The number of adult owl in South Zoo equals the total number of adult animals in Jefferson Circus. The number of adult blue jay in Jefferson Circus equals the number of adult eagle in Mayer Aquarium. The number of adult owl in Hamilton Farm equals 2 times the total number of adult animals in South Zoo. The number of adult parrot in Hamilton Farm equals 2 times the sum of the number of adult blue jay in Hamilton Farm and the number of adult eagle in Mayer Aquarium. The number of adult eagle in Mayer Aquarium equals 4. The number of adult blue jay in Hamilton Farm equals the number of adult owl in Hamilton Farm. The number of adult parrot in Jefferson Circus equals 2 times the total number of adult animals in Mayer Aquarium.

Question: How many adult parrot does Hamilton Farm have?

Solution: Define adult eagle in Mayer Aquarium as x; so x = 4. Define adult blue jay in Jefferson Circus as V; so V = x = 4. Define total number of adult animals in Mayer Aquarium as m; so m = x = 4. Define adult parrot in Jefferson Circus as J; j = m = 4; so J = 2 * j = 2 * 4 = 8. Define total number of adult animals in Jefferson Circus as g; so g = V + J = 4 + 8 = 12. Define adult owl in South Zoo as Z; so Z = g = 12. Define total number of adult animals in South Zoo as y; so y = Z = 12. Define adult owl in Hamilton Farm as c; K = y = 12; so c = 2 * K = 2 * 12 = 24. Define adult blue jay in Hamilton Farm as U; so U = c = 24. Define adult parrot in Hamilton Farm as n; f = U + x = 24 + 4 = 28; so n = 2 * f = 2 * 28 = 56. Answer: 56.


The number of elementary school in Evervale City equals 4. The number of regional medical school in Evervale City equals the number of elementary school in Evervale City. The number of elementary school in Glenfield City equals the difference between the total number of schools in Brightford and the number of private middle school in Brightford. The number of private middle school in Brightford equals 4 plus the number of regional medical school in Evervale City. The number of elementary school in Brightford equals 4 plus the sum of the total number of schools in Evervale City, the number of elementary school in Evervale City, and the number of regional medical school in Evervale City.

Question: What is the total number of schools in Glenfield City?

Solution: Define elementary school in Evervale City as w; so w = 4. Define regional medical school in Evervale City as K; so K = w = 4. Define total number of schools in Evervale City as E; so E = w + K = 4 + 4 = 8. Define elementary school in Brightford as G; S = E + w = 8 + 4 = 12; o = S + K = 12 + 4 = 16; so G = 4 + o = 4 + 16 = 20. Define private middle school in Brightford as R; i = K = 4; so R = 4 + i = 4 + 4 = 8. Define total number of schools in Brightford as v; so v = R + G = 8 + 20 = 28. Define elementary school in Glenfield City as H; so H = v - R = 28 - 8 = 20. Define total number of schools in Glenfield City as V; so V = H = 20. Answer: 20.


The number of adult deer in Jefferson Circus equals the total number of adult animals in Bundle Ranch. The number of adult bear in Hamilton Farm equals 3. The number of adult racoon in South Zoo equals the number of adult deer in Jefferson Circus. The number of adult deer in Bundle Ranch equals 4 times the number of adult bear in Hamilton Farm. The number of adult fox in South Zoo equals the sum of the total number of adult animals in Bundle Ranch, the number of adult deer in Hamilton Farm, and the number of adult fox in Bundle Ranch. The number of adult racoon in Jefferson Circus equals 4. The number of adult fox in Bundle Ranch equals the number of adult deer in Hamilton Farm. The number of adult deer in Hamilton Farm equals 4 times the number of adult deer in Bundle Ranch.

Question: What is the total number of adult animals in South Zoo?

Solution: Define adult bear in Hamilton Farm as V; so V = 3. Define adult deer in Bundle Ranch as J; Z = V = 3; so J = 4 * Z = 4 * 3 = 12. Define adult deer in Hamilton Farm as R; Y = J = 12; so R = 4 * Y = 4 * 12 = 48. Define adult fox in Bundle Ranch as z; so z = R = 48. Define total number of adult animals in Bundle Ranch as O; so O = J + z = 12 + 48 = 60. Define adult fox in South Zoo as I; D = O + R = 60 + 48 = 108; so I = D + z = 108 + 48 = 156. Define adult deer in Jefferson Circus as e; so e = O = 60. Define adult racoon in South Zoo as S; so S = e = 60. Define total number of adult animals in South Zoo as H; so H = S + I = 60 + 156 = 216. Answer: 216.


The number of elementary school in Brightford equals 2 times the number of private middle school in Hawkesbury. The number of regional medical school in Hawkesbury equals the number of public highschool in Brightford. The number of private middle school in Hawkesbury equals the number of regional medical school in Hawkesbury. The number of public highschool in Westhaven City equals 2. The number of private middle school in Westhaven City equals 4 plus the number of public highschool in Westhaven City. The number of public highschool in Hawkesbury equals 3. The number of elementary school in Westhaven City equals the number of regional medical school in Westhaven City. The number of regional medical school in Glenfield City equals the sum of the number of public highschool in Westhaven City and the number of private middle school in Westhaven City. The number of elementary school in Glenfield City equals 4. The number of elementary school in Hawkesbury equals the sum of the number of regional medical school in Brightford and the number of regional medical school in Westhaven City. The number of private middle school in Glenfield City equals the number of elementary school in Hawkesbury. The number of regional medical school in Brightford equals 1 plus the number of elementary school in Westhaven City. The number of public highschool in Glenfield City equals 3 plus the number of private middle school in Westhaven City. The number of regional medical school in Westhaven City equals 2. The number of public highschool in Brightford equals 4 times the number of private middle school in Brightford. The number of private middle school in Brightford equals the sum of the number of elementary school in Hawkesbury, the number of regional medical school in Brightford, and the number of regional medical school in Westhaven City.

Question: How many elementary school does Brightford have?

Solution: Define regional medical school in Westhaven City as f; so f = 2. Define elementary school in Westhaven City as A; so A = f = 2. Define regional medical school in Brightford as R; N = A = 2; so R = 1 + N = 1 + 2 = 3. Define elementary school in Hawkesbury as Y; so Y = R + f = 3 + 2 = 5. Define private middle school in Brightford as v; q = Y + R = 5 + 3 = 8; so v = q + f = 8 + 2 = 10. Define public highschool in Brightford as P; J = v = 10; so P = 4 * J = 4 * 10 = 40. Define regional medical school in Hawkesbury as M; so M = P = 40. Define private middle school in Hawkesbury as j; so j = M = 40. Define elementary school in Brightford as H; G = j = 40; so H = 2 * G = 2 * 40 = 80. Answer: 80.


The number of public highschool in Glenfield City equals 4. The number of elementary school in Brightford equals the number of regional medical school in Hawkesbury. The number of regional medical school in Evervale City equals 4. The number of public highschool in Evervale City equals the sum of the total number of schools in Brightford, the number of culinarian school in Brightford, and the number of regional medical school in Hawkesbury. The number of culinarian school in Hawkesbury equals 3 times the sum of the number of regional medical school in Evervale City, the number of public highschool in Brightford, and the total number of schools in Glenfield City. The number of public highschool in Brightford equals 2 times the number of culinarian school in Brightford. The number of regional medical school in Glenfield City equals 3. The number of regional medical school in Brightford equals the number of culinarian school in Brightford. The number of elementary school in Hawkesbury equals the sum of the number of public highschool in Evervale City and the total number of schools in Brightford. The number of culinarian school in Glenfield City equals 1. The number of culinarian school in Brightford equals the number of regional medical school in Hawkesbury. The number of elementary school in Evervale City equals the number of elementary school in Glenfield City. The number of regional medical school in Hawkesbury equals 3. The number of public highschool in Hawkesbury equals 3. The number of elementary school in Glenfield City equals 2 times the number of regional medical school in Evervale City.

Question: How many elementary school does Hawkesbury have?

Solution: Define regional medical school in Hawkesbury as c; so c = 3. Define culinarian school in Brightford as U; so U = c = 3. Define public highschool in Brightford as V; l = U = 3; so V = 2 * l = 2 * 3 = 6. Define elementary school in Brightford as J; so J = c = 3. Define regional medical school in Brightford as R; so R = U = 3. Define total number of schools in Brightford as S; G = J + U = 3 + 3 = 6; C = G + V = 6 + 6 = 12; so S = C + R = 12 + 3 = 15. Define public highschool in Evervale City as Z; y = S + U = 15 + 3 = 18; so Z = y + c = 18 + 3 = 21. Define elementary school in Hawkesbury as u; so u = Z + S = 21 + 15 = 36. Answer: 36.


The number of adult crow in Maple Creek equals the number of adult blue jay in Maple Creek. The number of adult eagle in Beverly Forest equals the number of adult parrot in Beverly Forest. The number of adult crow in Oakridge Riverside equals the number of adult eagle in Beverly Forest. The number of adult blue jay in Cedar Valley equals the total number of adult animals in Beverly Forest. The number of adult eagle in Oakridge Riverside equals the sum of the total number of adult animals in Cedar Valley and the number of adult eagle in Beverly Forest. The number of adult parrot in Beverly Forest equals the number of adult blue jay in Maple Creek. The number of adult blue jay in Maple Creek equals 1. The number of adult blue jay in Beverly Forest equals the number of adult crow in Maple Creek.

Question: What is the total number of adult animals in Oakridge Riverside?

Solution: Define adult blue jay in Maple Creek as o; so o = 1. Define adult parrot in Beverly Forest as f; so f = o = 1. Define adult crow in Maple Creek as w; so w = o = 1. Define adult blue jay in Beverly Forest as C; so C = w = 1. Define adult eagle in Beverly Forest as d; so d = f = 1. Define total number of adult animals in Beverly Forest as O; z = C + d = 1 + 1 = 2; so O = z + f = 2 + 1 = 3. Define adult blue jay in Cedar Valley as P; so P = O = 3. Define total number of adult animals in Cedar Valley as I; so I = P = 3. Define adult crow in Oakridge Riverside as y; so y = d = 1. Define adult eagle in Oakridge Riverside as N; so N = I + d = 3 + 1 = 4. Define total number of adult animals in Oakridge Riverside as r; so r = y + N = 1 + 4 = 5. Answer: 5.


The number of adult owl in Bundle Ranch equals the number of adult eagle in Bundle Ranch. The number of adult eagle in Bundle Ranch equals 4. The number of adult parrot in Mayer Aquarium equals the number of adult owl in Bundle Ranch. The number of adult owl in South Zoo equals the total number of adult animals in South Zoo. The number of adult eagle in Jefferson Circus equals 3. The number of adult eagle in Mayer Aquarium equals 2 times the difference between the total number of adult animals in Bundle Ranch and the number of adult owl in Bundle Ranch. The number of adult crow in South Zoo equals 4. The number of adult blue jay in South Zoo equals the sum of the number of adult owl in Mayer Aquarium, the number of adult eagle in Bundle Ranch, and the number of adult eagle in Jefferson Circus. The number of adult parrot in Bundle Ranch equals the sum of the number of adult owl in Mayer Aquarium and the number of adult eagle in Bundle Ranch. The number of adult crow in Mayer Aquarium equals 4. The number of adult blue jay in Mayer Aquarium equals the difference between the number of adult eagle in Mayer Aquarium and the number of adult blue jay in Bundle Ranch. The number of adult owl in Jefferson Circus equals 4. The number of adult owl in Hamilton Farm equals the number of adult eagle in Hamilton Farm. The number of adult blue jay in Jefferson Circus equals the total number of adult animals in South Zoo. The number of adult owl in Mayer Aquarium equals the number of adult eagle in Bundle Ranch. The number of adult blue jay in Bundle Ranch equals 4 times the sum of the number of adult owl in Mayer Aquarium and the number of adult eagle in Bundle Ranch. The number of adult eagle in Hamilton Farm equals 3.

Question: How many adult eagle does Mayer Aquarium have?

Solution: Define adult eagle in Bundle Ranch as D; so D = 4. Define adult owl in Mayer Aquarium as B; so B = D = 4. Define adult parrot in Bundle Ranch as V; so V = B + D = 4 + 4 = 8. Define adult blue jay in Bundle Ranch as p; a = B + D = 4 + 4 = 8; so p = 4 * a = 4 * 8 = 32. Define adult owl in Bundle Ranch as f; so f = D = 4. Define total number of adult animals in Bundle Ranch as Y; h = V + D = 8 + 4 = 12; i = h + p = 12 + 32 = 44; so Y = i + f = 44 + 4 = 48. Define adult eagle in Mayer Aquarium as Z; y = Y - f = 48 - 4 = 44; so Z = 2 * y = 2 * 44 = 88. Answer: 88.


The number of adult fox in Beverly Forest equals 4 times the number of adult wolf in Beverly Forest. The number of adult racoon in Oakridge Riverside equals the number of adult racoon in Cedar Valley. The number of adult racoon in Cedar Valley equals the number of adult wolf in Pine Ridge. The number of adult bear in Pine Ridge equals 2 plus the number of adult deer in Pine Ridge. The number of adult wolf in Beverly Forest equals 2. The number of adult deer in Oakridge Riverside equals 3. The number of adult fox in Oakridge Riverside equals 4 plus the number of adult deer in Pine Ridge. The number of adult wolf in Pine Ridge equals the number of adult fox in Beverly Forest. The number of adult bear in Oakridge Riverside equals 2 plus the number of adult deer in Oakridge Riverside. The number of adult bear in Beverly Forest equals 2. The number of adult deer in Beverly Forest equals the number of adult racoon in Oakridge Riverside. The number of adult racoon in Pine Ridge equals 3. The number of adult deer in Pine Ridge equals 4. The number of adult deer in Cedar Valley equals 2 plus the number of adult racoon in Oakridge Riverside. The number of adult fox in Cedar Valley equals the sum of the number of adult racoon in Cedar Valley and the number of adult wolf in Beverly Forest. The number of adult wolf in Cedar Valley equals 2. The number of adult racoon in Beverly Forest equals 2. The number of adult fox in Pine Ridge equals 3 plus the difference between the number of adult fox in Beverly Forest and the total number of adult animals in Beverly Forest.

Question: What is the total number of adult animals in Cedar Valley?

Solution: Define adult wolf in Beverly Forest as R; so R = 2. Define adult fox in Beverly Forest as M; L = R = 2; so M = 4 * L = 4 * 2 = 8. Define adult wolf in Pine Ridge as b; so b = M = 8. Define adult racoon in Cedar Valley as t; so t = b = 8. Define adult racoon in Oakridge Riverside as k; so k = t = 8. Define adult wolf in Cedar Valley as m; so m = 2. Define adult deer in Cedar Valley as E; l = k = 8; so E = 2 + l = 2 + 8 = 10. Define adult fox in Cedar Valley as X; so X = t + R = 8 + 2 = 10. Define total number of adult animals in Cedar Valley as a; z = m + E = 2 + 10 = 12; Y = z + t = 12 + 8 = 20; so a = Y + X = 20 + 10 = 30. Answer: 30.


The number of culinarian school in Glenfield City equals 4 times the sum of the total number of schools in Brightford and the total number of schools in Westhaven City. The number of regional medical school in Westhaven City equals 4 times the number of private middle school in Glenfield City. The number of regional medical school in Hawkesbury equals 4. The number of private middle school in Glenfield City equals 4. The number of private middle school in Hawkesbury equals 4 times the number of culinarian school in Westhaven City. The number of culinarian school in Westhaven City equals the number of private middle school in Glenfield City. The number of private middle school in Westhaven City equals 3 plus the number of regional medical school in Westhaven City. The number of culinarian school in Brightford equals the sum of the total number of schools in Westhaven City and the number of private middle school in Westhaven City.

Question: How many culinarian school does Glenfield City have?

Solution: Define private middle school in Glenfield City as L; so L = 4. Define regional medical school in Westhaven City as b; V = L = 4; so b = 4 * V = 4 * 4 = 16. Define private middle school in Westhaven City as q; Y = b = 16; so q = 3 + Y = 3 + 16 = 19. Define culinarian school in Westhaven City as d; so d = L = 4. Define total number of schools in Westhaven City as c; T = d + q = 4 + 19 = 23; so c = T + b = 23 + 16 = 39. Define culinarian school in Brightford as I; so I = c + q = 39 + 19 = 58. Define total number of schools in Brightford as k; so k = I = 58. Define culinarian school in Glenfield City as g; x = k + c = 58 + 39 = 97; so g = 4 * x = 4 * 97 = 388. Answer: 388.


The number of elementary school in Westhaven City equals 2 plus the number of elementary school in Glenfield City. The number of culinarian school in Brightford equals the number of elementary school in Glenfield City. The number of regional medical school in Brightford equals 4. The number of regional medical school in Hawkesbury equals 3 plus the sum of the number of elementary school in Westhaven City and the number of elementary school in Glenfield City. The number of public highschool in Brightford equals the number of elementary school in Brightford. The number of elementary school in Glenfield City equals 3. The number of public highschool in Hawkesbury equals 3 times the number of elementary school in Glenfield City. The number of elementary school in Brightford equals 2 times the number of private middle school in Evervale City. The number of private middle school in Evervale City equals the number of public highschool in Hawkesbury. The number of culinarian school in Glenfield City equals 4 plus the total number of schools in Brightford.

Question: How many culinarian school does Glenfield City have?

Solution: Define elementary school in Glenfield City as h; so h = 3. Define public highschool in Hawkesbury as q; C = h = 3; so q = 3 * C = 3 * 3 = 9. Define private middle school in Evervale City as z; so z = q = 9. Define elementary school in Brightford as x; e = z = 9; so x = 2 * e = 2 * 9 = 18. Define public highschool in Brightford as U; so U = x = 18. Define culinarian school in Brightford as j; so j = h = 3. Define regional medical school in Brightford as S; so S = 4. Define total number of schools in Brightford as r; A = j + S = 3 + 4 = 7; H = A + U = 7 + 18 = 25; so r = H + x = 25 + 18 = 43. Define culinarian school in Glenfield City as n; i = r = 43; so n = 4 + i = 4 + 43 = 47. Answer: 47.


The number of intense detective thriller in Northwood Movie Festival equals 1. The number of solemn period drama in Verdi Movie Festival equals 4. The number of futuristic sci-fi movie in Verdi Movie Festival equals 4 times the number of intense detective thriller in Northwood Movie Festival. The number of futuristic sci-fi movie in Northwood Movie Festival equals 4 plus the number of intense detective thriller in Northwood Movie Festival. The number of calm road movie in Verdi Movie Festival equals 3 times the number of futuristic sci-fi movie in Verdi Movie Festival. The number of calm road movie in Northwood Movie Festival equals the total number of movies in Verdi Movie Festival.

Question: What is the total number of movies in Northwood Movie Festival?

Solution: Define intense detective thriller in Northwood Movie Festival as a; so a = 1. Define futuristic sci-fi movie in Verdi Movie Festival as Q; o = a = 1; so Q = 4 * o = 4 * 1 = 4. Define futuristic sci-fi movie in Northwood Movie Festival as F; B = a = 1; so F = 4 + B = 4 + 1 = 5. Define solemn period drama in Verdi Movie Festival as i; so i = 4. Define calm road movie in Verdi Movie Festival as h; K = Q = 4; so h = 3 * K = 3 * 4 = 12. Define total number of movies in Verdi Movie Festival as w; u = Q + i = 4 + 4 = 8; so w = u + h = 8 + 12 = 20. Define calm road movie in Northwood Movie Festival as D; so D = w = 20. Define total number of movies in Northwood Movie Festival as A; H = F + a = 5 + 1 = 6; so A = H + D = 6 + 20 = 26. Answer: 26.


The number of adult eagle in Bundle Ranch equals 3 times the total number of adult animals in South Zoo. The number of adult blue jay in Hamilton Farm equals 3 plus the total number of adult animals in Bundle Ranch. The number of adult blue jay in South Zoo equals the number of adult eagle in South Zoo. The number of adult eagle in Hamilton Farm equals 3. The number of adult blue jay in Bundle Ranch equals 1 plus the number of adult eagle in South Zoo. The number of adult eagle in South Zoo equals 2.

Question: What is the total number of adult animals in Hamilton Farm?

Solution: Define adult eagle in South Zoo as Z; so Z = 2. Define adult blue jay in South Zoo as U; so U = Z = 2. Define total number of adult animals in South Zoo as O; so O = Z + U = 2 + 2 = 4. Define adult eagle in Bundle Ranch as v; H = O = 4; so v = 3 * H = 3 * 4 = 12. Define adult blue jay in Bundle Ranch as k; M = Z = 2; so k = 1 + M = 1 + 2 = 3. Define total number of adult animals in Bundle Ranch as W; so W = v + k = 12 + 3 = 15. Define adult blue jay in Hamilton Farm as T; Q = W = 15; so T = 3 + Q = 3 + 15 = 18. Define adult eagle in Hamilton Farm as s; so s = 3. Define total number of adult animals in Hamilton Farm as P; so P = s + T = 3 + 18 = 21. Answer: 21.


The number of adult bear in Oakridge Riverside equals 4 times the number of adult fox in Beverly Forest. The number of adult fox in Oakridge Riverside equals the difference between the number of adult bear in Oakridge Riverside and the number of adult fox in Beverly Forest. The number of adult bear in Maple Creek equals the total number of adult animals in Oakridge Riverside. The number of adult fox in Beverly Forest equals 4. The number of adult deer in Maple Creek equals the sum of the number of adult bear in Oakridge Riverside, the total number of adult animals in Oakridge Riverside, and the number of adult fox in Oakridge Riverside. The number of adult bear in Beverly Forest equals the difference between the total number of adult animals in Maple Creek and the number of adult fox in Oakridge Riverside.

Question: How many adult bear does Beverly Forest have?

Solution: Define adult fox in Beverly Forest as S; so S = 4. Define adult bear in Oakridge Riverside as Z; O = S = 4; so Z = 4 * O = 4 * 4 = 16. Define adult fox in Oakridge Riverside as G; so G = Z - S = 16 - 4 = 12. Define total number of adult animals in Oakridge Riverside as P; so P = G + Z = 12 + 16 = 28. Define adult bear in Maple Creek as r; so r = P = 28. Define adult deer in Maple Creek as C; k = Z + P = 16 + 28 = 44; so C = k + G = 44 + 12 = 56. Define total number of adult animals in Maple Creek as R; so R = r + C = 28 + 56 = 84. Define adult bear in Beverly Forest as M; so M = R - G = 84 - 12 = 72. Answer: 72.


The number of public highschool in Clearwater Bay equals the total number of schools in Oakbridge City. The number of elementary school in Clearwater Bay equals 3 times the total number of schools in Oakbridge City. The number of private middle school in Ruby Bay equals 4. The number of elementary school in Oakbridge City equals 3 plus the total number of schools in Ruby Bay. The number of private middle school in Oakbridge City equals 1 plus the number of elementary school in Oakbridge City. The number of public highschool in Oakbridge City equals the number of elementary school in Oakbridge City.

Question: What is the total number of schools in Clearwater Bay?

Solution: Define private middle school in Ruby Bay as l; so l = 4. Define total number of schools in Ruby Bay as L; so L = l = 4. Define elementary school in Oakbridge City as J; E = L = 4; so J = 3 + E = 3 + 4 = 7. Define private middle school in Oakbridge City as N; W = J = 7; so N = 1 + W = 1 + 7 = 8. Define public highschool in Oakbridge City as T; so T = J = 7. Define total number of schools in Oakbridge City as I; h = J + N = 7 + 8 = 15; so I = h + T = 15 + 7 = 22. Define elementary school in Clearwater Bay as g; A = I = 22; so g = 3 * A = 3 * 22 = 66. Define public highschool in Clearwater Bay as b; so b = I = 22. Define total number of schools in Clearwater Bay as O; so O = g + b = 66 + 22 = 88. Answer: 88.


The number of adult crow in Jefferson Circus equals the sum of the number of adult blue jay in South Zoo and the number of adult eagle in Mayer Aquarium. The number of adult eagle in Jefferson Circus equals 2. The number of adult owl in South Zoo equals the difference between the number of adult blue jay in South Zoo and the number of adult parrot in Mayer Aquarium. The number of adult parrot in Jefferson Circus equals the difference between the number of adult crow in Bundle Ranch and the total number of adult animals in Jefferson Circus. The number of adult owl in Jefferson Circus equals 1. The number of adult parrot in Mayer Aquarium equals 4. The number of adult owl in Hamilton Farm equals the number of adult eagle in Hamilton Farm. The number of adult blue jay in South Zoo equals 2. The number of adult parrot in Bundle Ranch equals 4. The number of adult crow in Hamilton Farm equals 2 plus the number of adult parrot in Hamilton Farm. The number of adult crow in Bundle Ranch equals 3. The number of adult eagle in Hamilton Farm equals 4 plus the total number of adult animals in Bundle Ranch. The number of adult parrot in Hamilton Farm equals 3 times the number of adult eagle in Hamilton Farm. The number of adult eagle in Mayer Aquarium equals 3.

Question: What is the total number of adult animals in Hamilton Farm?

Solution: Define adult parrot in Bundle Ranch as m; so m = 4. Define adult crow in Bundle Ranch as Z; so Z = 3. Define total number of adult animals in Bundle Ranch as N; so N = Z + m = 3 + 4 = 7. Define adult eagle in Hamilton Farm as v; j = N = 7; so v = 4 + j = 4 + 7 = 11. Define adult owl in Hamilton Farm as l; so l = v = 11. Define adult parrot in Hamilton Farm as J; T = v = 11; so J = 3 * T = 3 * 11 = 33. Define adult crow in Hamilton Farm as C; B = J = 33; so C = 2 + B = 2 + 33 = 35. Define total number of adult animals in Hamilton Farm as V; w = C + v = 35 + 11 = 46; e = w + l = 46 + 11 = 57; so V = e + J = 57 + 33 = 90. Answer: 90.


The number of public highschool in Shoreline City equals 4 times the number of elementary school in Riverton City. The number of regional medical school in Ruby Bay equals the number of culinarian school in Oakbridge City. The number of culinarian school in Riverton City equals the total number of schools in Shoreline City. The number of regional medical school in Riverton City equals the difference between the total number of schools in Ruby Bay and the total number of schools in Shoreline City. The number of culinarian school in Oakbridge City equals the number of private middle school in Clearwater Bay. The number of private middle school in Ruby Bay equals 3. The number of public highschool in Clearwater Bay equals 4 plus the number of public highschool in Shoreline City. The number of private middle school in Clearwater Bay equals the number of culinarian school in Riverton City. The number of culinarian school in Clearwater Bay equals 3. The number of elementary school in Riverton City equals 4 plus the number of culinarian school in Clearwater Bay.

Question: How many regional medical school does Riverton City have?

Solution: Define culinarian school in Clearwater Bay as d; so d = 3. Define elementary school in Riverton City as q; W = d = 3; so q = 4 + W = 4 + 3 = 7. Define public highschool in Shoreline City as E; C = q = 7; so E = 4 * C = 4 * 7 = 28. Define total number of schools in Shoreline City as o; so o = E = 28. Define culinarian school in Riverton City as X; so X = o = 28. Define private middle school in Clearwater Bay as T; so T = X = 28. Define culinarian school in Oakbridge City as Q; so Q = T = 28. Define private middle school in Ruby Bay as Y; so Y = 3. Define regional medical school in Ruby Bay as n; so n = Q = 28. Define total number of schools in Ruby Bay as i; so i = n + Y = 28 + 3 = 31. Define regional medical school in Riverton City as j; so j = i - o = 31 - 28 = 3. Answer: 3.


The number of private middle school in Riverton City equals 3. The number of private middle school in Oakbridge City equals 4. The number of elementary school in Clearwater Bay equals 4. The number of private middle school in Clearwater Bay equals 3 plus the number of elementary school in Clearwater Bay. The number of elementary school in Riverton City equals the total number of schools in Clearwater Bay. The number of elementary school in Oakbridge City equals the sum of the total number of schools in Riverton City, the number of private middle school in Riverton City, and the number of private middle school in Clearwater Bay.

Question: What is the total number of schools in Oakbridge City?

Solution: Define elementary school in Clearwater Bay as U; so U = 4. Define private middle school in Clearwater Bay as q; u = U = 4; so q = 3 + u = 3 + 4 = 7. Define total number of schools in Clearwater Bay as p; so p = q + U = 7 + 4 = 11. Define elementary school in Riverton City as k; so k = p = 11. Define private middle school in Riverton City as L; so L = 3. Define total number of schools in Riverton City as F; so F = L + k = 3 + 11 = 14. Define elementary school in Oakbridge City as O; G = F + L = 14 + 3 = 17; so O = G + q = 17 + 7 = 24. Define private middle school in Oakbridge City as I; so I = 4. Define total number of schools in Oakbridge City as f; so f = I + O = 4 + 24 = 28. Answer: 28.


The number of upbeat metropolis comedy in Festival de Saint-Rivage equals 2. The number of futuristic sci-fi movie in Festival de Clairmont equals the number of intense detective thriller in Rêves de Belleville. The number of futuristic sci-fi movie in Rêves de Belleville equals 2 times the number of futuristic sci-fi movie in Festival de Clairmont. The number of solemn period drama in Festival de Clairmont equals 4 times the number of intense detective thriller in Festival de Clairmont. The number of intense detective thriller in Festival de Clairmont equals 4. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals 4 plus the sum of the total number of movies in Rêves de Belleville and the number of futuristic sci-fi movie in Festival de Clairmont. The number of solemn period drama in Festival Lumière de Valmont equals 4 plus the total number of movies in Festival de Saint-Rivage. The number of intense detective thriller in Rêves de Belleville equals 3.

Question: What is the total number of movies in Festival Lumière de Valmont?

Solution: Define intense detective thriller in Rêves de Belleville as c; so c = 3. Define futuristic sci-fi movie in Festival de Clairmont as C; so C = c = 3. Define futuristic sci-fi movie in Rêves de Belleville as v; s = C = 3; so v = 2 * s = 2 * 3 = 6. Define total number of movies in Rêves de Belleville as R; so R = v + c = 6 + 3 = 9. Define futuristic sci-fi movie in Festival de Saint-Rivage as t; m = R + C = 9 + 3 = 12; so t = 4 + m = 4 + 12 = 16. Define upbeat metropolis comedy in Festival de Saint-Rivage as Y; so Y = 2. Define total number of movies in Festival de Saint-Rivage as g; so g = t + Y = 16 + 2 = 18. Define solemn period drama in Festival Lumière de Valmont as D; r = g = 18; so D = 4 + r = 4 + 18 = 22. Define total number of movies in Festival Lumière de Valmont as l; so l = D = 22. Answer: 22.


The number of elementary school in Hawkesbury equals 4. The number of culinarian school in Evervale City equals 2 times the total number of schools in Hawkesbury. The number of culinarian school in Brightford equals the sum of the total number of schools in Evervale City and the total number of schools in Hawkesbury. The number of public highschool in Westhaven City equals the sum of the number of elementary school in Hawkesbury and the number of culinarian school in Evervale City. The number of regional medical school in Evervale City equals the sum of the total number of schools in Westhaven City, the number of culinarian school in Evervale City, and the number of elementary school in Hawkesbury.

Question: What is the total number of schools in Brightford?

Solution: Define elementary school in Hawkesbury as o; so o = 4. Define total number of schools in Hawkesbury as f; so f = o = 4. Define culinarian school in Evervale City as X; x = f = 4; so X = 2 * x = 2 * 4 = 8. Define public highschool in Westhaven City as F; so F = o + X = 4 + 8 = 12. Define total number of schools in Westhaven City as n; so n = F = 12. Define regional medical school in Evervale City as t; m = n + X = 12 + 8 = 20; so t = m + o = 20 + 4 = 24. Define total number of schools in Evervale City as S; so S = X + t = 8 + 24 = 32. Define culinarian school in Brightford as B; so B = S + f = 32 + 4 = 36. Define total number of schools in Brightford as k; so k = B = 36. Answer: 36.


The number of intense detective thriller in Cinéma de Montreval equals 2 plus the number of intense detective thriller in Festival Lumière de Valmont. The number of calm road movie in Festival Lumière de Valmont equals 3. The number of futuristic sci-fi movie in Cinéma de Montreval equals the sum of the total number of movies in Festival Lumière de Valmont, the number of upbeat metropolis comedy in Festival Lumière de Valmont, and the number of intense detective thriller in Cinéma de Montreval. The number of intense detective thriller in Festival Lumière de Valmont equals 3. The number of calm road movie in Festival de Saint-Rivage equals the total number of movies in Cinéma de Montreval. The number of upbeat metropolis comedy in Festival Lumière de Valmont equals the number of calm road movie in Festival Lumière de Valmont.

Question: What is the total number of movies in Festival de Saint-Rivage?

Solution: Define calm road movie in Festival Lumière de Valmont as L; so L = 3. Define upbeat metropolis comedy in Festival Lumière de Valmont as p; so p = L = 3. Define intense detective thriller in Festival Lumière de Valmont as X; so X = 3. Define intense detective thriller in Cinéma de Montreval as h; k = X = 3; so h = 2 + k = 2 + 3 = 5. Define total number of movies in Festival Lumière de Valmont as B; R = X + L = 3 + 3 = 6; so B = R + p = 6 + 3 = 9. Define futuristic sci-fi movie in Cinéma de Montreval as i; F = B + p = 9 + 3 = 12; so i = F + h = 12 + 5 = 17. Define total number of movies in Cinéma de Montreval as g; so g = h + i = 5 + 17 = 22. Define calm road movie in Festival de Saint-Rivage as o; so o = g = 22. Define total number of movies in Festival de Saint-Rivage as e; so e = o = 22. Answer: 22.


The number of regional medical school in Hawkesbury equals the sum of the total number of schools in Glenfield City and the number of elementary school in Evervale City. The number of culinarian school in Glenfield City equals 1 plus the number of culinarian school in Brightford. The number of regional medical school in Evervale City equals the number of elementary school in Evervale City. The number of elementary school in Westhaven City equals 4. The number of public highschool in Glenfield City equals 3. The number of public highschool in Westhaven City equals 2 times the number of elementary school in Hawkesbury. The number of elementary school in Evervale City equals 2. The number of culinarian school in Hawkesbury equals 4. The number of elementary school in Hawkesbury equals the number of culinarian school in Glenfield City. The number of culinarian school in Brightford equals 3. The number of public highschool in Hawkesbury equals 3 plus the total number of schools in Westhaven City. The number of private middle school in Brightford equals the sum of the total number of schools in Westhaven City, the number of culinarian school in Brightford, the number of elementary school in Westhaven City, and the number of public highschool in Westhaven City. The number of culinarian school in Evervale City equals 2. The number of private middle school in Evervale City equals 3 plus the number of elementary school in Evervale City. The number of private middle school in Westhaven City equals the number of elementary school in Hawkesbury.

Question: How many private middle school does Brightford have?

Solution: Define culinarian school in Brightford as o; so o = 3. Define culinarian school in Glenfield City as O; j = o = 3; so O = 1 + j = 1 + 3 = 4. Define elementary school in Hawkesbury as H; so H = O = 4. Define public highschool in Westhaven City as i; t = H = 4; so i = 2 * t = 2 * 4 = 8. Define elementary school in Westhaven City as g; so g = 4. Define private middle school in Westhaven City as D; so D = H = 4. Define total number of schools in Westhaven City as C; a = i + g = 8 + 4 = 12; so C = a + D = 12 + 4 = 16. Define private middle school in Brightford as l; G = C + o = 16 + 3 = 19; y = G + g = 19 + 4 = 23; so l = y + i = 23 + 8 = 31. Answer: 31.


The number of adult wolf in South Zoo equals 4. The number of adult fox in South Zoo equals 4 plus the number of adult wolf in South Zoo. The number of adult wolf in Jefferson Circus equals 1 plus the total number of adult animals in Mayer Aquarium. The number of adult bear in Mayer Aquarium equals the total number of adult animals in South Zoo. The number of adult wolf in Mayer Aquarium equals the number of adult bear in Mayer Aquarium. The number of adult fox in Hamilton Farm equals 3 times the total number of adult animals in Jefferson Circus.

Question: What is the total number of adult animals in Hamilton Farm?

Solution: Define adult wolf in South Zoo as k; so k = 4. Define adult fox in South Zoo as p; A = k = 4; so p = 4 + A = 4 + 4 = 8. Define total number of adult animals in South Zoo as n; so n = p + k = 8 + 4 = 12. Define adult bear in Mayer Aquarium as Z; so Z = n = 12. Define adult wolf in Mayer Aquarium as D; so D = Z = 12. Define total number of adult animals in Mayer Aquarium as W; so W = Z + D = 12 + 12 = 24. Define adult wolf in Jefferson Circus as Q; O = W = 24; so Q = 1 + O = 1 + 24 = 25. Define total number of adult animals in Jefferson Circus as l; so l = Q = 25. Define adult fox in Hamilton Farm as L; M = l = 25; so L = 3 * M = 3 * 25 = 75. Define total number of adult animals in Hamilton Farm as b; so b = L = 75. Answer: 75.


The number of private middle school in Ruby Bay equals 3 plus the total number of schools in Riverton City. The number of private middle school in Clearwater Bay equals 4. The number of culinarian school in Clearwater Bay equals 2 times the number of private middle school in Clearwater Bay. The number of culinarian school in Riverton City equals 4 times the total number of schools in Clearwater Bay. The number of private middle school in Riverton City equals 2 times the difference between the number of culinarian school in Clearwater Bay and the number of private middle school in Clearwater Bay.

Question: What is the total number of schools in Ruby Bay?

Solution: Define private middle school in Clearwater Bay as Y; so Y = 4. Define culinarian school in Clearwater Bay as q; X = Y = 4; so q = 2 * X = 2 * 4 = 8. Define total number of schools in Clearwater Bay as L; so L = Y + q = 4 + 8 = 12. Define culinarian school in Riverton City as D; a = L = 12; so D = 4 * a = 4 * 12 = 48. Define private middle school in Riverton City as z; n = q - Y = 8 - 4 = 4; so z = 2 * n = 2 * 4 = 8. Define total number of schools in Riverton City as V; so V = z + D = 8 + 48 = 56. Define private middle school in Ruby Bay as m; O = V = 56; so m = 3 + O = 3 + 56 = 59. Define total number of schools in Ruby Bay as j; so j = m = 59. Answer: 59.


The number of intense detective thriller in Northwood Movie Festival equals the sum of the number of upbeat metropolis comedy in Northwood Movie Festival, the number of intense detective thriller in Verdi Movie Festival, and the total number of movies in Verdi Movie Festival. The number of solemn period drama in Northwood Movie Festival equals 4 times the sum of the number of upbeat metropolis comedy in Northwood Movie Festival and the number of intense detective thriller in Verdi Movie Festival. The number of futuristic sci-fi movie in Northwood Movie Festival equals the number of intense detective thriller in Verdi Movie Festival. The number of upbeat metropolis comedy in Northwood Movie Festival equals 1 plus the total number of movies in Verdi Movie Festival. The number of intense detective thriller in Verdi Movie Festival equals 2.

Question: What is the total number of movies in Northwood Movie Festival?

Solution: Define intense detective thriller in Verdi Movie Festival as U; so U = 2. Define total number of movies in Verdi Movie Festival as x; so x = U = 2. Define upbeat metropolis comedy in Northwood Movie Festival as V; W = x = 2; so V = 1 + W = 1 + 2 = 3. Define solemn period drama in Northwood Movie Festival as q; S = V + U = 3 + 2 = 5; so q = 4 * S = 4 * 5 = 20. Define futuristic sci-fi movie in Northwood Movie Festival as H; so H = U = 2. Define intense detective thriller in Northwood Movie Festival as u; E = V + U = 3 + 2 = 5; so u = E + x = 5 + 2 = 7. Define total number of movies in Northwood Movie Festival as i; Q = u + V = 7 + 3 = 10; f = Q + q = 10 + 20 = 30; so i = f + H = 30 + 2 = 32. Answer: 32.


The number of upbeat metropolis comedy in Festival de Saint-Rivage equals the number of futuristic sci-fi movie in Festival de Clairmont. The number of upbeat metropolis comedy in Festival de Clairmont equals 2. The number of intense detective thriller in Cinéma de Montreval equals 3 times the number of futuristic sci-fi movie in Festival de Clairmont. The number of futuristic sci-fi movie in Cinéma de Montreval equals 3 times the total number of movies in Festival de Clairmont. The number of futuristic sci-fi movie in Festival de Clairmont equals 4. The number of intense detective thriller in Festival de Saint-Rivage equals the difference between the total number of movies in Cinéma de Montreval and the total number of movies in Festival de Clairmont.

Question: What is the total number of movies in Festival de Saint-Rivage?

Solution: Define upbeat metropolis comedy in Festival de Clairmont as W; so W = 2. Define futuristic sci-fi movie in Festival de Clairmont as T; so T = 4. Define total number of movies in Festival de Clairmont as s; so s = W + T = 2 + 4 = 6. Define futuristic sci-fi movie in Cinéma de Montreval as I; J = s = 6; so I = 3 * J = 3 * 6 = 18. Define intense detective thriller in Cinéma de Montreval as y; F = T = 4; so y = 3 * F = 3 * 4 = 12. Define total number of movies in Cinéma de Montreval as d; so d = y + I = 12 + 18 = 30. Define intense detective thriller in Festival de Saint-Rivage as u; so u = d - s = 30 - 6 = 24. Define upbeat metropolis comedy in Festival de Saint-Rivage as X; so X = T = 4. Define total number of movies in Festival de Saint-Rivage as Z; so Z = X + u = 4 + 24 = 28. Answer: 28.


The number of adult crow in Bundle Ranch equals 1 plus the total number of adult animals in Hamilton Farm. The number of adult owl in Jefferson Circus equals the total number of adult animals in South Zoo. The number of adult parrot in Mayer Aquarium equals 2 times the total number of adult animals in Jefferson Circus. The number of adult eagle in Bundle Ranch equals 4. The number of adult crow in Jefferson Circus equals the number of adult blue jay in Hamilton Farm. The number of adult blue jay in Hamilton Farm equals 3 plus the number of adult eagle in Bundle Ranch. The number of adult parrot in South Zoo equals the number of adult crow in Bundle Ranch.

Question: What is the total number of adult animals in Mayer Aquarium?

Solution: Define adult eagle in Bundle Ranch as g; so g = 4. Define adult blue jay in Hamilton Farm as f; F = g = 4; so f = 3 + F = 3 + 4 = 7. Define total number of adult animals in Hamilton Farm as P; so P = f = 7. Define adult crow in Bundle Ranch as G; t = P = 7; so G = 1 + t = 1 + 7 = 8. Define adult parrot in South Zoo as A; so A = G = 8. Define total number of adult animals in South Zoo as n; so n = A = 8. Define adult owl in Jefferson Circus as u; so u = n = 8. Define adult crow in Jefferson Circus as d; so d = f = 7. Define total number of adult animals in Jefferson Circus as h; so h = u + d = 8 + 7 = 15. Define adult parrot in Mayer Aquarium as a; J = h = 15; so a = 2 * J = 2 * 15 = 30. Define total number of adult animals in Mayer Aquarium as Z; so Z = a = 30. Answer: 30.


The number of private middle school in Glenfield City equals 2. The number of elementary school in Glenfield City equals the number of public highschool in Glenfield City. The number of culinarian school in Glenfield City equals the number of elementary school in Hawkesbury. The number of elementary school in Hawkesbury equals the sum of the number of elementary school in Glenfield City and the number of public highschool in Glenfield City. The number of public highschool in Glenfield City equals 3 times the number of private middle school in Glenfield City. The number of public highschool in Hawkesbury equals 4 times the difference between the number of elementary school in Hawkesbury and the number of elementary school in Glenfield City. The number of private middle school in Hawkesbury equals 3 plus the number of culinarian school in Glenfield City.

Question: What is the total number of schools in Hawkesbury?

Solution: Define private middle school in Glenfield City as K; so K = 2. Define public highschool in Glenfield City as u; Q = K = 2; so u = 3 * Q = 3 * 2 = 6. Define elementary school in Glenfield City as f; so f = u = 6. Define elementary school in Hawkesbury as s; so s = f + u = 6 + 6 = 12. Define public highschool in Hawkesbury as R; X = s - f = 12 - 6 = 6; so R = 4 * X = 4 * 6 = 24. Define culinarian school in Glenfield City as r; so r = s = 12. Define private middle school in Hawkesbury as Y; g = r = 12; so Y = 3 + g = 3 + 12 = 15. Define total number of schools in Hawkesbury as J; O = R + Y = 24 + 15 = 39; so J = O + s = 39 + 12 = 51. Answer: 51.


The number of adult bear in Mayer Aquarium equals the number of adult bear in Hamilton Farm. The number of adult fox in Hamilton Farm equals the number of adult fox in Jefferson Circus. The number of adult racoon in Hamilton Farm equals 3. The number of adult fox in Bundle Ranch equals 4. The number of adult racoon in Mayer Aquarium equals 4. The number of adult bear in Hamilton Farm equals the number of adult racoon in Mayer Aquarium. The number of adult wolf in Bundle Ranch equals 2. The number of adult wolf in Jefferson Circus equals 3 times the number of adult racoon in Jefferson Circus. The number of adult racoon in Jefferson Circus equals 4. The number of adult fox in Mayer Aquarium equals the number of adult bear in Mayer Aquarium. The number of adult fox in Jefferson Circus equals 3 times the sum of the total number of adult animals in Mayer Aquarium and the number of adult bear in Mayer Aquarium.

Question: What is the total number of adult animals in Hamilton Farm?

Solution: Define adult racoon in Mayer Aquarium as g; so g = 4. Define adult bear in Hamilton Farm as E; so E = g = 4. Define adult racoon in Hamilton Farm as D; so D = 3. Define adult bear in Mayer Aquarium as q; so q = E = 4. Define adult fox in Mayer Aquarium as a; so a = q = 4. Define total number of adult animals in Mayer Aquarium as X; K = g + a = 4 + 4 = 8; so X = K + q = 8 + 4 = 12. Define adult fox in Jefferson Circus as I; r = X + q = 12 + 4 = 16; so I = 3 * r = 3 * 16 = 48. Define adult fox in Hamilton Farm as P; so P = I = 48. Define total number of adult animals in Hamilton Farm as B; T = P + D = 48 + 3 = 51; so B = T + E = 51 + 4 = 55. Answer: 55.


The number of solemn period drama in Verdi Movie Festival equals 2. The number of calm road movie in Golden Banana Movie Festival equals the number of calm road movie in West Sahara Movie Festival. The number of calm road movie in West Sahara Movie Festival equals the number of upbeat metropolis comedy in Northwood Movie Festival. The number of upbeat metropolis comedy in Verdi Movie Festival equals 2 plus the difference between the total number of movies in Northwood Movie Festival and the number of upbeat metropolis comedy in Northwood Movie Festival. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals the number of solemn period drama in Verdi Movie Festival. The number of upbeat metropolis comedy in Northwood Movie Festival equals 4 plus the number of upbeat metropolis comedy in Golden Banana Movie Festival. The number of solemn period drama in Northwood Movie Festival equals the number of upbeat metropolis comedy in Golden Banana Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals 2. The number of solemn period drama in West Sahara Movie Festival equals 1 plus the number of upbeat metropolis comedy in Verdi Movie Festival.

Question: What is the total number of movies in West Sahara Movie Festival?

Solution: Define solemn period drama in Verdi Movie Festival as E; so E = 2. Define upbeat metropolis comedy in Golden Banana Movie Festival as y; so y = E = 2. Define upbeat metropolis comedy in Northwood Movie Festival as D; l = y = 2; so D = 4 + l = 4 + 2 = 6. Define solemn period drama in Northwood Movie Festival as Y; so Y = y = 2. Define total number of movies in Northwood Movie Festival as A; so A = Y + D = 2 + 6 = 8. Define upbeat metropolis comedy in Verdi Movie Festival as t; L = A - D = 8 - 6 = 2; so t = 2 + L = 2 + 2 = 4. Define solemn period drama in West Sahara Movie Festival as f; G = t = 4; so f = 1 + G = 1 + 4 = 5. Define calm road movie in West Sahara Movie Festival as r; so r = D = 6. Define total number of movies in West Sahara Movie Festival as m; so m = r + f = 6 + 5 = 11. Answer: 11.


The number of upbeat metropolis comedy in Festival de Clairmont equals 3 plus the number of calm road movie in Cinéma de Montreval. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals the number of calm road movie in Festival de Saint-Rivage. The number of upbeat metropolis comedy in Cinéma de Montreval equals 4 times the total number of movies in Festival de Clairmont. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals the number of upbeat metropolis comedy in Festival de Clairmont. The number of futuristic sci-fi movie in Cinéma de Montreval equals 2. The number of calm road movie in Cinéma de Montreval equals 2 plus the number of futuristic sci-fi movie in Cinéma de Montreval. The number of calm road movie in Festival de Saint-Rivage equals 2 times the number of upbeat metropolis comedy in Cinéma de Montreval.

Question: What is the total number of movies in Festival de Saint-Rivage?

Solution: Define futuristic sci-fi movie in Cinéma de Montreval as f; so f = 2. Define calm road movie in Cinéma de Montreval as S; A = f = 2; so S = 2 + A = 2 + 2 = 4. Define upbeat metropolis comedy in Festival de Clairmont as c; w = S = 4; so c = 3 + w = 3 + 4 = 7. Define total number of movies in Festival de Clairmont as z; so z = c = 7. Define upbeat metropolis comedy in Cinéma de Montreval as n; p = z = 7; so n = 4 * p = 4 * 7 = 28. Define calm road movie in Festival de Saint-Rivage as r; y = n = 28; so r = 2 * y = 2 * 28 = 56. Define futuristic sci-fi movie in Festival de Saint-Rivage as l; so l = r = 56. Define upbeat metropolis comedy in Festival de Saint-Rivage as N; so N = c = 7. Define total number of movies in Festival de Saint-Rivage as Z; X = l + N = 56 + 7 = 63; so Z = X + r = 63 + 56 = 119. Answer: 119.


The number of regional medical school in Riverton City equals the sum of the total number of schools in Ruby Bay and the total number of schools in Clearwater Bay. The number of culinarian school in Clearwater Bay equals 4. The number of culinarian school in Riverton City equals the sum of the number of culinarian school in Ruby Bay and the number of culinarian school in Clearwater Bay. The number of culinarian school in Ruby Bay equals 2 plus the number of regional medical school in Ruby Bay. The number of regional medical school in Ruby Bay equals 2 times the sum of the total number of schools in Clearwater Bay and the number of culinarian school in Clearwater Bay.

Question: What is the total number of schools in Riverton City?

Solution: Define culinarian school in Clearwater Bay as n; so n = 4. Define total number of schools in Clearwater Bay as r; so r = n = 4. Define regional medical school in Ruby Bay as w; j = r + n = 4 + 4 = 8; so w = 2 * j = 2 * 8 = 16. Define culinarian school in Ruby Bay as S; D = w = 16; so S = 2 + D = 2 + 16 = 18. Define total number of schools in Ruby Bay as x; so x = S + w = 18 + 16 = 34. Define regional medical school in Riverton City as J; so J = x + r = 34 + 4 = 38. Define culinarian school in Riverton City as R; so R = S + n = 18 + 4 = 22. Define total number of schools in Riverton City as N; so N = R + J = 22 + 38 = 60. Answer: 60.


The number of adult parrot in Mayer Aquarium equals 3 plus the number of adult owl in Mayer Aquarium. The number of adult owl in Mayer Aquarium equals 1. The number of adult owl in Jefferson Circus equals 3 times the total number of adult animals in Hamilton Farm. The number of adult eagle in Bundle Ranch equals 2 times the number of adult owl in Jefferson Circus. The number of adult crow in South Zoo equals the total number of adult animals in Bundle Ranch. The number of adult crow in Jefferson Circus equals 4. The number of adult blue jay in Hamilton Farm equals the sum of the total number of adult animals in Mayer Aquarium, the number of adult owl in Mayer Aquarium, and the number of adult parrot in Mayer Aquarium.

Question: How many adult crow does South Zoo have?

Solution: Define adult owl in Mayer Aquarium as y; so y = 1. Define adult parrot in Mayer Aquarium as c; n = y = 1; so c = 3 + n = 3 + 1 = 4. Define total number of adult animals in Mayer Aquarium as J; so J = c + y = 4 + 1 = 5. Define adult blue jay in Hamilton Farm as X; e = J + y = 5 + 1 = 6; so X = e + c = 6 + 4 = 10. Define total number of adult animals in Hamilton Farm as v; so v = X = 10. Define adult owl in Jefferson Circus as t; L = v = 10; so t = 3 * L = 3 * 10 = 30. Define adult eagle in Bundle Ranch as i; M = t = 30; so i = 2 * M = 2 * 30 = 60. Define total number of adult animals in Bundle Ranch as l; so l = i = 60. Define adult crow in South Zoo as Q; so Q = l = 60. Answer: 60.


The number of calm road movie in Festival Lumière de Valmont equals the sum of the number of calm road movie in Rêves de Belleville and the number of solemn period drama in Cinéma de Montreval. The number of solemn period drama in Festival Lumière de Valmont equals the total number of movies in Cinéma de Montreval. The number of calm road movie in Cinéma de Montreval equals 2. The number of futuristic sci-fi movie in Rêves de Belleville equals 4 plus the number of futuristic sci-fi movie in Festival Lumière de Valmont. The number of futuristic sci-fi movie in Cinéma de Montreval equals the number of calm road movie in Cinéma de Montreval. The number of calm road movie in Rêves de Belleville equals 2 plus the sum of the number of solemn period drama in Festival Lumière de Valmont, the number of futuristic sci-fi movie in Cinéma de Montreval, and the total number of movies in Cinéma de Montreval. The number of solemn period drama in Rêves de Belleville equals 2. The number of futuristic sci-fi movie in Festival Lumière de Valmont equals 2. The number of solemn period drama in Cinéma de Montreval equals 2 times the sum of the number of calm road movie in Cinéma de Montreval and the number of futuristic sci-fi movie in Cinéma de Montreval.

Question: How many calm road movie does Festival Lumière de Valmont have?

Solution: Define calm road movie in Cinéma de Montreval as j; so j = 2. Define futuristic sci-fi movie in Cinéma de Montreval as f; so f = j = 2. Define solemn period drama in Cinéma de Montreval as Y; s = j + f = 2 + 2 = 4; so Y = 2 * s = 2 * 4 = 8. Define total number of movies in Cinéma de Montreval as x; Z = Y + j = 8 + 2 = 10; so x = Z + f = 10 + 2 = 12. Define solemn period drama in Festival Lumière de Valmont as i; so i = x = 12. Define calm road movie in Rêves de Belleville as g; Q = i + f = 12 + 2 = 14; d = Q + x = 14 + 12 = 26; so g = 2 + d = 2 + 26 = 28. Define calm road movie in Festival Lumière de Valmont as D; so D = g + Y = 28 + 8 = 36. Answer: 36.


The number of elementary school in Riverton City equals the number of elementary school in Shoreline City. The number of elementary school in Shoreline City equals the number of regional medical school in Shoreline City. The number of regional medical school in Riverton City equals 3 plus the total number of schools in Shoreline City. The number of regional medical school in Shoreline City equals 3. The number of private middle school in Riverton City equals 3 plus the total number of schools in Shoreline City. The number of private middle school in Shoreline City equals 2 times the number of regional medical school in Shoreline City.

Question: What is the total number of schools in Riverton City?

Solution: Define regional medical school in Shoreline City as U; so U = 3. Define private middle school in Shoreline City as A; m = U = 3; so A = 2 * m = 2 * 3 = 6. Define elementary school in Shoreline City as L; so L = U = 3. Define total number of schools in Shoreline City as e; w = U + A = 3 + 6 = 9; so e = w + L = 9 + 3 = 12. Define regional medical school in Riverton City as I; x = e = 12; so I = 3 + x = 3 + 12 = 15. Define private middle school in Riverton City as o; t = e = 12; so o = 3 + t = 3 + 12 = 15. Define elementary school in Riverton City as z; so z = L = 3. Define total number of schools in Riverton City as v; s = I + z = 15 + 3 = 18; so v = s + o = 18 + 15 = 33. Answer: 33.


The number of futuristic sci-fi movie in Taylor Movie Festival equals 1. The number of solemn period drama in Taylor Movie Festival equals the number of futuristic sci-fi movie in Taylor Movie Festival. The number of futuristic sci-fi movie in West Sahara Movie Festival equals 2 times the sum of the number of intense detective thriller in West Sahara Movie Festival, the number of futuristic sci-fi movie in Taylor Movie Festival, and the number of solemn period drama in Taylor Movie Festival. The number of intense detective thriller in West Sahara Movie Festival equals the sum of the total number of movies in Taylor Movie Festival, the number of futuristic sci-fi movie in Taylor Movie Festival, and the number of solemn period drama in Taylor Movie Festival. The number of intense detective thriller in Golden Banana Movie Festival equals 2 plus the sum of the number of futuristic sci-fi movie in West Sahara Movie Festival, the number of intense detective thriller in West Sahara Movie Festival, and the total number of movies in Taylor Movie Festival.

Question: How many intense detective thriller does Golden Banana Movie Festival have?

Solution: Define futuristic sci-fi movie in Taylor Movie Festival as D; so D = 1. Define solemn period drama in Taylor Movie Festival as G; so G = D = 1. Define total number of movies in Taylor Movie Festival as R; so R = D + G = 1 + 1 = 2. Define intense detective thriller in West Sahara Movie Festival as J; H = R + D = 2 + 1 = 3; so J = H + G = 3 + 1 = 4. Define futuristic sci-fi movie in West Sahara Movie Festival as S; g = J + D = 4 + 1 = 5; Q = g + G = 5 + 1 = 6; so S = 2 * Q = 2 * 6 = 12. Define intense detective thriller in Golden Banana Movie Festival as X; o = S + J = 12 + 4 = 16; F = o + R = 16 + 2 = 18; so X = 2 + F = 2 + 18 = 20. Answer: 20.


The number of regional medical school in Shoreline City equals 3. The number of regional medical school in Riverton City equals 3. The number of private middle school in Oakbridge City equals the total number of schools in Riverton City. The number of regional medical school in Oakbridge City equals the sum of the number of private middle school in Oakbridge City, the total number of schools in Riverton City, and the number of regional medical school in Riverton City. The number of private middle school in Shoreline City equals 2 times the total number of schools in Oakbridge City. The number of public highschool in Shoreline City equals 2.

Question: What is the total number of schools in Shoreline City?

Solution: Define regional medical school in Riverton City as d; so d = 3. Define total number of schools in Riverton City as r; so r = d = 3. Define private middle school in Oakbridge City as T; so T = r = 3. Define regional medical school in Oakbridge City as s; k = T + r = 3 + 3 = 6; so s = k + d = 6 + 3 = 9. Define total number of schools in Oakbridge City as A; so A = T + s = 3 + 9 = 12. Define private middle school in Shoreline City as M; O = A = 12; so M = 2 * O = 2 * 12 = 24. Define public highschool in Shoreline City as v; so v = 2. Define regional medical school in Shoreline City as Q; so Q = 3. Define total number of schools in Shoreline City as h; X = M + v = 24 + 2 = 26; so h = X + Q = 26 + 3 = 29. Answer: 29.


The number of solemn period drama in Rêves de Belleville equals the number of intense detective thriller in Rêves de Belleville. The number of upbeat metropolis comedy in Cinéma de Montreval equals 4 plus the number of intense detective thriller in Cinéma de Montreval. The number of intense detective thriller in Festival Lumière de Valmont equals 3. The number of upbeat metropolis comedy in Festival Lumière de Valmont equals the number of solemn period drama in Festival Lumière de Valmont. The number of solemn period drama in Festival Lumière de Valmont equals the number of intense detective thriller in Festival de Saint-Rivage. The number of upbeat metropolis comedy in Rêves de Belleville equals the number of intense detective thriller in Rêves de Belleville. The number of solemn period drama in Festival de Saint-Rivage equals the total number of movies in Festival Lumière de Valmont. The number of solemn period drama in Cinéma de Montreval equals 3. The number of intense detective thriller in Cinéma de Montreval equals 4. The number of intense detective thriller in Rêves de Belleville equals 4. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals 4 plus the difference between the number of upbeat metropolis comedy in Cinéma de Montreval and the number of solemn period drama in Cinéma de Montreval. The number of intense detective thriller in Festival de Saint-Rivage equals the total number of movies in Cinéma de Montreval.

Question: How many solemn period drama does Festival de Saint-Rivage have?

Solution: Define intense detective thriller in Cinéma de Montreval as I; so I = 4. Define upbeat metropolis comedy in Cinéma de Montreval as c; z = I = 4; so c = 4 + z = 4 + 4 = 8. Define solemn period drama in Cinéma de Montreval as j; so j = 3. Define total number of movies in Cinéma de Montreval as K; t = I + c = 4 + 8 = 12; so K = t + j = 12 + 3 = 15. Define intense detective thriller in Festival de Saint-Rivage as i; so i = K = 15. Define solemn period drama in Festival Lumière de Valmont as L; so L = i = 15. Define intense detective thriller in Festival Lumière de Valmont as e; so e = 3. Define upbeat metropolis comedy in Festival Lumière de Valmont as o; so o = L = 15. Define total number of movies in Festival Lumière de Valmont as b; O = e + o = 3 + 15 = 18; so b = O + L = 18 + 15 = 33. Define solemn period drama in Festival de Saint-Rivage as W; so W = b = 33. Answer: 33.


The number of public highschool in Hawkesbury equals 2 plus the number of public highschool in Glenfield City. The number of regional medical school in Brightford equals the total number of schools in Hawkesbury. The number of regional medical school in Glenfield City equals 1 plus the total number of schools in Brightford. The number of private middle school in Glenfield City equals the sum of the total number of schools in Hawkesbury and the number of public highschool in Glenfield City. The number of public highschool in Brightford equals 4 times the number of regional medical school in Brightford. The number of public highschool in Glenfield City equals 1. The number of private middle school in Brightford equals the number of private middle school in Glenfield City.

Question: How many regional medical school does Glenfield City have?

Solution: Define public highschool in Glenfield City as I; so I = 1. Define public highschool in Hawkesbury as d; e = I = 1; so d = 2 + e = 2 + 1 = 3. Define total number of schools in Hawkesbury as R; so R = d = 3. Define regional medical school in Brightford as j; so j = R = 3. Define public highschool in Brightford as w; k = j = 3; so w = 4 * k = 4 * 3 = 12. Define private middle school in Glenfield City as J; so J = R + I = 3 + 1 = 4. Define private middle school in Brightford as S; so S = J = 4. Define total number of schools in Brightford as v; N = j + S = 3 + 4 = 7; so v = N + w = 7 + 12 = 19. Define regional medical school in Glenfield City as L; U = v = 19; so L = 1 + U = 1 + 19 = 20. Answer: 20.


The number of adult eagle in Mayer Aquarium equals 4 times the number of adult blue jay in South Zoo. The number of adult blue jay in Mayer Aquarium equals 3. The number of adult eagle in Jefferson Circus equals the number of adult crow in Jefferson Circus. The number of adult crow in Mayer Aquarium equals 3 times the total number of adult animals in Jefferson Circus. The number of adult crow in Jefferson Circus equals 2 times the number of adult crow in South Zoo. The number of adult eagle in South Zoo equals the number of adult eagle in Mayer Aquarium. The number of adult crow in South Zoo equals 4. The number of adult blue jay in South Zoo equals the difference between the number of adult crow in Mayer Aquarium and the number of adult eagle in Jefferson Circus. The number of adult blue jay in Jefferson Circus equals the number of adult crow in South Zoo.

Question: How many adult eagle does South Zoo have?

Solution: Define adult crow in South Zoo as s; so s = 4. Define adult crow in Jefferson Circus as B; j = s = 4; so B = 2 * j = 2 * 4 = 8. Define adult eagle in Jefferson Circus as Y; so Y = B = 8. Define adult blue jay in Jefferson Circus as y; so y = s = 4. Define total number of adult animals in Jefferson Circus as Q; q = y + Y = 4 + 8 = 12; so Q = q + B = 12 + 8 = 20. Define adult crow in Mayer Aquarium as c; g = Q = 20; so c = 3 * g = 3 * 20 = 60. Define adult blue jay in South Zoo as O; so O = c - Y = 60 - 8 = 52. Define adult eagle in Mayer Aquarium as K; w = O = 52; so K = 4 * w = 4 * 52 = 208. Define adult eagle in South Zoo as E; so E = K = 208. Answer: 208.


The number of adult owl in Pine Ridge equals 2 times the number of adult eagle in Pine Ridge. The number of adult eagle in Oakridge Riverside equals 2. The number of adult parrot in Cedar Valley equals 2 times the total number of adult animals in Maple Creek. The number of adult eagle in Pine Ridge equals the number of adult parrot in Pine Ridge. The number of adult parrot in Oakridge Riverside equals 2 times the difference between the number of adult parrot in Cedar Valley and the total number of adult animals in Maple Creek. The number of adult parrot in Pine Ridge equals the number of adult parrot in Oakridge Riverside. The number of adult owl in Maple Creek equals 4 times the number of adult eagle in Oakridge Riverside. The number of adult blue jay in Pine Ridge equals 3 times the number of adult owl in Pine Ridge.

Question: How many adult blue jay does Pine Ridge have?

Solution: Define adult eagle in Oakridge Riverside as C; so C = 2. Define adult owl in Maple Creek as J; A = C = 2; so J = 4 * A = 4 * 2 = 8. Define total number of adult animals in Maple Creek as f; so f = J = 8. Define adult parrot in Cedar Valley as K; B = f = 8; so K = 2 * B = 2 * 8 = 16. Define adult parrot in Oakridge Riverside as b; x = K - f = 16 - 8 = 8; so b = 2 * x = 2 * 8 = 16. Define adult parrot in Pine Ridge as g; so g = b = 16. Define adult eagle in Pine Ridge as V; so V = g = 16. Define adult owl in Pine Ridge as k; w = V = 16; so k = 2 * w = 2 * 16 = 32. Define adult blue jay in Pine Ridge as i; M = k = 32; so i = 3 * M = 3 * 32 = 96. Answer: 96.


The number of intense detective thriller in Golden Banana Movie Festival equals the sum of the number of intense detective thriller in Taylor Movie Festival, the number of calm road movie in Northwood Movie Festival, the number of upbeat metropolis comedy in West Sahara Movie Festival, and the number of upbeat metropolis comedy in Golden Banana Movie Festival. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 2 times the number of upbeat metropolis comedy in West Sahara Movie Festival. The number of upbeat metropolis comedy in West Sahara Movie Festival equals 4 times the number of calm road movie in Northwood Movie Festival. The number of calm road movie in Taylor Movie Festival equals 1 plus the difference between the number of upbeat metropolis comedy in West Sahara Movie Festival and the total number of movies in Golden Banana Movie Festival. The number of intense detective thriller in West Sahara Movie Festival equals 1 plus the number of calm road movie in West Sahara Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals 2. The number of upbeat metropolis comedy in Taylor Movie Festival equals 1. The number of intense detective thriller in Taylor Movie Festival equals 2 plus the sum of the number of upbeat metropolis comedy in Northwood Movie Festival, the number of calm road movie in Northwood Movie Festival, and the number of upbeat metropolis comedy in Golden Banana Movie Festival. The number of calm road movie in Northwood Movie Festival equals 2. The number of calm road movie in West Sahara Movie Festival equals 4. The number of upbeat metropolis comedy in Northwood Movie Festival equals 2 plus the number of upbeat metropolis comedy in Golden Banana Movie Festival. The number of intense detective thriller in Northwood Movie Festival equals 4 plus the total number of movies in Taylor Movie Festival.

Question: How many intense detective thriller does Golden Banana Movie Festival have?

Solution: Define calm road movie in Northwood Movie Festival as B; so B = 2. Define upbeat metropolis comedy in West Sahara Movie Festival as S; L = B = 2; so S = 4 * L = 4 * 2 = 8. Define upbeat metropolis comedy in Golden Banana Movie Festival as N; p = S = 8; so N = 2 * p = 2 * 8 = 16. Define upbeat metropolis comedy in Northwood Movie Festival as T; d = N = 16; so T = 2 + d = 2 + 16 = 18. Define intense detective thriller in Taylor Movie Festival as P; D = T + B = 18 + 2 = 20; M = D + N = 20 + 16 = 36; so P = 2 + M = 2 + 36 = 38. Define intense detective thriller in Golden Banana Movie Festival as f; u = P + B = 38 + 2 = 40; O = u + S = 40 + 8 = 48; so f = O + N = 48 + 16 = 64. Answer: 64.


The number of solemn period drama in Cinéma de Montreval equals the number of solemn period drama in Festival Lumière de Valmont. The number of futuristic sci-fi movie in Festival Lumière de Valmont equals the sum of the total number of movies in Cinéma de Montreval and the number of futuristic sci-fi movie in Festival de Saint-Rivage. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals the difference between the number of upbeat metropolis comedy in Cinéma de Montreval and the number of upbeat metropolis comedy in Festival Lumière de Valmont. The number of upbeat metropolis comedy in Festival de Clairmont equals 4. The number of solemn period drama in Festival Lumière de Valmont equals 3. The number of upbeat metropolis comedy in Cinéma de Montreval equals the number of futuristic sci-fi movie in Cinéma de Montreval. The number of solemn period drama in Festival de Clairmont equals the total number of movies in Cinéma de Montreval. The number of upbeat metropolis comedy in Festival Lumière de Valmont equals 3 plus the total number of movies in Festival de Clairmont. The number of solemn period drama in Festival de Saint-Rivage equals 3. The number of futuristic sci-fi movie in Festival de Clairmont equals the number of upbeat metropolis comedy in Festival de Clairmont. The number of futuristic sci-fi movie in Cinéma de Montreval equals the number of solemn period drama in Festival Lumière de Valmont. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals 3.

Question: How many upbeat metropolis comedy does Festival Lumière de Valmont have?

Solution: Define solemn period drama in Festival Lumière de Valmont as Y; so Y = 3. Define solemn period drama in Cinéma de Montreval as N; so N = Y = 3. Define futuristic sci-fi movie in Cinéma de Montreval as V; so V = Y = 3. Define upbeat metropolis comedy in Cinéma de Montreval as E; so E = V = 3. Define total number of movies in Cinéma de Montreval as H; F = E + N = 3 + 3 = 6; so H = F + V = 6 + 3 = 9. Define solemn period drama in Festival de Clairmont as C; so C = H = 9. Define upbeat metropolis comedy in Festival de Clairmont as Z; so Z = 4. Define futuristic sci-fi movie in Festival de Clairmont as o; so o = Z = 4. Define total number of movies in Festival de Clairmont as h; B = Z + C = 4 + 9 = 13; so h = B + o = 13 + 4 = 17. Define upbeat metropolis comedy in Festival Lumière de Valmont as X; d = h = 17; so X = 3 + d = 3 + 17 = 20. Answer: 20.


The number of adult racoon in Maple Creek equals 3 plus the total number of adult animals in Beverly Forest. The number of adult wolf in Beverly Forest equals 3. The number of adult bear in Cedar Valley equals the sum of the total number of adult animals in Maple Creek, the number of adult racoon in Maple Creek, and the number of adult wolf in Beverly Forest. The number of adult racoon in Beverly Forest equals 1 plus the number of adult wolf in Beverly Forest. The number of adult wolf in Cedar Valley equals 3 times the total number of adult animals in Maple Creek.

Question: What is the total number of adult animals in Cedar Valley?

Solution: Define adult wolf in Beverly Forest as g; so g = 3. Define adult racoon in Beverly Forest as K; s = g = 3; so K = 1 + s = 1 + 3 = 4. Define total number of adult animals in Beverly Forest as Z; so Z = g + K = 3 + 4 = 7. Define adult racoon in Maple Creek as U; V = Z = 7; so U = 3 + V = 3 + 7 = 10. Define total number of adult animals in Maple Creek as F; so F = U = 10. Define adult bear in Cedar Valley as e; R = F + U = 10 + 10 = 20; so e = R + g = 20 + 3 = 23. Define adult wolf in Cedar Valley as i; m = F = 10; so i = 3 * m = 3 * 10 = 30. Define total number of adult animals in Cedar Valley as j; so j = i + e = 30 + 23 = 53. Answer: 53.


The number of calm road movie in Verdi Movie Festival equals 2 times the number of solemn period drama in Golden Banana Movie Festival. The number of calm road movie in Taylor Movie Festival equals the number of upbeat metropolis comedy in Golden Banana Movie Festival. The number of upbeat metropolis comedy in Verdi Movie Festival equals the number of calm road movie in Taylor Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals the number of intense detective thriller in Golden Banana Movie Festival. The number of solemn period drama in West Sahara Movie Festival equals the number of solemn period drama in Golden Banana Movie Festival. The number of upbeat metropolis comedy in Taylor Movie Festival equals the sum of the number of calm road movie in Golden Banana Movie Festival and the number of intense detective thriller in Golden Banana Movie Festival. The number of intense detective thriller in Golden Banana Movie Festival equals 3. The number of solemn period drama in Taylor Movie Festival equals the sum of the number of intense detective thriller in Verdi Movie Festival, the number of solemn period drama in Verdi Movie Festival, the number of intense detective thriller in West Sahara Movie Festival, and the number of calm road movie in Verdi Movie Festival. The number of upbeat metropolis comedy in West Sahara Movie Festival equals the difference between the number of upbeat metropolis comedy in Golden Banana Movie Festival and the number of calm road movie in Verdi Movie Festival. The number of solemn period drama in Verdi Movie Festival equals 3 plus the number of upbeat metropolis comedy in Verdi Movie Festival. The number of intense detective thriller in West Sahara Movie Festival equals 2 plus the sum of the number of intense detective thriller in Golden Banana Movie Festival, the number of calm road movie in Golden Banana Movie Festival, and the number of upbeat metropolis comedy in Taylor Movie Festival. The number of calm road movie in West Sahara Movie Festival equals 2 times the number of intense detective thriller in Verdi Movie Festival. The number of intense detective thriller in Verdi Movie Festival equals the number of upbeat metropolis comedy in Verdi Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals 2 plus the sum of the number of calm road movie in Taylor Movie Festival and the number of upbeat metropolis comedy in Golden Banana Movie Festival. The number of intense detective thriller in Taylor Movie Festival equals 3. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 3.

Question: What is the total number of movies in Verdi Movie Festival?

Solution: Define upbeat metropolis comedy in Golden Banana Movie Festival as H; so H = 3. Define calm road movie in Taylor Movie Festival as f; so f = H = 3. Define solemn period drama in Golden Banana Movie Festival as S; c = f + H = 3 + 3 = 6; so S = 2 + c = 2 + 6 = 8. Define upbeat metropolis comedy in Verdi Movie Festival as F; so F = f = 3. Define calm road movie in Verdi Movie Festival as b; G = S = 8; so b = 2 * G = 2 * 8 = 16. Define intense detective thriller in Verdi Movie Festival as d; so d = F = 3. Define solemn period drama in Verdi Movie Festival as v; i = F = 3; so v = 3 + i = 3 + 3 = 6. Define total number of movies in Verdi Movie Festival as M; o = b + d = 16 + 3 = 19; q = o + v = 19 + 6 = 25; so M = q + F = 25 + 3 = 28. Answer: 28.


The number of adult blue jay in Bundle Ranch equals 3 times the total number of adult animals in South Zoo. The number of adult eagle in South Zoo equals 2 times the number of adult crow in South Zoo. The number of adult crow in Bundle Ranch equals the number of adult blue jay in Bundle Ranch. The number of adult crow in South Zoo equals 4. The number of adult blue jay in Mayer Aquarium equals 3 times the number of adult blue jay in Bundle Ranch. The number of adult eagle in Mayer Aquarium equals the total number of adult animals in Bundle Ranch.

Question: What is the total number of adult animals in Mayer Aquarium?

Solution: Define adult crow in South Zoo as Y; so Y = 4. Define adult eagle in South Zoo as C; L = Y = 4; so C = 2 * L = 2 * 4 = 8. Define total number of adult animals in South Zoo as r; so r = Y + C = 4 + 8 = 12. Define adult blue jay in Bundle Ranch as v; e = r = 12; so v = 3 * e = 3 * 12 = 36. Define adult crow in Bundle Ranch as S; so S = v = 36. Define total number of adult animals in Bundle Ranch as w; so w = v + S = 36 + 36 = 72. Define adult eagle in Mayer Aquarium as q; so q = w = 72. Define adult blue jay in Mayer Aquarium as K; J = v = 36; so K = 3 * J = 3 * 36 = 108. Define total number of adult animals in Mayer Aquarium as A; so A = K + q = 108 + 72 = 180. Answer: 180.


The number of calm road movie in Rêves de Belleville equals 2. The number of upbeat metropolis comedy in Festival de Clairmont equals 4. The number of solemn period drama in Rêves de Belleville equals 3 times the number of futuristic sci-fi movie in Rêves de Belleville. The number of solemn period drama in Festival Lumière de Valmont equals 4 plus the number of upbeat metropolis comedy in Festival de Clairmont. The number of futuristic sci-fi movie in Rêves de Belleville equals the sum of the total number of movies in Cinéma de Montreval and the number of intense detective thriller in Rêves de Belleville. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals the total number of movies in Rêves de Belleville. The number of intense detective thriller in Rêves de Belleville equals 4 times the number of intense detective thriller in Cinéma de Montreval. The number of intense detective thriller in Cinéma de Montreval equals 2.

Question: What is the total number of movies in Festival de Saint-Rivage?

Solution: Define intense detective thriller in Cinéma de Montreval as s; so s = 2. Define intense detective thriller in Rêves de Belleville as F; E = s = 2; so F = 4 * E = 4 * 2 = 8. Define total number of movies in Cinéma de Montreval as M; so M = s = 2. Define futuristic sci-fi movie in Rêves de Belleville as y; so y = M + F = 2 + 8 = 10. Define solemn period drama in Rêves de Belleville as h; Q = y = 10; so h = 3 * Q = 3 * 10 = 30. Define calm road movie in Rêves de Belleville as i; so i = 2. Define total number of movies in Rêves de Belleville as X; q = h + i = 30 + 2 = 32; S = q + y = 32 + 10 = 42; so X = S + F = 42 + 8 = 50. Define upbeat metropolis comedy in Festival de Saint-Rivage as K; so K = X = 50. Define total number of movies in Festival de Saint-Rivage as C; so C = K = 50. Answer: 50.


The number of solemn period drama in Festival de Saint-Rivage equals 1 plus the number of solemn period drama in Festival Lumière de Valmont. The number of solemn period drama in Festival de Clairmont equals 2 plus the total number of movies in Cinéma de Montreval. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals the number of futuristic sci-fi movie in Festival Lumière de Valmont. The number of futuristic sci-fi movie in Festival Lumière de Valmont equals the sum of the number of intense detective thriller in Festival Lumière de Valmont and the total number of movies in Festival de Clairmont. The number of upbeat metropolis comedy in Cinéma de Montreval equals 1 plus the number of solemn period drama in Festival de Saint-Rivage. The number of solemn period drama in Festival Lumière de Valmont equals 4. The number of intense detective thriller in Festival Lumière de Valmont equals 3 times the sum of the total number of movies in Festival de Clairmont and the number of upbeat metropolis comedy in Cinéma de Montreval.

Question: How many upbeat metropolis comedy does Festival de Saint-Rivage have?

Solution: Define solemn period drama in Festival Lumière de Valmont as V; so V = 4. Define solemn period drama in Festival de Saint-Rivage as A; z = V = 4; so A = 1 + z = 1 + 4 = 5. Define upbeat metropolis comedy in Cinéma de Montreval as y; X = A = 5; so y = 1 + X = 1 + 5 = 6. Define total number of movies in Cinéma de Montreval as c; so c = y = 6. Define solemn period drama in Festival de Clairmont as m; b = c = 6; so m = 2 + b = 2 + 6 = 8. Define total number of movies in Festival de Clairmont as O; so O = m = 8. Define intense detective thriller in Festival Lumière de Valmont as u; e = O + y = 8 + 6 = 14; so u = 3 * e = 3 * 14 = 42. Define futuristic sci-fi movie in Festival Lumière de Valmont as t; so t = u + O = 42 + 8 = 50. Define upbeat metropolis comedy in Festival de Saint-Rivage as E; so E = t = 50. Answer: 50.


The number of private middle school in Glenfield City equals the total number of schools in Evervale City. The number of culinarian school in Brightford equals the total number of schools in Evervale City. The number of private middle school in Brightford equals 4 times the sum of the number of private middle school in Glenfield City and the total number of schools in Evervale City. The number of regional medical school in Glenfield City equals 2 times the sum of the total number of schools in Brightford, the number of private middle school in Glenfield City, and the total number of schools in Evervale City. The number of regional medical school in Evervale City equals the number of culinarian school in Evervale City. The number of regional medical school in Brightford equals 3 plus the sum of the total number of schools in Evervale City and the number of regional medical school in Evervale City. The number of culinarian school in Evervale City equals 1. The number of culinarian school in Glenfield City equals the total number of schools in Evervale City.

Question: What is the total number of schools in Brightford?

Solution: Define culinarian school in Evervale City as l; so l = 1. Define regional medical school in Evervale City as j; so j = l = 1. Define total number of schools in Evervale City as a; so a = l + j = 1 + 1 = 2. Define regional medical school in Brightford as n; k = a + j = 2 + 1 = 3; so n = 3 + k = 3 + 3 = 6. Define private middle school in Glenfield City as y; so y = a = 2. Define private middle school in Brightford as Q; T = y + a = 2 + 2 = 4; so Q = 4 * T = 4 * 4 = 16. Define culinarian school in Brightford as g; so g = a = 2. Define total number of schools in Brightford as e; I = g + Q = 2 + 16 = 18; so e = I + n = 18 + 6 = 24. Answer: 24.


The number of regional medical school in Brightford equals the total number of schools in Westhaven City. The number of elementary school in Westhaven City equals 4 plus the total number of schools in Hawkesbury. The number of private middle school in Evervale City equals the sum of the total number of schools in Glenfield City and the number of culinarian school in Glenfield City. The number of culinarian school in Glenfield City equals the total number of schools in Brightford. The number of public highschool in Hawkesbury equals 4. The number of private middle school in Glenfield City equals 3 plus the total number of schools in Brightford.

Question: What is the total number of schools in Evervale City?

Solution: Define public highschool in Hawkesbury as N; so N = 4. Define total number of schools in Hawkesbury as O; so O = N = 4. Define elementary school in Westhaven City as L; Z = O = 4; so L = 4 + Z = 4 + 4 = 8. Define total number of schools in Westhaven City as D; so D = L = 8. Define regional medical school in Brightford as o; so o = D = 8. Define total number of schools in Brightford as a; so a = o = 8. Define private middle school in Glenfield City as m; R = a = 8; so m = 3 + R = 3 + 8 = 11. Define culinarian school in Glenfield City as u; so u = a = 8. Define total number of schools in Glenfield City as c; so c = m + u = 11 + 8 = 19. Define private middle school in Evervale City as h; so h = c + u = 19 + 8 = 27. Define total number of schools in Evervale City as q; so q = h = 27. Answer: 27.


The number of adult wolf in South Zoo equals 2. The number of adult fox in South Zoo equals 3 times the number of adult deer in Hamilton Farm. The number of adult deer in Hamilton Farm equals 4. The number of adult wolf in Mayer Aquarium equals 2 times the sum of the total number of adult animals in Hamilton Farm, the total number of adult animals in Jefferson Circus, and the number of adult wolf in South Zoo. The number of adult wolf in Hamilton Farm equals 2. The number of adult fox in Mayer Aquarium equals 3 plus the sum of the number of adult bear in Jefferson Circus and the number of adult deer in Jefferson Circus. The number of adult bear in South Zoo equals 2. The number of adult bear in Mayer Aquarium equals 3 times the sum of the number of adult wolf in Mayer Aquarium, the total number of adult animals in Jefferson Circus, and the number of adult fox in Mayer Aquarium. The number of adult bear in Jefferson Circus equals the total number of adult animals in South Zoo. The number of adult deer in South Zoo equals 2 plus the number of adult fox in South Zoo. The number of adult deer in Jefferson Circus equals the number of adult fox in South Zoo.

Question: What is the total number of adult animals in Jefferson Circus?

Solution: Define adult deer in Hamilton Farm as R; so R = 4. Define adult fox in South Zoo as X; j = R = 4; so X = 3 * j = 3 * 4 = 12. Define adult bear in South Zoo as d; so d = 2. Define adult wolf in South Zoo as m; so m = 2. Define adult deer in South Zoo as v; z = X = 12; so v = 2 + z = 2 + 12 = 14. Define adult deer in Jefferson Circus as W; so W = X = 12. Define total number of adult animals in South Zoo as w; B = d + X = 2 + 12 = 14; c = B + v = 14 + 14 = 28; so w = c + m = 28 + 2 = 30. Define adult bear in Jefferson Circus as Q; so Q = w = 30. Define total number of adult animals in Jefferson Circus as i; so i = W + Q = 12 + 30 = 42. Answer: 42.


The number of regional medical school in Evervale City equals 3 plus the total number of schools in Hawkesbury. The number of public highschool in Westhaven City equals 2 plus the number of culinarian school in Westhaven City. The number of culinarian school in Westhaven City equals 4. The number of regional medical school in Hawkesbury equals 2 plus the total number of schools in Westhaven City. The number of public highschool in Hawkesbury equals the sum of the number of regional medical school in Hawkesbury, the number of culinarian school in Westhaven City, and the number of public highschool in Westhaven City.

Question: What is the total number of schools in Evervale City?

Solution: Define culinarian school in Westhaven City as g; so g = 4. Define public highschool in Westhaven City as f; S = g = 4; so f = 2 + S = 2 + 4 = 6. Define total number of schools in Westhaven City as U; so U = g + f = 4 + 6 = 10. Define regional medical school in Hawkesbury as y; F = U = 10; so y = 2 + F = 2 + 10 = 12. Define public highschool in Hawkesbury as O; Y = y + g = 12 + 4 = 16; so O = Y + f = 16 + 6 = 22. Define total number of schools in Hawkesbury as Q; so Q = y + O = 12 + 22 = 34. Define regional medical school in Evervale City as j; X = Q = 34; so j = 3 + X = 3 + 34 = 37. Define total number of schools in Evervale City as L; so L = j = 37. Answer: 37.


The number of solemn period drama in Verdi Movie Festival equals the sum of the total number of movies in Northwood Movie Festival, the total number of movies in Taylor Movie Festival, the number of solemn period drama in Taylor Movie Festival, and the number of solemn period drama in Golden Banana Movie Festival. The number of solemn period drama in Northwood Movie Festival equals 4 times the number of intense detective thriller in Taylor Movie Festival. The number of intense detective thriller in Taylor Movie Festival equals the total number of movies in Golden Banana Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals the sum of the number of calm road movie in Golden Banana Movie Festival and the number of intense detective thriller in Golden Banana Movie Festival. The number of solemn period drama in Taylor Movie Festival equals 4. The number of intense detective thriller in Golden Banana Movie Festival equals the number of futuristic sci-fi movie in Taylor Movie Festival. The number of intense detective thriller in Verdi Movie Festival equals 3 times the sum of the number of calm road movie in Taylor Movie Festival, the number of intense detective thriller in Golden Banana Movie Festival, and the number of calm road movie in Northwood Movie Festival. The number of intense detective thriller in Northwood Movie Festival equals 4. The number of futuristic sci-fi movie in Taylor Movie Festival equals 2 plus the number of solemn period drama in Taylor Movie Festival. The number of futuristic sci-fi movie in Northwood Movie Festival equals 3. The number of calm road movie in Northwood Movie Festival equals 3. The number of calm road movie in Verdi Movie Festival equals 4 times the number of calm road movie in Taylor Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals the number of futuristic sci-fi movie in Taylor Movie Festival. The number of futuristic sci-fi movie in Golden Banana Movie Festival equals the number of intense detective thriller in Golden Banana Movie Festival. The number of calm road movie in Taylor Movie Festival equals 3.

Question: How many solemn period drama does Northwood Movie Festival have?

Solution: Define solemn period drama in Taylor Movie Festival as L; so L = 4. Define futuristic sci-fi movie in Taylor Movie Festival as O; l = L = 4; so O = 2 + l = 2 + 4 = 6. Define calm road movie in Golden Banana Movie Festival as K; so K = O = 6. Define intense detective thriller in Golden Banana Movie Festival as G; so G = O = 6. Define futuristic sci-fi movie in Golden Banana Movie Festival as n; so n = G = 6. Define solemn period drama in Golden Banana Movie Festival as d; so d = K + G = 6 + 6 = 12. Define total number of movies in Golden Banana Movie Festival as v; H = K + n = 6 + 6 = 12; M = H + G = 12 + 6 = 18; so v = M + d = 18 + 12 = 30. Define intense detective thriller in Taylor Movie Festival as W; so W = v = 30. Define solemn period drama in Northwood Movie Festival as o; C = W = 30; so o = 4 * C = 4 * 30 = 120. Answer: 120.


The number of futuristic sci-fi movie in Festival Lumière de Valmont equals 4. The number of calm road movie in Rêves de Belleville equals the total number of movies in Festival Lumière de Valmont. The number of upbeat metropolis comedy in Festival Lumière de Valmont equals the number of upbeat metropolis comedy in Festival de Saint-Rivage. The number of upbeat metropolis comedy in Cinéma de Montreval equals the number of solemn period drama in Cinéma de Montreval. The number of solemn period drama in Rêves de Belleville equals 2. The number of solemn period drama in Festival Lumière de Valmont equals 1 plus the total number of movies in Festival de Saint-Rivage. The number of upbeat metropolis comedy in Rêves de Belleville equals 2. The number of solemn period drama in Cinéma de Montreval equals 4. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals 2 plus the total number of movies in Cinéma de Montreval. The number of intense detective thriller in Festival de Clairmont equals 1. The number of calm road movie in Festival de Clairmont equals the total number of movies in Cinéma de Montreval.

Question: How many calm road movie does Rêves de Belleville have?

Solution: Define solemn period drama in Cinéma de Montreval as I; so I = 4. Define upbeat metropolis comedy in Cinéma de Montreval as O; so O = I = 4. Define total number of movies in Cinéma de Montreval as C; so C = O + I = 4 + 4 = 8. Define upbeat metropolis comedy in Festival de Saint-Rivage as w; k = C = 8; so w = 2 + k = 2 + 8 = 10. Define total number of movies in Festival de Saint-Rivage as G; so G = w = 10. Define solemn period drama in Festival Lumière de Valmont as U; W = G = 10; so U = 1 + W = 1 + 10 = 11. Define upbeat metropolis comedy in Festival Lumière de Valmont as R; so R = w = 10. Define futuristic sci-fi movie in Festival Lumière de Valmont as i; so i = 4. Define total number of movies in Festival Lumière de Valmont as p; Z = R + i = 10 + 4 = 14; so p = Z + U = 14 + 11 = 25. Define calm road movie in Rêves de Belleville as D; so D = p = 25. Answer: 25.


The number of private middle school in Oakbridge City equals the sum of the number of public highschool in Riverton City and the number of private middle school in Riverton City. The number of public highschool in Ruby Bay equals 1 plus the difference between the number of private middle school in Ruby Bay and the number of public highschool in Oakbridge City. The number of private middle school in Riverton City equals 3. The number of private middle school in Ruby Bay equals the sum of the total number of schools in Oakbridge City, the number of private middle school in Oakbridge City, and the number of private middle school in Riverton City. The number of public highschool in Riverton City equals 2 times the number of private middle school in Riverton City. The number of public highschool in Oakbridge City equals 3 times the number of private middle school in Riverton City.

Question: How many public highschool does Ruby Bay have?

Solution: Define private middle school in Riverton City as G; so G = 3. Define public highschool in Oakbridge City as I; c = G = 3; so I = 3 * c = 3 * 3 = 9. Define public highschool in Riverton City as X; i = G = 3; so X = 2 * i = 2 * 3 = 6. Define private middle school in Oakbridge City as p; so p = X + G = 6 + 3 = 9. Define total number of schools in Oakbridge City as t; so t = p + I = 9 + 9 = 18. Define private middle school in Ruby Bay as h; B = t + p = 18 + 9 = 27; so h = B + G = 27 + 3 = 30. Define public highschool in Ruby Bay as A; g = h - I = 30 - 9 = 21; so A = 1 + g = 1 + 21 = 22. Answer: 22.


The number of upbeat metropolis comedy in Rêves de Belleville equals 3 times the sum of the number of upbeat metropolis comedy in Festival Lumière de Valmont, the number of intense detective thriller in Festival Lumière de Valmont, and the number of calm road movie in Cinéma de Montreval. The number of solemn period drama in Cinéma de Montreval equals the total number of movies in Rêves de Belleville. The number of futuristic sci-fi movie in Festival de Clairmont equals 3 times the number of solemn period drama in Cinéma de Montreval. The number of calm road movie in Cinéma de Montreval equals 3 times the number of intense detective thriller in Festival Lumière de Valmont. The number of intense detective thriller in Festival Lumière de Valmont equals 4. The number of upbeat metropolis comedy in Festival Lumière de Valmont equals 2 plus the sum of the number of calm road movie in Cinéma de Montreval and the number of intense detective thriller in Festival Lumière de Valmont.

Question: What is the total number of movies in Festival de Clairmont?

Solution: Define intense detective thriller in Festival Lumière de Valmont as I; so I = 4. Define calm road movie in Cinéma de Montreval as i; J = I = 4; so i = 3 * J = 3 * 4 = 12. Define upbeat metropolis comedy in Festival Lumière de Valmont as l; v = i + I = 12 + 4 = 16; so l = 2 + v = 2 + 16 = 18. Define upbeat metropolis comedy in Rêves de Belleville as L; W = l + I = 18 + 4 = 22; O = W + i = 22 + 12 = 34; so L = 3 * O = 3 * 34 = 102. Define total number of movies in Rêves de Belleville as R; so R = L = 102. Define solemn period drama in Cinéma de Montreval as V; so V = R = 102. Define futuristic sci-fi movie in Festival de Clairmont as G; H = V = 102; so G = 3 * H = 3 * 102 = 306. Define total number of movies in Festival de Clairmont as P; so P = G = 306. Answer: 306.