The number of solemn period drama in Festival de Saint-Rivage equals 2 times the number of calm road movie in Rêves de Belleville. The number of calm road movie in Rêves de Belleville equals 3. The number of intense detective thriller in Rêves de Belleville equals 3 times the sum of the total number of movies in Festival Lumière de Valmont, the number of upbeat metropolis comedy in Festival Lumière de Valmont, and the number of calm road movie in Rêves de Belleville. The number of intense detective thriller in Cinéma de Montreval equals 3. The number of solemn period drama in Festival Lumière de Valmont equals 1 plus the number of solemn period drama in Festival de Saint-Rivage. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals the total number of movies in Rêves de Belleville. The number of calm road movie in Festival Lumière de Valmont equals 4. The number of solemn period drama in Cinéma de Montreval equals 4 times the number of intense detective thriller in Cinéma de Montreval. The number of upbeat metropolis comedy in Festival Lumière de Valmont equals 2 plus the number of solemn period drama in Festival de Saint-Rivage. The number of calm road movie in Cinéma de Montreval equals 3 times the number of intense detective thriller in Cinéma de Montreval. The number of intense detective thriller in Festival de Saint-Rivage equals 4.

Question: How many intense detective thriller does Rêves de Belleville have?

Solution: Define calm road movie in Rêves de Belleville as z; so z = 3. Define solemn period drama in Festival de Saint-Rivage as H; k = z = 3; so H = 2 * k = 2 * 3 = 6. Define solemn period drama in Festival Lumière de Valmont as X; j = H = 6; so X = 1 + j = 1 + 6 = 7. Define calm road movie in Festival Lumière de Valmont as s; so s = 4. Define upbeat metropolis comedy in Festival Lumière de Valmont as r; Z = H = 6; so r = 2 + Z = 2 + 6 = 8. Define total number of movies in Festival Lumière de Valmont as A; V = r + X = 8 + 7 = 15; so A = V + s = 15 + 4 = 19. Define intense detective thriller in Rêves de Belleville as F; h = A + r = 19 + 8 = 27; x = h + z = 27 + 3 = 30; so F = 3 * x = 3 * 30 = 90. Answer: 90.


The number of adult blue jay in Bundle Ranch equals 4 plus the difference between the number of adult eagle in Bundle Ranch and the number of adult crow in South Zoo. The number of adult eagle in Bundle Ranch equals 2 plus the number of adult crow in Bundle Ranch. The number of adult crow in South Zoo equals the number of adult blue jay in South Zoo. The number of adult crow in Jefferson Circus equals the difference between the number of adult blue jay in Bundle Ranch and the number of adult eagle in South Zoo. The number of adult blue jay in South Zoo equals 2. The number of adult eagle in South Zoo equals 4. The number of adult crow in Bundle Ranch equals the total number of adult animals in South Zoo.

Question: What is the total number of adult animals in Jefferson Circus?

Solution: Define adult blue jay in South Zoo as l; so l = 2. Define adult crow in South Zoo as y; so y = l = 2. Define adult eagle in South Zoo as T; so T = 4. Define total number of adult animals in South Zoo as n; j = T + l = 4 + 2 = 6; so n = j + y = 6 + 2 = 8. Define adult crow in Bundle Ranch as H; so H = n = 8. Define adult eagle in Bundle Ranch as u; P = H = 8; so u = 2 + P = 2 + 8 = 10. Define adult blue jay in Bundle Ranch as B; r = u - y = 10 - 2 = 8; so B = 4 + r = 4 + 8 = 12. Define adult crow in Jefferson Circus as O; so O = B - T = 12 - 4 = 8. Define total number of adult animals in Jefferson Circus as s; so s = O = 8. Answer: 8.


The number of intense detective thriller in West Sahara Movie Festival equals 1 plus the total number of movies in Golden Banana Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals 1 plus the total number of movies in Verdi Movie Festival. The number of solemn period drama in Verdi Movie Festival equals 1 plus the sum of the total number of movies in Northwood Movie Festival and the number of calm road movie in Northwood Movie Festival. The number of calm road movie in Northwood Movie Festival equals 2. The number of futuristic sci-fi movie in Verdi Movie Festival equals 4 times the total number of movies in Northwood Movie Festival.

Question: What is the total number of movies in West Sahara Movie Festival?

Solution: Define calm road movie in Northwood Movie Festival as H; so H = 2. Define total number of movies in Northwood Movie Festival as e; so e = H = 2. Define solemn period drama in Verdi Movie Festival as L; V = e + H = 2 + 2 = 4; so L = 1 + V = 1 + 4 = 5. Define futuristic sci-fi movie in Verdi Movie Festival as K; P = e = 2; so K = 4 * P = 4 * 2 = 8. Define total number of movies in Verdi Movie Festival as G; so G = K + L = 8 + 5 = 13. Define calm road movie in Golden Banana Movie Festival as N; D = G = 13; so N = 1 + D = 1 + 13 = 14. Define total number of movies in Golden Banana Movie Festival as B; so B = N = 14. Define intense detective thriller in West Sahara Movie Festival as F; J = B = 14; so F = 1 + J = 1 + 14 = 15. Define total number of movies in West Sahara Movie Festival as r; so r = F = 15. Answer: 15.


The number of public highschool in Clearwater Bay equals the sum of the total number of schools in Riverton City, the number of public highschool in Riverton City, and the number of culinarian school in Oakbridge City. The number of elementary school in Oakbridge City equals 3. The number of elementary school in Riverton City equals 3 plus the sum of the total number of schools in Oakbridge City, the number of elementary school in Oakbridge City, and the number of culinarian school in Oakbridge City. The number of culinarian school in Oakbridge City equals the number of elementary school in Oakbridge City. The number of public highschool in Riverton City equals the total number of schools in Oakbridge City.

Question: What is the total number of schools in Clearwater Bay?

Solution: Define elementary school in Oakbridge City as O; so O = 3. Define culinarian school in Oakbridge City as z; so z = O = 3. Define total number of schools in Oakbridge City as n; so n = O + z = 3 + 3 = 6. Define elementary school in Riverton City as s; k = n + O = 6 + 3 = 9; g = k + z = 9 + 3 = 12; so s = 3 + g = 3 + 12 = 15. Define public highschool in Riverton City as t; so t = n = 6. Define total number of schools in Riverton City as c; so c = t + s = 6 + 15 = 21. Define public highschool in Clearwater Bay as C; o = c + t = 21 + 6 = 27; so C = o + z = 27 + 3 = 30. Define total number of schools in Clearwater Bay as W; so W = C = 30. Answer: 30.


The number of adult parrot in Pine Ridge equals 4. The number of adult eagle in Maple Creek equals 3. The number of adult owl in Maple Creek equals 4. The number of adult crow in Oakridge Riverside equals 1. The number of adult owl in Oakridge Riverside equals 4 times the number of adult crow in Oakridge Riverside. The number of adult owl in Pine Ridge equals the sum of the number of adult eagle in Maple Creek, the number of adult crow in Oakridge Riverside, the total number of adult animals in Oakridge Riverside, and the number of adult owl in Oakridge Riverside. The number of adult parrot in Oakridge Riverside equals the number of adult owl in Oakridge Riverside. The number of adult parrot in Maple Creek equals the difference between the number of adult eagle in Pine Ridge and the number of adult parrot in Oakridge Riverside. The number of adult eagle in Pine Ridge equals the total number of adult animals in Oakridge Riverside.

Question: What is the total number of adult animals in Maple Creek?

Solution: Define adult crow in Oakridge Riverside as W; so W = 1. Define adult owl in Oakridge Riverside as b; D = W = 1; so b = 4 * D = 4 * 1 = 4. Define adult parrot in Oakridge Riverside as A; so A = b = 4. Define total number of adult animals in Oakridge Riverside as F; u = A + W = 4 + 1 = 5; so F = u + b = 5 + 4 = 9. Define adult eagle in Pine Ridge as z; so z = F = 9. Define adult parrot in Maple Creek as R; so R = z - A = 9 - 4 = 5. Define adult eagle in Maple Creek as k; so k = 3. Define adult owl in Maple Creek as t; so t = 4. Define total number of adult animals in Maple Creek as q; E = R + t = 5 + 4 = 9; so q = E + k = 9 + 3 = 12. Answer: 12.


The number of adult parrot in South Zoo equals 3 times the number of adult owl in South Zoo. The number of adult parrot in Bundle Ranch equals 1 plus the number of adult parrot in South Zoo. The number of adult eagle in Mayer Aquarium equals 3. The number of adult owl in Bundle Ranch equals 3 plus the total number of adult animals in Mayer Aquarium. The number of adult parrot in Mayer Aquarium equals 3 plus the number of adult eagle in Mayer Aquarium. The number of adult eagle in South Zoo equals 1. The number of adult owl in South Zoo equals the sum of the number of adult parrot in Mayer Aquarium and the number of adult eagle in Mayer Aquarium.

Question: What is the total number of adult animals in Bundle Ranch?

Solution: Define adult eagle in Mayer Aquarium as Q; so Q = 3. Define adult parrot in Mayer Aquarium as m; v = Q = 3; so m = 3 + v = 3 + 3 = 6. Define adult owl in South Zoo as Z; so Z = m + Q = 6 + 3 = 9. Define total number of adult animals in Mayer Aquarium as i; so i = Q + m = 3 + 6 = 9. Define adult owl in Bundle Ranch as k; q = i = 9; so k = 3 + q = 3 + 9 = 12. Define adult parrot in South Zoo as h; R = Z = 9; so h = 3 * R = 3 * 9 = 27. Define adult parrot in Bundle Ranch as B; K = h = 27; so B = 1 + K = 1 + 27 = 28. Define total number of adult animals in Bundle Ranch as j; so j = k + B = 12 + 28 = 40. Answer: 40.


The number of adult wolf in Hamilton Farm equals 2. The number of adult deer in Hamilton Farm equals 1 plus the number of adult wolf in Hamilton Farm. The number of adult deer in Bundle Ranch equals the number of adult wolf in Bundle Ranch. The number of adult wolf in Jefferson Circus equals 2. The number of adult wolf in Bundle Ranch equals 1 plus the total number of adult animals in Hamilton Farm. The number of adult deer in Jefferson Circus equals 4 times the total number of adult animals in Bundle Ranch.

Question: What is the total number of adult animals in Jefferson Circus?

Solution: Define adult wolf in Hamilton Farm as P; so P = 2. Define adult deer in Hamilton Farm as Y; u = P = 2; so Y = 1 + u = 1 + 2 = 3. Define total number of adult animals in Hamilton Farm as V; so V = P + Y = 2 + 3 = 5. Define adult wolf in Bundle Ranch as D; c = V = 5; so D = 1 + c = 1 + 5 = 6. Define adult deer in Bundle Ranch as X; so X = D = 6. Define total number of adult animals in Bundle Ranch as x; so x = D + X = 6 + 6 = 12. Define adult deer in Jefferson Circus as z; m = x = 12; so z = 4 * m = 4 * 12 = 48. Define adult wolf in Jefferson Circus as W; so W = 2. Define total number of adult animals in Jefferson Circus as J; so J = W + z = 2 + 48 = 50. Answer: 50.


The number of culinarian school in Glenfield City equals 3. The number of culinarian school in Westhaven City equals the total number of schools in Glenfield City. The number of culinarian school in Evervale City equals 3 times the number of public highschool in Hawkesbury. The number of regional medical school in Evervale City equals 1 plus the total number of schools in Hawkesbury. The number of public highschool in Hawkesbury equals 4 times the total number of schools in Westhaven City. The number of public highschool in Evervale City equals 4.

Question: What is the total number of schools in Evervale City?

Solution: Define culinarian school in Glenfield City as I; so I = 3. Define total number of schools in Glenfield City as F; so F = I = 3. Define culinarian school in Westhaven City as Z; so Z = F = 3. Define total number of schools in Westhaven City as i; so i = Z = 3. Define public highschool in Hawkesbury as A; M = i = 3; so A = 4 * M = 4 * 3 = 12. Define total number of schools in Hawkesbury as q; so q = A = 12. Define regional medical school in Evervale City as Y; e = q = 12; so Y = 1 + e = 1 + 12 = 13. Define culinarian school in Evervale City as J; E = A = 12; so J = 3 * E = 3 * 12 = 36. Define public highschool in Evervale City as K; so K = 4. Define total number of schools in Evervale City as g; P = K + Y = 4 + 13 = 17; so g = P + J = 17 + 36 = 53. Answer: 53.


The number of adult racoon in Jefferson Circus equals the number of adult fox in Jefferson Circus. The number of adult fox in Bundle Ranch equals 2. The number of adult bear in Jefferson Circus equals the number of adult deer in Jefferson Circus. The number of adult deer in Bundle Ranch equals the difference between the number of adult wolf in Jefferson Circus and the number of adult bear in Jefferson Circus. The number of adult wolf in Jefferson Circus equals 4 times the number of adult bear in Jefferson Circus. The number of adult racoon in Bundle Ranch equals 4 times the number of adult wolf in Bundle Ranch. The number of adult fox in Jefferson Circus equals 1. The number of adult wolf in Bundle Ranch equals 4 plus the number of adult wolf in Jefferson Circus. The number of adult deer in Jefferson Circus equals 4.

Question: What is the total number of adult animals in Bundle Ranch?

Solution: Define adult deer in Jefferson Circus as c; so c = 4. Define adult bear in Jefferson Circus as C; so C = c = 4. Define adult wolf in Jefferson Circus as N; a = C = 4; so N = 4 * a = 4 * 4 = 16. Define adult deer in Bundle Ranch as D; so D = N - C = 16 - 4 = 12. Define adult wolf in Bundle Ranch as F; T = N = 16; so F = 4 + T = 4 + 16 = 20. Define adult racoon in Bundle Ranch as t; J = F = 20; so t = 4 * J = 4 * 20 = 80. Define adult fox in Bundle Ranch as K; so K = 2. Define total number of adult animals in Bundle Ranch as h; g = F + D = 20 + 12 = 32; O = g + K = 32 + 2 = 34; so h = O + t = 34 + 80 = 114. Answer: 114.


The number of adult crow in Oakridge Riverside equals 3 times the number of adult owl in Maple Creek. The number of adult crow in Maple Creek equals 4 plus the total number of adult animals in Cedar Valley. The number of adult eagle in Maple Creek equals 2. The number of adult owl in Maple Creek equals 4 times the number of adult eagle in Maple Creek. The number of adult eagle in Oakridge Riverside equals the number of adult crow in Oakridge Riverside. The number of adult eagle in Cedar Valley equals 1 plus the sum of the total number of adult animals in Oakridge Riverside, the number of adult crow in Oakridge Riverside, and the number of adult eagle in Oakridge Riverside.

Question: How many adult crow does Maple Creek have?

Solution: Define adult eagle in Maple Creek as c; so c = 2. Define adult owl in Maple Creek as u; V = c = 2; so u = 4 * V = 4 * 2 = 8. Define adult crow in Oakridge Riverside as t; I = u = 8; so t = 3 * I = 3 * 8 = 24. Define adult eagle in Oakridge Riverside as H; so H = t = 24. Define total number of adult animals in Oakridge Riverside as p; so p = H + t = 24 + 24 = 48. Define adult eagle in Cedar Valley as S; k = p + t = 48 + 24 = 72; i = k + H = 72 + 24 = 96; so S = 1 + i = 1 + 96 = 97. Define total number of adult animals in Cedar Valley as e; so e = S = 97. Define adult crow in Maple Creek as x; T = e = 97; so x = 4 + T = 4 + 97 = 101. Answer: 101.


The number of private middle school in Evervale City equals the number of private middle school in Hawkesbury. The number of regional medical school in Evervale City equals 1. The number of regional medical school in Glenfield City equals 3 plus the number of culinarian school in Evervale City. The number of culinarian school in Hawkesbury equals the sum of the total number of schools in Glenfield City, the number of private middle school in Glenfield City, and the number of culinarian school in Glenfield City. The number of culinarian school in Evervale City equals 3. The number of private middle school in Hawkesbury equals the sum of the number of culinarian school in Hawkesbury and the number of culinarian school in Glenfield City. The number of regional medical school in Hawkesbury equals 3. The number of culinarian school in Glenfield City equals 2. The number of private middle school in Glenfield City equals the difference between the number of regional medical school in Glenfield City and the number of culinarian school in Evervale City.

Question: How many private middle school does Evervale City have?

Solution: Define culinarian school in Evervale City as s; so s = 3. Define regional medical school in Glenfield City as S; V = s = 3; so S = 3 + V = 3 + 3 = 6. Define culinarian school in Glenfield City as A; so A = 2. Define private middle school in Glenfield City as E; so E = S - s = 6 - 3 = 3. Define total number of schools in Glenfield City as m; l = S + E = 6 + 3 = 9; so m = l + A = 9 + 2 = 11. Define culinarian school in Hawkesbury as K; y = m + E = 11 + 3 = 14; so K = y + A = 14 + 2 = 16. Define private middle school in Hawkesbury as c; so c = K + A = 16 + 2 = 18. Define private middle school in Evervale City as p; so p = c = 18. Answer: 18.


The number of solemn period drama in Verdi Movie Festival equals 4. The number of solemn period drama in Taylor Movie Festival equals the number of solemn period drama in Verdi Movie Festival. The number of upbeat metropolis comedy in Northwood Movie Festival equals 4. The number of upbeat metropolis comedy in Taylor Movie Festival equals 2. The number of upbeat metropolis comedy in Verdi Movie Festival equals 2 times the number of solemn period drama in Taylor Movie Festival. The number of futuristic sci-fi movie in Verdi Movie Festival equals the number of upbeat metropolis comedy in Taylor Movie Festival. The number of solemn period drama in Northwood Movie Festival equals 4. The number of futuristic sci-fi movie in Northwood Movie Festival equals the total number of movies in Verdi Movie Festival.

Question: What is the total number of movies in Northwood Movie Festival?

Solution: Define upbeat metropolis comedy in Taylor Movie Festival as C; so C = 2. Define solemn period drama in Verdi Movie Festival as M; so M = 4. Define futuristic sci-fi movie in Verdi Movie Festival as K; so K = C = 2. Define solemn period drama in Taylor Movie Festival as F; so F = M = 4. Define upbeat metropolis comedy in Verdi Movie Festival as o; B = F = 4; so o = 2 * B = 2 * 4 = 8. Define total number of movies in Verdi Movie Festival as t; i = K + M = 2 + 4 = 6; so t = i + o = 6 + 8 = 14. Define futuristic sci-fi movie in Northwood Movie Festival as a; so a = t = 14. Define upbeat metropolis comedy in Northwood Movie Festival as w; so w = 4. Define solemn period drama in Northwood Movie Festival as h; so h = 4. Define total number of movies in Northwood Movie Festival as S; y = a + h = 14 + 4 = 18; so S = y + w = 18 + 4 = 22. Answer: 22.


The number of solemn period drama in Northwood Movie Festival equals the number of futuristic sci-fi movie in Golden Banana Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals 2 times the number of calm road movie in Northwood Movie Festival. The number of futuristic sci-fi movie in Taylor Movie Festival equals the number of solemn period drama in Golden Banana Movie Festival. The number of futuristic sci-fi movie in Golden Banana Movie Festival equals the sum of the total number of movies in Taylor Movie Festival, the number of solemn period drama in Taylor Movie Festival, and the number of futuristic sci-fi movie in Taylor Movie Festival. The number of calm road movie in Taylor Movie Festival equals 4 times the number of solemn period drama in Golden Banana Movie Festival. The number of calm road movie in Northwood Movie Festival equals 3. The number of solemn period drama in Taylor Movie Festival equals 2 plus the number of calm road movie in Northwood Movie Festival.

Question: How many solemn period drama does Northwood Movie Festival have?

Solution: Define calm road movie in Northwood Movie Festival as H; so H = 3. Define solemn period drama in Golden Banana Movie Festival as S; r = H = 3; so S = 2 * r = 2 * 3 = 6. Define calm road movie in Taylor Movie Festival as D; s = S = 6; so D = 4 * s = 4 * 6 = 24. Define futuristic sci-fi movie in Taylor Movie Festival as l; so l = S = 6. Define solemn period drama in Taylor Movie Festival as u; Z = H = 3; so u = 2 + Z = 2 + 3 = 5. Define total number of movies in Taylor Movie Festival as L; y = u + D = 5 + 24 = 29; so L = y + l = 29 + 6 = 35. Define futuristic sci-fi movie in Golden Banana Movie Festival as G; V = L + u = 35 + 5 = 40; so G = V + l = 40 + 6 = 46. Define solemn period drama in Northwood Movie Festival as c; so c = G = 46. Answer: 46.


The number of culinarian school in Brightford equals the sum of the total number of schools in Hawkesbury, the number of culinarian school in Hawkesbury, and the number of regional medical school in Brightford. The number of regional medical school in Hawkesbury equals the number of culinarian school in Hawkesbury. The number of regional medical school in Brightford equals 1. The number of culinarian school in Evervale City equals 2 plus the total number of schools in Brightford. The number of regional medical school in Evervale City equals 4. The number of culinarian school in Hawkesbury equals the number of regional medical school in Brightford.

Question: What is the total number of schools in Evervale City?

Solution: Define regional medical school in Brightford as c; so c = 1. Define culinarian school in Hawkesbury as E; so E = c = 1. Define regional medical school in Hawkesbury as W; so W = E = 1. Define total number of schools in Hawkesbury as J; so J = E + W = 1 + 1 = 2. Define culinarian school in Brightford as O; Q = J + E = 2 + 1 = 3; so O = Q + c = 3 + 1 = 4. Define total number of schools in Brightford as j; so j = c + O = 1 + 4 = 5. Define culinarian school in Evervale City as X; Z = j = 5; so X = 2 + Z = 2 + 5 = 7. Define regional medical school in Evervale City as i; so i = 4. Define total number of schools in Evervale City as y; so y = i + X = 4 + 7 = 11. Answer: 11.


The number of public highschool in Glenfield City equals 3 plus the number of private middle school in Glenfield City. The number of private middle school in Glenfield City equals 1 plus the sum of the total number of schools in Brightford and the number of private middle school in Brightford. The number of private middle school in Evervale City equals 4 times the total number of schools in Glenfield City. The number of public highschool in Brightford equals 4. The number of private middle school in Brightford equals 3 times the number of public highschool in Brightford.

Question: What is the total number of schools in Evervale City?

Solution: Define public highschool in Brightford as U; so U = 4. Define private middle school in Brightford as A; d = U = 4; so A = 3 * d = 3 * 4 = 12. Define total number of schools in Brightford as w; so w = A + U = 12 + 4 = 16. Define private middle school in Glenfield City as D; X = w + A = 16 + 12 = 28; so D = 1 + X = 1 + 28 = 29. Define public highschool in Glenfield City as m; P = D = 29; so m = 3 + P = 3 + 29 = 32. Define total number of schools in Glenfield City as I; so I = D + m = 29 + 32 = 61. Define private middle school in Evervale City as y; l = I = 61; so y = 4 * l = 4 * 61 = 244. Define total number of schools in Evervale City as V; so V = y = 244. Answer: 244.


The number of futuristic sci-fi movie in Rêves de Belleville equals 1 plus the total number of movies in Cinéma de Montreval. The number of intense detective thriller in Rêves de Belleville equals 3. The number of upbeat metropolis comedy in Festival de Clairmont equals the sum of the total number of movies in Rêves de Belleville, the number of calm road movie in Rêves de Belleville, the number of futuristic sci-fi movie in Rêves de Belleville, and the number of intense detective thriller in Rêves de Belleville. The number of solemn period drama in Cinéma de Montreval equals 4. The number of calm road movie in Rêves de Belleville equals the sum of the total number of movies in Cinéma de Montreval and the number of solemn period drama in Cinéma de Montreval.

Question: What is the total number of movies in Festival de Clairmont?

Solution: Define solemn period drama in Cinéma de Montreval as T; so T = 4. Define total number of movies in Cinéma de Montreval as e; so e = T = 4. Define calm road movie in Rêves de Belleville as Q; so Q = e + T = 4 + 4 = 8. Define intense detective thriller in Rêves de Belleville as V; so V = 3. Define futuristic sci-fi movie in Rêves de Belleville as u; t = e = 4; so u = 1 + t = 1 + 4 = 5. Define total number of movies in Rêves de Belleville as v; N = Q + V = 8 + 3 = 11; so v = N + u = 11 + 5 = 16. Define upbeat metropolis comedy in Festival de Clairmont as m; l = v + Q = 16 + 8 = 24; C = l + u = 24 + 5 = 29; so m = C + V = 29 + 3 = 32. Define total number of movies in Festival de Clairmont as K; so K = m = 32. Answer: 32.


The number of futuristic sci-fi movie in Northwood Movie Festival equals 2 plus the number of intense detective thriller in West Sahara Movie Festival. The number of futuristic sci-fi movie in West Sahara Movie Festival equals 2 plus the total number of movies in Northwood Movie Festival. The number of intense detective thriller in Verdi Movie Festival equals the number of intense detective thriller in West Sahara Movie Festival. The number of futuristic sci-fi movie in Verdi Movie Festival equals 2 plus the total number of movies in West Sahara Movie Festival. The number of intense detective thriller in Northwood Movie Festival equals the number of intense detective thriller in West Sahara Movie Festival. The number of intense detective thriller in West Sahara Movie Festival equals 4.

Question: What is the total number of movies in Verdi Movie Festival?

Solution: Define intense detective thriller in West Sahara Movie Festival as F; so F = 4. Define futuristic sci-fi movie in Northwood Movie Festival as y; T = F = 4; so y = 2 + T = 2 + 4 = 6. Define intense detective thriller in Northwood Movie Festival as S; so S = F = 4. Define total number of movies in Northwood Movie Festival as U; so U = y + S = 6 + 4 = 10. Define futuristic sci-fi movie in West Sahara Movie Festival as m; u = U = 10; so m = 2 + u = 2 + 10 = 12. Define total number of movies in West Sahara Movie Festival as e; so e = m + F = 12 + 4 = 16. Define futuristic sci-fi movie in Verdi Movie Festival as q; j = e = 16; so q = 2 + j = 2 + 16 = 18. Define intense detective thriller in Verdi Movie Festival as s; so s = F = 4. Define total number of movies in Verdi Movie Festival as M; so M = q + s = 18 + 4 = 22. Answer: 22.


The number of adult owl in Hamilton Farm equals 4. The number of adult eagle in Jefferson Circus equals 3. The number of adult owl in Mayer Aquarium equals the number of adult eagle in Jefferson Circus. The number of adult blue jay in Mayer Aquarium equals 3. The number of adult eagle in Hamilton Farm equals 2 plus the difference between the total number of adult animals in Mayer Aquarium and the number of adult owl in Mayer Aquarium. The number of adult blue jay in Jefferson Circus equals the difference between the total number of adult animals in Hamilton Farm and the number of adult owl in Hamilton Farm. The number of adult blue jay in Hamilton Farm equals 2.

Question: How many adult blue jay does Jefferson Circus have?

Solution: Define adult eagle in Jefferson Circus as g; so g = 3. Define adult owl in Mayer Aquarium as t; so t = g = 3. Define adult blue jay in Mayer Aquarium as A; so A = 3. Define total number of adult animals in Mayer Aquarium as n; so n = t + A = 3 + 3 = 6. Define adult eagle in Hamilton Farm as s; x = n - t = 6 - 3 = 3; so s = 2 + x = 2 + 3 = 5. Define adult blue jay in Hamilton Farm as I; so I = 2. Define adult owl in Hamilton Farm as b; so b = 4. Define total number of adult animals in Hamilton Farm as J; G = I + b = 2 + 4 = 6; so J = G + s = 6 + 5 = 11. Define adult blue jay in Jefferson Circus as u; so u = J - b = 11 - 4 = 7. Answer: 7.


The number of calm road movie in Verdi Movie Festival equals the sum of the total number of movies in Taylor Movie Festival, the total number of movies in Northwood Movie Festival, and the number of upbeat metropolis comedy in Northwood Movie Festival. The number of calm road movie in Northwood Movie Festival equals the sum of the number of upbeat metropolis comedy in Northwood Movie Festival and the total number of movies in West Sahara Movie Festival. The number of upbeat metropolis comedy in Northwood Movie Festival equals the sum of the total number of movies in West Sahara Movie Festival and the number of upbeat metropolis comedy in West Sahara Movie Festival. The number of upbeat metropolis comedy in Taylor Movie Festival equals the difference between the total number of movies in Northwood Movie Festival and the total number of movies in West Sahara Movie Festival. The number of upbeat metropolis comedy in West Sahara Movie Festival equals 1.

Question: What is the total number of movies in Verdi Movie Festival?

Solution: Define upbeat metropolis comedy in West Sahara Movie Festival as x; so x = 1. Define total number of movies in West Sahara Movie Festival as S; so S = x = 1. Define upbeat metropolis comedy in Northwood Movie Festival as h; so h = S + x = 1 + 1 = 2. Define calm road movie in Northwood Movie Festival as w; so w = h + S = 2 + 1 = 3. Define total number of movies in Northwood Movie Festival as R; so R = w + h = 3 + 2 = 5. Define upbeat metropolis comedy in Taylor Movie Festival as t; so t = R - S = 5 - 1 = 4. Define total number of movies in Taylor Movie Festival as G; so G = t = 4. Define calm road movie in Verdi Movie Festival as X; f = G + R = 4 + 5 = 9; so X = f + h = 9 + 2 = 11. Define total number of movies in Verdi Movie Festival as c; so c = X = 11. Answer: 11.


The number of regional medical school in Shoreline City equals 2 plus the number of private middle school in Shoreline City. The number of private middle school in Ruby Bay equals 3 times the sum of the total number of schools in Shoreline City and the number of private middle school in Shoreline City. The number of culinarian school in Shoreline City equals 3 times the sum of the number of private middle school in Shoreline City and the number of regional medical school in Shoreline City. The number of culinarian school in Ruby Bay equals the total number of schools in Shoreline City. The number of private middle school in Shoreline City equals 2.

Question: What is the total number of schools in Ruby Bay?

Solution: Define private middle school in Shoreline City as Z; so Z = 2. Define regional medical school in Shoreline City as n; o = Z = 2; so n = 2 + o = 2 + 2 = 4. Define culinarian school in Shoreline City as V; R = Z + n = 2 + 4 = 6; so V = 3 * R = 3 * 6 = 18. Define total number of schools in Shoreline City as f; y = n + Z = 4 + 2 = 6; so f = y + V = 6 + 18 = 24. Define private middle school in Ruby Bay as m; W = f + Z = 24 + 2 = 26; so m = 3 * W = 3 * 26 = 78. Define culinarian school in Ruby Bay as b; so b = f = 24. Define total number of schools in Ruby Bay as P; so P = m + b = 78 + 24 = 102. Answer: 102.