The number of intense detective thriller in Rêves de Belleville equals 2. The number of calm road movie in Cinéma de Montreval equals the sum of the number of intense detective thriller in Festival de Saint-Rivage and the total number of movies in Rêves de Belleville. The number of solemn period drama in Festival de Saint-Rivage equals 3 times the total number of movies in Rêves de Belleville. The number of intense detective thriller in Festival de Saint-Rivage equals 2. The number of solemn period drama in Festival Lumière de Valmont equals 3 times the total number of movies in Festival de Saint-Rivage. The number of intense detective thriller in Festival Lumière de Valmont equals 4. The number of solemn period drama in Cinéma de Montreval equals the total number of movies in Festival Lumière de Valmont. The number of futuristic sci-fi movie in Festival Lumière de Valmont equals 3 times the number of intense detective thriller in Rêves de Belleville.

Question: What is the total number of movies in Cinéma de Montreval?

Solution: Define intense detective thriller in Rêves de Belleville as i; so i = 2. Define total number of movies in Rêves de Belleville as S; so S = i = 2. Define solemn period drama in Festival de Saint-Rivage as q; x = S = 2; so q = 3 * x = 3 * 2 = 6. Define intense detective thriller in Festival de Saint-Rivage as R; so R = 2. Define total number of movies in Festival de Saint-Rivage as I; so I = R + q = 2 + 6 = 8. Define solemn period drama in Festival Lumière de Valmont as d; n = I = 8; so d = 3 * n = 3 * 8 = 24. Define futuristic sci-fi movie in Festival Lumière de Valmont as W; a = i = 2; so W = 3 * a = 3 * 2 = 6. Define intense detective thriller in Festival Lumière de Valmont as G; so G = 4. Define total number of movies in Festival Lumière de Valmont as T; Y = G + W = 4 + 6 = 10; so T = Y + d = 10 + 24 = 34. Define calm road movie in Cinéma de Montreval as J; so J = R + S = 2 + 2 = 4. Define solemn period drama in Cinéma de Montreval as o; so o = T = 34. Define total number of movies in Cinéma de Montreval as r; so r = o + J = 34 + 4 = 38. Answer: 38.


The number of adult eagle in Jefferson Circus equals 4. The number of adult crow in South Zoo equals 4. The number of adult parrot in Hamilton Farm equals the sum of the total number of adult animals in Jefferson Circus and the number of adult eagle in South Zoo. The number of adult owl in Jefferson Circus equals the number of adult parrot in South Zoo. The number of adult blue jay in Hamilton Farm equals the number of adult eagle in Jefferson Circus. The number of adult eagle in South Zoo equals 3. The number of adult owl in Hamilton Farm equals the number of adult eagle in Jefferson Circus. The number of adult parrot in South Zoo equals the number of adult eagle in South Zoo. The number of adult parrot in Jefferson Circus equals the number of adult parrot in South Zoo. The number of adult crow in Hamilton Farm equals 3 plus the number of adult eagle in Jefferson Circus. The number of adult crow in Jefferson Circus equals 2. The number of adult owl in South Zoo equals the number of adult crow in South Zoo. The number of adult blue jay in South Zoo equals 1 plus the number of adult owl in Jefferson Circus.

Question: What is the total number of adult animals in Hamilton Farm?

Solution: Define adult eagle in South Zoo as B; so B = 3. Define adult parrot in South Zoo as r; so r = B = 3. Define adult owl in Jefferson Circus as f; so f = r = 3. Define adult crow in Jefferson Circus as a; so a = 2. Define adult eagle in Jefferson Circus as A; so A = 4. Define adult parrot in Jefferson Circus as L; so L = r = 3. Define total number of adult animals in Jefferson Circus as g; x = f + A = 3 + 4 = 7; J = x + a = 7 + 2 = 9; so g = J + L = 9 + 3 = 12. Define adult parrot in Hamilton Farm as V; so V = g + B = 12 + 3 = 15. Define adult owl in Hamilton Farm as S; so S = A = 4. Define adult blue jay in Hamilton Farm as y; so y = A = 4. Define adult crow in Hamilton Farm as M; Y = A = 4; so M = 3 + Y = 3 + 4 = 7. Define total number of adult animals in Hamilton Farm as v; H = S + y = 4 + 4 = 8; Q = H + M = 8 + 7 = 15; so v = Q + V = 15 + 15 = 30. Answer: 30.


The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 4 times the total number of movies in Verdi Movie Festival. The number of calm road movie in Verdi Movie Festival equals 3. The number of calm road movie in Northwood Movie Festival equals 4. The number of upbeat metropolis comedy in Verdi Movie Festival equals 2 plus the difference between the total number of movies in Northwood Movie Festival and the number of intense detective thriller in Northwood Movie Festival. The number of solemn period drama in West Sahara Movie Festival equals the total number of movies in Northwood Movie Festival. The number of solemn period drama in Verdi Movie Festival equals 1 plus the difference between the total number of movies in West Sahara Movie Festival and the number of solemn period drama in West Sahara Movie Festival. The number of intense detective thriller in Northwood Movie Festival equals 2 times the number of calm road movie in Northwood Movie Festival.

Question: What is the total number of movies in Golden Banana Movie Festival?

Solution: Define calm road movie in Northwood Movie Festival as m; so m = 4. Define intense detective thriller in Northwood Movie Festival as O; v = m = 4; so O = 2 * v = 2 * 4 = 8. Define total number of movies in Northwood Movie Festival as x; so x = O + m = 8 + 4 = 12. Define solemn period drama in West Sahara Movie Festival as z; so z = x = 12. Define upbeat metropolis comedy in Verdi Movie Festival as F; U = x - O = 12 - 8 = 4; so F = 2 + U = 2 + 4 = 6. Define total number of movies in West Sahara Movie Festival as D; so D = z = 12. Define calm road movie in Verdi Movie Festival as a; so a = 3. Define solemn period drama in Verdi Movie Festival as j; p = D - z = 12 - 12 = 0; so j = 1 + p = 1 + 0 = 1. Define total number of movies in Verdi Movie Festival as y; B = j + F = 1 + 6 = 7; so y = B + a = 7 + 3 = 10. Define upbeat metropolis comedy in Golden Banana Movie Festival as n; h = y = 10; so n = 4 * h = 4 * 10 = 40. Define total number of movies in Golden Banana Movie Festival as f; so f = n = 40. Answer: 40.


The number of private middle school in Riverton City equals 4 times the number of elementary school in Shoreline City. The number of regional medical school in Riverton City equals the difference between the number of private middle school in Riverton City and the number of elementary school in Shoreline City. The number of regional medical school in Shoreline City equals the number of regional medical school in Riverton City. The number of regional medical school in Ruby Bay equals the sum of the number of private middle school in Ruby Bay, the number of elementary school in Riverton City, and the total number of schools in Riverton City. The number of private middle school in Shoreline City equals the number of regional medical school in Ruby Bay. The number of elementary school in Shoreline City equals 3. The number of elementary school in Riverton City equals 4 times the number of private middle school in Riverton City. The number of elementary school in Ruby Bay equals 2 plus the number of regional medical school in Riverton City. The number of private middle school in Ruby Bay equals 3 plus the total number of schools in Riverton City.

Question: What is the total number of schools in Ruby Bay?

Solution: Define elementary school in Shoreline City as v; so v = 3. Define private middle school in Riverton City as K; r = v = 3; so K = 4 * r = 4 * 3 = 12. Define regional medical school in Riverton City as q; so q = K - v = 12 - 3 = 9. Define elementary school in Riverton City as p; I = K = 12; so p = 4 * I = 4 * 12 = 48. Define total number of schools in Riverton City as L; j = K + p = 12 + 48 = 60; so L = j + q = 60 + 9 = 69. Define private middle school in Ruby Bay as J; z = L = 69; so J = 3 + z = 3 + 69 = 72. Define elementary school in Ruby Bay as x; N = q = 9; so x = 2 + N = 2 + 9 = 11. Define regional medical school in Ruby Bay as w; n = J + p = 72 + 48 = 120; so w = n + L = 120 + 69 = 189. Define total number of schools in Ruby Bay as H; W = J + x = 72 + 11 = 83; so H = W + w = 83 + 189 = 272. Answer: 272.


The number of adult deer in Jefferson Circus equals the number of adult deer in Mayer Aquarium. The number of adult bear in Hamilton Farm equals the difference between the number of adult bear in Mayer Aquarium and the number of adult wolf in Jefferson Circus. The number of adult wolf in Jefferson Circus equals the sum of the number of adult deer in Jefferson Circus and the number of adult deer in Hamilton Farm. The number of adult wolf in Hamilton Farm equals the sum of the number of adult bear in Hamilton Farm, the number of adult bear in Jefferson Circus, and the number of adult deer in Hamilton Farm. The number of adult wolf in Mayer Aquarium equals 4. The number of adult bear in Mayer Aquarium equals the sum of the total number of adult animals in Jefferson Circus, the number of adult deer in Mayer Aquarium, and the number of adult bear in Jefferson Circus. The number of adult deer in Mayer Aquarium equals 2 times the number of adult deer in Hamilton Farm. The number of adult deer in Hamilton Farm equals 2. The number of adult bear in Jefferson Circus equals 1 plus the difference between the number of adult deer in Jefferson Circus and the number of adult deer in Hamilton Farm.

Question: How many adult wolf does Hamilton Farm have?

Solution: Define adult deer in Hamilton Farm as M; so M = 2. Define adult deer in Mayer Aquarium as Y; t = M = 2; so Y = 2 * t = 2 * 2 = 4. Define adult deer in Jefferson Circus as E; so E = Y = 4. Define adult bear in Jefferson Circus as Q; L = E - M = 4 - 2 = 2; so Q = 1 + L = 1 + 2 = 3. Define adult wolf in Jefferson Circus as m; so m = E + M = 4 + 2 = 6. Define total number of adult animals in Jefferson Circus as v; S = E + Q = 4 + 3 = 7; so v = S + m = 7 + 6 = 13. Define adult bear in Mayer Aquarium as c; P = v + Y = 13 + 4 = 17; so c = P + Q = 17 + 3 = 20. Define adult bear in Hamilton Farm as d; so d = c - m = 20 - 6 = 14. Define adult wolf in Hamilton Farm as w; D = d + Q = 14 + 3 = 17; so w = D + M = 17 + 2 = 19. Answer: 19.


The number of adult parrot in Bundle Ranch equals the number of adult parrot in South Zoo. The number of adult owl in Hamilton Farm equals 2 times the number of adult parrot in Hamilton Farm. The number of adult crow in Hamilton Farm equals 3. The number of adult blue jay in Bundle Ranch equals the number of adult parrot in Bundle Ranch. The number of adult parrot in Hamilton Farm equals 2 times the number of adult blue jay in Jefferson Circus. The number of adult crow in Mayer Aquarium equals the difference between the number of adult blue jay in Hamilton Farm and the number of adult blue jay in Bundle Ranch. The number of adult parrot in South Zoo equals 1. The number of adult crow in Jefferson Circus equals 3. The number of adult eagle in Bundle Ranch equals 3. The number of adult owl in Mayer Aquarium equals the sum of the number of adult blue jay in South Zoo, the number of adult parrot in Bundle Ranch, and the number of adult blue jay in Bundle Ranch. The number of adult blue jay in Hamilton Farm equals 3. The number of adult blue jay in South Zoo equals the number of adult blue jay in Bundle Ranch. The number of adult blue jay in Jefferson Circus equals the sum of the number of adult owl in Mayer Aquarium, the number of adult parrot in South Zoo, and the number of adult blue jay in Bundle Ranch. The number of adult eagle in Mayer Aquarium equals 2. The number of adult owl in Bundle Ranch equals the sum of the number of adult crow in Bundle Ranch and the number of adult eagle in Mayer Aquarium. The number of adult crow in Bundle Ranch equals 3 times the number of adult eagle in Mayer Aquarium. The number of adult eagle in South Zoo equals 4.

Question: What is the total number of adult animals in Hamilton Farm?

Solution: Define adult parrot in South Zoo as v; so v = 1. Define adult parrot in Bundle Ranch as u; so u = v = 1. Define adult blue jay in Bundle Ranch as X; so X = u = 1. Define adult blue jay in South Zoo as h; so h = X = 1. Define adult owl in Mayer Aquarium as G; q = h + u = 1 + 1 = 2; so G = q + X = 2 + 1 = 3. Define adult blue jay in Jefferson Circus as Z; S = G + v = 3 + 1 = 4; so Z = S + X = 4 + 1 = 5. Define adult parrot in Hamilton Farm as F; n = Z = 5; so F = 2 * n = 2 * 5 = 10. Define adult owl in Hamilton Farm as B; T = F = 10; so B = 2 * T = 2 * 10 = 20. Define adult crow in Hamilton Farm as w; so w = 3. Define adult blue jay in Hamilton Farm as J; so J = 3. Define total number of adult animals in Hamilton Farm as f; l = B + F = 20 + 10 = 30; y = l + J = 30 + 3 = 33; so f = y + w = 33 + 3 = 36. Answer: 36.


The number of adult crow in Hamilton Farm equals the total number of adult animals in Bundle Ranch. The number of adult owl in Mayer Aquarium equals 2. The number of adult blue jay in Hamilton Farm equals 3. The number of adult blue jay in Bundle Ranch equals 4 times the total number of adult animals in Mayer Aquarium. The number of adult owl in Bundle Ranch equals the sum of the number of adult blue jay in Bundle Ranch, the number of adult crow in Mayer Aquarium, the total number of adult animals in Mayer Aquarium, and the number of adult owl in Mayer Aquarium. The number of adult crow in Bundle Ranch equals 4. The number of adult owl in Hamilton Farm equals the number of adult owl in Mayer Aquarium. The number of adult crow in Mayer Aquarium equals 4.

Question: What is the total number of adult animals in Hamilton Farm?

Solution: Define adult crow in Mayer Aquarium as Z; so Z = 4. Define adult owl in Mayer Aquarium as B; so B = 2. Define total number of adult animals in Mayer Aquarium as D; so D = B + Z = 2 + 4 = 6. Define adult blue jay in Bundle Ranch as a; q = D = 6; so a = 4 * q = 4 * 6 = 24. Define adult crow in Bundle Ranch as h; so h = 4. Define adult owl in Bundle Ranch as s; R = a + Z = 24 + 4 = 28; y = R + D = 28 + 6 = 34; so s = y + B = 34 + 2 = 36. Define total number of adult animals in Bundle Ranch as Y; t = s + h = 36 + 4 = 40; so Y = t + a = 40 + 24 = 64. Define adult crow in Hamilton Farm as w; so w = Y = 64. Define adult blue jay in Hamilton Farm as v; so v = 3. Define adult owl in Hamilton Farm as c; so c = B = 2. Define total number of adult animals in Hamilton Farm as l; U = c + w = 2 + 64 = 66; so l = U + v = 66 + 3 = 69. Answer: 69.


The number of upbeat metropolis comedy in Taylor Movie Festival equals 2 times the sum of the total number of movies in Verdi Movie Festival, the number of upbeat metropolis comedy in Verdi Movie Festival, and the number of upbeat metropolis comedy in Northwood Movie Festival. The number of upbeat metropolis comedy in Verdi Movie Festival equals 4. The number of calm road movie in Taylor Movie Festival equals the sum of the total number of movies in Northwood Movie Festival, the total number of movies in Verdi Movie Festival, the number of upbeat metropolis comedy in Taylor Movie Festival, and the number of upbeat metropolis comedy in Verdi Movie Festival. The number of upbeat metropolis comedy in Northwood Movie Festival equals 4 plus the number of upbeat metropolis comedy in Verdi Movie Festival. The number of solemn period drama in Taylor Movie Festival equals the sum of the number of upbeat metropolis comedy in Verdi Movie Festival, the total number of movies in Verdi Movie Festival, the number of upbeat metropolis comedy in Taylor Movie Festival, and the number of upbeat metropolis comedy in Northwood Movie Festival.

Question: What is the total number of movies in Taylor Movie Festival?

Solution: Define upbeat metropolis comedy in Verdi Movie Festival as z; so z = 4. Define upbeat metropolis comedy in Northwood Movie Festival as p; i = z = 4; so p = 4 + i = 4 + 4 = 8. Define total number of movies in Verdi Movie Festival as L; so L = z = 4. Define upbeat metropolis comedy in Taylor Movie Festival as X; A = L + z = 4 + 4 = 8; j = A + p = 8 + 8 = 16; so X = 2 * j = 2 * 16 = 32. Define total number of movies in Northwood Movie Festival as Q; so Q = p = 8. Define solemn period drama in Taylor Movie Festival as O; F = z + L = 4 + 4 = 8; n = F + X = 8 + 32 = 40; so O = n + p = 40 + 8 = 48. Define calm road movie in Taylor Movie Festival as o; J = Q + L = 8 + 4 = 12; P = J + X = 12 + 32 = 44; so o = P + z = 44 + 4 = 48. Define total number of movies in Taylor Movie Festival as Z; m = O + o = 48 + 48 = 96; so Z = m + X = 96 + 32 = 128. Answer: 128.


The number of upbeat metropolis comedy in Northwood Movie Festival equals 4 times the difference between the number of calm road movie in Northwood Movie Festival and the number of intense detective thriller in Golden Banana Movie Festival. The number of intense detective thriller in Golden Banana Movie Festival equals 3 times the number of intense detective thriller in Northwood Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals 3. The number of intense detective thriller in Northwood Movie Festival equals 3. The number of calm road movie in Northwood Movie Festival equals the sum of the total number of movies in Golden Banana Movie Festival, the number of intense detective thriller in Golden Banana Movie Festival, and the number of upbeat metropolis comedy in Golden Banana Movie Festival. The number of upbeat metropolis comedy in West Sahara Movie Festival equals the sum of the number of upbeat metropolis comedy in Northwood Movie Festival, the number of intense detective thriller in Golden Banana Movie Festival, and the number of calm road movie in Northwood Movie Festival. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 2 times the sum of the number of intense detective thriller in Golden Banana Movie Festival and the number of intense detective thriller in Northwood Movie Festival.

Question: What is the total number of movies in West Sahara Movie Festival?

Solution: Define intense detective thriller in Northwood Movie Festival as x; so x = 3. Define intense detective thriller in Golden Banana Movie Festival as E; Z = x = 3; so E = 3 * Z = 3 * 3 = 9. Define upbeat metropolis comedy in Golden Banana Movie Festival as B; l = E + x = 9 + 3 = 12; so B = 2 * l = 2 * 12 = 24. Define calm road movie in Golden Banana Movie Festival as O; so O = 3. Define total number of movies in Golden Banana Movie Festival as n; X = B + E = 24 + 9 = 33; so n = X + O = 33 + 3 = 36. Define calm road movie in Northwood Movie Festival as D; J = n + E = 36 + 9 = 45; so D = J + B = 45 + 24 = 69. Define upbeat metropolis comedy in Northwood Movie Festival as t; C = D - E = 69 - 9 = 60; so t = 4 * C = 4 * 60 = 240. Define upbeat metropolis comedy in West Sahara Movie Festival as q; V = t + E = 240 + 9 = 249; so q = V + D = 249 + 69 = 318. Define total number of movies in West Sahara Movie Festival as W; so W = q = 318. Answer: 318.


The number of futuristic sci-fi movie in Golden Banana Movie Festival equals 3. The number of calm road movie in West Sahara Movie Festival equals the sum of the number of solemn period drama in West Sahara Movie Festival, the number of futuristic sci-fi movie in Golden Banana Movie Festival, the number of futuristic sci-fi movie in Northwood Movie Festival, and the number of calm road movie in Northwood Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals the number of solemn period drama in Northwood Movie Festival. The number of calm road movie in Northwood Movie Festival equals the number of futuristic sci-fi movie in Golden Banana Movie Festival. The number of futuristic sci-fi movie in Northwood Movie Festival equals 2 plus the sum of the number of calm road movie in Northwood Movie Festival and the number of futuristic sci-fi movie in Golden Banana Movie Festival. The number of solemn period drama in Northwood Movie Festival equals 2. The number of calm road movie in Golden Banana Movie Festival equals the difference between the total number of movies in West Sahara Movie Festival and the number of futuristic sci-fi movie in Northwood Movie Festival. The number of solemn period drama in West Sahara Movie Festival equals 4 plus the sum of the number of futuristic sci-fi movie in Northwood Movie Festival and the number of calm road movie in Northwood Movie Festival. The number of upbeat metropolis comedy in Northwood Movie Festival equals the sum of the number of calm road movie in Golden Banana Movie Festival, the number of futuristic sci-fi movie in Northwood Movie Festival, the number of calm road movie in Northwood Movie Festival, and the number of calm road movie in West Sahara Movie Festival.

Question: How many upbeat metropolis comedy does Northwood Movie Festival have?

Solution: Define futuristic sci-fi movie in Golden Banana Movie Festival as D; so D = 3. Define calm road movie in Northwood Movie Festival as L; so L = D = 3. Define futuristic sci-fi movie in Northwood Movie Festival as X; i = L + D = 3 + 3 = 6; so X = 2 + i = 2 + 6 = 8. Define solemn period drama in West Sahara Movie Festival as t; W = X + L = 8 + 3 = 11; so t = 4 + W = 4 + 11 = 15. Define calm road movie in West Sahara Movie Festival as G; T = t + D = 15 + 3 = 18; U = T + X = 18 + 8 = 26; so G = U + L = 26 + 3 = 29. Define total number of movies in West Sahara Movie Festival as Z; so Z = t + G = 15 + 29 = 44. Define calm road movie in Golden Banana Movie Festival as y; so y = Z - X = 44 - 8 = 36. Define upbeat metropolis comedy in Northwood Movie Festival as l; I = y + X = 36 + 8 = 44; p = I + L = 44 + 3 = 47; so l = p + G = 47 + 29 = 76. Answer: 76.


The number of calm road movie in Golden Banana Movie Festival equals the total number of movies in Verdi Movie Festival. The number of solemn period drama in Northwood Movie Festival equals the sum of the total number of movies in West Sahara Movie Festival, the total number of movies in Taylor Movie Festival, the number of upbeat metropolis comedy in Taylor Movie Festival, and the number of intense detective thriller in West Sahara Movie Festival. The number of upbeat metropolis comedy in Taylor Movie Festival equals 3. The number of intense detective thriller in West Sahara Movie Festival equals the total number of movies in Taylor Movie Festival. The number of upbeat metropolis comedy in West Sahara Movie Festival equals 3 plus the total number of movies in Taylor Movie Festival. The number of calm road movie in Northwood Movie Festival equals 3. The number of futuristic sci-fi movie in Verdi Movie Festival equals the sum of the total number of movies in Northwood Movie Festival, the total number of movies in Taylor Movie Festival, and the number of calm road movie in Northwood Movie Festival.

Question: What is the total number of movies in Golden Banana Movie Festival?

Solution: Define upbeat metropolis comedy in Taylor Movie Festival as G; so G = 3. Define total number of movies in Taylor Movie Festival as S; so S = G = 3. Define upbeat metropolis comedy in West Sahara Movie Festival as w; K = S = 3; so w = 3 + K = 3 + 3 = 6. Define intense detective thriller in West Sahara Movie Festival as r; so r = S = 3. Define total number of movies in West Sahara Movie Festival as v; so v = w + r = 6 + 3 = 9. Define solemn period drama in Northwood Movie Festival as T; Z = v + S = 9 + 3 = 12; Y = Z + G = 12 + 3 = 15; so T = Y + r = 15 + 3 = 18. Define calm road movie in Northwood Movie Festival as o; so o = 3. Define total number of movies in Northwood Movie Festival as g; so g = o + T = 3 + 18 = 21. Define futuristic sci-fi movie in Verdi Movie Festival as l; e = g + S = 21 + 3 = 24; so l = e + o = 24 + 3 = 27. Define total number of movies in Verdi Movie Festival as k; so k = l = 27. Define calm road movie in Golden Banana Movie Festival as a; so a = k = 27. Define total number of movies in Golden Banana Movie Festival as i; so i = a = 27. Answer: 27.


The number of adult bear in Hamilton Farm equals 3. The number of adult racoon in Hamilton Farm equals the difference between the total number of adult animals in Bundle Ranch and the number of adult wolf in Bundle Ranch. The number of adult racoon in Bundle Ranch equals the number of adult wolf in Mayer Aquarium. The number of adult bear in Bundle Ranch equals the difference between the total number of adult animals in Mayer Aquarium and the number of adult racoon in Mayer Aquarium. The number of adult wolf in Bundle Ranch equals 3 times the difference between the number of adult bear in Bundle Ranch and the number of adult racoon in Mayer Aquarium. The number of adult bear in Mayer Aquarium equals 2. The number of adult wolf in Mayer Aquarium equals the number of adult bear in Mayer Aquarium. The number of adult racoon in Mayer Aquarium equals the number of adult bear in Mayer Aquarium.

Question: What is the total number of adult animals in Hamilton Farm?

Solution: Define adult bear in Mayer Aquarium as P; so P = 2. Define adult wolf in Mayer Aquarium as R; so R = P = 2. Define adult racoon in Mayer Aquarium as x; so x = P = 2. Define total number of adult animals in Mayer Aquarium as c; l = P + R = 2 + 2 = 4; so c = l + x = 4 + 2 = 6. Define adult bear in Bundle Ranch as V; so V = c - x = 6 - 2 = 4. Define adult racoon in Bundle Ranch as t; so t = R = 2. Define adult wolf in Bundle Ranch as M; W = V - x = 4 - 2 = 2; so M = 3 * W = 3 * 2 = 6. Define total number of adult animals in Bundle Ranch as q; r = M + V = 6 + 4 = 10; so q = r + t = 10 + 2 = 12. Define adult racoon in Hamilton Farm as J; so J = q - M = 12 - 6 = 6. Define adult bear in Hamilton Farm as A; so A = 3. Define total number of adult animals in Hamilton Farm as m; so m = A + J = 3 + 6 = 9. Answer: 9.


The number of adult owl in Mayer Aquarium equals 4. The number of adult eagle in Mayer Aquarium equals 4 plus the number of adult parrot in Mayer Aquarium. The number of adult owl in Bundle Ranch equals the sum of the number of adult eagle in Bundle Ranch, the number of adult eagle in Mayer Aquarium, the number of adult owl in Mayer Aquarium, and the number of adult parrot in Mayer Aquarium. The number of adult parrot in Bundle Ranch equals 3 plus the number of adult eagle in Bundle Ranch. The number of adult parrot in Mayer Aquarium equals 3 plus the number of adult owl in Mayer Aquarium. The number of adult eagle in Bundle Ranch equals 3 times the sum of the total number of adult animals in Mayer Aquarium and the number of adult eagle in Mayer Aquarium.

Question: What is the total number of adult animals in Bundle Ranch?

Solution: Define adult owl in Mayer Aquarium as g; so g = 4. Define adult parrot in Mayer Aquarium as E; u = g = 4; so E = 3 + u = 3 + 4 = 7. Define adult eagle in Mayer Aquarium as t; Q = E = 7; so t = 4 + Q = 4 + 7 = 11. Define total number of adult animals in Mayer Aquarium as O; L = E + g = 7 + 4 = 11; so O = L + t = 11 + 11 = 22. Define adult eagle in Bundle Ranch as N; b = O + t = 22 + 11 = 33; so N = 3 * b = 3 * 33 = 99. Define adult parrot in Bundle Ranch as y; d = N = 99; so y = 3 + d = 3 + 99 = 102. Define adult owl in Bundle Ranch as x; G = N + t = 99 + 11 = 110; c = G + g = 110 + 4 = 114; so x = c + E = 114 + 7 = 121. Define total number of adult animals in Bundle Ranch as k; U = y + x = 102 + 121 = 223; so k = U + N = 223 + 99 = 322. Answer: 322.


The number of calm road movie in Festival de Clairmont equals the total number of movies in Festival Lumière de Valmont. The number of calm road movie in Festival Lumière de Valmont equals 3. The number of solemn period drama in Festival de Clairmont equals 2. The number of futuristic sci-fi movie in Festival Lumière de Valmont equals 4. The number of calm road movie in Rêves de Belleville equals 2 times the number of futuristic sci-fi movie in Festival Lumière de Valmont. The number of futuristic sci-fi movie in Festival de Clairmont equals the number of calm road movie in Rêves de Belleville. The number of futuristic sci-fi movie in Rêves de Belleville equals 4 plus the number of solemn period drama in Rêves de Belleville. The number of solemn period drama in Festival Lumière de Valmont equals 1 plus the number of calm road movie in Rêves de Belleville. The number of solemn period drama in Rêves de Belleville equals the sum of the total number of movies in Festival de Clairmont, the total number of movies in Festival Lumière de Valmont, and the number of futuristic sci-fi movie in Festival de Clairmont.

Question: How many futuristic sci-fi movie does Rêves de Belleville have?

Solution: Define futuristic sci-fi movie in Festival Lumière de Valmont as t; so t = 4. Define calm road movie in Rêves de Belleville as e; u = t = 4; so e = 2 * u = 2 * 4 = 8. Define solemn period drama in Festival Lumière de Valmont as X; z = e = 8; so X = 1 + z = 1 + 8 = 9. Define calm road movie in Festival Lumière de Valmont as M; so M = 3. Define total number of movies in Festival Lumière de Valmont as l; F = X + t = 9 + 4 = 13; so l = F + M = 13 + 3 = 16. Define calm road movie in Festival de Clairmont as m; so m = l = 16. Define futuristic sci-fi movie in Festival de Clairmont as L; so L = e = 8. Define solemn period drama in Festival de Clairmont as V; so V = 2. Define total number of movies in Festival de Clairmont as j; i = V + L = 2 + 8 = 10; so j = i + m = 10 + 16 = 26. Define solemn period drama in Rêves de Belleville as g; k = j + l = 26 + 16 = 42; so g = k + L = 42 + 8 = 50. Define futuristic sci-fi movie in Rêves de Belleville as G; I = g = 50; so G = 4 + I = 4 + 50 = 54. Answer: 54.


The number of adult fox in Maple Creek equals the sum of the total number of adult animals in Oakridge Riverside, the number of adult bear in Oakridge Riverside, and the number of adult racoon in Maple Creek. The number of adult racoon in Cedar Valley equals 3. The number of adult fox in Cedar Valley equals 2. The number of adult bear in Oakridge Riverside equals 2. The number of adult racoon in Maple Creek equals 1 plus the sum of the number of adult racoon in Oakridge Riverside, the number of adult bear in Oakridge Riverside, and the number of adult bear in Maple Creek. The number of adult bear in Cedar Valley equals the sum of the number of adult racoon in Maple Creek and the total number of adult animals in Maple Creek. The number of adult racoon in Oakridge Riverside equals 3 times the number of adult bear in Oakridge Riverside. The number of adult bear in Maple Creek equals 3. The number of adult fox in Oakridge Riverside equals 4 times the sum of the number of adult bear in Oakridge Riverside and the number of adult bear in Maple Creek.

Question: What is the total number of adult animals in Maple Creek?

Solution: Define adult bear in Oakridge Riverside as H; so H = 2. Define adult bear in Maple Creek as g; so g = 3. Define adult racoon in Oakridge Riverside as c; I = H = 2; so c = 3 * I = 3 * 2 = 6. Define adult racoon in Maple Creek as m; r = c + H = 6 + 2 = 8; f = r + g = 8 + 3 = 11; so m = 1 + f = 1 + 11 = 12. Define adult fox in Oakridge Riverside as S; L = H + g = 2 + 3 = 5; so S = 4 * L = 4 * 5 = 20. Define total number of adult animals in Oakridge Riverside as N; p = H + S = 2 + 20 = 22; so N = p + c = 22 + 6 = 28. Define adult fox in Maple Creek as V; K = N + H = 28 + 2 = 30; so V = K + m = 30 + 12 = 42. Define total number of adult animals in Maple Creek as E; s = g + V = 3 + 42 = 45; so E = s + m = 45 + 12 = 57. Answer: 57.