay in Hamilton Farm as V; l = v - y = 24 - 8 = 16; so V = 3 + l = 3 + 16 = 19. Define total number of adult animals in Hamilton Farm as g; x = v + V = 24 + 19 = 43; so g = x + L = 43 + 24 = 67. Answer: 67.


The number of adult deer in Cedar Valley equals the difference between the number of adult fox in Cedar Valley and the number of adult wolf in Cedar Valley. The number of adult wolf in Oakridge Riverside equals 4 times the difference between the number of adult bear in Oakridge Riverside and the number of adult racoon in Pine Ridge. The number of adult fox in Cedar Valley equals the number of adult wolf in Cedar Valley. The number of adult racoon in Maple Creek equals the sum of the total number of adult animals in Cedar Valley and the number of adult fox in Cedar Valley. The number of adult bear in Maple Creek equals 4. The number of adult wolf in Cedar Valley equals 3. The number of adult deer in Oakridge Riverside equals 4. The number of adult deer in Beverly Forest equals 3 plus the sum of the number of adult bear in Oakridge Riverside, the number of adult racoon in Pine Ridge, and the number of adult wolf in Oakridge Riverside. The number of adult racoon in Pine Ridge equals 4 times the number of adult bear in Oakridge Riverside. The number of adult wolf in Pine Ridge equals the sum of the number of adult bear in Oakridge Riverside, the number of adult deer in Cedar Valley, and the number of adult racoon in Pine Ridge. The number of adult bear in Oakridge Riverside equals 3. The number of adult racoon in Cedar Valley equals 2 times the number of adult wolf in Cedar Valley.

Question: What is the total number of adult animals in Maple Creek?

Solution: Define adult wolf in Cedar Valley as M; so M = 3. Define adult racoon in Cedar Valley as f; F = M = 3; so f = 2 * F = 2 * 3 = 6. Define adult fox in Cedar Valley as b; so b = M = 3. Define adult deer in Cedar Valley as k; so k = b - M = 3 - 3 = 0. Define total number of adult animals in Cedar Valley as B; K = M + k = 3 + 0 = 3; z = K + f = 3 + 6 = 9; so B = z + b = 9 + 3 = 12. Define adult racoon in Maple Creek as w; so w = B + b = 12 + 3 = 15. Define adult bear in Maple Creek as o; so o = 4. Define total number of adult animals in Maple Creek as y; so y = o + w = 4 + 15 = 19. Answer: 19.


The number of adult blue jay in Cedar Valley equals 4 times the number of adult eagle in Cedar Valley. The number of adult blue jay in Oakridge Riverside equals 2. The number of adult crow in Beverly Forest equals the sum of the number of adult blue jay in Cedar Valley, the number of adult owl in Cedar Valley, and the number of adult eagle in Pine Ridge. The number of adult crow in Cedar Valley equals the difference between the total number of adult animals in Oakridge Riverside and the number of adult parrot in Pine Ridge. The number of adult eagle in Cedar Valley equals 4 plus the sum of the number of adult owl in Cedar Valley, the number of adult blue jay in Oakridge Riverside, and the number of adult eagle in Pine Ridge. The number of adult owl in Oakridge Riverside equals 2. The number of adult owl in Pine Ridge equals the number of adult crow in Beverly Forest. The number of adult parrot in Oakridge Riverside equals 4. The number of adult crow in Pine Ridge equals 2 plus the sum of the number of adult crow in Cedar Valley, the number of adult owl in Cedar Valley, and the number of adult owl in Oakridge Riverside. The number of adult parrot in Pine Ridge equals 1. The number of adult eagle in Pine Ridge equals 4 plus the number of adult blue jay in Oakridge Riverside. The number of adult owl in Cedar Valley equals 1 plus the number of adult eagle in Pine Ridge. The number of adult parrot in Cedar Valley equals 4 plus the sum of the number of adult blue jay in Cedar Valley and the number of adult crow in Beverly Forest.

Question: What is the total number of adult animals in Beverly Forest?

Solution: Define adult blue jay in Oakridge Riverside as Y; so Y = 2. Define adult eagle in Pine Ridge as d; D = Y = 2; so d = 4 + D = 4 + 2 = 6. Define adult owl in Cedar Valley as o; E = d = 6; so o = 1 + E = 1 + 6 = 7. Define adult eagle in Cedar Valley as A; L = o + Y = 7 + 2 = 9; a = L + d = 9 + 6 = 15; so A = 4 + a = 4 + 15 = 19. Define adult blue jay in Cedar Valley as k; p = A = 19; so k = 4 * p = 4 * 19 = 76. Define adult crow in Beverly Forest as b; K = k + o = 76 + 7 = 83; so b = K + d = 83 + 6 = 89. Define total number of adult animals in Beverly Forest as W; so W = b = 89. Answer: 89.


The number of calm road movie in West Sahara Movie Festival equals 4. The number of intense detective thriller in West Sahara Movie Festival equals 1 plus the sum of the total number of movies in Taylor Movie Festival, the number of calm road movie in West Sahara Movie Festival, and the number of upbeat metropolis comedy in Taylor Movie Festival. The number of calm road movie in Taylor Movie Festival equals 4 times the number of calm road movie in West Sahara Movie Festival. The number of intense detective thriller in Taylor Movie Festival equals the number of calm road movie in Taylor Movie Festival. The number of upbeat metropolis comedy in West Sahara Movie Festival equals the number of intense detective thriller in West Sahara Movie Festival. The number of upbeat metropolis comedy in Taylor Movie Festival equals 1 plus the sum of the number of calm road movie in West Sahara Movie Festival and the number of calm road movie in Taylor Movie Festival.

Question: How many upbeat metropolis comedy does West Sahara Movie Festival have?

Solution: Define calm road movie in West Sahara Movie Festival as I; so I = 4. Define calm road movie in Taylor Movie Festival as l; S = I = 4; so l = 4 * S = 4 * 4 = 16. Define upbeat metropolis comedy in Taylor Movie Festival as O; u = I + l = 4 + 16 = 20; so O = 1 + u = 1 + 20 = 21. Define intense detective thriller in Taylor Movie Festival as m; so m = l = 16. Define total number of movies in Taylor Movie Festival as o; s = m + l = 16 + 16 = 32; so o = s + O = 32 + 21 = 53. Define intense detective thriller in West Sahara Movie Festival as h; C = o + I = 53 + 4 = 57; v = C + O = 57 + 21 = 78; so h = 1 + v = 1 + 78 = 79. Define upbeat metropolis comedy in West Sahara Movie Festival as y; so y = h = 79. Answer: 79.


The number of adult deer in Mayer Aquarium equals the number of adult fox in Mayer Aquarium. The number of adult wolf in Jefferson Circus equals 2. The number of adult fox in Jefferson Circus equals 3 times the sum of the number of adult wolf in Jefferson Circus, the number of adult deer in Bundle Ranch, and the number of adult fox in Mayer Aquarium. The number of adult wolf in Bundle Ranch equals the number of adult wolf in Jefferson Circus. The number of adult deer in Jefferson Circus equals the total number of adult animals in Bundle Ranch. The number of adult wolf in Mayer Aquarium equals 3. The number of adult fox in Bundle Ranch equals 4 times the total number of adult animals in Mayer Aquarium. The number of adult fox in Mayer Aquarium equals 4 plus the number of adult wolf in Jefferson Circus. The number of adult deer in Bundle Ranch equals 4.

Question: What is the total number of adult animals in Bundle Ranch?

Solution: Define adult wolf in Jefferson Circus as e; so e = 2. Define adult fox in Mayer Aquarium as X; k = e = 2; so X = 4 + k = 4 + 2 = 6. Define adult deer in Mayer Aquarium as h; so h = X = 6. Define adult wolf in Mayer Aquarium as M; so M = 3. Define total number of adult animals in Mayer Aquarium as W; v = h + X = 6 + 6 = 12; so W = v + M = 12 + 3 = 15. Define adult fox in Bundle Ranch as c; g = W = 15; so c = 4 * g = 4 * 15 = 60. Define adult wolf in Bundle Ranch as T; so T = e = 2. Define adult deer in Bundle Ranch as N; so N = 4. Define total number of adult animals in Bundle Ranch as r; O = N + c = 4 + 60 = 64; so r = O + T = 64 + 2 = 66. Answer: 66.


The number of adult fox in Mayer Aquarium equals 4. The number of adult bear in South Zoo equals 4. The number of adult fox in South Zoo equals the total number of adult animals in Mayer Aquarium. The number of adult fox in Bundle Ranch equals 2. The number of adult fox in Jefferson Circus equals 1. The number of adult deer in Bundle Ranch equals the sum of the total number of adult animals in South Zoo and the number of adult fox in Mayer Aquarium. The number of adult bear in Mayer Aquarium equals the number of adult fox in Mayer Aquarium. The number of adult deer in South Zoo equals the number of adult fox in Mayer Aquarium. The number of adult bear in Jefferson Circus equals 3. The number of adult bear in Bundle Ranch equals 2. The number of adult deer in Jefferson Circus equals 3. The number of adult deer in Mayer Aquarium equals 2 times the number of adult fox in Mayer Aquarium.

Question: How many adult deer does Bundle Ranch have?

Solution: Define adult fox in Mayer Aquarium as o; so o = 4. Define adult bear in Mayer Aquarium as I; so I = o = 4. Define adult deer in Mayer Aquarium as G; J = o = 4; so G = 2 * J = 2 * 4 = 8. Define adult deer in South Zoo as W; so W = o = 4. Define adult bear in South Zoo as l; so l = 4. Define total number of adult animals in Mayer Aquarium as V; E = G + I = 8 + 4 = 12; so V = E + o = 12 + 4 = 16. Define adult fox in South Zoo as v; so v = V = 16. Define total number of adult animals in South Zoo as d; D = l + v = 4 + 16 = 20; so d = D + W = 20 + 4 = 24. Define adult deer in Bundle Ranch as H; so H = d + o = 24 + 4 = 28. Answer: 28.


The number of upbeat metropolis comedy in Taylor Movie Festival equals the number of solemn period drama in Northwood Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals 3. The number of upbeat metropolis comedy in Northwood Movie Festival equals the difference between the total number of movies in Taylor Movie Festival and the number of solemn period drama in Northwood Movie Festival. The number of intense detective thriller in Taylor Movie Festival equals 2. The number of solemn period drama in Northwood Movie Festival equals the total number of movies in Golden Banana Movie Festival. The number of intense detective thriller in Golden Banana Movie Festival equals the number of solemn period drama in Golden Banana Movie Festival. The number of solemn period drama in Taylor Movie Festival equals the number of upbeat metropolis comedy in Taylor Movie Festival. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals the number of intense detective thriller in Golden Banana Movie Festival. The number of intense detective thriller in Northwood Movie Festival equals the number of solemn period drama in Golden Banana Movie Festival.

Question: How many upbeat metropolis comedy does Northwood Movie Festival have?

Solution: Define solemn period drama in Golden Banana Movie Festival as k; so k = 3. Define intense detective thriller in Golden Banana Movie Festival as b; so b = k = 3. Define upbeat metropolis comedy in Golden Banana Movie Festival as K; so K = b = 3. Define total number of movies in Golden Banana Movie Festival as q; U = K + k = 3 + 3 = 6; so q = U + b = 6 + 3 = 9. Define solemn period drama in Northwood Movie Festival as Y; so Y = q = 9. Define upbeat metropolis comedy in Taylor Movie Festival as N; so N = Y = 9. Define intense detective thriller in Taylor Movie Festival as j; so j = 2. Define solemn period drama in Taylor Movie Festival as A; so A = N = 9. Define total number of movies in Taylor Movie Festival as u; Q = N + A = 9 + 9 = 18; so u = Q + j = 18 + 2 = 20. Define upbeat metropolis comedy in Northwood Movie Festival as P; so P = u - Y = 20 - 9 = 11. Answer: 11.


The number of private middle school in Ruby Bay equals the number of public highschool in Ruby Bay. The number of public highschool in Shoreline City equals 3 times the total number of schools in Ruby Bay. The number of public highschool in Oakbridge City equals the number of private middle school in Shoreline City. The number of private middle school in Oakbridge City equals 3 times the difference between the number of private middle school in Shoreline City and the total number of schools in Ruby Bay. The number of private middle school in Shoreline City equals 4. The number of elementary school in Oakbridge City equals 3 plus the number of public highschool in Shoreline City. The number of elementary school in Ruby Bay equals the number of private middle school in Shoreline City. The number of public highschool in Ruby Bay equals the sum of the number of culinarian school in Ruby Bay and the number of private middle school in Shoreline City. The number of culinarian school in Ruby Bay equals 3 times the number of private middle school in Shoreline City.

Question: How many elementary school does Oakbridge City have?

Solution: Define private middle school in Shoreline City as H; so H = 4. Define culinarian school in Ruby Bay as c; V = H = 4; so c = 3 * V = 3 * 4 = 12. Define public highschool in Ruby Bay as Y; so Y = c + H = 12 + 4 = 16. Define private middle school in Ruby Bay as n; so n = Y = 16. Define elementary school in Ruby Bay as e; so e = H = 4. Define total number of schools in Ruby Bay as Z; B = Y + e = 16 + 4 = 20; W = B + n = 20 + 16 = 36; so Z = W + c = 36 + 12 = 48. Define public highschool in Shoreline City as w; h = Z = 48; so w = 3 * h = 3 * 48 = 144. Define elementary school in Oakbridge City as f; R = w = 144; so f = 3 + R = 3 + 144 = 147. Answer: 147.