The number of adult fox in Bundle Ranch equals the sum of the total number of adult animals in Hamilton Farm and the number of adult fox in Hamilton Farm. The number of adult wolf in South Zoo equals 4 plus the number of adult fox in South Zoo. The number of adult fox in Mayer Aquarium equals the number of adult fox in Bundle Ranch. The number of adult fox in Hamilton Farm equals 2. The number of adult racoon in Mayer Aquarium equals the sum of the total number of adult animals in South Zoo and the number of adult fox in Hamilton Farm. The number of adult fox in South Zoo equals the total number of adult animals in Bundle Ranch.

Question: What is the total number of adult animals in Mayer Aquarium?

Solution: Define adult fox in Hamilton Farm as t; so t = 2. Define total number of adult animals in Hamilton Farm as n; so n = t = 2. Define adult fox in Bundle Ranch as G; so G = n + t = 2 + 2 = 4. Define total number of adult animals in Bundle Ranch as a; so a = G = 4. Define adult fox in South Zoo as S; so S = a = 4. Define adult wolf in South Zoo as X; u = S = 4; so X = 4 + u = 4 + 4 = 8. Define total number of adult animals in South Zoo as w; so w = X + S = 8 + 4 = 12. Define adult racoon in Mayer Aquarium as h; so h = w + t = 12 + 2 = 14. Define adult fox in Mayer Aquarium as o; so o = G = 4. Define total number of adult animals in Mayer Aquarium as M; so M = h + o = 14 + 4 = 18. Answer: 18.


The number of futuristic sci-fi movie in Verdi Movie Festival equals 3 plus the total number of movies in Taylor Movie Festival. The number of intense detective thriller in West Sahara Movie Festival equals the sum of the total number of movies in Golden Banana Movie Festival, the total number of movies in Taylor Movie Festival, and the total number of movies in Verdi Movie Festival. The number of intense detective thriller in Golden Banana Movie Festival equals 4 times the total number of movies in Verdi Movie Festival. The number of futuristic sci-fi movie in Taylor Movie Festival equals 4 plus the number of upbeat metropolis comedy in Taylor Movie Festival. The number of upbeat metropolis comedy in Taylor Movie Festival equals 4.

Question: What is the total number of movies in West Sahara Movie Festival?

Solution: Define upbeat metropolis comedy in Taylor Movie Festival as J; so J = 4. Define futuristic sci-fi movie in Taylor Movie Festival as C; s = J = 4; so C = 4 + s = 4 + 4 = 8. Define total number of movies in Taylor Movie Festival as l; so l = J + C = 4 + 8 = 12. Define futuristic sci-fi movie in Verdi Movie Festival as w; X = l = 12; so w = 3 + X = 3 + 12 = 15. Define total number of movies in Verdi Movie Festival as H; so H = w = 15. Define intense detective thriller in Golden Banana Movie Festival as o; x = H = 15; so o = 4 * x = 4 * 15 = 60. Define total number of movies in Golden Banana Movie Festival as t; so t = o = 60. Define intense detective thriller in West Sahara Movie Festival as F; I = t + l = 60 + 12 = 72; so F = I + H = 72 + 15 = 87. Define total number of movies in West Sahara Movie Festival as u; so u = F = 87. Answer: 87.


The number of adult blue jay in Pine Ridge equals 4 plus the sum of the number of adult crow in Maple Creek and the number of adult blue jay in Maple Creek. The number of adult crow in Maple Creek equals 4 plus the number of adult owl in Oakridge Riverside. The number of adult owl in Oakridge Riverside equals 4 plus the sum of the number of adult blue jay in Maple Creek, the number of adult owl in Maple Creek, and the number of adult blue jay in Oakridge Riverside. The number of adult crow in Pine Ridge equals 2. The number of adult blue jay in Maple Creek equals 2 plus the sum of the number of adult blue jay in Oakridge Riverside and the number of adult owl in Maple Creek. The number of adult owl in Maple Creek equals 3. The number of adult blue jay in Oakridge Riverside equals 4 plus the number of adult owl in Maple Creek. The number of adult owl in Pine Ridge equals 2 times the number of adult crow in Pine Ridge.

Question: How many adult blue jay does Pine Ridge have?

Solution: Define adult owl in Maple Creek as z; so z = 3. Define adult blue jay in Oakridge Riverside as b; P = z = 3; so b = 4 + P = 4 + 3 = 7. Define adult blue jay in Maple Creek as C; o = b + z = 7 + 3 = 10; so C = 2 + o = 2 + 10 = 12. Define adult owl in Oakridge Riverside as F; q = C + z = 12 + 3 = 15; y = q + b = 15 + 7 = 22; so F = 4 + y = 4 + 22 = 26. Define adult crow in Maple Creek as K; w = F = 26; so K = 4 + w = 4 + 26 = 30. Define adult blue jay in Pine Ridge as c; Y = K + C = 30 + 12 = 42; so c = 4 + Y = 4 + 42 = 46. Answer: 46.


The number of adult racoon in Cedar Valley equals 3 times the number of adult bear in Cedar Valley. The number of adult deer in Maple Creek equals 4 times the sum of the number of adult fox in Pine Ridge and the number of adult racoon in Pine Ridge. The number of adult racoon in Oakridge Riverside equals 4 times the total number of adult animals in Cedar Valley. The number of adult deer in Pine Ridge equals the difference between the number of adult fox in Cedar Valley and the number of adult fox in Pine Ridge. The number of adult bear in Cedar Valley equals 1. The number of adult bear in Oakridge Riverside equals 2 plus the number of adult racoon in Oakridge Riverside. The number of adult deer in Cedar Valley equals the number of adult fox in Cedar Valley. The number of adult racoon in Maple Creek equals 3 times the total number of adult animals in Cedar Valley. The number of adult fox in Pine Ridge equals 3. The number of adult fox in Cedar Valley equals 2. The number of adult racoon in Pine Ridge equals 3 plus the number of adult fox in Pine Ridge. The number of adult bear in Maple Creek equals 2. The number of adult bear in Pine Ridge equals 3.

Question: What is the total number of adult animals in Oakridge Riverside?

Solution: Define adult fox in Cedar Valley as Y; so Y = 2. Define adult bear in Cedar Valley as W; so W = 1. Define adult deer in Cedar Valley as F; so F = Y = 2. Define adult racoon in Cedar Valley as Z; B = W = 1; so Z = 3 * B = 3 * 1 = 3. Define total number of adult animals in Cedar Valley as u; j = W + Y = 1 + 2 = 3; c = j + F = 3 + 2 = 5; so u = c + Z = 5 + 3 = 8. Define adult racoon in Oakridge Riverside as V; O = u = 8; so V = 4 * O = 4 * 8 = 32. Define adult bear in Oakridge Riverside as k; H = V = 32; so k = 2 + H = 2 + 32 = 34. Define total number of adult animals in Oakridge Riverside as w; so w = k + V = 34 + 32 = 66. Answer: 66.


The number of adult racoon in Mayer Aquarium equals the number of adult wolf in Mayer Aquarium. The number of adult wolf in Hamilton Farm equals 1. The number of adult wolf in Mayer Aquarium equals 3 times the sum of the total number of adult animals in Hamilton Farm, the number of adult wolf in Hamilton Farm, and the number of adult bear in Hamilton Farm. The number of adult wolf in Bundle Ranch equals the sum of the total number of adult animals in Mayer Aquarium and the number of adult wolf in Hamilton Farm. The number of adult bear in Hamilton Farm equals 3 plus the number of adult wolf in Hamilton Farm.

Question: What is the total number of adult animals in Bundle Ranch?

Solution: Define adult wolf in Hamilton Farm as Q; so Q = 1. Define adult bear in Hamilton Farm as D; s = Q = 1; so D = 3 + s = 3 + 1 = 4. Define total number of adult animals in Hamilton Farm as C; so C = Q + D = 1 + 4 = 5. Define adult wolf in Mayer Aquarium as h; c = C + Q = 5 + 1 = 6; O = c + D = 6 + 4 = 10; so h = 3 * O = 3 * 10 = 30. Define adult racoon in Mayer Aquarium as a; so a = h = 30. Define total number of adult animals in Mayer Aquarium as R; so R = h + a = 30 + 30 = 60. Define adult wolf in Bundle Ranch as j; so j = R + Q = 60 + 1 = 61. Define total number of adult animals in Bundle Ranch as B; so B = j = 61. Answer: 61.


The number of elementary school in Oakbridge City equals 4. The number of public highschool in Shoreline City equals 4 plus the sum of the total number of schools in Riverton City and the number of public highschool in Riverton City. The number of public highschool in Riverton City equals 2 times the total number of schools in Oakbridge City. The number of culinarian school in Ruby Bay equals 3 plus the total number of schools in Shoreline City. The number of public highschool in Oakbridge City equals 3 plus the number of elementary school in Oakbridge City.

Question: What is the total number of schools in Ruby Bay?

Solution: Define elementary school in Oakbridge City as o; so o = 4. Define public highschool in Oakbridge City as c; L = o = 4; so c = 3 + L = 3 + 4 = 7. Define total number of schools in Oakbridge City as u; so u = o + c = 4 + 7 = 11. Define public highschool in Riverton City as w; z = u = 11; so w = 2 * z = 2 * 11 = 22. Define total number of schools in Riverton City as m; so m = w = 22. Define public highschool in Shoreline City as S; b = m + w = 22 + 22 = 44; so S = 4 + b = 4 + 44 = 48. Define total number of schools in Shoreline City as P; so P = S = 48. Define culinarian school in Ruby Bay as d; W = P = 48; so d = 3 + W = 3 + 48 = 51. Define total number of schools in Ruby Bay as O; so O = d = 51. Answer: 51.


The number of elementary school in Ruby Bay equals 2. The number of culinarian school in Shoreline City equals 3 times the total number of schools in Riverton City. The number of culinarian school in Ruby Bay equals 3. The number of elementary school in Oakbridge City equals 4 plus the sum of the total number of schools in Ruby Bay and the number of culinarian school in Ruby Bay. The number of public highschool in Riverton City equals 3 times the difference between the total number of schools in Oakbridge City and the number of culinarian school in Ruby Bay.

Question: What is the total number of schools in Shoreline City?

Solution: Define culinarian school in Ruby Bay as u; so u = 3. Define elementary school in Ruby Bay as c; so c = 2. Define total number of schools in Ruby Bay as Z; so Z = c + u = 2 + 3 = 5. Define elementary school in Oakbridge City as U; T = Z + u = 5 + 3 = 8; so U = 4 + T = 4 + 8 = 12. Define total number of schools in Oakbridge City as e; so e = U = 12. Define public highschool in Riverton City as C; p = e - u = 12 - 3 = 9; so C = 3 * p = 3 * 9 = 27. Define total number of schools in Riverton City as W; so W = C = 27. Define culinarian school in Shoreline City as M; d = W = 27; so M = 3 * d = 3 * 27 = 81. Define total number of schools in Shoreline City as G; so G = M = 81. Answer: 81.


The number of adult blue jay in Mayer Aquarium equals the difference between the total number of adult animals in Bundle Ranch and the number of adult owl in Bundle Ranch. The number of adult owl in Jefferson Circus equals 3 times the total number of adult animals in Mayer Aquarium. The number of adult parrot in South Zoo equals 4 plus the difference between the total number of adult animals in Jefferson Circus and the total number of adult animals in Mayer Aquarium. The number of adult owl in Bundle Ranch equals 3 times the number of adult eagle in Bundle Ranch. The number of adult eagle in Bundle Ranch equals 2.

Question: What is the total number of adult animals in South Zoo?

Solution: Define adult eagle in Bundle Ranch as R; so R = 2. Define adult owl in Bundle Ranch as Q; o = R = 2; so Q = 3 * o = 3 * 2 = 6. Define total number of adult animals in Bundle Ranch as B; so B = R + Q = 2 + 6 = 8. Define adult blue jay in Mayer Aquarium as C; so C = B - Q = 8 - 6 = 2. Define total number of adult animals in Mayer Aquarium as D; so D = C = 2. Define adult owl in Jefferson Circus as K; m = D = 2; so K = 3 * m = 3 * 2 = 6. Define total number of adult animals in Jefferson Circus as Z; so Z = K = 6. Define adult parrot in South Zoo as t; i = Z - D = 6 - 2 = 4; so t = 4 + i = 4 + 4 = 8. Define total number of adult animals in South Zoo as P; so P = t = 8. Answer: 8.


The number of public highschool in Ruby Bay equals 3. The number of elementary school in Clearwater Bay equals the sum of the number of culinarian school in Ruby Bay and the number of culinarian school in Oakbridge City. The number of private middle school in Ruby Bay equals 4. The number of private middle school in Shoreline City equals 1 plus the total number of schools in Oakbridge City. The number of culinarian school in Oakbridge City equals the difference between the number of elementary school in Oakbridge City and the number of public highschool in Oakbridge City. The number of private middle school in Oakbridge City equals 1 plus the number of private middle school in Ruby Bay. The number of elementary school in Oakbridge City equals 4 plus the number of private middle school in Oakbridge City. The number of culinarian school in Ruby Bay equals the sum of the number of culinarian school in Oakbridge City, the number of private middle school in Oakbridge City, the total number of schools in Oakbridge City, and the total number of schools in Shoreline City. The number of public highschool in Oakbridge City equals the number of private middle school in Ruby Bay.

Question: What is the total number of schools in Shoreline City?

Solution: Define private middle school in Ruby Bay as M; so M = 4. Define private middle school in Oakbridge City as m; e = M = 4; so m = 1 + e = 1 + 4 = 5. Define public highschool in Oakbridge City as Q; so Q = M = 4. Define elementary school in Oakbridge City as t; k = m = 5; so t = 4 + k = 4 + 5 = 9. Define culinarian school in Oakbridge City as Z; so Z = t - Q = 9 - 4 = 5. Define total number of schools in Oakbridge City as O; X = Z + m = 5 + 5 = 10; S = X + t = 10 + 9 = 19; so O = S + Q = 19 + 4 = 23. Define private middle school in Shoreline City as q; j = O = 23; so q = 1 + j = 1 + 23 = 24. Define total number of schools in Shoreline City as I; so I = q = 24. Answer: 24.


The number of adult eagle in Pine Ridge equals 2. The number of adult owl in Maple Creek equals the number of adult blue jay in Oakridge Riverside. The number of adult blue jay in Cedar Valley equals 2 plus the sum of the total number of adult animals in Pine Ridge, the number of adult blue jay in Pine Ridge, and the total number of adult animals in Maple Creek. The number of adult eagle in Cedar Valley equals the number of adult blue jay in Pine Ridge. The number of adult blue jay in Oakridge Riverside equals 1. The number of adult owl in Beverly Forest equals 3. The number of adult parrot in Beverly Forest equals 4. The number of adult parrot in Oakridge Riverside equals 4. The number of adult blue jay in Beverly Forest equals the sum of the total number of adult animals in Maple Creek, the total number of adult animals in Oakridge Riverside, and the number of adult blue jay in Cedar Valley. The number of adult parrot in Pine Ridge equals the sum of the total number of adult animals in Maple Creek, the number of adult blue jay in Oakridge Riverside, and the number of adult owl in Maple Creek. The number of adult parrot in Cedar Valley equals the number of adult owl in Beverly Forest. The number of adult blue jay in Pine Ridge equals the number of adult parrot in Pine Ridge.

Question: How many adult blue jay does Cedar Valley have?

Solution: Define adult blue jay in Oakridge Riverside as N; so N = 1. Define adult owl in Maple Creek as L; so L = N = 1. Define total number of adult animals in Maple Creek as j; so j = L = 1. Define adult parrot in Pine Ridge as x; C = j + N = 1 + 1 = 2; so x = C + L = 2 + 1 = 3. Define adult blue jay in Pine Ridge as c; so c = x = 3. Define adult eagle in Pine Ridge as p; so p = 2. Define total number of adult animals in Pine Ridge as Y; P = c + p = 3 + 2 = 5; so Y = P + x = 5 + 3 = 8. Define adult blue jay in Cedar Valley as G; W = Y + c = 8 + 3 = 11; B = W + j = 11 + 1 = 12; so G = 2 + B = 2 + 12 = 14. Answer: 14.


The number of solemn period drama in Cinéma de Montreval equals the number of upbeat metropolis comedy in Cinéma de Montreval. The number of intense detective thriller in Cinéma de Montreval equals the number of solemn period drama in Cinéma de Montreval. The number of solemn period drama in Festival Lumière de Valmont equals the number of intense detective thriller in Rêves de Belleville. The number of intense detective thriller in Festival Lumière de Valmont equals 1. The number of upbeat metropolis comedy in Cinéma de Montreval equals the difference between the total number of movies in Festival Lumière de Valmont and the number of intense detective thriller in Rêves de Belleville. The number of upbeat metropolis comedy in Rêves de Belleville equals the difference between the number of intense detective thriller in Festival Lumière de Valmont and the total number of movies in Cinéma de Montreval. The number of solemn period drama in Rêves de Belleville equals 2 times the total number of movies in Cinéma de Montreval. The number of intense detective thriller in Rêves de Belleville equals 2 plus the number of intense detective thriller in Festival Lumière de Valmont.

Question: How many solemn period drama does Rêves de Belleville have?

Solution: Define intense detective thriller in Festival Lumière de Valmont as R; so R = 1. Define intense detective thriller in Rêves de Belleville as l; n = R = 1; so l = 2 + n = 2 + 1 = 3. Define solemn period drama in Festival Lumière de Valmont as i; so i = l = 3. Define total number of movies in Festival Lumière de Valmont as H; so H = R + i = 1 + 3 = 4. Define upbeat metropolis comedy in Cinéma de Montreval as r; so r = H - l = 4 - 3 = 1. Define solemn period drama in Cinéma de Montreval as I; so I = r = 1. Define intense detective thriller in Cinéma de Montreval as j; so j = I = 1. Define total number of movies in Cinéma de Montreval as K; Z = j + I = 1 + 1 = 2; so K = Z + r = 2 + 1 = 3. Define solemn period drama in Rêves de Belleville as c; g = K = 3; so c = 2 * g = 2 * 3 = 6. Answer: 6.


The number of regional medical school in Hawkesbury equals 4. The number of private middle school in Hawkesbury equals 1 plus the number of regional medical school in Hawkesbury. The number of private middle school in Glenfield City equals 2 times the number of culinarian school in Glenfield City. The number of culinarian school in Hawkesbury equals 2. The number of culinarian school in Evervale City equals the total number of schools in Glenfield City. The number of regional medical school in Glenfield City equals 4 plus the number of culinarian school in Glenfield City. The number of regional medical school in Evervale City equals 2 times the number of culinarian school in Glenfield City. The number of private middle school in Evervale City equals 3. The number of culinarian school in Glenfield City equals 3.

Question: What is the total number of schools in Evervale City?

Solution: Define culinarian school in Glenfield City as Y; so Y = 3. Define private middle school in Glenfield City as p; v = Y = 3; so p = 2 * v = 2 * 3 = 6. Define regional medical school in Glenfield City as z; U = Y = 3; so z = 4 + U = 4 + 3 = 7. Define total number of schools in Glenfield City as B; l = Y + z = 3 + 7 = 10; so B = l + p = 10 + 6 = 16. Define culinarian school in Evervale City as N; so N = B = 16. Define private middle school in Evervale City as w; so w = 3. Define regional medical school in Evervale City as F; J = Y = 3; so F = 2 * J = 2 * 3 = 6. Define total number of schools in Evervale City as k; D = N + F = 16 + 6 = 22; so k = D + w = 22 + 3 = 25. Answer: 25.


The number of adult deer in Beverly Forest equals 3. The number of adult wolf in Beverly Forest equals 1 plus the number of adult deer in Beverly Forest. The number of adult wolf in Maple Creek equals the difference between the total number of adult animals in Oakridge Riverside and the number of adult wolf in Oakridge Riverside. The number of adult wolf in Oakridge Riverside equals 2 times the total number of adult animals in Beverly Forest. The number of adult bear in Oakridge Riverside equals the sum of the number of adult wolf in Oakridge Riverside, the number of adult wolf in Beverly Forest, and the total number of adult animals in Beverly Forest.

Question: What is the total number of adult animals in Maple Creek?

Solution: Define adult deer in Beverly Forest as k; so k = 3. Define adult wolf in Beverly Forest as Z; c = k = 3; so Z = 1 + c = 1 + 3 = 4. Define total number of adult animals in Beverly Forest as w; so w = k + Z = 3 + 4 = 7. Define adult wolf in Oakridge Riverside as M; u = w = 7; so M = 2 * u = 2 * 7 = 14. Define adult bear in Oakridge Riverside as j; s = M + Z = 14 + 4 = 18; so j = s + w = 18 + 7 = 25. Define total number of adult animals in Oakridge Riverside as B; so B = j + M = 25 + 14 = 39. Define adult wolf in Maple Creek as S; so S = B - M = 39 - 14 = 25. Define total number of adult animals in Maple Creek as v; so v = S = 25. Answer: 25.


The number of adult owl in Mayer Aquarium equals the total number of adult animals in Jefferson Circus. The number of adult blue jay in South Zoo equals the number of adult eagle in Jefferson Circus. The number of adult blue jay in Jefferson Circus equals 3. The number of adult blue jay in Mayer Aquarium equals the total number of adult animals in Jefferson Circus. The number of adult eagle in Jefferson Circus equals the number of adult blue jay in Jefferson Circus. The number of adult owl in South Zoo equals the total number of adult animals in Mayer Aquarium. The number of adult eagle in South Zoo equals the sum of the number of adult eagle in Jefferson Circus and the number of adult owl in Mayer Aquarium.

Question: What is the total number of adult animals in South Zoo?

Solution: Define adult blue jay in Jefferson Circus as P; so P = 3. Define adult eagle in Jefferson Circus as D; so D = P = 3. Define total number of adult animals in Jefferson Circus as A; so A = D + P = 3 + 3 = 6. Define adult owl in Mayer Aquarium as c; so c = A = 6. Define adult blue jay in Mayer Aquarium as p; so p = A = 6. Define total number of adult animals in Mayer Aquarium as q; so q = c + p = 6 + 6 = 12. Define adult owl in South Zoo as X; so X = q = 12. Define adult eagle in South Zoo as k; so k = D + c = 3 + 6 = 9. Define adult blue jay in South Zoo as z; so z = D = 3. Define total number of adult animals in South Zoo as a; V = k + X = 9 + 12 = 21; so a = V + z = 21 + 3 = 24. Answer: 24.


The number of culinarian school in Ruby Bay equals 3. The number of private middle school in Ruby Bay equals 3 plus the number of culinarian school in Ruby Bay. The number of private middle school in Oakbridge City equals 3 times the sum of the total number of schools in Ruby Bay and the number of private middle school in Ruby Bay. The number of public highschool in Shoreline City equals 1 plus the sum of the total number of schools in Oakbridge City and the total number of schools in Ruby Bay. The number of public highschool in Oakbridge City equals the total number of schools in Ruby Bay.

Question: What is the total number of schools in Shoreline City?

Solution: Define culinarian school in Ruby Bay as R; so R = 3. Define private middle school in Ruby Bay as y; F = R = 3; so y = 3 + F = 3 + 3 = 6. Define total number of schools in Ruby Bay as z; so z = y + R = 6 + 3 = 9. Define private middle school in Oakbridge City as O; N = z + y = 9 + 6 = 15; so O = 3 * N = 3 * 15 = 45. Define public highschool in Oakbridge City as u; so u = z = 9. Define total number of schools in Oakbridge City as s; so s = u + O = 9 + 45 = 54. Define public highschool in Shoreline City as S; o = s + z = 54 + 9 = 63; so S = 1 + o = 1 + 63 = 64. Define total number of schools in Shoreline City as l; so l = S = 64. Answer: 64.


The number of regional medical school in Westhaven City equals 4. The number of private middle school in Westhaven City equals 2. The number of culinarian school in Glenfield City equals the number of regional medical school in Glenfield City. The number of regional medical school in Evervale City equals 4 plus the number of regional medical school in Glenfield City. The number of regional medical school in Glenfield City equals 3 plus the number of private middle school in Westhaven City. The number of regional medical school in Hawkesbury equals 1 plus the number of elementary school in Hawkesbury. The number of culinarian school in Brightford equals 4. The number of elementary school in Glenfield City equals 4 times the number of culinarian school in Brightford. The number of public highschool in Westhaven City equals the difference between the number of culinarian school in Hawkesbury and the total number of schools in Brightford. The number of private middle school in Glenfield City equals the sum of the total number of schools in Hawkesbury, the number of public highschool in Hawkesbury, and the number of regional medical school in Hawkesbury. The number of culinarian school in Hawkesbury equals 4 times the number of public highschool in Hawkesbury. The number of public highschool in Brightford equals the sum of the number of elementary school in Hawkesbury and the total number of schools in Brightford. The number of public highschool in Hawkesbury equals the number of culinarian school in Brightford. The number of elementary school in Hawkesbury equals the sum of the number of culinarian school in Hawkesbury and the number of public highschool in Hawkesbury. The number of private middle school in Evervale City equals 2 times the sum of the number of regional medical school in Evervale City, the number of regional medical school in Glenfield City, and the number of public highschool in Evervale City. The number of regional medical school in Brightford equals 3. The number of public highschool in Evervale City equals the sum of the number of regional medical school in Evervale City and the number of private middle school in Westhaven City.

Question: How many private middle school does Glenfield City have?

Solution: Define culinarian school in Brightford as R; so R = 4. Define public highschool in Hawkesbury as P; so P = R = 4. Define culinarian school in Hawkesbury as O; k = P = 4; so O = 4 * k = 4 * 4 = 16. Define elementary school in Hawkesbury as H; so H = O + P = 16 + 4 = 20. Define regional medical school in Hawkesbury as h; G = H = 20; so h = 1 + G = 1 + 20 = 21. Define total number of schools in Hawkesbury as z; a = P + H = 4 + 20 = 24; K = a + O = 24 + 16 = 40; so z = K + h = 40 + 21 = 61. Define private middle school in Glenfield City as v; u = z + P = 61 + 4 = 65; so v = u + h = 65 + 21 = 86. Answer: 86.


The number of calm road movie in Cinéma de Montreval equals 3 plus the total number of movies in Festival de Clairmont. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals 2 times the sum of the total number of movies in Rêves de Belleville and the number of solemn period drama in Rêves de Belleville. The number of solemn period drama in Rêves de Belleville equals the total number of movies in Cinéma de Montreval. The number of calm road movie in Festival de Clairmont equals 1. The number of intense detective thriller in Rêves de Belleville equals 2. The number of intense detective thriller in Cinéma de Montreval equals the number of calm road movie in Cinéma de Montreval.

Question: What is the total number of movies in Festival de Saint-Rivage?

Solution: Define calm road movie in Festival de Clairmont as R; so R = 1. Define total number of movies in Festival de Clairmont as A; so A = R = 1. Define calm road movie in Cinéma de Montreval as t; I = A = 1; so t = 3 + I = 3 + 1 = 4. Define intense detective thriller in Cinéma de Montreval as b; so b = t = 4. Define total number of movies in Cinéma de Montreval as G; so G = b + t = 4 + 4 = 8. Define solemn period drama in Rêves de Belleville as y; so y = G = 8. Define intense detective thriller in Rêves de Belleville as g; so g = 2. Define total number of movies in Rêves de Belleville as j; so j = g + y = 2 + 8 = 10. Define upbeat metropolis comedy in Festival de Saint-Rivage as O; T = j + y = 10 + 8 = 18; so O = 2 * T = 2 * 18 = 36. Define total number of movies in Festival de Saint-Rivage as e; so e = O = 36. Answer: 36.


The number of private middle school in Brightford equals 4. The number of public highschool in Westhaven City equals 4 times the number of public highschool in Hawkesbury. The number of culinarian school in Hawkesbury equals the number of private middle school in Hawkesbury. The number of culinarian school in Westhaven City equals the number of public highschool in Westhaven City. The number of culinarian school in Brightford equals 3. The number of private middle school in Hawkesbury equals the number of private middle school in Brightford. The number of public highschool in Brightford equals 3. The number of elementary school in Hawkesbury equals 3 times the number of public highschool in Brightford. The number of public highschool in Hawkesbury equals 3 plus the number of culinarian school in Hawkesbury. The number of elementary school in Westhaven City equals 2. The number of private middle school in Westhaven City equals 3 times the number of culinarian school in Westhaven City. The number of elementary school in Brightford equals 2 times the number of public highschool in Brightford.

Question: What is the total number of schools in Westhaven City?

Solution: Define private middle school in Brightford as X; so X = 4. Define private middle school in Hawkesbury as C; so C = X = 4. Define culinarian school in Hawkesbury as n; so n = C = 4. Define public highschool in Hawkesbury as T; J = n = 4; so T = 3 + J = 3 + 4 = 7. Define public highschool in Westhaven City as o; c = T = 7; so o = 4 * c = 4 * 7 = 28. Define culinarian school in Westhaven City as E; so E = o = 28. Define private middle school in Westhaven City as W; V = E = 28; so W = 3 * V = 3 * 28 = 84. Define elementary school in Westhaven City as N; so N = 2. Define total number of schools in Westhaven City as t; S = N + o = 2 + 28 = 30; i = S + E = 30 + 28 = 58; so t = i + W = 58 + 84 = 142. Answer: 142.