The number of adult fox in Mayer Aquarium equals 3. The number of adult wolf in Bundle Ranch equals 4 plus the number of adult fox in Mayer Aquarium. The number of adult wolf in Mayer Aquarium equals the sum of the number of adult wolf in Bundle Ranch and the number of adult fox in Mayer Aquarium. The number of adult fox in Bundle Ranch equals the total number of adult animals in Mayer Aquarium.

Question: What is the total number of adult animals in Bundle Ranch?

Solution: Define adult fox in Mayer Aquarium as T; so T = 3. Define adult wolf in Bundle Ranch as y; D = T = 3; so y = 4 + D = 4 + 3 = 7. Define adult wolf in Mayer Aquarium as O; so O = y + T = 7 + 3 = 10. Define total number of adult animals in Mayer Aquarium as o; so o = O + T = 10 + 3 = 13. Define adult fox in Bundle Ranch as K; so K = o = 13. Define total number of adult animals in Bundle Ranch as Z; so Z = y + K = 7 + 13 = 20. Answer: 20.


The number of futuristic sci-fi movie in Festival Lumière de Valmont equals 2 times the number of solemn period drama in Festival Lumière de Valmont. The number of upbeat metropolis comedy in Cinéma de Montreval equals 1 plus the difference between the number of calm road movie in Festival de Saint-Rivage and the number of solemn period drama in Rêves de Belleville. The number of futuristic sci-fi movie in Cinéma de Montreval equals the number of solemn period drama in Cinéma de Montreval. The number of calm road movie in Cinéma de Montreval equals the total number of movies in Rêves de Belleville. The number of solemn period drama in Festival Lumière de Valmont equals 1. The number of upbeat metropolis comedy in Festival Lumière de Valmont equals the number of solemn period drama in Cinéma de Montreval. The number of upbeat metropolis comedy in Rêves de Belleville equals 2 plus the number of futuristic sci-fi movie in Cinéma de Montreval. The number of calm road movie in Festival de Saint-Rivage equals the number of calm road movie in Cinéma de Montreval. The number of solemn period drama in Cinéma de Montreval equals 4. The number of solemn period drama in Rêves de Belleville equals the number of futuristic sci-fi movie in Cinéma de Montreval.

Question: What is the total number of movies in Festival de Saint-Rivage?

Solution: Define solemn period drama in Cinéma de Montreval as E; so E = 4. Define futuristic sci-fi movie in Cinéma de Montreval as h; so h = E = 4. Define solemn period drama in Rêves de Belleville as j; so j = h = 4. Define upbeat metropolis comedy in Rêves de Belleville as U; l = h = 4; so U = 2 + l = 2 + 4 = 6. Define total number of movies in Rêves de Belleville as i; so i = U + j = 6 + 4 = 10. Define calm road movie in Cinéma de Montreval as e; so e = i = 10. Define calm road movie in Festival de Saint-Rivage as y; so y = e = 10. Define total number of movies in Festival de Saint-Rivage as g; so g = y = 10. Answer: 10.


The number of adult racoon in Bundle Ranch equals 4. The number of adult bear in Hamilton Farm equals 2 times the difference between the number of adult deer in Hamilton Farm and the total number of adult animals in Bundle Ranch. The number of adult deer in Hamilton Farm equals 4 plus the sum of the total number of adult animals in Bundle Ranch and the number of adult racoon in Bundle Ranch.

Question: What is the total number of adult animals in Hamilton Farm?

Solution: Define adult racoon in Bundle Ranch as x; so x = 4. Define total number of adult animals in Bundle Ranch as h; so h = x = 4. Define adult deer in Hamilton Farm as k; X = h + x = 4 + 4 = 8; so k = 4 + X = 4 + 8 = 12. Define adult bear in Hamilton Farm as Q; L = k - h = 12 - 4 = 8; so Q = 2 * L = 2 * 8 = 16. Define total number of adult animals in Hamilton Farm as G; so G = Q + k = 16 + 12 = 28. Answer: 28.


The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 4 times the difference between the total number of movies in Taylor Movie Festival and the number of futuristic sci-fi movie in Taylor Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals 1 plus the sum of the number of solemn period drama in Taylor Movie Festival and the total number of movies in Taylor Movie Festival. The number of solemn period drama in Taylor Movie Festival equals 1 plus the difference between the number of futuristic sci-fi movie in Golden Banana Movie Festival and the number of futuristic sci-fi movie in Taylor Movie Festival. The number of futuristic sci-fi movie in Golden Banana Movie Festival equals 2. The number of futuristic sci-fi movie in Taylor Movie Festival equals the number of futuristic sci-fi movie in Golden Banana Movie Festival.

Question: How many upbeat metropolis comedy does Golden Banana Movie Festival have?

Solution: Define futuristic sci-fi movie in Golden Banana Movie Festival as W; so W = 2. Define futuristic sci-fi movie in Taylor Movie Festival as A; so A = W = 2. Define solemn period drama in Taylor Movie Festival as f; Y = W - A = 2 - 2 = 0; so f = 1 + Y = 1 + 0 = 1. Define total number of movies in Taylor Movie Festival as i; so i = A + f = 2 + 1 = 3. Define upbeat metropolis comedy in Golden Banana Movie Festival as w; J = i - A = 3 - 2 = 1; so w = 4 * J = 4 * 1 = 4. Answer: 4.


The number of intense detective thriller in Festival de Clairmont equals 3. The number of intense detective thriller in Cinéma de Montreval equals 1 plus the difference between the number of futuristic sci-fi movie in Cinéma de Montreval and the number of calm road movie in Festival de Clairmont. The number of calm road movie in Cinéma de Montreval equals the number of intense detective thriller in Cinéma de Montreval. The number of futuristic sci-fi movie in Cinéma de Montreval equals the number of calm road movie in Festival de Clairmont. The number of intense detective thriller in Festival Lumière de Valmont equals the total number of movies in Cinéma de Montreval. The number of calm road movie in Festival de Clairmont equals 3. The number of calm road movie in Festival Lumière de Valmont equals 2.

Question: How many intense detective thriller does Festival Lumière de Valmont have?

Solution: Define calm road movie in Festival de Clairmont as J; so J = 3. Define futuristic sci-fi movie in Cinéma de Montreval as l; so l = J = 3. Define intense detective thriller in Cinéma de Montreval as a; L = l - J = 3 - 3 = 0; so a = 1 + L = 1 + 0 = 1. Define calm road movie in Cinéma de Montreval as D; so D = a = 1. Define total number of movies in Cinéma de Montreval as U; f = a + l = 1 + 3 = 4; so U = f + D = 4 + 1 = 5. Define intense detective thriller in Festival Lumière de Valmont as M; so M = U = 5. Answer: 5.


The number of adult wolf in Cedar Valley equals 1 plus the number of adult deer in Cedar Valley. The number of adult wolf in Oakridge Riverside equals 2 times the sum of the total number of adult animals in Cedar Valley, the number of adult deer in Cedar Valley, and the number of adult wolf in Cedar Valley. The number of adult deer in Cedar Valley equals 3.

Question: What is the total number of adult animals in Oakridge Riverside?

Solution: Define adult deer in Cedar Valley as N; so N = 3. Define adult wolf in Cedar Valley as Y; D = N = 3; so Y = 1 + D = 1 + 3 = 4. Define total number of adult animals in Cedar Valley as k; so k = Y + N = 4 + 3 = 7. Define adult wolf in Oakridge Riverside as u; e = k + N = 7 + 3 = 10; S = e + Y = 10 + 4 = 14; so u = 2 * S = 2 * 14 = 28. Define total number of adult animals in Oakridge Riverside as v; so v = u = 28. Answer: 28.


The number of elementary school in Ruby Bay equals 1 plus the difference between the total number of schools in Clearwater Bay and the number of private middle school in Clearwater Bay. The number of private middle school in Ruby Bay equals the sum of the total number of schools in Clearwater Bay, the number of elementary school in Ruby Bay, and the number of private middle school in Clearwater Bay. The number of private middle school in Clearwater Bay equals 3.

Question: What is the total number of schools in Ruby Bay?

Solution: Define private middle school in Clearwater Bay as j; so j = 3. Define total number of schools in Clearwater Bay as a; so a = j = 3. Define elementary school in Ruby Bay as r; J = a - j = 3 - 3 = 0; so r = 1 + J = 1 + 0 = 1. Define private middle school in Ruby Bay as z; f = a + r = 3 + 1 = 4; so z = f + j = 4 + 3 = 7. Define total number of schools in Ruby Bay as S; so S = z + r = 7 + 1 = 8. Answer: 8.


The number of elementary school in Evervale City equals 1. The number of regional medical school in Evervale City equals the number of elementary school in Evervale City. The number of elementary school in Hawkesbury equals the total number of schools in Evervale City. The number of regional medical school in Hawkesbury equals the sum of the number of elementary school in Evervale City, the number of elementary school in Hawkesbury, and the total number of schools in Evervale City.

Question: What is the total number of schools in Hawkesbury?

Solution: Define elementary school in Evervale City as m; so m = 1. Define regional medical school in Evervale City as H; so H = m = 1. Define total number of schools in Evervale City as z; so z = H + m = 1 + 1 = 2. Define elementary school in Hawkesbury as M; so M = z = 2. Define regional medical school in Hawkesbury as V; J = m + M = 1 + 2 = 3; so V = J + z = 3 + 2 = 5. Define total number of schools in Hawkesbury as W; so W = V + M = 5 + 2 = 7. Answer: 7.


The number of elementary school in Clearwater Bay equals 2. The number of public highschool in Clearwater Bay equals the sum of the number of elementary school in Clearwater Bay and the number of culinarian school in Clearwater Bay. The number of regional medical school in Riverton City equals the difference between the total number of schools in Clearwater Bay and the number of elementary school in Clearwater Bay. The number of culinarian school in Clearwater Bay equals the number of elementary school in Clearwater Bay.

Question: What is the total number of schools in Riverton City?

Solution: Define elementary school in Clearwater Bay as R; so R = 2. Define culinarian school in Clearwater Bay as Q; so Q = R = 2. Define public highschool in Clearwater Bay as W; so W = R + Q = 2 + 2 = 4. Define total number of schools in Clearwater Bay as o; E = Q + R = 2 + 2 = 4; so o = E + W = 4 + 4 = 8. Define regional medical school in Riverton City as Z; so Z = o - R = 8 - 2 = 6. Define total number of schools in Riverton City as F; so F = Z = 6. Answer: 6.


The number of upbeat metropolis comedy in Cinéma de Montreval equals 3. The number of solemn period drama in Festival Lumière de Valmont equals the sum of the number of solemn period drama in Cinéma de Montreval, the number of upbeat metropolis comedy in Cinéma de Montreval, and the total number of movies in Cinéma de Montreval. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals the number of upbeat metropolis comedy in Rêves de Belleville. The number of upbeat metropolis comedy in Festival Lumière de Valmont equals the total number of movies in Cinéma de Montreval. The number of solemn period drama in Cinéma de Montreval equals the number of upbeat metropolis comedy in Cinéma de Montreval. The number of solemn period drama in Rêves de Belleville equals 3. The number of upbeat metropolis comedy in Rêves de Belleville equals 4 times the number of solemn period drama in Rêves de Belleville. The number of solemn period drama in Festival de Saint-Rivage equals the difference between the number of upbeat metropolis comedy in Rêves de Belleville and the number of solemn period drama in Rêves de Belleville.

Question: What is the total number of movies in Festival Lumière de Valmont?

Solution: Define upbeat metropolis comedy in Cinéma de Montreval as M; so M = 3. Define solemn period drama in Cinéma de Montreval as y; so y = M = 3. Define total number of movies in Cinéma de Montreval as h; so h = y + M = 3 + 3 = 6. Define upbeat metropolis comedy in Festival Lumière de Valmont as F; so F = h = 6. Define solemn period drama in Festival Lumière de Valmont as l; m = y + M = 3 + 3 = 6; so l = m + h = 6 + 6 = 12. Define total number of movies in Festival Lumière de Valmont as p; so p = l + F = 12 + 6 = 18. Answer: 18.


The number of adult racoon in Hamilton Farm equals the number of adult wolf in Hamilton Farm. The number of adult racoon in Mayer Aquarium equals 2. The number of adult wolf in Mayer Aquarium equals the sum of the total number of adult animals in Hamilton Farm, the number of adult wolf in Hamilton Farm, and the number of adult racoon in Mayer Aquarium. The number of adult wolf in Hamilton Farm equals 1.

Question: What is the total number of adult animals in Mayer Aquarium?

Solution: Define adult racoon in Mayer Aquarium as b; so b = 2. Define adult wolf in Hamilton Farm as s; so s = 1. Define adult racoon in Hamilton Farm as D; so D = s = 1. Define total number of adult animals in Hamilton Farm as r; so r = s + D = 1 + 1 = 2. Define adult wolf in Mayer Aquarium as K; C = r + s = 2 + 1 = 3; so K = C + b = 3 + 2 = 5. Define total number of adult animals in Mayer Aquarium as X; so X = K + b = 5 + 2 = 7. Answer: 7.


The number of adult deer in Jefferson Circus equals 1. The number of adult racoon in Mayer Aquarium equals 2 times the sum of the number of adult deer in Jefferson Circus and the total number of adult animals in Jefferson Circus. The number of adult deer in Mayer Aquarium equals 4 plus the sum of the total number of adult animals in Jefferson Circus and the number of adult deer in Jefferson Circus.

Question: What is the total number of adult animals in Mayer Aquarium?

Solution: Define adult deer in Jefferson Circus as O; so O = 1. Define total number of adult animals in Jefferson Circus as a; so a = O = 1. Define adult racoon in Mayer Aquarium as T; Z = O + a = 1 + 1 = 2; so T = 2 * Z = 2 * 2 = 4. Define adult deer in Mayer Aquarium as w; U = a + O = 1 + 1 = 2; so w = 4 + U = 4 + 2 = 6. Define total number of adult animals in Mayer Aquarium as c; so c = w + T = 6 + 4 = 10. Answer: 10.


The number of adult blue jay in Cedar Valley equals the total number of adult animals in Oakridge Riverside. The number of adult eagle in Oakridge Riverside equals 3. The number of adult blue jay in Oakridge Riverside equals 2 plus the number of adult eagle in Oakridge Riverside. The number of adult eagle in Cedar Valley equals 2 plus the number of adult eagle in Oakridge Riverside.

Question: What is the total number of adult animals in Cedar Valley?

Solution: Define adult eagle in Oakridge Riverside as u; so u = 3. Define adult blue jay in Oakridge Riverside as C; g = u = 3; so C = 2 + g = 2 + 3 = 5. Define adult eagle in Cedar Valley as x; v = u = 3; so x = 2 + v = 2 + 3 = 5. Define total number of adult animals in Oakridge Riverside as e; so e = C + u = 5 + 3 = 8. Define adult blue jay in Cedar Valley as D; so D = e = 8. Define total number of adult animals in Cedar Valley as M; so M = D + x = 8 + 5 = 13. Answer: 13.


The number of adult bear in Maple Creek equals the number of adult fox in Maple Creek. The number of adult fox in Beverly Forest equals 2. The number of adult deer in Beverly Forest equals the number of adult fox in Beverly Forest. The number of adult deer in Pine Ridge equals the sum of the number of adult racoon in Oakridge Riverside, the total number of adult animals in Oakridge Riverside, the number of adult racoon in Maple Creek, and the number of adult fox in Maple Creek. The number of adult racoon in Pine Ridge equals 1. The number of adult deer in Oakridge Riverside equals 2 plus the sum of the total number of adult animals in Maple Creek and the number of adult fox in Maple Creek. The number of adult bear in Beverly Forest equals the sum of the number of adult bear in Maple Creek and the number of adult fox in Maple Creek. The number of adult racoon in Maple Creek equals 3 times the number of adult fox in Maple Creek. The number of adult bear in Pine Ridge equals the total number of adult animals in Pine Ridge. The number of adult fox in Maple Creek equals 3. The number of adult bear in Oakridge Riverside equals 2. The number of adult racoon in Oakridge Riverside equals the number of adult bear in Maple Creek. The number of adult fox in Pine Ridge equals 3 times the number of adult fox in Beverly Forest.

Question: How many adult deer does Oakridge Riverside have?

Solution: Define adult fox in Maple Creek as l; so l = 3. Define adult racoon in Maple Creek as q; O = l = 3; so q = 3 * O = 3 * 3 = 9. Define adult bear in Maple Creek as A; so A = l = 3. Define total number of adult animals in Maple Creek as M; X = q + l = 9 + 3 = 12; so M = X + A = 12 + 3 = 15. Define adult deer in Oakridge Riverside as p; J = M + l = 15 + 3 = 18; so p = 2 + J = 2 + 18 = 20. Answer: 20.


The number of adult wolf in Cedar Valley equals the sum of the total number of adult animals in Pine Ridge, the total number of adult animals in Maple Creek, and the number of adult bear in Pine Ridge. The number of adult bear in Pine Ridge equals 4 plus the sum of the total number of adult animals in Maple Creek and the number of adult fox in Maple Creek. The number of adult fox in Maple Creek equals 4.

Question: What is the total number of adult animals in Cedar Valley?

Solution: Define adult fox in Maple Creek as m; so m = 4. Define total number of adult animals in Maple Creek as a; so a = m = 4. Define adult bear in Pine Ridge as r; P = a + m = 4 + 4 = 8; so r = 4 + P = 4 + 8 = 12. Define total number of adult animals in Pine Ridge as b; so b = r = 12. Define adult wolf in Cedar Valley as I; h = b + a = 12 + 4 = 16; so I = h + r = 16 + 12 = 28. Define total number of adult animals in Cedar Valley as G; so G = I = 28. Answer: 28.


The number of adult crow in Maple Creek equals 4. The number of adult owl in Pine Ridge equals 4 times the number of adult blue jay in Pine Ridge. The number of adult blue jay in Maple Creek equals 2 times the difference between the total number of adult animals in Pine Ridge and the number of adult crow in Beverly Forest. The number of adult owl in Maple Creek equals the number of adult crow in Maple Creek. The number of adult blue jay in Pine Ridge equals the total number of adult animals in Beverly Forest. The number of adult crow in Beverly Forest equals 1.

Question: How many adult blue jay does Maple Creek have?

Solution: Define adult crow in Beverly Forest as b; so b = 1. Define total number of adult animals in Beverly Forest as D; so D = b = 1. Define adult blue jay in Pine Ridge as W; so W = D = 1. Define adult owl in Pine Ridge as l; y = W = 1; so l = 4 * y = 4 * 1 = 4. Define total number of adult animals in Pine Ridge as s; so s = W + l = 1 + 4 = 5. Define adult blue jay in Maple Creek as Y; Q = s - b = 5 - 1 = 4; so Y = 2 * Q = 2 * 4 = 8. Answer: 8.


The number of futuristic sci-fi movie in Cinéma de Montreval equals the number of futuristic sci-fi movie in Festival Lumière de Valmont. The number of intense detective thriller in Festival Lumière de Valmont equals 2 times the number of futuristic sci-fi movie in Festival Lumière de Valmont. The number of intense detective thriller in Cinéma de Montreval equals the difference between the total number of movies in Festival Lumière de Valmont and the number of intense detective thriller in Festival Lumière de Valmont. The number of futuristic sci-fi movie in Festival Lumière de Valmont equals 2.

Question: What is the total number of movies in Cinéma de Montreval?

Solution: Define futuristic sci-fi movie in Festival Lumière de Valmont as j; so j = 2. Define intense detective thriller in Festival Lumière de Valmont as o; t = j = 2; so o = 2 * t = 2 * 2 = 4. Define total number of movies in Festival Lumière de Valmont as M; so M = o + j = 4 + 2 = 6. Define intense detective thriller in Cinéma de Montreval as B; so B = M - o = 6 - 4 = 2. Define futuristic sci-fi movie in Cinéma de Montreval as V; so V = j = 2. Define total number of movies in Cinéma de Montreval as l; so l = B + V = 2 + 2 = 4. Answer: 4.


The number of adult wolf in Oakridge Riverside equals 3. The number of adult deer in Oakridge Riverside equals the number of adult wolf in Oakridge Riverside. The number of adult wolf in Beverly Forest equals 3 plus the number of adult deer in Oakridge Riverside. The number of adult fox in Beverly Forest equals 2 times the total number of adult animals in Oakridge Riverside. The number of adult fox in Pine Ridge equals 4. The number of adult deer in Pine Ridge equals the number of adult wolf in Oakridge Riverside.

Question: What is the total number of adult animals in Beverly Forest?

Solution: Define adult wolf in Oakridge Riverside as N; so N = 3. Define adult deer in Oakridge Riverside as Y; so Y = N = 3. Define total number of adult animals in Oakridge Riverside as O; so O = N + Y = 3 + 3 = 6. Define adult fox in Beverly Forest as j; E = O = 6; so j = 2 * E = 2 * 6 = 12. Define adult wolf in Beverly Forest as w; H = Y = 3; so w = 3 + H = 3 + 3 = 6. Define total number of adult animals in Beverly Forest as P; so P = w + j = 6 + 12 = 18. Answer: 18.


The number of adult blue jay in Oakridge Riverside equals 3 times the difference between the number of adult blue jay in Cedar Valley and the number of adult owl in Cedar Valley. The number of adult parrot in Oakridge Riverside equals 4 times the sum of the number of adult parrot in Pine Ridge and the total number of adult animals in Pine Ridge. The number of adult owl in Cedar Valley equals the total number of adult animals in Maple Creek. The number of adult blue jay in Cedar Valley equals 3. The number of adult owl in Pine Ridge equals 3. The number of adult parrot in Pine Ridge equals the difference between the number of adult blue jay in Cedar Valley and the total number of adult animals in Cedar Valley. The number of adult owl in Maple Creek equals 4 plus the number of adult blue jay in Cedar Valley. The number of adult parrot in Maple Creek equals 1 plus the number of adult blue jay in Cedar Valley. The number of adult owl in Oakridge Riverside equals the number of adult parrot in Oakridge Riverside.

Question: What is the total number of adult animals in Cedar Valley?

Solution: Define adult blue jay in Cedar Valley as a; so a = 3. Define adult owl in Maple Creek as U; N = a = 3; so U = 4 + N = 4 + 3 = 7. Define adult parrot in Maple Creek as w; g = a = 3; so w = 1 + g = 1 + 3 = 4. Define total number of adult animals in Maple Creek as z; so z = w + U = 4 + 7 = 11. Define adult owl in Cedar Valley as Y; so Y = z = 11. Define total number of adult animals in Cedar Valley as o; so o = Y + a = 11 + 3 = 14. Answer: 14.


The number of public highschool in Riverton City equals 3. The number of private middle school in Shoreline City equals the total number of schools in Riverton City. The number of private middle school in Riverton City equals 4 times the number of public highschool in Riverton City. The number of public highschool in Shoreline City equals the sum of the number of private middle school in Shoreline City and the number of public highschool in Riverton City.

Question: What is the total number of schools in Shoreline City?

Solution: Define public highschool in Riverton City as c; so c = 3. Define private middle school in Riverton City as b; Y = c = 3; so b = 4 * Y = 4 * 3 = 12. Define total number of schools in Riverton City as G; so G = b + c = 12 + 3 = 15. Define private middle school in Shoreline City as k; so k = G = 15. Define public highschool in Shoreline City as u; so u = k + c = 15 + 3 = 18. Define total number of schools in Shoreline City as M; so M = k + u = 15 + 18 = 33. Answer: 33.


The number of adult blue jay in Maple Creek equals the number of adult eagle in Maple Creek. The number of adult eagle in Maple Creek equals 2 plus the number of adult crow in Oakridge Riverside. The number of adult eagle in Beverly Forest equals 1. The number of adult owl in Pine Ridge equals the total number of adult animals in Maple Creek. The number of adult owl in Oakridge Riverside equals 4 times the sum of the number of adult blue jay in Maple Creek, the total number of adult animals in Beverly Forest, and the number of adult owl in Pine Ridge. The number of adult blue jay in Beverly Forest equals 4. The number of adult crow in Beverly Forest equals 3. The number of adult eagle in Pine Ridge equals the number of adult owl in Pine Ridge. The number of adult crow in Oakridge Riverside equals 2. The number of adult blue jay in Oakridge Riverside equals the sum of the total number of adult animals in Pine Ridge, the number of adult eagle in Maple Creek, and the number of adult owl in Pine Ridge.

Question: What is the total number of adult animals in Pine Ridge?

Solution: Define adult crow in Oakridge Riverside as z; so z = 2. Define adult eagle in Maple Creek as v; I = z = 2; so v = 2 + I = 2 + 2 = 4. Define adult blue jay in Maple Creek as w; so w = v = 4. Define total number of adult animals in Maple Creek as E; so E = w + v = 4 + 4 = 8. Define adult owl in Pine Ridge as T; so T = E = 8. Define adult eagle in Pine Ridge as p; so p = T = 8. Define total number of adult animals in Pine Ridge as K; so K = T + p = 8 + 8 = 16. Answer: 16.


The number of elementary school in Hawkesbury equals 3 times the number of private middle school in Hawkesbury. The number of elementary school in Evervale City equals the number of private middle school in Evervale City. The number of private middle school in Hawkesbury equals 1. The number of private middle school in Evervale City equals 2 plus the total number of schools in Hawkesbury.

Question: What is the total number of schools in Evervale City?

Solution: Define private middle school in Hawkesbury as s; so s = 1. Define elementary school in Hawkesbury as P; o = s = 1; so P = 3 * o = 3 * 1 = 3. Define total number of schools in Hawkesbury as z; so z = s + P = 1 + 3 = 4. Define private middle school in Evervale City as t; h = z = 4; so t = 2 + h = 2 + 4 = 6. Define elementary school in Evervale City as w; so w = t = 6. Define total number of schools in Evervale City as S; so S = t + w = 6 + 6 = 12. Answer: 12.


The number of calm road movie in Golden Banana Movie Festival equals 4 times the total number of movies in Northwood Movie Festival. The number of calm road movie in Northwood Movie Festival equals the number of upbeat metropolis comedy in Golden Banana Movie Festival. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 4. The number of upbeat metropolis comedy in Northwood Movie Festival equals 1 plus the number of upbeat metropolis comedy in Golden Banana Movie Festival.

Question: What is the total number of movies in Golden Banana Movie Festival?

Solution: Define upbeat metropolis comedy in Golden Banana Movie Festival as O; so O = 4. Define calm road movie in Northwood Movie Festival as Y; so Y = O = 4. Define upbeat metropolis comedy in Northwood Movie Festival as i; v = O = 4; so i = 1 + v = 1 + 4 = 5. Define total number of movies in Northwood Movie Festival as x; so x = i + Y = 5 + 4 = 9. Define calm road movie in Golden Banana Movie Festival as m; A = x = 9; so m = 4 * A = 4 * 9 = 36. Define total number of movies in Golden Banana Movie Festival as K; so K = O + m = 4 + 36 = 40. Answer: 40.


The number of culinarian school in Shoreline City equals 4 plus the difference between the total number of schools in Clearwater Bay and the number of culinarian school in Clearwater Bay. The number of public highschool in Ruby Bay equals 3 times the sum of the total number of schools in Shoreline City and the number of culinarian school in Clearwater Bay. The number of culinarian school in Clearwater Bay equals 2.

Question: What is the total number of schools in Ruby Bay?

Solution: Define culinarian school in Clearwater Bay as A; so A = 2. Define total number of schools in Clearwater Bay as Z; so Z = A = 2. Define culinarian school in Shoreline City as b; o = Z - A = 2 - 2 = 0; so b = 4 + o = 4 + 0 = 4. Define total number of schools in Shoreline City as G; so G = b = 4. Define public highschool in Ruby Bay as V; r = G + A = 4 + 2 = 6; so V = 3 * r = 3 * 6 = 18. Define total number of schools in Ruby Bay as a; so a = V = 18. Answer: 18.


The number of futuristic sci-fi movie in Festival de Clairmont equals 2. The number of futuristic sci-fi movie in Cinéma de Montreval equals the number of futuristic sci-fi movie in Festival de Clairmont. The number of solemn period drama in Cinéma de Montreval equals 1 plus the number of futuristic sci-fi movie in Festival de Clairmont. The number of solemn period drama in Festival de Clairmont equals the sum of the total number of movies in Cinéma de Montreval, the number of solemn period drama in Cinéma de Montreval, the number of futuristic sci-fi movie in Cinéma de Montreval, and the number of futuristic sci-fi movie in Festival de Clairmont.

Question: How many solemn period drama does Festival de Clairmont have?

Solution: Define futuristic sci-fi movie in Festival de Clairmont as K; so K = 2. Define solemn period drama in Cinéma de Montreval as g; e = K = 2; so g = 1 + e = 1 + 2 = 3. Define futuristic sci-fi movie in Cinéma de Montreval as C; so C = K = 2. Define total number of movies in Cinéma de Montreval as h; so h = C + g = 2 + 3 = 5. Define solemn period drama in Festival de Clairmont as F; w = h + g = 5 + 3 = 8; U = w + C = 8 + 2 = 10; so F = U + K = 10 + 2 = 12. Answer: 12.


The number of adult bear in Mayer Aquarium equals 4 plus the sum of the total number of adult animals in Bundle Ranch, the number of adult wolf in Bundle Ranch, and the number of adult fox in Mayer Aquarium. The number of adult fox in Mayer Aquarium equals 2 plus the number of adult wolf in Bundle Ranch. The number of adult wolf in Bundle Ranch equals 4.

Question: What is the total number of adult animals in Mayer Aquarium?

Solution: Define adult wolf in Bundle Ranch as t; so t = 4. Define adult fox in Mayer Aquarium as k; z = t = 4; so k = 2 + z = 2 + 4 = 6. Define total number of adult animals in Bundle Ranch as u; so u = t = 4. Define adult bear in Mayer Aquarium as X; J = u + t = 4 + 4 = 8; r = J + k = 8 + 6 = 14; so X = 4 + r = 4 + 14 = 18. Define total number of adult animals in Mayer Aquarium as Q; so Q = k + X = 6 + 18 = 24. Answer: 24.


The number of adult crow in Hamilton Farm equals 4 times the sum of the total number of adult animals in Mayer Aquarium, the number of adult crow in Mayer Aquarium, and the number of adult eagle in Mayer Aquarium. The number of adult crow in Mayer Aquarium equals 4. The number of adult eagle in Mayer Aquarium equals 3 plus the number of adult crow in Mayer Aquarium.

Question: What is the total number of adult animals in Hamilton Farm?

Solution: Define adult crow in Mayer Aquarium as t; so t = 4. Define adult eagle in Mayer Aquarium as L; q = t = 4; so L = 3 + q = 3 + 4 = 7. Define total number of adult animals in Mayer Aquarium as h; so h = t + L = 4 + 7 = 11. Define adult crow in Hamilton Farm as F; w = h + t = 11 + 4 = 15; d = w + L = 15 + 7 = 22; so F = 4 * d = 4 * 22 = 88. Define total number of adult animals in Hamilton Farm as S; so S = F = 88. Answer: 88.


The number of public highschool in Riverton City equals 4. The number of private middle school in Oakbridge City equals 2 times the sum of the total number of schools in Riverton City, the number of public highschool in Riverton City, and the number of private middle school in Riverton City. The number of private middle school in Riverton City equals 3 plus the number of public highschool in Riverton City.

Question: What is the total number of schools in Oakbridge City?

Solution: Define public highschool in Riverton City as N; so N = 4. Define private middle school in Riverton City as l; R = N = 4; so l = 3 + R = 3 + 4 = 7. Define total number of schools in Riverton City as s; so s = N + l = 4 + 7 = 11. Define private middle school in Oakbridge City as m; h = s + N = 11 + 4 = 15; Y = h + l = 15 + 7 = 22; so m = 2 * Y = 2 * 22 = 44. Define total number of schools in Oakbridge City as a; so a = m = 44. Answer: 44.


The number of adult wolf in Pine Ridge equals 1. The number of adult wolf in Beverly Forest equals the number of adult bear in Beverly Forest. The number of adult bear in Pine Ridge equals 1 plus the number of adult wolf in Pine Ridge. The number of adult bear in Beverly Forest equals 2 times the total number of adult animals in Pine Ridge.

Question: What is the total number of adult animals in Beverly Forest?

Solution: Define adult wolf in Pine Ridge as H; so H = 1. Define adult bear in Pine Ridge as g; s = H = 1; so g = 1 + s = 1 + 1 = 2. Define total number of adult animals in Pine Ridge as L; so L = H + g = 1 + 2 = 3. Define adult bear in Beverly Forest as b; R = L = 3; so b = 2 * R = 2 * 3 = 6. Define adult wolf in Beverly Forest as l; so l = b = 6. Define total number of adult animals in Beverly Forest as K; so K = l + b = 6 + 6 = 12. Answer: 12.