The number of private middle school in Glenfield City equals 4. The number of private middle school in Brightford equals the total number of schools in Hawkesbury. The number of public highschool in Brightford equals the number of private middle school in Glenfield City. The number of private middle school in Hawkesbury equals the total number of schools in Glenfield City. The number of public highschool in Evervale City equals 4. The number of private middle school in Evervale City equals 4 plus the sum of the number of public highschool in Brightford, the number of public highschool in Glenfield City, and the number of private middle school in Glenfield City. The number of public highschool in Glenfield City equals the number of private middle school in Glenfield City. The number of public highschool in Hawkesbury equals 3 times the number of private middle school in Glenfield City.

Question: What is the total number of schools in Brightford?

Solution: Define private middle school in Glenfield City as C; so C = 4. Define public highschool in Glenfield City as f; so f = C = 4. Define total number of schools in Glenfield City as H; so H = f + C = 4 + 4 = 8. Define private middle school in Hawkesbury as l; so l = H = 8. Define public highschool in Hawkesbury as y; s = C = 4; so y = 3 * s = 3 * 4 = 12. Define total number of schools in Hawkesbury as i; so i = l + y = 8 + 12 = 20. Define private middle school in Brightford as F; so F = i = 20. Define public highschool in Brightford as O; so O = C = 4. Define total number of schools in Brightford as e; so e = O + F = 4 + 20 = 24. Answer: 24.


The number of futuristic sci-fi movie in Rêves de Belleville equals the sum of the total number of movies in Cinéma de Montreval, the number of futuristic sci-fi movie in Cinéma de Montreval, and the number of intense detective thriller in Cinéma de Montreval. The number of intense detective thriller in Cinéma de Montreval equals 2. The number of solemn period drama in Festival de Saint-Rivage equals 2 plus the sum of the total number of movies in Rêves de Belleville, the number of intense detective thriller in Cinéma de Montreval, and the total number of movies in Cinéma de Montreval. The number of futuristic sci-fi movie in Cinéma de Montreval equals 4.

Question: What is the total number of movies in Festival de Saint-Rivage?

Solution: Define futuristic sci-fi movie in Cinéma de Montreval as N; so N = 4. Define intense detective thriller in Cinéma de Montreval as L; so L = 2. Define total number of movies in Cinéma de Montreval as T; so T = N + L = 4 + 2 = 6. Define futuristic sci-fi movie in Rêves de Belleville as x; m = T + N = 6 + 4 = 10; so x = m + L = 10 + 2 = 12. Define total number of movies in Rêves de Belleville as w; so w = x = 12. Define solemn period drama in Festival de Saint-Rivage as G; C = w + L = 12 + 2 = 14; B = C + T = 14 + 6 = 20; so G = 2 + B = 2 + 20 = 22. Define total number of movies in Festival de Saint-Rivage as X; so X = G = 22. Answer: 22.


The number of regional medical school in Riverton City equals the number of private middle school in Riverton City. The number of regional medical school in Shoreline City equals 4. The number of private middle school in Riverton City equals 3. The number of regional medical school in Clearwater Bay equals 4 plus the sum of the total number of schools in Shoreline City and the number of private middle school in Shoreline City. The number of private middle school in Shoreline City equals 3 times the sum of the number of regional medical school in Riverton City and the number of private middle school in Riverton City. The number of culinarian school in Clearwater Bay equals 2 plus the sum of the number of elementary school in Ruby Bay, the number of regional medical school in Riverton City, and the number of private middle school in Shoreline City. The number of culinarian school in Shoreline City equals the sum of the number of regional medical school in Riverton City and the total number of schools in Ruby Bay. The number of elementary school in Ruby Bay equals 2 times the sum of the number of private middle school in Shoreline City, the number of private middle school in Riverton City, and the number of regional medical school in Riverton City.

Question: How many culinarian school does Clearwater Bay have?

Solution: Define private middle school in Riverton City as R; so R = 3. Define regional medical school in Riverton City as o; so o = R = 3. Define private middle school in Shoreline City as u; E = o + R = 3 + 3 = 6; so u = 3 * E = 3 * 6 = 18. Define elementary school in Ruby Bay as i; g = u + R = 18 + 3 = 21; e = g + o = 21 + 3 = 24; so i = 2 * e = 2 * 24 = 48. Define culinarian school in Clearwater Bay as H; P = i + o = 48 + 3 = 51; n = P + u = 51 + 18 = 69; so H = 2 + n = 2 + 69 = 71. Answer: 71.


The number of solemn period drama in Festival Lumière de Valmont equals the sum of the total number of movies in Rêves de Belleville, the number of upbeat metropolis comedy in Rêves de Belleville, the total number of movies in Festival de Saint-Rivage, and the number of upbeat metropolis comedy in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Rêves de Belleville equals 4 plus the sum of the total number of movies in Festival de Saint-Rivage and the number of upbeat metropolis comedy in Festival de Saint-Rivage. The number of upbeat metropolis comedy in Rêves de Belleville equals the number of futuristic sci-fi movie in Rêves de Belleville. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals 4.

Question: What is the total number of movies in Festival Lumière de Valmont?

Solution: Define upbeat metropolis comedy in Festival de Saint-Rivage as Q; so Q = 4. Define total number of movies in Festival de Saint-Rivage as Z; so Z = Q = 4. Define futuristic sci-fi movie in Rêves de Belleville as M; g = Z + Q = 4 + 4 = 8; so M = 4 + g = 4 + 8 = 12. Define upbeat metropolis comedy in Rêves de Belleville as U; so U = M = 12. Define total number of movies in Rêves de Belleville as f; so f = U + M = 12 + 12 = 24. Define solemn period drama in Festival Lumière de Valmont as O; K = f + U = 24 + 12 = 36; W = K + Z = 36 + 4 = 40; so O = W + Q = 40 + 4 = 44. Define total number of movies in Festival Lumière de Valmont as N; so N = O = 44. Answer: 44.


The number of futuristic sci-fi movie in Festival de Clairmont equals 3. The number of futuristic sci-fi movie in Rêves de Belleville equals 4 times the sum of the total number of movies in Festival de Clairmont, the number of futuristic sci-fi movie in Festival de Clairmont, and the number of solemn period drama in Festival de Clairmont. The number of solemn period drama in Rêves de Belleville equals 2 plus the total number of movies in Festival de Clairmont. The number of solemn period drama in Festival de Clairmont equals 4 times the number of futuristic sci-fi movie in Festival de Clairmont.

Question: What is the total number of movies in Rêves de Belleville?

Solution: Define futuristic sci-fi movie in Festival de Clairmont as h; so h = 3. Define solemn period drama in Festival de Clairmont as c; S = h = 3; so c = 4 * S = 4 * 3 = 12. Define total number of movies in Festival de Clairmont as k; so k = c + h = 12 + 3 = 15. Define futuristic sci-fi movie in Rêves de Belleville as P; M = k + h = 15 + 3 = 18; B = M + c = 18 + 12 = 30; so P = 4 * B = 4 * 30 = 120. Define solemn period drama in Rêves de Belleville as s; j = k = 15; so s = 2 + j = 2 + 15 = 17. Define total number of movies in Rêves de Belleville as g; so g = s + P = 17 + 120 = 137. Answer: 137.


The number of adult parrot in Pine Ridge equals 3 times the number of adult owl in Pine Ridge. The number of adult owl in Maple Creek equals the sum of the total number of adult animals in Pine Ridge, the number of adult parrot in Pine Ridge, and the number of adult owl in Pine Ridge. The number of adult parrot in Maple Creek equals the sum of the number of adult owl in Maple Creek, the total number of adult animals in Pine Ridge, and the number of adult parrot in Pine Ridge. The number of adult owl in Pine Ridge equals 3.

Question: What is the total number of adult animals in Maple Creek?

Solution: Define adult owl in Pine Ridge as O; so O = 3. Define adult parrot in Pine Ridge as c; M = O = 3; so c = 3 * M = 3 * 3 = 9. Define total number of adult animals in Pine Ridge as V; so V = c + O = 9 + 3 = 12. Define adult owl in Maple Creek as l; H = V + c = 12 + 9 = 21; so l = H + O = 21 + 3 = 24. Define adult parrot in Maple Creek as h; p = l + V = 24 + 12 = 36; so h = p + c = 36 + 9 = 45. Define total number of adult animals in Maple Creek as x; so x = h + l = 45 + 24 = 69. Answer: 69.


The number of public highschool in Ruby Bay equals the sum of the number of elementary school in Oakbridge City and the number of public highschool in Clearwater Bay. The number of culinarian school in Clearwater Bay equals 4 times the number of regional medical school in Clearwater Bay. The number of regional medical school in Clearwater Bay equals 1. The number of public highschool in Shoreline City equals 2 plus the number of culinarian school in Shoreline City. The number of culinarian school in Riverton City equals the sum of the number of regional medical school in Riverton City and the number of culinarian school in Shoreline City. The number of public highschool in Oakbridge City equals 1. The number of culinarian school in Ruby Bay equals 4. The number of regional medical school in Riverton City equals 2 times the sum of the total number of schools in Shoreline City, the number of culinarian school in Shoreline City, and the number of public highschool in Shoreline City. The number of private middle school in Clearwater Bay equals 2. The number of culinarian school in Shoreline City equals 1. The number of elementary school in Oakbridge City equals 4 plus the number of private middle school in Ruby Bay. The number of public highschool in Clearwater Bay equals 4. The number of private middle school in Ruby Bay equals 4.

Question: What is the total number of schools in Riverton City?

Solution: Define culinarian school in Shoreline City as H; so H = 1. Define public highschool in Shoreline City as B; O = H = 1; so B = 2 + O = 2 + 1 = 3. Define total number of schools in Shoreline City as R; so R = B + H = 3 + 1 = 4. Define regional medical school in Riverton City as Q; Y = R + H = 4 + 1 = 5; G = Y + B = 5 + 3 = 8; so Q = 2 * G = 2 * 8 = 16. Define culinarian school in Riverton City as S; so S = Q + H = 16 + 1 = 17. Define total number of schools in Riverton City as x; so x = S + Q = 17 + 16 = 33. Answer: 33.


The number of adult parrot in Beverly Forest equals the total number of adult animals in Pine Ridge. The number of adult owl in Oakridge Riverside equals 3 times the number of adult blue jay in Oakridge Riverside. The number of adult parrot in Oakridge Riverside equals 3 plus the number of adult parrot in Beverly Forest. The number of adult owl in Pine Ridge equals 4. The number of adult parrot in Pine Ridge equals the number of adult owl in Pine Ridge. The number of adult owl in Beverly Forest equals the total number of adult animals in Pine Ridge. The number of adult blue jay in Oakridge Riverside equals 3. The number of adult blue jay in Pine Ridge equals the number of adult owl in Pine Ridge. The number of adult blue jay in Beverly Forest equals 2 times the number of adult parrot in Pine Ridge.

Question: What is the total number of adult animals in Beverly Forest?

Solution: Define adult owl in Pine Ridge as h; so h = 4. Define adult blue jay in Pine Ridge as C; so C = h = 4. Define adult parrot in Pine Ridge as m; so m = h = 4. Define total number of adult animals in Pine Ridge as T; o = C + h = 4 + 4 = 8; so T = o + m = 8 + 4 = 12. Define adult parrot in Beverly Forest as d; so d = T = 12. Define adult blue jay in Beverly Forest as g; S = m = 4; so g = 2 * S = 2 * 4 = 8. Define adult owl in Beverly Forest as G; so G = T = 12. Define total number of adult animals in Beverly Forest as Q; e = g + G = 8 + 12 = 20; so Q = e + d = 20 + 12 = 32. Answer: 32.


The number of adult eagle in Hamilton Farm equals 3 plus the sum of the number of adult blue jay in Bundle Ranch, the number of adult parrot in Hamilton Farm, and the number of adult blue jay in Hamilton Farm. The number of adult eagle in Bundle Ranch equals 4 times the number of adult eagle in Hamilton Farm. The number of adult parrot in Hamilton Farm equals 4 times the number of adult blue jay in Bundle Ranch. The number of adult eagle in Mayer Aquarium equals 4 times the number of adult parrot in Mayer Aquarium. The number of adult blue jay in Bundle Ranch equals 3. The number of adult blue jay in Mayer Aquarium equals the sum of the total number of adult animals in Hamilton Farm, the number of adult parrot in Hamilton Farm, the number of adult parrot in Mayer Aquarium, and the total number of adult animals in Mayer Aquarium. The number of adult parrot in Bundle Ranch equals the sum of the number of adult eagle in Mayer Aquarium and the total number of adult animals in Hamilton Farm. The number of adult parrot in Mayer Aquarium equals 3. The number of adult blue jay in Hamilton Farm equals 2 plus the sum of the number of adult blue jay in Bundle Ranch and the number of adult parrot in Hamilton Farm.

Question: What is the total number of adult animals in Hamilton Farm?

Solution: Define adult blue jay in Bundle Ranch as A; so A = 3. Define adult parrot in Hamilton Farm as C; a = A = 3; so C = 4 * a = 4 * 3 = 12. Define adult blue jay in Hamilton Farm as n; B = A + C = 3 + 12 = 15; so n = 2 + B = 2 + 15 = 17. Define adult eagle in Hamilton Farm as I; G = A + C = 3 + 12 = 15; Q = G + n = 15 + 17 = 32; so I = 3 + Q = 3 + 32 = 35. Define total number of adult animals in Hamilton Farm as l; M = n + I = 17 + 35 = 52; so l = M + C = 52 + 12 = 64. Answer: 64.


The number of solemn period drama in Golden Banana Movie Festival equals the sum of the total number of movies in Taylor Movie Festival, the total number of movies in Northwood Movie Festival, and the number of futuristic sci-fi movie in Taylor Movie Festival. The number of solemn period drama in Taylor Movie Festival equals 2 times the total number of movies in Northwood Movie Festival. The number of futuristic sci-fi movie in Taylor Movie Festival equals 2. The number of futuristic sci-fi movie in Golden Banana Movie Festival equals the total number of movies in Northwood Movie Festival. The number of solemn period drama in Northwood Movie Festival equals 4.

Question: What is the total number of movies in Golden Banana Movie Festival?

Solution: Define solemn period drama in Northwood Movie Festival as J; so J = 4. Define total number of movies in Northwood Movie Festival as l; so l = J = 4. Define solemn period drama in Taylor Movie Festival as k; z = l = 4; so k = 2 * z = 2 * 4 = 8. Define futuristic sci-fi movie in Taylor Movie Festival as Z; so Z = 2. Define total number of movies in Taylor Movie Festival as q; so q = Z + k = 2 + 8 = 10. Define solemn period drama in Golden Banana Movie Festival as R; E = q + l = 10 + 4 = 14; so R = E + Z = 14 + 2 = 16. Define futuristic sci-fi movie in Golden Banana Movie Festival as x; so x = l = 4. Define total number of movies in Golden Banana Movie Festival as M; so M = R + x = 16 + 4 = 20. Answer: 20.


The number of adult fox in Cedar Valley equals 1. The number of adult fox in Beverly Forest equals 4 plus the total number of adult animals in Cedar Valley. The number of adult bear in Cedar Valley equals 3 plus the number of adult fox in Cedar Valley. The number of adult bear in Beverly Forest equals the sum of the total number of adult animals in Cedar Valley, the number of adult fox in Beverly Forest, the number of adult fox in Cedar Valley, and the number of adult bear in Cedar Valley.

Question: What is the total number of adult animals in Beverly Forest?

Solution: Define adult fox in Cedar Valley as l; so l = 1. Define adult bear in Cedar Valley as U; V = l = 1; so U = 3 + V = 3 + 1 = 4. Define total number of adult animals in Cedar Valley as x; so x = l + U = 1 + 4 = 5. Define adult fox in Beverly Forest as c; K = x = 5; so c = 4 + K = 4 + 5 = 9. Define adult bear in Beverly Forest as n; g = x + c = 5 + 9 = 14; b = g + l = 14 + 1 = 15; so n = b + U = 15 + 4 = 19. Define total number of adult animals in Beverly Forest as m; so m = c + n = 9 + 19 = 28. Answer: 28.


The number of public highschool in Clearwater Bay equals 3. The number of public highschool in Oakbridge City equals 2 times the number of public highschool in Clearwater Bay. The number of regional medical school in Oakbridge City equals 2 times the sum of the number of public highschool in Clearwater Bay and the number of public highschool in Oakbridge City. The number of regional medical school in Clearwater Bay equals 3 times the sum of the total number of schools in Oakbridge City and the number of regional medical school in Oakbridge City.

Question: What is the total number of schools in Clearwater Bay?

Solution: Define public highschool in Clearwater Bay as W; so W = 3. Define public highschool in Oakbridge City as N; f = W = 3; so N = 2 * f = 2 * 3 = 6. Define regional medical school in Oakbridge City as w; x = W + N = 3 + 6 = 9; so w = 2 * x = 2 * 9 = 18. Define total number of schools in Oakbridge City as h; so h = N + w = 6 + 18 = 24. Define regional medical school in Clearwater Bay as A; V = h + w = 24 + 18 = 42; so A = 3 * V = 3 * 42 = 126. Define total number of schools in Clearwater Bay as n; so n = W + A = 3 + 126 = 129. Answer: 129.


The number of solemn period drama in Verdi Movie Festival equals the sum of the number of calm road movie in West Sahara Movie Festival, the number of upbeat metropolis comedy in West Sahara Movie Festival, and the number of intense detective thriller in Verdi Movie Festival. The number of calm road movie in Taylor Movie Festival equals the total number of movies in Verdi Movie Festival. The number of upbeat metropolis comedy in West Sahara Movie Festival equals 3 plus the number of calm road movie in West Sahara Movie Festival. The number of calm road movie in West Sahara Movie Festival equals 3. The number of upbeat metropolis comedy in Northwood Movie Festival equals 3 plus the number of calm road movie in Taylor Movie Festival. The number of futuristic sci-fi movie in Taylor Movie Festival equals 2. The number of solemn period drama in Taylor Movie Festival equals the number of futuristic sci-fi movie in Taylor Movie Festival. The number of intense detective thriller in Verdi Movie Festival equals 4 times the sum of the total number of movies in West Sahara Movie Festival and the number of upbeat metropolis comedy in West Sahara Movie Festival. The number of futuristic sci-fi movie in Northwood Movie Festival equals 1. The number of intense detective thriller in Golden Banana Movie Festival equals 4 plus the sum of the number of calm road movie in West Sahara Movie Festival, the number of upbeat metropolis comedy in Northwood Movie Festival, and the number of futuristic sci-fi movie in Northwood Movie Festival. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals the total number of movies in Verdi Movie Festival.

Question: What is the total number of movies in Verdi Movie Festival?

Solution: Define calm road movie in West Sahara Movie Festival as c; so c = 3. Define upbeat metropolis comedy in West Sahara Movie Festival as E; x = c = 3; so E = 3 + x = 3 + 3 = 6. Define total number of movies in West Sahara Movie Festival as k; so k = c + E = 3 + 6 = 9. Define intense detective thriller in Verdi Movie Festival as T; G = k + E = 9 + 6 = 15; so T = 4 * G = 4 * 15 = 60. Define solemn period drama in Verdi Movie Festival as M; y = c + E = 3 + 6 = 9; so M = y + T = 9 + 60 = 69. Define total number of movies in Verdi Movie Festival as O; so O = T + M = 60 + 69 = 129. Answer: 129.


The number of calm road movie in Cinéma de Montreval equals 3 times the difference between the total number of movies in Festival de Saint-Rivage and the number of futuristic sci-fi movie in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Festival de Clairmont equals the number of futuristic sci-fi movie in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Festival Lumière de Valmont equals 2 times the number of solemn period drama in Festival de Clairmont. The number of calm road movie in Festival de Saint-Rivage equals 3 times the number of futuristic sci-fi movie in Festival de Saint-Rivage. The number of solemn period drama in Festival de Clairmont equals 1. The number of calm road movie in Festival de Clairmont equals 4. The number of solemn period drama in Cinéma de Montreval equals 3 times the sum of the total number of movies in Festival de Saint-Rivage and the number of futuristic sci-fi movie in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals 4. The number of solemn period drama in Festival Lumière de Valmont equals the difference between the number of solemn period drama in Festival de Clairmont and the number of futuristic sci-fi movie in Festival Lumière de Valmont.

Question: What is the total number of movies in Cinéma de Montreval?

Solution: Define futuristic sci-fi movie in Festival de Saint-Rivage as E; so E = 4. Define calm road movie in Festival de Saint-Rivage as t; r = E = 4; so t = 3 * r = 3 * 4 = 12. Define total number of movies in Festival de Saint-Rivage as e; so e = t + E = 12 + 4 = 16. Define calm road movie in Cinéma de Montreval as b; n = e - E = 16 - 4 = 12; so b = 3 * n = 3 * 12 = 36. Define solemn period drama in Cinéma de Montreval as U; p = e + E = 16 + 4 = 20; so U = 3 * p = 3 * 20 = 60. Define total number of movies in Cinéma de Montreval as M; so M = b + U = 36 + 60 = 96. Answer: 96.


The number of adult eagle in Beverly Forest equals 1 plus the sum of the total number of adult animals in Pine Ridge and the number of adult eagle in Pine Ridge. The number of adult eagle in Pine Ridge equals the number of adult crow in Pine Ridge. The number of adult crow in Beverly Forest equals the sum of the total number of adult animals in Pine Ridge, the number of adult crow in Pine Ridge, the number of adult eagle in Pine Ridge, and the number of adult eagle in Beverly Forest. The number of adult crow in Pine Ridge equals 2.

Question: What is the total number of adult animals in Beverly Forest?

Solution: Define adult crow in Pine Ridge as N; so N = 2. Define adult eagle in Pine Ridge as p; so p = N = 2. Define total number of adult animals in Pine Ridge as w; so w = p + N = 2 + 2 = 4. Define adult eagle in Beverly Forest as C; T = w + p = 4 + 2 = 6; so C = 1 + T = 1 + 6 = 7. Define adult crow in Beverly Forest as n; g = w + N = 4 + 2 = 6; P = g + p = 6 + 2 = 8; so n = P + C = 8 + 7 = 15. Define total number of adult animals in Beverly Forest as K; so K = C + n = 7 + 15 = 22. Answer: 22.


The number of elementary school in Glenfield City equals the sum of the number of elementary school in Evervale City, the number of culinarian school in Glenfield City, and the number of culinarian school in Evervale City. The number of elementary school in Evervale City equals 2. The number of culinarian school in Glenfield City equals the sum of the total number of schools in Evervale City, the number of culinarian school in Evervale City, and the number of elementary school in Evervale City. The number of culinarian school in Evervale City equals 2 plus the number of elementary school in Evervale City.

Question: What is the total number of schools in Glenfield City?

Solution: Define elementary school in Evervale City as K; so K = 2. Define culinarian school in Evervale City as l; S = K = 2; so l = 2 + S = 2 + 2 = 4. Define total number of schools in Evervale City as s; so s = K + l = 2 + 4 = 6. Define culinarian school in Glenfield City as m; j = s + l = 6 + 4 = 10; so m = j + K = 10 + 2 = 12. Define elementary school in Glenfield City as e; z = K + m = 2 + 12 = 14; so e = z + l = 14 + 4 = 18. Define total number of schools in Glenfield City as g; so g = m + e = 12 + 18 = 30. Answer: 30.


The number of adult bear in Jefferson Circus equals the number of adult wolf in Jefferson Circus. The number of adult wolf in Jefferson Circus equals 4. The number of adult bear in South Zoo equals the sum of the number of adult wolf in Jefferson Circus, the number of adult wolf in South Zoo, the number of adult bear in Jefferson Circus, and the total number of adult animals in Jefferson Circus. The number of adult wolf in South Zoo equals the sum of the total number of adult animals in Jefferson Circus, the number of adult bear in Jefferson Circus, and the number of adult wolf in Jefferson Circus.

Question: What is the total number of adult animals in South Zoo?

Solution: Define adult wolf in Jefferson Circus as x; so x = 4. Define adult bear in Jefferson Circus as f; so f = x = 4. Define total number of adult animals in Jefferson Circus as q; so q = x + f = 4 + 4 = 8. Define adult wolf in South Zoo as l; j = q + f = 8 + 4 = 12; so l = j + x = 12 + 4 = 16. Define adult bear in South Zoo as m; G = x + l = 4 + 16 = 20; e = G + f = 20 + 4 = 24; so m = e + q = 24 + 8 = 32. Define total number of adult animals in South Zoo as n; so n = l + m = 16 + 32 = 48. Answer: 48.


The number of culinarian school in Westhaven City equals 3. The number of culinarian school in Glenfield City equals 2 times the sum of the total number of schools in Westhaven City, the number of regional medical school in Westhaven City, and the number of culinarian school in Westhaven City. The number of regional medical school in Westhaven City equals 2. The number of regional medical school in Glenfield City equals 3 times the sum of the number of culinarian school in Westhaven City and the total number of schools in Westhaven City.

Question: What is the total number of schools in Glenfield City?

Solution: Define regional medical school in Westhaven City as J; so J = 2. Define culinarian school in Westhaven City as B; so B = 3. Define total number of schools in Westhaven City as M; so M = B + J = 3 + 2 = 5. Define culinarian school in Glenfield City as g; d = M + J = 5 + 2 = 7; N = d + B = 7 + 3 = 10; so g = 2 * N = 2 * 10 = 20. Define regional medical school in Glenfield City as s; i = B + M = 3 + 5 = 8; so s = 3 * i = 3 * 8 = 24. Define total number of schools in Glenfield City as v; so v = s + g = 24 + 20 = 44. Answer: 44.


The number of culinarian school in Ruby Bay equals 3. The number of regional medical school in Riverton City equals 1 plus the difference between the total number of schools in Ruby Bay and the number of culinarian school in Ruby Bay. The number of regional medical school in Ruby Bay equals 4 times the number of culinarian school in Ruby Bay. The number of culinarian school in Riverton City equals the sum of the number of regional medical school in Riverton City, the total number of schools in Ruby Bay, and the number of regional medical school in Ruby Bay.

Question: What is the total number of schools in Riverton City?

Solution: Define culinarian school in Ruby Bay as V; so V = 3. Define regional medical school in Ruby Bay as y; S = V = 3; so y = 4 * S = 4 * 3 = 12. Define total number of schools in Ruby Bay as d; so d = V + y = 3 + 12 = 15. Define regional medical school in Riverton City as s; B = d - V = 15 - 3 = 12; so s = 1 + B = 1 + 12 = 13. Define culinarian school in Riverton City as G; q = s + d = 13 + 15 = 28; so G = q + y = 28 + 12 = 40. Define total number of schools in Riverton City as h; so h = s + G = 13 + 40 = 53. Answer: 53.


The number of futuristic sci-fi movie in Festival Lumière de Valmont equals 2. The number of calm road movie in Rêves de Belleville equals 3 plus the difference between the total number of movies in Festival Lumière de Valmont and the number of futuristic sci-fi movie in Festival Lumière de Valmont. The number of upbeat metropolis comedy in Festival Lumière de Valmont equals 4 times the total number of movies in Festival de Clairmont. The number of futuristic sci-fi movie in Festival de Clairmont equals 3. The number of upbeat metropolis comedy in Rêves de Belleville equals the total number of movies in Festival Lumière de Valmont.

Question: What is the total number of movies in Rêves de Belleville?

Solution: Define futuristic sci-fi movie in Festival de Clairmont as A; so A = 3. Define total number of movies in Festival de Clairmont as C; so C = A = 3. Define futuristic sci-fi movie in Festival Lumière de Valmont as U; so U = 2. Define upbeat metropolis comedy in Festival Lumière de Valmont as T; W = C = 3; so T = 4 * W = 4 * 3 = 12. Define total number of movies in Festival Lumière de Valmont as j; so j = T + U = 12 + 2 = 14. Define calm road movie in Rêves de Belleville as B; V = j - U = 14 - 2 = 12; so B = 3 + V = 3 + 12 = 15. Define upbeat metropolis comedy in Rêves de Belleville as F; so F = j = 14. Define total number of movies in Rêves de Belleville as Y; so Y = F + B = 14 + 15 = 29. Answer: 29.


The number of elementary school in Brightford equals 1 plus the number of culinarian school in Brightford. The number of elementary school in Glenfield City equals 2 times the sum of the total number of schools in Brightford, the number of culinarian school in Brightford, and the number of elementary school in Brightford. The number of culinarian school in Brightford equals 2. The number of culinarian school in Glenfield City equals the sum of the number of elementary school in Brightford and the number of elementary school in Glenfield City.

Question: What is the total number of schools in Glenfield City?

Solution: Define culinarian school in Brightford as u; so u = 2. Define elementary school in Brightford as f; N = u = 2; so f = 1 + N = 1 + 2 = 3. Define total number of schools in Brightford as i; so i = f + u = 3 + 2 = 5. Define elementary school in Glenfield City as v; R = i + u = 5 + 2 = 7; M = R + f = 7 + 3 = 10; so v = 2 * M = 2 * 10 = 20. Define culinarian school in Glenfield City as D; so D = f + v = 3 + 20 = 23. Define total number of schools in Glenfield City as Q; so Q = v + D = 20 + 23 = 43. Answer: 43.


The number of elementary school in Brightford equals the number of regional medical school in Brightford. The number of elementary school in Glenfield City equals 3. The number of culinarian school in Glenfield City equals the sum of the number of regional medical school in Brightford and the number of elementary school in Brightford. The number of culinarian school in Hawkesbury equals 2. The number of elementary school in Hawkesbury equals 3. The number of regional medical school in Brightford equals 4. The number of culinarian school in Brightford equals 4. The number of regional medical school in Hawkesbury equals 2 times the number of culinarian school in Hawkesbury. The number of regional medical school in Glenfield City equals the total number of schools in Brightford.

Question: What is the total number of schools in Glenfield City?

Solution: Define regional medical school in Brightford as s; so s = 4. Define elementary school in Brightford as W; so W = s = 4. Define culinarian school in Brightford as k; so k = 4. Define total number of schools in Brightford as S; F = s + k = 4 + 4 = 8; so S = F + W = 8 + 4 = 12. Define regional medical school in Glenfield City as P; so P = S = 12. Define elementary school in Glenfield City as j; so j = 3. Define culinarian school in Glenfield City as G; so G = s + W = 4 + 4 = 8. Define total number of schools in Glenfield City as R; n = j + G = 3 + 8 = 11; so R = n + P = 11 + 12 = 23. Answer: 23.