The number of public highschool in Brightford equals 2 plus the total number of schools in Westhaven City. The number of regional medical school in Brightford equals 2 plus the number of public highschool in Brightford. The number of regional medical school in Westhaven City equals 2. The number of public highschool in Westhaven City equals 1.

Question: What is the total number of schools in Brightford?

Solution: Define public highschool in Westhaven City as y; so y = 1. Define regional medical school in Westhaven City as s; so s = 2. Define total number of schools in Westhaven City as W; so W = s + y = 2 + 1 = 3. Define public highschool in Brightford as l; h = W = 3; so l = 2 + h = 2 + 3 = 5. Define regional medical school in Brightford as q; V = l = 5; so q = 2 + V = 2 + 5 = 7. Define total number of schools in Brightford as R; so R = q + l = 7 + 5 = 12. Answer: 12.


The number of upbeat metropolis comedy in Cinéma de Montreval equals the sum of the number of intense detective thriller in Festival de Saint-Rivage and the number of intense detective thriller in Cinéma de Montreval. The number of intense detective thriller in Cinéma de Montreval equals the number of intense detective thriller in Festival de Saint-Rivage. The number of intense detective thriller in Festival de Saint-Rivage equals 3. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals 4. The number of futuristic sci-fi movie in Festival Lumière de Valmont equals the number of upbeat metropolis comedy in Cinéma de Montreval. The number of upbeat metropolis comedy in Festival Lumière de Valmont equals the sum of the number of intense detective thriller in Festival de Saint-Rivage and the number of futuristic sci-fi movie in Festival de Saint-Rivage. The number of intense detective thriller in Festival Lumière de Valmont equals 2. The number of futuristic sci-fi movie in Cinéma de Montreval equals 4 plus the difference between the number of intense detective thriller in Cinéma de Montreval and the number of upbeat metropolis comedy in Cinéma de Montreval. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals the number of intense detective thriller in Festival de Saint-Rivage.

Question: What is the total number of movies in Cinéma de Montreval?

Solution: Define intense detective thriller in Festival de Saint-Rivage as O; so O = 3. Define intense detective thriller in Cinéma de Montreval as K; so K = O = 3. Define upbeat metropolis comedy in Cinéma de Montreval as i; so i = O + K = 3 + 3 = 6. Define futuristic sci-fi movie in Cinéma de Montreval as F; v = K - i = 3 - 6 = -3; so F = 4 + v = 4 + -3 = 1. Define total number of movies in Cinéma de Montreval as G; I = K + i = 3 + 6 = 9; so G = I + F = 9 + 1 = 10. Answer: 10.


The number of adult bear in Maple Creek equals 4 times the total number of adult animals in Oakridge Riverside. The number of adult wolf in Oakridge Riverside equals 3 times the number of adult fox in Oakridge Riverside. The number of adult bear in Oakridge Riverside equals 2. The number of adult fox in Oakridge Riverside equals 3.

Question: What is the total number of adult animals in Maple Creek?

Solution: Define adult fox in Oakridge Riverside as v; so v = 3. Define adult bear in Oakridge Riverside as d; so d = 2. Define adult wolf in Oakridge Riverside as E; S = v = 3; so E = 3 * S = 3 * 3 = 9. Define total number of adult animals in Oakridge Riverside as H; Q = v + d = 3 + 2 = 5; so H = Q + E = 5 + 9 = 14. Define adult bear in Maple Creek as R; o = H = 14; so R = 4 * o = 4 * 14 = 56. Define total number of adult animals in Maple Creek as h; so h = R = 56. Answer: 56.


The number of public highschool in Glenfield City equals 2 times the total number of schools in Hawkesbury. The number of elementary school in Hawkesbury equals 4. The number of public highschool in Hawkesbury equals 3 plus the number of elementary school in Hawkesbury. The number of elementary school in Glenfield City equals the total number of schools in Hawkesbury.

Question: What is the total number of schools in Glenfield City?

Solution: Define elementary school in Hawkesbury as T; so T = 4. Define public highschool in Hawkesbury as f; V = T = 4; so f = 3 + V = 3 + 4 = 7. Define total number of schools in Hawkesbury as t; so t = T + f = 4 + 7 = 11. Define public highschool in Glenfield City as d; B = t = 11; so d = 2 * B = 2 * 11 = 22. Define elementary school in Glenfield City as e; so e = t = 11. Define total number of schools in Glenfield City as q; so q = e + d = 11 + 22 = 33. Answer: 33.


The number of intense detective thriller in Taylor Movie Festival equals 3. The number of calm road movie in Verdi Movie Festival equals 3 plus the sum of the total number of movies in Golden Banana Movie Festival and the number of intense detective thriller in Taylor Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals 4 times the sum of the total number of movies in Taylor Movie Festival and the number of intense detective thriller in Taylor Movie Festival.

Question: What is the total number of movies in Verdi Movie Festival?

Solution: Define intense detective thriller in Taylor Movie Festival as R; so R = 3. Define total number of movies in Taylor Movie Festival as O; so O = R = 3. Define calm road movie in Golden Banana Movie Festival as p; S = O + R = 3 + 3 = 6; so p = 4 * S = 4 * 6 = 24. Define total number of movies in Golden Banana Movie Festival as v; so v = p = 24. Define calm road movie in Verdi Movie Festival as a; C = v + R = 24 + 3 = 27; so a = 3 + C = 3 + 27 = 30. Define total number of movies in Verdi Movie Festival as Y; so Y = a = 30. Answer: 30.


The number of adult bear in Bundle Ranch equals the total number of adult animals in Mayer Aquarium. The number of adult bear in Mayer Aquarium equals the number of adult wolf in Mayer Aquarium. The number of adult wolf in Mayer Aquarium equals 3. The number of adult wolf in Bundle Ranch equals 3 times the difference between the total number of adult animals in Mayer Aquarium and the number of adult bear in Mayer Aquarium.

Question: What is the total number of adult animals in Bundle Ranch?

Solution: Define adult wolf in Mayer Aquarium as S; so S = 3. Define adult bear in Mayer Aquarium as y; so y = S = 3. Define total number of adult animals in Mayer Aquarium as q; so q = S + y = 3 + 3 = 6. Define adult wolf in Bundle Ranch as H; Y = q - y = 6 - 3 = 3; so H = 3 * Y = 3 * 3 = 9. Define adult bear in Bundle Ranch as L; so L = q = 6. Define total number of adult animals in Bundle Ranch as R; so R = H + L = 9 + 6 = 15. Answer: 15.


The number of adult wolf in Cedar Valley equals 1 plus the sum of the total number of adult animals in Maple Creek and the number of adult deer in Maple Creek. The number of adult deer in Cedar Valley equals 4. The number of adult deer in Maple Creek equals the number of adult wolf in Maple Creek. The number of adult wolf in Maple Creek equals 4.

Question: What is the total number of adult animals in Cedar Valley?

Solution: Define adult wolf in Maple Creek as r; so r = 4. Define adult deer in Maple Creek as G; so G = r = 4. Define total number of adult animals in Maple Creek as g; so g = G + r = 4 + 4 = 8. Define adult wolf in Cedar Valley as F; x = g + G = 8 + 4 = 12; so F = 1 + x = 1 + 12 = 13. Define adult deer in Cedar Valley as X; so X = 4. Define total number of adult animals in Cedar Valley as y; so y = X + F = 4 + 13 = 17. Answer: 17.


The number of adult bear in Oakridge Riverside equals 2. The number of adult deer in Cedar Valley equals 4. The number of adult bear in Cedar Valley equals the number of adult deer in Oakridge Riverside. The number of adult deer in Maple Creek equals 3. The number of adult deer in Oakridge Riverside equals 1 plus the number of adult bear in Oakridge Riverside. The number of adult deer in Pine Ridge equals 4 times the sum of the total number of adult animals in Oakridge Riverside, the number of adult bear in Oakridge Riverside, and the number of adult deer in Oakridge Riverside.

Question: What is the total number of adult animals in Pine Ridge?

Solution: Define adult bear in Oakridge Riverside as P; so P = 2. Define adult deer in Oakridge Riverside as X; v = P = 2; so X = 1 + v = 1 + 2 = 3. Define total number of adult animals in Oakridge Riverside as m; so m = X + P = 3 + 2 = 5. Define adult deer in Pine Ridge as y; d = m + P = 5 + 2 = 7; l = d + X = 7 + 3 = 10; so y = 4 * l = 4 * 10 = 40. Define total number of adult animals in Pine Ridge as V; so V = y = 40. Answer: 40.


The number of adult racoon in South Zoo equals 4. The number of adult deer in Mayer Aquarium equals 3 times the sum of the number of adult fox in Mayer Aquarium and the number of adult racoon in South Zoo. The number of adult fox in Mayer Aquarium equals the number of adult racoon in South Zoo. The number of adult fox in Jefferson Circus equals 4 plus the sum of the number of adult deer in Mayer Aquarium, the number of adult racoon in South Zoo, and the number of adult fox in Mayer Aquarium.

Question: What is the total number of adult animals in Jefferson Circus?

Solution: Define adult racoon in South Zoo as H; so H = 4. Define adult fox in Mayer Aquarium as w; so w = H = 4. Define adult deer in Mayer Aquarium as K; g = w + H = 4 + 4 = 8; so K = 3 * g = 3 * 8 = 24. Define adult fox in Jefferson Circus as v; t = K + H = 24 + 4 = 28; S = t + w = 28 + 4 = 32; so v = 4 + S = 4 + 32 = 36. Define total number of adult animals in Jefferson Circus as s; so s = v = 36. Answer: 36.


The number of private middle school in Glenfield City equals 3. The number of public highschool in Glenfield City equals 1. The number of public highschool in Hawkesbury equals 4. The number of private middle school in Hawkesbury equals 2 plus the difference between the total number of schools in Glenfield City and the number of public highschool in Glenfield City.

Question: What is the total number of schools in Hawkesbury?

Solution: Define public highschool in Hawkesbury as O; so O = 4. Define public highschool in Glenfield City as B; so B = 1. Define private middle school in Glenfield City as l; so l = 3. Define total number of schools in Glenfield City as E; so E = B + l = 1 + 3 = 4. Define private middle school in Hawkesbury as n; F = E - B = 4 - 1 = 3; so n = 2 + F = 2 + 3 = 5. Define total number of schools in Hawkesbury as C; so C = O + n = 4 + 5 = 9. Answer: 9.


The number of intense detective thriller in Festival de Saint-Rivage equals 2 times the sum of the total number of movies in Rêves de Belleville and the number of intense detective thriller in Rêves de Belleville. The number of intense detective thriller in Rêves de Belleville equals 2. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals the sum of the number of intense detective thriller in Festival de Saint-Rivage, the number of intense detective thriller in Rêves de Belleville, and the total number of movies in Rêves de Belleville.

Question: What is the total number of movies in Festival de Saint-Rivage?

Solution: Define intense detective thriller in Rêves de Belleville as C; so C = 2. Define total number of movies in Rêves de Belleville as c; so c = C = 2. Define intense detective thriller in Festival de Saint-Rivage as I; L = c + C = 2 + 2 = 4; so I = 2 * L = 2 * 4 = 8. Define futuristic sci-fi movie in Festival de Saint-Rivage as x; t = I + C = 8 + 2 = 10; so x = t + c = 10 + 2 = 12. Define total number of movies in Festival de Saint-Rivage as w; so w = I + x = 8 + 12 = 20. Answer: 20.


The number of adult owl in Oakridge Riverside equals 3 plus the number of adult parrot in Oakridge Riverside. The number of adult parrot in Oakridge Riverside equals 2. The number of adult parrot in Beverly Forest equals the number of adult owl in Beverly Forest. The number of adult owl in Beverly Forest equals 2 plus the total number of adult animals in Oakridge Riverside.

Question: What is the total number of adult animals in Beverly Forest?

Solution: Define adult parrot in Oakridge Riverside as u; so u = 2. Define adult owl in Oakridge Riverside as F; y = u = 2; so F = 3 + y = 3 + 2 = 5. Define total number of adult animals in Oakridge Riverside as j; so j = F + u = 5 + 2 = 7. Define adult owl in Beverly Forest as M; O = j = 7; so M = 2 + O = 2 + 7 = 9. Define adult parrot in Beverly Forest as o; so o = M = 9. Define total number of adult animals in Beverly Forest as p; so p = M + o = 9 + 9 = 18. Answer: 18.


The number of public highschool in Hawkesbury equals 2. The number of public highschool in Evervale City equals 2. The number of private middle school in Westhaven City equals the number of public highschool in Evervale City. The number of public highschool in Westhaven City equals 3 times the sum of the total number of schools in Evervale City and the number of public highschool in Evervale City. The number of culinarian school in Westhaven City equals the total number of schools in Evervale City.

Question: What is the total number of schools in Westhaven City?

Solution: Define public highschool in Evervale City as G; so G = 2. Define total number of schools in Evervale City as m; so m = G = 2. Define public highschool in Westhaven City as a; f = m + G = 2 + 2 = 4; so a = 3 * f = 3 * 4 = 12. Define private middle school in Westhaven City as K; so K = G = 2. Define culinarian school in Westhaven City as z; so z = m = 2. Define total number of schools in Westhaven City as A; W = z + a = 2 + 12 = 14; so A = W + K = 14 + 2 = 16. Answer: 16.